U=GM m /r is the formula for the potential energy of a system that includes the Earth and an object orbiting the planet.
How much does the gravitational potential energy ?U=GM m /r is the formula for the potential energy of a system that includes the Earth and an object orbiting the planet.
G stands for gravity constant.
The Earth's mass is M.
m is the object's mass.
r is the separation between the item and the center of the Earth.
Here it is:
M = 5.98-10(24) kg, where m = 102 kg is the object's mass.
The object's distance from the center of the Earth is given by the formula r = 2R.
is the radius of the Earth
when substituting
U = -3.19 - 10 (9) J
The object's combined potential and kinetic energies make up its total mechanical energy:
where
the mechanical energy is E.
The potential energy is U.
K stands for kinetic energy.
E = U +K
E = 0 in this case because we want the item to have no energy, which results in kinetic energy of K = -U = 3.19- 10 (9) J.
The object's kinetic energy can be represented as where m = 102 kg is its mass and v is its speed.
And solving for v, we find:
r = 7909 m/s
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I need answers, do your thing,
Theres also a question at the bottom asking to find the escape velocity at the surface if the moon in mph.
I don’t need breakdowns or explanations, just answers.
Because the acceleration caused by gravity affects escape velocity. Therefore, the moon's escape velocity must be lower than that of the earth. Moreover, due to a lower escape velocity.
What is the escape velocity of Earth?Ve therefore equals 11.2 km/s x 103 m/s. On Mars, the escape speed is approximately 40,270 kmph, or 11,186 m/s. For instance, when a rocket is used to propel a spacecraft into orbit, the velocity obtained must be higher than the orbital speed to prevent the rocket from returning to Earth.
Escape velocity: What is it?Escape velocity is indeed the bare minimum speed at which a body must be propelled in order to escape the earth's gravitational pull. The smallest speed at which an object must move in order to escape the gravity field is.
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a gray kangaroo can bound across a flat stretch of ground with each jump carrying it 8.0 m from the takeoff point. what is its horizontal speed?
A gray kangaroo can bound across a flat stretch of ground with each jump carrying it 8.0 m from the takeoff point, so his horizontal speed is 12.69 m/sec.
The projectile appears to be travelling straight forward without changing directions, according to the horizontal speed. The moment the projectile is launched, no net forces are exerted in a horizontal direction. As a result of zero acceleration, the projectile's horizontal speed remains constant throughout the trajectory motion.
To aid in their hopping, kangaroos have modified their bodies to include robust tails and larger rear feet. Some kangaroo subspecies, like red and grey kangaroos, are capable of successfully jump 10 feet vertically, 40 feet horizontally, and at speeds of over 30 mph because to these modifications.
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how do I find average distance with the numbers below:
MAIN: 92.2g
255cm,242 cm,245cm
for science help pls
Answer:
To find the average distance of the numbers you provided (255cm, 242cm, 245cm), you can add all the numbers together and divide by the number of numbers in the set.
In this case, you would add 255cm + 242cm + 245cm = 742cm, and then divide by 3 (the number of numbers in the set) to get an average distance of 244cm.
You can also use this formula: (255 +242 + 245) /3 = 244
betelgeuse is the bright red star representing the left shoulder of the constellation orion. all the following statements about betelgeuse are true. which one can you infer from its red color?
Its surface is cooler than the surface of the sun is the statement that we can infer from its red color.
Betelgeuse is also called Alpha Orionis. It is the second brightest star in the constellation Orion, thus marking the eastern shoulder of the hunter. Its name is derived from the Arabic term, which means “the giant’s shoulder.” It is one of the most luminous stars in the sky at night.
Having an apparent magnitude of about 0.6 it is a variable star. Its size is roughly 764 times as that of the Sun. As the apparent magnitude of this star is 0.6 which is a comparison with the sunlight, we can say it is cooler than the surface of the sun.
Hence the correct option is A.
--The given question is incomplete, the complete question is,
"betelgeuse is the bright red star representing the left shoulder of the constellation orion. all the following statements about betelgeuse are true. which one can you infer from its red color? a) Its surface is cooler than the surface of the Sun. b) It is much more massive than the Sun c) It is much brighter than the Sun d) It is moving away from us
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a 24-g bullet moving at 1,200 m/s is fired through a one-kg block of wood emerging at a speed of 100 m/s. what is the kinetic energy of the block that results from the collision if the block had not been moving prior to the collision and was free to move?
The kinetic energy of the block of wood would be 1148 m/s. The result is obtained by using the law of conservation of momentum.
What is the law of conservation of momentum?
The law of conservation of momentum states that the momentum of a closed system before and after the collision is constant. A closed system means there is no external force acting on the system. The formula would be:
∑p initial = ∑p final
p₁ + p₂ = p₁' + p₂'
m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂'
Where
∑p initial is momentum before the collision.∑p final is momentum after the collision.m₁ and m₂ is the mass of objectv₁ and v₂ is the speed of object before collisionv₁' and v₂' is the speed of object after collisionA bullet moving through a block of wood that is at rest. It has
Mass of bullet, m₁ = 24 gSpeed of bullet, v₁ = 1,200 m/sMass of wood, m₂ = 1 kgSpeed of wood, v₂ = 0Find the kinetic energy of the block that results from collision!
If a bullet moving through a block of wood, it means that the bullet will be united with the block of wood. Then, the speed of both bullet and wood after collision is the same, v'.
The speed of the bullet is
m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂'
m₁v₁ + m₂v₂ = (m₁ + m₂)v'
v' = (m₁v₁ + m₂v₂)/(m₁ + m₂)
v' = (24(1200) + 1(-100))/(24 + 1)
v' = (28800 - 100)/25
v' = (28700)/25
v' = 1148 m/s
The kinetic energy of the block of wood would be
KE₂ = ½m₂v₂'
KE₂ = ½(1)(1148)²
KE₂ = 13,171,904 Joule
Hence, after the collision, the kinetic energy of the block of wood is 13,171,904 Joule.
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A skier with mass of 62kg is sliding down a snowy slope. Find the coefficient of kinetic friction for the skier if friction is known to be 45. 0
A skier with mass of 62 kg is sliding down a snowy slope. The coefficient of kinetic friction is 0.0738 N
Calculating the problem:The coefficient of kinetic friction can be found using the formula:
Friction = coefficient of kinetic friction × Normal force
We know that the friction force is 45 N and the normal force is equal to the skier's weight, which can be found using the formula
Weight = mass × gravity
Where the mass is 62 kg and the acceleration due to gravity is approximately :9.8 m/s²
So the normal force is: 62 kg × 9.8 = 607.6 N
Therefore, the coefficient of kinetic friction is: Friction / Normal force or approximately
= [tex]\frac{45}{607.6}[/tex] = 0.0738
How does kinetic friction work?The force that opposes the motion of two surfaces in contact as they slide against one another is known as kinetic friction, but other names for it include sliding friction and dynamic friction. The properties of the two surfaces in contact, such as the roughness of their surfaces and the materials they are made of, determine its strength. It acts in the opposite direction of the force applied to an object.
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Two wires enter a box, are each connected to a terminal, and then exit again. The total conductor count is
Two wires enter a box, connect to individual terminals, and then leave the box once more. There are 2 conductor in total.
In physics, a conductor is a material that allows electric current to flow through it easily. This is in contrast to an insulator, which does not allow electric current to flow through it easily. Common examples of conductors include metals such as copper and aluminum, while common examples of insulators include rubber and plastic. Conductors are used in many electrical devices, such as wires and circuit boards, to help transfer electrical energy. The electrical resistance of a conductor is a measure of how easily electric current flows through it and is affected by factors such as the conductor's material, temperature, and cross-sectional area.
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A highway curves to the left with radius of curvature of 46 m and is banked at 19° so that cars can take this curve at higher speeds.
Consider a car of mass 843 kg whose tires have a static friction coefficient 0.88 against the pavement.
How fast can the car take this curve without skidding to the outside of the curve? The acceleration of gravity is 9.8 m/s^2
Answer in units of m/s.
The maximum speed in which the car can move on the curve without skidding to the outside of the curve is 12.46 m/s.
What is the maximum speed of the car without skidding?
The maximum speed in which the car can move on the curve without skidding to the outside of the curve is calculated by using the following formula.
v = √ ( rg tanθ )
where;
r is the radius of the curveg is acceleration due to gravityθ is the banking anglev = √ ( 46 x 9.8 x tan 19 )
v = 12.46 m/s
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Look at the table of results in the
diagram. Calculate the value
shown by the letter E.
The value shown by the letter E is 24V.
Define resistance
A material's ability to obstruct the flow of electrical current is referred to as resistance. The capital letter R serves as a symbol for it. A conductor's ability to obstruct the flow of charges through it is referred to as resistance.
A closed loop is referred to as a circuit where electrons can move. The circuit receives power from an electricity source, like a battery. There won't be any electron movement until the circuit is finished, or until it has made a full circuit loop back to the electrical source.
V = IR
For circuit 5, V = E
I = 8A
R = 3
E = 8*3 = 24V
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Answer:
8
Explanation:
6
The best way to increase the mechanical advantage of the following second-class lever is
4
Effort
Load
Fulcrum
Class 2 Lever
A To increase the size of the fulcrum
B) To move the load closer to the fulcrum
To increase the effort
D To move the load further away from the fulcrum
The best way to increase the mechanical advantage of the class 2 lever is to move the load closer to the fulcrum.
option B.
What is mechanical advantage?
The mechanical advantage of a simple machine is the ratio of output force to input force. It is also the ratio of load overcame by a simple machine to the effort applied by the simple machine.
Mathematically, the formula for mechanical advantage of a simple machine is given as;
M.A = output force / input force
M.A = Load / effort
Efficiency of machine = M.A/V.R x 100% = ( distance travelled by load x load ) / ( distance travelled by effort x effort )
Thus, to increase the mechanical advantage requires decrease in the distance travelled by the effort.
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you purchased 2.2 kg of apples from wollaston. you noticed that they used a spring scale with the smallest division of 17.7 g to weigh them. what is the relative error in this weight measurement as a percentage?
The weight measurement was off by 0.8% of the accepted value.
What is weight?Weight is a measure of the gravitational force that an object experiences due to its mass. Weight is typically measured in Newtons (N), and the formula for weight is mass multiplied by the acceleration due to gravity (g). Weight is an important factor in many activities such as sports, exercise, and even everyday tasks. The amount of weight an object carries affects its balance, stability, and momentum. Weight is an important factor to consider when using machines and tools.
Relative error is the ratio of the amount of error to the accepted value. To calculate the relative error in this weight measurement, we can use the following equation:
Relative Error = (17.7 g/2.2 kg) * 100%
The relative error in this weight measurement is 0.8%. This means that the weight measurement was off by 0.8% of the accepted value.
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3. Suppose a free-fall ride at an amusement park starts at rest and is in free fall.
a. What is the velocity of the ride after 2. 3 s?
b. How far do people on the ride fall during the 2. 3-s time period?
The velocity of the ride after 2.3s is 22.54m/s and the displacement covered is 26m.
What is free fall?
An object that is falling only due to gravity is said to be in free fall. Any object that is merely subject to the effects of gravity is said to be in free fall. Two crucial aspects of an object's motion are present while it is falling freely:
1) Air resistance does not exist for falling objects in free fall.
2) On Earth, all objects in free fall experience a downward acceleration of 9.8 m/s/s (which is frequently approximated to 10 m/s/s in computations).
Let the upward direction be positive and the downward be negative.
Now, according to the question we have given
The ride is in free fall i.e., u=0m/s and we have to find the velocity after 2.3s in part a.
so we can use the formula
v=u+at
v=0+9.8×2.3
v=22.54m/s
For part b we can use the 2nd equation of motion.
since xi=0 and u=0
xf=0+0+1/2×(-9.8)*2.3²
xf=-26m
Therefore, velocity of the ride after 2.3s is 22.54m/s and the displacement covered is 26m.
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which is not true about the celestial sphere? group of answer choices the model puts all of the stars at the same distance from earth. the ecliptic is an extension of earth's equator. the north celestial pole is an extension of earth's north pole. the model shows the sun and the stars moving around the earth.
The celestial model doesn't shows the Sun and the stars moving around the earth.
Celestial globes depict the apparent positions of the stars in the sky. They exclude the Sun, Moon, and planets since their positions differ from those of the stars, but the ecliptic, along which the Sun moves, is depicted.
A fictitious sphere surrounding the Earth in which the stars, Sun, Moon, and planets appear to reside.
The celestial sphere is a hypothetical sphere centered on the Earth onto which all celestial bodies can be projected. An observer on the Earth's surface can only view half of the celestial sphere at any given moment because the other half is hidden beneath the horizon.
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DESCRIBE Why is conifer sap important?
The reasons why conifer sap is important include:
It serves as a source of energy and nutrition for the treeIt helps the tree to defend against pathogens and pestsHow does conifer sap help the tree ?Conifer sap is rich in sugars and other nutrients that the tree needs to grow and survive. It is transported from the roots to the branches and leaves where it is used to fuel the tree's growth and metabolism.
Conifer sap is also known to contain compounds that protect the tree from pathogens and pests. These compounds act as a natural defense mechanism, helping the tree to resist infections and infestations.
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A proton is moved so that its electric potential energy increases from 2. 0 × 10-18 J to 6. 0 × 10-18 J. The magnitude of the charge on a proton is 1. 602 × 10-19 C.
The electric potential difference through which the proton moved, to the nearest whole number, is ____V
The electric potential difference through which the proton is moved is [tex]2.49 * 10^-18[/tex]V.
How to calculate electric potential difference?The electric potential difference through which the proton is moved can be calculated using the formula:
V = ΔU/q
Where V is the electric potential difference, ΔU is the change in electric potential energy, and q is the charge of the proton.
Given that the electric potential energy increases from [tex]2.0 * 10^-18[/tex] J to [tex]6.0 * 10^-18[/tex] J and the charge of the proton is 1.602 x 10^-19 C, we can substitute these values into the formula to find the electric potential difference:
V = (6.0 x 10^-18 J - 2.0 x 10^-18 J) / 1.602 x 10^-19 C
V = 4.0 x 10^-18 J / 1.602 x 10^-19 C
V = 2.49 x 10^-18 V
Therefore, the electric potential difference through which the proton is moved is [tex]2.49 x 10^-18[/tex] V.
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Would the speed of a satellite in close circular orbit about Jupiter be greater than, equal to, or less than 8 km/s?
Due to the satellite's overshooting circular course and movement away from Earth against the pull of gravity, the speed of satellite in such a closed circular orbit would be greater than 8 km/s.
Explain the effect of gravity on satellite in close circular orbit?The direction of gravity always seems to be toward the core of the Earth when a satellite travels around it in a circular orbit.
The satellite will move further before colliding with the Earth if it is assigned speed in either direction that is horizontal to a surface of the planet. This would travel so far if it is provided enough speed that even as it curves it toward the Earth, this should completely miss it. It will circle the Earth if it moves at just the proper pace. An orbit is the term used to describe this kind of motion and indeed the path which a satellite follows.A satellite must move at a speed of 8 km/s (28,000 km/h) or faster to stay its orbit when it is 100 km above the Earth. Satellites do not required to move as quickly at higher altitudes. The higher-altitude, 36,000 km, television communication satellites may fly at a speed of only 3 km/s (11,000 km/h).Thus, due to the satellite's overshooting circular course and movement away from Earth against the pull of gravity, the speed of satellite in such a closed circular orbit would be greater than 8 km/s.
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H= 0.0055m, R= 3m, How far did the object fall?
The formula s = (1/2)gt2 = 0.5 * 9.80665 * 82 = 313.8 m can be used to calculate the free fall distance. If you are aware of how high the object is.
How far can you fall into?Most falls occur from a height of 20 to 25 feet (6 to 8 metres), but anything higher than that can be fatal very quickly. According to a 2005 study conducted in Paris on 287 fall victims, falls from 8 storeys (30 metres) or above are always lethal.The highest survival thresholds for a person to tolerate impact velocity in water are ostensibly near to 100 ft/sec (68.2 mph) corrected velocity, or the equivalent of a 186-foot freefall.Nearly half of all fatal falls occur at a height between 0 and 20 feet, according to a study of construction accidents in India. Between 21 and 40-foot deadly falls made up the next-largest group. Alternatively stated, 20 feet is sufficient to be fata.To learn more about fall refer to:
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According to newton's second law of motion, if we have a rigid, unchanging mass and we observe it accelerating, what must be happening? question 8 options: a. a force is being applied to the mass b. no force was or is being applied to the massc. the mass must be changing d. the object's inertia is decreasing
"A force is being applied to the mass." that is option A is happening if we have a rigid, unchanging mass and we observe it accelerating.
What is force?A force is an effect in physics that may modify the velocity of an item. A force can cause a mass item to change its velocity, or accelerate. Intuitively, force may be characterized as a push or a pull. A force is a vector quantity since it has both magnitude and direction. The term "force" has a specific meaning in science. At this level, it is quite acceptable to refer to a force as a push or a pull. A force is not something that an item possesses or possesses. Another item applies a force to another. The concept of a force is not restricted to living or non-living entities.
Here,
Newton's second law of motion: F = m · a.
F - force applied.
m - mass of the object receiving the force.
a - the acceleration of the object.
One newton is the force needed to accelerate one kilogram of mass at the rate of one metre per second squared in direction of the applied force. The weight of an object is the amount of force acting on the object due to gravity. SI unit for weight is newton (N).
"There is a force acting on the mass." Option A is what happens when we see a stiff, unchanging mass accelerating.
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what is simple harmonic oscillation? select all that apply. what is simple harmonic oscillation? select all that apply. simple harmonic oscillation occurs for objects whose motion can be defined by a sine or cosine curve. , for example simple harmonic oscillation only occurs for a mas-on-a-spring system. simple harmonic oscillation occurs for objects which experience a position () dependent force () of the form , where is some positive constant. simple harmonic oscillation occurs when an object regularly returns to an equilibrium position.
Simple harmonic oscillation occurs when an object regularly returns to an equilibrium position and experiences a position-dependent force of the form , where is some positive constant.
What is harmonic oscillation?Harmonic oscillation is a type of periodic motion where an object oscillates back and forth along a path in a predictable and regular pattern. Examples of harmonic oscillation include the motion of a simple pendulum, the oscillation of a spring, and the vibration of a guitar string. The motion of an object undergoing harmonic oscillation can be described mathematically using a sinusoidal function such as sine, cosine, or a combination of the two.
This force is often associated with a mass-on-a-spring system, and the motion of the object can be defined by a sine or cosine curve.
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a cube whose sides are of length d is placed in a uniform electric field of magnitude so that the field is perpendicular to two opposite faces of the cube. what is the net flux through the cube?
The net flux through the cube is equal to [tex]2E*d^2[/tex]
The net flux through the cube is calculated by the flux through each of the six faces of the cube. The flux through a face is calculated by the electric field through the face multiplied by the area of the face.
For this situation, the electric field is perpendicular to two inverse faces of the cube, which means that the flux through these two faces is the maximum possible (since the field is perpendicular to the face).
The flux through these two faces is given by:
[tex]Flux = E * A = E * d^2[/tex] (where E is the electric field and d is the side length of the cube)
The electric field is parallel to the other four faces of the cube, which means that the flux through these faces is zero (since the field is parallel to the face and not passing through it).
Therefore, the net flux through the cube is the sum of the flux through the two faces where the field is perpendicular:
[tex]Net flux = 2 * (E * d^2) = 2E*d^2[/tex]
So the net flux through the cube is equal to [tex]2E*d^2[/tex], with E being the magnitude of the uniform electric field and d is the side length of the cube.
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a harmonic wave traveling along a string is generated by an oscillator that completes 180 vibrations per minute. if it is observed that a given crest, or maximum, travels 300 cm in 10 s, what is the wavelength?
The wavelength of the harmonic wave is 90 cm, if it completes 180 vibrations per minute and travels 300 cm in 10 s.
Time taken to complete 180 vibrations, = 1 minute = 60 sec
Number of vibrations completed by wave in 1 sec, = 180/60 = 3
So the frequency, f = 3 Hertz
Time taken to complete 1 vibration, T = 1/3 seconds
Wavelength is the distance travelled by the wave in one vibration/cycle. We know one cycle takes 1/3 seconds to complete, so the distance travelled by the wave in 1/3 second = (300/10) × (1/3) = 90 cm
So the wavelength λ = 90 cm.
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two point charges placed 5 cm apart on the x axis. at what points along the x axis is the potential zero?
The distance where the potential of two similar charges (in terms of magnitude and charge) will be zero at 2.5 cm from both sides. That is at Exect middle of both charges.
For finding the potential at any point due to a point charge(q0) is(Vr) = 1/4π∈*q0/r.
if both the charges are the same sign then the point will be in between of both the charges placed,
so Let the distance where the potential is zero be x in the left side so on the right side it will be 5-x.
as lets assume left charge if placed at the origin
so 1/4π∈*q0/x=1/4π∈*q0/5-x. ............. As both the potentials are equals
so 1/x = 1/5-x
x=5-x
so 2x =5 and here x= 2.5 cm
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a ball thrown horizontally at 26 m/s travels a horizontal distance of 58 m before hitting the ground. from what height was the ball throw
The ball was thrown from a height of 15.82 meters above the ground.
To find the height from which the ball was thrown, we can use the equations of motion for vertical and horizontal motion individually.
First, we know that the horizontal velocity of the ball is constant, so we can use the equation:
distance = velocity * time
We know the distance (58 m) and the velocity (26 m/s) of the ball, so we can find the time it takes for the ball to travel 58 m:
time = distance/velocity
time = 58 m / 26 m/s
Now we can use this time to find the height from which the ball was thrown. Since the vertical motion of the ball is affected by gravity, we can use the equation:
vertical distance = initial vertical velocity * time + (1/2) * acceleration due to gravity * time^2
Since the ball was thrown horizontally, its initial vertical velocity is 0 m/s. The acceleration due to gravity is 9.8 m/s^2 (going down).
We can substitute the values into the equation:
[tex]height = 0 m/s * time + (1/2) * 9.8 m/s^2 * time^2[/tex]
[tex]h = (1/2) * 9.8 m/s^2 * time^2[/tex]
[tex]h = (1/2) * 9.8 m/s^2 * (58 m / 26 m/s)^2[/tex]
height = 15.82 m
Therefore, the ball was thrown from a height of 15.82 meters above the ground.
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9. two solid spheres, both of radius 5 cm, carry identical total charges of 2 !c. sphere a is a good conductor. sphere b is an insulator, and its charge is distributed uniformly through- out its volume. (i) how do the magnitudes of the electric fields they separately create at a radial distance of 6 cm compare?(a)ea.eb 50(b)ea.eb.0(c)ea5eb.0 (d)0,ea,eb (e)05ea,eb (ii)howdothemagnitudes of the electric fields they separately create at radius 4 cm compare? choose from the same possibilities as in part (i).
(i) The magnitudes of the electric fields they separately create at a radial distance of 6 cm is [tex]E_{a}[/tex]=[tex]E_b}[/tex]. and (ii) The magnitudes of the electric fields they separately create at radius 4 cm is [tex]E_{a} =E_{b}[/tex], so the correct option is option b.
What do you mean by conductor?A conductor refers to a material that allows an electric current to flow through it with ease. In other words, it has a low electrical resistance. Conductors are materials that have a high number of free electrons that are able to move freely through the material. Examples of conductors include copper, aluminum, gold, and silver. These materials are commonly used in the electrical industry to make wires and other electrical components that need to conduct electricity. In addition to materials, a conductor can also refer to a person or an organization that is responsible for directing or leading an orchestra or a choir. In this context, a conductor is in charge of maintaining the ensemble's rhythm and intonation, and interpreting the score in a way that brings out the music's emotional content and intended meaning.
(i) The magnitude of the electric field created by a charged conductor is given by the formula E = [tex]\frac{kq}{r}[/tex], where k is the Coulomb constant, q is the charge, and r is the distance from the center of the sphere.
For a good conductor, like sphere A, the charge will be distributed evenly on the surface of the sphere. So, the electric field at a radial distance of 6cm will be Eₐ = [tex]\frac{kq}{r^{2} }[/tex] = [tex]k\frac{210^{-6} }{(619^{-2} )}^{2} =\frac{k}{72}[/tex]
For an insulator, like sphere B, the charge is distributed uniformly throughout its volume. The electric field at a radial distance of 6cm will be [tex]E_{b}[/tex]= [tex]\frac{kq}{r^{2} }=k\frac{210^{-6} }{(619^{-2} )}^{2} =\frac{k}{72}[/tex]
As we can see, the magnitudes of the electric fields created by both spheres are equal, so the answer is (b) [tex]E_{a} =E_{b}[/tex]
(ii) For the radius of 4cm, the electric field created by sphere A and sphere B will
[tex]E_{a} =\frac{kq}{r^{2} }=k\frac{210^{-6} }{(410^{-2} )^{2} } =\frac{k}{16}\\E_{b} =\frac{kq}{r^{2} }=k\frac{210^{-6} }{(410^{-2} )^{2} } =\frac{k}{16}\\[/tex]
As we can see, the magnitudes of the electric fields created by both spheres are equal at a radius of 4cm, so the answer is (b) [tex]E_{a} =E_{b}[/tex]
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Two billiard balls, each with a mass of 0. 35 kg, strike each other head-on. One ball is initially moving left at 4. 1 m/s and ends up moving right at 3. 5 m/s. The second ball is initially moving to the right at 3. 5 m/s. Find the velocity of the second ball
The velocity of the second ball will be 4.1 m/s towards the left, If the initial velocity of the second ball is 3.5 m/sec towards right.
Initial velocity of first ball, v₁ = +4.1 m/s [positive: towards the left]
Initial velocity of second ball, v₂ = -3.5 m/s [negative: towards the right]
final velocity after collision of first ball, v₃ = -3.5 m/s
Let the final velocity after collision of second ball, = v₄
Mass of each ball is 0.35 kg
By the law of conservation of momentum,
m₁v₁ + m₂v₂ = m₃v₃ + m₄v₄
0.35×(4.1) + 0.35(-3.5) = 0.35×(-3.5) + 0.35×v₄
4.1 - 3.5 = -3.5 + v₄
v₄ = +4.1
Positive sign indicates that the velocity will be towards the left.
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Help!!! A heat engine receives 1240 J of heat and exhausts 910 J per cycle of the engine what net work does the engine perform during the cycle?
a) 0 J
b) 330 J
c) 910 J
d) 2150 J
Net work the engine perform during the cycle is b) 330 J.
The net work done by a heat engine is the difference between the heat absorbed by the engine and the heat exhausted. Therefore, the net work done by the engine during a cycle is
1240 J - 910 J = 330 J.
How does the temperature of the hot reservoir affect the efficiency of a heat engine?
The efficiency of a heat engine is directly related to the temperature of the hot reservoir. The higher the temperature of the hot reservoir, the more thermal energy is available for conversion into work. This means that the efficiency of the heat engine increases as the temperature of the hot reservoir increases. The maximum efficiency of a heat engine is given by the Carnot efficiency, which is only achievable when the temperature of the cold reservoir is 0 K (absolute zero) and the temperature of the hot reservoir is infinite.
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Which of the following scenarios describes an object being acted on by a conservative force?
A scenario which describes an object being acted on by a conservative force is the one in which a feather falls from one end of a tube to the other inside a vacuum. Thus, the correct option is C.
What is Conservative force?The conservative force is a force with the property which the total work done in moving a particle between two points, it is independent of the path taken by the object. Equivalently, if a particle travels in a closed loop, then the total work done by the object is the sum of the independent forces which are acting along the path multiplied by the displacement of the object by a conservative force is zero.
A feather which is falling from one end of a tube to the other inside a vacuum is an example of conservative force. This is a Conservative force because, here we are looking at a vacuum and it is a closed system of no other forces present in it due to vacuum.
Therefore, the correct option is C.
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Your question is incomplete, most probably the complete question is:
Which of the following scenarios describes an object being acted on by a conservative force?
A. A woman hikes up a mountain to a point 20 feet above ground.
B. A dishwasher was pulled up to a window by a rope, using a pulley system.
C. A feather falls from one end of a tube to the other inside a vacuum.
D. A puck glides across and slowly comes to a stop on an ice rink.
A −10 nC charge is at the origin. In which direction does the electric field from the charge point at x + 10 cm ?
The direction of the field would be towards the positive end of the charge.
What is the direction of the electric field?We know that the electric field has to do with the region in space where the influence of a charge can be felt. We can see from the question that there is a region around the −10 nC charge where its influence is felt.
Thus, we can see that that the direction of the charge would be in the positive direction to the charge that has been given which is around the charge that has a magnitude of −10 nC.
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a car moves with a total distance of 45.0 meters in 10 seconds while slowing down smoothly with a final speed of 3.00 m/s. a) what is the original speed of the car? (2 points) b) what is the car's acceleration? (2 points)
Answer : Original Speed is 6m/s while acceleration is 0.3m/s^2.
What is speed?
--In everyday use and in kinematics, the speed of an object is the magnitude of the change of its position over time or the magnitude of the change of its position per unit of time;
-- it is thus a scalar quantity.
Here in this question we have given final speed , we have to find the intial speed as well as the acceleration of the body.
d = V1 + V2 /2 × t
45 = V1 + 3/2 × 10
V1 = 6 m/s.
Hence initial speed of body is 6m/s .
By using first equation of motion we find the acceleration
we get acceleration is 0.3 .
What is velocity?
-- Velocity is the directional speed of an object in motion as an indication of its rate of change in position as observed from a particular frame of reference and as measured by a particular standard of time .
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a car is driving on a curve on the interstate when, all of the sudden, the car encounters ice - reducing the friction to zero. assuming the curve has a radius of 20-m and the interstate is banked at an angle of 10 to the inside, what is the maximum velocity the car can travel to avoid sliding off the interstate
The maximum amount of static friction that the tyres can generate on the road can be used to calculate the maximum speed at which the car can go without slamming off the interstate.
The only force acting on the car when friction is eliminated is gravity, which pulls the vehicle towards the curve's centre.
The formula for calculating the maximum static friction force is
f_max = μ_s * m * g, where
μ_s = coefficient of static friction
m = mass of the car
g = acceleration due to gravity (9.8 m/s^2)
The maximum static friction force can be computed as follows using an assumed static friction coefficient of 0.7:
f_max = 0.7 * m * 9.8 = 6.86 * m N
The formula for the gravitational force is:
f_gravity = m * g * sin(θ), where
θ = bank angle (10°)
The difference between the gravitational force and the maximal static friction force is the net force operating on the automobile. The car won't skid off the road if the net force is zero.
The formula for calculating the maximum velocity is:
v = sqrt(R * g / sin(θ))
where
R = radius of the curve (20 m)
By substituting the values, we get:
v = sqrt(20 * 9.8 / sin(10)) = 26.51 m/s = 94.91 km/h
As a result, the maximum speed at which the car may move without swerving off the highway is roughly 94.91 km/h.
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