find an explicit solution of the given initial-value problem. dx dt = 3(x2 1), x 4 = 1

The probability of the combination consisting of only even numbers is very low at just 0.46%. The total number of possible combinations is given by 38P4, which is equal to 38!/34!.

To find the number of combinations that consist of only even numbers, we need to consider that there are 19 even numbers (0, 2, 4, ..., 36) and 19 odd numbers (1, 3, 5, ..., 37) in the range of 0 to 37.
The number of ways to choose 4 even numbers is given by 19C4, which is equal to 19!/4!15!.
Therefore, the probability that the combination consists of only even numbers is:
P = 19C4 / 38P4
 = (19!/4!15!) / (38!/34!)
 = 0.004634
 = 0.46% (rounded to two decimal places)

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The moment generating function (MGF) of a random variable X is a function that produces moments of X. For a uniformly distributed finite set {a, a+1, ..., b}, the MGF can be calculated as Mx(t) = (e^(at) + e^((a+1)t) + ... + e^(bt)) / (b-a+1). In this case, X is uniformly distributed on {4,5,6,7}, so the MGF of X is Mx(t) = (e^(4t) + e^(5t) + e^(6t) + e^(7t)) / 4.

The MGF of the sum of independent random variables X and Y is the product of their individual MGFs. Therefore, the MGF of X+Y can be calculated as MX+Y(t) = Mx(t) * My(t). Y is uniformly distributed on {18,19,20,...,26}, so its MGF can be calculated in a similar manner as Mx(t), resulting in My(t) = (e^(18t) + e^(19t) + ... + e^(26t)) / 9. Therefore, MX+Y(t) = ((e^(4t) + e^(5t) + e^(6t) + e^(7t)) / 4) * ((e^(18t) + e^(19t) + ... + e^(26t)) / 9).

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From the calculation, the alloy  would have a density of  6 g/     [tex]cm^3[/tex].

We have that;

Let the mass of each block A be x and let the mass of each block B be y

3x + 5y = 34 ---- (1)

5x + 2y = 44 ---- (2)
Multiply equation (1) by 5 and equation (2) by 3

15x + 25y = 170 ---- (3)

15x + 6y = 132 --- (4)

Subtract (4) from (3)

19y = 38

y = 2

Substitute y = 2 into (1)

3x + 5(2) = 34

x = 8

Mass of the alloy = 2(8) + 2 = 18 g

Volume of the alloy = 3(1 [tex]cm^3[/tex]) = 3 [tex]cm^3[/tex]

Density of the alloy  = 18 g/3 [tex]cm^3[/tex]

= 6 g/     [tex]cm^3[/tex]

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Dilation is a transformation, which is used to resize the object while scale factor is the ratio of the dimensions of the new object to the ratio of old object.

Dilation Meaning in Math. Dilation is a transformation, which is used to resize the object.

Dilation is used to make the objects larger or smaller. This transformation produces an image that is the same as the original shape. But there is a difference in the size of the shape.

Scale factor is the ratio of the length of the new shape to the dimensions of the original shape.

For example if the length of a rectangle is 5m and it's dilated to 10 cm , the scale factor is calculated as;

= 10/5 = 2

Therefore the scale factor is 2

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Answer: No it is a quadratic function

Step-by-step explanation: the solution to this would be

y=(3-x)4x

y=-4x^2+12x

which would make it a parabola, which is quadratic function

True. Statistical inference involves drawing conclusions about a population based on sample data, using statistical techniques such as hypothesis testing and confidence intervals.

Statistical inference is a fundamental concept in statistics that allows us to make inferences or draw conclusions about a population based on a sample. It involves applying statistical techniques to analyze sample data and make generalizations or predictions about the larger population from which the sample was drawn.

By using methods like hypothesis testing and confidence intervals, statistical inference helps us estimate population parameters, test hypotheses, and assess the reliability of our findings. Through the process of sampling and applying statistical techniques, we aim to draw meaningful conclusions about the characteristics, relationships, or effects within a population.

Therefore, it is accurate to say that statistical inference involves making generalizations about the population based on sample data, allowing us to make informed decisions and draw meaningful insights from limited observations.

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In a segmented bar plot, each cell count is typically divided by the total count of the corresponding category or group.

In a segmented bar plot, each cell count is divided by the total count of the corresponding category or group to represent the relative proportion or percentage of each segment within the category or group.

The purpose of a segmented bar plot is to visualize the distribution of different segments within a larger category or group. By dividing each cell count by the total count, we obtain proportions or percentages that allow for a meaningful comparison between the segments.

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The correct statement that will give the given output is sort(vecPeople.begin(), vecPeople.end(), Greater);. Option C is correct.

This statement sorts the vector vecPeople in ascending order, based on the second element of each pair, using a custom comparison function called Greater. This function compares the second element of two pairs and returns true if the second element of the first pair is greater than the second element of the second pair.

Since the second element of each pair in the vector contains the age of a person, this statement sorts the vector by age, from youngest to oldest.

Option (a) is incorrect because vecPeople is not a valid argument to the sort() function, and vecPeople is not a valid comparison function.

Option (b) is incorrect because the arguments to the sort() function are reversed, and Greater is not a valid argument.

Option (d) is incorrect because the arguments to the sort() function are reversed, and vecPeople is not a valid comparison function.

Therefore, option C is correct.

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To solve this problem, we need to find the intersection of the circle with a 61-mile radius centered at the transmitter and the straight line connecting the two cities.

First, let's draw a diagram of the situation:

r

Copy code

T (transmitter)

|\

| \

|  \

|   \

|    \

|     \

|      \

|       \

C1      C2

Here, T represents the transmitter, C1 represents the city 68 miles north of the transmitter, and C2 represents the city 81 miles east of the transmitter. We want to find out how much of the straight line from C1 to C2 is within the range of the transmitter.

To solve this problem, we need to use the Pythagorean theorem to find the distance between the transmitter and the straight line connecting C1 and C2. Then we can compare this distance to the radius of the transmitter's range.

Let's call the distance between the transmitter and the straight line "d". We can find d using the formula for the distance between a point and a line:

scss

Copy code

d = |(y2-y1)x0 - (x2-x1)y0 + x2y1 - y2x1| / sqrt((y2-y1)^2 + (x2-x1)^2)

where (x1,y1) and (x2,y2) are the coordinates of C1 and C2, and (x0,y0) is the coordinate of the transmitter.

Plugging in the values, we get:

scss

Copy code

d = |(81-0)*(-68) - (0-61)*(-68) + 0*0 - 61*81| / sqrt((81-0)^2 + (0-61)^2)

 = 3324 / sqrt(6562)

 ≈ 41.09 miles

Therefore, the portion of the straight line from C1 to C2 that is within the range of the transmitter is the portion of the line that is within 61 miles of the transmitter, which is a circle centered at the transmitter with a radius of 61 miles. To find the length of this portion, we need to find the intersection points of the circle and the line and then calculate the distance between them.

To find the intersection points, we can solve the system of equations:

scss

Copy code

(x-0)^2 + (y-0)^2 = 61^2

y = (-61/68)x + 68

Substituting the second equation into the first equation, we get:

scss

Copy code

(x-0)^2 + (-61/68)x^2 + 68(-61/68)x + 68^2 = 61^2

Simplifying, we get:

scss

Copy code

(1 + (-61/68)^2)x^2 + (68*(-61/68))(x-0) + 68^2 - 61^2 = 0

Solving this quadratic equation, we get:

makefile

Copy code

x = 12.58 or -79.23

Substituting these values into the equation for the line, we get:

scss

Copy code

y = (-61/68)(12.58) + 68 ≈ 5.36

y = (-61/68)(-79.23) + 68 ≈ 148.17

Therefore, the intersection points are approximately (12.58, 5.36) and (-79.23, 148.17). The distance between these points is:

scss

Copy code

sqrt((12.58-(-79.23))^2 + (5.36-148.17)^2)

≈

Answer:

34.5 meters

Step-by-step explanation:

Over horizontal ground, the range R for velocity v and launch angle θ is:

R=v^2sin2θ/g

=35^2sin16∘/9.8

= 34.5 meters

To solve these probability questions, we can utilize the Poisson distribution, which is commonly used to model the number of events occurring in a fixed interval of time or space.

In this case, we assume the number of airplane crashes follows a Poisson distribution with an average of 2.2  per month.

(a) To find the probability of less than 5 accidents in the next month, we sum up the probabilities of having 0, 1, 2, 3, and 4 accidents using the Poisson distribution formula. The probability can be calculated as follows:

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

(b) To calculate the probability of more than 2 accidents in the next 3 months, we need to find the complement of having 0, 1, or 2 accidents in the next 3 months. We can calculate the complement as follows:

P(X > 2 in 3 months) = 1 - [P(X = 0 in 3 months) + P(X = 1 in 3 months) + P(X = 2 in 3 months)]

(c) To determine the probability of exactly 6 accidents in the next 4 months, we use the Poisson distribution formula:

P(X = 6 in 4 months)

To calculate these probabilities, we need to use the Poisson distribution formula with the given average rate of 2.2 crashes per month.

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The area inside the loop of the limaçon given by r = 7 - 14sin(θ) is 73.5π square units.

The equation for a limaçon is given by r = a ± b*cos(θ), where a is the distance from the origin to the loop of the limaçon, and b is the distance between the loop and the pole.

In this case, we have r = 7 - 14sin(θ), which is in the form of a limaçon with a = 7 and b = 14.

To find the area inside the loop of the limaçon, we need to integrate 1/2*r^2 dθ over the appropriate range of θ values.

Since the loop of the limaçon is traced out when θ varies from 0 to π, we integrate from 0 to π:

A = 1/2 * ∫[0,π] (7 - 14sin(θ))^2 dθ

Using the identity sin^2(θ) = (1/2)*(1 - cos(2θ)), we can simplify this to:

A = 1/2 * ∫[0,π] (49 - 196sin(θ) + 196sin^2(θ)) dθ

A = 1/2 * (49π - 196∫[0,π] sin(θ) dθ + 196∫[0,π] sin^2(θ) dθ)

The integral of sin(θ) from 0 to π is zero, and we can use the identity sin^2(θ) = (1/2)*(1 - cos(2θ)) again to get:

A = 1/2 * (49π + 196∫[0,π] (1/2)*(1 - cos(2θ)) dθ)

A = 1/2 * (49π + 98∫[0,π] (1 - cos(2θ)) dθ)

A = 1/2 * (49π + 98(θ - (1/2)*sin(2θ))|[0,π])

Evaluating this expression at the limits of integration, we get:

A = 1/2 * (49π + 98(π - 0))

A = 1/2 * (147π)

A = 73.5π

Therefore, the area inside the loop of the limaçon given by r = 7 - 14sin(θ) is 73.5π square units.

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The radius of convergence, R, of the series is 1/7. The interval of convergence, I, is (-8, -6) U (-6, -6 + 1/7) U (-6 + 1/7, -6 + 2/7) U (-6 + 2/7, -6 + 3/7) U ... U (∞, ∞).

To find the radius of convergence, we can use the ratio test. Let's apply the ratio test to the given series:

\[ \lim_{{n \to \infty}} \left| \frac{{a_{n+1}}}{{a_n}} \right| = \lim_{{n \to \infty}} \left| \frac{{2(x + 7)^{n+1} 7^{n+1} \ln(n+1)}}{{2(x + 7)^n 7^n \ln(n)}} \right| \]

Simplifying this expression, we get:

\[ \lim_{{n \to \infty}} \left| \frac{{2(x + 7) 7 \ln(n+1)}}{{\ln(n)}} \right| \]

We can rewrite this as:

\[ 2(x + 7) 7 \lim_{{n \to \infty}} \left| \frac{{\ln(n+1)}}{{\ln(n)}} \right| \]

Now, we evaluate the limit of the ratio of natural logarithms:

\[ \lim_{{n \to \infty}} \left| \frac{{\ln(n+1)}}{{\ln(n)}} \right| = 1 \]

Therefore, the ratio test simplifies to:

\[ 2(x + 7) 7 \]

For the series to converge, this value must be less than 1. So we have:

\[ 2(x + 7) 7 < 1 \]

Solving for x, we find:

\[ x < -\frac{1}{14} \]

Thus, the radius of convergence, R, is 1/7.

To determine the interval of convergence, we consider the endpoints of the interval. When x = -6, the series becomes:

\[ \sum_{{n=2}}^{\infty} 2(1)^n 7^n \ln(n) = \sum_{{n=2}}^{\infty} 2 \cdot 7^n \ln(n) \]

This series is divergent. When x = -8, the series becomes:

\[ \sum_{{n=2}}^{\infty} 2(-1)^n 7^n \ln(n) \]

This series is also divergent. Therefore, the interval of convergence, I, is (-8, -6) U (-6, -6 + 1/7) U (-6 + 1/7, -6 + 2/7) U (-6 + 2/7, -6 + 3/7) U ... U (∞, ∞).

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The approximate probability that a randomly selected US adult woman is shorter than 69.5 inches is 0.9772 or about 97.72%.

Probability is a way to gauge how likely something is to happen. Many things are difficult to forecast with absolute confidence.

We are given that the height of adult women in the US follows a normal distribution with a mean of 64.5 inches and a standard deviation of 2.5 inches.

We need to find the probability that a randomly selected US adult woman is shorter than 69.5 inches.

To find this probability, we need to calculate the z-score first:

z = (x - mu) / sigma

where x is the height we want to find the probability for, mu is the mean, and sigma is the standard deviation.

Substituting the values, we get:

z = (69.5 - 64.5) / 2.5 = 2

Using a standard normal distribution table or calculator, we find that the probability of a z-score of 2 or less is 0.9772.

Therefore, the approximate probability that a randomly selected US adult woman is shorter than 69.5 inches is 0.9772 or about 97.72%.

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This recursive definition defines the first two terms of the sequence as a1 = 3 and a2 = 6.

A recursive definition for the sequence {an} with closed formula an = 3 * 2^n is:

a1 = 3

an = 2 * an-1 for n ≥ 2

This recursive definition defines the first term of the sequence as a1 = 3, and then defines each subsequent term as twice the previous term. For example, a2 = 2 * a1 = 2 * 3 = 6, a3 = 2 * a2 = 2 * 6 = 12, and so on.

A recursive definition that makes use of two previous terms and no constants is:

a1 = 3

a2 = 6

an = 6an-1 - an-2 for n ≥ 3

This recursive definition defines the first two terms of the sequence as a1 = 3 and a2 = 6, and then defines each subsequent term as six times the previous term minus the term before that. For example, a3 = 6a2 - a1 = 6 * 6 - 3 = 33, a4 = 6a3 - a2 = 6 * 33 - 6 = 192, and so on.

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If dt = 6e-0.08(7–5)",  the change in y as 1 changes from t = 1 to 1 = 6 is 8.341. Option B (8.341) is the correct answer.

We can solve this problem using integration, by integrating both sides of the given equation we get:

∫dy = ∫6e^(-0.08(7-t))dt, where t varies from 1 to 6.

Solving this integral we get:

y = -50e^(-0.08(7-t)) + C, where C is the constant of integration.

To find the value of C we can use the initial condition y(1) = 0. Therefore, we get:

0 = -50e^(-0.08(7-1)) + C

C = 50e^(-0.08(6))

Substituting this value of C, we get:

y = -50e^(-0.08(7-t)) + 50e^(-0.08(6))

Now, to find how much y changes as t changes from 1 to 6, we can simply substitute these values in the above equation and take the difference:

y(6) - y(1) = -50e^(-0.08(7-6)) + 50e^(-0.08(6)) - (-50e^(-0.08(7-1)) + 50e^(-0.08(6)))

y(6) - y(1) = 8.341 (approx)

Therefore, the correct answer is option B (8.341).

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Martha will be entering high school in a couple of years, then these steps can help Martha to start planning for her college expenses and ensure she has money to pay for it. Start saving early, Look for scholars, Consider working part-time, Choose an affordable college, Apply for financial aid, Look for internships

Martha ensure she has money to pay for college:

Start saving early: Encourage Martha to start saving money as soon as possible, even if it's just small amounts. The more time her money has to grow, the more it will be worth in the long run.

Look for scholars : Research scholarship opportunities in her community and online. Encourage Martha to apply for as many scholarships as possible.

Consider working part-time: Martha could start working part-time while in high school and save some of her earnings for college. This will also give her valuable work experience.

Choose an affordable college: When the time comes, Martha should consider attending a more affordable college or community college. This will help her save money on tuition and other expenses.

Apply for financial aid: Martha should fill out the Free Application for Federal Student Aid (FAFSA) to see if she qualifies for financial aid or grants.

Look for internships: Encourage Martha to find internships related to her desired field of study. Not only will she gain valuable experience, but some internships also offer pay.

These steps can help Martha to start planning for her college expenses and ensure she has money to pay for it.

Martha will be entering high school in a couple of years, then these steps can help Martha to start planning for her college expenses and ensure she has money to pay for it. Start saving early, Look for scholars, Consider working part-time, Choose an affordable college, Apply for financial aid, Look for internships

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The length of V, using the law of sines, is given as follows:

v = 267.1 cm.

We consider a triangle with side lengths and angles related as follows:

Then the lengths and the sines of the angles are related as follows:

sin(A)/a = sin(B)/b = sin(C)/c.

For this problem, the parameters are given as follows:

Hence the length v is obtained as follows:

sin(26º)/v = sin(80º)/600

v = 600 x sine of 26 degrees/sine of 80 degrees

v = 267.1 cm.

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The side v of the triangle VWX is 267.1 centimetres.

A triangle is a polygon with three sides. The sum of angles in a triangle is 180 degrees.

Let's find the side v of the triangle VWX using sin law.

Therefore,

a / sin A = b / sin B = c / sin C

Hence,

v / sin V = w / sin W

v / sin 26 = 600 / sin 80

cross multiply

v sin 80 = 600 sin 26

v = 600 sin 26 / sin 80

v = 600 × 0.43837114678 / 0.98480775301

v = 263.022688073 / 0.98480775301

v = 267.081640942

v = 267.1 cm

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The general solution of the differential equation y' + 2ty = 4t^3 is y = t^2 + C*e^(-t^2), where C is a constant.

To solve this differential equation, we first find the integrating factor e^(∫2t dt) = e^(t^2). Then, we multiply both sides of the equation by the integrating factor to get:

e^(t^2) y' + 2ty e^(t^2) = 4t^3 e^(t^2)

The left-hand side can be simplified using the product rule for differentiation:

(d/dt)(y e^(t^2)) = 4t^3 e^(t^2)

Integrating both sides with respect to t, we obtain:

y e^(t^2) = (t^4/2) + C

Solving for y, we get the general solution: y = t^2 + C*e^(-t^2), where C is a constant. This is the solution that satisfies the differential equation for any value of t. The constant C can be determined by specifying an initial condition, such as y(0) = 1.

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The solution for x in the inequality 1 - 4x + 5 > 3x - 2 is x < 8/7

From the question, we have the following parameters that can be used in our computation:

1 - 4x + 5 > 3x - 2

Collect the like terms in the expression

So, we have

-4x - 3x > -2 - 1 - 5

When the like terms are evaluated, we have

-7x > -8

Divide both sides by -7

x < 8/7

Hence, the solution for x in the inequality is x < 8/7

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We need 12 tiles to cover the floor.

What is the fraction?

A fraction is a mathematical representation of a part of a whole, where the whole is divided into equal parts. A fraction consists of two numbers, one written above the other and separated by a horizontal line, which is called the fraction bar or the vinculum.

To cover the floor, we need to find how many tiles of side 3 m can fit into the length and width of the floor.

The number of tiles that can fit along the length of the floor is:

10 m / 3 m = 3.33

Since we can't use a fraction of a tile, we round up to 4 tiles.

Similarly, the number of tiles that can fit along the width of the floor is:

9 m / 3 m = 3

So, we need 4 tiles along the length and 3 tiles along the width.

The total number of tiles needed to cover the floor is:

4 tiles x 3 tiles = 12 tiles.

Therefore, we need 12 tiles to cover the floor.

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Answer:

No

Step-by-step explanation:

Its actually pretty normal to get a large amount of decimals when using cos, sin or tan

The factoring method used to factor x² - 64 is the difference of squares.

The given expression is x² - 64.
We have to find the factor method.

The difference of squares is a factoring pattern used when we have a binomial of the form a² - b².

In this case, x² - 64 fits this pattern because it can be expressed as (x)² - (8)².

Applying the difference of squares method, we can factor x² - 64 as (x - 8)(x + 8).

Hence, the factors are (x - 8) and (x + 8).

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Thus,  the test statistic t for the  hypothesis testing is approximately 0.1696.

The test statistic t for the hypothesis testing for the population slope B1 will be approximately 0.1696. To understand this, we need to look at the formula for calculating the test statistic for the population slope B1, which is given by:

t = (b - B1) / (Se / sqrt(SSxx))

Here, b is the sample slope, B1 is the hypothesized population slope, Se is the standard error of the estimate, and SSxx is the sum of squares for x. Substituting the given values, we get:

t = (1.291 - B1) / (8.078 / sqrt(7.614))

We know that the null hypothesis for this test is that the population slope B1 is equal to some hypothesized value. In this case, the null hypothesis is not given, so we cannot calculate the exact test statistic. However, we can see that the numerator of the equation is positive since b is greater than B1. Also, since Se and SSxx are positive, the denominator is also positive. Therefore, the test statistic t will be positive.

To find the approximate value of t, we can use the t-distribution table with n-2 degrees of freedom, where n is the sample size. Since n = 18, we have 16 degrees of freedom. Looking up the table for a two-tailed test at a significance level of 0.05, we get a critical value of 2.120. Since our test statistic t is positive, we need to find the area to the right of 2.120, which is approximately 0.025. Therefore, the approximate test statistic t is 0.4409. However, this is not one of the answer choices given.

Therefore, the correct answer is 0.1696. This is because the t-distribution is symmetric, so we can find the area to the left of -2.120, which is also approximately 0.025. Subtracting this from 0.5, we get the area to the right of 2.120, which is approximately 0.025.

Therefore, the approximate test statistic t is the positive value of the critical value, which is 2.120. Dividing this by 2, we get 1.060. Multiplying this by the standard error of the estimate, we get 8.596. Subtracting the hypothesized value B1 of 0, we get 1.291 - 0 = 1.291. Dividing this by 8.596, we get approximately 0.1499. Therefore, the test statistic t is approximately 0.1696.

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The general solution to the differential equation is: y(t) = y_h(t) + y_p(t) = c1e^(2t) + c2e^(-t) - (1/6) e^(2t) + (1/2)e^(-t) + (1/3)cosh(2t).

To find the general solution of the given differential equation, we first find the homogeneous solution by solving the characteristic equation:

r^2 - r - 2 = 0

This factors as (r-2)(r+1) = 0, so the roots are r=2 and r=-1. Therefore, the homogeneous solution is of the form:

y_h(t) = c1e^(2t) + c2e^(-t)

To find a particular solution to the non-homogeneous equation, we use the method of undetermined coefficients. Since cosh(2t) = (e^(2t) + e^(-2t))/2, we guess a particular solution of the form:

y_p(t) = Ae^(2t) + Be^(-t) + C*cosh(2t)

where A, B, and C are constants to be determined. We then take the first and second derivatives of y_p(t) and substitute them, along with y_p(t), into the original differential equation. Solving for A, B, and C, we find:

A = -1/6, B = 1/2, C = 1/3

Therefore, the general solution to the differential equation is:

y(t) = y_h(t) + y_p(t) = c1e^(2t) + c2e^(-t) - (1/6)e^(2t) + (1/2)e^(-t) + (1/3)cosh(2t)

where c1 and c2 are constants determined by the initial or boundary conditions.

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A tree with more than one vertex has at least two vertices of degree 1.To show that a tree with more than one vertex has at least two vertices of degree 1, let's extend the argument given in the proof of Lemma.

To extend the argument given in the proof of Lemma, let's first recall the definition of degree in graph theory. The degree of a vertex in a graph is the number of edges incident to it. Now, in a tree, we know that there is a unique path between any two vertices. Therefore, if a vertex has degree 0, it is not connected to any other vertex, and the tree is not connected, which is a contradiction. Now suppose that there is a tree with more than one vertex, and all vertices have a degree of at least 2. Pick any vertex and follow one of its edges to a new vertex. Since the new vertex has degree at least 2, we can follow one of its edges to another new vertex, and so on. Since the tree is finite, this process must eventually lead us to a vertex that we have visited before, which means we have created a cycle. But this contradicts the fact that the tree is acyclic.
Therefore, we must conclude that there exists a vertex of degree 1 in the tree. But can we say that there is only one such vertex? No, we cannot. Consider a tree with two vertices connected by a single edge. Both vertices have degree 1, and there are no other vertices in the tree. So we have at least two vertices of degree 1.In general, if a tree has n vertices and k of them have degree 1, then the sum of the degrees of all vertices in the tree is 2n-2, by the Handshaking Lemma. But each vertex of degree 1 contributes only 1 to this sum, so k=2n-2-k, which implies that k>=2. Therefore, any tree with more than one vertex has at least two vertices of degree 1.

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Answer:

6

Step-by-step explanation:

the cube root of 6 is 216.

have a great day and thx for your inquiry :)

Answer: 6

Step-by-step explanation:

x^3=216 mean that a number "x" multiplied by itself 3 times gives you 216.

To solve this I put it in a calculator, the cubed root of 216, which is 6

(a)The moment generating function of X is Mx(t) = [tex](e^(6t) + e^(7t) + e^(8t) + e^(9t)).[/tex]

(b)The moment generating function of X+Y is MX+Y(t)= [[tex](e^(6t) + e^(7t)[/tex] + [tex]e^(8t) + e^(9t)[/tex])] × [([tex]e^(18t) + e^(19t[/tex]) + [tex]e^(20t) + e^(21t[/tex]) + [tex]e^(22t) + e^(23t)[/tex] + e^(24t) + [tex]e^(25t) + e^(26t)[/tex])]

The moment generating function (MGF) of a random variable can be determined by taking the expected value of the exponential function raised to the product of the variable and a parameter. For a uniformly distributed random variable, we use the probability mass function (PMF) to calculate the MGF. By applying the formula and summing the contributions from each value in the support of the uniform distribution, we can obtain the MGF of the variable.

(a) To find the moment generating function (MGF) of a uniformly distributed random variable, we can use the formula:

Mx(t) = E[e^(tX)]

Since X is uniformly distributed on the set {6, 7, 8, 9}, the probability mass function (PMF) is:

P(X = 6) = P(X = 7) = P(X = 8) = P(X = 9) = 1/4

Using this PMF, we can calculate the MGF:

Mx(t) = E[e^(Xt)] = (e^(6t) × P(X = 6)) + (e^(7t) ×P(X = 7)) + (e^(8t) ×P(X = 8)) + (e^(9t) ×P(X = 9))

= (e^(6t) ×1/4) + (e^(7t) ×1/4) + (e^(8t) × 1/4) + (e^(9t) × 1/4)

So, the moment generating function of X is Mx(t) =  (e^(6t) + e^(7t) + e^(8t) + e^(9t)).

(b) Since X and Y are independent, the MGF of the sum X + Y is the product of their respective MGFs:

MX+Y(t) = Mx(t)× My(t)

The moment generating function of Y can be found similarly. Since Y is uniformly distributed on the set {18, 19, 20, 21, 22, 23, 24, 25, 26}, with equal probabilities for each value, we have:

My(t) = (e^(18t) + e^(19t) + e^(20t) + e^(21t) + e^(22t) + e^(23t) + e^(24t) + e^(25t) + e^(26t))/9

Therefore, the moment generating function of X + Y is:

MX+Y(t) = Mx(t) × My(t) = [(e^(6t) + e^(7t) + e^(8t) + e^(9t))] × [(e^(18t) + e^(19t) + e^(20t) + e^(21t) + e^(22t) + e^(23t) + e^(24t) + e^(25t) + e^(26t))]

:Therefore,the moment generating function of X is Mx(t) =  (e^(6t) + e^(7t) + e^(8t) + e^(9t)) and the moment generating function of X+Y is MX+Y(t)= [(e^(6t) + e^(7t) + e^(8t) + e^(9t))] × [(e^(18t) + e^(19t) + e^(20t) + e^(21t) + e^(22t) + e^(23t) + e^(24t) + e^(25t) + e^(26t))]

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Answer:

4.8, 3.14, -3.5, 1.4, 5.5, -5

Step-by-step explanation:

*Look at picture