Find a polynomial f(x) of degree 3 that has the following zeros. -1 (multiplicity 2), 8 Leave your answer in factored form

Answer:

You have to simplify the fraction and turn it into a decimal.

Step-by-step explanation:

Meaning: Make the fraction smaller and turn it into the correct decimal.

EXAMPLE:

2/4 simplified is 1/2

1/2 is equal to 0.50

Answer:

.01 + .3 = 0.31

Step-by-step explanation:

Answer:

∠A and ∠G is the pair of vertical angles.

Step-by-step explanation:

From the figure attached,

Two lines 'm' and 'n' are two parallel lines. These lines intersect a horizontal line 'l'.

Since, "Pair of opposite angles formed at the point of intersection are the vertical angles and equal in measure."

Therefore, Opposite angles ∠A ≅ ∠G, ∠B ≅ ∠H, ∠C ≅ ∠E and ∠D ∠F are the vertical angles.

From the given options,

∠A and ∠G is the pair representing the pair of vertical angles and thus congruent.

Answer:

∠A and ∠G

Step-by-Step Explaination:

I did it on

E

D

G

E

N

U

I

T

Y

Answer:

True

Step-by-step explanation:

Equivalent fractions are fractions with different numbers representing the same part of a whole.

Answer:

C. The number of hours she babysits

Step-by-step explanation:

In this situation, the number of hours she babysits is the independent variable.

This is because it will directly influence the amount of money that she earns, which is the dependent variable.

For example, working for 1 hour will earn her $15.

So, the correct answer is C. The number of hours she babysits

Answer:

Area= 90

Step-by-step explanation:

triangle area: (b x h) / 2

(12 x 15) / 2

(180) / 2

a= 90

Answer:

-9 + 4i

Step-by-step explanation:

The additive inverse ("opposite") of a complex number a + bi  is  -a - bi.

Just use the opposites of  a  and  b.

Answer:

[tex]\frac{a^2 + b^2 +c ^2}{a*b + a*c + b*c} = -2[/tex]

Step-by-step explanation:

if:

a + b + c = 0

then we can rewrite:

c = -a - b

Now we can replace this in our expression:

[tex]\frac{a^2 + b^2 + c^2}{a*b + a*c + b*c} = \frac{a^2 + b^2 + (-a - b)^2}{a*b + a*(-a - b) + b*(-a - c)}[/tex]

Now we can rewrite:

(-a - b)^2 = a^2 + 2*a*b + b^2

Then we can rewrite our expression as:

[tex]\frac{a^2 + b^2 + a^2 + b^2 + 2*a*b}{a*b - a^2 - a*b - b^2 - b*a}[/tex]

Let's keep simplifying this:

[tex]\frac{2*(a^2 + b^2 + a*b)}{-a*b - b^2 - a^2}[/tex]

Here is easy to see the simplification we need to do, as we have the same factor in the denominator as in the numerator (just a different of sign).

[tex]\frac{2*(a^2 + b^2 + a*b)}{-a*b - b^2 - a^2} = \frac{2*(a^2 + b^2 + a*b)}{-(a^2 + b^2 + a*b)} = -2[/tex]

Then the expression is equal to -2

[tex]\frac{a^2 + b^2 +c ^2}{a*b + a*c + b*c} = -2[/tex]

Answer:

the probability that they are assigned adjacent cubicles is  1 ÷ 4

Step-by-step explanation:

Given that

There is 8 new graduates are hired

2 of the graduates are bill and cathy

And, each one is assigned on random basis

We need to find out the probability

So,

= (2) (7!) ÷ (8!)

= (2) ÷ (8)

= 1 ÷ 4

Hence, the probability that they are assigned adjacent cubicles is  1 ÷ 4

The same would be relevant

Answer:

[tex]40[/tex]

hope this helps you.

Can I have the brainliest please?

Answer: [tex]3x^{-2.5}[/tex]

Step-by-step explanation:

Given

Expression is

[tex]\dfrac{12\sqrt{x}}{4x^3}[/tex]

Using exponent property [tex]x^a\cdot x^b=x^{a+b}[/tex]

Writing expression in the form of [tex]k\cdot x^n[/tex]

[tex]\Rightarrow \dfrac{12\sqrt{x}}{4x^3}=\dfrac{3\times 4}{4}\times \dfrac{x^{0.5}}{x^3}\\\\\Rightarrow \dfrac{3\times 4}{4}\times x^{0.5-3}\\\\\Rightarrow 3x^{-2.5}[/tex]

Answer:

Part a:  Since the calculated value of t = 2.412 does not fall in the critical region t > ± 2.539 we conclude that population mean expense ratio does not exceed 1% at 0.01 significance level.

Part b:  Yes we accepted the null hypothesis when it is false so we made a type II error.

Part c: Power = 0.6591=0.66

Step-by-step explanation:

Part a:

Let the null and alternate hypotheses be

H0: u ≤ 1 against the claim Ha: u > 1

The significance level is ∝=0.01

As the standard deviation of the population is not given we use t- test which has n-1= 20-1= 19 degrees of freedom

This is one tailed test the critical region is t > ± 2.539

The mean is calculated to be 1.24 and standard deviation of the sample = s= 0.4486

We take population mean = u= 1

The test statistic is

t = x`-u/ s/ √n

t= 1.24-1 / 0.445/√20

t= 0.24/0.0995

t= 2.412

Since the calculated value of t = 2.412 does not fall in the critical region t > ± 2.539 we conclude that population mean expense ratio does not exceed 1% at 0.01 significance level.

Part b:

Type I errors are those errors when the null hypothesis is true and is rejected.

Type II errors are those in which the null hypothesis is false and is accepted.

If we had rejected the null hypothesis as it was true then we would have made a type I error.

Population mean = u = 1.33

And our null hypothesis is u= 1

Yes we accepted the null hypothesis when it is false so we made a type II error.

Part c:

When σ= 0.5

For Part a: μ= 1.33

Power = P (reject H0/ H0 is false)

= 1-β

P (reject H0/ H0 is false) = P (z > 2.539+ (u`-u0) / σ*√n)

= P (z > 2.539+ (1-1.33) /0.5 *√20)

=P (z > 2.539-2.9516)

= P (z > 0.4126)

= 0.5 - P (z= 0.2938)                                         from the area of table.

= 0.5- 0.1591

=0.3409

Power = 1-β = 1- 0.3409= 0.6591=0.66

Answer:

2,144.66 miles³

Step-by-step explanation:

v = (4/3)πr³

v = (4/3)π(8³)

v = 2,144.6605848506

Rounded

2,144.66 miles³

Answer:

9yx

Step-by-step explanation:

product means multiply.

nine, y and x

9yx

Answer:

52 miles

Step-by-step explanation:

total miles needed to average 56

56 * 6 = 336

miles after 5 days

51 + 62 + 61 + 47 + 63 = 284

miles needed on last day

336 - 284 = 52 miles

Answer:

x^20 please mark me brainliest

Step-by-step explanation:

We can solve this by substitution method.

Look at the second equation. If we rearrange to find 7x, we can substitute in the value into the first equation.

[tex]5y-7x=12[/tex]

[tex]5y-7x-12=0[/tex]

[tex]5y-12=7x[/tex]

Therefore, [tex]7x=5y-12[/tex]

Now replace the 7x in the first equation with 5y - 12:

[tex]2y+7x=-5[/tex] (substitute in 7x = 5y - 12)

[tex]2y+(5y-12)=-5[/tex]

[tex]7y-12=-5[/tex]

[tex]7y=7[/tex]

[tex]y=1[/tex]

Now that we know y, we can find x by substituting in y = 1 into any equation we want. I will use the equation: 7x = 5y - 12

[tex]7x=5y-12[/tex] (substitute in y = 1)

[tex]7x=5(1) -12[/tex]

[tex]5x=5-12[/tex]

[tex]7x=-7[/tex]

[tex]x=-1[/tex]

__________________________________________________________

Answer:

[tex]y=1\\x=-1[/tex]

Answer:

7 socks were sold

Step-by-step explanation:

7*8=56

11-7=4

4×11=44

56+44=100

This proves the answer of 7 to be correct

GE = 26

Step-by-step explanation:

OP = 16 + 9 = 25

PE - OG = 7

Using Pythagorean theorem,

(GE)^2 = (OP)^2 + (PE - OG)^2

=(25)^2 + (7)^2

= 625 + 49

= 674

or

GE = √674 = 25.96 or 26

Answer:

Step-by-step explanation:

-4<n≤5

Multipuly po ba (15;000 7%)

Answer:

[tex]Fraction = \frac{31}{38}[/tex]

[tex]\theta = 296.18^\circ[/tex]

[tex]Area = 29.62 \pi[/tex]

Step-by-step explanation:

Given

[tex]r = 6[/tex]--- radius

[tex]L = 31[/tex] --- arc length

Solving (a): Fraction represented by the arc

First, calculate the circumference (C)

[tex]C = 2\pi r[/tex]

So, we have:

[tex]C = 2 * 3.14 * 6[/tex]

[tex]C = 38[/tex] --- approximated

So, the fraction represented by the arc is:

[tex]Fraction = \frac{L}{C}[/tex]

[tex]Fraction = \frac{31}{38}[/tex]

Solving (b): Measure of the center angle

Using arc length formula, we have:

[tex]L = \frac{\theta}{360} * 2\pi r[/tex]

This gives

[tex]31 = \frac{\theta}{360} * 2 * 3.14 * 6[/tex]

[tex]31 = \frac{\theta}{360} * 37.68[/tex]

Make [tex]\theta[/tex] the subject

[tex]\theta = \frac{360 * 31}{37.68}[/tex]

[tex]\theta = 296.18^\circ[/tex]

Solving (c): The area of the sector

This is calculated as:

[tex]Area = \frac{\theta}{360} * \pi r^2[/tex]

So, we have:

[tex]Area = \frac{296.18}{360} * \pi * 6^2[/tex]

[tex]Area = \frac{296.18}{360} * \pi * 36[/tex]

Divide 360 and 36

[tex]Area = \frac{296.18}{10} * \pi[/tex]

[tex]Area = 29.618 * \pi\\[/tex]

[tex]Area = 29.62 \pi[/tex] --- approximated

Answer:

The average rate of change of the function over the interval is of 6.

Step-by-step explanation:

Average rate of change:

The average rate of change of a function h(x) over an interval [a,b] is given by:

[tex]A = \frac{h(b)-h(a)}{b-a}[/tex]

In this question:

Over the interval [-9,-2], so [tex]a = -9, b = -2, b - a = -2 -(-9) = 7[/tex]

The function is:

[tex]h(x) = -x^2 - 5x + 14[/tex]

[tex]h(-9) = -9^2 -5(-9) + 14 = -81 + 45 + 14 = -22[/tex]

[tex]h(-2) = -2^2 -5(-2) + 14 = -4 + 10 + 14 = 20[/tex]

Then

[tex]A = \frac{h(-2)-h(-9)}{7} = \frac{20-(-22)}{7} = \frac{42}{7} = 6[/tex]

The average rate of change of the function over the interval is of 6.

Answer:

Ed's answer of [tex]\frac{3}{8}[/tex] is correct because he divided [tex]\frac{1}{4}[/tex] by [tex]\frac{2}{3}[/tex] to get his answer.

Step-by-step explanation:

To solve for m in [tex]\frac{2}{3}m=\frac{1}{4}[/tex] you want to isolate m by dividing by [tex]\frac{2}{3}[/tex] on both sides, therefore he divided [tex]\frac{1}{4}[/tex] by [tex]\frac{2}{3}[/tex] to get his answer of [tex]\frac{3}{8}[/tex], and his answer is correct.

Solution :

From the table,

Number of countries = [tex]$N_i$[/tex]

Mean = [tex]$\overline Y_i$[/tex]

Standard deviation = [tex]$\sigma_i$[/tex]

Margin of error of B = 50,000 acres

So we determine the [tex]$\text{sample size n}$[/tex] and then allocate the four regions of [tex]$n_1, n_2, n_3$[/tex] and [tex]$n_4$[/tex].

Under the [tex]$\text{proportional allocation}$[/tex], the [tex]$\text{equation}$[/tex] for the value of [tex]$n_1$[/tex] which yields [tex]$V(\overline Y_{st}) = D = \frac{B^2}{H}$[/tex]  is given by :

[tex]$n=\frac{\sum_{K=1}^L N_K \sigma^2_K}{ND+\frac{1}{N}\sum_{K=1}^L N_K \sigma^2_K}$[/tex]

Let us complete the numerator

[tex]$\sum_{K=1}^L N_K \sigma^2_K = N_1\sigma_1^2 + N_2\sigma_2^2 + N_3\sigma_3^2 + N_4\sigma_4^2$[/tex]

                [tex]$= 1052 \times (271)^2 + 210 \times (79)^2 + 1376 \times (244)^2 + 418 \times (837)^2 $[/tex]

                = 453329920

The bound on the error of estimation is B = 50,000 acres

Hence we get

[tex]$D=\frac{B^2}{H}$[/tex]

  [tex]$=\frac{50000^2}{4}$[/tex]

  = 625,000,000

[tex]$n=\frac{\sum_{K=1}^L N_K \sigma^2_K}{ND+\frac{1}{N}\sum_{K=1}^L N_K \sigma^2_K}$[/tex]

  [tex]$=\frac{453329920}{3056 \times 625 + \frac{1}{3056} \times 453329920}$[/tex]

 = 220.24044

≈ 221 (approximately)

Therefore, the sample size under the proportional allocation from each stratum are given by :

[tex]$n_1=n\left[\frac{N_1}{\sum_{K=1}^\mu N_K}\right]$[/tex]

   [tex]$=221\left[\frac{1052}{3056}\right]$[/tex]

   ≈ 76

[tex]$n_2=n\left[\frac{N_2}{\sum_{K=1}^\mu N_K}\right]$[/tex]

   [tex]$=221\left[\frac{210}{3056}\right]$[/tex]

   ≈ 15

[tex]$n_3=n\left[\frac{N_3}{\sum_{K=1}^\mu N_K}\right]$[/tex]

   [tex]$=221\left[\frac{1376}{3056}\right]$[/tex]

   ≈ 100

[tex]$n_4=n\left[\frac{N_4}{\sum_{K=1}^\mu N_K}\right]$[/tex]

   [tex]$=221\left[\frac{418}{3056}\right]$[/tex]

   ≈ 30

Thus, we should select 76 counties from North central region, 15 counties from the north east region, 100 from south region and 30 from west region.

We can also estimate mean acreage of each county across all the county with a margin of error of 50,000 acres.

Answer:

See image

Step-by-step explanation:

I clicked submit and it was right

Also dude I remember doing this and struggling before

Answer:

3000 in3 ? I haven't actually done this i-ready before- but I believe it's

Width x Length x Height = Final result?

Step-by-step explanation:

Answer:

11+y > -33

Step-by-step explanation:

Answer:

You wrote

"Which of the following" Meaning there's should be options present.

But Going with the statement...

The sum of 11 and y is greater than -33

I'd say

11 + y > -33.

Answer:

76 books

Step-by-step explanation:

2/3 × 114 = 76

__________