OPTIONS :
A.) the force that the ball exerts on the wall
B.) the frictional force between the wall and the ball
C.) the acceleration of the ball as it approaches the wall
D.) the normal force that the wall exerts on the ball
Answer: D.) the normal force that the wall exerts on the ball
Explanation: The normal force acting on an object can be explained as a force experienced by an object when it comes in contact with a flat surface. The normal force acts perpendicular to the surface of contact.
In the scenario described above, Erica's tennis ball experiences an opposite reaction after hitting the wall.This is in relation to Newton's 3rd law of motion, which states that, For every action, there is an equal and opposite reaction.
The reaction force in this case is the normal force exerted on the ball by the wall perpendicular to the surface of contact.
At which point does the planet have the least gravitational force acting on it?
Answer:
At which point does the planet have the least gravitational force acting on it?
Explanation:
In an elliptical orbit, when a planet is at its furthest point from the Sun, it is under the least amount of gravity, meaning that the force of gravity is strongest when it is closest.
Answer:
Point A
Explanation:
Recall that gravitational force is inversely proportional to the square of the distance between the 2 objects.
This means that the farther away the objects are from each other, the lesser their gravitational interaction will be.
In this case we can see that Point A is furthest away from the star, hence this will be the location with the least gravitational force from the star.
this is a non graded disscussion i want to fill out it is just a worksheet to help me get better 30 points
Answer:
1.) 30m/s
2) 5m/s
3) 40Hz
4) 400Hz
5) 300Hz
6) 0.77m
7) 0.386m
8) 0.625m
9) 100m/s
10) 50m/s
Explanation:
The speed of a wave (V) equals :
V = fλ ; where f = frequency, λ = wavelength
1.) f = 100Hz, λ = 0.30m
v = 100 * 0.30 = 30m/s
2) f = 50Hz λ = 0.10m
v = 50 × 0.10 = 5m/s
3) v = 20m/s, λ= 0.5m
f = v / λ
f = 20 / 0.5 = 40Hz
4) v = 80m/s, λ= 0.2m
f = 80/0.2 = 400Hz
5) v = 120m/s, λ = 0.4m
f = 120 / 0.4 = 300Hz
6) v = 340m/s, f = 440Hz
λ = v / f ; 340 / 440 = 0.77m
7) v = 340m/s, f = 880Hz
λ = 340 / 880 = 0.386m
8) v = 250m/s, f = 400
λ = 250 / 400 = 0.625m
9) f = 50Hz, λ = 2m
v = 50 × 2 = 100m/s
10) f = 100Hz, λ = 0.5m
v = 100 × 0.5 = 50m/s
The lack of ________ between the train and the tracks allow the train to reach unbelievable speed.
Answer:
Friction
Explanation:
Friction is the force that is created when two objects rub against each other. All objects are rough, even though it might not appear that way, on the microscopic scale. These little grooves and ridges get stuck against each other when two objects are moved against each other, and they slow down motion. If there is no friction between a train and its tracks, then it can continue to accelerate without slowing down. Hope this helps!
A camera lens focuses on an object 75.0 cm from the lens. The image forms 3.50 cm behind the lens. What is the magnification of the image?
Answer:
- 0.0466666667
Explanation:
We are told in the question above that:
A camera lens focuses on an object 75.0 cm from the lens. The image forms 3.50 cm behind the lens.
The formula for Magnification of an image = - image distance / object distance
Image distance = 3.50 cm
Object distance = 75 cm
Magnification = - 3.5/75
= -0.0466666667
= Approximately = -0.0467
Therefore, the magnification of the image is -0.0467
Answer:
0.557
Explanation:
That's the answer to a similar problem that asks us to solve for how tall the image is.
if it's 12.4 cm tall
correct for Acellus
This one:
A camera lens focuses on an image 78.0 cm from the lens
The image is 3.5 cm behind the lens
If it's 12.4 cm tall, how tall is the image
hope it helps
What happens to the object if the line crosses the x-axis from the positive portion of a velocity versus time diagram?
Answer:
A velocity time graph shows the change of velocity of an object with respect ot time. If the slope of the graph is increasing in the postive region, it means that the velocity is changing, if the slope is decreasing, it means the the velocity is decreasing, but the object is moving in the same direction (positve direction).
If this slope intersects the graph at x-axis, it means that the body has 0 velocity and has become still. After that, if the line enters in the negative region, it means that its velocity is started to increases again, but the body is movinging in the opposite direction (negative direction)
If an electromagnetic wave has a frequency of 4.5 x 1018 Hz, what is its
wavelength? Use î=”. The speed of light is 3 * 108 m/s.
A. 1.5 x 10-26
B. 6.7 x 1026 m
C. 1.5 x 10-10 m
D. 6.7 * 10-11 m
Answer:
Wavelength of electromagnetic wave = 6.7 × 10⁻¹¹
Explanation:
Given:
Frequency of electromagnetic wave = 4.5 × 10¹⁸ Hz
Speed of light = 3 × 10⁸ m/s
Find:
Wavelength of electromagnetic wave
Computation:
⇒ Wavelength = Speed of light / Frequency
⇒ Wavelength of electromagnetic wave = 3 × 10⁸ / 4.5 × 10¹⁸
⇒ Wavelength of electromagnetic wave = 0.67 × 10⁻¹⁰
Wavelength of electromagnetic wave = 6.7 × 10⁻¹¹
A lens is used to make an image of magnification -1.50. The image is 30.0 cm from the lens. What is the object’s distance (unit=cm)? PLS HELP
Answer: 20cm
Explanation:
Given the following data:
Magnification of image = - 1.50
Distance of image from the lens = 30.0cm
The Magnification of an image is the ratio of the image distance from the lens and the object distance from the lens.
Mathematically,
Magnification(M) = - (image distance (di) / object distance (do))
M = - (di/do)
-1.50 = - (30/do)
do = 30 / 1.5
do = 20 cm
Object is placed at a distance of 20cm from the lens.
How is a voltmeter used in a circuit?
A. It is connected in series and measures current.
B. It is connected in parallel and measures potential difference.
C. It is connected in parallel and measures current.
D. It is connected in series and measures potential difference.
Answer:
Explanation:
A voltmeter is usually connected in parallel with a part of a complete circuit. The meter itself is connected in series to a very high resistance so that the amount of current drained is very tiny.
So you see, you could answer this in two ways, but since you are asking a question at a very beginning level, I think the answer should be
B
because voltmeters are made to measure potential difference and they are placed in parallel to the part measured. How it works is interesting but is not really part of the question.
Answer:
B. It is connected in parallel and measures potential difference.
Explanation:
A voltmeter is connected in parallel.
A voltmeter is used for measuring the electrical potential difference between two points in an electric circuit.
A deep-space satellite is sent to orbit a distant planet with unknown mass. On
arrival, the satellite begins its orbit and measures a gravitational pull from the
planet of 620 N. If the satellite has a mass of 450 kg and orbits the planet at a
radius of 4.0 x 10^6m, what is the approximate mass of the planet?(recall that G=6.7x10^-11 N•m2/kg^2.)
Answer:
The mass of the planet is [tex]3.29\times 10^{23}\ kg[/tex].
Explanation:
Given that,
The gravitational pull on the planet is 620 N
Mass of a satellite is, m₁ = 450 kg
Radius of a planet is [tex]4\times 10^6\ m[/tex]
We need to find the mass of the planet. Gravitational force is given by :
[tex]F=\dfrac{Gm_1m_2}{r^2}[/tex][tex]m_2[/tex] is the mass of the planet
[tex]m_2=\dfrac{Fr^2}{Gm_1}\\\\m_2=\dfrac{620\times (4\times 10^6)^2}{6.7\times 10^{-11}\times 450}\\\\m_2=3.29\times 10^{23}\ kg[/tex]
So, the mass of the planet is [tex]3.29\times 10^{23}\ kg[/tex].
14. Which of the following ray diagrams is correct for the mirror shown?
Answer:
C is the correct answer
Answer:
B
Explanation:
A hollow, uniformly charged sphere has an inner radius of r1 = 0.105 m and an outer radius of r2 = 0.31 m. The sphere has a net charge of Q = 1.9 μC. What is the magnitude of the electric field, in newtons per coulomb, at a distance of r = 0.17 m from the center of the sphere?
Answer:
E = 77532.42N/C
Explanation:
In order to find the magnitude of the electric field for a point that is in between the inner radius and outer radius, you take into account the Gauss' law for the electric flux trough a spherical surface with radius r:
[tex]\int E\cdot dS=\frac{Q}{\epsilon_o}[/tex] (1)
Q: net charge of the hollow sphere = 1.9*10-6C
ε0: dielectric permittivity of vacuum = 8.85*10^-12 C^2/Nm^2
Furthermore, you have that the net charge contained in a sphere of radius r is:
[tex]Q=\rho V=\rho \frac{4\pi (r^3-r_1^3)}{3}[/tex] (2)
with the charge density is:
[tex]\rho=\frac{Q}{\frac{4}{3}\pi(r_2^3-r_1^3)}[/tex] (3)
r2: outer radius = 0.31m
r1: inner radius = 0.105m
The electric field trough the Gaussian surface is parallel to the normal to the surface, the, you have in the integral of the equation (1):
[tex]\int E\cdot dS=E(4\pi r^2)[/tex] (4)
where you have used the expression for a surface of a sphere.
Next, you replace the expressions of equations (2), (3) and (4) in the equation (1) and solve for E:
[tex]E(4\pi r^2)=\frac{1}{\epsilon_o}\frac{Q}{\frac{4}{3}\pi(r_2^3-r_1^3)}(\frac{4\pi (r^3-r_1^3)}{3})\\\\E=\frac{1}{\epsilon_o}\frac{Q(r^3-r_1^3)}{4\pi r^2(r_2^3-r_1^3)}[/tex]
you replace the values of all parameters, and with r = 0.17m
[tex]E=\frac{(1.6*10^{-6}C)((0.17m)^3-(0.105m)^3)}{4\pi(8.85*10^{-12}C^2/Nm^2)(0.17m)^2((0.31m)^3-(0.105m)^3)}\\\\E=77532.42\frac{N}{C}[/tex]
The magnitude of the electric field at a distance r=0.17m to the center of the hollow sphere is 77532.42N/C
A fire truck drives 3 miles to the east, then 1.2 miles to the west. What is the
displacement of the fire truck?
A. 4.2 miles east
B. 4.2 miles west
C. 4.2 miles
D. 1.8 miles east
Answer:
the answer is D. you have to go 3 miles to the east and then subtract the distance that the fire truck traveled to the the west.
Answer: D. 1.8 miles east
Explanation:
(Each "→" or "←" = .2 miles)
3 miles east: →→→→→ →→→→→ →→→→→
minus 1.2 miles west: ← ←←←←←
3 - 1.2 = 1.8 miles east: →→→→→ →→→→
An ion has a charge of +3.2 x 1014 C. Another charge is brought near it and
experiences a repulsive electrostatic force. This other charge must be
Answer: Positive.
Explanation:
Given that the ion has a charge of +3.2 x 10^14 C.
When another charge is brought near it, it experiences a repulsive electrostatic force. The other charge brought near the ion must be positive.
This is because the electric field which is a region of space created by the positive ion with a charge of +3.2 x 1014 C have electric lines of force moving outward. Therefore, when another charge is brought near the positive ion, it will either attract or repel depending on the charge of the ion brought into the electric field created by the positive ion.
If the charge on the second ion is also positive, the electric lines of force will be in the same direction as that on the first ion and will their repel. However, if the second ion is negative, the electric field lines are in the opposite direction to that of the first positive ion, thereby creating an attractive electrostatic force in the electric field.
In summary, like charges repel, unlike charges attract.
3. How do we measure the average kinetic motion of molecules in a solution?
I have a test tomorrow and I can't find the definitions in my book so can you pls help me study by answering the following question? thnx! I will also mark the brainliest.
Answer:
See explanation
Explanation:
An element is a substance that cannot be chemically converted to another substance or broken down chemically into other substances.
Elements are represented by symbols. The symbol of an element may be the first one or two letters from its English or Latin name. For instance, the symbol of nitrogen is N. This symbol was derived from the first letter of its English name. The symbol for sodium is Na. This was derived from the first two letters of its Latin name, Natrium.
The periodic table is divided into horizontal rows called periods and vertical columns called groups. All members of the same period have the same number of electron shells while all members of the same group have the same number of valence electrons.
Metals are found towards the left hand side of the periodic table while non metals are found towards the right hand side of the periodic table. Metals looses electrons easily while nonmetals accepts electrons easily. Metals are good conductors of heat and electricity while non metals are poor conductors of heat and electricity.Metalloids have properties intermediate between those of metals and non metals and are found at the boarder line between metals and non metals in the periodic table. Metalloids include; silicon, boron, germanium, etc. The electrical conductivity of metalloids increases with temperature while the electrical conductivity of metals decreases with temperature.
In general, the the string or air column of a musical instrument is, the more harmonics are generated.
Answer:
In general, the LONGER the string or air column of a musical instrument is, the more harmonics are generated.
plz help!!!
urgent!!
will give the brainliest!!!
Answer: Find the answer in the explanation.
Explanation:
I.) A piece of wire at room temperature.
The resistance of a piece of wire at room temperature is independent of both current and the voltage because it is an Ohmic component.
II.) Filament bulb
The filament wire in the filament bulb does not obey Ohms law.
For very small currents and voltage, the graph is roughly a straight line. At higher voltages, the line starts to curve.
III.) A diode is any component that allows electric current in only one direction. The resistance of a diode depends on the potential difference across it. Therefore, it does not obey Ohms law. It is a non-Ohmic component.
Find the attached files for the figures
Throwing a football is an example of what type of motion ?
a) two-dimensional
b) one-dimensional
c) displacement
d) distance
A 24.8 cm tall object is placed in front of a lens, which creates a -3.09 cm tall image. If the object is 37.5 cm from the lens, what is the image distance? pls help
Answer:
v = 4.67 m
Explanation:
It is given that,
Height of the object is 24.8 cm
Height of the formed image is -3.09 cm
Object distance is 37.5 cm, it is negative always
We need to find the image distance. Let v is the image distance. Magnification of an object is given by the formula as follows :
[tex]\dfrac{h'}{h}=\dfrac{v}{u}\\\\v=\dfrac{uh'}{h}\\\\v=\dfrac{-37.5\times (-3.09)}{24.8}\\\\v=4.67\ m[/tex]
So, the image is formed at a distance of 4.67 m.
Compare and contrast electromagnetic force, electromagnetic waves, and an electromagnetic field
Electromagnetic fields are a combination of invisible electric and magnetic fields of force.
Electromagnetic waves is a way or path to represent electromagnetic field
When conductor comes in an Electromagnetic field the electromagnetic waves exerts a force on it called electromagnetic force
What are electromagnetic waves?Electromagnetic waves or EM waves are waves that are created as a result of vibrations between an electric field and a magnetic field.
Electromagnetic fields are a combination of invisible electric and magnetic fields of force.
Electromagnetic waves or EM waves are waves that are created as a result of vibrations between an electric field and a magnetic field. It is a way or path to represent electromagnetic field
When a conductor is placed in a magnetic field and current flows in the conductor, the magnetic field and the current interact each other to produce force. The force is called "Electromagnetic force". When conductor comes in an Electromagnetic field the electromagnetic waves exerts a force on it called electromagnetic force
learn more about electromagnetic waves
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A stone was projected at an angle of 40o and initial velocity of 20m/s. (a.)Determine the time of flight (b)Maximum height.
Answer:
A.) 1.3 seconds
B.) 0.42 m
Explanation:
A.) You are given the angle of projection to be 40 degrees and initial velocity of 20m/s.
At vertical component
U = Usin 40 that is,
U = 20sin40
Using the first equation of motion under gravity
V = U - gt
Let V = 0
0 = UsinØ - gt
gt = UsinØ
t = UsinØ/g
Where U = 20 m/s
Ø = 40 degree
g = 9.8 m/s^2
Substitutes all the parameters into the formula
t = 20sin40/9.8
t = 1.3 seconds
Total time of flight T = 2t
T = 2 × 1.3 = 2.6 s
B.) To calculate the maximum height,
You will use the formula
V^2 = U^2 - 2gH
At maximum height, V = 0
2gH = Usin^2Ø
H = Usin^2Ø/ 2g
Substitutes all the parameters into the formula
H = 20 sin^2(40) ÷ 2(9.8)
H = 8.2635/19.6
H = 0.42 m
TP-35 How many minutes should a blower be operated before starting an engine?
Answer:
The required minutes is 4 minutes.
Explanation:
Blowers are very important or Crucial because it's safeguard life on boat.
Blowers are constructed so that gasoline fumes will be cleared from comparments.
It is important to operate the blower for 4 minutes before starting an engine to remove fuel vapor so as to prevent explosion because explosive gasoline's or battery fumes could be present in engine compartments which could cause explosion if it's not operated for 4 minutes before you start the engine
ASSIGNMENTS
COURSES
Assignment
Attempt 1 of 3
SECTION 101
QUESTION 9 OF 35
A box is suspended from a series of cables as shown below. The angle of the cable attached to the ceiling is 30°
relative to the horizontal. The cable to the left has a tension force of 40 N. What is the approximate weight of the box?
30°
40N
23N
Answer:
23 N
Explanation:
By using the diagram above
[tex] \tan(30) = \frac{x}{40} [/tex]
By cross multiplying
[tex]x = \tan(30) \times 40[/tex]
[tex]x = 0.577 \times 40[/tex]
[tex]x = 0.577 \times 40[/tex]
[tex] x = 23.08[/tex]
[tex]approximately \: 23 [/tex]
What is the wave speed of a wave that has a frequency of 50 Hz and a wavelength of 0.10 m? What is the frequency of a wave that has a wave speed of 20 m/s and a wavelength of 0.50 m?
Answer:
a) What is the wave speed of a wave that has a frequency of 50 Hz and a wavelength of 0.10 m?
5m/s
b) What is the frequency of a wave that has a wave speed of 20 m/s and a wavelength of 0.50 m?
40Hz
Explanation:
a) What is the wave speed of a wave that has a frequency of 50 Hz and a wavelength of 0.10 m?
Wave speed(v) = Frequency(f) × Wavelength (λ)
= 50Hz × 0.10m
=5m/s
b) What is the frequency of a wave that has a wave speed of 20 m/s and a wavelength of 0.50 m?
The formula for Frequency when given wave speed and wave length = Wave speed/ wave length
f = v/λ
Frequency = 20m/s ÷ 0.50m
Frequency = 40Hz
Answer:
40 Hz
Explanation:
Suppose the initial position of an object is zero, the starting velocity is 3 m/s and the final velocity was 10 m/s. The object moves with constant acceleration. Which part of a velocity vs. time graph can be used to calculate the displacement of the object?
the area of the rectangle under the line
the area of the rectangle above the line
the area of the rectangle plus the area of the triangle under the line
the area of the rectangle plus the area of the triangle above the line
Answer:
The area of the rectangle plus the area of the triangle under the line
Explanation:
In this case, the object moves with constant acceleration. Initial speed of the object is 0.
Equation of kinematics :
v = u +at
v = at
v is directly proportional to time. If means that the graph is straight line passing through origin. We know that area under v-t graph gives displacement. So, the correct option is (c).
Answer:
c) the area of the rectangle plus the area of the triangle under the line
Explanation:
edge2021
A ball is tied to the end of a length of string. A student holds one end of the string and whirls it so the ball travels in a vertical circle. First she whirls the ball at a very fast speed, and then she very gradually lowers the speed. Where is the ball most likely to be when the string begins to sag?
Answer:
The top of the circle
Explanation:
At the top of the circle, there are two forces pulling the ball towards the center of the circle: weight and tension.
∑F = ma
mg + T = mv²/r
As v goes down, T also goes down, until it eventually reaches 0.
At the bottom of the circle, weight is pulling down, or away from the center of the circle. Sum of the forces:
∑F = ma
T − mg = mv²/r
As v goes down, T also goes down. However, even at v=0, T cannot be less than mg.
A 15.0 cm object is 12.0 cm from a convex mirror that has a focal length of -6.0 cm. What is the height of the image produced by the mirror? A. –5.0 cm B. 7.5 cm C. -7.5 cm D. 5.0 cm
Answer: D. 5cm
Explanation:
Given the following :
Focal length (f) = - 6.0 cm
Height of object = 15.0cm
Distance of object from mirror (u) = 12.0cm
Height of image produced by the mirror =?
Firstly, we calculate the distance of the image from the mirror.
Using the mirror formula
1/f = 1/u + 1/v
1/v = 1/f - 1/u
1/v = 1/-6 - 1/12
1/v = - 1/6 - 1/12
1/v = (- 2 - 1) / 12
1/v = - 3 / 12
v = 12 / - 3
v = - 4
Using the relation :
(Image height / object height) = (- image distance / object distance)
Image height / 15 = - (-4) / 12
Image height / 15 = 4 / 12
Image height = (15 × 4) / 12
Image height = 60 / 12
Image height = 5cm
Answer:
D. 5 cm
Explanation:got it right
Rosa records the distance that a toy car rolls and the time it takes to cover the distance. What scientific practice is this? collecting data asking a question providing explanations communicating results
Answer:
collecting data
Explanation:
Data collection refers to a systematic method for gathering and analyzing information from a number of sources in order to provide a complete and reliable image of a subject region. The collection of data helps an individual or organization to answer specific questions, determine outcomes, and predicting future possibilities and outcomes. As per the question, rosa is collecting data about the distance and time of her toy car intrigued by the scientific query.
Answer:
A : Data
Explanation:
I’m doing the exam
A graph titled Position versus Time shows time in seconds on the x axis, numbered 0 to 5, position in meters on the y axis, numbered 0 to 4. The graph has a horizontal line starting at (0, 3) to (5, 3). Given the information in the velocity vs. time graph, what is the displacement of the object after 1 second? m After 3 seconds? m After 5 seconds? m
Answer:
After 1 second: 3
After 3 seconds: 9
After 5 seconds: 15
Explanation:
You just multiply the time and velocity.
1 x 3 = 3, 3 x 3 = 9, etc.
Answer:
C.) The bicycle is not in motion.
Explanation:
Which optical devices spread light apart?
A. A and B
B. A and D
C. B and D
D. B and C
[tex]\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}[/tex]
Actually Welcome to the Concept of the Optical Devices.
Now basically here the devices that can spread light over apart are the CONCAVE LENS and Convex mirror.
so the Answer is
C. B and D
The optical devices that spread light apart is B and D.
What are optical devices?Optical devices are implements or instruments that process,analyses light waves and interprete it in order to enhance an image for visibility and determine the features of such image.
Therefore, The optical devices that spread light apart is B and D.
Learn more about optical devices below.
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