we have the expression
y^3-5y^2+3y-15
Grouping terms
(y^3-5y^2)+(3y-15)
factor y^2
y^2(y-5)+(3y-15)
factor 3
y^2(y-5)+3(y-5)
factor (y-5)
(y-5)[y^2+3]Is the number -3.7 a natural number, a whole number, an integer, a rational number, an irrational number or a real number?
ANSWER
Rational number and Real number
EXPLANATION
We want to identify what type of number -3.7 is.
A natural number is a number that is a positive integer, used in counting things. Examples are 4, 7 and 55.
A whole number is a number that is used in counting, including 0 i.e. natural numbers including 0.
An integer is a whole number but the difference is that an integer can be positive, negative or zero.
A rational number is a number that can be expressed as a fraction of two integers i.e. a/b while an irrational number is one that cannot be expressed as a fraction of two integers.
A real number is any number that can be found as a distance between two points on the number line.
From the definitions above, we see that we can classify -3.7 as a rational number and a real number.
It is not a natural number, whole number, irrational number or an integer.
Find all numbers whose absolute value is .4]
The numbers 4 and - 4 have an absolute value equal to 4.
What numbers are associated to a given absolute value?
In this question we need to find all the numbers such that absolute value is equal to 4. This can be found by using the definition of absolute value:
|x| = x for x ≥ 0.|x| = - x for x < 0.Absolute values are functions that contains only the magnitudes of the numbers, that is, their distances with respect to zero. Then, if the absolute value is 4, then, the number may be 4 or - 4.
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The absolute value is 4, then, the number may be 4 or - 4.
What are Absolute values?Absolute value describes the distance from zero that a number is on the number line, without considering direction
To find all the numbers such that absolute value is equal to 4.
By definition of absolute value we have
|x| = x for x ≥ 0.
|x| = - x for x < 0.
Absolute values contains magnitude which does not have direction.
|4|=4 for 4≥ 0.
|4| = -4 for x < 0.
Then, if the absolute value is 4, then, the number may be 4 or - 4.
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need help with this as soon as possible, answer quick
Answer:
Given points are,
A'(2,3) and A(3,-4), under the translation.
we get the graph as,
where B is A(3,-4) and A is A'(2,3).
A translation by 1 unit left and 7 units up.
Answer is:
A translation by 1 unit left and 7 units up.
Not everyone pays the same price for the same model of a car that the figure is the streets a normal distribution for the price paid for the particular model of a new car the meanest $24,000 and a standard deviation is $1000 user 68–95-99.7 Raw to find a percentage of buyers who paid more than $27,000
The Solution:
The correct answer is 0.15%
Given the data in the given question,
We are required to find the percentage of buyers who paid more than $27,000.
The percentage of the total buyers is 100%
The percentage of buyers that paid between $21,000 and $27,000 is given to be 99.7%
This means that the total percentage of buyers who paid less than $21,000 and the buyers who paid more than $27,000 is
[tex]100-99.7=0.3\text{ \%}[/tex]Since the distribution is a normal distribution, it follows that half of 0.3% is the percentage of buyers who paid more than $27,000.
[tex]\frac{0.3}{2}=0.15\text{ \%}[/tex]Thus, the percentage of buyers who paid more than $27,000 is 0.15%
Find the slope of the line that goes through the given points.
(-3,-2) and (– 15,13)
Answer:
Answer:
Slope m= [tex]-\frac{5}{4}[/tex]
As a decimal:
m = -1.25
Step-by-step explanation:
[tex]m=\frac{Rise}{Run} =\frac{y}{x} \\m=\frac{y2-y1}{x2-x1} \\m=\frac{13--2}{-15--3} \\m=\frac{15}{-12} \\m=-\frac{5}{4}[/tex]
What kind of transformation converts the graph of f(x)=(5x+6)^2 into the graph of g(x)=-(5x+6)^2
In order to get from
[tex]f(x)=(5x+6)^2[/tex]To
[tex]f(x)=-(5x+6)^2[/tex]You have to reflect across the x-axis.
Remember that the x-axis is the line with equation
[tex]y=0[/tex]Answer: Option A
I I need help solving problem number 8 please :)
Answer:
(8, -1)
Explanation:
Given the below system of equations;
[tex]\begin{gathered} y^2+x^2=65\ldots\ldots\ldots\text{.Equation 1} \\ y+x=7\ldots\ldots\ldots\ldots\text{.Equation 2} \end{gathered}[/tex]Let's go ahead and test each of the given solutions and see which of them is the correct one;
For (8, -1), we have x = 8 and y = -1;
Substituting the above values in Equation 1, we have;
[tex]\begin{gathered} (-1)^2+(8)^2=65 \\ 1+64=65 \\ 65=65 \end{gathered}[/tex]Substituting the values into Equation 2;
[tex]\begin{gathered} (-1)+8=7 \\ -1+8=7 \\ 7=7 \end{gathered}[/tex]We can see that (8, -1) is a solution to the given system of equations
1. A train moves at a constant speed and travels 6 miles in 4 minutes. What is its speed in miles per minute? d/t = r time distance t d 4 mins. 6 miles
Answer: 1.5 miles / minute
Given that:
Distance travelled = 6
Time = 4 minutes
Speed = Distance / time
Speed = 6 / 4
1.5 mile / minute
Please find the coordinates and graph the points on the graph and rotate the image.Please demonstrate the pre image and the rotated image on the graph after finding the coordinates.
We have that the general rule for a counterclockwise rotation of 270 degrees is given by the following expression:
[tex]R_{270}(x,y)=(y,-x)[/tex]then, in this case,we have the following:
[tex]\begin{gathered} R_{270}(4,5)=(5,-4)=D^{\prime} \\ R_{270}(6,-2)=(-2,-6)=E^{\prime} \\ R_{270}(1,-2)=(-2,-1)=F^{\prime} \end{gathered}[/tex]and the graph would look like this:
which is the new equation written in the slope-intercept form
he slope-intercept form is
y = mx + c
here, m = slope of the line and C is intercept on y axis.
Benny is flying a kite directly over his friend Frank, who is 125 meters away.When he holds the kite string down to the ground, the string makes a 39° anglewith the level ground. How high is Benny's kite?Draw a sketch depicting the situation above.b.)Use trigonometry to determine the height of Benny's kite.
Solution
Let us draw a diagram to illustrate the information
Using SOHCAHTOA
[tex]\begin{gathered} tan\theta=\frac{opposite}{adjacent} \\ \\ tan39=\frac{h}{125} \\ cross\text{ multiply} \\ h=125\times tan39 \\ \\ h=101.2230041 \\ \\ h=101.22m\text{ \lparen to two decimal places\rparen} \end{gathered}[/tex]helpppppppppp!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:f(x) = 1/4x
Step-by-step explanation:
Assuming this is a linear equation, we simply use the two points given to find the slope (or gradient depending on where you’re from), to find the equation. So just do rise over run:
Edited: I divided backwards, apologies!
-3 - (-2)/-8 - (-12) = -5/-20 = 1/4x.
These figures are similar. Thearea of one is given. Find thearea of the other.area=32 in?9 in12 in[ ? Jina
To find the area of similar figures whe you know the area of one of the figures and the length of corresponding sides:
1. Find the scale factor: in this case as you have the area of the largest figure find the scale factor for a reduction:
[tex]SF=\frac{small}{\text{big}}=\frac{9}{12}=\frac{3}{4}[/tex]2. Find the missing area: the area in similar figures is equal to the scale factor squared multiplied by the given area.
[tex]\begin{gathered} A=(\frac{3}{4})^2\cdot32in^2 \\ \\ A=(\frac{9}{16})\cdot32in^2 \\ \\ A=\frac{288}{16}in^2 \\ \\ A=18in^2 \end{gathered}[/tex]Then, the missing area is 18 square inchesGraph the inequality. Then write the solution set in interval notation.
Representing intervals as we are doing for your question means we will represent all the possible values of x. To do that we will colour in blue all possible values of x but there is a detail we must to consider. The limits of the interval. for that we have two symbols, [ that means "closed on the value" and ( that means "opened on the value". So if there is a [ on a number it means that number makes part of the interval, but if there is a ( it means that number is not in the interval.
Now, for our inequality we have
Once x can be equal or superior to 2 it means 2 is part of the interval because x can be this value, but x is inferior to 8 but it can not be 8 so 8 is not on the interval. Once we know that, know we can represent our interval as follows:
And that is our final answer.
For an interval notation we can write [2,8).
y= 3(x-3)^2-12E) Find two more points on The Graph. You can choose what x-values to use. Write your points as coordinates x y
Given:
[tex]y=3(x-3)^2-12[/tex]The quadractic equation above is written in vertex form:
[tex]y=a(x-h)^2+k[/tex]Where:
(h, k) is the coordinate of the vertex of the parabola
We have
a = 3
h = 3
k = -12
Let's find the following:
A.) Identify the coefficients, a, h, and k
Comparing the equation with the vertex form, we have:
a = 3
h = 3
k = -12
B.) Identify whether the graph opens up or opens down.
If a is greater than zero, then the graph opens up
If a is less than zero, then the graph opens downwards
Here, a = 3
Since a is greater than zero, the graph opens up.
The graph of the equation opens up
C.) Find the vertex.
The coordinates of the vertex is = (h, k)
Given:
h = 3
k = -12
Therefore, the vertex is: (3, -12)
D.) Find the axis of symmetry.
The axis of symmetry is the line that passes through the vertex and the focus.
To find the axis of symmetry we have:
x = h
where h = 3
Thus, the axis of symmetry is:
x = 3
E.) Let's find two more points.
Point 1 ==> (x, y)
Let's take x = 1
Substitute 1 for x and solve for y:
[tex]\begin{gathered} y=3\mleft(x-3\mright)^2-12 \\ \\ y=3(1-3)^2-12 \\ \\ y=3(-2)^2-12 \\ \\ y=3(4)-12 \\ \\ y=12-12 \\ \\ y=0 \end{gathered}[/tex]When x is 1, y is 0.
Therefore, we have the point:
(x, y) ==> (1, 0)
Point 2:
Let's take x = 2
Substitute 2 for x and solve for y:
[tex]\begin{gathered} y=3\mleft(x-3\mright)^2-12 \\ \\ y=3(2-3)^2-12 \\ \\ y=3(-1)^2-12 \\ \\ y=3(1)-12 \\ \\ y=3-12 \\ \\ y=-9 \end{gathered}[/tex]When x is 2, y is -9.
Therefore, we have the points:
(x, y) ==> (2, -9)
ANSWER:
A.) a = 3
h = 3
k = -12
B.) The graph opens up
C.) (3, -12)
D.) x= 3
E.) (1, 0), (2, -9)
Simplify.1,5m^7(-4m^50^2A. -6m^14B. 24m^17C. 24m^14D. 12m^17There is a picture too if you need it.
The expression can be simplified as,
[tex]\begin{gathered} 1.5m^7(-4m^5)^2 \\ =1.5m^7(16m^{10}) \\ =24m^{17} \end{gathered}[/tex]Thus, option (b) is the correct solution.
A pair of bikes cost $89.99 and the sales tax is 8%.What is the total cost of the shoes including tax?
Answer
Total Cost of the bike including tax = $97.1892
Explanation
Cost of the bike = $89.99
Sales Tax = 8% of Cost of bike = 8% (89.99) = 0.08 (89.99) = $7.1992
Total Cost of the bike = (Cost of the bike) + (Sales Tax)
= 89.99 + 7.1992
= $97.1892
Hope this Helps!!!
3 Drag each equation to the correct location on the table. Determine the number of solutions to each equation. Then place each equation in the box that corresponds to its number of solutions. 35 = 2+ +1 2 – 1 = 45 + 3 31 – 2 35 + 1 2x + 3 = 35 – 1 1 2x + 1 = 21 No Solutions 1 Solution 2 Solutions Reset Next All rights reserved. i NE
Then, it has just 1 solution, and it should be placed in the second column.
[tex]\begin{gathered} 2^x-1=4^x+3. \\ \text{This has no solution} \end{gathered}[/tex][tex]\begin{gathered} 3x-2=3^x+1 \\ \text{This has no solution.} \end{gathered}[/tex]Next;
[tex]\begin{gathered} \frac{1}{2}x+3=3^x-1 \\ \text{This has no solution. It should be in the first column} \end{gathered}[/tex][tex]\begin{gathered} 2x+1=2^x \\ \text{Let x=0,} \\ 2(0)+1=2^0=1 \end{gathered}[/tex]This has one solution, and it should be placed in the second column.
I need help with this Tyler’s mom purchased a saving bond for Tyler. The value of the savings bond increases by 4% each year one year after it was purchased, the value of the savings bond was $156.00 find the value of the bond when Tyler’s mom purchased it. Explain your reason
Let x = value of the bond when Tyler’s mom purchased it.
After one year, this value increased by 4%. This new value is calculated as follows:
[tex]\text{new value = }x\cdot1.04[/tex]The new value is $156.00, then
[tex]\begin{gathered} 156.00=x\cdot1.04 \\ \frac{156.00}{1.04}=x \\ 150.00=x \end{gathered}[/tex]The value of the bond was $150.00 when Tyler’s mom purchased
Which of the following shapes is the cross-section for a cylinder?A. SquareB. TriangleC. CircleD. Pentagon
Solution:
Concept:
The vertical cross-section of a cylinder is a rectangle, and the horizontal cross-section is a circle.
From the explanation above,
The final answer is CIRCLE
OPTION C is the right answer
5. A baker makes 275 wheat rolls.
He fills 9 boxes with 24 rolls in
each box. How many rolls are
not in boxes?
Answer:
59 rolls are not in boxes
Step-by-step explanation:
9×24=216-275=59
Use any strategy to determine a combination of apples
and pineapples that will balance the scale.
Explain how you know it will balance.
1 Pine- apple equal to 9 Apples.
What is Ratio proportion?The divisional comparison of two quantities yields a ratio, and the equality of two ratios yields a proportion.
A ratio is commonly written as "x: y," though it can also be read as "x is to y" or "x/y."
In terms of comparison, a proportional equation says that two ratios are equal.
When x: y: z: w is used to represent a ratio, it is understood to mean that x is to y as z is to w.
In this case, w and Y are not equal to 0, therefore x/y Equals z/w.
6 Apples = 4 Pomegranates
6 Pomegranates = 1 Pine- apple
1 Pine- apple = 9 Apples.
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Finding a time to reach the limit in a word problem on exponential growth or decay
We are told that each year the value of the laptop is 75% of the value of the value of the previous year. This means that every year the current value of the laptop is multiplied by 0.75. Then if v is the original value of the laptop its value after t years is given by:
[tex]V(t)=v0.75^t[/tex]We need to find after which year V(t) is equal to 500 or less then we have V(t)≤500 and since the original value of the laptop was 4200 we have v=4200:
[tex]4200*0.75^t\leq500[/tex]We divide both sides by 4200:
[tex]\begin{gathered} \frac{4200\times0.75^t}{4200}\leqslant\frac{500}{4200} \\ 0.75^t\leq\frac{5}{42} \end{gathered}[/tex]Then we apply the logarithm to both sides:
[tex]\log_{10}(0.75^t)\leqslant\log_{10}(\frac{5}{42})[/tex]Then we use the property of logarithm regarding exponents:
[tex]\begin{gathered} \operatorname{\log}_{10}(0.75^{t})\leqslant\operatorname{\log}_{10}(\frac{5}{42}) \\ t\log_{10}(0.75)\leq\operatorname{\log}_{10}(\frac{5}{42}) \end{gathered}[/tex]And we divide both sides by the logarithm of 0.75 (we change the inequality symbol because log(0.75) is negative):
[tex]\begin{gathered} \frac{t\operatorname{\log}_{10}(0.75)}{\operatorname{\log}_{10}(0.75)}\ge\frac{\log_{10}(\frac{5}{42})}{\operatorname{\log}_{10}(0.75)} \\ t\ge\frac{\log_{10}(\frac{5}{42})}{\operatorname{\log}_{10}(0.75)} \end{gathered}[/tex]Then we get:
[tex]t\ge7.398[/tex]So the laptop's value is less than $500 after 7.398 years.
AnswerSince we are requested to write a whole number as the answer and the smallest whole number that is bigger than 7.398 is 8 we have that the answer is 8 years.
write the linear equation that passes through the two given points (2,-2) and (0,-1)
Given the points:
(x1, y1) ==> (2, -2)
(x2, y2) ==> (0, -1)
To find the linear equation, use the form:
y = mx + b
where m is the slope.
To find the slope, use the formula below:
[tex]m=\frac{y2-y1}{x2-x1}[/tex]Thus, we have the slope as:
[tex]m=\frac{-1-(-2)}{0-2}=\frac{-1+2}{0-2}=\frac{1}{-2}=-\frac{1}{2}[/tex]Input 2 for x, -2 for y, and -1/2 for b to find b.
[tex]\begin{gathered} -2=-\frac{1}{2}(2)+b \\ \\ -2=-1+b \\ \\ -2+1=b \\ \\ -1=b \end{gathered}[/tex]Therefore, the linear equation is:
[tex]y=-\frac{1}{2}x-1[/tex]ANSWER:
[tex]y=-\frac{1}{2}x-1[/tex]kenny has red marbles, 3 blue marbles,and 4 black marbes. Which ration compares a part to the whole? Please help me
A ratio comparing a part to the whole must then have 9 as the second number.
In this question, we have been given Kenny has red marbles, 3 blue marbles, and 4 black marbles.
We need to find the ratio that compares a part to the whole.
Here, the total number of marbles are:
2 red + 3 blue + 4 black = 9 marbles.
Let x be either number of marbles (either red marbles or blue marbles or black marbles)
Then the ratio that compares a part to the whole would be,
x : 9
Therefore, a ratio comparing a part to the whole must then have 9 as the second number.
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write each percent as a decimal 1%
You have the following percentage:
24.1%
In order to determine the associated decimal to this fraction you proceed as follow:
2625÷32 long division way
Answer: 82 R1 or decimal form 82.031
Step-by-step explanation:
0082
. --------
-0
26
. - 0
. 262
. -256
65
-64
. 1
A building worth $829,000 is depreciated for tax purposes by its owner using the straight-line depreciation method.
The value of the building, y, after x months of use, is given by y=829,000-2700x dollars. After how many years will
the value of the building be $699,400?
The value of the building would be $699,400 in 4 years.
What will be the value of the building?Depreciation is the when the value of an asset reduces as a result of wear and tear. Straight line depreciation is a method used in depreciating the value of an asset linearly with the passage of time.
The equation that can be used to determine the value of the building with a straight line depreciation is:
Value of the asset = initial value of the asset - (number of months x deprecation rate)
y = 829,000 - 2700x
The first step is to determine the number of months it would take for the building to have a value of $699,400.
$699,400 = 829,000 - 2700x
829,000 - 699,400 = 2,700x
129,600 = 2,700x
x = 129,600 / 2,700
x = 48 months
Now convert, months to years
1 year = 12 months
48 / 12 = 4 years
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the product of 4 and the diference of 9 and 2 find the value of your expression
Answer:
28
Step-by-step explanation:
4(9-2)
4(7)
28
an alloy contains copper and zinc in the ratio 3:7. find the mass of the metal in 750g of alloy
Given:
An alloy contains copper and zinc in a ratio of 3:7. The total mass of the alloy is 750g.
Required:
Find the mass of the metal in 750g of alloy.
Explanation:
Let the mass of the metal is x gm.
The weight of copper = 3x
The weight of zinc= 7x
Total weight
[tex]\begin{gathered} 3x+7x=750 \\ 10x=750 \\ x=\frac{750}{10} \\ x=75\text{ gm} \end{gathered}[/tex]