Find the area of the triangle.

The value of tan C in the figure is 7/24

Information from the question

The value of tan x is worked using SOH CAH TOA

Sin = opposite / hypotenuse - SOH

Cos = adjacent / hypotenuse - CAH

Tan = opposite / adjacent - TOA

The figure describes a right angle triangle of

hypotenuse = 50

opposite = ?

adjacent = 14

Using cos, CAH for angle C

sin C = Opposite / hypotenuse

sin C = 14 / 50

x = arc sin (14/50)

Solving for tan x

tan (arc sin (14/50)) = 7/24

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Linear functions used in predictive analytical models are typically used when there is a steady increase or decrease over a range of a variable(A).

Linear functions are mathematical models that describe a relationship between two variables that is a straight line. In predictive analytical models, linear functions are used when there is a consistent and steady increase or decrease over a range of a variable.

This means that for every unit increase in one variable, there is a constant increase or decrease in the other variable. Linear functions are not used when the rate of change is variable or when there is an increase in the rate of change at a specific rate.

In these cases, other mathematical models, such as exponential or polynomial functions, may be more appropriate. So correct option is A.

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E = tan(2) cosh(2) / sinh(2) + i cos(2) / sinh(2) in rectangular form.

We have:

D = (-5+5i)(2+2i)

= -10 - 10i + 10i - 10i^2

= -10 - 10i + 10 + 10i (since i^2 = -1)

= 0

Therefore, D = 0 + 0i in rectangular form.

We have:

E = tan(1- i) cot(1+i)

= (sin(1-i)/cos(1-i)) (cos(1+i)/sin(1+i))

= (sin(1)cos(i) - cos(1)sin(i)) / (cos(1)cos(i) + sin(1)sin(i)) * (cos(1)cos(i) - sin(1)sin(i)) / (sin(1)cos(i) + cos(1)sin(i))

= (sin(1) cosh(1) - i cos(1) sinh(1)) / (cos(1) cosh(1) + i sin(1) sinh(1)) * (cos(1) cosh(1) + i sin(1) sinh(1)) / (sin(1) cosh(1) - i cos(1) sinh(1)) (using hyperbolic identities)

= [(sin(1) cosh(1))^2 + (cos(1) sinh(1))^2] / [(sin(1) cosh(1))^2 - (cos(1) sinh(1))^2] + i [(cos(1) cosh(1) sin(1) sinh(1)) / [(sin(1) cosh(1))^2 - (cos(1) sinh(1))^2]]

= [(sin(2) sinh(2)) / (sinh(2) cos(2))] + i [(cos(2) sinh(2)) / (sinh(2) cos(2))]

= [(sin(2) / cos(2))] / [(sinh(2) / cosh(2))] + i [(cos(2) / cosh(2))] / [(sinh(2) / cosh(2))]

= tan(2) cosh(2) / sinh(2) + i cos(2) / sinh(2)

Therefore, E = tan(2) cosh(2) / sinh(2) + i cos(2) / sinh(2) in rectangular form.

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Yes, you can still cover the remaining squares with dominoes. The necessary and sufficient condition for this to work is that the chessboard originally had an even number of squares.


A standard chessboard has 64 squares. If one corner square is missing, we are left with 63 squares. Each domino covers exactly 2 squares, so we need 31.5 dominoes to cover the remaining squares. Since we cannot use half a domino, this means we need a whole number of dominoes. Therefore, the number of squares must be even.

Conversely, if the chessboard originally had an even number of squares, then we can remove any one square and still have an odd number of squares left. Since each domino covers 2 squares, it is easy to see that we can always cover an odd number of squares with dominoes, by placing one domino vertically in the middle of the board. Therefore, in this case we can also cover the remaining squares with dominoes.

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The key words in the question are "descriptive statistics." "Descriptive" refers to describing or summarizing data, while "statistics" refers to the collection, analysis, and interpretation of data.

This question relates to the topic of statistics.

To solve this question, you need to identify which situation involves the use of descriptive statistics. You can do this by understanding that descriptive statistics involves summarizing or describing data, such as calculating measures of central tendency (like the mean or median) or analyzing the distribution of data.

The correct answer choice is C) A study shows that the average student leaves a four-year college with a student loan debt of more than $30,000. This situation involves the use of descriptive statistics because it describes the average amount of student loan debt for a particular group of people (students who attend four-year colleges).

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The direction of the resultant vector is 251.57°

From the graph, we see that we have two vectors w = (10, 4) and v = (-14 , -16). Re-writing both vectors in component form, we have that

W = 10i + 4j and

v = -14i - 16j

So, the resultant vector is the sum of both vectors.

So, we have that

R = w + v

= 10i + 4j + (-14i - 16j)

= 10i - 14i + 4j - 16j

= -4i - 12j

So, the direction of the resultant vector is given by Ф = tan⁻¹(y/x) where y = -12 and x = -4

So, substituting the vaklues of the variables into the equation, we have that

Ф = tan⁻¹(y/x)

Ф = tan⁻¹(-12/-4)

Ф = tan⁻¹(3)

= 71.57°

Since the vector is in the 3rd quadrant, its directions is Ф = 180° + 71.57° = 251.57°

So, the direction is 251.57°

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You have been contracted to complete a square garden landscape. You will need to add $75 to the total cost of supplies to pay for shipping and tax; you would also like to make $450, then we need to charge the client $63[tex]x^2[/tex] + 525 for this job.

Let's denote the length and width of the square garden by x. Then, the area of the garden is given by A = [tex]x^2[/tex].

To complete the landscape, we need to cover the garden with bushes and gravel. The area of the garden is [tex]x^2[/tex] square feet, so we need to order [tex]x^2[/tex] bushes and [tex]x^2[/tex] bags of gravel.

The cost of the bushes is $45 per bush, so the total cost for the bushes is [tex]45x^2[/tex]. The cost of the gravel is $18 per bag, so the total cost for the gravel is [tex]18x^2.[/tex]

The total cost of the supplies is the sum of the cost of the bushes and the cost of the gravel, plus $75 for shipping and tax:

Total cost = [tex]45x^2 + 18x^2 + 75 = 63x^2 + 75[/tex]

We also want to make a profit of $450, so the amount we need to charge the client is:

Total cost + Profit = 63x^2 + 75 + 450 = 63[tex]x^2[/tex] + 525

Therefore, we need to charge the client $63[tex]x^2[/tex] + 525 for this job.

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Yes, the corner of the frame create a 90 degree angle

The picture frame's sides labeled as:

Employing the Pythagorean theorem provides us means to check whether side C, i.e., the frame's diagonal and the hypotenuse produces a right angle amidst sides A and B.

The Pythagorean formula states that:

C^2 = A^2 + B^2

C^2 = 15^2 + 8^2,

C^2 = 225 + 64

C = sqrt(289)

C = 17

since the result from Pythagoras equals the result of the equation then we have the hypotenuse is equal to the diagonal and the frame forms angle 90 degrees

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Answer: For the first one

9037 and 21800

Step-by-step explanation:

Add them all up.

Answer:

62%

Step-by-step explanation:

Its addition, 38+24=62

30+20+12=62 to make thing simpler.

The statement "if two continuous functions defined on the interval have the same Laplace transform, then the two functions are identical" is false.

The Laplace transform is a mathematical tool used to convert a function of time into a function of complex frequency. It is used to solve differential equations and study the behavior of systems in the time domain. The Laplace transform of a function f(t) is defined as:

F(s) = L{f(t)} = ∫[0, ∞] f(t)[tex]e^{(-st)[/tex] dt

where s is a complex frequency.

It is possible for two different functions to have the same Laplace transform. This phenomenon is known as Laplace transform pairs. For example, the Laplace transform of both sin(t) and cos(t) is (s/(s^2+1)). Therefore, it is not true that if two functions have the same Laplace transform, then they are identical.

However, there are certain conditions under which the inverse Laplace transform can be used to recover the original function. For example, if the Laplace transform of a function is known to be rational, then the original function can be recovered using partial fraction decomposition. Similarly, if the Laplace transform of a function is known to be an exponential function, then the original function can be recovered using a table of Laplace transforms.

In general, the relationship between a function and its Laplace transform is complex and depends on the properties of the function and the Laplace transform. So, the statement "if two continuous functions defined on the interval have the same Laplace transform, then the two functions are identical" is false.

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The gradient of the function f(x, y) = [tex]-10x^2[/tex] - 8y at the given point (-8, 6) is (160, -8).

To compute the gradient of the function f(x, y) = -[tex]10x^2[/tex] - 8y at the given point (-8, 6), follow these steps:

1. Find the partial derivatives of f with respect to x and y.

2. Evaluate the partial derivatives at the given point.

3. Combine the partial derivatives into a gradient vector.

Step 1: Find the partial derivatives.

∂f/∂x = -20x

∂f/∂y = -8

Step 2: Evaluate the partial derivatives at the given point (-8, 6).

∂f/∂x at (-8, 6) = -20(-8) = 160

∂f/∂y at (-8, 6) = -8

Step 3: Combine the partial derivatives into a gradient vector.

Gradient = (∂f/∂x, ∂f/∂y) = (160, -8)

So, the gradient of the function f(x, y) = [tex]-10x^2[/tex] - 8y at the given point (-8, 6) is (160, -8).

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The result is stored in the array `X`, which represents the frequency of the gene over time.

We have,
To generate random variates according to the standard normal distribution in Python, you can use the `numpy` library:

```python
import numpy as np

# Generate random variates according to the standard normal distribution
random_variates = np.random.randn(1024)
```

Now that you have the random variates, you can simulate an approximate realization of the Brownian motion using the Euler-Maruyama method with Δt = 1:
```python
# Set the parameters
delta_t = 1
X = np.zeros(len(random_variates) + 1)

# Initialize the gene frequency
X[0] = 0.5

# Use the Euler-Maruyama method to simulate the Brownian motion
for i in range(len(random_variates)):
   dW = random_variates[i] * np.sqrt(delta_t)
   X[i + 1] = X[i] + X[i] * (1 - X[i]) * dW
```

With this code, you have generated an approximate realization of the Wright-Fisher model using a numerical method (Euler-Maruyama) for a Brownian motion with Δt = 1.

Thus,

The result is stored in the array `X`, which represents the frequency of the gene over time.

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The maximum number of coins that the oldest thief might get is 751.

Let's assume that there are seven thieves, numbered 1 through 7, and their ages are a1, a2, ..., a7 such that a1 is the age of the oldest thief.

If the oldest thief proposes that he gets all 1000 coins, then he will vote for his own proposal, and at most one other thief will vote for it (since they would receive nothing in this scenario). Therefore, the proposal would be rejected.

If the oldest thief proposes that he gets 999 coins and the remaining 1 coin is split among the other six thieves, then he will vote for his own proposal, and all the other thieves will vote for it as well (since they would receive a positive amount of coins in this scenario). Therefore, the proposal would be accepted, and the oldest thief would receive 999 coins.

If the oldest thief proposes that he gets 998 coins and the remaining 2 coins are split among the other six thieves, then he will vote for his own proposal, and at least two other thieves will vote for it (since they would receive a positive amount of coins in this scenario). Therefore, the proposal would be accepted, and the oldest thief would receive 998 coins.

Continuing in this manner, the oldest thief can propose that he receives n coins and the remaining 1000-n coins are split among the other six thieves, where n ranges from 999 to 502. For each value of n, the oldest thief will vote for his own proposal, and at least four other thieves will vote for it (since they would receive a positive amount of coins in this scenario). Therefore, the proposal would be accepted, and the oldest thief would receive n coins.

The maximum value of n for which the proposal would be accepted is when n=751, since in this case, the oldest thief would receive more than half of the coins (i.e., 751 coins), and therefore, at least four other thieves would vote for the proposal. Therefore, the maximum number of coins that the oldest thief might get is 751.

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The rectangle has 222.2 cm² more area than the square.

We have,

The area of the rectangle is:

= 6 cm x 41.2 cm

= 247.2 cm²

The area of the square is:

= 5 cm x 5 cm

= 25 cm²

The rectangle has a greater area than the square, by:

= 247.2 cm² - 25 cm²

= 222.2 cm²

Therefore,

The rectangle has 222.2 cm² more area than the square.

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Answer:

142 ft

Step-by-step explanation:

We have to find the perimeter of the rectangular garden.

     length = 30 ft

      Width = 41 ft

        [tex]\sf \boxed{\text{\bf Perimeter of rectangle =2*( length + width)}}[/tex]

                                                  = 2 * (30 + 41)

                                                  = 2 * 71

                                                  = 142 ft

You will need 142 feet of fence to enclose the rectangular garden with length 30 feet and width 41 feet. To determine the amount of fence needed to enclose a rectangular garden with length 30 feet and width 41 feet, follow these steps:

1. Identify the dimensions of the rectangular garden. In this case, the length is 30 feet and the width is 41 feet.
2. Recall the formula for the perimeter of a rectangle: P = 2(L + W), where P is the perimeter, L is the length, and W is the width.
3. Plug in the given dimensions: P = 2(30 + 41).
4. Calculate the sum inside the parentheses: P = 2(71).
5. Multiply by 2 to find the perimeter: P = 142 feet.

So, you will need 142 feet of fence to enclose the rectangular garden with length 30 feet and width 41 feet.

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The value of Cos K as a fraction in simplest terms is K= 42.3⁰

Pythagoras Theorem states that “In a right-angled triangle”, “the square of the hypotenuse side is equal to the sum of squares”. This theorem can be used to derive the base, perpendicular and hypotenuse formulas

CosK = Adj/Hypo

where the Adj = ?

Hypo = 12 Using pyth. rule to find adj

12² = (√51)² + x²

= 144 = 51 + x²

144-51 = x²

93 = x²

x = √93 = 9.6

Then Applying CosK = Adj/Hypo

CosK = √51/9.6

Cos K = 7.1/9.6

Cosk = 0.7396

Making K the subject of the relation we have

K = cos⁻0.7396

K= 42.3⁰

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Answer:

I assume that "Rud" is a typo and you mean "Sin" instead.

To find the derivative of Sin(x^2) - Cos(x), we need to use the chain rule and the derivative of the trigonometric functions.

The derivative of Sin(x^2) is:

d/dx [Sin(x^2)] = Cos(x^2) * d/dx [x^2] = 2x * Cos(x^2)

The derivative of -Cos(x) is:

d/dx [-Cos(x)] = Sin(x)

Therefore, the derivative of the function Sin(x^2) - Cos(x) is:

2x * Cos(x^2) + Sin(x)

So the answer is option (b) -2xcos(x^2) + sin(x).

The answer is option (b): -2xcos(x^2).

Assuming that "Rud-cost" is a typo and the function is meant to be "Rudin-cost", which is a function defined as:

Rudin-cost(x) = cos(x^2)

To find the derivative of Rudin-cost(x), we can use the chain rule and the power rule for differentiation. Specifically, if we let u = x^2, then we have:

Rudin-cost(x) = cos(u)

Using the chain rule, we get:

Rudin-cost'(x) = -sin(u) * u'

where u' is the derivative of u with respect to x, which is:

u' = d/dx(x^2) = 2x

Substituting this back into the expression for Rudin-cost'(x), we get:

Rudin-cost'(x) = -sin(x^2) * 2x

Therefore, the answer is option (b): -2xcos(x^2).

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We have shown that if A, B, and C are sets, and ACB, then A-CCB-C.

To prove: If A, B, and C are sets, and ACB, then A-CCB-C.

Proof:

Assume that A, B, and C are sets, and ACB.

To show: A-CCB-C.

Let x be an arbitrary element of A-CC. Then, by definition, x is an element of A and not an element of C.

Since ACB, we know that x is either an element of A and B, or an element of C and B.

If x is an element of A and B, then x is an element of B. Since x is not an element of C, we can conclude that x is an element of B-C.

If x is an element of C and B, then x is an element of B. Since x is not an element of C, we can conclude that x is an element of B-C

In either case, we have shown that x is an element of B-C.

Therefore, we have shown that if A, B, and C are sets, and ACB, then A-CCB-C.

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The percentage of budget that is allotted to variable expenses is 46.03%

We first have to determine the solution for what the va,riable expenses is supposed to be

$2,003 (total budget) - $1,081 (fixed expenses)

= $922

Next we will have to solve for the percentage that is the budget which is allocated to the variable expenses

This is simply written as

variable expenses / total budget * 100

($922 (variable expenses) ÷ $2,003 (total budget)) × 100 = 46.03%

Hence the percentage of budget that is allotted to variable expenses is 46.03%

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Answer:

46.03%

Step-by-step explanation:

922 ÷ 2003 x 100 which gives you 46.03

The given function is a valid probability density function.

We have,

B.

As f(x) ≥ 0 for all values of x and the total area under the density function above the x-axis is 1, the given function is a valid probability density function.

(a)

P(x < 6) = 0.5 (area of the rectangle with base 6 and height 0.1)

(b) P(x > 5) = 0.3 (area of the triangle with base 1 and height 0.3)

(c) P(4 < x < 8) = 0.8 (area of the rectangle with base 4 and height 0.1 plus the area of the triangle with base 4 and height 0.7 plus the area of the rectangle with base 2 and height 0.1)

(d) P(6 < x < 7) = 0.4 (area of the rectangle with base 1 and height 0.4)

Thus,

The given function is a valid probability density function.

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Fron the sine rule of a right angled triangle, the missing values of table are

The complete table with all values is present in below attached figure 2.

We have a right angled triangle with one angle as right angle present in above figure. We have to complete the table present below the figure. The measure of angles of triangle except right angle are 60° and 45°. Also, the side lengths of triangle are 'a', 'b' and 'c' units. Using the sine rule, [tex]\frac{a}{sin(A)} =\frac{ b}{sin (B)} = \frac{c}{sin(C)}[/tex]

Here, A = 30°, B = 60°, C = 90° so, [tex]\frac{a}{sin(30°)} = \frac{ b}{sin(60°)} = \frac{c}{sin(90°)} [/tex]

From the Trigonometry Ratio table of

So, [tex] \frac{ a}{ \frac{1}{2} } = \frac{b}{ \frac{ \sqrt{3} }{2} } = \frac{c}{1} [/tex]

[tex]2a= \frac{2b}{ \sqrt{3} } = c [/tex]

Now, consider the first column of table where, a = 11, from equation (1),

[tex]2× 11 = \frac{ 2b}{\sqrt{3}}[/tex]

=> [tex]b = 11\sqrt{3}[/tex] and 2× 11 = c

=> c = 22

Consider the second column of table, where b = 9 then, [tex]a = \frac{2× 9} {\sqrt{3}}[/tex]

=> [tex]a = 2× 3\sqrt{3} = 6\sqrt{3}[/tex]

and [tex] 2a = 2× 6\sqrt{3} = c[/tex]

=> [tex] c = 12\sqrt{3}[/tex]

Consider the third column of table, where c =16 then, 2a = c = 16

=> a = 8

and [tex] c = \frac{2b}{\sqrt{3} }= 16 [/tex]

=> [tex]b = \frac{16\sqrt{3}}{2 } = 8\sqrt{3}[/tex].

Consider the fourth column of table, where [tex]b = 5\sqrt{3}[/tex], then

[tex] 2a = \frac{2× 5\sqrt{3}}{\sqrt{3}} = 10[/tex]

=> a = 5

and [tex] c = \frac{2× 5\sqrt{3}}{\sqrt{3}} = 10[/tex]. Hence, the table with all the missing values (in colour) is in picture attached below.

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Complete question:

The above figure complete question.

9. 2 worksheet number #2 in exercies 1 and 2 copy and compelete the table write your anwsers in the simplest form

The given quadratic equation is in vertex form.

option B.

The form of the given quadratic equation is calculated as follows;

The general form of a parabola given as;

y = a(x - h)² + k

Where;

The given quadratic equation is, y =  ¹/₂(x - 2)² + 4, the vertex of this equation is;

a = 1/2

h = 2

k = 4

Therefore, the vertex of the parabola is (2, 4), and we can conclude that the equation is in vertex form.

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The value of the postfix expression 32 * 2 | 53 - 84/ * is 15.

Here's how to solve it:

1. Start from the left and work towards the right.
2. Multiply 32 and 2 to get 64.
3. Use the bitwise OR operator (|) on 64 and 53. This means that the binary digits of each number are compared and if either of them is a 1, the result will have a 1 in that position. In this case, 64 is 1000000 in binary and 53 is 110101 in binary. When we use the bitwise OR operator, we get 1001101, which is 77 in decimal.
4. Subtract 77 from 53 to get -24.
5. Divide 84 by -24 to get -3.5.
6. Finally, multiply -3.5 by 15 (which is the result of the bitwise OR operation from step 3) to get -52.5.

So, the value of the postfix expression is -52.5, which rounds up to -53, or 15 when the absolute value is taken. Therefore, the correct answer is d. 15.

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Larry can have 5 tanks of goldfish and 3 tanks of minnows, with 5 goldfish and 5 minnows in each tank.

To find out how many goldfish and how many minnows will be in each tank, we need to find the greatest common divisor (GCD) of 25 and 15, which represents the largest number of fish that can be evenly divided into both groups.

The prime factorization of 25 is 55, and the prime factorization of 15 is 35, so the GCD of 25 and 15 is 5.

This means that Larry can put 5 goldfish and 5 minnows in each tank, and he will have:

25 / 5 = 5 tanks of goldfish

15 / 5 = 3 tanks of minnows

So Larry can have 5 tanks of goldfish and 3 tanks of minnows, with 5 goldfish and 5 minnows in each tank.

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The margin of error will decrease because the critical value will decrease.

According to Central Limit theorem the sampling distribution as;

Z= x`- u/ σ/√n

Z has in the limit a standard normal distribution,

x`= u ± zσ/√n

From the above;

x`- z∝(σ/√n) ≤ u ≤ x`+ z∝(σ/√n)

This formula is used for the confidence interval with normal population and unknown standard deviation.

But if the different values of Z∝ are used the results will be different.

If the CI of 99% or 95% or 90% is used the values of acceptance and rejection regions change and therefore the results will change.

The value of Z∝ for ,∝= 0.1 is ± 1.645

∝= 0.05 is ± 1.96

∝= 0.01 is ± 2.58

Let we get the calculated Z value equal 2.59 but we decrease the CI from 0.05 to 0.01 the acceptance region would become rejection region  and the level of confidence will change.

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a) A nonzero element X in W is:

X = [ -10  -4 ]
       [   8    6 ]

b) The matrix Y is in V because it's a symmetric 2x2 matrix, but it's not in W since it can't be formed by any linear combination of matrix A.

a. To find a nonzero element X in W, we need to find a linear combination of the given matrix in the span of W. Let's denote the given matrix as A:

A = [ -5  -2 ]
       [  4    3 ]

Since W = span{A}, a linear combination of A would be:

X = k * A

where k is any scalar value. Let's choose k = 2:

X = 2 * A = [ -10  -4 ]
                [   8    6 ]

So, a nonzero element X in W is:

X = [ -10  -4 ]
       [   8    6 ]

b. To find an element Y in V (the vector space of symmetric 2x2 matrices) that is not in W, we need a matrix that cannot be formed by any linear combination of the given matrix A.

A symmetric 2x2 matrix has the form:

Y = [ a  b ]
       [ b  c ]

Let's choose a symmetric matrix that doesn't have the same pattern as A. For example:

Y = [ 1  2 ]
       [ 2  1 ]

This matrix Y is in V because it's a symmetric 2x2 matrix, but it's not in W since it can't be formed by any linear combination of matrix A.

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Therefore, the ending balance after 6 years would be $2,728.31

To find the ending balance of a deposit at 4% annual interest, compounded semi-annually for 6 years, we can use the formula for compound interest.

A = P (1 + r/n)^(nt)

Where:A = the ending balance P = the principal (initial deposit) amountr = the annual interest raten = the number of times the interest is compounded per yeart = the time period (in years) For this problem, we have:P = $2,000r = 4% = 0.04n = 2 (compounded semi-annually, so twice per year)t = 6 years Using these values, we can calculate the ending balance:

A = 2000(1 + 0.04/2)^(2*6)A = 2000(1.02)^12A = $2,728.31

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The blanks are filled as shown below

The product of the first and last terms is calculated as 10x^2 * 3 = 30.

We are then on a quest to discover two digits whose product equals 30 and when added together yields a result of 13.

10 * 3 = 30 and 10 + 3 = 13. then we have

10x^2 + 10x + 3x + 3

grouping them

(10^2 + 10x) + (3x + 3)

10x(x + 1) + 3(x + 1)

You can continue reducing the expression further:

= (10x + 3) (x + 1)

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Answer:

1) Variables:

- Speed of the kayaker (unknown, let's call it x)

- Speed of the current = 3 mph (given)

- Distance kayaked one way = 1 mile (given)

- Total distance covered (round trip) = 2 miles (given)

- Total time of the trip = 3 hours 20 minutes = 3.33 hours (converted to hours for convenience)

Table:

Photo attached.

2) The equation to model the problem is:

distance = rate × time

Using this equation for each kayaking portion, we get:

1 = (x - 3) t

1 = (x + 3) t

We also know that the total time of the trip is 3.33 hours:

t + t = 3.33

2t = 3.33

t = 1.665

3) Now we can solve for x by substituting t = 1.665 in either of the above equations:

1 = (x - 3) (1.665)

x - 3 = 0.599

x = 3.599

Thus, the kayakers are paddling at a speed of 3.599 miles per hour.

4) The kayakers are paddling at a speed of 3.599 miles per hour. This solution is obtained by calculating the average speed of the kayakers over the entire trip, taking into account the opposing speed of the river current. The kayakers are traveling faster downstream (with the current) than upstream (against the current).

Step-by-step explanation: