Find the area of the triangle below.Be sure to include the correct unit in your answer.Bft015 Ft1717 ft

Answers

Answer 1

The area of the triangle is , A= 1/2 Bh.

We can redraw the triangle this way, for us to be sure which side of the triangle which we have to consider as the base and height. Notice that we have a right triangle.

The base and height of the triangle are 8 feet and 15 feet respectively. Therefore, the area is:

A = 1/2 Bh = 1/2 ( 8 feet) (15 feet) = 60 square feet.

The unit of area is always raised to the second power ( or square units) such as ft^2, square meters, sq.in, etc.

Answer : A = 60 sq. ft.

Find The Area Of The Triangle Below.Be Sure To Include The Correct Unit In Your Answer.Bft015 Ft1717

Related Questions

during blowing pratice marley rolled 14 strikes out of 70 attemps what percent of marleys attempts were strikes enter anwser

Answers

we know that

To find out the percentage, divide the number of strikes by the total attemps, and multiply by 100

so

(14/70)(100)=20%

therefore

the answer is

20%

(8 + 9m) -3 =step by step how to solve

Answers

Given the expression :

[tex](8+9m)-3[/tex]

We need to simplify the expression , so, combine the like terms

[tex]\begin{gathered} 8+9m-3 \\ =(8-3)+9m \\ \\ =5+9m \end{gathered}[/tex]

-3 < p/2 < 0Solve and graph solution

Answers

[tex]\begin{gathered} -3<\frac{p}{2}<0\rightarrow \\ -6

Suppose there is a 16.6% probability that a randomly selected person aged 25 years or older is a smoker. In addition, there is a 17.9% probability that a randomy selected person aged 25 years or older is male, given that he or she smokes. What is the probability that a randomly selected person aged 25 years or older is male and smokes? Would it be unusual to randomly select a person aged 25 years or older who is male and smokes?The probability that a randomly selected person aged 25 years or older is male and smokes is (Round to three decimal places as needed.).

Answers

We define the following events:

• A = a person aged 25 years or older is male,

,

• B = a person aged 25 years or older is a smoker,

• A | B = a person aged 25 years or older is male, ,given, that he or she smokes,

,

• A ∩ B = a person aged 25 years or older is male ,and, he or she smokes.

From the statement of the problem, we know that:

1) there is a 16.6% probability that a randomly selected person aged 25 years or older is a smoker, so we have:

[tex]P\mleft(B\mright)=16.6\%=\frac{16.6}{100}=0.166,[/tex]

2) there is a 17.9% probability that a randomly selected person aged 25 years or older is male, given that he or she smokes, so we have:

[tex]P(A|B)=17.9\%=\frac{17.9}{100}=0.179.[/tex]

Now, we know that the conditional probability P(A | B) is given by:

[tex]P(A|B)=\frac{P(A\cap B)}{P(B)}.[/tex]

From the last equation, we have:

[tex]P(A\cap B)=P(A|B)\cdot P(B).[/tex]

Replacing the values of P(A | B) and P(B), we get:

[tex]P(A\cap B)=0.179\cdot0.166=0.029714\cong0.030.[/tex]

Answer

• So the probability that a randomly selected person aged 25 years or older is male ,and, smokes is ,0.030, in decimal form to three decimal places.

,

• So from 100 random persons, approximately 3 will be aged 25 years or older, male and smoker. We conclude that it will be unusual to randomly select a person with those atributes.

A population of drosophila exhibits density-independent growth. There are currently 500 individuals and they have an r of 0.7 offspring/individual/day. How many drosophila will there be 6 days from now?

Answers

In this problem, we have an exponential growth function of the form

[tex]y=a(1+r)^x[/tex]

where

a=500

r=0.7

substitute

[tex]\begin{gathered} y=500(1+0.7)^x \\ y=500(1.7)^x \end{gathered}[/tex]

For x=6 days

substitute

[tex]\begin{gathered} y=500(1.7)^6 \\ y=12,069 \end{gathered}[/tex]

therefore

The answer is 12,069 drosophila

simply 3y- 2y/ - 3/4

Answers

Given:

[tex]3y-\frac{2y-3}{4}[/tex]

thank you for viewing my question I seem to be having some trouble on this problem please help

Answers

[tex]925\text{ km}^2[/tex]

Explanation

Exponential decay function describes the process of reducing an amount by a consistent percentage rate over a period of time. It can be expressed by the formula

[tex]\begin{gathered} f\lparen t)=a\left(1-r\right)^t \\ where\text{ a is the initial value} \\ r\text{ is the rate of decay\lparen in decimals}) \\ t\text{ is the time} \end{gathered}[/tex]

Step 1

a)

Let

[tex]\begin{gathered} a=2600 \\ r=8.25\text{ \%}=\frac{8.25}{100}=0.0825 \\ t=12 \end{gathered}[/tex]

b) now, replace in the formula

[tex]\begin{gathered} f\operatorname{\lparen}t)=a\left(1-r\right)^t \\ f\lparen12)=2600\left(1-0.0825\right)^{12} \\ f\lparen12)=2600\left(0.9175\right)^{12} \\ f\lparen12)=2600\left(0.35585483838\right) \\ f\lparen12)=925.222 \\ rounded \\ f\lparen12)=925 \end{gathered}[/tex]

therefore, the answer is

[tex]925\text{ km}^2[/tex]

Blank: 925

I hope this helps you

A piggy bank contains 4 quarters, 18 dimes, 10 nickels, and 8 pennies. A coin is chosen at random, not replaced, then another is chosen. Find each probability. P(worth at least 10 cents, then penny)

Answers

The probability of choosing a coin that is worth at leas 10 cents is:

[tex]P=\frac{22}{40}=\frac{11}{20}[/tex]

then the probability of obtaining a penny is:

[tex]P=\frac{8}{39}[/tex]

Then the probability to obtain a coin of at least 10 cents and then a penny is:

[tex]P=\frac{11}{20}\cdot\frac{8}{39}=\frac{22}{195}[/tex]

2(-4+3+5) with GEMDAS simplify

Answers

Answer:

The solution to the problem is;

[tex]8[/tex]

Explanation:

Applying GEMDAS;

Grouping comes first (bracket)

We need to first solve the grouped operations.

[tex]\begin{gathered} 2\mleft(-4+3+5\mright) \\ =2(-4+8) \\ =2(4) \\ =8 \end{gathered}[/tex]

GEMDAS means; Grouping, Exponent, Multiplication, Division, Addition and Subtraction Order of operations.

Therefore, the solution to the problem is;

[tex]8[/tex]

Given \sin A=-\frac{6}{\sqrt{61}}sinA=−
61


6

and that angle AA is in Quadrant IV, find the exact value of \cos AcosA in simplest radical form using a rational denominator.

Answers

The value of Cos A is postive in fourth quadrant , Cos A=5/[tex]\sqrt{61}[/tex]

Here we can solve the problem using  the Pythagoras theorem . Hence we draw triangle with  the details given in the question.

It is given  that A is lying  in IV quadrant . So that Sin A is less than zero and thus Cos A will be positive value.

As the value of sinθ= -6/[tex]\sqrt{61}[/tex]=Altitude/ Hypotenuse . Thus here with the help of Pythagoras theorem  we can solve the problem.

That is ,

[tex]Base^{2} =Hypotenuse ^{2} -Altittude ^{2} \\B^{2} =\sqrt{61}^{2} -36\\B= \sqrt{25}=5[/tex]

We know that Base\Hypotenuse =Cos A. Which is positive and in fourth quadrant .

Thus we get answer as Cos A=5/[tex]\sqrt{61}[/tex]

To know more about Pythagoras theorem here:

https://brainly.in/question/2829237

#SPJ1

hi I am working on an assignment and i came up on a question that I did not understand please help me understand and answer this please

Answers

Solution

Step 1:

Write the two equations:

2x + 3y = 12

2x + y = 6

2x = 6 - y

[tex]\begin{gathered} 6\text{ - y + 3y = 12} \\ 2y\text{ = 12 - 6} \\ \\ 2y\text{ = 6} \\ \\ y\text{ = 3} \end{gathered}[/tex]

Answer

The first step in solving by substitution would be to solve the second equation for x, since the coefficient is 2.

First

y = 6 - 2x

y = 3

Which of these expressions CANNOT be simplified by combining like terms? CLEAR CHECK 5ab3 +7 - 3a²b2 + a'b – 10 5ab3 + 3a2b2 + ab - 10 5ab3 + 3a2b2 + a363 - 10ab 5ab3 + 26(3ab2) + a’b – 10

Answers

Which of these expressions CANNOT be simplified by combining like terms?

The answer:

to simplify the terms , the terms must be similar like ab and 3ab the result will be 4ab.

So for our giving options:

1) 5ab3 +7 - 3a²b2 + a'b – 10

2) 5ab3 + 3a2b2 + ab - 10

3) 5ab3 + 3a2b2 + a363 - 10ab

4) 5ab3 + 26(3ab2) + a’b – 10​

so, as shown at the options:

option 1) Can be simplified to 5ab3 - 3a²b2 + a'b – 3

becuse it has only two like terms {7 - 10}

Option 2) CANNOT be simplified

Becuse, it is not contain like terms

Option 3) CANNOT be simplified

Becuse, it is not contain like terms

Option 4) CANNOT be simplified

Becuse, it is not contain like terms

So, the answer is all: All expressions CANNOT be simplified by combining like terms except the first expressions.

====================================================================

can some help? or at least explain how to solve how to solve for the missing length?

Answers

This image shows two similar triangles, which can be expressed as:

[tex]\Delta1=k\Delta2[/tex]

in which K is the constant of similarity, this can be obtain by making the proportion on 2 sets of corresponding sides.

[tex]\frac{12}{28}=\frac{x}{49}[/tex]

solve the relationship for x

[tex]\begin{gathered} x=\frac{12\cdot49}{28} \\ x=21 \end{gathered}[/tex]

Now this 21 is the corresponding measurement of the side in the smaller triangle, however the questions ask for the portion thats between the vertex at the top and the vertex at the top for the smaller triangle, to find this measurement we find the difference between the sides.

[tex]\begin{gathered} 49-21=\text{?} \\ 28=\text{?} \end{gathered}[/tex]

The missing length is 28.

Find the smallest positive integer N that satisfies all of the following conditions: • N is a square.
• N is a cube.
• N is an odd number.
• N is divisible by twelve different prime numbers. How many digits does this number N have?

Answers

Answer:

16

Step-by-step explanation:

first primes: 2,3,5,7,11,13,17,19,23,29,31,37,41

then,cube 2 and square 3 to get 3.6510032e+15 which has 15+1=16 digits

The perimeter of a rectangle is 84. The length is 2 1/2 times the width. Find the dimensions of the rectangle.

Answers

The Solution:

Given:

The perimeter of a rectangle is 84.

We are asked to find the dimensions ( that is, length and width) of the rectangle.

Let the length of the rectangle be L and W for the width.

So,

[tex]L=2\frac{1}{2}of\text{ W}=\frac{5}{2}W[/tex]

By formula, the perimeter of a rectangle is:

[tex]\begin{gathered} P=2(L+W) \\ \\ In\text{ this case,} \\ P=perimeter=84 \\ W=width=? \\ L=length=\frac{5}{2}W \end{gathered}[/tex]

Substitute these values in the formula, we get:

[tex]84=2(\frac{5}{2}W+W)[/tex]

Dividing both sides by 2, we get:

[tex]\begin{gathered} 42=\frac{5}{2}W+W \\ \\ 42=\frac{5W+2W}{2} \\ \\ 42=\frac{7W}{2} \end{gathered}[/tex]

Cross multiplying, we get:

[tex]\begin{gathered} 7W=2\times42 \\ 7W=84 \end{gathered}[/tex]

Dividing both sides by 7, we get:

[tex]W=\frac{84}{7}=12[/tex]

To find the length L, we shall put 12 for W.

[tex]L=\frac{5}{2}W=\frac{5}{2}\times12=5\times6=30[/tex]

Therefore, the dimensions of the rectangle is 30 by 12.

Length = 30 units

Width = 12 units

Graph the compound inequality on the number line. x>-8 and x _<8

Answers

We want to graph the compound inequality below on the number line;

[tex]\begin{gathered} x>-8 \\ \text{and} \\ x\leq8 \end{gathered}[/tex]

We can show the inequality on the number line below;

The shaded dot on 8 is because of the less than or equal to sign,

Given the equilateral triangle ABC; AE, BD, & CF are altitude intersecting at point G. How many right triangles are in the diagram?

Answers

Solution

Given the equilateral triangle ABC;

The following are the numbers of right triangles:

[tex]\begin{gathered} CFB \\ CFA \\ CEA \\ AEB \\ CDB \\ BDA \\ FHD \\ FHE \\ DJE \\ DJF \\ EID \\ EIF \end{gathered}[/tex]

There are 12 right triangles in the diagram.

I sent pic for help. This question has 4 parts

Answers

Explanation

Skewness refers to a distortion or asymmetry that deviates from the symmetrical bell curve, or normal distribution, in a set of data.

There are two main things that make a distribution skewed left: The mean is to the left of the peak. This is the main definition behind “skewness”, which is technically a measure of the distribution of values around the mean. The tail is longer on the left.

A "skewed right" distribution is one in which the tail is on the right side. A "skewed left" distribution is one in which the tail is on the left side. The above histogram is for a distribution that is skewed right.

From the given question

Part B

Since the answer to part A is option C

We can infer from the definition above that the tail is on the right-hand side

Therefore, It is Right-Skewed.

2. Given: -2x =4y +62(2y+3) =3x -5What is the solution (x,y)?I

Answers

this is a 2x2 system of equations.

Let:

-2x = 4y + 6 (1)

and

2(2y+3) = 3x - 5 (2)

Let's rewrite (1) as:

2x + 4y = -6 (1)

and (2) as:

3x - 4y = 11 (2)

Now, from (1)

Let's solve for x:

2x + 4y = -6

Subtract 4y from both sides:

2x + 4y - 4y = -6 - 4y

2x = -6 - 4y

Divide both sides by 2:

2x/2 = (-6 - 4y)/2

x = -3 - 2y (3)

Replacing (3) into (2)

3x - 4y = 11

3(-3 - 2y) - 4y = 11

Using distributive property:

-9 - 6y - 4y = 11

Add like terms:

-10y - 9 = 11

Add 9 to both sides:

-10y - 9 + 9 = 11 + 9

-10y = 20

Divide both sides by -10:

(-10y)/-10 = 20/-10

y = -2

Finally, replace the value of y into (3)

x = -3 - 2y

x = -3 - 2(-2)

x = -3 + 4

x = 1

Therefore the solution is :

x= 1 and y=-2

(x,y) = (1,-2)

Need help please with 1Calculate the relative frequency for the given dataa, b and c

Answers

The relative frequency can be calculated using the formula:

[tex]relative\text{ frequency = }\frac{frequency\text{ of the set}}{Total\text{ frequency}}[/tex]

The completed table can be shown below:

This is a sample calculation of the relative frequency:

[tex]\begin{gathered} rel\text{ freq = }\frac{2}{21}\text{ }\times\text{ 100 \%} \\ =\text{ 9.52\%} \end{gathered}[/tex]

(b) The class 121-160 list the data values that are in the third class of your frequency distribution table

(c) The data value 99 falls in the 81-120 class

A study of a local high school tried to determine the mean amount of money that eachstudent had saved. The study surveyed a random sample of 74 students in the highschool and found a mean savings of 2600 dollars with a standard deviation of 1400dollars. At the 95% confidence level, find the margin of error for the mean, roundingto the nearest whole number. (Do not write +).

Answers

To calculate the margin of error, we use the formula:

[tex]M_{\gamma}=z_{\gamma}\sqrt[]{\frac{\sigma^2}{n}}[/tex]

So, we got n, the number of students, sigma, the standard deviation, and gamma, the confidence level. z for 95% is 1.64, so:

[tex]M_{95\text{ \%}}=1.64\sqrt[]{\frac{1400^2}{74}}=1.64\frac{1400}{\sqrt[]{74}}=266.9\approx267[/tex]

So, the margin of error goes from mean - 267 to mean + 267:

[tex]undefined[/tex]

Solve this system of equations:3x - 2y = -8y=3/2x - 2

Answers

The system of equations that we have are:

3x - 2y = -8 ________(1)

y = 3/2x - 2 ________(2)

Multiply both sides in (2) by 2x:

=> 2xy = 3 - 4x ______(3)

From (1), make y the subject of the formula:

3x + 8 = 2y

=> y = 3x/2 + 4

Put this into (3):

2x(3x/2 + 4) = 3 - 4x

Open the bracket:

[tex]3x^2\text{ + 8x = 3 - 4x}[/tex]

Collect like terms:

[tex]3x^2\text{ + 8x + 4x = 3}[/tex][tex]3x^2\text{ + 12x - 3 = 0}[/tex]

We

a) Write a multiplication expression without exponents that is equivalent to 3^3b) how many factors of 3 did you write

Answers

hello

the question given is to find an expression that's equivalent to the exponent of 3^3

[tex]3^3=27[/tex]

now we just simply look for another way to write 3^3 to give 27

[tex]3^3=3\times3\times3[/tex]

the answer to the question is 3*3*3

b)

the number of factors of three here is one

the slope of the graph is? as a fraction in simplest terms

Answers

EXPLANATION

Given the line in the graph, in order to find the slope, we must apply the following relationship:

[tex]\text{Slope = }\frac{(y_2-y_1)}{(x_2-x_1)}[/tex]

Now, we need at least two ordered pairs to get the slope.

Let's consider (x1,y1)=(0,-6) and (x2,y2)=(6,-2)

Then, replacing into the equation:

[tex]\text{Slope = }\frac{(-2-(-6))}{(6-0)}=\frac{(-2+6)}{(6)}=\frac{4}{6}=\frac{2}{3}[/tex]

So, the slope is 2/3

Question 7 of 25Which histogram represents the following data?16, 19, 24, 11, 20, 32, 14, 29, 17, 22, 13, 31

Answers

Find the frequency of each class:

11-15:

Data: 11,14,13

Frequency: 3

16-20:

Data: 16,19,20,17

Frequency: 4

21-25:

Data: 24,22

Frequency: 2

26-30:

Data: 29

Frequency: 1

31-35:

Data: 32,31

Frequency: 2

Then, the histogram that represents the given data is:

solving for x - (6x -5) = 2x+6 2

Answers

we have

[tex]\frac{6x-5}{2}=2x+6[/tex]

step 1

Multiply by 2 both sides

[tex]\begin{gathered} 6x-5=2(2x+6) \\ 6x-5=4x+12 \end{gathered}[/tex]

step 2

Group terms

[tex]6x-4x=12+5[/tex]

Combine like terms

[tex]2x=17[/tex]

divide by 2 both sides

[tex]\begin{gathered} x=\frac{17}{2} \\ x=8.5 \end{gathered}[/tex]

Verify

substitute the value of x in the original expression

[tex]\begin{gathered} \frac{6(8.5)-5}{2}=2(8.5)+6 \\ 23=23 \end{gathered}[/tex]

is ok

the value of x satisfy the equation

what is -3 2 / 3 + (-2 5/6) need help asap!!

Answers

[tex]-3\frac{2}{3}+(-2\frac{5}{6})[/tex]

Look at the system of equations shown in the graph. What is the solution to the system?

Answers

Solution

A solution to a system of linear equations is the point of intersection of both lines when graphed.

Parallel lines do not ever cross so there are zero solutions.

However, there could be a chance that there is a solution because often, the equation of two lines that look parallel are actually the same line, in which case the system will produce an infinite number of solutions.

The way to be sure is just to pick an x value randomly and put it in both equations and see if the answers are equal. If it is really two parallel lines, they will not be equal otherwise, they will be equal.

Hence from the graph, we will first get the equation for both lines

Line 1

[tex]\begin{gathered} y_2=-4 \\ y_1=2 \\ x_2=0 \\ x_1=-2 \\ \text{Hence the equation of the line is given as} \\ y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)_{} \end{gathered}[/tex][tex]\begin{gathered} y\text{ -(2)=}\frac{-4-(2)_{}}{0-(-2)}(x-(-2)) \\ y-2=\frac{-6}{2}(x+2) \\ y-2\text{ = -3x}-6 \\ y\text{ = -3x -}6+2 \\ y\text{ = -3x-4} \end{gathered}[/tex]

For line 2

[tex]\begin{gathered} y_1=4 \\ y_2=\text{ 1} \\ x_2=0 \\ x_1=-1 \\ \text{The equation of the line is} \\ y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1) \\ \text{After susbstitution} \\ y\text{ -4=}\frac{1-4}{0-(-1)}(x-(-1)) \\ y-4\text{ = }\frac{-3}{1}(x+1) \\ y-4=-3x-3 \\ y\text{ = -3x-3+4} \\ y\text{ = -3x+1} \end{gathered}[/tex]

So picking a random value of x= -1

we will have

[tex]\begin{gathered} \text{Line 1} \\ y\text{ = -3(-1)-4} \\ y=3-4 \\ y\text{ = -1} \\ \text{Line 2} \\ y\text{ = -3(-1)+1} \\ y=\text{ 3+1} \\ y\text{ =4} \end{gathered}[/tex]

Since both values of y using a constant random value of x gives us different answers, the lines, therefore, are not images of each other and the system has no solution.

Final answer------ No solution

Someone please help me on this type of problem, I tried multiple times but still got correct answer. :(

Answers

ANSWER

P(both girls) = 3/20

EXPLANATION

The probability of the event E where the teacher selects one student from each grade and both are girls is:

[tex]P(E)=P(girl\text{ 7th)}\cdot P(girl\text{ 8th)}[/tex]

The probability of selecting a girl from 7th grade is:

[tex]P(\text{girl 7th)}=\frac{\text{ \# of girls in 7th grade}}{\text{ \# of students in 7th grade}}=\frac{5}{10}=\frac{1}{2}[/tex]

The probability of selecting a girl from 8th grade is:

[tex]P(\text{girl 8th)}=\frac{\text{ \# of girls in8th grade}}{\text{ \# of students in 8th grade}}=\frac{3}{10}[/tex]

The probability of event E is then:

[tex]P(E)=\frac{1}{2}\cdot\frac{3}{10}=\frac{3}{20}[/tex]

In the diagram, RSTU ~ ABCD. Find the ratio of their perimeter

Answers

The ratio of their perimeters is the same ratio between corresponding sides.

Looking at the image, the side ST corresponds to the side BC.

Calculating their ratio, we have:

[tex]\begin{gathered} \text{ratio}=\frac{ST}{BC} \\ \text{ratio}=\frac{12}{8} \\ \text{ratio}=\frac{3}{2} \end{gathered}[/tex]

So the ratio of their perimeters is 3 : 2

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