Find the area of a triangular garden if the sides are approximately 6 feet, 14 feet, and 13 feet (to the nearest square foot).

546 ft2

39 ft2

10 ft2

578 ft2

Answer:

6 feet per minute

Step-by-step explanation:

Answer:

6 feet per minute.

Step-by-step explanation:

5ft + 1ft = 6ft per minute.

Answer:

82.97cm^2

Step-by-step explanation:

Given data

Circumference=  131.88 centimeters

We want to find the area of 6/10 part of a circle

Firstly, let us find the area of the circle

We need to get the radius

C= 2πr

131.88= 2*3.142*r

131.88=6.284r

r=  131.88/6.284

r=20.98 cm

Area= πr^2

Area= 3.142*20.98^2

Area= 3.142*440.16

Area= 1382.98cm^2

Hence 6/10 of a 1382.98

=0.06*1382.98

=82.97cm^2

Answer:

true

Step-by-step explanation:

first find the median of the lower and upper half of the data. These values are quartile 1 (Q1) and quartile 3 (Q3). The IQR is the difference between Q3 and Q1.

Answer:

Step-by-step explanation:

1) r = 5mm; d = 10 mm

2) r = 6 cm; d = 12 cm

3) r = 9 m; d = 18 m

4) r = 8 km; d = 16 km

5) r = 11 m; d = 22 m

6) r = 15 mm; d = 30 mm

7) r = 13 km; d = 26 km

8) r = 7 cm; 14 cm

Answer:

4*s= 520

s= 130

area=s*s=130*130=16900m^2

Step-by-step explanation:

Answer:

y = 1/2x + 5

Step-by-step explanation:

The formula for an equation is y = mx + b

m is the slope. It is given

y = 1/2x + b

b is the y-intercept

In this case, we must substitute to find the y-intercept

We are given coordinate pair (4,7)

Plug our pair in and we get => 7 = 1/2(4) + b

=> 7 = 2 + b

easily, we find b = 5

We get our equation: y = 1/2x + 5

Cheers!

1) Power of a Product

2) Power Rule (or Power of a Power)

Answer:

-Number 1 is Power of a Power Property, I think

-Number 2 is Power of a Power Property

Answer:

10x + 12 and 6x² + 11x - 7

Step-by-step explanation:

The perimeter (P) of a rectangle is calculated as

P = 2l + 2w ( l is length and w is width )

   = 2(2x - 1) + 2(3x + 7) ← distribute parenthesis

    = 4x - 2 + 6x + 14 ← collect like terms

     = 10x + 12

--------------------------------------------------

The area (A) of a rectangle is calculated as

A = lw

   = (2x - 1)(3x + 7) ← expand using FOIL

    = 6x² + 14x - 3x - 7 ← collect like terms

    = 6x² + 11x - 7

Answer:

29

Step-by-step explanation: pls dont get mad if it is wrong

<3<3<3<3<3<3

Answer:

29

<3<3<3<3<3<3

Answer:

7 cars

Step-by-step explanation:

The computation of the number of cars to be filled is shown below:

A car that is 90% full and the total people is 20 so 90% would be

= (.90)(20)

= 18

A car that is 65% full and the total people is 20 so 65% would be

= (.65)(20)

= 13

Now

Total number of people = (5)(18) + (3)(13).

= 129

Now the number of cars to be filled is

= 129 ÷ 20

= 6.45

= 7 cars

Answer:

i love ur profile pic

Step-by-step explanation:

and j

put a dot on 3 for the y side

Answer:

D

Step-by-step explanation:

Where the graphs intersect each other is where the solution is. The graphs intersect each other at the points (0,-8) and (4,8). Hope this helps!

Answer:

B

Step-by-step explanation:

The answer is B hope that help

Answer:

6

Step-by-step explanation:

Answer:

g-6=b

hope this helps

Answer:

60

Step-by-step explanation:

24 dividend by 4 equals 6.

this means 10% of the original price is 6.

6 times 10 equals 60

hope this helps!!!

Answer:

( + 10)

Hope this helps you out

9514 1404 393

Explanation:

The length CD can be found from the Pythagorean theorem.

  CF² + CD² = DF²

  2² + CD² = (2√10)²

  CD² = 40 -4 = 36

  CD = √36 = 6

From here, any of several methods could be used to find the area of ΔDEF.

One of them is to subtract the areas of the triangles that are not ΔDEF from the area of the rectangle ABCD.

  area ABCD = bh = (6 cm)(5 cm) = 30 cm²

  area ΔADE = 1/2bh = 1/2(4 cm)(5 cm) = 10 cm²

  area ΔBEF = 1/2bh = 1/2(2 cm)(3 cm) = 3 cm²

  area ΔCDF = 1/2bh = 1/2(6 cm)(2 cm) = 6 cm²

Then the area of interest is ...

  area ΔDEF = area ABCD -area ΔADE -area ΔBEF -area ΔCDF

  area ΔDEF = (30 -10 -3 -6) cm²

  area ΔDEF = 11 cm²

__

Alternate solution

If we define A as the origin of a coordinate system, then the coordinates of the vertices of ΔDEF are ...

  D(0, 5), E(4, 0), F(6, 3)

The area can be computed as half the absolute value of the sum of the determinants of 2×2 matrices consisting of adjacent points.

  [tex]A=\dfrac{1}{2}\left|\left|\begin{array}{cc}0&5\\4&0\end{array}\right|+\left|\begin{array}{cc}4&0\\6&3\end{array}\right|+\left|\begin{array}{cc}6&3\\0&5\end{array}\right| \right|\\\\=\dfrac{1}{2}|(0-20)+(12-0)+(30-0)|=\dfrac{1}{2}(22) = \boxed{11}[/tex]

_____

Additional comment

The solution using coordinates is effectively equivalent to the computation of the area of trapezoid ABFD, less the areas of triangles EBF and AED.

9514 1404 393

Answer:

  (b)  a trapezoid

Step-by-step explanation:

A graph of the points reveals one pair of parallel sides: a trapezoid.

Answer:

7 cds

Step-by-step explanation:

8.49*x +5=70 => 8.49*x=65 => x= 65/8.49 => x= 7 approximately

Answer:

3. D

4. A

5. B

Step-by-step explanation:

Answer:

Amplitude: 4

Period: π

midline: y = 1

Step-by-step explanation:

r(x) = -4 sin(2x) + 1

r(x) = a sin(bx + c) + d where |a| is the amplitude and |b| for the period

a = -4         |a| = 4 :   Amplitude = 4

b = 2          |b| = 2     period of sin(x) = 2π

                                period of sin(bx + c) = 2π/|b| = 2π/2 = π

range of sin(2x) ... -1 ≤ sin(2x) ≤ 1

range of -4 sin(2x) + 1: -4+1 ≤ -4 sin(2x) + 1 ≤ 4+1    

-3 ≤ -4 sin(2x) + 1 ≤ 5

midline: y = (-3 + 5) / 2 = 1        y = 1

Answer:

Part A: The amplitude [tex]\displaystyle r[/tex]is [tex]\displaystyle 4.[/tex]

Part B: The period of [tex]\displaystyle r[/tex]is [tex]\displaystyle \pi.[/tex]

Part C: The equation of the midline of [tex]\displaystyle r[/tex]is [tex]\displaystyle y = 1.[/tex]

Step-by-step explanation:

[tex]\displaystyle \boxed{r(x) = -4cos\:(2x - \frac{\pi}{2}) + 1} \\ \\ r(x) = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 1 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{\frac{\pi}{4}} \hookrightarrow \frac{\frac{\pi}{2}}{2} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\pi} \hookrightarrow \frac{2}{2}\pi \\ Amplitude \hookrightarrow 4[/tex]

OR

[tex]\displaystyle r(x) = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 1 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\pi} \hookrightarrow \frac{2}{2}\pi \\ Amplitude \hookrightarrow 4[/tex]

Keep in mind that although this IS a sine function, if you plan on writing your equation as a function of cosine, then there WILL be a horisontal shift, meaning that a C-term will be involved. As you can see, the centre photograph displays the trigonometric graph of [tex]\displaystyle r(x) = -4cos\:2x + 1,[/tex]in which you need to replase "sine" with "cosine", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the sine graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the cosine graph [centre photograph] is shifted [tex]\displaystyle \frac{\pi}{4}\:unit[/tex]to the left, which means that in order to match the sine graph [photograph on the left], we need to shift the graph FORWARD [tex]\displaystyle \frac{\pi}{4}\:unit,[/tex]which means the C-term will be positive, and by perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{\frac{\pi}{4}} = \frac{\frac{\pi}{2}}{2}.[/tex]So, the cosine graph of the sine graph, accourding to the horisontal shift, is [tex]\displaystyle r(x) = -4cos\:(2x - \frac{\pi}{2}) + 1.[/tex]So, with all that being said, to find the period, again, take a look at the above information next to [tex]\displaystyle Wavelength\:[Period].[/tex]Now, the amplitude is obvious to figure out because it is the A-term. Moreover, the midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = 1,[/tex]in which each crest is extended four units beyond the midline, hence, your amplitude. Now, there is one more piese of information you should know -- the sine graph in the photograph farthest to the right is the OPPOCITE of the sine graph in the photograph farthest to the left, and the reason for this is because of the negative inserted in front of the amplitude value. Whenever you insert a negative in front of the amplitude value of any trigonometric equation, the whole graph reflects over the midline. Keep this in mind moving forward. Now, with all that being said, no matter how far the graph shifts vertically, the midline will ALWAYS follow.

I am delighted to assist you at any time.

Answer:

[tex]x=\sqrt{41}[/tex]

Step-by-step explanation:

Pythagorean theorem: [tex]a^{2}+ b^{2}=c^{2}[/tex]

Answer:

Option B

Step-by-step explanation:

Pythagorean Theron is:

[tex]a^2+b^2=c^2\\\\\text{a and b - legs}\\\text{c - hypotenuse}[/tex]

We would be solving for 'c', or the hypotenuse.

[tex]4^2+5^2=c^2\\\\16+25=c^2\\\\41=c^2\\\\\boxed{\sqrt{41}, -\sqrt{41} =c}[/tex]

The correct answer should be option B.

Hope this helps.

Answer:

8.6

Step-by-step explanation:

Use the distance formula to find the distance between the two points.

√[(x₂ - x₁)² + (y₂ - y₁)²]

√[(3 - -4)² + (3 - -2)²]

√[(7)² + (5)²]

√[(49) + (25)]

√74

8.6

Answer:

11,000

Step-by-step explanation: