Answer:
1. Cr₂O₇²−(aq) + 14H+ (aq) + 6e- ---->⟶2 Cr³+(aq) + 7H₂O (l)
2. CrO₄²− (aq)⟶+ 4H+ (aq) + 3e- ---> Cr(OH)₄ −(aq)
3. Bi³+ (aq) + 3H₂O (l) ---> BiO₃− (aq) + 6 H+ (aq) + 2 e-
4. CIO −(aq)⟶+ 2H+ (aq) + 2e- ---> Cl −(aq) + H₂O
Explanation:
The given equations are redox reaction equations expressed as as half reactions.
The first step is to identify whether the half-reaction is oxidation reduction.
Then the number of electrons gained or lost are added on the right side of the equation.
Appropriate H+ ions and water molecules are added where necessary since the reaction takes place in acidic environment
The atoms of elements involved in the reaction are balanced by adding the correct coefficients.
1. (acidic) Cr2O7 2−(aq)⟶Cr 3+(aq)
The half-reaction is reduction as the oxidation number of chromium changes from +6 to +3. Two Cr⁶+ ions accepts 3 electrons each to form Cr³+ ions
Cr₂O₇²−(aq) + 6e- ---->⟶2 Cr³+(aq)
Cr₂O₇²−(aq) + 14H+ (aq) + 6e- ---->⟶2 Cr³+(aq) + 7H₂O (l)
2. (acidic) CrO₄²− (aq)⟶---> Cr(OH)₄ −(aq)
The half-reaction is a reduction. One Cr⁶+ accepts 3 electrons to become Cr³+
CrO₄²− (aq)⟶+ 3e- ---> Cr(OH)₄ −(aq)
CrO₄²− (aq)⟶+ 4H+ (aq) + 3e- ---> Cr(OH)₄ −(aq)
3, (acidic) Bi³+ (aq)⟶---> BiO₃− (aq)
The half-reaction is an oxidation. One Bi³+ ion gives up two electrons to become Bi⁵+
Bi³+ (aq)⟶---> BiO₃− (aq) + 2e-
Bi³+ (aq) + 3H₂O (l) ---> BiO₃− (aq) + 6 H+ (aq) + 2 e-
4. (acidic) CIO −(aq)⟶---> Cl −(aq)
The half-reaction is a reduction. One Cl+ ion accepts two electrons to become Cl- ion.
CIO −(aq) + 2e-⟶---> Cl −(aq)
CIO −(aq)⟶+ 2H+ (aq) + 2e- ---> Cl −(aq) + H₂O
A beaker contains 0.125 L of a 3.00 M solution. If the volume goes up to 0.325 L, what is the new molarity?
Answer:
1.15 M
Explanation:
Step 1: Given data
Initial volume (V₁): 0.125 LInitial concentration (C₁): 3.00 MFinal volume (V₂): 0.325 LFinal concentration (C₂): ?Step 2: Calculate the final concentration of the solution
We want to prepare a dilute solution from a concentrated one by adding water. We can calculate the concentration of the dilute solution using the dilution rule.
C₁ × V₁ = C₂ × V₂
C₂ = C₁ × V₁/V₂
C₂ = 3.00 M × 0.125 L/0.325 L = 1.15 M
How did Robert Millikan's oil drop experiment change scientists' view of the
atom?
A. It identified the location of the nucleus.
B. It showed that atoms could not be divided into smaller particles.
C. It identified the charge on a single electron.
D. It showed that atoms were found in different energy levels.
SUBMIT
Answer:
Hello There!!
Explanation:
I think the answer is possibly C. It identified the charge on a single electron.
hope this helps,have a great day!!
~Pinky~
[tex]\huge{\textbf{\textsf{{\color{navy}{An}}{\purple{sw}}{\pink{er}} {\color{pink}{:}}}}}[/tex]
C. It identified the charge on a single electron.
ThanksHope it helpsPart A
How many moles of chlorine gas are needed to make 0.6 moles of sodium chloride?
Given the reaction: 2Na + Cl2 + 2NaCl
O 1.2
O 0.6
0 3.6
O 0.3
not enough information
Submit
Request Answer
Answer:
[tex]n_{Cl_2}=0.3molCl_2[/tex]
Explanation:
Hello there!
In this case, according to the given chemical reaction whereas the sodium chloride is in a 2:1 mole ratio with chlorine, the required moles of the later are computed as shown below:
[tex]n_{Cl_2}=0.6molNaCl*\frac{1molCl_2}{2molNaCl}[/tex]
So we cancel out the moles of NaCl to obtain:
[tex]n_{Cl_2}=0.3molCl_2[/tex]
Best regards!
How many joules of energy are required to vaporize 13.1 kg of lead at its normal boiling point?
Answer: 1123000 Joules of energy are required to vaporize 13.1 kg of lead at its normal boiling point
Explanation:
Latent heat of vaporization is the amount of heat required to convert 1 mole of liquid to gas at atmospheric pressure.
Amount of heat required to vaporize 1 mole of lead = 177.7 kJ
Molar mass of lead = 207.2 g
Mass of lead given = 1.31 kg = 1310 g (1kg=1000g)
Heat required to vaporize 207.2 of lead = 177.7 kJ
Thus Heat required to vaporize 1310 g of lead =[tex]\frac{177.7}{207.2}\times 1310=1123kJ=1123000J[/tex]
Thus 1123000 Joules of energy are required to vaporize 13.1 kg of lead at its normal boiling point
The nature particle model of matter describe the property of solid, liquid and gas in molecular level. Which of the given statements below is TRUE?
A. Matter is made up of large particles.
B. Particles of matter have spaces between them.
C. Particles of matter are not moving all the time.
D. The particles of matter do not attract each other.
Answer:
B. Particles of matter have spaces between them.
Explanation:
The particle nature model of matter is an model used to explain the properties and nature of matter. The statements of the particle nature model of matter are as follows :
1. Matter is made of small particles of atoms or molecules.
2. The particles of matter have space between them. The spaces between the particles are least in solids as they are closely packed together but are greatest in gases whose particles are far apart from each other.
3. The particles of matter are in constant motion at all times. Solids particles are not free to move due to strong molecular forces between the particles, but are constantly vibrating in their mean positions. Liquid particles free to move due to lesser molecular forces while gas molecules which have negligible intermolecular forces have the greatest ability to move.
4. The particles of matter are attracted to each other by intermolecular forces. These forces are greatest in solids and least in gases.
The correct option is B.
Is a cold and b is warm? Please help
Answer:
Label A shows cold area on the mug, while label B shows a warm area.
Explanation:
Have a good day
What is the phase label on HCl?
A. g
B. aq
C.
D. e
E. s
Answer:
B. aq if the reaction is inorganic (double or single displacement), neutralization, etc.
Explanation:
Hello there!
In this case, unfortunately we are not given the undergoing chemical reaction; however, in the most of the double displacement, neutralization, precipitation and in general, inorganic reactions, the hydrochloric acid must be B. aq as it must be dissolved in water as the reaction media. On the other hand, in some organic reactions, it can be either aqueous or gaseous, the latter, specially as a product. For that reason, you will need to make sure whether your reaction is organic or inorganic to correctly figure out the phase label.
Best regards!
What is the ratio by atoms of elements present in hafnium phosphite?
1:3:4
3:6:2
3:4:12
1:6:15
3:6:2 is the correct answer
How many grams of CuSO4 are required to make a 5.0 ml solution that has a concentration of 400 mg/ml?
Answer: molecular weight of CUSO4 or grams. The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles CUSO4, or 346.10221 grams. Note that rounding errors may occur, so always check the results.
Explanation:
Draw curved arrows to show electron reorganization for the mechanism step below. (For a resonance-stabilized anion, draw a single resonance form with the negative charge on oxygen, not on carbon.) Make the ends of your arrows specify the origin and destination of reorganizing electrons.
Answer:
Explanation:
Dear student, this question appears to be incomplete but in the diagram attached below, I have carefully drawn out the required organic structure.
The aim of this question is to show the mechanism of the given structure and to point out the resonance structure.
The first diagram shows the complete part (i.e. the structure of the organic compound) and its major product(answer).
The second diagram shows the mechanism by which we arrived at the major product.
From the second diagram attached below, the -oxo substituent of the methanol attacks the hydrogen atom as shown below, leading to the formation of the enolate ion (a resonance stabilized anion).
However, this is because the alpha carbon attaches to the hydrogens readily leaves as H⁺ to yield an enolate ion as a result of -C- that is doubly bonded to oxygen (an Electron withdrawing group).
Kindly check out the images attached below to see the mechanism.
- Calculate the Standard Enthalpy of the reaction below:
NH3(g) + HCI (g) → NH4Cl(s)
Using the following Enthalpy of Reactions:
2HCI(g) → H2(g) + Cl2(g)
AH = +184.6 KJ
2H2(g) + 1/2 N2(g) + 1/2 Cl2(g) → NH4Cl(s) deltaH = -314.4 kJ
N2(g) + 3 H2(g) → 2 NH3(g)
deltaH = +184.6 kJ
Answer:
Explanation:
We have the three equations:
[tex]NH_{3(g)} + HCl_{(g)} => NH_4Cl_{(s)} ..... \Delta H = ? (1)\\2HCl_{(g)} => H_{2(g)} + Cl_{2(g)} .... \Delta H = +184.6 kJ (2)\\2H_{2(g)} + 1/2N_{2(g)} + 1/2Cl_{2(g)} => NH_4Cl_{(s)} ..... \Delta H = -314.2 kJ (3)\\ N_{2(g)} + 3H_{2(g)} => 2NH_{3(g)} .... \Delta H = +184.6kJ (4)[/tex]
(can you double check that it is 184.6kJ for both equations 2 and 4 because it seems unlikely). We need to solve for equation 1 by addition and changing equations 2, 3 and 4. After possibly some trial and error, we can find that if we flip equations 4, multiply equation 3 by 2, add the equations together, and then finally divide by 2, we can get equation 1. We will get the answer of -314.2 kJ. However, I am again skeptical about the delta H values for equation 2 and 4 so double check that. This method might be super confusing and it is really hard to explain. So what I would suggest you to watch videos on Hess' law.
The table shows characteristics of two plants, Plant A and Plant B.
Answer:
Plant A
Explanation:
A chemist titrates 0.200 M NaOH, strong base, with 50.00 ML of 0.150 M HCI, strong acid. How many mL of NaOH will be required to titrate to the endpoint
[tex](normality \: of \: acid)×(volum \: of \: acid) = (normality \: of \: base)×(volum \: of \: base)[/tex]
0.15N × 50mL = 0.2N × (Vbase)
75mL = Volum of base
37.5mL of NaOH will be required to titrate 0.200 M NaOH, strong base, with 50.00 ML of 0.150 M HCI, strong acid to the endpoint.
How to calculate volume?The volume of a solution can be calculated using the following formula:
C1V1 = C2V2
Where;
C1 = initial concentrationC2 = final concentrationV1 = initial volumeV2 = final volumeC1 = 0.200MC2 = 0.150MV1 = ?V2 = 50mL0.2 × V1 = 0.150 × 50
0.2V1 = 7.5
V1 = 7.5/0.2
V1 = 37.5mL
Therefore, 37.5mL of NaOH will be required to titrate 0.200 M NaOH, strong base, with 50.00 mL of 0.150 M HCI, strong acid to the endpoint.
Learn more about volume at: https://brainly.com/question/26416088
How are gas giants different from each other
Answer:there different from the rocky like planets gas giants don't have such a firm surface like rocky terrestrial planets
Explanation:
explain the significance
Answer:
Dictionary
Definitions from Oxford Languages
Search for a word
significance
/sɪɡˈnɪfɪk(ə)ns/
Learn to pronounce
noun
1.
the quality of being worthy of attention; importance.
"adolescent education was felt to be a social issue of some significance"
Similar:
importance
import
noteworthiness
consequence
substance
seriousness
gravity
weight
weightiness
magnitude
moment
momentousness
memorableness
unforgettableness
pronounced nature
remarkableness
outstanding nature
markedness
obviousness
conspicuousness
strikingness
distinction
impressiveness
uncommonness
unusualness
rarity
extraordinariness
exceptionalness
specialness
cruciality
Opposite:
insignificance
2.
the meaning to be found in words or events.
"the significance of what was happening was clearer to me than to her"
Similar:
meaning
sense
signification
import
thrust
drift
gist
burden
theme
implication
tenor
message
essence
substance
relevance
If you dilute 18.8 mL of a 3.5 M solution to make 296.6 mL of solution, what is the molarity of the dilute solution?
Answer:
0.22M
Explanation:
We will be using the law of dilutions. We are simply increasing the amount of solvent to create a larger volume of solution.
So: moles before dilution = moles after dilution & [tex]moles_{concentrated} = moles_{dilute}[/tex]. And M = moles/liter of solution, so if we express this as moles = M x [tex]L_{soln}[/tex].
That is how we derive the formula we will be using: [tex]M_{concentrated} * Vol_{conc} = M_{dilute} * Vol_{dilute}[/tex]
or
[tex]M_{1} * Vol_{1} = M_{2} * Vol_{2}[/tex]
Applying this formula to our problem, we can substitute the variables with the given values to find the molarity of the dilute solution.
M1 = 3.5M
V1 = 18.8mL
M2 = ?
V2 = 296.6mL
Equation: (3.5M)(18.8mL) = (296.6mL)(M2)
==> 65.8M*mL = 296.6mL * M2
==> M2 = (65.8 M*mL)/296.6mL
==> M2 = 0.22M
A gas in a sealed container has a pressure of 125 atm at a temperature of 303 K. If the pressure in the container is increased to 200 atm, what is the new temperature if the volume remains constant?
(Show work pls :)!)
Answer:
[tex]T_2=484.8K[/tex]
Explanation:
Hello there!
In this case, according to the the variable temperature and pressure and constant volume, it turns out possible for us to calculate the new temperature via the Gay-Lussac's law as shown below:
[tex]\frac{T_2}{P_2} =\frac{T_1}{P_1}[/tex]
Thus, by solving for the final temperature, T2, we obtain:
[tex]T_2 =\frac{T_1P_2}{P_1}[/tex]
So we plug in the given data to obtain:
[tex]T_2 =\frac{303K*200atm}{125atm}\\\\T_2=484.8K[/tex]
Best regards!
3. Convert the word equations below to symbolic:
Sodium + chlorine sodium chloride
• Calcium + bromine ---- calcium bromide
• Potassium + water → potassium hydroxide + hydrogen
ot
Answer:
1)2Na + Cl2 ----> 2NaCl
2)Ca + Br2 ---->CaBr2
3)K + H2O -----> KOH + H2
calculate the percentage of CL in AL(CLO3)3
Answer:
46.41%
Explanation:
Find the total r.m.m of AL(CLO3)3 put it equals to 100%.....The take 106.5,the total r.m.m of Cl and find the missing which is the percentage by cross multiplication
the desity of gold is 19.3 g/cm3. what is the volume of a 13 g gold nugget .
Answer:
0.67 cm³
Explanation:
We can solve this problem by using the definition of density:
Density = Mass / VolumeWe can rearrange the equation and isolate volume:
Volume = Mass / DensityAs we are given both the mass and the density, we can now calculate the volume:
Volume = 13 g ÷ 19.3 g/cm³Volume = 0.67 cm³Calculate the pH of a solution with [H+] = 1.8 x 10^-5 M
Answer:
4.74
Explanation:
pH= -log[H+]
pH= -log(1.8 x 10^-5)= 4.74
how we can remove temporary hardness of water?and write the chemical reaction?
Answer:
it can be removed
1. by boiling
Ca(HCO3)2 > CaCO3 + H2O +CO2
2. by treating with calcium hydroxide
A motorcycle that travels north 201m in 7s. What is it's velocity?
7. D=
8. TE
9. V=
Express each of the following answers in the IUPAC format. Do not include any capitals or spaces in your name. Separate multiple substituent numbers using a comma. Use a hyphen between numbers and names. (ex: 1,2-dichloro-3-methylcyclopentane). Part A Spell out the full name of the molecule. Part B Spell out the full name of the molecule. Part C Spell out the full name of the molecule. Part D Spell out the full name of the molecule.
The full question is shown in the image attached
Answer:
See explanation
Explanation:
In naming an alkane, the first thing we do is to obtain the parent chain by counting the number of carbon atoms in the chain.
When we obtain that, then we identify the substituents and number them in such a way that they have the lowest numbers. The compounds shown have the following names according to the order in which the structures appear in the image attached;
1. 2-methyl propane
2. 2,4-dimethyl heptane
3. 2,2,3,3-tetramethyl butane
4. 5-ethyl-2,4-dimethyl octane
select two correct answers
Answer:
D and E
Explanation:
The other answers don't support steel, they support iron or are supporting both, and the question is why steel alloys are more often used
C supports both
B supports how iron's strength
A supports iron being easily shaped and bent
hope this helps
What is the highest occupied level of Carbon
Answer:
Highest occupied level of carbon is 3
Explanation:
its called Alkynes
Explanation:
4trust me!#carryonlearning❤Due today! Why is it a good idea to have floating cities?
A: We are running out of land
B: We need it for pollution cleanup
C: Oceans are rising
D: It's a sustainable way to live
Answer:
in my opinion I think the answer the be "A"
2 CO + O2 → 2 CO2, how many grams of oxygen is required to produce 1.0 mole of CO2?
Answer:
16 g
Explanation:
Step 1: Write the balanced equation
2 CO + O₂ → 2 CO₂
Step 2: Calculate the moles of O₂ required to produce 1.0 moles of CO₂
The molar ratio of O₂ to CO₂ is 1:2.
1.0 mol CO₂ × 1 mol O₂/2 mol CO₂ = 0.50 mol O₂
Step 3: Calculate the mass corresponding to 0.50 moles of O₂
The molar mass of O₂ is 32.00 g/mol.
0.50 mol × 32.00 g/mol = 16 g
Identify the term that matches each electrochemistry definition.
a. The electrode where reduction occurs ___________
b. An electrochemical cell powered by a spontaneous redox reaction ___________
c. The electrode where oxidation occurs__________
d. An electrochemical cell that takes in energy to carry out a nonspontaneous redox reaction ____________
e. A chemical equation showing either oxidation or reduction ___________
Answer: a. Cathode
b. Galvanic cell
c. Anode
d. Electrolytic cell
e. half reaction
Explanation:
Galvanic cell or Electrochemical cell is defined as a device which is used for the conversion of the chemical energy produced in a spontaneous redox reaction into the electrical energy.
Electrolytic cell is a device where electrical energy is used to drive a non spontaneous chemical reaction.
In the electrochemical cell, the oxidation occurs at an anode which is a negative electrode and the reduction occurs at the cathode which is a positive electrode. Thus the electrons are produced at anode and travel towards cathode.
The balanced two-half reactions will be:
Oxidation half reaction : [tex]M\rightarrow M^{n+}+ne^-[/tex]
Reduction half reaction : [tex]N^{n+}+ne^-\rightarrow N[/tex]
Thus the overall reaction will be: [tex]M+N^{n+}\rghtarrow M^{n+}+N[/tex]
Try moving an electron from the metal to the non metal.What happens?
Answer:
Sodium becomes a positive ion and chlorine becomes a negative ion. ... Each atom is neutrally charged, which means that each atom has the same number of protons and electrons.
Explanation: