Answer:
[tex]193743.49\ \text{Pa}[/tex]
Explanation:
G = Gravitational constant = [tex]6.674\times 10^{-11}\ \text{Nm}^2/\text{kg}^2[/tex]
M = Mass of Europa = [tex]4.74\times 10^{22}\ \text{kg}[/tex]
R = Radius of Europa = [tex]\dfrac{3130}{2}=1565\ \text{km}[/tex]
h = Depth = 150 m
[tex]\rho[/tex] = Density of water = [tex]1000\ \text{kg/m}^3[/tex]
Acceleration due to gravity is given by
[tex]g=\dfrac{GM}{R^2}[/tex]
Pressure is given by
[tex]P=\rho gh\\\Rightarrow P=\rho \dfrac{GM}{R^2}h\\\Rightarrow P=1000\times \dfrac{6.674\times 10^{-11}\times 4.74\times 10^{22}}{1565000^2}\times 150\\\Rightarrow P=193743.49\ \text{Pa}[/tex]
The submarine should be designed to withstand a pressure of [tex]193743.49\ \text{Pa}[/tex].
The pressure due to column of liquid increases with the gravitational
attraction, density of the liquid and height of the liquid column.
The submarine should be able to withstand a pressure of approximately 194863.65 Pa.Reasons:
Mass of Europa, M = 4.78 × 10²² kg
Diameter of Europa, r = 3,130 km
Required:
The pressure a submarine must be designed to withstand when submerged to a depth of 150 meters.
Solution:
Gravitational acceleration on Europa is given by the formula;
[tex]\displaystyle g = \mathbf{\frac{G \cdot M}{r^2}}[/tex]
G = Universal gravitational constant = 6.67408 × 10⁻¹¹ m³/(kg·s²)
[tex]Radius \ of \ the \ satellite\ Europa = \dfrac{3,130 \ km}{2} = \mathbf{1,565 \ km}[/tex]
[tex]\displaystyle g = \frac{6.67408 \times 10^{-11} \times 4.78 \times ^{22}}{1565000^2} \approx 1.303[/tex]
The gravitational acceleration on Europa, g ≈ 1.303 m/s²
Therefore;
Pressure due to a liquid's weight, P = ρ·g·h
The pressure at 150 m, P₁₅₀ = 150 × 1.303 × 997 = 194863.65
The pressure the submarine must be designed to withstand is, P₁₅₀ ≈ 194863.65 Pa.
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The Hydrogen Spectrum
When a low-pressure gas of hydrogen atoms is placed in a tube and a large voltage is applied to the end of the tube, the atoms will emit electromagnetic radiation and visible light can be observed. If this light passes through a diffraction grating, the resulting spectrum appears as a pattern of four isolated, sharp parallel lines, called spectral lines. Each spectral line corresponds to one specific wavelength that is present in the light emitted by the source. Such a discrete spectrum is referred to as a line spectrum
By the early 19th century, it was found that discrete spectra were produced by every chemical element in its gaseous state. Even though these spectra were found to share the common feature of appearing as a set of isolated lines, it was observed that each element produces its own unique pattern of lines. This indicated that the light emitted by each element contains a specific set of wavelengths that is characteristic of that element.
The first quantitative description of the hydrogen spectrum was given by Johann Balmer, a Swiss school teacher, in 1885, By trial and error, he found that the correct wavelength λ of each line observed in the hydrogen spectrum was given by
1/λ = R ( 1/2^2-1/n^2)
where R is a constant, later called the Rydberg constant, and n may have the integer values 3, 4, 5, If λ is in meters, the numerical value of the Rydberg constant (determined from measurements of wavelengths) s R= 1.097x10^7 m-1
Balmer knew only the four lines in the visible spectrum of hydrogen. Thus, the original formula was written for a limited set of values of T. However, as more techniques to detect other regions of the spectrum were developed, it became clear that Balmer's formula was valid for all values of n. The entire series of spectral lines predicted by Balmers formula is now referred to as the Balmer series
Part A) What is the wavelength of the line corresponding to n =4 in the Balmer series? Express your answer in nanometers to three significant figures .
Part B) What is the wavelength of the line corresponding to n =5 in the Balmer series?
Answer:
a) λ = 4.862 10⁻⁷ m, b) λ = 4.341 10⁻⁷ m
Explanation:
The spectrum of hydrogen can be described by the expression
[tex]\frac{1}{\lambda} = R_H ( \frac{1}{n_o^2} - \frac{1}{n^2} ) \ \ \ \ n>n_o[/tex]
in the case of the initial state n = 2 this series is the Balmer series
a) Find the wavelength for n = 4
let's calculate
[tex]\frac{1}{ \lambda}[/tex] = 1,097 10⁷ ([tex]\frac{1}{2^2} - \frac{1}{4^2}[/tex])
\frac{1}{ \lambda} = 1.097 10⁷ 0.1875 = 0.2056 10⁷
λ = 4.862 10⁻⁷ m
b) n = 5
\frac{1}{ \lambda} = 1,097 10⁷ ([tex]\frac{1}{2^2} - \frac{1}{5^2}[/tex])
\frac{1}{ \lambda} = 1.097 10⁷ 0.21 = 0.23037 10⁷
λ = 4.341 10⁻⁷ m
can u pls help me ........
Answer:
solidification
Explanation:
a liquid becoming a solid, is called solidification. For any pure substance, the temperature at which melting occurs—known as the melting point—is a characteristic of that substance.
A toroidal solenoid has a radius of 0.12 m and a cross sectional area of 20×10^-4 m2. It is found that when the current is 20A, the energy is 0.1 J. How many turns does the winding have?
Answer:
the number of turns in the winding is 387 turns.
Explanation:
Given;
radius of the solenoid, r = 0.12 m
cross sectional area of the solenoid, A = 20 x 10⁻⁴ m²
current flowing through the solenoid, I = 20 A
the energy of the flowing current, E = 0.1 J
The energy stored in solenoid is given as;
[tex]U = \frac{1}{2} LI^2\\\\L = \frac{2U}{I^2} \\\\L = \frac{2 \times 0.1}{20^2} \\\\L = 5 \times 10^{-4} \ H[/tex]
The number of turns in the winding is calculated as follows;
[tex]L = \frac{\mu_o N^2A}{2\pi r} \\\\N^2 = \frac{2\pi r L}{\mu_o A} \\\\N = \sqrt{\frac{2\pi r L}{\mu_o A}} \\\\N = \sqrt{\frac{2\pi \times 0.12 \times 5\times 10^{-4} }{4\pi \times 10^{-7} \times 20\times 10^{-4} }}\\\\N = 387 \ turns[/tex]
Therefore, the number of turns in the winding is 387 turns.
there are 3 balls , ball 1 has a mass of 2 kg ,ball number 2 has a mass of 0.5 kg, and ball number 3 has the mass of 0.02 kg ...for all the balls to have the same momentum which one has the greatest velocity? PLSSSS I NEED HELP
Answer:
If it moves at the same speed but has twice as much mass, its momentum is ... there is no air in space; there is no friction in space; there is no gravity in outer space ... One cart rolls rightward at 2 m/s and the other cart rolls leftward at 1 m/s. ... A 5-N force is applied to a 3-kg ball to change its velocity from +9 m/s to +3 m/s.
Explanation:
What efforts are made to conserve wildlife in Nepal ?
When a reaction that occurs when a person experiences very strong emotion especially those associated with a perceived threat is called.
Answer:
The correct answer is - fight or flight response or reaction.
Explanation:
According to Cannon, the fight or flight reaction is a strong emotion experienced by a person especially people experiences associated with a perceived threat.
This reaction takes place in form of arousal in a perceived threat or stress conditions. It helps in maintaining the body environment in panic or stressed conditions.
Priscilla is driving her car on a busy street and Harvey passes her on his motorcycle. What will happen to the sound from his motorcycle after it passes her car?
A.
The frequency of the sound will decrease.
B.
The amplitude of the sound will increase.
C.
The intensity of the sound will increase.
D.
The wavelength of the sound will decrease.
E.
The velocity of the sound will increase.
Answer:
the correct answer is A
Explanation:
This is a doppler effect exercise which is the change in frequency due to the relative movement of the sound source and the observer.
[tex]f' = f_o \ \frac{v+v_o}{v-v_s}[/tex]
where v₀ is the speed of the observer and v_s the speed of the source, the signs correspond when the two are closing in
with this expression let's analyze the different answers
A) True. The observed change is in the frequency, in this case the two are moving away, so the expression that describes the phenomenon is
[tex]f'= f_o \ \frac {v-v_o}{ v+v_s}[/tex]
In this case, the speed of the source is greater than the speed of the observer, so when the denominator increases faster than the numerator, consequently the frequency must decrease
B) False. The amplitude does not depend on the relative velocity
C) False. The intensity depends on the distance, by or which when increasing the distance the intensity should decrease
D) False. The speed of sound is a constant, if the frequency decreases the wavelength must increase to maintain equality
E) False. The speed of sound depends on the properties of the propagating medium, not on the relative speed of the source and the observer.
Consequently the correct answer is A
Which statement describes what some people might consider a benefit of wireless technology?
O Micah interacts with people to play video games.
O Nadia pays a monthly fee to have high-speed internet for her tablet.
O Luca relies on a printed store receipt instead of the emailed version.
O Quinn watches television for hours while her friends spend time together.
Help
I've got this question, which option is correct?
Answer:
option c is the correct one
balance Al +N₂ --> AIN
Answer:
[tex]2Al + N_{2} ==> 2AlN[/tex]
Explanation:
1.00 x 100 kg of clear liquid (specific heat
capacity = 5.11 x 102 J/kg•°C) at a temperature
of 15.0°C gains 3.33 x 10 J of heat. What is the
final temperature of the liquid? (Assume the
melting point is less than 15.0°C and the boiling
point is greater than 62.0°C.)
Answer:
No temperature change occurs from heat transfer if ice melts and becomes liquid water (i.e., during a ... to change 1 kg of liquid water at the normal boiling point (100ºC at atmospheric pressure) to steam (water vapor).
The melting point of lead is 327.3o C. Assume the final temperature of the system is T. Then the amount of energy released by the lead as it solidifies is. ΔQ = mleadLlead = 0.09 kg*(2.45*104 J/kg) = 2205 J
2.) Assume you decided to build a cabin off the electrical grid in a remote region of the United States, and your cabin would require 720 kWh per month to easily meet your needs. You decide to produce your electricity using photovoltaic cells and store it using a battery system so that it is available when you wish to use it. If every photovoltaic cell has the potential to produce 0.25 kilowatts (250 watts), and they produced electricity for 24 hours a day, how many photovoltaic cells would you need to meet your electricity needs for a month
Answer:
4 photovoltaic cells are required to meet monthly energy consumption of the cabin.
Explanation:
Let suppose that PV generation system produces energy at constant energy, the number of photovoltaic system to meet energy consumption of the cabin is:
[tex]n = \frac{E}{\dot E \cdot t}[/tex] (1)
Where:
[tex]E[/tex] - Energy consumption of the PV system, in kilowatt-hours.
[tex]\dot E[/tex] - Power generation of the PV cell, in kilowatts.
[tex]t[/tex] - Working times, in hours.
If we know that [tex]E = 720\,kWh[/tex], [tex]\dot E = 0.25\,kW[/tex] and [tex]t = 720\,h[/tex], then the number of photovoltai cells is:
[tex]n = \frac{E}{\dot E \cdot t}[/tex]
[tex]n = 4[/tex]
4 photovoltaic cells are required to meet monthly energy consumption of the cabin.
A wheelbarrow full of bricks is lifted to the top of a wall. If the mass of the loaded wheelbarrow is 3000.0 g and the height of the wall is 0.45 meters, what is its GPE?
Answer:
the Gravitational potential energy is 13.23 J
Explanation:
The computation of the GPE is shown below:
GPE stands for Gravitational potential energy
The following formula should be used for the same
= mass × gravity × height
= 3000 g × 9.8m/sec^2 × 0.45 m
= 13.23 J
Hence, the Gravitational potential energy is 13.23 J
We simply applied the above formula so that we can easily determine the GPE
A 1.4-cm-tall object is 22 cm to the left of a lens with a focal length of 11 cm . A second lens with a focal length of -5 cm is 37 cm to the right of the first lens.
Calculate the distance between the final image and the second lens.
Calculate the image height.
Answer:
can you explain yourself more please
Explanation:
Help please due tomorrow
Please help The half-life of argon-44 is 12 minutes. Suppose you start with 20 atoms of
argon-44 and wait 12 minutes. How many atoms of argon-44 will be left?
A. 20 atoms
B. 40 atoms
C. 5 atoms
D. 10 atoms
Answer:
D. 10 atoms
Explanation:
PLEASE HELP ME PLEASE! BRAINLEST
Answer:
10kg
Explanation:
Weight is "how much does gravity drag this down".
Mass is "how much matter is there here".
The relation is:
[tex]F_g = mg[/tex]
where [tex]F_g[/tex] is the weight, [tex]m[/tex] is the mass and [tex]g[/tex] is the gravitational acceleration (roughly equal to 10N/kg on Earth).
From the task we know that:
[tex]F_g = 100N\\g = 10\frac{N}{kg}[/tex]
So let's input it into the relation:
[tex]100N = m\cdot 10\frac{N}{kg}\\10N = m \cdot 1\frac{N}{kg}\\10N \cdot \frac{kg}{N} = m\\~\\m = 10kg[/tex]
How do home computer scanners generally use electromagnetic waves?
O A. They change information received from sound waves into electromagnetic waves.
OB. They gather information from reflected and absorbed waves.
O C. They receive microwaves that are emitted by natural objects.
O D. They use X-rays that penetrate most objects. SUBMIT
Answer:
they gather information from reflected and absorbed waves.
Explanation:
PLEASE HELP ME WITH THIS ONE QUESTION
A diverging lens has a focal length of –10 cm. Suppose an object is placed 15 cm in front of the lens. a) What is the image distance? b) Is the image real or virtual?
Answer:
b
Explanation:
For given diverging lens(Concave) ; a) The distance of the image is -6 Cm, b) The image is virtual.
What is diverging lens?The lens that diverge incident parallel beam of light after refraction from the lens, is called diverging or concave lens.
The images formed by it are always smaller, upright, towards object and between focus and optical center of the lens.Given data:
a)
u = -15 Cm, f = -10 Cm, v= ?by using lens formula,[tex]\frac{1}{f} = \frac{1}{v} - \frac{1}{u} \\[/tex]
On putting the values,[tex]\frac{1}{-10} = \frac{1}{v} - \frac{1}{-15}\\\frac{1}{-10} = \frac{1}{v} + \frac{1}{15}[/tex]
[tex]\frac{1}{v} = \frac{1}{-10} -\frac{1}{15} \\\frac{1}{v} = \frac{-3-2}{30} \\[/tex]
[tex]v = -6 Cm[/tex]
b) Magnification ,
m= ([tex]\frac{v}{u}[/tex])
on putting values,
[tex]m =(\frac{-6}{-15} )=\frac{2}{5} =0.4[/tex]
since m is positive it means the image is virtual
Hence a) distance of image is -6 Cm and b) the image is virtual.
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sorry i was gone hope you dident mess me hers a question
Identify the organ that brings oxygen into the body.
brain
chest
heart
lungs
Answer:
lungs
Explanation:
lungs bring oxygen
Answer:
lungs
Explanation:
i took the quiz
An AC circuit has resistor, capacitor and inductor connected in series. It is
connected to a voltage supply at resonant frequency. If the frequency of the
voltage supply is reduced, which of the following quantities will be reduced? *
Answer:
Z = (R^2 + X^2)^1/2
At the resonant frequency, the quantity X equal zero and
w L - 1 / (w * C) equals zero where w is omega the angular frequency
A lens with f= 20.0 cm creates a
virtual image at -37.5 cm (in front
of the lens). What is the object
distance?
Answer:
13.04
Explanation:
credit to the comment above
A lens with f= 20.0 cm creates a virtual image at -37.5 cm, then the object distance is approximately 0.0767 cm.
To determine the object distance in this scenario, we can use the lens formula:
[tex]\rm \frac{1}{f} =\frac{1}{v} -\frac{1}{u}[/tex]
Here, we have:
f = 20.0 cm (positive for a converging lens)
v = -37.5 cm (negative because it is a virtual image formed in front of the lens)
Substituting the values into the lens formula:
1÷20.0 = 1 ÷ (-37.5) - 1 ÷ u
Simplifying the equation:
1 ÷ 20.0 + 1÷ 37.5 = 1 ÷ u
Multiplying through by the common denominator:
(37.5 + 20.0) ÷ (20.0 * 37.5) = 1 ÷ u
57.5 ÷ 750 = 1 ÷ u
Dividing both sides by 57.5:
1 ÷ u = 750 ÷ 57.5
u = 57.5 ÷ 750
u ≈ 0.0767 cm
Thus, the object distance is approximately 0.0767 cm.
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which describes the attraction of one water molecule toward another
A hammer with mass m is dropped from rest from a height h above the earth's surface. This height is not necessarily small compared with the radius RE of the earth. If you ignore air resistance, derive an expression for the speed v of the hammer when it reaches the surface of the earth. Your expression should involve h, RE, and mE, the mass of the earth.
Answer:
v = √{2(GmE(1/RE - 1/(RE + h)]}
Explanation:
From the law of conservation of energy, the total kinetic + potential energy at h = total kinetic + potential energy at the surface of the earth(h = 0)
So, K + U = K' + U'
where K = kinetic energy of hammer at h = 0
U = gravitational potential energy of hammer at h = -GmEm/(RE + h)
K' = kinetic energy of hammer at the earth's surface (h = 0) = 1/2mv²
U = gravitational potential energy of hammer at earth's surface (h = 0) = -GmEm/RE
So, K + U = K' + U'
0 + [-GmEm/(RE + h)] = 1/2mv² + [-GmEm/RE]
0 - GmEm/(RE + h) = 1/2mv² - GmEm/RE
collecting like terms,we have
1/2mv² = GmEm/RE - GmEm/(RE + h)
Factorizing GmE and multiplying both sides by 2, we have
v² = 2(GmE(1/RE - 1/(RE + h)]
taking square-root of both sides, we have
v = √{2(GmE(1/RE - 1/(RE + h)]}
The expression for the speed of the hammer will be:
[tex]V=\sqrt{2(Gm_e(\dfrac{1}{R_e}-\dfrac{1}{R_e+h}) }[/tex]
What will be the speed of the hammer?The law of conservation says that the total energy at the height h and the total energy at the surface of the earth will remain constant.
From the law of conservation of energy
[tex]KE+PE=KE'+PE'[/tex]
where
KE = kinetic energy of hammer at h = 0
PE = gravitational potential energy of hammer at h height
[tex]PE=\dfrac{-Gm_em}{R_e+h}[/tex]
KE' = kinetic energy of hammer at the earth's surface (h = 0)
[tex]KE'=\dfrac{1}{2} mv^2[/tex]
PE' = gravitational potential energy of hammer at earth's surface (h = 0)
[tex]PE'=\dfrac{Gm_em}{R_e}[/tex]
Now by putting the values
[tex]KE+PE=KE'+PE'[/tex]
[tex]0+ \dfrac{-Gm_em}{R_e+h}[/tex] [tex]=\dfrac{1}{2} mv^2[/tex] [tex]-\dfrac{Gm_em}{R_e}[/tex]
[tex]\dfrac{1}{2} mv^2=\dfrac{Gm_em}{R_e} -\dfrac{Gm_em}{R_e+h}[/tex]
[tex]v^2=2Gm_e(\dfrac{1}{R_e} -\dfrac{1}{R_e+h} )[/tex]
[tex]v=\sqrt{2Gm_e(\dfrac{1}{R_e} -\dfrac{1}{R_e+h} )}[/tex]
Thus the expression for the speed of the hammer will be:
[tex]V=\sqrt{2(Gm_e(\dfrac{1}{R_e}-\dfrac{1}{R_e+h}) }[/tex]
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a 0.1 kg object oscillates as a simple harmonic motion along x axis with a frequency f=3.185 hz. At a position x1 , the object has a kinetic energy of o.7 j and a potential energy 0.3 J.The amplitude of oscillation A is:
Answer:
The total energy must be .7 J + .3 J = 1 J for a particle at the endpoint or midpoint of motion.
Also, omega = (k / m)^1/2
f = omega / (2 * pi)
omega^2 = 4 pi^2 * f^2 = k / m
k = 4 * pi^2 * f^2 * m = 40.05
Max KE or PE = 1/2 k A^2
A^2 = 2 * E / k = 2 * 1 / k = .0499
A = .223 meters
Research the main categories of mental disorders and their evaluation and assessments. For example, you can use your favorite Internet search engine to look up the following sites:
National Institute of Mental Health
Mental Help.net
American Psychological Association Help Center
Step 2 Report on methods of diagnosis and assessments of the major mental disorders.
Write a one and one-half-page report on mental disorders, their diagnosis, and treatment. Identify the following elements in your paper:
The major categories of mental disorders. ( Hint: Anxiety disorders are one category.)
The commonly used methods of diagnosis.
The treatment of choice (meaning the favorite current treatment) for this disorder.
Answer:
D
Explanation:
It’s D
How does a battery generate electrical energy?
An auto, moving too fast on a horizontal stretch of mountain road, slides off the road,
falling into deep snow 43.9 m below the road and 87.7 m beyond the edge of the road. What was the acceleration 10m below the edge of the road?
Answer:
acceleration = - 9.8 m/s²
Explanation:
From the question, we can deduce that the only force that will be acting on the car is gravity and as such the acceleration during free fall will be equal to the acceleration due to gravity but will be negative since it is towards the ground.
Thus, acceleration = - 9.8 m/s²
Which of the following is NOT a geological event caused by the movement of tectonic plates?
A) Sand Dunes
B) Mountain forming
C) Earthquakes
D) Volcanoes
PLEASE HELP ME IN THE QUESTION ALSO!
Answer:
467
Explanation: