Explain why a ball thrown in space could keep moving forever, while a ball thrown here on Earth will come to a stop.

Explanation:

George Washington (1789–1797)

John Adams (1797–1801)

Thomas Jefferson (1801–1809)

James Madison (1809–1817)

James Monroe (1817–1825)

John Quincy Adams (1825–1829)

Andrew Jackson (1829–1837)

Martin Van Buren (1837–1841)

William Henry Harrison (1841)

John Tyler (1841–1845)

James K. Polk (1845–1849)

Zachary Taylor (1849–1850)

Millard Fillmore (1850–1853)

Franklin Pierce (1853–1857)

James Buchanan (1857–1861)

Abraham Lincoln (1861–1865)

.

George Washington, the 1st President of the United States

  John Adams, the 2nd President of the United States

 Thomas Jefferson, the 3rd President of the United States

 James Madison, the 4th President of the United States

James Monroe, the 5th President of the United States

John Quincy Adams, the 6th President of the United States

Andrew Jackson, the 7th President of the United States

Martin Van Buren, the 8th President of the United States

William Henry Harrison, the 9th President of the United States

John Tyler, the 10th President of the United States

James K. Polk, the 11th President of the United States

Zachary Taylor  THE 12TH PRESIDENT OF THE UNITED STATES

 Millard Fillmore, the 13th President of the United States

Franklin Pierce, the 14th President of the United States

James Buchanan, the 15th President of the United States

 Abraham Lincoln, the 16th President of the United States

Answer:

the rate of change of velocity per unit of time.

Answer:

accelerate is rate of chang of velocity

Answer:

A. Copper (||) sulfate

Explanation:

just got it right on quizlet

Answer:

Decrease in the object's maximum kinetic energy is caused by loss of energy by the system to its immediate surroundings.

Explanation:

None of the options are correct because for an object spring system, maximum kinetic energy is reduced when the system loses energy to the immediate surrounding.

Thus, decrease in the object's maximum kinetic energy is caused by loss of energy by the system to its immediate surroundings.

Answer:

(a) 0.014 A

(b) 2 V

Explanation:

(a) Applying

V = IR'...................... Equation 1

Where V = Voltge, I = current, R = total resistance.

make I the subject of the equation

I = V/R'................... Equation 2

From the question,

Given: V = 12 V, R' = (122+232+500) ohms (The resistance are connected in series) = 854 ohms

Substitute these values into equation 2

I = 12/854

I = 0.014 A

(b)  Applying

V' = V(R₁)/(R₁+R₂+R₃)...................... Equation 3

Where V' = Voltage across the 100 ohms resistor.

From the question,

V = 12V, R₁ = 100 ohm, R₂ = 200 ohm, R₃ = 300 ohm.

Substitute these values into equation 3

V' = (12×100)/(100+200+300)

V' = 1200/600

V' = 2 V

Answer:

A: An object has potential energy (stored energy) when it is not in motion. Once a force has been applied or it begins to move the potential energy changes to kinetic energy (energy of motion).

Explanation:

Answer:

I think its d matter accreted from a companion star unstable ignites on the surface of a white dwarf.

Answer:

A stormy ocean, having the most kinetic energy means it moves more and faster

Answer:

Explanation:

(a) Electron Emission (Beta- decay):

When an unstable nucleus decays by the emission of Beta- particle, its charge number ‘Z’ increases by 1 but, its mass number ‘A’ remains unchanged. The transformation is represented by the equation:  

[tex]_zX^A\ -------->\ _{Z+1}Y^A\ +\ _{-1}e^0[/tex]

It is called ‘Negative Beta Decay’. It is more common than alpha decay.

Example:

[tex]_6C^{14}\ -------->\ _{7}N^{14}\ +\ _{-1}e^0[/tex]

Note:  

There are no electrons in a nucleus so, with the emission of a particle, one of the neutrons is converted to a proton and an electron.

[tex]_0n^1\ --------->\ _1P^1\ +\ _{-1}e^0[/tex]

(b) Positron Emission (Beta+ decay):

When an unstable nucleus decays by the emission of the positron, its charge number ‘Z’ decreases by 1 but,  its mass number ‘A’ remains unchanged. The transformation is represented by the equation:

[tex]_zX^A\ -------->\ _{Z-1}Y^A\ +\ _{+1}e^0[/tex]

Examples:

[tex]_{15}P^{30}\ -------->\ _{14}Si^{30}\ +\ _{+1}e^0[/tex]

Note:  

Inside the nucleus, only a proton can be transformed into a neutron with the emission of a positron (anti-particle of electron)

[tex]_1P^1\ -------->\ _0n^1\ +\ _{+1}e^0[/tex]

Farenheit is an interesting unit so the conversions get a bit weird.

To convert from Farenheit to Celcius you follow this formula:

T(°C) = (T(°F) - 32) × 5/9

It is also easier to convert to Celcius to Kelvin shown in this formula:

T(K) = T(°C) + 273.15

To Answer your question:

105° F = 40.5°C

-25° F = -31.7°C

105° F = 313.65K

-25° F = 241.45K

The cross-sectional area of the cylindrical copper wire is  1.7 x 10⁻⁹ m².

Resistivity is defined as the amount of electrical resistance of a conductor, per unit cross-sectional area and unit length.

Here,

Resistance of the wire, R = 10 Ω

Length of the wire, l = 1 m

Resistivity of the wire, ρ = 1.7 x 10⁻⁸ Ωm

The expression for the resistivity of a conductor is given as,

ρ = RA/l

where A is the cross-sectional area of the conductor.

Therefore, the area of cross-section of the copper wire,

A = ρl/R

A = 1.7 x 10⁻⁸ x 1/10

A = 1.7 x 10⁻⁹ m²

Hence,

The cross-sectional area of the cylindrical copper wire is  1.7 x 10⁻⁹ m².

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Answer:

Total energy, T= 4704 Joules

Explanation:

Given the following data;

Mass = 8kg

Initial height, h1 = 100m

Final height, h2 = 40 m

We know that acceleration due to gravity is equal to 9.8 m/s².

To find the total energy, T;

T = mg(h1 - h2)

T = 8 * 9.8 * (100 - 40)

T = 78.4 * 60

Total energy, T= 4704 Joules

Answer:

The correct answer is D C A

Answer:

F₁ = 499.61 N , this is the force that Bubba support

Explanation:

The trunk is in equilibrium with the two forces applied by man, let's use the equilibrium relation

let's set a reference frame at the extreme left and assume that the counterclockwise rotations are positive

Let's write the expression for the translational equilibrium

subscript 1 is for Bubba's mass and subscript 2 for his partner

               F₁ + F₂ -W = 0

                F₁ + F₂ = W

the expression for rotational equilibrium

               ∑ τ = 0

               F₁  2.2 + F₂  (6.2-0.9) - W  6.2/2 = 0

               2.2 F1 + 5.3 F2 = 3.1 W

let's write our system of equations

             F₁ + F₂ = W

             2.2 F₁ + 5.3 F₂ = 3.1 W

we solve for F₁ in the first equation and substitute in the second

            F₁ = W-F₂

            2.2 (W- F₂) + 5.3 F₂ = 3.1 W

            F₂ ( -2.2 +5.3) = W (3.1 - 2.2)

            F₂ = 704  0.9 / 3.1            

            F₂ = 204.39 N

This is the force that the partner supports

we look for F1

            F₁ = W-F₂

            F₁ = 704 - 204.39

             F₁ = 499.61 N

This is the force that Bubba support

Answer: 0.553

Explanation:

Answer:

[tex]0.01\ \text{A}[/tex]

[tex]0.0015\ \text{C}[/tex]

[tex]0.0608\ \text{s}[/tex]

Explanation:

[tex]V_0[/tex] = Voltage = 1.5 V

[tex]C[/tex] = Capacitance = [tex]1000\ \mu\text{F}[/tex]

[tex]R[/tex] = Resistance = [tex]150\ \Omega[/tex]

Current is given by

[tex]I=\dfrac{V_0}{R}\\\Rightarrow I=\dfrac{1.5}{150}\\\Rightarrow I=0.01\ \text{A}[/tex]

Current flowing in the resistor is [tex]0.01\ \text{A}[/tex].

Charge is given by

[tex]Q=CV\\\Rightarrow Q=1000\times 10^{-6}\times 1.5\\\Rightarrow Q=0.0015\ \text{C}[/tex]

The charge on the capacitor is [tex]0.0015\ \text{C}[/tex].

Voltage is given by

[tex]V=V_0e^{-\dfrac{t}{RC}}\\\Rightarrow t=-RC\ln\dfrac{V}{V_0}\\\Rightarrow t=-150\times 1000\times 10^{-6}\times\ln\dfrac{1}{1.5}\\\Rightarrow t=0.0608\ \text{s}[/tex]

Time taken to reach 1 V is [tex]0.0608\ \text{s}[/tex].

Explanation:

Given

mass of the rock is 10 kg

Force requires to hold the rock is equal to its weight

Weight is given by the product of mass and acceleration due to gravity

Weight on the earth surface

[tex]\Rightarrow W_e=10\times 9.8\\\Rightarrow W_e=98\ N[/tex]

Weight on the moon surface

[tex]\Rightarrow W_m=1.6\times 10\\\Rightarrow W_m=16\ N[/tex]

So, the force holding the rock on earth is approximately 6 times the force on the moon.

Answer:

1.a

2.b

3.d

4.c

5.d

Explanation:

Track and field is an individual sport. This statement is True.

Track and field is a sport which includes jumping, running, and throwing. it is also know as track and field athletics, or track. This sport is organized in a stadium in which there are running tracks, set up for high jump and long jump and field for throwing. Hence the name is track and field. In this sport different participant participate to get one winner from each game from each weight group. The International Association of Athletics Federations(IAAF) is the international governing body for track and field.

The two most prestigious international track and field competitions are the athletics competition at the Olympic Games and the World Athletics Championships. World Athletics, formerly known as the International Association of Athletics Federations (IAAF),

Hence Track and field is an individual sport.

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Answer:

λ = 266 nm

Explanation:

In this case, we need to determine first the separation of the second fringe from the central maximum. We can determine that with the following expression:

d sinθ = mλ   (1)

However, as the slits are very narrow, we can assume that sin θ ≈ θ and so θ = x/l

Replacing this in (1) we have:

d(x/l) = mλ

and solving for x:

x = mλl / d    (2)

Where:

x: separation of the 2nd fringe from the central maximum

m: order of the fringe

λ: wavelength of light

l: distance of the screen

d: distance between the slits

All the units must be in meters (m), so we can convert the units first or during the resolution. In this case, we'll do it in the resolution. Replacing the given data, we have:

x = 2 * (520 nm * 1m/10⁻⁹ nm) * 1.6 m / (0.66 mm * 1m/1000 mm)

x = 0.00252 m or just 2.52 mm

With this value, we can compute or determine the separation of the 2nd order fringe of the unknown light in the central maximum:

x₂ = 2.52 - 1.23 = 1.29 mm or 0.00129 m

Now, using (2) we can solve for λ:

λ = dx / ml   (3)

Replacing we have:

λ = (0.00129 * 0.0066) / (2 * 1.6)

Hope this helps

Answer:

v = 4.233  m/s

Explanation:

By applying the rate of boiling from [tex]Q= mL_v[/tex];

the rate of the boiling can be described as:

[tex]\mathcal{P} = \dfrac{Q}{\Delta t} \\ \\ \mathcal{P} = \dfrac{mL_v}{\Delta t}[/tex]

The mode of the steam (water vapor) as an ideal gas can be illustrated by formula:

[tex]P_oV_o = nRT[/tex] --- (1)

where;

n = number of moles;

[tex]n = \dfrac{mass (m)}{Molar mass (M)}[/tex]

Then; equation (1) can be rewritten as:

[tex]P_oV_o = (\dfrac{m}{M}) RT \\ \\ \dfrac{P_oV}{\Delta T} = \dfrac{m}{\Delta t} ( \dfrac{RT}{M})[/tex]

∴

[tex]\dfrac{m}{\Delta t} = \dfrac{\mathcal{P}}{L_v}[/tex]

Then:

[tex]P_o \times A \times v= \dfrac{\mathcal{P}}{L_v}\Big ( \dfrac{RT}{M }\Big)[/tex]

making (v) the subject of the formula:

[tex]v= \Big ( \dfrac{\mathcal{P} RT}{M\times L_v \times P_o \times A }\Big)[/tex]

Given that:

[tex]\mathcal{P}[/tex] = 0.90  kW = 900 W

R(rate constant) = 8.314 J/mol.K

Temperature at 100° C = 373K

molar mass= 18.015 g/mol ≅ 0.0180 kg/mol

Latent heat of vaporisation [tex]L_v[/tex] = 2.26 × 10⁶ J/kg

Atmospheric pressure [tex]P_o = 1.013 \times 10^6 \ N/m^2[/tex]

Cross sectional area A =1.60 cm² = 1.60 × 10⁻⁴ m²

[tex]v= \Big ( \dfrac{900 W (8.314 \ J/mol.K)(373)}{0.0180 \ kg/mol) (2.26 \times 10^6 \ J/kg) (1.013 \times 10^5 \ N/m^2)(1.60 \times 10^{-4} \ m^2)}\Big)[/tex]

v = 4.233  m/s

Answer:

A step down transformer is a device that can be connected to the switch and the appliance. There are two types of transformers that you should know about: step up and step down transformers. Step up transformers generally produce a higher output voltage than the input voltage.

Explanation:

60

because mass of an object never change

but weight can change for example if it's

mass is 60kg 5he wieght will be 60kg * 9.8m/s²

=588N

B. The wavelength of the wave

Answer:

c

Explanation:

units c mark me brainless k

Answer:

Explanation:

1. All screws give the same M.A.

False - it depends on screw size and threads

2. A screw does its job by moving.

True - as far as screw as a machine

3. A screw with more threads has a smaller M.A.

False - more threads increase output force i.e. higher MA

4. Screws can be used to move things. *

True

Answer:

Explanation:

1. false

2. true

3. false

4. true