As given by the question
There are given that the expression
[tex]15-(-14)[/tex]Now,
The simplification of the given expression is:
[tex]\begin{gathered} 15-(-14)=15+14 \\ =29 \end{gathered}[/tex]Hence, the value of the expression is 29.
Student Calendar Dars 0Sth Grade Srd. Aarianna Moore - GraphingLinearEquationsActivity-1.pdf+Automatic.5 TurnPart 1: Graphing Using a Table of ValuesUse the equation to complete each table, and then sketch the graph.1. y = 2x + 3y- 1(x, y)1-1,1X-2-101232x+32(-2)+32(-1)+32(0)+32(1) 132(2)+330,31.5522,72(3)+393,9
Once we have the table we can graph the points in the plane.
To graph a point (x,y) in the plane we have to start at the origin, then we will count x units in the horizontal direction (to the left if x is negative and to the right if x is positive); then from the point we reach while moving horizontally we are going to count y units in the vertical direction (up is y is positive and down if y is negative).
Let's take for example the first point (-2,-1). We start at the origin and move two units to the left, and from there one unit down. That way the point will be graph as shown
If we do this with all the point we get
Finally, to get the graph of the equation we join the points with a line
Circle rectangle that has a length of 12 inches and a width of 4 inches explain your reasoning as to how you figured out which rectangle was the correct answer
Answer:
Step-by-step explanation:
Rectangle:
Has two dimensions, length(l) and width(w).
The perimeter is: P = 2*(l+w)
In this question:
l = 12, w = 4.
We want a triangle with perimeter of
P = 2*(l+w) = 2*(12 + 4) = 2*16 = 32 inches
Hi. Been out due to medical reasons trying to catch up. thanks in advance
We have a mixture of 300 ml with 15% alcohol content, this means that in this mixture we have an alcohol total of:
[tex]\text{alcohol}=300\cdot\frac{15}{100}=45\text{ ml}[/tex]And we want to obtain a 60% alcohol solution by mixing a 90% mixture with the 15% one we have.
[tex]\begin{gathered} \text{volume 90 \%}=v \\ \text{ alcohool content}=0.9\cdot v \end{gathered}[/tex]When we add this volume to what we already have, we will obtain:
[tex]\begin{gathered} \text{ final mixture}=300+v \\ \text{alcohool content}=45+0.9\cdot v \end{gathered}[/tex]And what we want is that the alcohol content must be equal to 60% of the final mixture, so we have:
[tex]\begin{gathered} 60\text{ \%}\cdot\text{ final mixture}=\text{ alcohol content} \\ \frac{60}{100}\cdot(300+v)=45+0.9\cdot v \\ 0.6\cdot(300+v)=45+0.9\cdot v \\ 180+0.6\cdot v=45+0.9\cdot v \\ \text{0}.9\cdot v-0.6\cdot v=180-45 \\ 0.3\cdot v=135 \\ v=\frac{135}{0.3}=450\text{ ml} \end{gathered}[/tex]This means that we need to add 450 ml of the 90% solution to obtain the desired final mixture.
Of the 660 students eating lunch, 420 purchased their lunch and the rest brought a bag lunch. Find the ratio in simplest form of the number of students purchasing lunch to total number of students eating lunch.
Answer:
7:11.
Explanation:
Number of students eating lunch = 660
Number of students purchasing lunch = 420
The ratio of the number of students purchasing lunch to the total number of students eating lunch will be:
[tex]420\colon660[/tex]We reduce it to its simplest form.
[tex]\begin{gathered} \frac{420}{10}\colon\frac{660}{10} \\ 42\colon66 \\ \frac{42}{6}\colon\frac{66}{6} \\ 7\colon11 \end{gathered}[/tex]The ratio in simplest form is 7:11.
Mrs Nelson has a total of 150 students in her classes . of these students 30% eat during the first lunch period 20% 8 during the second lunch period and the rest eat during the third lunch period and the rest eat during the third lunch period how many of her students eat during each lunch.
we have
total students-------> 150
First period
Eat 30%
30%=30/100=0.30
number of students First period is equal to
150*(0.30)=45 students
Second period
Eat 20%
20%=20/100=0.20
number of students 2 period is
150*(0.20)=30 students
Thsrd period
Eat=100%-(30%+20%)=50%
number of students
150*(0.50)=75 students
therefore
answer is
I period ----> 45 students
II period ----> 30 students
III period ----> 75 students
Equation for Searcy:C= 1.25 +5Equation for Little Rock:C= lr + 10Both fairs charge the same amount at___rides which would cost $___
we have that
the equation 1 is equal to
C=1.25r+5
Equation 2 is
C=r+10
Equate both equations
1.25r+5=r+10
solve for r
1.25r-r=10-5
0.25r=5
r=20
Find the value of C for r=20 rides
C=r+10
C=20+10=$30
Note: The result is the same if you use equation 1
so
C=1.25(20) +5
C=$30
therefore
the answer is
r=20 rides and the cost is C=$30Which of the following inqualities best describes the graph below? A. y ≤ -1/4x - 8B. y ≤ -1/4x - 2C. y ≥ -1/4x - 8D. y ≥ -1/4x - 2
we have that
The solution is the shaded area below the solid line
The slope of the solid line is negative
The y-intercept of the solid line is -2
therefore
the answer is the option Ba mall did a survey of grandmothers who shop with grandchildren.
ANSWER
[tex]200[/tex]EXPLANATION
From the given data;
The ratio of the grandmother who buys lunch : all grandmother is;
[tex]\begin{gathered} 35:50 \\ =7:10 \end{gathered}[/tex]To calculate the corresponding values of grandmothers who buys lunch and all grandmother;
For the 3rd column;
When all grandmother is 150.
The grandmothers who buy lunch will be;
[tex]70+35=105[/tex]Hence the ratio;
[tex]105:150[/tex]also, the next column;
[tex]105+35=140[/tex]For all grandmother, add 50 to 150
[tex]50+150=200[/tex]Hence, the ratio equals;
[tex]140:200[/tex]The next column for grandmothers who buy lunch;
[tex]140+35=175[/tex]For all grandmother;
[tex]200+50=250[/tex]The ratio;
[tex]175:250[/tex]About 200
This probability distribution shows thenumber of times a group of people takesselfies before liking them.Retakes01234Frequency2729181412Using this distribution, find the probability that apersoit will retake their selfie exactly 3 times.p = ?1
Probability that a person will retake their selfie 3 times = 7/50
Explanations:The total number of times the groupof people take selfies = 27+29+18+14+12
The total number of times the groupof people take selfies = 100
The number of times the selfie was taken thrice = 14
Probability that a person will retake their selfie 3 times = 14/100 = 7/50
Use the equation below to find y,if m=7,x=6 and b11
Given the following parameters m=7,x=6 and b=11, we will substitute them into the equation y=mx-b
[tex]\begin{gathered} y=mx-b \\ y=7(6)-11 \\ y=42-11 \\ y=31 \end{gathered}[/tex]Therefore, the value of y is 31
y < 5x - 4y > -2x – Solution to system of inequality
Answers:
(4, 3)
(6, 0)
(3, -1)
Explanation:
An ordered pair is a solution to the system of inequalities if when we replace x and y, the ordered pair satisfies both equations.
So, for (4, 3), we get:
y ≤ 5x - 4
3 ≤ 5(4) - 4
3 ≤ 20 - 4
3 ≤ 16
y ≥ -2x - 1
3 ≥ -2(4) - 1
3 ≥ -8 - 1
3 ≥ -9
Therefore, (4, 3) is a solution of the system since 3 is less than 16 and 3 is greater than -9.
For (6, 0), we get:
y ≤ 5x - 4
0 ≤ 5(6) - 4
0 ≤ 30 - 4
0 ≤ 26
y ≥ -2x - 1
0 ≥ -2(6) - 1
0 ≥ -12 - 1
0 ≥ -13
Therefore, (6, 0) is a solution of the system
For (-4, -3), we get:
y ≤ 5x - 4
-3 ≤ 5(-4) - 4
-3 ≤ -20 - 4
-3 ≤ -24
Since -3 is greater than -24, (-4, -3) is not a solution to the system.
For (1, 3), we get:
y ≤ 5x - 4
3 ≤ 5(1) - 4
3 ≤ 5 - 4
3 ≤ 1
Since 3 is greater than 1, (1, 3) is not a solution to the system.
Finally, for (3, -1), we get:
y ≤ 5x - 4
-1 ≤ 5(3) - 4
-1 ≤ 15 - 4
-1 ≤ 11
y ≥ -2x - 1
-1 ≥ -2(3) - 1
-1 ≥ - 6 - 1
-1 ≥ -7
Therefore, (3, -1) is a solution to the system.
X-Sarah spends hour vacuuming her mom's car. She spends 4 times as long washing the car. What is thetotal amount of time Sarah spends washing her mom's car?O A 15 hoursO B hourO C.45 hoursrOD 5 hour
Given:
Sarah spends 1/6 hour vacuuming her mom's car.
She spends 4 times as long washing the car.
Sarah spends washing her mom's car = 4 times 1/6 hour
Sarah spends washing her mom's car is
[tex]=4\text{ }\frac{1}{6}\text{hours}[/tex]Hence the answer is
[tex]4\text{ }\frac{1}{6}\text{hours}[/tex]An Aircraft factory manufactures airplane engines. The unit cost C ( the cost in dollars to make each airplane engine) depends on the number of engines made. If x engines are made, then the unit cost is given by the function C(x)=0.6^2-324x+56,258. What is the minimum unit cost? Do not round your answer.
We have that the unit cost is given by a parabola, and the leading coefficient is given by 0.6 (it is positive), then, we have a minimum in the shape of the parabola.
A way to find the minimum is to find the vertex of the parabola (in this given case, the vertex is the minimum point) which coordinates are as follows:
[tex]x_v=-\frac{b}{2a},y_v=c-\frac{b^2}{4a}[/tex]Since we need to find the minimum unit cost, we need to find the value for y. Then, we have:
[tex]0.6x^2-324x+56258[/tex]a = 0.6
b = -324
c = 56258
Then
[tex]y_v=56258-\frac{(-324)^2}{4\cdot(0.6)}\Rightarrow y_v=12518[/tex]Therefore, the minimum unit cost is equal to $12,518.
Solve the system by graphing. Y = -X-4 4x-y=-1
x = -1 and y = -3
Here, we want to solve the system of equations by graphing
A plot of both lines are required on same axes
The point at which they meet is the solution to the system
Kindly find attached a plot of the equations on same axes below;
As can be seen from the plot, the value of x is -1 while the value of y is -3
2/4, 2/16, 16/20 reducing fraction
To reduce fracions follow these steps:
1. Find a number that can divide both numerator and denominator, for the first fraction 2/4, it can be 2
2. Divide top and bottom by that number (2), then we get:
2÷2 / 4÷2 = 1 / 2
3. Repeat from step 1 until there is no number, greater than 1, that can divide the top and the bottom, in this case, there is not such number.
Then when reduced, the first traction 2/4 we get : 1
On a school bus there are 10 sixth graders , 4 seventh graders and 6 eighth graders. Calculate the following randomly selected students. A. P( seventh grader) = ?B. P( not seventh grader) =?
In order to calculate the probability of a student from this sample to be a seventh grader, we need to divide the number of seventh graders by the total number of students. This is done below:
[tex]\begin{gathered} P(\text{seventh grader)}=\frac{4}{10+4+6} \\ P(\text{seventh grader)}=\frac{4}{20} \\ P(\text{seventh grader)}=\frac{1}{5} \end{gathered}[/tex]A. The probability of a random selected student being a seventh grader is 1/5.
In order to calculate the probability of the selected student not being a seventh grader, we need to subtract the probability of them being a seven grader from one, because these two events are mutually exclusive. So we have:
[tex]\begin{gathered} P(\text{not seventh grader)}=1-\frac{1}{5} \\ P(\text{not seventh grader)}=\frac{5}{5}-\frac{1}{5} \\ P(\text{not seventh grader)}=\frac{4}{5} \end{gathered}[/tex]B. The probability of a random selected student not being a seventh grader is 4/5.
Solve the absolute value inequality and write the notation for the solution set
Answer:
[tex]x\ge1\text{ or }x\le-4\frac{1}{5}[/tex]Explanation:
Given the absolute inequality:
[tex]|8+5x|\ge13[/tex]Solving the absolute inequality:
[tex]5x+8\ge13\text{ or }5x+8\le-13[/tex]We solve each of the inequality for x:
[tex]\begin{gathered} 5x+8\ge13\text{ or }5x+8\le-13 \\ 5x\ge13-8\text{ or }5x\le-13-8 \\ 5x\ge5\text{ or }5x\le-21 \\ \frac{5x}{5}\ge\frac{5}{5}\text{ or }\frac{5x}{5}\le-\frac{21}{5} \\ \implies x\ge1\text{ or }x\le-4\frac{1}{5} \end{gathered}[/tex]The solution to the absolute inequality are:
[tex]x\ge1\text{ or }x\le-4\frac{1}{5}[/tex]The solution set is given below:
[tex](-\infty,-4\frac{1}{5}\rbrack\cup\lbrack1,\infty)[/tex]Find the amount of interest $450,000 earns in 1 year at a simple interest rate of 3.5%.
ANSWER
$15,750
EXPLANATION
We want to find the interest that is earned from $450,000 in a year at a rate of 3.5%.
To do this, we have to use the formula for Simple Interest:
[tex]SI\text{ = }\frac{P\cdot\text{ R }\cdot\text{ T}}{100}[/tex]where P = principal = $450,000
R = rate = 3.5%
T = time (in years) = 1 year
Therefore, the simple interest is:
[tex]\begin{gathered} SI\text{ = }\frac{450000\cdot\text{ 3.5 }\cdot\text{ 1}}{100} \\ SI\text{ = \$15,750} \end{gathered}[/tex]Which of the following equations describes the line shown below? Check allthat apply.(2,1) (-4,4)
The LCM of 3 and 8 is____
We list the multiples of 3 and 8 and select the common ones.
Then, the least out of those is the LCM (Least Common Multiple).
The first few multiples of "3" and "8" are:
3 - 3, 6, 9, 12, 15, 18, 21, 24, 27, 30 ...
8 - 8, 16, 24, 32, 40 ...
The common multiple is 24 and it is the least.
Thus,
The LCM of 3 and 8 is 24
Answer
24
convert 40,762 ft = _mi_ft
Question: convert 40,762 ft = _mi_ft
Solution:
[tex]40762\text{ ft ( }\frac{0.000189394}{1\text{ ft }}\text{ ) = }7.7200758[/tex]The endpoints of a diameter of a circle are (-3,-2) and (11,-10). What are the coordinates of the center of the circle?
Given:
The endpoints of a diameter of a circle are (-3,-2) and (11,-10).
The objective is to find the coordinates of the center of the circle.
Explanation:
Consider the given coordinates as
[tex]\begin{gathered} (x_1,y_1)=(-3,-2) \\ (x_2,y_2)=(11,-10) \end{gathered}[/tex]The center of the circle must be the midpoint of the diameter of the circle.
Since the coordinates of diameter are given, the midpoint of the coordinates can be calculated as,
[tex](x,y)=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})\text{ . . . . .(1)}[/tex]On plugging the given coordinates in equation (1),
[tex]\begin{gathered} (x,y)=(\frac{-3+11}{2},\frac{-2+(-10)}{2}) \\ =(\frac{8}{2},\frac{-12}{2}) \\ =(4,-6) \end{gathered}[/tex]Hence, the coordinates of the center of the circle is (4,-6).
Solve the equationbelow:71<-Ea+3A qq=1-87B a=16
Solve the equation;
[tex]\begin{gathered} \frac{7}{8}=q+\frac{1}{2} \\ \\ \text{Subtract }\frac{1}{2}\text{ from both sides} \\ \frac{7}{8}-\frac{1}{2}=q+\frac{1}{2}-\frac{1}{2} \\ \text{Take the LCM of the fractions on the left side} \\ \frac{7-4}{8}=q \\ \frac{3}{8}=q \end{gathered}[/tex]The answer is
q = 3/8
Option C is the correct answer
You treated 457 acres of corn land with 2.1 quarts per acre of an herbicide. The herbicide is sold in a 2%-gallon container that costs $93.80.a. How many containers of the herbicide were used?b. What was the cost of the herbicide?
Solution
Part a
We can do the folowing operation:
[tex]457Ac\cdot\frac{2.1qu}{1Ac}=959.7qu[/tex]Then we can use the following conversion: 1gal = 4 quarts
[tex]959.7qu\cdot\frac{1\text{gal}}{4qu}=239.925\text{gal}[/tex]We also know that the herbicide is sold in a 2% gallon container so we can do this:
[tex]239.925\text{gal}\cdot0.2=47.985\text{container}[/tex]Then is possible to see that is neccessary at least 48 containers
Part b
The price would be:
[tex]48\cdot93.80=4502.4[/tex]A triangle shaped Forrest is shaped by roads AB, BC, and CA per attached picture. Find the perimeter using the distance formula.
The perimeter of the triangle is 8.83 km
Explanation:Given:
2) Triangle ABC with sides AB, BC and CA
To find:
The perimeter of the triangle using the distance formula
To determine the perimeter, we need to first find the 3 sides of the triangle. To do this, the distance formula will be used:
[tex]$$dis\tan ce\text{ = }\sqrt[]{(y_2-y_1)^2+(x_2-x_1)^2}$$[/tex]A = (0, 0), B = (3.5, 0) and C = (2, -2)
[tex]\begin{gathered} Distance\text{ AB: A = \lparen0, 0\rparen, B = \lparen3.5, 0\rparen} \\ dis\tan ce\text{ AB = }\sqrt{(0-0)^2+(3.5-0)^2}\text{ = }\sqrt{0\text{ + 12.25}} \\ distance\text{ AB = 3.5} \end{gathered}[/tex][tex]\begin{gathered} Distance\text{ BC: B = \lparen3.5, 0\rparen and C = \lparen2, -2\rparen} \\ dis\tan ce\text{ = }\sqrt{(-2-0)^2+(2-3.5)^2}\text{ = }\sqrt{(-2)^2+(-1.5)^2} \\ distance\text{ = }\sqrt{4\text{ + 2.25}}\text{ = }\sqrt{6.25} \\ distance\text{ = 2.5} \end{gathered}[/tex][tex]\begin{gathered} Distance\text{ CA = C = \lparen2, -2\rparen and A = \lparen0, 0\rparen} \\ dis\tan ce\text{ CA = }\sqrt{(0-(-2))^2+(0-2)^2}\text{ = }\sqrt{(0+2)^2+(-2)^2} \\ distance\text{ CA}=\text{ }\sqrt{4+4}\text{ = }\sqrt{8} \\ distance\text{ CA = 2.83} \end{gathered}[/tex]The perimeter of the triangle = sum of all 3 sides
[tex]\begin{gathered} Perimeter\text{ = AB + BC + CA} \\ Perimeter\text{ of the triangle = 3.5 + 2.5 + 2.83} \\ \\ The\text{ perimeter of the triangle = 8.83 km} \end{gathered}[/tex]50 feetA lawn is in the shape of a trapezoid with a height of40 feet and bases of 50 feet and 150 feet. Howmany bags of fertilizer must be purchased to coverthe lawn if each bag covers 2400 square feet?40 feet150 feet....bags of fertilizer must be purchased to cover the lawn.(Round up to the nearest bag.)
The area of a trapezoid is given by the formula
[tex]A=\frac{a+b}{2}h[/tex]where a and b are the bases, and h is the height.
Therefore, in our case,
[tex]\begin{gathered} a=50,b=150,h=40 \\ \Rightarrow A=\frac{(50+150)}{2}\cdot40=\frac{200}{2}\cdot40=100\cdot40=4000 \\ \Rightarrow A=4000ft^2 \end{gathered}[/tex]The area is equal to 4000ft^2
Finally, divide the total area by the surface one can cover with one bag of fertilizer, as shown below
[tex]\frac{4000}{2400}=\frac{5}{3}\approx1.6666\ldots\approx2[/tex]Therefore, once we have rounded it up, the answer is 2 bags.
Share an observation that you have made in your everyday life where you have noticed that you were getting diminishing marginal returns.
An observation made in your everyday life where you have noticed that you were getting diminishing marginal returns is when the consumption of additional bottle of water will give lesser satisfaction than the first one.
What is marginal return?The marginal return is the rate of return on a marginal increase in investment; generally, it is the additional output resulting from a one-unit increase in the use of a variable input while all other inputs remain constant.
The law of declining marginal returns is an economic theory that states that once an optimal level of capacity is reached, adding another factor of production will result in lesser improvements in output.
In economics, diminishing returns refers to the reduction in marginal output of a production process as the amount of a single factor of production is progressively raised while all other factors of production remain constant.
The inflection point of a return function or the maximum point of the underlying marginal return function is referred to as the point of declining returns.
Learn more about marginal return on:
https://brainly.com/question/22778256
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The numbers of students in the 7 schools are given below. ( Note that these are already ordered from least to greatest.)
a) We know that:
[tex]\overline{x}=\frac{\sum_{i=1}^nx_i}{n}.[/tex]Now, if we change xi by yi and:
[tex]y_i>x_i[/tex]then:
[tex]\frac{\sum_{i\mathop{=}1}^ny_i}{n}>\frac{\sum_{i\mathop{=}1}^nx_i}{n}.[/tex]Therefore, if 179 changes to 305, then the mean increases.
The mean of the given values is:
[tex]\frac{179+193+284+299+308+317+436}{7}=288.[/tex]The mean after change 179 by 305 is:
[tex]\frac{305+193+284+299+308+317+436}{7}=306.[/tex]Also, notice that:
[tex]306-288=18.[/tex]b) The median of the given set is:
[tex]299.[/tex]And the median after change 179 by 305 is:
[tex]305.[/tex]Therefore the median increases by 6.
Answer:
a) It increases by 18.
b) It increases by 6.
In triangle UVW, the measure of W=90°, WU = 35 feet, and UV = 92 feet. Find the measure of ZU to the nearest tenth of a degree.
U = 67.6 degrees
Explanation:The triangle is illustrated below
To find the measure of U, we use:
[tex]\begin{gathered} \cos U=\frac{35}{92} \\ \\ U=\cos ^{-1}(\frac{35}{92}) \\ \\ =67.6 \end{gathered}[/tex]I need help to find the nearest tenth of this triangle. I've been struggling for about 30 minutes now. I will include the photo!
Area of the triangle PQR can be determined as,
[tex]\begin{gathered} \Delta=\frac{1}{2}\times QP\times RS \\ =\frac{1}{2}\times8\text{ cm}\times RP\sin 39^{\circ} \\ =\frac{1}{2}\times8\text{ cm}\times15\operatorname{cm}\times\sin 39^{\circ} \\ =37.759cm^2 \end{gathered}[/tex]Thus, the required area of the triangle to the nearest tenth is 37.8 square centimeters.