find the derivative of the function. g(x) = 7x u2 − 3 u2 3 du 4x

The value of composition of function is 26.

The given function is,

f(x) = 3x -9

g(x) = x²

We know that,

A function composition is an operation in which two functions, f and g, generate a new function, h, in such a way that h(x) = g(f(x)). This signifies that function g is being applied to the function x. So, in essence, a function is applied to the output of another function.

Therefore,

gof(x)  = g(f(x))

          = (3x -9)²

          = 9x² -56x + 81

Now put x = 5

Then,

gof(5) = 9x² -56x + 81

         = 26

Hence,

gof(5)  = 26

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The circumference of the swimming pool is 66 feet

The circumference is the perimeter of a circle or ellipse. That is, the circumference would be the arc length of the circle, as if it were opened up and straightened out to a line segment.

The circumference of the circle is expressed as;

C = 2πr

Where c is the circumference, r is the radius, we are yo take π as 22/7

radius = diameter /2. Therefore we can say

C = πd

C = 22/7 × 21

C = 22 × 3

C = 66 feet

therefore the circumference of the pool is 66 feet

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The solution for the trapezoid with median is:

1. If MY || LE, then MY || IK

2. MY = 52 cm

3. MY = 109 cm

4. IK = 10 cm

5. LE = 45 cm

The trapezoid mid-segment or median theorem states that "a line connecting the midpoints of the non-parallel sides (legs) is parallel to the bases". It measures half the sum of lengths of the bases. That is:

m = 1/2 (b₁ + b₂)

where b₁ and b₂ are the bases of the trapezoid.

No. 1

Since the midpoints of the non-parallel sides (legs) is parallel to the bases. Thus:

If MY || LE, then MY || IK

Note: || means parallel

No. 2

In this case, the midpoint is MY. IK and LE are the bases. Thus:

MY = 1/2 * (IK + LE)

MY = 1/2 * (56 + 48)

MY = 52 cm

No. 3

MY = 1/2 * (142 + 76)

MY = 109 cm

No. 4

45.7 = 1/2 * (IK + 85)

45.7 * 2 = IK + 85

95 = IK + 85

IK = 95 - 85

IK = 10 cm

No. 5

37.5 = 1/2 * (120 + LE)

37.5 * 2 = 120 + LE

75 = 120 + LE

LE = 120 - 75

LE = 45 cm

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a) The cost of one McGriddle is $2.75.

b) The equation that models the scenario is y = $2.75x + $11

c) We can buy a total of 4 McGriddles with the $30 gift card.

We have,

a.

To find the cost of one McGriddle, we can start by subtracting the remaining balance from the initial balance:

$30 - $19 = $11

Since we bought a McGriddle for 4 days, the cost of one McGriddle is:

$11 ÷ 4 = $2.75

b.

We can model this scenario with the linear equation:

y = mx + b

where y represents the remaining balance on the gift card, x represents the number of McGriddles bought, m represents the cost of one McGriddle, and b represents the initial balance.

We know that b = $30, m = $2.75, and y = $19 when x = 4.

Plugging in these values, we get:

$19 = $2.75(4) + $30

Simplifying, we get:

$19 = $11 + $11

So this equation models the scenario:

y = $2.75x + $11

c.

To find the total number of McGriddles we can afford, we can solve the equation for x when y = 0 (meaning we've used up all the money on the gift card).

$0 = $2.75x + $11

Solving for x, we get:

x = $11 ÷ $2.75

x = 4

Thus,

a) The cost of one McGriddle is $2.75.

b) The equation that models the scenario is y = $2.75x + $11

c) We can buy a total of 4 McGriddles with the $30 gift card.

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(a) The combinations are,

Number of 6 player games = 8, if number of 2 player games = 1.

Number of 2 player games = 22, if number of 6 player games = 1.

Number of 6 player games = 7, if number of 2 player games = 4.

Number of 2 player games = 13, if number of 6 player games = 4.

(b) The number of 6 player games is 6 and the number of 2 player games is 7.

Given that total number of athletes = 50

Players needed for 6 player game = 6 and players needed for 2 player games = 2

(a) When number of 2 player games = 1,

Number of athletes left = 50 - (1 × 2) = 48

Number of 6 player games = 48/6 = 8

When number of 6 player games = 1,

Number of athletes left = 50 - (1 × 6) = 44

Number of 2 player games = 44/2 = 22

When number of 2 player games = 4,

Number of athletes left = 50 - (4 × 2) = 42

Number of 6 player games = 42/6 = 7

When number of 6 player games = 4,

Number of athletes left = 50 - (4 × 6) = 26

Number of 2 player games = 26/2 = 13

(b) Let x represents the number of 2 player games and y represents the number of 6 player games.

We get the linear equations,

x + y = 13

AND

2x + 6y = 50

From first equation,

y = 13 - x

Substituting this to second equation,

2x + 6(13 - x) = 50

2x + 78 - 6x = 50

-4x = -28

x = 7

So, y = 13 - 7 = 6

Hence the number of 2 player games played is 7 and the number of 6 player games played is 6.

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When a country replaces a sales tax with an income tax that includes a tax on interest income, it increases the tax burden on individuals' interest earnings. Option B is correct.

This change in the tax structure affects the incentives for saving and borrowing, resulting in changes in interest rates and the equilibrium quantity of loanable funds.

With an increased tax on interest income, individuals will have a reduced incentive to save, as a higher portion of their interest earnings is subject to taxation. This leads to a decrease in the supply of loanable funds available for borrowing. As a result, the equilibrium interest rates rise due to the decrease in the supply of loanable funds.

Additionally, the higher interest rates discourage borrowing, leading to a decrease in the demand for loanable funds. Consequently, the equilibrium quantity of loanable funds falls.

Therefore, option B is correct.

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There are 216 different possible combinations for the lock.

What is linear combinations?

In mathematics, a linear combination is a sum of scalar multiples of one or more variables. More formally, given a set of variables x1, x2, ..., xn and a set of constants a1, a2, ..., an, their linear combination is given by the expression:

a1x1 + a2x2 + ... + anxn

Since there are three dials on the combination lock and each dial can be set to one of six numbers, the total number of possible combinations is the product of the number of options for each dial.

Therefore, the total number of combinations is: 6 x 6 x 6 = 216

So there are 216 different possible combinations for the lock.

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The matrix a = [5k-9, -1; -1, 5k-9] has one real eigenvalue of algebraic multiplicity 2 when k = 2 or k = 7/5.

The eigenvalues of a 2x2 matrix can be found using the characteristic equation, which is given by: det(a - λI) = 0

where λ is the eigenvalue and I is the identity matrix of the same size as a. For the matrix a, this equation becomes:

(5k - 9 - λ)^2 - 1 = 0

Expanding this equation gives:

25k^2 - 90k + 80 - 10λk + λ^2 - 1 = 0

Simplifying this equation gives:

λ^2 - 10kλ + 25k^2 - 90k + 79 = 0

For a real eigenvalue of algebraic multiplicity 2, the discriminant of this quadratic equation must be zero. Therefore, we have:

(-10k)^2 - 4(25k^2 - 90k + 79) = 0

Simplifying this equation gives:

k^2 - 9k + 20 = 0

Factoring this equation gives:

(k - 2)(k - 7/5) = 0

Therefore, the matrix a has one real eigenvalue of algebraic multiplicity 2 when k = 2 or k = 7/5.

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The conclusion that is appropriate at a 5% level of significance is this:C. There are statistically significant differences in the mean time to recurrence of depression symptoms for patients in the three treatment groups. this suggests that there is a treatment effect.

The correct conclusion is that the result obtained from the analysis is statistically significant, so the null hypothesis can be rejected. This also means that there are 1 in 20 chances of obtaining an error.

So, for a study checking the relationship between the mean time to recurrence of depression symptoms, the 5% level of significance would demonstrate a relationship.

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1. The derivative of y = (4x⁴ - 5)(-x⁴ + x² + 2) is:

(4x⁴ - 5)(-4x³ + 2x) + (-x⁴ + x² + 2)16x³

2. The derivative of y = (x⁴ + 4x² - 4) / (2x³ - 4) is:

[(2x³ - 4)(4x³ + 8x) - (x⁴ + 4x² - 4)6x²] / (2x³ - 4)²

1. The derivative of y = (4x⁴ - 5)(-x⁴ + x² + 2) can be obtain as follow

Let

Thus,

du/dx = 16x³

dv/dx = -4x³ + 2x

Finally, the derivative of y is obtained as follow:

d(uv)/dx = udv/dx + vdu/dx

dy/dx = (4x⁴ - 5)(-4x³ + 2x) + (-x⁴ + x² + 2)16x³

Thus, the derivative of y is (4x⁴ - 5)(-4x³ + 2x) + (-x⁴ + x² + 2)16x³

2. The derivative of y = (x⁴ + 4x² - 4) / (2x³ - 4) can be obtain as shown below:

Let

Thus,

du/dx = 4x³ + 8x

dv/dx = 6x²

Finally, the derivative of y is obtained as follow:

d(uv)/dx = (vdu/dx - udv/dx) / v²

dy/dx = [(2x³ - 4)(4x³ + 8x) - (x⁴ + 4x² - 4)6x²] / (2x³ - 4)²

Thus, the derivative of y is  [(2x³ - 4)(4x³ + 8x) - (x⁴ + 4x² - 4)6x²] / (2x³ - 4)²

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To find the total area of the six sides of a cube, we can calculate the sum of the areas of each side. Since the cube has equal sides, we only need to find the area of one side and multiply it by 6.

The area of one side of a cube is given by the formula A = s^2, where s represents the length of each side. In this case, the length of each side is x-4. Therefore, the area of one side is (x-4)^2.

To find the total area of the six sides, we multiply the area of one side by 6:

Total area = 6 * (x-4)^2

So, the polynomial that represents the total area of the six sides of the cube with edges of length x-4 is 6 * (x-4)^2.

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The new wavelength of the light predominantly reflected is 955.08 nm.

and the thickness of film is 230.37nm.

The minimum thickness of the soap film can be found using the equation for constructive interference of reflected light: 2nt = mλ, where n is the refractive index of the soap, t is the thickness of the film, m is an integer .

(in this case m = 1 for the first order maximum), and λ is the wavelength of the reflected light. Solving for t, we get t = (mλ)/(2n) = (1)(622 nm)/(2(1.35)) = 230.37 nm.

When the soap film is on the sheet of glass, the wavelength of the reflected light changes due to the change in refractive index. The equation for the new wavelength can be found using the formula for the index of refraction: n = c/v, where c is the speed of light in a vacuum and v is the speed of light in the medium.

Rearranging this equation, we get v = c/n. Thus, the new wavelength λ' can be found by multiplying the original wavelength by the ratio of the speeds of light in air and in the soap film on the glass: λ' = λ(c/n_air)/(c/n_soap) = λ(n_soap/n_air) = 622 nm(1.54/1) = 955.08 nm.

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Answer:179.5

Step-by-step explanation:

The best graphical representation to display the data would be a histogram.

Since the data is categorical (the type of item purchased), a histogram would be the most appropriate way to display the data.

A histogram would show the number of purchases for each category of item purchased, while a pie chart would show the proportion of purchases for each category.

Both of these graphical representations would be easy to read and would allow for easy comparison between the different categories of items purchased.

A box plot, line plot, or stem-and-leaf plot would not be appropriate for this type of data.

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The statistical method that you are referring to is called multiple regression analysis. This method is used to assess the relationship between two variables while controlling for the effects of other variables, also known as covariates.

Multiple regression analysis is a common tool in social science research and is used to explore and explain the relationships between variables.

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The magnitude of the vector a⃗ is 5.41 m. This means that the length of the vector is 5.41 meters,

The question asks for the magnitude of the vector a⃗ = (4.8 m) x^ + (-2.5 m) y^, which represents a vector in two-dimensional space. The magnitude of a vector represents the length of the vector and is always a non-negative scalar quantity.

To calculate the magnitude of a two-dimensional vector, we can use the Pythagorean theorem. This theorem states that the magnitude of a vector is equal to the square root of the sum of the squares of its components. In this case, the components of the vector a⃗ are (4.8 m) in the x direction and (-2.5 m) in the y direction.

By applying the Pythagorean theorem, we can compute the magnitude of a⃗ as follows:

|a⃗| = sqrt((4.8 m)^2 + (-2.5 m)^2)

|a⃗| = sqrt(23.04 m^2 + 6.25 m^2)

|a⃗| = sqrt(29.29 m^2)

|a⃗| = 5.41 m

Therefore, the magnitude of the vector a⃗ is 5.41 m. This means that the length of the vector is 5.41 meters, and its direction is determined by the angle between the vector and the positive x-axis.

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To solve the equation cosθ - 1 = -1 in the interval [0, 2π), we first add 1 to both sides of the equation to obtain cosθ = 0. Then, we recall that the cosine function equals 0 at π/2 and 3π/2 in the given interval. Thus, the solutions are θ = π/2 and θ = 3π/2.

We can add 1 to both sides of the equation to obtain cosθ = 0. This is because -1 + 1 = 0. Then, we recall the values of the cosine function in the given interval. The cosine function equals 0 at π/2 and 3π/2, so these are the solutions to the equation.

The solutions to the equation cosθ - 1 = -1 in the interval [0, 2π) are θ = π/2 and θ = 3π/2, expressed in radians in terms of π. There are two solutions, separated by a comma.

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The expected number of gumballs Erin needs to pull out of the bag until she gets her favorite color is 8, which is the total number of gumball colors. This is because each gumball has an equal probability of being chosen, regardless of the previous choices. Therefore, Erin has an equal chance of choosing her favorite color on each turn. The probability of not getting her favorite color on the first turn is 7/8. After putting the gumball back and shaking the bag, the probability of not getting her favorite color on the second turn is also 7/8. This pattern continues until Erin finally chooses her favorite color.

The probability of not getting Erin's favorite color on any given turn is 7/8. This is because there are 8 colors in the bag, and only one of them is her favorite. Therefore, the probability of getting her favorite color on any given turn is 1/8.

The expected number of gumballs that Erin needs to pull out of the bag until she gets her favorite color can be calculated using the formula:

E(X) = 1/p

Where X is the number of gumballs Erin needs to pull out, and p is the probability of getting her favorite color on any given turn.

In this case, p = 1/8.

Therefore,

E(X) = 1/(1/8) = 8

Erin is expected to pull out 8 gumballs from the bag before she gets her favorite color. This is because each gumball has an equal probability of being chosen, regardless of the previous choices. Therefore, the expected number of gumballs that Erin needs to pull out until she gets her favorite color is equal to the total number of gumball colors in the bag.

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The expected number of gumballs that Erin will need to pull out of the bag until she gets her favorite color is 8.

Since there are eight different colors of gumballs in the bag, the probability of pulling out Erin's favorite color on any given try is 1/8. Since Erin puts the gumball back in the bag after each try and shakes the bag to remix the gumballs, each try is independent of the others.

To calculate the expected number of tries until Erin gets her favorite color, we can use the formula E(X) = 1/p, where p is the probability of the event happening and X is the number of trials until the event happens. In this case, p = 1/8 since there is a 1/8 chance of pulling out Erin's favorite color on any given try.

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The three expressions ∂r/∂y − ∂q/∂z, ∂p/∂z − ∂r/∂x, and ∂q/∂x − ∂p/∂y represent the components of the curl of the vector field F. So, the curl of the given vector field F can be expressed as Curl(F) = (∂r/∂y − ∂q/∂z)i + (∂p/∂z − ∂r/∂x)j + (∂q/∂x − ∂p/∂y)k.

Using the given values of p, q, and r, we can find the partial derivatives of each component with respect to x, y, and z. Then, we can substitute these values into the expression for the curl to obtain the final answer. So, evaluating the partial derivatives and substituting into the expression for the curl gives Curl(F) = (-48xyz)i + (24x^2z - 24xy^2)j + (16xy - 16yz^2)k.

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The area of the bigger sector and the smaller sector of the circle are 100.53 km² and 50.265 km² respectively.

The area of a sector of a circle is given by the formula A = (θ/360)πr², where θ is the central angle of the sector and r is the radius of the circle. For the bigger sector with a central angle of 225 degrees, the area is,

A₁ = (225/360)π(8 km)² ≈ 100.53 km²

To find the area of the smaller sector, we need to subtract the area of the bigger sector from the total area of the circle, which is,

A_circle = πr² = π(8 km)² ≈ 201.06 km²

The central angle of the smaller sector is,

θ₂ = 360 - 225 = 135 degrees

So the area of the smaller sector is,

A₂ = (135/360)π(8 km)² ≈ 50.265 km²

Therefore, the area of the bigger sector is approximately 100.53 square kilometers and the area of the smaller sector is approximately 50.265 square kilometers.

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To find the price that will give the greatest profit, we need to maximize the profit function, which is given by the difference between the revenue and the cost. Revenue is equal to the price multiplied by the number of copies sold, while cost is equal to the cost per copy multiplied by the number of copies sold. So, profit can be expressed as p(280,000 - 14,000p) - 4(280,000 - 14,000p).

To find the price that will maximize profit, we need to take the derivative of the profit function with respect to p, set it equal to zero, and solve for p. After some algebraic manipulation, we get -28p^2 + 280p - 1120 = 0. Solving for p using the quadratic formula, we get p = 5 or p = 10.

To determine which value of p will give the greatest profit, we need to evaluate the profit function at both values of p. When p = 5, profit is equal to $420,000, and when p = 10, profit is equal to $408,000. Therefore, the price that will give the greatest profit is $5.

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The expression sum of i from 1 to n of sum of j from 1 to n of (i-j) squared can be rewritten as the sum of squares of all the differences (i-j), where i and j range from 1 to n.

The given expression, sum of i from 1 to n of sum of j from 1 to n of (i-j) squared, is equal to n squared times (n - 1) squared divided by 6.

To prove this, we can use the formula for the sum of squares of the first n natural numbers, which is n(n+1)(2n+1)/6. We can rewrite the given expression as the sum of the squares of all the differences (i-j), where i and j range from 1 to n.

Expanding the squares, we get

(i-j)^2 = i^2 - 2ij + j^2. Summing over all i and j,

we obtain the expression 2sum(i^2) - 2sum(ij) + 2sum(j^2).

Using the formulas for the sum of squares and the sum of products of the first n natural numbers, we can simplify this expression to

n(n+1)(2n+1)/3 - n(n+1)^2/2 + n(n+1)(2n+1)/3.

Simplifying further, we get n^2(n+1)^2/4, which is equal to n squared times (n - 1) squared divided by 6, as required.

In summary, the expression sum of i from 1 to n of sum of j from 1 to n of (i-j) squared can be rewritten as the sum of squares of all the differences (i-j), where i and j range from 1 to n. Using the formulas for the sum of squares and the sum of products of the first n natural numbers, we can simplify this expression to n squared times (n - 1) squared divided by 6.

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The products that are defined are given as follows:

LP, LQ.

The products that are not defined are given as follows:

NM, QM.

The multiplication of two matrices is possible when the number of columns of the first matrix is equals to the number of rows of the second matrix.

The dimensions of each matrix are given as follows:

Hence the defined products are:

LP, LQ.

The non-defined products are:

NM, QM.

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Thus, the general solution is y(x) = -x + 2x^3 + c₁x + c₂x^3.

To find the general solution of the differential equation x^2y'' + 3xy' + 3xy = 4x^7, we can use the method of variation of parameters.

Given that {x, x^3} is a fundamental set of solutions of the homogeneous equation x^2y'' - 3xy' + 3y = 0, we can use these solutions to find the particular solution.

Let's assume the particular solution has the form y_p = u(x)x + v(x)x^3, where u(x) and v(x) are unknown functions.

Differentiating y_p:

y_p' = u'x + u + v'x^3 + 3v(x)x^2

Differentiating again:

y_p'' = u''x + 2u' + v''x^3 + 6v'x^2 + 6v(x)x

Substituting these derivatives into the original differential equation, we have:

x^2(u''x + 2u' + v''x^3 + 6v'x^2 + 6v(x)x) + 3x(u'x + u + v'x^3 + 3v(x)x^2) + 3x(u(x)x + v(x)x^3) = 4x^7

Simplifying and grouping like terms:

x^3(u'' + 3v') + x^2(2u' + 3v'' + 3v) + x(u + 3v' + 3v) + (2u + v) = 4x^5

Setting the coefficients of each power of x to zero, we get the following system of equations:

x^3: u'' + 3v' = 0

x^2: 2u' + 3v'' + 3v = 0

x^1: u + 3v' + 3v = 0

x^0: 2u + v = 4

Solving this system of equations, we find:

u = -1

v = 2

Therefore, the particular solution is y_p = -x + 2x^3.

The general solution of the differential equation x^2y'' + 3xy' + 3xy = 4x^7 is given by the sum of the particular solution and the homogeneous solutions:

y(x) = y_p + c₁x + c₂x^3

where c₁ and c₂ are arbitrary constants.

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Option(2) 4 / sqrt(41)  is the value of cos(θ) when point P(4,5) lies on the terminal side of angle C.

To find the value of cos(θ), we need to determine the coordinates of the point P(4,5) on the unit circle.

Let's assume that angle C is in standard position, which means its vertex is at the origin (0,0) and its initial side lies along the positive x-axis. Since point P(4,5) lies on the terminal side of angle C, we can find the length of the hypotenuse and use it to calculate the value of cos(θ).

Using the Pythagorean theorem, we can determine the length of the hypotenuse (r) as follows:

r = sqrt(x^2 + y^2)

= sqrt(4^2 + 5^2)

= sqrt(16 + 25)

= sqrt(41)

Now that we have the length of the hypotenuse, we can calculate the value of cos(θ) using the formula:

cos(θ) = x / r

In this case, x = 4 and r = sqrt(41), so we have:

cos(θ) = 4 / sqrt(41)

This is the value of cos(θ) when point P(4,5) lies on the terminal side of angle C.

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The dimensions of the rectangular storage room are 13 feet by 5 feet.

Let's start by using the formula for the area of a rectangle, which is:
Area = Length x Width
We know that the area of the room is 65 square feet, so we can write:
65 = Length x Width
Now, we also know that the length of the room is 8 feet longer than its width. We can represent this using the equation:
Length = Width + 8
We can substitute this expression for length into our equation for the area, giving:
65 = (Width + 8) x Width
Expanding the brackets, we get:
65 = Width^2 + 8Width
Rearranging this equation into standard quadratic form (with the squared term first), we get:
Width^2 + 8Width - 65 = 0

To solve for the width, we can use the quadratic formula:
Width = (-b ± sqrt(b^2 - 4ac)) / 2a
In this case, a = 1, b = 8, and c = -65. Plugging these values in, we get:
Width = (-8 ± sqrt(8^2 - 4(1)(-65))) / 2(1)

Simplifying under the square root, we get:
Width = (-8 ± sqrt(324)) / 2
Width = (-8 ± 18) / 2
This gives us two possible solutions for the width:
Width = 5 or Width = -13

Since the width of a room cannot be negative, we can discard the second solution and conclude that the width of the room is 5 feet.
Now, to find the length, we can use the expression we derived earlier:
Length = Width + 8
Substituting in the value we just found for the width, we get:
Length = 5 + 8
Length = 13

Therefore, the dimensions of the rectangular storage room are 13 feet by 5 feet.

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Answer:

Step-by-step explanation:

total cashiers 13

total stock clerks 27

total deli personnel 5

total total 45

total married 23

total not married 22

a. 27+11=38

38/45=.84

answer is 84%

b.22/45=49%

c. 13+17=30

30/45=67%

d. 8/23= 35%

e. 15/27= 56%

f. 8/45= 18%

Answer:

43,5311

Step-by-step explanation:

Cos A= 6²+10²-7²/2×6×10

this is the cosin theorem in triangle

The element (1 2 3 4 5)(1 2 3 4 5 6 7 8 9 10) in A12 has order 30.:

To find an element in A12 of order 30, we can start by considering the cycle structure of permutations of order 30. Since 30 is a product of distinct primes, the only possible cycle types for permutations of order 30 in S12 are (2,3,5), (2,2,3,5), and (2,2,2,3,3). However, not all of these cycle types are possible in A12, since some permutations of these cycle types will have an odd number of transpositions.

One possible element in A12 of order 30 is (1 2 3 4 5)(1 2 3 4 5 6 7 8 9 10), which is a product of a 5-cycle and a 10-cycle. To see that this element is even, note that it can be expressed as (1 5)(1 4 3 2)(1 10 9 8 7 6 5 4 3 2), which is a product of three transpositions. To see that the order of this element is indeed 30, note that applying this element 30 times results in the identity permutation, and no power less than 30 yields the identity permutation. Therefore, (1 2 3 4 5)(1 2 3 4 5 6 7 8 9 10) is an element in A12 of order 30.

To learn more about identity permutation click here: brainly.com/question/30557698

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