Emma opens a savings account with $100. She saves $60 per month. The equation T(n) = 60n + 100 can be used to represent this problem, where T(n) is Emma's total savings in dollars and n, represents the number of months. Question 1 (2 points) Which term in the equation is fixed? What does the fixed term represent in the context of the problem?

Answers

Answer 1

Answer:

The fixed term is the y-intercept. In this case the y-intercept would be 100.

Step-by-step explanation:

This is because the 100 dollars cannot be changed. You can always change the amount you save per month and the amount of months you save.


Related Questions

Find m2ABC.
PLZZZ ASAPPPP

Answers

Answer:

83

Step-by-step explanation:

You're given two vertical angles, and vertical angles are congruent. This means that (6x - 7) = (4x + 23); x = 15. Plug it into ABC (which is (6x - 7)) to get 6(15) - 7 = 90 - 7 = 83

Which statements are true regarding the system of equations? Check all that apply. 8 x + 10 y = 30. 12 x + 15 y = 60. The lines coincide. The lines are parallel. The slopes are equal. The y-intercepts are different. The system has one solution. The system has an infinite number of solutions. The system has no solution. Mark this and return

Answers

Answer: The lines are parallel.

The slopes are equal.

The y-intercepts are different.

The system has no solution.

Step-by-step explanation:

For  a pair of equations: [tex]a_1x+b_1y=c_1\\\\a_2x+b_2y=c_2[/tex]

They coincide if [tex]\dfrac{a_1}{a_2}=\dfrac{b_1}{b_2}=\dfrac{c_1}{c_2}[/tex]

They are parallel if [tex]\dfrac{a_1}{a_2}=\dfrac{b_1}{b_2}\neq\dfrac{c_1}{c_2}[/tex]

They intersect if [tex]\dfrac{a_1}{a_2}\neq\dfrac{b_1}{b_2}[/tex]

Given equations: [tex]8 x + 10 y = 30\\ 12 x + 15 y = 60[/tex]

Here,

[tex]\dfrac{a_1}{a_2}=\dfrac{8}{12}=\dfrac{2}{3}\\\\ \dfrac{b_1}{b_2}=\dfrac{10}{15}=\dfrac{2}{3}\\\\ \dfrac{c_1}{c_2}=\dfrac{30}{60}=\dfrac{1}{2}[/tex]

⇒[tex]\dfrac{a_1}{a_2}=\dfrac{b_1}{b_2}\neq\dfrac{c_1}{c_2}[/tex]  

Hence, The lines are parallel.

It has no solution. [parallel lines have no solution]

Write 8 x + 10 y = 30 in the form of y= mx+c, where m is slope and c is the y-intercept.

[tex]y=-\dfrac{8}{10}x+\dfrac{30}{10}\Rightarrow\ y=-0.8x+3[/tex]

i.e. slope of 8 x + 10 y = 30 is -0.8 and y-intercept =3

Write  12 x + 15 y = 60 in the form of y= mx+c, where m is slope

[tex]y=-\dfrac{12}{15}x+\dfrac{60}{15}\Rightarrow\ y=-0.8x+4[/tex]

i.e. slope of  12 x + 15 y = 60 is -0.8 and y-intercept =4

i.e. The slopes are equal but y-intercepts are different.

Answer: The lines are parallel.

The slopes are equal.

The y-intercepts are different.

The system has no solution.

Step-by-step explanation:

For  a pair of equations:  

They coincide if  

They are parallel if  

They intersect if  

Given equations:  

Here,

⇒  

Hence, The lines are parallel.

It has no solution. [parallel lines have no solution]

Write 8 x + 10 y = 30 in the form of y= mx+c, where m is slope and c is the y-intercept.

i.e. slope of 8 x + 10 y = 30 is -0.8 and y-intercept =3

Write  12 x + 15 y = 60 in the form of y= mx+c, where m is slope

i.e. slope of  12 x + 15 y = 60 is -0.8 and y-intercept =4

i.e. The slopes are equal but y-intercepts are different.

The confidence interval for the water consumption of a certain plant is 5 gallons to 13 gallons per year. The level of confidence is 95%. What is the average consumption and the margin of error?

Answers

Answer:

Average consumption ( mean )  =  9

MOE = 4

Step-by-step explanation:

We know that

CI   ( 5  ;  13 )

and   CI [ μ - MOE  ;  μ + MOE ]

From the above relations we get

μ - MOE = 5

μ + MOE = 13

Adding member to member these two equations we get

2*μ  =  18

μ = 9    and MOE = 13 - 9

MOE = 4

Solve for x using the Quadratic Formula: x2 + 2x + 1 = 0 x equals negative b plus or minus the square root of b squared minus 4 times a times c, all over 2 times a
x = 2
x = 1
x = 0
x = −1

Answers

Answer:

x = - 1

Step-by-step explanation:

x² + 2x + 1 = 0

Using the quadratic formula

[tex]x = \frac{ - b± \sqrt{ {b}^{2} - 4ac } }{2a} [/tex]

a = 1 , b = 2 , c = 1

We have

[tex]x = \frac{ - 2± \sqrt{ {2}^{2} - 4(1)(1)} }{2(1)} \\ \\ x = \frac{ - 2 ± \sqrt{4 - 4} }{2} \\ \\ x = \frac{ - 2 ± \sqrt{0} }{2} \\ \\ x = - \frac{2}{2} \\ \\ x = - 1[/tex]

Hope this helps you

X=-1

You can factor this because it is already a perfect square. you can check this by seeing if half of b squared is equal to c.

In this problem
a=1
b=2
c=1
Half of b is 1
1 squared is 1

After that you just break it down

There’s 2 x so,

(x+_)(x+_)
The blank is just half of b which we already found to be 1

So,
(x+1)(x+1)

Also can be written as (x+1)^2

Set both parenthesis equal to 0
(In this case you only have to do it once since it’s the same value)

x+1=0
x=-1

Another way to factor is to see if there are two numbers that result in c when multiplied and result in b when added.
In this case it’s 1 and 1
So you just factor out the x and the ones

(x+1)(x+1)
Which will give you the same answer.

(If you get used to factoring, it’s quicker to use)

X=-1

Enter the correct answer in the box. What is the standard form of function

Answers

Answer:

f(x) = 4x² + 48x + 149

Step-by-step explanation:

Given

f(x) = 4(x + 6)² + 5 ← expand (x + 6)² using FOIL

     = 4(x² + 12x + 36) + 5 ← distribute parenthesis by 4

     = 4x² + 48x + 144 + 5 ← collect like terms

     = 4x² + 48x + 149 ← in standard form

Answer:

[tex]f(x)=4x^{2} +149[/tex]

Step-by-step explanation:

Start off by writing the equation out as it is given:

[tex]f(x)=4(x+6)^{2} +5[/tex]

Then, get handle to exponent and distribution of the 4 outside the parenthesis:

[tex]f(x)=4(x^{2} +36)+5\\f(x)=4x^{2} +144+5[/tex]

Finally, combine any like terms:

[tex]f(x)=4x^{2} +149[/tex]

Below given are the details of transaction of a bank account of three brother Ram, Rahul and Rohit having AED 1000 in each account. a. Ram – Credits AED 500 on 12th May 2020 b. Rahul – Debits AED 700 on 12th May 2020 and Credits AED 500 on 15th May 2020. c. Rohit – Credits AED 700 on 12th May 2002 and Debits AED 500 on 15th May 2020. Who has more amount in his account at the end of the month Arrange the amounts in ascend

Answers

Answer:

Ram therefore has more amount in his account at the end of the month, and the balances in their bank accounts at the end of the month are arranged in ascending order, i.e. from the smallest to the largest, as follows:

Rahul – Debits AED 200; Rohit – Credits AED 200; and Ram – Credits AED 500.

Step-by-step explanation:

In banking and finance, a credit transaction on a bank account indicates that an additional amount of money has been added to the bank account and the balance has increased. This gives a positive balance in the account

On the other hand, a debit transaction on a bank account indicates that an amount of money has been deducted or withdrawn from the bank account and the balance has therefore reduced. This gives a negative balance in the account.

Based on the above, we have:

a. Ram – Credits AED 500 on 12th May 2020

Since there is no any other credit or debit transaction during the month, this implies that Ram still has Credits AED 500 in his account at the end of the month.

The Credits AED 500 indicates that Ram has a positive balance of AED 500 in his account at the end of the month.

b. Rahul – Debits AED 700 on 12th May 2020 and Credits AED 500 on 15th May 2020.

The balance in the account of Rahul gives Debits of AED 200 as follows:

Debits AED 700 - Credits AED 500 = Debits AED 200

The Debits AED 200 indicates that Rahul has a negative balance of AED 200 in his account at the end of the month.

c. Rohit – Credits AED 700 on 12th May 2002 and Debits AED 500 on 15th May 2020.

The balance in the account of Rohit gives Credits of AED 200 as follows:

Credits AED 700 - Dedits AED 500 = Credits AED 200

The Credits AED 200 indicates that Rohit has a positive balance of AED 200 in his account at the end of the month.

Conclusion

Arrangement of numbers or amounts of money in ascending order implies that they are arranged from the smallest to the largest number or amount.

Since Credits implies positive amount and Debits implies negative amount, Ram therefore has more amount in his account at the end of the month, and the balances in their bank accounts at the end of the month are arranged in ascending order, i.e. from the smallest to the largest, as follows:

Rahul – Debits AED 200; Rohit – Credits AED 200; and Ram – Credits AED 500.

The mode of the numbers 1,1,3,3, 5, 6, 6, 6, 7, 8 is​

Answers

Answer:

The mode of the above is 6.

Step-by-step explanation:

Mode-the number that occurs most frequently in a set of numbers.

The six appeared three times being the most.

I really hope this helps.

Type the correct answer in each box. If necessary, use / for the fraction bar. Complete the statements about series A and B. Series A: 10+4+8/5+16/25+32/125+⋯ Series B: 15+3/5+9/5+27/5+81/5+⋯ Series__ has an r value of___where 0<|r|<1. So, we can find the sum of the series. The sum of the series is___ need help guys please :/

Answers

Answer:

Series A has an r value of 2/5 and series A has an r value of 3. The sum of the series A is 50/3

Step-by-step explanation:

A geometric sequence is in the form a, ar, ar², ar³, .  .   .

Where a is the first term and r is the common ratio = [tex]\frac{a_{n+1}}{a_n}[/tex]

For series A:  10+4+8/5+16/25+32/125+⋯   The common ratio r is given as:

[tex]r=\frac{a_{n+1}}{a_n}=\frac{4}{10} =\frac{2}{5}[/tex]

For series B: 1/5+3/5+9/5+27/5+81/5+⋯   The common ratio r is given as:

[tex]r=\frac{a_{n+1}}{a_n}=\frac{3/5}{1/5} =3[/tex]

For series A a = 10, r = 2/5, which mean 0 < r < 1, the sum of the series is given as:

[tex]S_{\infty}=\frac{a}{1-r}=\frac{10}{1-\frac{2}{5} } =\frac{50}{3}[/tex]

Please answer it now in two minutes

Answers

Answer:  3.2 yd

Step-by-step explanation:

Notice that TWV is a right triangle.  

Segment TU is not needed to answer this question.

∠V = 32°, opposite side (TW) is unknown, hypotenuse (TV) = 6

[tex]\sin \theta=\dfrac{opposite}{hypotenuse}\\\\\\\sin 32=\dfrac{\overline{TW}}{6}\\\\\\6\sin 32=\overline{TW}\\\\\\\large\boxed{3.2=\overline{TW}}[/tex]

[tex]Let $u$ and $v$ be the solutions to $3x^2 + 5x + 7 = 0.$ Find\[\frac{u}{v} + \frac{v}{u}.\][/tex]

Answers

By the factor theorem,

[tex]3x^2+5x+7=3(x-u)(x-v)\implies\begin{cases}uv=\frac73\\u+v=-\frac53\end{cases}[/tex]

Now,

[tex](u+v)^2=u^2+2uv+v^2=\left(-\dfrac53\right)^2=\dfrac{25}9[/tex]

[tex]\implies u^2+v^2=\dfrac{25}9-\dfrac{14}3=-\dfrac{17}9[/tex]

So we have

[tex]\dfrac uv+\dfrac vu=\dfrac{u^2+v^2}{uv}=\dfrac{-\frac{17}9}{\frac73}=\boxed{-\dfrac{17}{21}}[/tex]

The value of [tex]\frac{u}{v} +\frac{v}{u}[/tex] is [tex]\frac{-17}{21}[/tex].

What is quadratic equation?

A quadratic equation is an algebraic equation of the second degree in x. The quadratic equation in its standard form is[tex]ax^{2} +bx+c=0[/tex], where a and b are the coefficients, x is the variable, and c is the constant term.

What is the sum and product of the roots of the quadratic equation?

If [tex]ax^{2} +bx+c = 0[/tex] be the quadratic equation then

Sum of the roots = [tex]\frac{-b}{a}[/tex]

And,

Product of the roots = [tex]\frac{c}{a}[/tex]

According to the given question.

We have a quadratic equation [tex]3x^{2} +5x+7=0..(i)[/tex]

On comparing the above quadratic equation with standard equation or general equation [tex]ax^{2} +bx+c = 0[/tex].

We get

[tex]a = 3\\b = 5\\and\\c = 7[/tex]

Also, u and v are the solutions of the quadratic equation.

⇒ u and v are the roots of the given quadratic equation.

Since, we know that the sum of the roots of the quadratic equation is [tex]-\frac{b}{a}[/tex].

And product of the roots of the quadratic equation is [tex]\frac{c}{a}[/tex].

Therefore,

[tex]u +v = \frac{-5}{3}[/tex] ...(ii) (sum of the roots)

[tex]uv=\frac{7}{3}[/tex]   ....(iii)       (product of the roots)

Now,

[tex]\frac{u}{v} +\frac{v}{u} = \frac{u^{2} +v^{2} }{uv} = \frac{(u+v)^{2}-2uv }{uv}[/tex]                    ([tex](a+b)^{2} =a^{2} +b^{2} +2ab[/tex])

Therefore,

[tex]\frac{u}{v} +\frac{v}{u} =\frac{(\frac{-5}{3} )^{2}-2(\frac{7}{3} ) }{\frac{7}{3} }[/tex]         (from (i) and (ii))

⇒ [tex]\frac{u}{v} +\frac{v}{u} =\frac{\frac{25}{9}-\frac{14}{3} }{\frac{7}{3} }[/tex]

⇒ [tex]\frac{u}{v} +\frac{v}{u} = \frac{\frac{25-42}{9} }{\frac{7}{3} }[/tex]

⇒ [tex]\frac{u}{v} +\frac{v}{u} = \frac{\frac{-17}{9} }{\frac{7}{3} }[/tex]

⇒ [tex]\frac{u}{v} +\frac{v}{u} =\frac{-17}{21}[/tex]

Therefore, the value of [tex]\frac{u}{v} +\frac{v}{u}[/tex] is [tex]\frac{-17}{21}[/tex].

Find out more information about sum and product of the roots of the quadratic equation here:

https://brainly.com/question/14266582

#SPJ3

Jane wants to estimate the proportion of students on her campus who eat cauliflower. After surveying 24 ​students, she finds 2 who eat cauliflower. Obtain and interpret a 95​% confidence interval for the proportion of students who eat cauliflower on​ Jane's campus using Agresti and​ Coull's method.
Construct and interpret the 95​% confidence interval. Select the correct choice below and fill in the answer boxes within your choice.
​(Round to three decimal places as​ needed.)
A. The proportion of students who eat cauliflower on​ Jane's campus is between___ and __ 95​% of the time.
B.There is a 95​% chance that the proportion of students who eat cauliflower in​ Jane's sample is between __ and __.
C. There is a 95​% chance that the proportion of students who eat cauliflower on​ Jane's campus is between __ and__.
D. One is 95​% confident that the proportion of students who eat cauliflower on​ Jane's campus is between __ and __.

Answers

Answer:

A 95​% confidence interval for the proportion of students who eat cauliflower on​ Jane's campus is [0.012, 0.270].

Step-by-step explanation:

We are given that Jane wants to estimate the proportion of students on her campus who eat cauliflower. After surveying 24 ​students, she finds 2 who eat cauliflower.

Firstly, the pivotal quantity for finding the confidence interval for the population proportion is given by;

                              P.Q.  =  [tex]\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex]  ~ N(0,1)

where, [tex]\hat p[/tex] = sample proportion of students who eat cauliflower

           n = sample of students

           p = population proportion of students who eat cauliflower

Here for constructing a 95% confidence interval we have used a One-sample z-test for proportions.

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level

                                                   of significance are -1.96 & 1.96}  

P(-1.96 < [tex]\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] < 1.96) = 0.95

P( [tex]-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] < [tex]{\hat p-p}[/tex] < [tex]1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] ) = 0.95

P( [tex]\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] < p < [tex]\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] ) = 0.95

Now, in Agresti and​ Coull's method; the sample size and the sample proportion is calculated as;

[tex]n = n + Z^{2}__(\frac{_\alpha}{2})[/tex]

n = [tex]24 + 1.96^{2}[/tex] = 27.842

[tex]\hat p = \frac{x+\frac{Z^{2}__(\frac{\alpha}{2}_) }{2} }{n}[/tex] = [tex]\hat p = \frac{2+\frac{1.96^{2} }{2} }{27.842}[/tex] = 0.141

95% confidence interval for p = [ [tex]\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] , [tex]\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] ]

 = [ [tex]0.141 -1.96 \times {\sqrt{\frac{0.141(1-0.141)}{27.842} } }[/tex] , [tex]0.141 +1.96 \times {\sqrt{\frac{0.141(1-0.141)}{27.842} } }[/tex] ]

 = [0.012, 0.270]

Therefore, a 95​% confidence interval for the proportion of students who eat cauliflower on​ Jane's campus [0.012, 0.270].

The interpretation of the above confidence interval is that we are 95​% confident that the proportion of students who eat cauliflower on​ Jane's campus is between 0.012 and 0.270.

I WILL MARK THE BRAINLIEST! please help me

There are 200 students in 8th grade. There are 3 different elective classes. All 8th grade students must take at least one elective.
- 35 total students are in drama
- 75 total students are in cooking
- 15 students are in both drama and P.E
-10 Students are in drama and cooking
- 5 students are in P.E and cooking
- 8 students are in all three electives
How many students are in P.E?
How many are ONLY in P.E?
Please answer both questions in two sentences.

Answers

Answer:

How many students are in P.E? 90

How many are ONLY in P.E? 62

Step-by-step explanation:

How many students are in P.E?

200 students in 8th grade.

35=drama

75=cooking

200-110=90=PE.

How many are ONLY in P.E?

Within 90 students, 15 is also in drama, with 5 is also in cooking, and 8 is in all of 3. =28.

90-28=62

Hope this helps!

Find the measure of angle A associated with the following ratios and round to the nearest degree. CosA=0.2785 m∠A=

Answers

Answer:

74°.

Step-by-step explanation:

From the question given above,

Cos A = 0.2785

To get the value of angle A, we simply find the inverse of Cos as shown below:

Cos A = 0.2785

Take the inverse of Cos.

A = Cos¯¹ 0.2785

A = 73.8° ≈ 74°

Therefore, the value of angle A is approximately 74°

Select the correct answer.
Write (21 − 4i) − (16 + 7i) + 28i as a complex number in standard form.

A.
5 + 39i
B.
5 + 17i
C.
5 − 39i
D.
5 − 17i

Answers

Answer:

B) 5 + 17i is your answer.

Step-by-step explanation:

In order to write this equation as a complex number in standard form, you must first simplify each term.

Apple the distributive property.

21 - 4i - 1 * 16 - (7i) + 28i

Multiply -1 by 16.

21 - 4i -16 - (7i) + 28i

Multiply 7 by -1.

21 - 4i - 16 - 7i + 28i

Now simplify by adding terms :)

Subtract 16 from 21.

5 - 4i - 7i + 28i

Subtract 7i from -4i.

5 - 11i + 28i

Add -11i and 28i.

= 5 + 17i

Instructions: Find the missing side. Round your answer to the
nearest tenth

Answers

Answer:

x = 50°

Step-by-step explanation:

To find x we use cosine

cos ∅ = adjacent / hypotenuse

From the question

The hypotenuse is x

The adjacent is 18

So we have

cos 69 = 18/x

x cos 69 = 18

Divide both sides by cos 69

x = 18/cos 69

x = 50.2

x = 50° to the nearest tenth

Hope this helps you

Which shows the rational expression written using the least common denominator?
x+1/4x^2 + x+1/x^2

A) x+1/4x^2 + 4(x+1)/4x^2
B) x+1/x^2 + x+1/x^2
C) x+1/x^2 + 4(x+1)/x^2
D) x+1/4x^2 + x+1/4x^2

Answers

Answer:

(x + 1)/4x² + 4(x + 1)/4x²

Step-by-step explanation:

x+1/4x² + x+1/x²

The above can be simply as follow:

Find the least common multiple (LCM) of 4x² and x². The result is 4x²

Now Divide the LCM by the denominator of each term and multiply the result with the numerator as show below:

(4x² ÷ 4x²) × (x + 1) = x + 1

(4x² ÷ x²) × (x + 1) = 4(x + 1)

x+1/4x² + x+1/x² = [(x + 1) + 4(x + 1)]/ 4x²

= (x + 1)/4x² + 4(x + 1)/4x²

Therefore,

x+1/4x² + x+1/x² = (x + 1)/4x² + 4(x + 1)/4x²

Answer: A

Step-by-step explanation:

Can someone help me on this finance problem?

Answers

The answer is x= 2400
And y= 1600

All the step by step is below

A plane started on a flight at 9:30 a.m and arrived at its destination at 1:45pm. The plane used 51 gallons of gas. The number of gallons used per hour was
Will mark Brainlist

Answers

Answer:

12 gallons per hour

Step-by-step explanation:

Given the following :

Start time of flight = 9:30 a.m

Arrival time of flight = 1:45p.m

Gallons of gas used during duration of flight = 51 gallons

Number of hours spent during flight:

Arrival time - start time

1:45 pm - 9:30 am = 4hours and 15minutes

4hours 15minutes = 4.25hours

If 4.25hours requires 51 gallons of gas;

Then 1 hour will require ( 51 / 4.25)gallons

= 51 / 4.25

= 12 gallons

Which sum or difference is modeled by the algebra tiles?

Answers

Answer:

(C)[tex]x^2+4x-2-(-x^2+2x-4)=2x^2+2x+2[/tex]

Step-by-step explanation:

The expression represented by the upper tiles is: [tex]x^2+4x-2[/tex]

The expression represented by the lower tiles is: [tex]x^2-2x+4[/tex]

Adding the two

[tex]x^2+4x-2+(x^2-2x+4)=2x^2+2x+2[/tex]

Writing it as a difference, we have:

[tex]x^2+4x-2-(-x^2+2x-4)=2x^2+2x+2[/tex]

The correct option is C.

Answer:

yeah, what newton said :]

Two angles form a linear pair. The measure of one angle is x and the measure of the other angle is 1.4 times x plus 12∘ . Find the measure of each angle.

Answers

Answer:

70° and 110°

Step-by-step explanation:

If two angles forms a linear pair, this means that the sum of the angles is 180°. If the measure of one angle is x and the measure of the other angle is 1.4 times x plus 12∘

Let A be the first angle = x°

Let B be the second angle = (1.4x+12)°

Since they form a linear pair, then

A+B = 180°

x + 1.4x+12 = 180°

2.4x = 180-12

2.4x = 168

x = 168/2.4

x = 70°

The measure of angle A = 70°

The measure if angle B = 1.4x+12

B = 1.4(70)+12

B = 98+12

B = 110°

The measure of both angles are 70° and 110°

can anyone help me with this ?

Answers

Answer: x=35

Step-by-step explanation:

There are 720 degrees total in a hexagon. So, all of the angles should add up to that. Write out the equation

720= (4x-5)+(117)+(3x-3)+(3x+6)+(118)+(4x-3)

720=14x+230

490=14x

x=35

hope this helped you:)

Find the product.

(5ab3b) (2ab)

PLEASE HELP!!! ASAP!!!

Answers

Answer:

10a²b²6ab²

Step-by-step explanation:

Distribute the 2ab the other values

If cos0=-3/5 in quadrant II, what is sin0

Answers

Answer:

[tex]\displaystyle \sin \theta = \frac{4}{5}[/tex] if [tex]\displaystyle \cos\theta = -\frac{3}{5}[/tex] and [tex]\theta[/tex] is in the second quadrant.

Step-by-step explanation:

By the Pythagorean Trigonometric Identity:

[tex]\left(\sin \theta\right)^2 + \left(\cos\theta)^2 = 1[/tex] for all real [tex]\theta[/tex] values.

In this question:

[tex]\displaystyle \left(\cos\theta\right)^2 = \left(-\frac{3}{5}\right)^2 = \frac{9}{25}[/tex].

Therefore:

[tex]\begin{aligned} \left(\sin\theta\right)^2 &= 1 -\left(\cos\theta\right)^2 \\ &= 1 - \left(\frac{3}{5}\right)^2 = \frac{16}{25}\end{aligned}[/tex].

Note, that depending on [tex]\theta[/tex], the sign [tex]\sin \theta[/tex] can either be positive or negative. The sine of any angles above the [tex]x[/tex] axis should be positive. That region includes the first quadrant, the positive [tex]y[/tex]-axis, and the second quadrant.

According to this question, the [tex]\theta[/tex] here is in the second quadrant of the cartesian plane, which is indeed above the [tex]x[/tex]-axis. As a result, the sine of this

It was already found (using the Pythagorean Trigonometric Identity) that:

[tex]\displaystyle \left(\sin\theta\right)^2 = \frac{16}{25}[/tex].

Take the positive square root of both sides to find the value of [tex]\sin \theta[/tex]:

[tex]\displaystyle \sin\theta =\sqrt{\frac{16}{25}} = \frac{4}{5}[/tex].

BRAINLEST Use the function f(x) = 2x^2 − 5x + 3 to answer the questions. Part A: Completely factor f(x). Part B: What are the x-intercepts of the graph of f(x)? Show your work.

Answers

Answer:

answer pic below :)

Step-by-step explanation:

On a coordinate plane, kite K L M N is shown. Point K is at (5, 3), point L is at (3, 2), point M is at (2, 3), and point N is at (3, 4). What is the perimeter of kite KLMN? StartRoot 2 EndRoot + StartRoot 5 EndRoot units StartRoot 14 EndRoot units 2 StartRoot 2 EndRoot + 2 StartRoot 5 EndRoot units 4 StartRoot 5 EndRoot units HELP PLEASE

Answers

Answer:

[tex]2\sqrt{2} +2\sqrt{5}[/tex]

Step-by-step explanation:

i just got this one right

the kite has two pairs of congruent sides. using the distance formula, the two shorter sides=[tex]\sqrt{2}[/tex] (since there are two of those length sides, you multiply it by two). Again with the distance formula, the two longer sides=[tex]\sqrt{5}[/tex] (also multiply this by two).this gives the answer c or [tex]2\sqrt{2}+2\sqrt{5}[/tex]

Answer:

The answer is c [tex]\sqrt[2]{2}[/tex] + [tex]\sqrt[2]{5}[/tex] units. just took the test

Step-by-step explanation:

Consider the equations:
y=15x-45
y=12x+18
How many solutions do they have?

Answers

Answer: One solution

Explanation:

Because the two equation has a different slope and different y intercept

Answer:

1

Step-by-step explanation:

Both equations are linear, and they do not have an equivalent slope, therefore they MUST intercept each other once and only once.

Which of the following is not a rigid motion transformation?

Answers

Answer:

D. Stretch

Step-by-step explanation:

All the others keep the same dimensions

The one which is not a rigid motion transformation is D. Stretch.

What is Geometric Transformation?

Transformation of geometrical figures or points is the manipulation of a given figure to some other way.

Different types of transformations are Rotation, Reflection, Glide reflection, Translation and Dilation.

Rigid motion transformation is the transformation which is formed when a point or a shape is transformed such that the size or the shape of the original object does not change.

In rotation, translation and reflection, there is no change in the size or the shape.

But in dilation, the size becomes smaller or larger based on it is enlargement or stretch.

So stretch is not a rigid motion transformation.

Hence option D is the correct answer.

Learn more about Rigid Motion Transformation here :

https://brainly.com/question/1408127

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Write as an equation: Alice, Barbara, and Carol are sisters. Alice is 3 years younger than Barbara, and Barbara is 5 years younger than Carol. Together the sisters are 68 years old. How old is Barbara? (Let b = Barbara)

Answers

a+b+c=68

b-3=a

c-5=b

now just solve the system of equations, substitue so that there are only b's in the equation:

a+b+c=68

(b-3) + b + (b+5) = 68

3b=66

b=22

Therefore Barbara is 22

The required age of barbar is 22 years.

Alice, Barbara, and Carol are sisters. Alice is 3 years younger than Barbara, and Barbara is 5 years younger than Carol. Together the sisters are 68 years old.  How old is Barbara to be determined.

What is arithmetic?

In mathematics, it deals with numbers of operations according to the statements.

Let the age of Alice, Barbara and Carol are a, b and c.

Age Alice is 3 years younger than Barbara,

a = b - 3     - - - -(1)

Age Barbara is 5 years younger than Carol

b = c - 5

c = b + 5     - - - -(2)

Together the sisters are 68 years old i.e.

a + b +c =68

From equation 1 and 2

b - 3 + b + b +5 = 68

3b + 2 = 68

3b = 66

b  = 33

Thus, the required age of barbar is 22 years.

Learn more about arithmetic here:

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ASAP! I really need help with this question! Please do not send nonsense answers. Full solutions please!

Answers

Answer:

first option

Step-by-step explanation:

Given

[tex]\frac{15}{x}[/tex] + 6 = [tex]\frac{9}{x^2}[/tex]

Multiply through by x² to clear the fractions

15x + 6x² = 9 ( subtract 9 from both sides )

6x² + 15x - 9 = 0 ( divide through by 3 )

2x² + 5x - 3 = 0 ← in standard form

Consider the factors of the product of the coefficient of x² and the constant term which sum to give the coefficient of the x- term.

product = 2 × - 3 = - 6 and sum = + 5

The factors are + 6 and - 1

Use these factors to slit the x- term

2x² + 6x - x - 3 = 0 ( factor the first/second and third/fourth terms )

2x(x + 3) - 1(x + 3) = 0 ← factor out (x + 3) from each term

(x + 3)(2x - 1) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 3 = 0 ⇒ x = - 3

2x - 1 = 0 ⇒ 2x = 1 ⇒ x = 0.5

Solution set is { - 3, 0.5 }

Golden Corral charges $11 for a buffet plus $1 for each drink. Western Sizzlin charges $9 for a buffet plus $2 for each drink. Which restaurant has the best deal? Verify that the intersection point show in your graph is a solution for both equations

Answers

Answer:

At 2 drinks, the prices are equal. For 1 drink, Western Sizzlin is better since the buffet price is lower. From 3 drinks and up, Golden Corral is better.

Step-by-step explanation:

"Golden Corral charges $11 for a buffet plus $1 for each drink."

d + 11

"Western Sizzlin charges $9 for a buffet plus $2 for each drink."

2d + 9

Set the 2 cost functions equal:

2d + 9 = d + 11

d = 2

At 2 drinks, the prices are equal. For 1 drink, Western Sizzlin is better since the buffet price is lower. From 3 drinks and up, Golden Corral is better.

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