For a satellite to orbit Earth at a constant distance, its centrifugal acceleration
must be equal and opposite Earth's gravitational acceleration. If a satellite is
to orbit at a constant distance from Earth at a circular radius of 8,300,000 m,
what is the required velocity of the satellite? (Assume the acceleration due to
Earth's gravity is 5.6 m/s2 at this altitude.)
A. 7043 m/s
B. 8239 m/s
C. 7576 m/s
D. 6818 m/s
If a satellite is to orbit at a constant distance from Earth at a circular radius of 8,300,000, the required velocity of the satellite is 8239m/s.
What is a satellite?
Most spacecraft, with the exception of passive satellites, contain a means of generating electricity for the technology they carry, such as solar panels or radioisotope thermoelectric generators (RTGs). The majority of satellites also feature transponders, which are a type of ground station communication system. The most common satellites, small CubeSats, use a standardised bus to reduce costs and labour. Satellites of a similar type can cooperate with one another to form constellations.To know more about satellite, click the link given below:
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Question number 11 how did we found the answer ?
Answer:
Option A. 57.14 Ω
Explanation:
From the question given above, the following data were obtained:
Resistor 1 (R₁) = 100 Ω
Resistor 2 (R₂) = 400 Ω
Resistor 3 (R₃) = 200 Ω
Equivalent Resistor (Rₚ) =?
The equivalent resistor in the above circuit can be obtained as follow:
1/Rₚ = 1/R₁ + 1/R₂ + 1/R₃
1/Rₚ = 1/100 + 1/400 + 1/200
Find the least common multiple (lcm) of 100, 400 and 200. The result is 400. Divide 400 by 100, 200 and 400 respectively and multiply the result with the numerator as shown
1/Rₚ = (4 + 1 + 2)/400
1/Rₚ = 7/400
Invert
Rₚ = 400/7
Rₚ = 57.14 Ω
The statement "if I raise the temperature of
a cup of water, then an increased amount of
sugar will be dissolved" is an example of
A. an observation
B. a hypothesis.
C. a theory
How do y’all solve this
Answer:
you Subtract
Explanation:
A = 6
B = 6
C = 0
D = 5
9-3= 6
13-7=6
11-11=0
6-1=5
Simple hope it helps
Which graph shows acceleration? A graph of position (meters) versus time (seconds) has a straight line running from 0 seconds 0 meters upward. A graph of position (meters) versus time (seconds) has a concave line running from 0 seconds 0 meters upward. A graph of position (meters) versus time (seconds) has a straight line running from 0 seconds positive number of meters downward to some later time 0 meters.
It's the one that has a concave line running upward.
Answer:
its the middle one
Explanation:
i did it on edge 2021
9.
A 2.85-cm diameter coin is placed a distance of 31.4 cm from a diverging lens that has a focal length
of-11.6 cm. Determine the image distance and the diameter of the image.
Answer:
image distance = -8.47 cm
diameter of the image = 0.769 cm
When measuring volume, your final
result must be in
A. linear units.
B. single units.
C. squared units.
D. cubed units.
A 16 lb weight stretches a spring 6 inches in equilibrium. It is attached to a damping mechanism with constant c. Find all values of c such that the free vibration of the weight has infinitely many oscillations.
Answer:
[tex]-8<c<8[/tex]
Explanation:
Given data:
Weight W = 16 lb
length l = 6/12 = 0.5 ft
hence, spring constant k = W/l = 16/0.5 = 32 lb/ft
The equation of motion of spring is
[tex]mx''+cx+kx=0\\0.5x''+cx'+32x=0[/tex]
the auxiliary equation can be written as
[tex]0.5r^2+cr+32=0\\r^2+2cr+64=0[/tex]
The discriminate of equation is
[tex]D =(2c)^2+-4(1)(64)\\=4(c^2-64)[/tex]
To get the value of the damping constant,
[tex]D<0\\4(c^2-64)<0\\c>-8, c<8\\-8<c<8[/tex]
According to Newton’s second law of motion, weight depends on an object’s mass and the net force acting on the object. True or false
Answer:
true..
Explanation:
Newton's 2nd law of motion is greater the mass of an object the more force it will take to accelerate the object
According to Newton’s second law of motion, weight depends on an object’s mass and the net force acting on the object. The given statement is true.
What is force?Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size, and direction of the body.
The following equation help to understand the statement;
Force is defined as the product of mass and acceleration. Its unit is Newton.
F=ma
F=mg
W=mg
The weight of an item is determined by its mass and the net force exerted on it, according to Newton's second rule of motion. The provided assertion is correct.
Hence,the given statement is true.
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A constant applied force Fp of 11.0 N pushes a box with a mass=7 kg a distance x=15.0 m across a level floor. The coefficient of kinetic friction between the box and the floor is .110. Assuming the box starts from the rest, what is the final velocity vf of the box at 15.0 m point? If there were no friction between the box and the floor, what applied force Fnew would give the box the same final velocity?
We have that for the Question " constant applied force Fp of 11.0 N pushes a box with a mass=7 kg a distance x=15.0 m across a level floor. The coefficient of kinetic friction between the box and the floor is .110." it can be said that
the final velocity vf is
[tex]vf=3.83m/s[/tex]
and the applied force Fnew is
[tex]F_{new}=3.43N[/tex]
From the question we are told
A constant applied force Fp of 11.0 N pushes a box with a mass=7 kg a distance x=15.0 m across a level floor. The coefficient of kinetic friction between the box and the floor is .110. Assuming the box starts from the rest, what is the final velocity vf of the box at 15.0 m point? If there were no friction between the box and the floor, what applied force F new would give the box the same final velocity?
Generally the equation for the Force is mathematically given as
F_p-\mu mg=ma
Therefore
11-0.110*7*9.8=7*a
a=0.49m/s^2
Using Newtons equation
v^2=u^2+2as
v^2=0+2*0.49*15
v=3.83m/s
Therefore
F=ma
F=0.49*7
F_{new}=3.43N
Therefore
the final velocity vf is
[tex]vf=3.83m/s[/tex]
and the applied force Fnew is
[tex]F_{new}=3.43N[/tex]
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what is the main cause of the seasons
a stone on the ground has zero energy why
Explanation:
it has no energy when considered with respect to earth ,as it has neither height (i e potential energy) nor velocity (i.e kinetic energy).
Two vehicles are approaching an intersection. One is a 2600 kgkg pickup traveling at 17.0 m/sm/s from east to west (the −x−x- direction), and the other is a 1300 kgkg sedan going from south to north (the +y−+y− direction at 24.0 m/sm/s ). Part A Find the xx -component of the net momentum of this system. pxpx = nothing kg⋅m/skg⋅m/s SubmitRequest Answer Part B Find the yy-component of the net momentum of this system. pypy = 0 kg⋅m/skg⋅m/s SubmitPrevious AnswersRequest Answer Incorrect; Try Again; 4 attempts remaining Part C What is the magnitude of the net momentum?
Answer:
a) the x-component of the net momentum is 44200 kgm/s [tex](-x)[/tex]
b) the y-component of the net momentum is 31200 kgm/s [tex](y)[/tex]
c) the magnitude of the net momentum is 54102.5 kgm/s
Explanation:
Given the data in the question;
a) x-component of the net momentum of this system.
the second vehicle ( sedan ) doesn't have momentum along x-axis, the momentum along x-axis is strictly contributed by the pick up
so;
Px = 2600 kg × 17.0 m/s [tex](-x)[/tex]
Px = 44200 kgm/s [tex](-x)[/tex]
Therefore, the x-component of the net momentum is 44200 kgm/s [tex](-x)[/tex]
b) y-component of the net momentum of this system
Also, momentum along y-axis is entirely provided by the sedan
Py = 1300 kg × 24.0 m/s [tex](y)[/tex]
Py = 31200 kgm/s [tex](y)[/tex]
Therefore, the y-component of the net momentum is 31200 kgm/s [tex](y)[/tex]
c) magnitude of the net momentum?
magnitude of the net momentum P = √( Px² + Py² )
so we substitute
P = √( (44200)² + (31200)² )
P = √( 2927080000 )
P = 54102.5 kgm/s
Therefore, the magnitude of the net momentum is 54102.5 kgm/s
A knife thrower throws a knife toward a 300 g target that is sliding in her direction at a speed of 2.30 m/s on a horizontal frictionless surface. She throws a 22.5 g knife at the target with a speed of 40.0 m/s. The target is stopped by the impact and the knife passes through the target. Determine the speed of the knife (in m/s) after passing through the target.
Answer:
The speed of the knife after passing through the target is 9.33 m/s.
Explanation:
We can find the speed of the knife after the impact by conservation of linear momentum:
[tex] p_{i} = p_{f} [/tex]
[tex] m_{k}v_{i_{k}} + m_{t}v_{i_{t}} = m_{k}v_{f_{k}} + m_{t}v_{f_{t}} [/tex]
Where:
[tex] m_{k}[/tex]: is the mass of the knife = 22.5 g = 0.0225 kg
[tex] m_{t}[/tex]: is the mass of the target = 300 g = 0.300 kg
[tex] v_{i_{k}}[/tex]: is the initial speed of the knife = 40.0 m/s
[tex] v_{i_{t}} [/tex]: is the initial speed of the target = 2.30 m/s
[tex]v_{f_{k}}[/tex]: is the final speed of the knife =?
[tex] v_{f_{t}} [/tex]: is the final speed of the target = 0 (it is stopped)
Taking as a positive direction the direction of the knife movement, we have:
[tex] m_{k}v_{i_{k}} - m_{t}v_{i_{t}} = m_{k}v_{f_{k}} [/tex]
[tex] v_{f_{k}} = \frac{m_{k}v_{i_{k}} - m_{t}v_{i_{t}}}{m_{k}} = \frac{0.0225 kg*40.0 m/s - 0.300 kg*2.30 m/s}{0.0225 kg} = 9.33 m/s [/tex]
Therefore, the speed of the knife after passing through the target is 9.33 m/s.
I hope it helps you!
Future space rockets might propel themselves by firing laser beams, rather than exhaust gases, out the back. The acceleration would be small, but it could continue for months or years in the vacuum of space. Consider a 1200 kg uncrewed space probe powered by a 15 MW laser. After one year, how far will it have traveled and how fast will it be going
Answer:
Acceleration = 0.0282 m/s^2
Distance = 13.98 * 10^12 m
Explanation:
we will apply the energy theorem
work done = ΔK.E ( change in Kinetic energy ) ---- ( 1 )
where :
work done = p * t
= 15 * 10^6 watts * ( 1 year ) = 473040000 * 10^6 J
( note : convert 1 year to seconds )
and ΔK.E = 1/2 mVf^2 given ; m = 1200 kg and initial V = 0
back to equation 1
473040000 * 10^6 = 1/2 mv^2
Vf^2 = 2(473040000 * 10^6 ) / 1200
∴ Vf = 887918.92 m/s
i) Determine how fast the rocket is ( acceleration of the rocket )
a = Vf / t
= 887918.92 / ( 1 year )
= 0.0282 m/s^2
ii) determine distance travelled by rocket
Vf^2 - Vi^2 = 2as
Vi = 0
hence ; Vf^2 = 2as
s ( distance ) = Vf^2 / ( 2a )
= ( 887918.92 )^2 / ( 2 * 0.0282 )
= 13.98 * 10^12 m
A motorcyclist is moving 24.5 m/s
away from a stationary siren, and
hears an 894 Hz sound. What is
the frequency of the siren when the
cyclist is stationary?
(Hint: 894 Hz is the Doppler-shifted
frequency)
(Speed of sound = 343 m/s)
(Unit = Hz)
w
Answer:962 hz
Explanation: got it right on acellus
The frequency of the siren when the cyclist is stationary will be 963 Hz.
What is frequency ?The frequency of a wave is the number of cycles per second.
FRom the doppler effect,
f =f'[ (V+Vs/V-Vo) ]
Here, doppler shifted frequency f' = 894 Hz, Source is stationary, Vs =0. Velocity of observer Vo = 24.5m/s and velocity of sound wave V = 343m/s
Substitute the value into the expression , we get
f = 894 x [(343/343 - 24.5)}
f = 963 Hz
Thus, the frequency of the siren when the cyclist is stationary is 963 Hz.
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0.5-lbm of a saturated vapor is converted to asaturated liquid by being cooled in a weighted piston-cylinder device maintained at 50 psia. During the phase conversion,thesystem volume decreases by 1.5 ft3; 250 Btu of heat areremoved; and the temperature remains fixed at 15F. Estimatethe boiling point temperature of this substance when itspressure is 60 psia.
Answer:
The boiling point temperature of this substance when its pressure is 60 psia is 480.275 R
Explanation:
Given the data in the question;
Using the Clapeyron equation
[tex](\frac{dP}{dT} )_{sat } = \frac{h_{fg}}{Tv_{fg}}[/tex]
[tex](\frac{dP}{dT} )_{sat } = \frac{\frac{H_{fg}}{m} }{T\frac{V_{fg}}{m} }[/tex]
where [tex]h_{fg[/tex] is the change in enthalpy of saturated vapor to saturated liquid ( 250 Btu
T is the temperature ( 15 + 460 )R
m is the mass of water ( 0.5 Ibm )
[tex]V_{fg[/tex] is specific volume ( 1.5 ft³ )
we substitute
[tex](\frac{dP}{dT} )_{sat } =( \frac{250Btu\frac{778Ibf-ft}{Btu} }{0.5})[/tex] / [tex]( (15+460)\frac{1.5}{0.5})[/tex]
[tex](\frac{dP}{dT} )_{sat } =[/tex] 272.98 Ibf-ft²/R
Now,
[tex](\frac{dP}{dT} )_{sat } =[/tex] [tex](\frac{P_2 - P_1}{T_2 - T_1})_{sat[/tex]
where P₁ is the initial pressure ( 50 psia )
P₂ is the final pressure ( 60 psia )
T₁ is the initial temperature ( 15 + 460 )R
T₂ is the final temperature = ?
we substitute;
[tex]T_2[/tex] [tex]= ( 15 + 460 ) + \frac{(60-50)psia(\frac{144in^2}{ft^2}) }{272.98}[/tex]
[tex]T_2 = 475 + 5.2751\\[/tex]
[tex]T_2 =[/tex] 480.275 R
Therefore, boiling point temperature of this substance when its pressure is 60 psia is 480.275 R
Which wave type could move in the empty space between the Sun and the Earth
Answer:
Electromagnetic waves
two resistors, 5.0 ohm's each can be combined to give an equivalent resistance of
Answer:
2 possible answers:
1# 2.5 Ω (when the resistors are in parallel)
2# 10 Ω (when the resistors are in series)
Explanation:
there are two possible answers for this:
1# if the resistors are in parallel in the circuit
then:
1/R-equivalent=1/5+1/5
1/R-equivalent=2/5
R-equivalent=5/2=2.5 Ω
2# if the resistors are in series in the circuit
then:
R-equivalent=5+5
R-equivalent=10 Ω
Two resistors, 5.0 ohm's each can be combined to give an equivalent resistance of
If connected in series :
R = R1 + R2
R = 5 + 5
R = 10 ohms
If connected in parallel :
R = 1/R1 + 1/R2
R = 1/ 5 + 1/5
= 2 / 5
= 2.5 ohms
What is equivalent resistance ?
"The equivalent resistance is where the aggregate resistance connected either in parallel or series is calculated." Essentially, the circuit is designed either in Series or Parallel. Electrical resistance shows how much energy one needs when you move the charges/current through your devices.
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What would be the mass of an atom with 2 protons and 3 neutrons?
Answer:
5
Explanation:
From the question given above, the following data were obtained:
Proton number = 2
Neutron number = 3
Mass number =.?
The mass number of a given atom is simply the sum of the protons and neutrons in the nucleus of the atom. Mathematically, it is expressed as:
Mass number = proton + neutron
With the above formula, we can obtain the mass number of the atom as follow:
Proton number = 2
Neutron number = 3
Mass number =.?
Mass number = proton + neutron
Mass number = 2 + 3
Mass number = 5
Thus, the mass number the atom is 5.
Which device helps safely transmit electricity from the power plant to your
home?
Answer:
A. Transformer
Explanation:
it’s correct
As amplitude of a wave increases, the
_____ of the wave also increases.
frequency
wave speed
wavelength
energy
i think so it is frequency
1. A temperature of 162 °F is equivalent to what temperature in kelvins?
(a) 373 K
(b) 288 K
(C) 345 K
(d) 201 K (e) 308 K
345k
Because the formula for our Fahrenheit is Kevin = 5 * (°Fahrenheit + 459.67)
9.
Suppose you design an apparatus in which a uniformly charged disk of radius R is to produce an electric field. The field magnitude is most important along the central perpendicular axis of the disk, at a point P at distance 2.00R from the disk. Cost analysis suggests that you switch to a ring of the same outer radius R but with inner radius R/2.00 . Assume that the ring will have the same surface charge density as the original disk. If you switch to the ring, by what percentage will you decrease the electric field magnitude at P?
Answer:
The electric field will be decreased by 29%
Explanation:
The distance between point P from the distance z = 2.0 R
Inner radius = R/2
Outer raidus = R
Thus;
The electrical field due to disk is:
[tex]\hat {K_a} = \dfrac{\sigma}{2 \varepsilon _o} \Big( 1 - \dfrac{z}{\sqrt{z^2+R_i^2}} \Big)[/tex])
[tex]\implies \dfrac{\sigma}{2 \vaepsilon _o} \Big ( 1 - \dfrac{2.0 \ R}{\sqrt{ (2.0\ R)^2+(R)^2}} \Big)[/tex]
Similarly;
[tex]\hat {K_b} = \hat {k_a} - \dfrac{\sigma}{2 \varepsilon_o} \Big( 1 - \dfrac{2.0 \ R}{\sqrt{(2.0 \ r)^2 + (\dfrac{R}{2}^2)}}\Big)[/tex]
However; the relative difference is: [tex]\dfrac{\hat {k_a} - \hat {k_b}}{\hat {k_a} }= \dfrac{E_a -E_a + \dfrac{\sigma}{2 \varepsilon_o \Big[1 - \dfrac{2.0 \ R}{\sqrt{(2.0 \ R)^2 + (\dfrac{R}{2})^2}} \Big] } } { \dfrac{\sigma}{2 \varepsilon_o \Big [ 1 - \dfrac{2.0 \ R}{\sqrt{ (2.0 \ R)^2 + (R)^2}} \Big] }}[/tex]
[tex]\dfrac{\hat {k_a} - \hat {k_b}}{\hat {k_a} }= \dfrac{1 - \dfrac{2.0}{\sqrt{(2.0)^2 + \dfrac{1}{4}}} }{1 - \dfrac{2.0 }{\sqrt{(2.0)^2 + 1}}}[/tex]
[tex]= 0.2828 \\ \\ \mathbf{\simeq 29\%}[/tex]
What do all clouds contain the some amount of
Answer:
A cloud is made up of liquid water droplets. A cloud forms when air is heated by the sun. As it rises, it slowly cools it reaches the saturation point and water condenses, forming a cloud.
Explanation:
Which two criteria are least important for engineers to consider when developing a process to produce an important chemical?
A. The process should be located in a major city.
B. The process should use local, organic reactants.
C. The process should produce a significant amount of the product.
D. The process should be cost-effective.
Answer:
two least important criteria are A and B.
Explanation:
In an industrial production process there are criteria on the location of the production plants. Among the most important criteria we have that a good quantity is produced from the producer and that the process is cost-beneficial - cats to increase the profit of the company.
There are other desirable but minor criteria
A) The size of the city is of minor importance
b) Finding raw material locally is interesting, but its importance is less, the raw material can be sent from other locations.
Consequently the two least important criteria are A and B.
Answer:
A. The process should be located in a major city.
B. The process should use local, organic reactants.
Explanation:
ap.ex
A small car is traveling at a speed of 60 mph on the highway. In the next lane, a large passenger bus is traveling at the same speed.
Answer:
A. The bus has more kinetic energy than the car.
Explanation:
As we know that
Kinetic energy is the amount of energy possessed by the body at the time when it is in motion.
Also,
Kinetic energy = 1 ÷ 2mv²
Here m denotes the mass of the body
and v denotes the velocity of the body.
So it would be based on the mass & velocity of the body
As if the passenger bus contains more kinetic energy as compared to the car because of the big mass
Hence, the first option is correct
(c) A coal-fired power station generates electricity at night when it is not needed.
Some of this energy is stored by pumping water up to a mountain lake. When there is high
demand for electricity, the water is allowed to flow back through turbines to generate electricity.
On one occasion, 2.05 x 108kg of water is pumped up through a vertical height of 500 m.
(i) Calculate the weight of the water.
weight =
[1]
Answer:
ion know tbh
Explanation:
write short note : power
Answer:
In physics, power is the amount of energy transferred or converted per unit time. In the International System of Units, the unit of power is the watt, equal to one joule per second. In older works, power is sometimes called activity. Power is a scalar quantity.
SI unit: watt (W)
Derivations from other quantities: P = E/t; P = F·v; P = V·I; P = τ·ω
In SI base units: kg⋅m2⋅s−3
Answer:
As a student, what are your insights about this lesson? Write an essay on your
toughts about the types of drugs/subtance of abuse, discussing its description and
effects
A 2.60 kg lion runs at a speed of 5.00 m/s until he sees his prey. The lion then speeds up 8.00 m/s to catch it. How much work did do after he speeds up?
Answer: 50.7 J
Explanation:
Given
mass of lion is [tex]m=2.6\ kg[/tex]
The initial speed of the lion is [tex]v_1=5\ m/s[/tex]
increased speed of lion is [tex]v_2=8\ m/s[/tex]
Initially, its kinetic energy is [tex]K_1=\frac{1}{2}mv_1^2[/tex]
Final kinetic energy [tex]k_2=\frac{1}{2}mv_2^2[/tex]
work did by lion after speed up is [tex]k_2-k_1[/tex]
[tex]\Rightarrow W=\dfrac{1}{2}\times 2.6[8^2-5^2]\\\\\Rightarrow W=1.3\times [39]=50.7\ J[/tex]