Find the critical numbers for f(x)=cos(x)+sin^2(x) on the interval [0,2pi]

Answer:

its b.

Step-by-step explanation: 5n − 19 + n + 7 = 144 − 6n

6n − 12 = 144 − 6n

12n = 156

n = 13

m∠z = (144−6n)°

m∠z = (144−6×13)°

m∠z = 66°

Answer:

5 added to a number, x.

Step-by-step explanation:

I phrased it like other ones I saw before so... :) (Also if you ask someone to write it, I'm sure they'd get x+5)

Answer:5 added to a number, x

Step-by-step explanation:

Answer:

Inverse proportion

Step-by-step explanation:

Inverse proportion: in this type of relation, two quantities proportion such that one decreases and other increases or vice-versa.

So, in the given question when the number of workers increases, time is taken for certain work decreases.

So, Inverse proportion is the correct answer.

Answer:

I'm pretty sure it's the last one that is incorrect

Step-by-step explanation:

Answer:

The first one - “line segment TA is congruent to line segment DO” is incorrect

Step-by-step explanation:

Since the triangles are similar, the angle measurements would be the same (congruent), but the line segments are are only similar, not congruent, as they have different lengths. So the first statement is incorrect.  

Answer:

a) = Rs 16000

b) = 5%

c) = Rs 30,000,000

10% = 24,000,00/10 = Rs 240,000

20% = 240,000 x 2 = Rs 480,000

480,000/30 = Rs 16000

b) The bonus percentage needs to be increased by 5%

explanation:

Since every worker needs Rs 20000 we need to times it by 30

20000 x 30 = Rs 600,000

600,000 - 480,000 = Rs 120,000

Now we need to find the percentage of Rs 120,000

10% = Rs 240,000

5% = 240,000 divide by 2 = Rs 120,000

This is the best I can do for now please let me know if you understood the answer!

Answer:

1.Rs.16000

2.Bonus rate:25%

3.profit:Rs.3000000

Step-by-step explanation:

Case 1

Profit=Rs.2400000

Bonus Rate:20%

No.of employees =30

Now,

Bonus = (Bonus Rate of Profit) / no. Of employees

= 20% of Rs.2400000 / 30

= Rs. 16000

Case 2

Bonus=Rs.20000

Profit=Rs.2400000

Bonus rate=?

Now,

Bonus=bonus rate of profit / no. Of employees

Or,Rs. 20000 = Bonus rate × Rs. 2400000/30

Or, Rs. 20000=Bonus rate × Rs. 80000

Or,Rs.20000/Rs.80000 = Bonus rate

Bonus rate = 1/4=25%

Case 3

Bonus=Rs.20000

Bonus Rate = 20%

Now,

Bonus = bonus Rate of profit / no.of employees

Or, Rs. 20000 = 20% × Profit / 30

Or, Rs. 20000 × 30 / 0.2 = profit

Profit= Rs. 3000000

I hope it helped you

Answer:

[tex]$\left(-\infty, \frac{17}{3} \right]$[/tex]

Step-by-step explanation:

[tex]2x - 5 \le -x +12[/tex]

[tex]2x - 5 +5\le -x +12+5[/tex]

[tex]2x\le -x+17[/tex]

[tex]3x \le17[/tex]

[tex]$x \le \frac{17}{3} $[/tex]

We have

[tex]$\{x \in \mathbb{R}:x \le \frac{17}{3} \}$[/tex]

Interval notation:

[tex]$\left(-\infty, \frac{17}{3} \right]$[/tex]

Answer:

6p+19

Step-by-step explanation:

combine like terms:

8p+10+-2p+-1+10

(8p+-2p)+(10+-1+10)

6p+19

HOPE THIS HELPS!!!!!!:)

Answer:

78.5

Step-by-step explanation:

It is 78.5 because you first get the area of the circle, which is 314. Then divide 314 by 4 to get 78.5

The area of 1/4 of a circle with a radius of 10 is 78.5 units²

Given,

1/4 of a circle.

Radius = 10

π = 3.14

We need to find the area of 1/4 of a circle.

It is given as:

Area = πr²

Find the area of 1/4 of a circle.

We have,

Area of a circle = πr²

Radius = 10

1/4 area of a circle:

= 1/4 x πr²

= 1/4 x 3.14 x 10²

= 1/4 x 3.14 x 100

= 78.5 units²

Thus the area of 1/4 of a circle is 78.5 units²

Learn more about finding the circumference and area of a circle here:

https://brainly.com/question/14966973

#SPJ6

[tex]\frac{1}{15}[/tex] or 6.67%

In practice, the relative frequency of an event happening is the same as the probability that that event happened. In other words, the terms "relative frequency" and "probability" can be used interchangeably.

Now, the probability P(A) of an event A happening is given by;

P(A) = [tex]\frac{number-of-outcomes-in-the-event-A}{number-of-outcomes-in-the-sample-space}[/tex]

From the question;

The event A is the situation of local residents having a post office box. Therefore the;

number-of-outcomes-in-the-event-A = 8   [since only 8 of the local residents have a post office box]

number-of-outcomes-in-the-sample-space = 120 [since there are altogether 120 local residents]

Therefore,

P(A) = [tex]\frac{8}{120}[/tex]

P(A) = [tex]\frac{1}{15}[/tex]

The relative frequency that a local resident does not have a post office box for receiving a mail is therefore, [tex]\frac{1}{15}[/tex]

PS: Sometimes it is much more convenient to express relative frequencies as percentage. Therefore, the result above expressed in percentage gives:

[tex]\frac{1}{15} * 100%[/tex]% = 6.67%