Answer:
Endothermic
Exothermic
Endothermic
Exothermic
Exothermic
Exothermic
Explanation:
Endothermic is when a reaction absorbs heat.
Exothermic is when a reaction releases heat.
Endothermic reactions:
The reaction between
ammonium nitrate and
water absorbs heat
from the surrounding
environment.
Ammonium chloride dissolved
in a beaker of water makes the
beaker cold.
Water separates into
hydrogen and oxygen
when an electric current
is run through it.
Exothermic reactions:
Three drops of concentrated
sulfuric acid added to 100
milliliters of water in a beaker
makes the beaker hot.
Uranium atoms are split to
produce nuclear energy.
Methane and oxygen are
combined to produce
methanol and heat.
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does anyone know how to do question nine if can you please show working out. thanks.
Answer:
A. 257600g (i.e 257.6 Kg) of CaO were produced.
B. 202400g (i.e 202.4 Kg) of CO2 were produced.
Explanation:
We'll begin by calculating the mass of CaCO3 present in 5×10² Kg of lime stone. This is illustrated below:
From the question given, the lime stone contains 92% of CaCO3.
Mass of CaCO3 = 92% x 5×10² Kg
Mass of CaCO3 = 92/100 x 5×10² Kg
Mass of CaCO3 = 460 Kg
Therefore, 460 kg of CaCO3 is present in the lime stone.
Next, we shall determine the mass of CaCO3 that was heated and the masses of CaO and CO2 produced from the balanced equation. This is illustrated below:
CaCO3(s) —> CaO(s) + CO2(g)
Molar mass of CaCO3 = 40 + 12 + (16x3) = 100g/mol
Mass of CaCO3 from the balanced equation = 1 x 100 = 100g
Molar mass of CaO = 40 + 16 = 56g
Mass of CaO from the balanced equation = 1 x 56 = 56g
Molar mass of CO2 = 12 + (2x16) = 44g/mol
Mass of CO2 from the balanced equation = 1 x 44 = 44g
Summary:
From the balanced equation above,
100g of CaCO3 were heated to produce 56g of CaO and 44g of CO2.
A. Determination of the mass of quick lime, CaO produced by heating 5×10² Kg of lime stone.
5×10² Kg of lime stone contains 460 Kg (i.e 460×10³ g) of CaCO3.
From the balanced equation above,
100g of CaCO3 were heated to produce 56g of CaO.
Therefore, 460×10³g of CaCO3 will be heated to produce = (460×10³ x 56)/100 = 257600g of CaO.
Therefore, 257600g (i.e 257.6 Kg) of CaO were produced.
B. Determination of mass of carbon dioxide, CO2 produced by heating 5×10² Kg of lime stone.
5×10² Kg of lime stone contains 460 Kg (i.e 460×10³ g) of CaCO3.
From the balanced equation above,
100g of CaCO3 were heated to produce 44g of CO2.
Therefore, Therefore, 460×10³g of CaCO3 will be heated to produce = (460×10³ x 44)/100 = 202400g of CO2.
Therefore, 202400g (i.e 202.4 Kg) of CO2 produced.
A 0.4647-g sample of a compound known to contain only carbon, hydrogen, and oxygen was burned in oxygen to yield 0.01962 mol of CO2 and 0.01961 mol of H2O. The empirical formula of the compound was found to be C3H6O2
Answer:
The essence including its given problem is outlined in the following segment on the context..
Explanation:
The given values are:
Moles of CO₂,
x = 0.01962
Moles of water,
[tex]\frac{y}{2} =0.01961[/tex]
[tex]y=2\times 0.01961[/tex]
[tex]=0.03922[/tex]
Compound's mass,
= 0.4647 g
Let the compound's formula will be:
[tex]C_{x}H_{y}O_{z}[/tex]
Combustion's general equation will be:
⇒ [tex]C_{x}H_{y}O_{z}+x+(\frac{y}{4}-\frac{z}{2}) O_{2}=xCO_{2}+\frac{y}{2H_{2}O}[/tex]
On putting the estimated values, we get
⇒ [tex]12\times x=1\times y+16\times z=0.4647[/tex]
⇒ [tex]12\times 0.01962+1\times 0.03922+16\times z=0.4647[/tex]
⇒ [tex]0.27466+16z=0.4647[/tex]
⇒ [tex]z=0.01187[/tex]
Now,
x : y : z = [tex]0.01962:0.03922:0.01187[/tex]
= [tex]\frac{0.01962}{0.0118}:\frac{0.03922}{0.0188}:\frac{0.0188}{0.0188}[/tex]
= [tex]1.6:3.3:1.0[/tex]
= [tex]3:6:2[/tex]
So that the empirical formula seems to be "C₃H₆O₂".
how many atoms are in 2.10 g of K? molar mass of K=39.10g/mole.
Answer:
The answer is option BExplanation:
To calculate the number of atoms we must first calculate the number of moles
Molar mass = mass / number of moles
number of moles = mass / Molar mass
Molar mass (K) = 39.10mole
mass = 2.10g
number of moles = 2.10/ 39.10
= 0.0537mol
After that we use the formula
N = n × L
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10^23 entities
Number of K atoms is
N = 0.0537 × 6.02 × 10^13
N = 3.23×10^22 atoms of KHope this helps you.
Magnesium reacts with fluorine to form magnesium fluoride. Which diagram shows the correct arrangement of electrons in the product?
Answer:
Diagram B shows the correct arrangement of electrons in the product.
Magnesium reacts with fluorine to form magnesium fluoride two electrons of magnesium are transferred to the 2 atoms of fluorine and fluorine is the most electronegative element of the periodic table. Option C is correct.
What is electronegativity?Electronegativity is the tendency or power of an atom to attract the electrons from the metals they are mostly nonmetals and want to complete their octave too.
The most electronegative elements of the periodic table are oxygen, nitrogen, and fluorine, as they are always willing to complete the octave, and fluorine will take electrons from magnesium.
Therefore, Option C is correct if the 2 atoms of fluorine and fluorine are the most electronegative element of the periodic table. Magnesium reacts with fluorine to form magnesium fluoride two electrons of magnesium are transferred.
Learn more about electronegativity, here:
https://brainly.com/question/17762711
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Use enthalpies of formation to determine the ΔHreaction for the reaction
CaCl2(s)---> CaCl2(aq).
Answer:
The enthalpy is increased by the increased heat of the reaction.
Explanation:
In this reaction, as the transition from solid to liquid state, enthalpy increases, that is, the heat applied to change its state is greater and this increases, reaching a mayor disorder.
If the reaction increases its heat, and a liquid state passes, the enthalpy increases, therefore the disorder also and the entropy will also be increased.
What are the periodic trends of ionic radii? Check all that apply. Ionic radii tend to increase down a group. Ionic radii tend to decrease across a period. Anionic radii tend to increase across a period. Cationic radii tend to decrease across a period. Ionic radii increase when switching from cations to anions in a period.
Answer:
What are the periodic trends of ionic radii? Check all that apply.
*Ionic radii tend to increase down a group.
Ionic radii tend to decrease across a period.
Anionic radii tend to increase across a period.
*Cationic radii tend to decrease across a period.
*Ionic radii increase when switching from cations to anions in a period.
Answer:
- Ionic Radii Tend To Increase Down A Group.
- Cationic Radii Tend To Decrease Across A Period.
- Ionic Radii Increase When Switching From Cations To Anions In A Period.
Explanation:
i got it correct on edge
The table lists some organelles and functions. Only one pair is correctly matched. Functions of Organelles Organelle Function Chloroplast Stores water and waste materials Cell wall Supports cell membrane, maintains cell shape, and protects cell Cell membrane Breaks down waste materials and debris Vacuole Produces proteins for the cell Which organelle in the table is correctly matched with its function? chloroplast cell wall cell membrane vacuole plz help soon
The organelle that is matched correctly is the Cell Wall
The cell wall functions as a protective organelle as well as gives shape to the cell.
Functions of the cell wallThe cell wall is an organelle found in prokaryotic cells and plant cells.
Cell walls generally function to protect the cell by delimiting its surroundings the membrane from damage.
They also act as permeable structures to substances as well as give the respective cells their characteristic shapes.
More on cell walls can be found here: https://brainly.com/question/965751