The critical value for this problem would be 1.729, as this corresponds to a 5% error level and a two-tailed test.
To explain further, we can use hypothesis testing to determine whether the claim made by the local professor is supported by the sample data.
H0: The true mean salary for college graduates in the program is equal to or less than $53,500.
And our alternative hypothesis as:
Ha: The true mean salary for college graduates in the program is greater than $53,500.
We can then use the sample mean and standard deviation to calculate the test statistic:
t = (sample mean - hypothesized mean) / (standard deviation / sqrt(sample size))
t = (50994 - 53500) / (521 / sqrt(20))
t = -2.01
Using a t-distribution table with 19 degrees of freedom (sample size minus 1), and a significance level of 0.05 (corresponding to a 5% error), we can find the critical value for a two-tailed test:
t_critical = +/- 2.093
Since our calculated test statistic falls outside of the critical value range, we can reject the null hypothesis and conclude that there is evidence to suggest that the true mean salary for college graduates in the program is less than $53,500. Therefore, the rival university's faculty may have a valid point in disputing the local professor's claim.
To find the critical value for this problem, we will use a one-tailed t-test since we want to test if the actual value is less than $53,500.
Given:
- Sample size (n) = 20 graduates
- Significance level (α) = 5% or 0.05
- Degrees of freedom (df) = n - 1 = 20 - 1 = 19
Now, let's find the critical value (t) using the t-distribution table. For a one-tailed test at a 5% significance level and 19 degrees of freedom, the critical value is -1.729.
So, the critical value for this problem is -1.729.
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Un granjero tiene para vender 1800 pollo primero vende 2/5 del total luego los 5/6 del resto y si se mueren 37 pollo¿ ¿cuantos pollos le quedan todavia?
Based on the mentioned informations, the farmer is calculated to have 143 chickens left after selling 2/5 and 5/6 of the initial 1800 chickens and 37 chickens died.
The farmer starts with 1800 chickens.
He sells 2/5 of the total, which is:
(2/5) x 1800 = 720 chickens.
So he has 1080 chickens left.
He then sells 5/6 of the remaining chickens, which is:
(5/6) x 1080 = 900 chickens.
So he has 180 chickens left.
Unfortunately, 37 chickens die, so the final number of chickens he has left is:
180 - 37 = 143 chickens.
Therefore, the farmer has 143 chickens left after selling 2/5 and 5/6 of the initial 1800 chickens and 37 chickens died.
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The complete question is :
A farmer has to sell 1800 chickens, first he sells 2/5 of the total, then 5/6 of the rest and if 37 chickens die, how many chickens does he still have left?
(6) The figure shows a rectangle and 6 identical semicircles in a circle. Find the area of the shaded part. (Take π = 3.14.)
[tex]\blue{\boxed{\bold{\mathbb{SOLUTION}}}}[/tex]
Area of the biggest circle:
[tex]\pi r^{2}=\pi \times 6^{2}=\pi \times 36 \ cm^2[/tex].
Area of the rectangle:
[tex]4 \times (2+2+2+2) = 4 \times 8 = 32 \ cm^2[/tex].
Area of the 6 semicircles:
[tex]6 \times \dfrac{1}{2} \times \pi \times r^2 = 3 \times \pi \times 2^2 = \pi \times 12 \ cm^2.[/tex]
Total shaded area:
Biggest circle area - rectangle area - 6 semicircles area
[tex]= \pi \times 36 - 32 - \pi \times 12\\= \pi \times (36-12) - 32\\= \pi \times 24 - 32\\= 3.14 \times 24 - 32\\= 75.36 - 32\\= \boxed{43.36 \ cm^2}[/tex]
Therefore, the shaded part area is [tex]43.36 \ cm^2[/tex].
[tex]\aqua{\boxed{\mathfrak{Thank \: You}}}\\\aqua{\boxed{\bold{answered \: by: \: akbarsdtazm}}}[/tex]
a. A kicker punts a football. The height (in yards) of the football is represented by f(x)=-1/9(x-30)^2+25 , where x is the horizontal distance (in yards) from the kicker's goal line.
Find the domain and range.
b. On the next possession, the kicker punts the football again. The height of the football is represented by g(x)=f(x+5) .
Find the domain and range.
c. Compare the graphs.
d. On which possession does the kicker punts closer to his goal line? Explain.
The kicker's ability to punt the ball any distance from the goal line means that the domain is unlimited in range.
How to explain the informationAs a transformation of f(x), g(x) carries the same infinity of values within its range as well with a limit up to 25.
Decidedly opening downwards, f(x)'s parabola possesses a vertex located at (30, 25). For playing according to territory: representing the kicker’s goal line, x = 30 houses the vertex of f(x) , so punting happens closer there.
In sum, while f(x) equips football players to strategically understand their field posisioning ranging across all heights, trajectory of direction & ranges, executing effective plays based on the available resources; along with g(x) which offers a modified visual representation- they both obey the constraints of physics-based rules.
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A random sample of 111 people was taken. 80 of the people in the sample favored candidate a. we are interested in determining whether or not the proportion of the population in favor of candidate a is significantly more than 70%. the test statistic is:__________
The test statistic is z = 2.75. Since the test statistic is greater than 1.96, we reject the null hypothesis and conclude that the proportion of the population in favor of candidate a is significantly more than 70%.
To calculate the test statistic, we first need to find the proportion of the sample that favored candidate a:
Proportion = 80/111 = 0.72
Next, we calculate the standard error of the proportion:
SE = sqrt[(0.7)(0.3)/111] = 0.045
Finally, we calculate the test statistic using the formula:
z = (Proportion - Hypothesized Proportion) / SE
z = (0.72 - 0.7) / 0.045 = 2.75
Since the test statistic is greater than 1.96 (the critical value for a two-tailed test at the 5% level of significance), we reject the null hypothesis and conclude that the proportion of the population in favor of candidate a is significantly more than 70%.
To determine whether the proportion of the population in favor of candidate A is significantly more than 70%, we'll use the test statistic formula for proportions:
Test statistic = (Sample proportion - Hypothesized proportion) / Standard error
In this case, a random sample of 111 people was taken, and 80 of them favored candidate A. We are interested in finding if the proportion favoring candidate A is more than 70% (0.7).
First, calculate the sample proportion:
Sample proportion = Favored candidate / Total sample
Sample proportion = 80 / 111 ≈ 0.7207
Next, calculate the standard error using the formula:
Standard error = √(p(1-p)/n), where p is the hypothesized proportion and n is the sample size.
Standard error = √(0.7 * (1-0.7) / 111) ≈ 0.0452
Finally, calculate the test statistic:
Test statistic = (0.7207 - 0.7) / 0.0452 ≈ 0.4581
The test statistic for determining whether the proportion of the population in favor of candidate A is significantly more than 70% is approximately 0.4581.
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which of the following is an example of systematic sampling? a) using a random number table, people are chosen and then only the people with even numbers are selected. b) in a population of 500, the first and last 100 for a total of 200 people are chosen. c) in a population of 1000 at a school, every 64th person is chosen. d) a government official uses a list of all the people that have returned tax forms and uses those people that h
The example of systematic sampling is option c) in a population of 1000 at a school, every 64th person is chosen.
In systematic sampling, the population is first divided into a sampling frame (for example, a list or a map) and then every kth individual is selected from the list. In this example, every 64th person is chosen from the list of 1000 individuals, which is an example of systematic sampling. In the example given, there is a list of 1000 individuals, and every 64th person is chosen from the list. This means that the sampling interval k is 64, and the first individual is selected randomly from the first 64 individuals in the list. From then on, every 64th individual is selected to be included in the sample. For instance, if the first individual selected is number 8, then the individuals selected for the sample would be 8+64=72, 8+264=136, 8+364=200, and so on.
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Determine the general solution for: 3.2.1 sinx. (2 cos x - 1) = 0
The general solution for: 3.2.1 sinx. (2 cos x - 1) = 0 is: x = nπ or x = ±π/3 + 2πn.
What is the integer?The zero product property which asserts that at least one of the components must be zero if the product of two factors equals zero must be used to answer this problem. So, we must determine the values of x that bring each factor to zero:
3.2.1 Either x sin or x cos - 1 = 0
When x is a multiple of or when x = n, where n is an integer. we can see that sinx = 0 for the first component. We can find cos x by solving for the second factor:
2 cos x - 1 = 0
2 cos x = 1
cos x = 1/2
Where n is an integer, x is equal to /3 + 2n.
So, x = nπ or x = ±π/3 + 2πn, where n is an integer.
Therefore the solution is x = nπ or x = ±π/3 + 2πn.
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The following probability model describes the number of golf balls ordered by customers of a pro shop and the corresponding probabilities. What is the mean number of golf balls? Round your answer to 2 decimal places if needed. Х P(X) 3 0.14 6 0.29 9 0.36 12 0.11 15 0.10
The mean number of golf balls ordered by customers is 8.22 (rounded to 2 decimal places).
To find the mean number of golf balls, we need to multiply each possible value of X by its corresponding probability, and then sum up the products. That is:
Mean number of golf balls = E(X) = Σ[X*P(X)] where Σ is the summation symbol.
Using the given probability model, we have:
E(X) = 30.14 + 60.29 + 90.36 + 120.11 + 15*0.10
E(X) = 0.42 + 1.74 + 3.24 + 1.32 + 1.50
E(X) = 8.22
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Amy ran 8 miles. She recorded how long it took her to run each mile, rounded to the nearest 1/4 of a minute?
It took Amy a total of 18 1/4 minutes (or 18 minutes and 15 seconds) to run her slowest and fastest miles combined, rounded to the nearest 1/4 of a minute.
To find out how long it took for Amy to run her slowest and fastest mile combined, we need to first determine her slowest and fastest mile times.
From the frequency table, we can see that the slowest mile time recorded is 9 2/4 (which can be simplified to 9 1/2) and it occurred once. The fastest mile time recorded is 8 3/4 and it occurred twice.
To find the total time it took for Amy to run her slowest and fastest miles combined, we need to add these two times together.
9 1/2 + 8 3/4 = 18 1/4
Therefore, it took Amy a total of 18 1/4 minutes (or 18 minutes and 15 seconds) to run her slowest and fastest miles combined, rounded to the nearest 1/4 of a minute.
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Here is the complete question:
Amy ran 8 miles. She recorded how long it took her to run each mile, rounded to the nearest 1/4 of a minute?
TIME FREQUENCY
8 3/4 2
9 3
9 1/4 2
9 2/4 1
How long did it take army to run her slowest and fastest mile combined?
Choose the answer based on the most efficient method as presented in the lesson.
If the first step in the solution of the equation -x+6=5-3x is "subtract 5," then what should the next step be?
O add x
O add 3x
O subtract 6
NEXT QUESTION
READ NEXT SECTION
O ASK FOR HELP
The next step in solving the equation, if the first step was to subtract 5, is to A. add x.
How is this the next move ?To solve the equation -x + 6 = 5 - 3x, given that its first step is "subtract 5", one should move on to the next step which requires adding x to both sides of the equation.
Upon completing this newly introduced action, the resulting equation can be viewed as follows:
-x + 6 - 5 = 5 - 3x - 5
-x + 1 = -3x
-x + x + 1 = -3x + x
1 = -2x
By isolating x term on the right side of the equation through addition, resolving for x will become much more manageable and feasible in the succeeding steps.
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a ____ simulation is one in which the quantities to be estimated are defined over a theoretically infinite time frame. group of answer choices A. terminating B. steady-state C. discrete D. stochastic
Stochastic simulations use random variables or probability distributions to model uncertainty in the system being simulated.
The type of simulation that is defined over a theoretically infinite time frame is called a "steady-state simulation".
In a steady-state simulation, the system being modeled is assumed to have reached a stable state where the behavior of the system does not change over time. The simulation is then run for a long period of time, allowing the outputs to converge to a steady state. The quantities to be estimated are defined over this theoretically infinite time frame.
On the other hand, terminating simulations have a fixed end time, and the simulation is terminated when that time is reached. Discrete simulations model systems where the state changes only at discrete points in time. Stochastic simulations use random variables or probability distributions to model uncertainty in the system being simulated.
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8. do the penders live within their monthly net income? if so by how much?
Yes, the Penders are living within their monthly net income.
How to determine the monthly living costTo determine the monthly living cost, you have to add up the monthly fixed and variable costs. Next, you will subtract these from the monthly net income, if there is a remainder, or none, then they are living within their monthly income.
However, if there is a deficit from the calculation, we can arrive at an answer that shows that the Penders are living above their monthly net income. Subtracting the expenses from the income of $2,600 shows a controlled budget.
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The total cost of attending a state university is $20,000 for the first year. The student's grandparents will pay half of this cost. An academic scholarship will pay another $5,000. Which amount is closest to the minimum that the student will need to save every month in order to pay off the remaining cost at the end of the 12 months?
Answer: The student will need to save about 416.66 dollars a month.
Step-by-step explanation:
Step 1. Find out how much the student will need to pay themselves.
20,000 - 10,000 (grandparents) - 5,000 (scholarship) = 5,000
Step 2. Divide the student's cost by the number of months
5,000/12 = about 416.66
I will give 20 points to whoever helps me! Luke planted seeds and recorded the growth after 3 months. The height, in inches, of each plant is listed below. 9, 12, 11, 8, 7, 9, 12, 12, 9, 11, 8, 9 Complete the line plot for the data. Click on each bar and drag up to represent the data.
A line plot for the data is shown in the image attached below.
What is a line plot?In Mathematics and Statistics, a line plot can be defined as a type of graph that is used for the graphical representation of data set above a number line, while using crosses, dots, or any other mathematical symbol.
In this scenario and exercise, we would use an online graphing calculator to graphically represent the given data set on a line plot as shown in the image attached below.
In conclusion, we can reasonably infer and logically deduce that the mode of the data set is equal to 9 because it has the highest frequency of 4.
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Find the value of each variable.
The values of the variables x and y for the cyclic quadrilateral are 85° and 100° respectively.
How to evaluate for the variables in the cyclic quadrilateralThe figure is a cyclic quadrilateral since it four side vertices lie on the circumference of the circle. The sum of the interior angles of a cyclic quadrilateral is also 360°. Also opposite angles of a cyclic quadrilateral add up to 180°
Thus;
x + 95° = 180° {opposite angles of a cyclic quadrilateral}
x = 180° - 95° {collect like terms}
x = 85°
Also;
y + 80° = 180°
y = 180° - 80°
y = 100°.
Therefore, the values of the variables x and y for the cyclic quadrilateral are 85° and 100° respectively.
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the conditions are met for use of a normal model to represent the distribution of sample means. which of the following are used to verify normality conditions for this scenario?
There are several methods that can be used to verify the normality conditions for a scenario where a normal model is used to represent the distribution of sample means.
One common method is the visual inspection of a histogram or a normal probability plot. Another method is to use statistical tests such as the Shapiro-Wilk test or the Kolmogorov-Smirnov test to assess the normality of the sample data. Additionally, the sample size and the presence of outliers can also impact the normality conditions and should be taken into consideration when verifying normality.
Hi! To verify the normality conditions for the distribution of sample means, you should consider the following criteria:
1. Randomness: The sample data must be collected randomly to ensure independence of observations.
2. Sample size: The sample size should be sufficiently large (typically, n ≥ 30) to allow the Central Limit Theorem to apply.
3. Underlying distribution: If the population distribution is known to be normal, the sample means will also be normally distributed regardless of sample size.
These criteria help ensure the use of a normal model is appropriate in representing the distribution of sample means.
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According to the Empirical Rule. Find specified probability. (Round to FOUR decimal places. Write like 0.1234). P(Z > 2.72)
The answer is 0.0034 (rounded to four decimal places). According to the Empirical Rule, 68% of the data falls within 1 standard deviation, 95% within 2 standard deviations, and 99.7% within 3 standard deviations of the mean in a normal distribution.
However, the given value Z > 2.72 is beyond the scope of the Empirical Rule, so we'll need to use a Z-table to find the probability.
Using a Z-table, we find that the area to the left of Z = 2.72 is approximately 0.9966. Since we want the probability of P(Z > 2.72), we'll subtract this value from 1:
P(Z > 2.72) = 1 - 0.9966 = 0.0034
So, the probability of Z > 2.72 is approximately 0.0034.
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What is the value of x?
61
Why my answer is sixty one Because the Triangle ls the same size Of the other sixty one
Answer:
61
Step-by-step explanation:
Consider a population having a standard deviation equal to 10. We wish to estimate the mean of this population.(a) How large a random sample is needed to construct a 95 percent confidence interval for the mean of this population with a margin of error equal to 1? (Round your answer to the next whole number.)A= 385(b) Suppose that we now take a random sample of the size we have determined in part a. If we obtain a sample mean equal to 295, calculate the 95 percent confidence interval for the population mean.What is the interval's margin of error? (Round your answers to 3 decimal places.)B=?
(a) The answer of the question "What is the interval's margin of error (Round your answers to 3 decimal places.)" to part (b) is B = 0.978.
(b) margin of error = 1.96*(10/sqrt(385)) = 0.978
(a) To find the sample size needed to construct a 95% confidence interval with a margin of error of 1, we use the formula:
margin of error = z*(standard deviation/sqrt(sample size))
where z is the critical value from the standard normal distribution for a 95% confidence level, which is approximately 1.96.
Plugging in the given values and solving for the sample size, we get:
[tex]1 = 1.96*(10/sqrt(sample size))[/tex]
[tex]sqrt(sample size) = 1.96*10/1[/tex]
[tex]sample size = (1.96*10)^2 = 384.16[/tex]
Rounding up to the nearest whole number, we need a sample size of 385.
Therefore, the answer to part (a) is 385.
(b) To calculate the 95% confidence interval for the population mean given a sample size of 385 and a sample mean of 295, we use the same formula as above with the values we have:
1 = 1.96*(10/sqrt(385))
Solving for the margin of error, we get:
margin of error = 1.96*(10/sqrt(385)) = 0.978
The 95% confidence interval for the population mean is then:
295 - 0.978 to 295 + 0.978
or
(294.022, 295.978)
Therefore, the answer to part (b) is B = 0.978.
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6) Find the perimeter of the triangle.
3x + 4
+²
19cm
+
The perimeter of the triangle with sides 3x + 4, x² and 19 cm is is x² + 3x + 23 centimetres.
How to find the perimeter of a triangle?The perimeter of the triangle is the sum of the whole sides of the triangle. A triangle have three sides. Therefore, let's sum the sides of the triangle to find the perimeter of the triangle.
Hence,
perimeter of the triangle = x² + 3x + 4 + 19
perimeter of the triangle = x² + 3x + 23
Therefore, the perimeter of the triangle is x² + 3x + 23 centimetres.
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Two different simple random samples are drawn from two different populations. The first sample consists of 20 people with 10 having a common attribute. The second sample consists of 1800 people with 1284 of them having the same common attribute. Compare the results from a hypothesis test of P = P2 (with a 0.01 significance level) and a 99% confidence interval estimate of p, - P2, What are the null and alternative hypotheses for the hypothesis test?
The hypothesis test would give a binary answer of whether or not the proportions are significantly different, while the confidence interval estimate would provide a range of plausible values for P1.
The null hypothesis for the hypothesis test is that the proportion of people with the common attribute in the first population (P1) is equal to the proportion of people with the common attribute in the second population (P2). The alternative hypothesis is that P1 is not equal to P2.
When conducting the hypothesis test with a 0.01 significance level, we would calculate the test statistic and compare it to the critical value from a t-distribution with degrees of freedom equal to the sum of the sample sizes minus two. If the test statistic falls outside of the critical region, we would reject the null hypothesis and conclude that the proportions are significantly different.
On the other hand, the 99% confidence interval estimate of p would provide a range of values that P1 could fall within with 99% confidence. We would calculate the confidence interval by taking the difference in proportions (P2 - P1) and adding/subtracting the margin of error, which is based on the sample sizes and the level of confidence desired.
Overall, comparing the results from the hypothesis test and the confidence interval estimate would provide different information about the proportions in the two populations.
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Chelsey needs 18\frac{3}{4} grams of Chemical X for a science project. She found 5\frac{1}{2} grams in one container and 11\frac{1}{4} grams in another container. How much more does she need?
Answer:
2 g
Step-by-step explanation:
She has a total of
5 1/2 + 11 1/4 =
= 5 2/4 + 11 1/4
= 16 3/4
She needs a total of 18 3/4.
She needs an additional
18 3/4 - 16 3/4 = 2
Answer: 2 g
T/F : Find a 3 by 3 matrix A which is not invertible, but where no two columns are scalar multiples of each other, and no two rows are scalar multiples of each other
False.
It is not possible to find a 3 by 3 matrix A which is not invertible, but where no two columns are scalar multiples of each other, and no two rows are scalar multiples of each other.
It is not possible to find a 3 by 3 matrix A which is not invertible, but where no two columns are scalar multiples of each other, and no two rows are scalar multiples of each other.
This is because if no two columns of A are scalar multiples of each other, then the columns are linearly independent, and the rank of A is at least 3. Similarly, if no two rows of A are scalar multiples of each other, then the rows are linearly independent, and the rank of A is also at least 3. Since A is a 3 by 3 matrix, it follows that the rank of A is at most 3. Therefore, the only way for A to have rank 3 is for A to be invertible.
So, any 3 by 3 matrix A that is not invertible must have either two columns that are scalar multiples of each other, or two rows that are scalar multiples of each other.
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Gabriel wants to buy some items in a hardware store. The cost of 3 handles and 1 bolt is £11. The cost of 2 handles and 3 bolts is £12. The cost of 7 handles and 5 bolts is £31. Work out how much the following cost: a) 10 handles and 6 bolts. b) 5 handles and 2 bolts. c) 12 handles and 9 bolts.
Answer:
10h+6b=£48
5h+2b=£19
12h+9b=£60
Step-by-step explanation:
10h+6b=(3h+1b)+(7h+5b)
5h+2b=(7h+5b)-(2h+3b)
12h+9b=(10h+6b)+(2h+3b)
h=handles
b=bolts
which equation results from applying the secant and tangent segment theorem to the figure?12(a 12)
This simplifies to:
a² = 12x + 144
This is the equation that results from applying the Secant-Tangent Segment Theorem to the given figure.
Let's first define the terms and state the Secant-Tangent Segment Theorem.
1. Equation: A mathematical statement that shows the equality of two expressions.
2. Secant: A line that intersects a circle at two points.
3. Tangent: A line that touches a circle at only one point, without crossing it.
Secant-Tangent Segment Theorem: If a secant and a tangent are drawn from a point outside a circle, the product of the length of the secant segment and its external part is equal to the square of the length of the tangent segment.
Let's represent the given lengths as follows:
- Length of tangent segment = a
- Length of secant segment (inside the circle) = 12
- Length of the external part of the secant segment (outside the circle) = x
According to the Secant-Tangent Segment Theorem, the equation is:
(a)(a) = (12)(x + 12)
This simplifies to:
a² = 12x + 144
This is the equation that results from applying the Secant-Tangent Segment Theorem to the given figure.
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(6x10^1) + (9x10^1) in scientific notation
The requried, (6x10¹) + (9x10¹) in scientific notation is 1.50x10²
To add (6x10^1) + (9x10^1) in scientific notation, we need to first make sure that the exponents of 10 are the same.
Now we can add the two numbers:
6.0x10¹ + 9.0x10¹ = 15.0x10¹
To express the result in scientific notation, we need to write 15.0 as 1.50 and move the decimal point one place to the left, which gives:
1.50x10²
Therefore, (6x10¹) + (9x10¹) in scientific notation is 1.50x10².
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How many ordered quadruplets (a1,a2,a3,a4) of non-negative integers, where at least one of the integers is even, satisfy the equation a1+a2+a3+a4=100 ? Please express your answer in the form (wx)−(yz). (Note that the values of w,x,y and z will be integers, but not necessarily all distinct.)
The number of ordered quadruplets of non-negative integers that satisfy the given condition is:
|A| - |B| = 161,700 - 16,215 = 145,485
To solve this problem, we need to use the Principle of Inclusion-Exclusion (PIE). Let A be the set of all quadruplets (a1,a2,a3,a4) of non-negative integers that satisfy the equation a1+a2+a3+a4=100, and let B be the set of all quadruplets where all four integers are odd. Then the number of quadruplets that satisfy the given condition is given by:
|A| - |B|
To find |A|, we can use stars and bars. If we consider 100 stars and 3 bars, we can partition the stars into 4 groups, corresponding to the four integers. There will be 99 gaps between the stars and bars, and we need to choose 3 of them to place the bars. This gives us:
|A| = (99 choose 3) = 161,700
To find |B|, we can use a similar approach. If all four integers are odd, then they must be of the form 2k+1, where k is a non-negative integer. Substituting this into the equation a1+a2+a3+a4=100, we get:
2k1 + 1 + 2k2 + 1 + 2k3 + 1 + 2k4 + 1 = 100
Simplifying this equation, we get:
k1 + k2 + k3 + k4 = 48
This is now an equation in non-negative integers, which we can solve using stars and bars. We need to partition 48 stars into 4 groups, and there will be 3 bars separating them. This gives us:
|B| = (47 choose 3) = 16,215.
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The opinions of all 450 students at a high school on whether they support Candidate A for student body president are shown below. Hide and shuffle all of the values. Take a random sample of 25 values from the population. Based on that sample, find the sample proportion and use that value to create a 95% confidence interval for the true proportion of the population who support Candidate A, rounding to the nearest thousandth.
Sample Yes: 19 Sample No: 6 Samples: 25
Answer:
Step-by-step explanation:
Les opinions des 450 élèves d'un lycée quant à savoir s'ils soutiennent le candidat A à la présidence du corps étudiant sont présentées ci-dessous. Masquez et mélangez toutes les valeurs. Prenez un échantillon aléatoire de 25 valeurs de la population. Sur la base de cet échantillon, trouvez la proportion de l'échantillon et utilisez cette valeur pour créer un intervalle de confiance à 95 % pour la véritable proportion de la population qui soutient le candidat A, en arrondissant au millième le plus proche.
Échantillon Oui : 19 Échantillon N° : 6 Échantillons : 25
Use trigonometric ratios to solve for x.
X
49°
16
A
The side x of the given right angle triangle is: 24.388
How to find trigonometric ratios?The six trigonometric ratios that we have are:
sine (sin)
cosine (cos)
tangent (tan)
cotangent (cot)
cosecant (cosec)
secant (sec).
In geometry, trigonometry is defined as a branch of mathematics that caters for the sides and also the angles of right-angled triangles. Thus, trigonometric ratios are evaluated considering the sides and angles
The three main trigonometric ratios are expressed as:
sin x = opposite/hypotenuse
cos x = adjacent/hypotenuse
tan x = opposite/adjacent
We want to find the side x of the given right angle triangle.
Thus:
16/x = cos 49
x = 16/cos 49
x = 24.388
Thus, we can say that is the value of x
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Based on the results of this hypothesis test, would you expect a confidence interval for the average difference between the reading and writing scores to include 0? Explain your reasoning. a. yes, because there is almost a 0% chance that average reading and writing scores are the same b. no, because most people will not earn an average score of 0 on either exam c. yes, because the evidence was not strong enough to suggest that average reading and writing scores differ d. no, because we rejected the idea that average reading and writing scores are equal
The correct answer is c. Yes, because the evidence was not strong enough to suggest that average reading and writing scores differ.
In hypothesis testing, we use a significance level to determine whether to reject or fail to reject the null hypothesis. If the p-value is less than the significance level, we reject the null hypothesis and conclude that there is evidence to support the alternative hypothesis. If the p-value is greater than the significance level, we fail to reject the null hypothesis and conclude that there is not enough evidence to support the alternative hypothesis.
Based on the results of the hypothesis test, if we failed to reject the null hypothesis (which is the case in this question), then we cannot conclude that the average reading and writing scores differ. Therefore, it is reasonable to expect a confidence interval for the average difference between the reading and writing scores to include 0. A confidence interval is a range of values that is likely to contain the true population parameter with a certain degree of confidence. Since we cannot conclude that the average scores differ, it is possible that the true population parameter is 0, and thus 0 could be included in the confidence interval.
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A right rectangular prism is sliced in a way such that the plane passes through the prism at a slant. what is the resulting cross section?
The resulting cross section of the prism will be a parallelogram.
When a right rectangular prism is sliced in a way such that the plane passes through the prism at a slant, the resulting cross section is a parallelogram. This is because the intersection of a plane and a rectangular prism that is not parallel to any of its faces is always a parallelogram.
The shape and size of the parallelogram will depend on the orientation of the plane and the dimensions of the prism. Since the prism is a right rectangular prism, the opposite faces are parallel and congruent, and so are the opposite edges of the parallelogram cross section.
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