Factorize Completely​

Answer:Answer and Explanation:

When a number is said to be 'to the fourth power,' that just means that you need to multiply the number by itself four times. For example, 7 to the...

Step-by-step explanation:

The solution to each of the question takes different approach, as the questions are taken from different concepts; however, a common operation among all questions, is factorization.

[tex](1)\ (-xy)^3(xz)[/tex]

Expand

[tex](-xy)^3(xz) = (-x)^3* y^3*(xz)[/tex]

[tex](-xy)^3(xz) = -x^3* y^3*xz[/tex]

Rewrite as:

[tex](-xy)^3(xz) = -x^3*x* y^3*z[/tex]

Apply law of indices

[tex](-xy)^3(xz) = -x^4y^3z[/tex]

[tex](2)\ (\frac{1}{3}mn^{-4})^2[/tex]

Expand

[tex](\frac{1}{3}mn^{-4})^2 =(\frac{1}{3})^2m^2n^{-4*2}[/tex]

[tex](\frac{1}{3}mn^{-4})^2 =\frac{1}{9}m^2n^{-8[/tex]

[tex](3)\ (\frac{1}{5x^4})^{-2}[/tex]

Apply negative power rule of indices

[tex](\frac{1}{5x^4})^{-2}= (5x^4)^2[/tex]

Expand

[tex](\frac{1}{5x^4})^{-2}= 5^2x^{4*2}[/tex]

[tex](\frac{1}{5x^4})^{-2}= 25x^{8[/tex]

[tex](4)\ -x(2x^2 - 4x) - 6x^2[/tex]

Expand

[tex]-x(2x^2 - 4x) - 6x^2 = -2x^3 + 4x^2 - 6x^2[/tex]

Evaluate like terms

[tex]-x(2x^2 - 4x) - 6x^2 = -2x^3 -2x^2[/tex]

Factor out x^2

[tex]-x(2x^2 - 4x) - 6x^2 = (-2x-2)x^2[/tex]

Factor out -2

[tex]-x(2x^2 - 4x) - 6x^2 = -2(x+1)x^2[/tex]

[tex](5)\ \sqrt{\frac{4y}{3y^2}}[/tex]

Divide by y

[tex]\sqrt{\frac{4y}{3y^2}} = \sqrt{\frac{4}{3y}}[/tex]

Split

[tex]\sqrt{\frac{4y}{3y^2}} = \frac{\sqrt{4}}{\sqrt{3y}}[/tex]

[tex]\sqrt{\frac{4y}{3y^2}} = \frac{2}{\sqrt{3y}}[/tex]

Rationalize

[tex]\sqrt{\frac{4y}{3y^2}} = \frac{2}{\sqrt{3y}} * \frac{\sqrt{3y}}{\sqrt{3y}}[/tex]

[tex]\sqrt{\frac{4y}{3y^2}} = \frac{2\sqrt{3y}}{3y}[/tex]

[tex](6)\ \frac{8}{3 + \sqrt 3}[/tex]

Rationalize

[tex]\frac{8}{3 + \sqrt 3} = \frac{3 - \sqrt 3}{3 - \sqrt 3}[/tex]

[tex]\frac{8}{3 + \sqrt 3} = \frac{8(3 - \sqrt 3)}{(3 + \sqrt 3)(3 - \sqrt 3)}[/tex]

Apply difference of two squares to the denominator

[tex]\frac{8}{3 + \sqrt 3} = \frac{8(3 - \sqrt 3)}{3^2 - (\sqrt 3)^2}[/tex]

[tex]\frac{8}{3 + \sqrt 3} = \frac{8(3 - \sqrt 3)}{9 - 3}[/tex]

[tex]\frac{8}{3 + \sqrt 3} = \frac{8(3 - \sqrt 3)}{6}[/tex]

Simplify

[tex]\frac{8}{3 + \sqrt 3} = \frac{4(3 - \sqrt 3)}{3}[/tex]

[tex](7)\ \sqrt{40} - \sqrt{10} + \sqrt{90}[/tex]

Expand

[tex]\sqrt{40} - \sqrt{10} + \sqrt{90} =\sqrt{4*10} - \sqrt{10} + \sqrt{9*10}[/tex]

Split

[tex]\sqrt{40} - \sqrt{10} + \sqrt{90} =\sqrt{4}*\sqrt{10} - \sqrt{10} + \sqrt{9}*\sqrt{10}[/tex]

Evaluate all roots

[tex]\sqrt{40} - \sqrt{10} + \sqrt{90} =2*\sqrt{10} - \sqrt{10} + 3*\sqrt{10}[/tex]

[tex]\sqrt{40} - \sqrt{10} + \sqrt{90} =2\sqrt{10} - \sqrt{10} + 3\sqrt{10}[/tex]

[tex]\sqrt{40} - \sqrt{10} + \sqrt{90} =4\sqrt{10}[/tex]

[tex](8)\ \frac{r^2 + r - 6}{r^2 + 4r -12}[/tex]

Expand

[tex]\frac{r^2 + r - 6}{r^2 + 4r -12}=\frac{r^2 + 3r-2r - 6}{r^2 + 6r-2r -12}[/tex]

Factorize each

[tex]\frac{r^2 + r - 6}{r^2 + 4r -12}=\frac{r(r + 3)-2(r + 3)}{r(r + 6)-2(r +6)}[/tex]

Factor out (r+3) in the numerator and (r + 6) in the denominator

[tex]\frac{r^2 + r - 6}{r^2 + 4r -12}=\frac{(r -2)(r + 3)}{(r - 2)(r +6)}[/tex]

Cancel out r - 2

[tex]\frac{r^2 + r - 6}{r^2 + 4r -12}=\frac{r + 3}{r +6}[/tex]

[tex](9)\ \frac{4x + 8}{x^2} \cdot \frac{x}{x^2 - 5x - 14}[/tex]

Cancel out x

[tex]\frac{4x + 8}{x^2} \cdot \frac{x}{x^2 - 5x - 14} = \frac{4x + 8}{x} \cdot \frac{1}{x^2 - 5x - 14}[/tex]

Expand the numerator of the 2nd fraction

[tex]\frac{4x + 8}{x^2} \cdot \frac{x}{x^2 - 5x - 14} = \frac{4x + 8}{x} \cdot \frac{1}{x^2 - 7x+2x - 14}[/tex]

Factorize

[tex]\frac{4x + 8}{x^2} \cdot \frac{x}{x^2 - 5x - 14} = \frac{4x + 8}{x} \cdot \frac{1}{x(x - 7)+2(x - 7)}[/tex]

Factor out x - 7

[tex]\frac{4x + 8}{x^2} \cdot \frac{x}{x^2 - 5x - 14} = \frac{4x + 8}{x} \cdot \frac{1}{(x + 2)(x - 7)}[/tex]

Factor out 4 from 4x + 8

[tex]\frac{4x + 8}{x^2} \cdot \frac{x}{x^2 - 5x - 14} = \frac{4(x + 2)}{x} \cdot \frac{1}{(x + 2)(x - 7)}[/tex]

Cancel out x + 2

[tex]\frac{4x + 8}{x^2} \cdot \frac{x}{x^2 - 5x - 14} = \frac{4}{x} \cdot \frac{1}{(x - 7)}[/tex]

[tex]\frac{4x + 8}{x^2} \cdot \frac{x}{x^2 - 5x - 14} = \frac{4}{x(x - 7)}[/tex]

[tex](10)\ (3x^3 + 15x^2 -21x) \div 3x[/tex]

Factorize

[tex](3x^3 + 15x^2 -21x) \div 3x = 3x(x^2 + 5x -7) \div 3x[/tex]

Cancel out 3x

[tex](3x^3 + 15x^2 -21x) \div 3x = x^2 + 5x -7[/tex]

[tex](11)\ \frac{m}{6m + 6} - \frac{1}{m+1}[/tex]

Take LCM

[tex]\frac{m}{6m + 6} - \frac{1}{m+1} = \frac{m(m + 1) - 1(6m + 6)}{(6m + 6)(m + 1)}[/tex]

Expand

[tex]\frac{m}{6m + 6} - \frac{1}{m+1} = \frac{m^2 + m- 6m - 6}{(6m + 6)(m + 1)}[/tex]

[tex]\frac{m}{6m + 6} - \frac{1}{m+1} = \frac{m^2 - 5m - 6}{(6m + 6)(m + 1)}[/tex]

[tex](12)\ \frac{\frac{1}{y - 3}}{\frac{2}{y^2 - 9}}[/tex]

Rewrite as:

[tex]\frac{\frac{1}{y - 3}}{\frac{2}{y^2 - 9}} = \frac{1}{y - 3} \div \frac{2}{y^2 - 9}[/tex]

Express as multiplication

[tex]\frac{\frac{1}{y - 3}}{\frac{2}{y^2 - 9}} = \frac{1}{y - 3} * \frac{y^2 - 9}{2}[/tex]

Express y^2 - 9 as y^2 - 3^2

[tex]\frac{\frac{1}{y - 3}}{\frac{2}{y^2 - 9}} = \frac{1}{y - 3} * \frac{y^2 - 3^2}{2}[/tex]

Express as difference of two squares

[tex]\frac{\frac{1}{y - 3}}{\frac{2}{y^2 - 9}} = \frac{1}{y - 3} * \frac{(y - 3)(y+3)}{2}[/tex]

[tex]\frac{\frac{1}{y - 3}}{\frac{2}{y^2 - 9}} = \frac{1}{1} * \frac{(y+3)}{2}[/tex]

[tex]\frac{\frac{1}{y - 3}}{\frac{2}{y^2 - 9}} = \frac{y+3}{2}[/tex]

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Answer:

x = 24.4°

Hope this helps... Have a good day!!

Answer:

16

Step-by-step explanation:

2 (l+b)​

Let l=5 and b=3

2 (5+3)​

Parentheses first

2(8)

Multiply

16

Answer:

16

Step-by-step explanation:

Plug in:

2 (l + b)

2 (5 + 3)

2 (8)

 16

Hope this helped.

There are at most 4 distinct absolute values of elements taken from this sequence. (If there were at least 5 distinct absolute values, then you could pick [tex]a_i,a_j,a_k,a_\ell,a_m[/tex] each with different absolute values, but that would contradict the given statement "for every five indices ... at least two of ... have the same absolute value".)

The pigeonhole principle then says that 2 of any 5 numbers taken from this sequence have the same absolute value. Both |x| = x and |-x| = x, so there can be at most 8 distinct numbers in the sequence.

Answer:

A = 15

B = -3

Step-by-step explanation:

3 ,7,11..... You add 4 each time so 11+4 is 15

12,7,2.... You take 5 each time so 2-5 is -3

Answer:

6/5

Step-by-step explanation:

8/15 - (-2/3)

8/15 + 2/3

24 + 30/45

54/45 = 6/5

Thus, the difference between 8/15 and -2/3 is 6/5

Start by changing the minus a negative to plus a positive.

So we have 8/15 + 2/3.

To add these two fractions together, we need a common denominator.

The common denominator is simply the

least common multiple for the two denominators.

You should find that the least common multiple is 15.

Since 8/15 already has 15 as its denominator, leave it.

To get a denominator of 15 in 2/3, we multiply top

and bottom of 2/3 by 5 to get 10/15.

So we have 8/15 + 10/5.

This simplifies to 18/15.

Now reduce to get 6/5.

Answer:

9

Step-by-step explanation:

6x=2*x*(a number), (a number)^2=the number we need. A number=3, the number is 3^2=9

Answer:

20boys and 15girls

Step-by-step explanation:

Let no of boys be 4x

no of girls be 3x

4x+3x=35

7x=35

x=35/7

x=5

no of boys=4×5=20

no of girls=3×5=15

20+15=35 students

Answer:

4

plug in -1 for all the x's

3 + 2 + 7 = 12 (remeber that -1 *-1 = + 1 and that -2*-1 = + 2

-2+ 5 = + 3

12/3 = 4

Step-by-step explanation:

Answer:

The answer is B.

I think I answered the wrong answer.

Answer:

9 hours

11 hours

19 hours

Step-by-step explanation:

The graph represents the percentage of battery life remaining after a certain number of hours is attached below.

At which times could Rory's phone have been plugged into the charger? Select three options.

6 hours

9 hours

11 hours

14 hours

19 hours

Answer: From the graph, the line segment with negative slope (that is decreasing value) shows that the phone is not plugged but being used while the line segment with positive slope (increasing value) or stays at 100% shows that the phone is plugged to the charger.

As shown, from 0 to 8 hours their is a decreasing value, the phone is not plugged. From 8 to 10 hours their is an increasing value therefore the phone is plugged also from 10 to 12 hours the phone is plugged since it is constant. From 12 to 16 hours it is not plugged. From 16 to 18 hours it is plugged and from 18 to 20 hours it is plugged.

From the options it is plugged at 9 hours, 11 hours and 19 hours

Answer:

B - 9 HOURS

C - 11 HOURS

E - 19 BHOURS

Step-by-step explanation:

i took the test

Answer:

18z + 24

Step-by-step explanation:

The distributive property is the multiplication of the number outside the parenthesis with the numbers inside.

All you need to do to solve this is to multiply 6 with 3z, and 6 with 4.

6 × 3 = 18 =

18z

6 × 4 = 24

Put them together:

18z + 24

Another way to do this:

Answer:

f(x)^-1(x) =sqrt(x+5) -6

Step-by-step explanation:

f(x) = (x + 6)^2 - 5

y =  (x + 6)^2 - 5

Exchange x and y and solve for y

x = (y + 6)^2 - 5

Add 5 to each side

x+5 =  (y + 6)^2 - 5+5

x+5 =  (y + 6)^2

Take the square root of each side

sqrt(x+5 )= sqrt( (y + 6)^2 )

sqrt(x+5 )=(y + 6)

Subtract 6 from each side

sqrt(x+5 ) -6=y + 6-6

sqrt(x+5) -6 = y

Answer:

1 [tex]\frac{1}{6}[/tex] pounds of candy

Step-by-step explanation:

Add together the fractions by creating a common denominator of 6:

[tex]\frac{5}{6} + \frac{1}{3}[/tex]

[tex]\frac{5}{6} + \frac{2}{6}[/tex]

= [tex]\frac{7}{6}[/tex]

Simplify into a mixed fraction:

= 1 [tex]\frac{1}{6}[/tex]

So, the girls had 1 [tex]\frac{1}{6}[/tex] pounds of candy

Answer:

is it 2

Step-by-step explanation:

Answer:

U in the line x=-2: (-4,0)

U in the line x=-1: (-2-0)

Step-by-step explanation:

...............

Answer:

Hey there!

11 meters is about 36 feet tall.

Let me know if this helps :)

Answer:

you answer is :33.8328

Let the no be x

ATQ

[tex]\\ \sf\longmapsto 6x+11=17[/tex]

[tex]\\ \sf\longmapsto 6x=17-11[/tex]

[tex]\\ \sf\longmapsto 6x=6[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{6}{6}[/tex]

[tex]\\ \sf\longmapsto x=1[/tex]

Answer:

1

Step-by-step explanation:

let the number be x

and solve it

Answer:

[tex]5x^3\sqrt{6}[/tex]

Step-by-step explanation:

We need to simplify

[tex]\sqrt{3x^4}\times\sqrt{5x^2}\times\sqrt{10}[/tex]

Right away we can take out the perfect squares. Remember a perfect square is the result of multiplying any value by itself.

[tex]= x^2\sqrt{3}\times x\sqrt{5}\times\sqrt{10} \\= x^3\sqrt{3\times 5 \times 10}\\= x^3\sqrt{3 \times 5 \times 5 \times 2 }\\= 5x^3\sqrt{6}[/tex]

The square root of 3x⁴ times square root of 5x² times square root of 10, the product of all the term is,  5x³ [tex]\sqrt{6}[/tex]

In mathematics, square roots is a concept in which, if we multiply square roots of any number by itself then it will give us an original number.

if 'a' is square root of 'b' then it will represent as, a = √b.

Given that,

three terms,

[tex]\sqrt3{x^{4} }[/tex]

[tex]\sqrt{5x^{2} }[/tex]

[tex]\sqrt{10}[/tex]

by multiplying all the three terms,

⇒ [tex]\sqrt3{x^{4} }[/tex] × [tex]\sqrt{5x^{2} }[/tex] × [tex]\sqrt10} }[/tex]

⇒  √(3x⁴×5x²10)

⇒   √ 150x⁶

⇒     5x³ [tex]\sqrt{6}[/tex]

Hence, the product is   5x³ [tex]\sqrt{6}[/tex]

To know more about square root check:

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Answer:

Jenny´s age is 19 and her mother is 43.

Step-by-step explanation:

Given that

x + 2x + 5 = 62

where,

x = Jenny’s age

Now the following cases occured

a.  

x = 12

Now put the x value to the above equation

12 + 2(12) + 5 = 62

12 + 24 + 5 = 62

41 = 62

It is not equaled so the Jenny age is not 12

b.

x = 15

Now put the x value to the above equation

12 + 2(15) + 5 = 62

15 + 30 + 5 = 62

50 = 62

It is not equaled so the Jenny age is not 15

c.  

x = 18

Now put the x value to the above equation

18 + 2(18) + 5 = 62

18 + 36 + 5 = 62

59 = 62

It is not equaled so the Jenny age is not 12

d.

x = 19

Now put the x value to the above equation

19 + 2(19) + 5 = 62

19 + 38 + 5 = 62

62 = 62

It is equaled so the Jenny age is 19

Now the mother age is

as we know that

x + y = 62

19 + y = 62

y = 62 - 19

= 43

Also it proved that if we doubles the jenny age i.e 38 and then add 5 so the total is 43 i.e. equivalent to her mother age

-2x + 8 = 3x + 14

-2x - 3x = 14 - 8

-5x = 6 / : (-5)

x = -1,2

Answer: x = -6/5

Step-by-step explanation:

Given equation

-2x + 8 = 3x + 14

Subtract 3x on both sides

-2x + 8 - 3x = 3x + 14 - 3x

-5x + 8 = 14

Subtract 8 on both sides

-5x + 8 - 8 = 14 - 8

-5x = 6

Divide -5 on both sides

-5x / -5 = 6 / -5

[tex]\boxed{x = -\frac{6}{5} }[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Answer:

79°

Step-by-step explanation:

PQO is straight angle with measure of 180°

the given angles' sum makes 101° and we need 79 to complete it to 180° therefore the angle STQ = 79°

Answer:

B

Step-by-step explanation:

if it is shaded under than it is <

the slope is 1/2x so that is the answer

Answer:

40-b

Step-by-step explanation:

x is the unknown number

x+b = 40

We want to find x

Subtract b from each side

x+b-b = 40 -b

x = 40-b

The unknown number is 40-b

Answer:

[tex]\huge \boxed{40-b}[/tex]

Step-by-step explanation:

[tex]\sf Let \ x \ be \ that \ number.[/tex]

[tex]x+b=40[/tex]

[tex]\sf Solve \ for \ x.[/tex]

[tex]\sf Subtract \ b \ from \ both \ sides.[/tex]

[tex]x+b-b=40-b[/tex]

[tex]\sf Simplify \ the \ equation.[/tex]

[tex]x=40-b[/tex]

Answer:

pair3

Step-by-step explanation:

it is when they have same number of sides .

Answer:

1 and 3.

Step-by-step explanation:

Pair 1 and pair 3.

If we reposition one of them we see that it exactly fits onto the other.

Answer:

y =  4  or y = 6

Step-by-step explanation:

2log4y - log4 (5y - 12) = 1/2

​2log_4(y) - log_4(5y-12) = log_4(2)           apply law of logarithms

log_4(y^2) + log_4(1/(5y-12)) = log_4(/2)    apply law of logarithms

log_4(y^2/(5y-12)) = log_4(2)                     remove logarithm

y^2/(5y-12) = 2                                            cross multiply

y^2 = 10y-24                                                  rearrange and factor

y^2 - 10y + 24 = 0

(y-4)(y-6) = 0

y= 4 or y=6

Hi there! Hopefully this helps!

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Q1: (For what)"Will you find the number of combinations?"

Answer: (I unfortunately don't understand this very well so I'm giving it my best, and take this with a grain of salt.) I will be able to find combinations using a school cafeteria!

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Q2: "List at least three categories to consider."

My choices:

Answer: Fruits, Vegetables, Protein.

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Q3: "List the choices within each category."

Answer:

Fruits: Apples, Bananas, and Grapes.

Vegetables: Cauliflower, Carrot, and Corn.

Protein: Green beans, Salmon, and Almonds.

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Q4: "Assign each choice a symbol. Ex. juice = (diamond shape)"

Answer:

Fruits: Apples, Bananas, and Grapes.

Vegetables: Cauliflower✨, Carrot, and Corn.

Protein: Green beans, Salmon, and Almonds.

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Q5: "Create a tree diagram to determine the number of combinations available."

(I'm not very familiar with a tree diagram so here is my interpretation at the bottom.)

(You can rewrite this and do it your way if you want).

Q6: "List all possible combinations and count the total number of possibilities."

There are 27 combinations possible!

All of my possible combinations:

The last image below is for Qestion 5.

Answer:

Option C

Step-by-step explanation:

Options A, B, C, and D all satisfy the base case of V(0) = 10; however, they also all fail the next step case of V(4) = 452.

A at t = 4, results in 163047.361

B at t = 4, results in 1770

C at t = 4, results in 450 (close but not 452)

D at t = 4, results in 41740124.42

Note that at option C, we had the closet value 450 which is only 2 from 452 whereas the next closet was 1218 away.

Choose option C as the curve of best fit.

Cheers.

Answer:

c

Step-by-step explanation:

[tex](6x - 5) + (4x^2- 3x + 4)=\\6x-5+4x^2-3x+4=\\4x^2+3x-1[/tex]