the parameter and obtain the standard form of the rectangular equation would be: [tex]\frac{y-k}{r} = sin\theta.................(2)\\\\[/tex]
[tex]x=h+rcos\theta ,y=k+rsin\theta\\x-h=rcos\theta\\\frac{x-h}{r}=cos\theta...................(1)y=k+rsin\thetay-k=rsin\theta[/tex]
[tex]\frac{y-k}{r} = sin\theta.................(2)\\\\[/tex]
square and add both the equations
[tex]\frac{(x-h)^2}{(r^2)} + \frac{(y-k)^2}{(r^2)} = sin^2\s\theta + cos^2\s\theta\\\\\frac{(x-h)^{2}}{r^{2}}+\frac{(y-k)^{2}}{r^{2}}=1\\\\ the value of (sin^{2}\theta+cos^{2}\theta=1)\\\\(x-h)^{2}+(y-k)^{2}=r^{2}[/tex]
The overall rectangular (or standard) form of the perplexing numbers is a + b I. We can change over complex numbers in rectangular form, by tracking down r = a 2 + b 2 and θ = tan − 1 .
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DUE TOMORROW PLEASE HELP WELL WRITTEN ANSWERS ONLY!!!!!!
Sketch a graph of the function f given by f(Θ) = 2 sin(Θ)
The graph of the function f given by f(Θ) = 2 sin(Θ) is attached below the sum,
Use the form
a sin(bx−c)+d to find the variables used to find the amplitude, period, phase shift, and vertical shift.
a=2
b=1
c=0
d=0
Find the amplitude |a|.
Amplitude: 2
Find the period of 2 sin(x).
Its 2π.
List the properties of the trigonometric function.
Amplitude: 2
Period: 2π
Phase Shift: None
Vertical Shift: None
x y
0 0
[tex]\frac{\pi }{2}[/tex] 2
[tex]\pi[/tex] 0
[tex]\frac{3\pi }{2}[/tex] -2
[tex]2\pi[/tex] 0
Then we can plot the according to the given function f(Θ) = 2 sin(Θ).
Hence the graph is attached below.
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find an algebraic expression for the particle's velocity vx at a later time t . express your answer in terms of the variables c , t , v0x , and m .
The algebraic expression for the particle's velocity vₓ at a later time t is v(t) = ct²/2m +v₀ₓ.
Given that,
c = speed of light
t = time
v₀ₓ = initial velocity of particle
m = mass of particle
Velocity and acceleration are related through time. Acceleration is the rate of change of velocity, which is represented graphically as the slope of the velocity vs. time line. Velocity can be represented as the area underneath an acceleration vs. time line.
Newton's second law declares that an object having mass m will accelerate due to a net force (F) will accelerate at a rate of:
α = F/m
Therefore, the function that describes the acceleration at any point in time of the particle is:
α(t)=ct/m
The velocity function is the integral of the acceleration function, so we get:
v(t)= ∫ct/m dt
= ct²/2m +C
where the constant C is the initial velocity of the particle at time t=0. Therefore, the velocity function representing the velocity at any point in time is:
v(t) = ct²/2m +v₀ₓ
Therefore, the algebraic expression for the particle's velocity vₓ at a later time t is v(t) = ct²/2m +v₀ₓ.
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Ming took a cab across town. His fare was $22, and he leaves an 18% tip.
What is the total amount Ming pays the cab driver?
Answer:
$25.96
Step-by-step explanation:
Since the tip is 18% of the fare, he pays 118% of the fare.
118% of $22 =
= 1.18 × $22
= $25.96
if someone told you that a distribution showed a floor effect, you would surmise that it is group of answer choices
When someone describes a distribution as having a floor effect, it means that the distribution is characterized by a significant clustering of values at the minimum value, creating a skewed distribution with a long tail on the higher end.
This phenomenon is often observed in situations where there is a lower limit or minimum value that restricts the possible range of values that can be observed. The floor effect can be seen in various domains such as clinical trials, educational testing, psychological assessments, and market research, to name a few.
For instance, in a clinical trial, the use of an intervention that is highly effective in reducing symptoms may lead to a large number of participants reaching the minimum score, making it difficult to differentiate between groups in terms of treatment response.
Similarly, in educational testing, a poorly designed test or a test that is too easy for the group being tested may result in a floor effect, where students cluster around the lowest score and scores do not differentiate between students with different levels of knowledge.
A floor effect can be problematic because it can limit the ability to detect differences or changes in scores or performance, which can have implications for interpreting and comparing results across different groups or time points.
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The base of the parallelogram has a length
of 10 cm. What is the height?
10cm
12 cm
14 cm
The height is either 10 cm,12 cm,14 cm.
What is an expression?Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.
Given that;
The base of the parallelogram has a length of 10 cm.
Here, area is not given so the height may be anything.
suppose h = 10
Hence, We get;
Area = base * height
= 10 * 10
= 100 cm²
if h = 12
area = 10 * 12
= 120 cm²
if h = 14
area = 10 * 14
= 140 cm²
Therefore, the height is either 10 cm,12 cm,14 cm.
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the equation above relates the number of hours, a, kevin spends doing homework each week and the number of hours he spends watching television each week. if kevin spends a total of 15 hours doing homework and watching television each week, what does the variable b represent?
Variable b represents the number of hours Kevin spends watching television each week.
Define the term equation?A statement proving the equality of two mathematical expressions is known as an equation.
Given equation a + b = 15 relates the number of hours.
If here Kevin spends doing homework each week (represented by the variable "a") and the number of hours he spends watching television each week (represented by the variable "b").
Since the total number of hours Kevin spends doing homework and watching television each week is 15, we can write:
homework + watching television = 15 hours
a + b = 15
To find out what b represents, we can rearrange the equation to solve for b:
b = 15 - a
This means that b represents the number of hours Kevin spends watching television each week, given that he spends a hours doing homework each week and the total number of hours spent on both activities is 15.
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Complete question-
The equation is a + b = 15
what is the radical equivalent to s^3/2
Answer:
√1.5
Step-by-step explanation:
As a fraction, the square root of 3/2 can be expressed as √1.51 or just as √1.5.
a box contains 8 red balls and 8 blue balls, and 4 balls are taken at random without replacement. what is the probability that 2 red balls and 2 blue balls are taken?
The probability that 2 red balls and 2 blue balls are taken from the box is 3/7. This can be expressed mathematically as [tex](8C2 * 8C2) / (16C4) = 3/7[/tex].
To better understand this probability, let's look at an example. Say there are 8 red balls and 8 blue balls in the box. This can be represented as:
R = 8, B = 8
We want to determine the probability of taking 2 red balls and 2 blue balls out of the box. To do this, we need to calculate the total number of ways of selecting 4 balls from the box (16 balls in total) and then calculate the total number of ways of selecting 2 red and 2 blue balls out of the box.
The total number of ways of selecting 4 balls from the box can be expressed as (16C4). This is calculated by dividing the number of ways of selecting 4 balls out of 16 (16!) by the number of ways of arranging those 4 balls in any order (4!):
[tex](16C4) = 16! / 4! = 1820[/tex]
The total number of ways of selecting 2 red and 2 blue balls out of the box can be expressed as (8C2 * 8C2). This is calculated by multiplying the number of ways of selecting 2 red balls out of 8 (8C2) by the number of ways of selecting 2 blue balls out of 8 (8C2):
[tex](8C2 * 8C2) = 8C2 * 8C2 = 28[/tex]
The probability of taking 2 red balls and 2 blue balls out of the box is then the ratio of the number of ways of selecting 2 red and 2 blue balls out of the box (28) to the total number of ways of selecting 4 balls from the box (1820):
P(2 red balls, 2 blue balls) = 28 / 1820 = 3/7
In conclusion, the probability of taking 2 red balls and 2 blue balls out of a box containing 8 red balls and 8 blue balls is 3/7.
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An empty shipping box has a mass of 2. 75 kilograms. An electronics store is packing 5 identical laptops in the shipping box. Each laptop has a mass of 1. 65 kg. The cost to ship the box was $40. 00 for the first 5 kg and $3. 15 for each kilogram over 5 kg. What was the cost to ship the packed box?
The cost to ship a box containing 5 laptops, weighing a total of 11 kg (including the empty box), is $58.90, with a cost of $40.00 for the first 5 kg and $3.15 for each additional kilogram.
The total mass of the packed shipping box can be found by adding the mass of the laptops (5 * 1.65 kg = 8.25 kg) to the mass of the empty box (2.75 kg) for a total mass of 11 kg.
Since the cost to ship the box is $40.00 for the first 5 kg and $3.15 for each additional kilogram over 5 kg, we can split the total mass into two parts: the first 5 kg and the additional weight above 5 kg.
The cost to ship the first 5 kg is $40.00, and the remaining weight is 11 kg - 5 kg = 6 kg.
The cost to ship the additional 6 kg is $3.15 per kilogram, so the total cost to ship the packed box is:
$40.00 + $3.15 * 6 kg = $58.90
Therefore, the cost to ship the packed box is $58.90.
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The following data points represent the number of points the Hawaii Eagles football team scored each game.
17, 33,28,23,10,42,3
Using the data, create and histogram
The class intervals are given as:
0 - 15 15-30 30-45
2 3 2
What is a Histogram?A histogram is a graphical representation of the distribution of numerical data. It is a way of summarizing the shape and spread of a set of continuous data values into a series of bins or intervals.
The histogram is a bar graph-like representation of the data, where the data is grouped into intervals or bins on the horizontal axis and the frequency or count of observations falling into each bin is represented by the height of the bar on the vertical axis.
Each value is grouped into one of three ranges, 0-15, 15-30, 30-45, once we know how many values are in each group, we can graph it.
The class intervals are given as:
0 - 15 15-30 30-45
2 3 2
The histogram is provided below:
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Your report discusses trends in net profits over a period of four years. To visually display these trends, you should use a __________.
A. table
B. flowchart
C. line chart
D. pie chart
To visually display the trends in net profits over a period of four years, you should use a line chart
Explanation:
.What is a line chart?A line chart is a type of chart used to show information as a series of data points connected by straight line segments. A line chart is a basic type of chart that is often used in data analysis. It is also known as a line graph or a curve chart. This type of chart is commonly used to display trends in data over time.
In the given question, it has been asked to visually display the trends in net profits over a period of four years. To visually display the trends in net profits, a line chart is the best choice. Therefore, the correct answer is option C, a line chart.
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a rectangular flag is 29ft long and 17ft wide. if a triangle is cut out of the center of the flag that has a base of 9ft and a height of 2ft , what is the remaining area of the flag?
A rectangular flag is 29ft long and 17ft wide. if a triangle is cut out of the center of the flag that has a base of 9ft and a height of 2ft, So the remaining area of the flag is 484 ft².
The data we get from the question is,
Length of rectangular flag = 29 ft
Width of rectangular flag = 17 ft
Base of triangle = 9 ft
Height of triangle = 2 ft
We need to find the remaining area of the flag when a triangle is cut out of the center of the flag.
We know that the area of the rectangle is given by:
Area of rectangle = length × breadth
Area of rectangle = 29 × 17
= 493 ft²
The area of the triangle is given by:
Area of triangle = (1/2) × base × height
Area of triangle = (1/2) × 9 × 2
= 9 ft²
The remaining area of the flag will be the area of the rectangle minus the area of the triangle.
The remaining area of the flag = Area of the rectangle - Area of the triangle
= 493 - 9
= 484 ft²
Therefore, the remaining area of the flag is 484 ft².
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the nonparametric tests discussed in your book (wilcoxon rank sum test, sign test, wilcoxon signed rank sum test, kruskal-wallis test, and friedman test) all require that the probability distributions be:
Nonparametric tests can be useful in situations where the data may not follow a specific distribution or where the assumptions of a parametric test are not met.
The nonparametric tests mentioned in your question do not assume any specific probability distribution for the data. Hence, they are called nonparametric tests. These tests are used when the assumptions required for parametric tests (e.g., normality) are not met, or when the data is measured on ordinal or nominal scales rather than continuous ones.
The Wilcoxon rank-sum test, sign test, and Wilcoxon signed-rank test are used to compare two independent or dependent samples. The Kruskal-Wallis test and Friedman test are used to compare three or more independent or dependent samples.
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Which of the following equations represent(s) a line that goes through the
points (2,3) and (1,1)?
1) y = 2(x-2) + 3
II) y = 2x - 1
III) y = 2(x-1) + 1
O I, II & III
O III only
OI and III
OI only
O II only
Answer:
O I, II & III
Step-by-step explanation:
(2, 3) and (1, 1)
m = (3 - 1)/(2 - 1) = 2
y = 2x + b
1 = 2(1) + b
b = -1
The equation of the line is
y = 2x - 1
I) y = 2(x - 2) + 3 = 2x - 4 + 3 = 2x - 1 Yes
II) y = 2x - 1 Yes
III) y = 2(x - 1) + 1 = 2x - 2 + 1 = 2x - 1 Yes
Answer: O I, II & III
how much work, in foot-pounds, is done when a 50-foot long cable with a weight-density of 8 pounds per foot is wound up 14 feet? do not include any units in your answer.
The amount of work done when winding up a 50-foot long cable with a weight density of 8 pounds per foot is 14 feet is 5600 foot-pounds.
To explain this answer in more detail, work is a measure of energy and is calculated by multiplying force and distance. In this case, the force is the weight-density of the cable, which is 8 pounds per foot. The distance is the amount of cable that was wound up, which is 14 feet. Multiplying 8 and 14 together gives us the force of 112 pounds. Multiplying 112 by the total length of the cable, which is 50 feet, gives us the answer of 5600 foot-pounds.
To further explain, it is important to remember that 1 foot-pound is equal to 1 pound-foot. That means that 1 pound of force must be applied to move an object 1 foot in order to do 1 foot-pound of work. When this is applied to the example above, we can see that 8 pounds of force must be applied to the cable in order to move it 1 foot. Multiplying this by the length of the cable (50 feet) and the amount of cable wound up (14 feet) gives us the total amount of work done, which is 5600 foot-pounds.
In summary, the amount of work done when winding up a 50-foot long cable with a weight density of 8 pounds per foot is 14 feet is 14 x 8 x 50 = 5600 foot-pounds.
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If g(x) = 1 – 2x + 3x2, find the average rate of change of the function as x varies from 2 to 5
The average rate of change of the function as x varies from 2 to 5 is 22.
Given function: g(x) = 1 – 2x + [tex]3x^2[/tex]
To find the average rate of change of the function as x varies from 2 to 5.
Solution: We are given a function: g(x) = 1 – 2x + [tex]3x^2[/tex]
The average rate of change of the function as x varies from a to b is given by:
Average rate of change = f(b) - f(a) / b - a
Let a = 2 and b = 5
We have to find the average rate of change of g(x) as x varies from 2 to 5.
So, the average rate of change of g(x) is given by:
Average rate of change = g(5) - g(2) / 5 - 2
= [1 - 2(5) + 3([tex]5^2[/tex])] - [1 - 2(2) + 3([tex]2^2[/tex])] / 3
= [1 - 10 + 75] - [1 - 4 + 12] / 3= 66 / 3= 22
Therefore, the average rate of change of the function as x varies from 2 to 5 is 22.
An average rate of change is the amount that the function changes on average over a specified interval.
The formula for average rate of change is given as the change in the function value divided by the change in x value for two distinct points on the function.
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44.0183 rounded to the nearest thousands
the top of an l-shaped desk has the dimensions shown. what volume of wood is needed to make the top of the desk? complete the explanation of how you solved this problem.
The volume of wood needed to make the top of the l-shaped desk is 0.728 cubic feet
The top of an l-shaped desk has the dimensions shown in the diagram. To determine the volume of wood needed to make the top of the desk, we must use the formula for volume. The formula for volume is length times width times height, or V = lwh. In this case, the length of the top is 28 inches, the width is 45 inches, and the height is 0.75 inches.
Plugging these values into the volume formula gives us V = 28 x 45 x 0.75, which equals 1260 cubic inches. Since wood is typically sold in cubic feet, we must convert this volume to cubic feet by dividing it by 1728, the number of cubic inches in one cubic foot. 1260/1728 = 0.728, so the volume of wood needed to make the top of the desk is 0.728 cubic feet.
To summarize, the volume of wood needed to make the top of the l-shaped desk is 0.728 cubic feet. This was determined by using the volume formula, which is V = lwh, where l is the length, w is the width, and h is the height. The length, width, and height of the desk top were 28 inches, 45 inches, and 0.75 inches, respectively. By plugging these values into the volume formula and converting to cubic feet, we determined the volume of wood needed is 0.728 cubic feet.
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Which recursively defined function has a first term equal to 10 and a common difference of 4?
The recursively defined function has a first term equal to 10 and a common difference of 4 is f(n) = 6 + 4n.
When a recursive procedure gets repeated, it's called recursion. A recursive is a type of function or expression stating some conception or property of one or further variables, which is specified by a procedure that yields values or cases of that function by constantly applying a given relation or routine operation to known values of the function.
We have first term = a = 10
And the common difference of d = 4
We have the formula for the t terms of a as 10 and d as 4
f(n) = a + (n - 1)d
f(n) = 10 + (n-1) x 4
f(n) = 10 + 4n - 4
f(n) = 6 + 4n
So, the defined function is f(n) = 6 + 4n.
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at 99% confidence, how large a sample should be taken to obtain a margin of error of for the estimation of a population proportion? assume that past data are not available for developing a planning value for . round up to the next whole number.
To estimate a population proportion with a margin of error of 1% and a 99% confidence interval, we would need a sample size of at least 6644 individuals.
The formula to calculate the sample size is:
n = [z² x p(1-p)] / e²
where:
n is the sample size
z is the z-score corresponding to the desired confidence level (in this case, 2.576 for a 99% confidence level)
p is the planning value for the population proportion, which we don't know in this case, so we will assume the worst-case scenario of p=0.5 (which gives us the maximum sample size needed)
e is the desired margin of error
Plugging in the values, we get:
n = [(2.576)² x 0.5(1-0.5)] / (0.01)²
n = 6643.04
Since we need to round up to the next whole number, the minimum sample size needed is 6644.
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The school cafeteria has 150 cups of strawberries and 450 cups of blackberries. How many total cups of berries does the school cafeteria have?
Total number of cups of berries does the school cafeteria have is 600
Addition is a basic mathematical operation that involves combining two or more numbers or quantities to find a total or sum. In other words, it is the process of finding the total amount when two or more numbers are added together.
To find the total number of cups of berries in the school cafeteria, you can add the number of cups of strawberries and blackberries.
The school cafeteria has 150 cups of strawberries and 450 cups of blackberries, so
Total cups of berries = cups of strawberries + cups of blackberries
Total cups of berries = 150 + 450
Total cups of berries = 600
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please answer asap!!
Answer:
y = csc(3x)
Step-by-step explanation:
You want an equation for a cosecant curve with vertical asymptotes at multiples of π/3.
Horizontal compressionThe vertical asymptotes of the parent cosecant function are at multiples of π. Putting them at multiples of π/3 means compressing the graph horizontally by a factor of 3.
That compression means x will be replaced by 3x in the equation. You want ...
y = csc(3x)
the speed of light is approximately 6.7106*10^7 per hour, and the speed of sound is approximately 7.54*10^2 miles per hour. How many times faster is the speed of light than the speed of sound?
Answer: The speed of light is approximately 89,100 times faster than the speed of sound.
Step-by-step explanation: To find out how many times faster the speed of light is than the speed of sound, we need to divide the speed of light by the speed of sound:
Speed of light / Speed of sound = (6.710610^7) / (7.5410^2)
Simplifying this calculation gives us:
Speed of light / Speed of sound = 8.91*10^4
This means that the speed of light is approximately 89,100 times faster than the speed of sound.
Hope this helps, and have a great day!
An plane covers 50 miles in 1/5 of an hour. How many miles can the plane cover in 5 hours
Answer: 1250 miles
Step-by-step explanation:
50 miles in 1/5 of an hour = 250 miles in 1 hour = 1250 miles in 5 hours
Answer:
1,250
Step-by-step explanation:
50 divided by 1/5 equals 250.
Multiply 250 by 5.
250*5= 1,250
Use the multiplication method to increase £88 by 14%
To increase £88 by 14%, we can use the multiplication method, which involves multiplying the original amount by the decimal equivalent of the percentage increase.
The multiplication method is a mathematical technique used to solve problems involving multiplication. It involves breaking down numbers into their constituent parts and then multiplying those parts together to arrive at the final answer.
To find the decimal equivalent of 14%, we divide the percentage by 100:
14% ÷ 100 = 0.14
This tells us that a 14% increase is equivalent to multiplying the original amount by 1.14 (1 + 0.14).
To increase £88 by 14%, we can multiply it by 1.14:
£88 x 1.14 = £100.32
Therefore, the increased amount is £100.32.
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Thank you for the help!
Using the volume formula it is obtained that the least number of bags Martin should buy is Option C: 13.
What is volume?
Each thing in three dimensions takes up some space. The volume of this area is what is being measured. The space occupied within an object's borders in three dimensions is referred to as its volume. It is sometimes referred to as the object's capacity.
First, we need to convert the height of the cylinder from inches to feet -
6 inches = 6/12 feet = 0.5 feet
The volume of the cylinder can be calculated as -
V = πr²h
where r is the radius and h is the height.
Substituting the given values, we get -
V = 3.14 x 2² x 0.5
V = 6.28 cubic feet
Since each bag contains 0.5 cubic feet of sand, we can find the number of bags needed by dividing the total volume by the volume of each bag -
n = V / 0.5
n = 6.28 / 0.5
n = 12.56
Since we can't buy a fractional number of bags, we must round up to the nearest whole number.
Therefore, Martin needs to buy at least 13 bags of sand.
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5. A-postage box should weigh 1.0 pound. If there is a 5% error on the weight, what is the range of acceptable weight ?
Answer:
0.95P - 1.05P
Step-by-step explanation:
Calculate the error
5% of 1.0 Pound
5/100 x 1.0 = 5/100
1/20 = 0.05
The error is + or - 0.05
If you add 0.05 to 1.0Pound, you get 1.05P
If you Subract 0.05 to 1.0Poumd, you get 0.95Pound
The weight will be between 0.95Pound and 1.05 Pound
setting up squares of known dimension over the entire pattern describes what method of documentation?
The method of documentation that describes the setting up of squares of known dimension over the entire pattern is known as grid method.
Grid method is a method of documentation that involves the setting up of squares of known dimensions over the entire pattern to document a site. This method is commonly used in archaeological surveys and historical preservation.
Grids are used to help maintain a sense of orientation and scale in the documentation process, and they provide a reference point for mapping and recording data. Grids can be set up on maps or site plans, as well as on the ground using physical markers such as stakes or string.Grids can also be used to help facilitate excavation by allowing archaeologists to isolate specific areas of a site and keep track of their findings in a consistent and organized manner.Therefore, grid method is a simple and effective way of recording data, and it is still widely used in the field of archaeology today.
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The associative property works with expressions that use
A
division and subtraction. B
addition and subtraction. C
multiplication and division. D
multiplication and addition
The associative property works with expressions that use multiplication and addition. The correct option is (D).
The associative property is a rule in mathematics that allows us to change the grouping of the numbers or variables in an expression without changing the result. This property only applies to addition and multiplication, and not to subtraction and division.
The associative property of addition tells us that we can add a group of numbers in any order, and the result will be the same. For example, (2 + 3) + 4 is the same as 2 + (3 + 4). The associative property of multiplication tells us that we can multiply a group of numbers in any order, and the result will be the same. For example, (2 × 3) × 4 is the same as 2 × (3 × 4).
However, the associative property does not work with subtraction and division. For example, (10 - 3) - 2 is not the same as 10 - (3 - 2). Similarly, (12 ÷ 2) ÷ 3 is not the same as 12 ÷ (2 ÷ 3). Therefore, the correct answer to the question is D - the associative property works with expressions that use multiplication and addition.
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help me, please I will give 30 points
We can solve the system by elimination without multiplying first only when, [tex]$a = 8$[/tex].
How to solve the system by elimination?To solve the system by elimination, we want to eliminate one of the variables, either x or y, from one of the equations. To do this, we need to find a multiple of one equation that cancels out one of the variables in the other equation.
We can eliminate x by multiplying the first equation by -4 and adding it to the second equation:
[tex]-4(ax+3y) + (4x+5y) &=\\ -4(7) + 15\(-4a+4)x + (5-12)y &=\\ -13\ (4-4a)x - 7y &= -13[/tex]
By adding the first equation to the second equation and multiplying it by -4, we can get rid of x:
[tex](4-4a)x-7y=13\\4x+5y=15[/tex]
We can eliminate y by multiplying the second equation by 7 and subtracting it from the first equation:
[tex](4-4a)x - 7y &=\\ -13-28x - 35y &=\\ -105[/tex]
Simplifying this last equation, we get:
[tex](4a-4)x &= 28x\\4a &= 32\\a &= 8[/tex]
Therefore, we can solve the system by elimination without multiplying first only when, [tex]$a = 8$[/tex].
For any other value of a, we need to multiply one or both equations by a constant before we can eliminate a variable.
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