Find the differential of each function. (a) y = x2 sin 8x dy = X (b) y = 4+ dy =

Answers

Answer 1

For part (a), we use the product rule and chain rule of differentiation:

y = x^2 sin(8x)

dy/dx = (2x sin(8x)) + (x^2 cos(8x) * 8)

dy/dx = 2x sin(8x) + 8x^2 cos(8x)

So, the differential of y = x^2 sin(8x) is dy = (2x sin(8x) + 8x^2 cos(8x)) dx.

For part (b), the differential is simply the derivative of y with respect to x, since y is not a function of x in this case:

y = 4+

dy/dx = 0

So, the differential of y = 4+ is dy = 0 dx.

To find the differential of each function, we will use the derivative rules. Let's solve each part step-by-step:

(a) y = x^2 sin(8x)

To find the differential (dy) of this function, we will need to find the derivative of y with respect to x (dy/dx). In this case, we will use the product rule, which states that if y = uv, where u and v are functions of x, then:

dy/dx = u(dv/dx) + v(du/dx)

Let u = x^2 and v = sin(8x).

Now, we need to find du/dx and dv/dx:

du/dx = 2x (by using the power rule)
dv/dx = 8*cos(8x) (by using the chain rule)

Now apply the product rule:

dy/dx = x^2 * 8*cos(8x) + sin(8x) * 2x
dy/dx = 8x^2*cos(8x) + 2x*sin(8x)

So, the differential of the function y = x^2*sin(8x) is dy/dx = 8x^2*cos(8x) + 2x*sin(8x).

(b) y = 4

To find the differential (dy) of this function, we will find the derivative of y with respect to x (dy/dx).

Since y is a constant function (it doesn't depend on x), its derivative is simply:

dy/dx = 0

So, the differential of the function y = 4 is dy/dx = 0.

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Related Questions

(a) Make a scatter plot of the data.
(b) Draw a line of best fit.
(c) Write an equation of the line of best fit
(d) Does the data show a positive, a negative, or no association?
(e) Interpret the relationship.
Answer:

Answers

Answer:

a) For help, plot the points on the graphing calculator.

b) Generate a linear regression equation:

y = -2.2857x + 16.8571

y = (-16/7)x + (118/7)

c) See part b.

d) The data shows a negative association.

e) We expect the number of losses to decrease by about 2.2857 per week. The y-intercept, 16.8571, is meaningless since the gamer received the video game at

x = 0.

At a university, 10% of students smoke. Calculate the expected number of smokers in a random sample of 150 students from this university.

Answers

The expected number of smokers in a random sample of 150 students from this university is 15.

To calculate the expected number of smokers in a random sample of 150 students at a university where 10% of students smoke, you simply multiply the total number of students in the sample by the percentage of students who smoke:
Expected number of smokers = Total number of students x Percentage of smokers
= 150 students x 10%
= 150 x 0.10
= 15
So, if we know that 10% of students smoke at this university, and we have a random sample of 150 students, we can calculate the expected number of smokers as follows:

Expected number of smokers = 150 x 0.10 = 15

Therefore, we can expect that there will be approximately 15 smokers in a random sample of 150 students from this university.


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set up the partial fraction decomposition for each rational expression. do not try to find values for a, b, c, etc. the independent variable is x foreach expression. all other letters represent constants.

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To set up a partial fraction decomposition for a rational expression, we want to express it as a sum of simpler fractions, with each denominator being a linear factor (i.e. a factor of the form ax + b, where a and b are constants). The general form of a partial fraction decomposition is:

f(x) = A/(ax + b) + B/(cx + d) + ...

where A, B, etc. are constants that we'll need to solve for.

Note that we're not trying to find specific values for A, B, etc. in this question - we're just setting up the decomposition.

So, for each rational expression, we'll need to factor the denominator into linear factors (if it's not already in that form). Then we'll set up the partial fraction decomposition using the formula above. Here are a few examples:

Example 1: (x^2 + 5x + 6)/(x^2 + 4x + 3)

First, let's factor the denominator: x^2 + 4x + 3 = (x + 1)(x + 3). So we can write:

(x^2 + 5x + 6)/(x^2 + 4x + 3) = A/(x + 1) + B/(x + 3)

Note that we have two linear factors in the denominator, so we need two terms in the partial fraction decomposition. We don't know what A and B are yet - we'll need to solve for them.

Example 2: (2x + 5)/(x^2 - 4)

The denominator here is not yet in factored form, so we'll need to factor it first: x^2 - 4 = (x + 2)(x - 2). Then we can write:

(2x + 5)/(x^2 - 4) = A/(x + 2) + B/(x - 2)

Again, we have two linear factors in the denominator, so we need two terms in the partial fraction decomposition.

Example 3: (4x^2 - 2x + 1)/(x^3 + x)

The denominator here is not in factored form, so we'll need to factor it: x^3 + x = x(x^2 + 1). Then we can write:

(4x^2 - 2x + 1)/(x^3 + x) = A/x + B/(x^2 + 1)

In this case, we have one linear factor (x) and one quadratic factor (x^2 + 1), so we need two terms in the partial fraction decomposition.

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a card game using 36 unique cards: four suits (diamonds, hearts, clubs, and spades) with cards numbered from 1 to 9 in each suit. a hand is a collection of 9 cards, which can be sorted however the player chooses. how many 9 card hands, out of the total set of 36 possible cards, can be made?

Answers

There are 9,075,135,300 possible 9 card hands that can be made from a set of 36 unique cards.

This is a combination problem, where we want to select 9 cards from a set of 36 cards.

The order of the cards in the hand does not matter, so we need to use the formula for combinations:

n C r = n! / (r! * (n-r)!)

where n is the total number of items, r is the number we want to select, and ! denotes the factorial function.

In this case, we have n = 36 and r = 9. So, the number of 9 card hands we can make is:

36 C 9 = 36! / (9! * (36-9)!)

= (36 x 35 x 34 x 33 x 32 x 31 x 30 x 29 x 28) / (9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1)

= 9,075,135,300

Therefore, there are 9,075,135,300 possible 9 card hands that can be made from a set of 36 unique cards.

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which of the intervals contains the root of the f(x) = 2x − x3 + 2?

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To determine which interval contains the root of f(x) = 2x - x3 + 2, we need to examine the behavior of the function around the x-axis.

First, we can find the critical points by setting f(x) = 0: 0 = 2x - x3 + 2
Rearranging, we get: x3 - 2x + 2 = 0



This is a cubic equation, which can be difficult to solve exactly. However, we can use the Intermediate Value Theorem to determine whether there is a root in a given interval.


One critical point is x ≈ -1.7693. We can test whether there is a root in the interval (-∞, -1.7693) by evaluating f(x) at a point in the interval, such as x = -2:

f(-2) = 2(-2) - (-2)3 + 2 = -12

Since f(-2) is negative and f(x) is a continuous function, there must be at least one root in the interval (-∞, -1.7693).



Another critical point is x ≈ 1.7693. We can test whether there is a root in the interval (1.7693, ∞) by evaluating f(x) at a point in the interval, such as x = 2: f(2) = 2(2) - 23 + 2 = 0.



Since f(2) is zero and f(x) is a continuous function, there must be at least one root in the interval (1.7693, ∞).


Therefore, the intervals that contain the root of f(x) = 2x - x3 + 2 are (-∞, -1.7693) and (1.7693, ∞).
To determine which interval contains the root of the function f(x) = 2x - x^3 + 2, we can follow these steps:


Step 1: Identify the intervals of interest. For this question, the intervals are not specified, so we will assume the intervals are (-∞, 0) and (0, ∞).

Step 2: Check the value of f(x) at the endpoints of each interval. In our case, we will check f(0) for both intervals. f(0) = 2(0) - (0)^3 + 2 = 2.



Since f(0) > 0, we know that there is a root between the intervals (-∞, 0) and (0, ∞) if there's a change of sign between the intervals.

Step 3: Check the sign of f(x) within each interval. Pick a representative point from each interval and evaluate f(x) at that point.

For the interval (-∞, 0), let's pick x = -1:

f(-1) = 2(-1) - (-1)^3 + 2 = -1
For the interval (0, ∞), let's pick x = 1:
f(1) = 2(1) - (1)^3 + 2 = 3

Step 4: Determine which interval contains the root based on the change of sign.

The function f(x) changes its sign from negative to positive as we move from the interval (-∞, 0) to the interval (0, ∞). Therefore, the interval that contains the root of the function f(x) = 2x - x^3 + 2 is (-∞, 0).

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while working as a reace driver, jalen nedded to replace the trie on his car, tries are sold by the measurment around the outside of the tire. he measures the dimeter of the tire be 24 inches. what size tire does he need to by ( round to the nearest half inch)?

Answers

Jalen need to buy a tire of 69.08 m.

Given that, the tire diameter is 24 inches, we need to calculate the size tire does Jalen need to buy,

To find the same, we will calculate the circumference of the tire,

Circumference = π × diameter

= 3.14 × 22

= 69.08

Hence, Jalen need to buy a tire of 69.08 m.

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Which set of ordered pairs (x, y) could represent a linear function?
A = {(-5,7), (-2,4), (1,1), (4,−3)}
B = {(-4,2), (-2,4), (0,7), (2,9)}
C = {(0,9), (3, 3), (6,-3), (8,-9)}
D = {(-9,7), (-3,4), (3, 1), (9,-2)}

Answers

Answer:

B = {(-4,2), (-2,4), (0,7), (2,9)}

Step-by-step explanation:

Find four rational numbers between-1/3 and-2/3

Answers

Answer:

Step-by-step explanation:

-1/3 and - 2/3

can be written as

-11/33 and -22/33

so 4 rational numbers between these are:

-13/33, -14/33, -17/33 and - 19/33.

At the beginning of the year, a company estimates total overhead costs of $1,309,620. The company applies overhead using machine hours and
estimates that it will use 2,990 machine hours during the year. What amount of overhead should be applied to a job that uses 30 machine hours that
year?

Answers

If at the beginning of the year, a company estimates total overhead costs of $1,309,620. The amount of overhead should be applied to a job that uses 30 machine hours that year is: 13,140.

What amount of overhead should be applied to a job?

Overhead rate per machine hour = Total estimated overhead costs / Estimated number of machine hour

Overhead rate per machine hour = $1,309,620 / 2,990

Overhead rate per machine hour  = $438 per machine hour

Overhead applied to job = Overhead rate per machine hour x Number of machine hours used

Overhead applied to job = $438 x 30

Overhead applied to job = $13,140

Therefore, the amount of overhead is $13,140.

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Write the inverse of each function. 4. f(x)=-4/3x​

Answers

Answer:

-4/3 = -1 1/3 (In decimal form: -1.3)

Step-by-step explanation:

f(x) = -4/3x

(The derivative of ax^n is nax^n-1.)

-4/3x^1-1

(Subtract 1 from 1.)

-4/3x^0

(For any term t except 0, t^0 = 1.)

-4/3

A function, f ( x ) = − 3 4 x + 6 f(x)=− 4 3 ​ x+6 is given. Part A Determine the x-intercept and the y-intercept of the function.

Answers

The x-intercept and the y-intercept of the function

1.(8, 6)

2. (4.5, 6)

We have,

1. f(x) = -3/4x + 6

2. f(x) = -4/3x + 6

So, to find x intercept put f(x)= 0

1. 0 = -3/4x + 6

-6 = -3/4x

x = 24/3

x= 8

2. 0= -4/3x + 6

-4/3x = -6

x= 18/4

x= 4.5

Now, to find y intercept put x = 0

1. f(x) = -3/4(0)+6 =

2. f(x) = -4/3(0) +6 = 6

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A random sample of 50 purchases from a particular pharmacy was taken. The type of item purchased was recorded, and a table of the data was created.


Item Purchased Health & Medicine Beauty Household Grocery
Number of Purchases 10 18 15 7


Which graphical representation would be best to display the data?
Box plot
Line plot
Histogram
Stem-and-leaf plot

Answers

A bar chart or box plot would be the most appropriate graphical representation to display the given data. The correct option is A.

The best graphical representation to display the given data would be a bar chart, also known as a bar graph.

A bar chart is a graph that represents categorical data with rectangular bars, where the height or length of each bar corresponds to the frequency or relative frequency of the category. In this case, the categories are the types of items purchased (Health & Medicine, Beauty, Household, and Grocery), and the frequency is the number of purchases in each category.

A box plot would not be appropriate for this data because it is not numerical data and cannot be separated into quartiles or percentiles. A line plot would also not be appropriate because it is used to display individual data points rather than grouped data.

A histogram would not be appropriate because it is used to display continuous numerical data rather than categorical data. A stem-and-leaf plot would not be appropriate because it is also used to display numerical data.

Therefore, a bar chart would be the most appropriate graphical representation to display the given data.

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Need help urgent! Write an equation y=mx+b just given a line. Picture listed below

Answers

Answer: y = 1x - 1

Step-by-step explanation: To make the equation using y = mx +b, we need to find the slope of the line and the y intercept (the y value of the graph when the line goes through the y axis).

To find the slope (m), we need to calculate the rise over run or the change in y over the change in x value. Because it is a straight line, the slope is the same throughout the line. Let's choose two points: (2,1) and (-2,-3). Now we use the formula:

Δy/Δx or (y2 - y1)/(x2 - x1)

In this case y2 = 1, x2 = 2, y1 = -3, and x1=-2

Plug in the values in the equation to give...

(1 - (-3)) / (2 - (-2)) = 4/4 = 1

Thus the slope is 1.

This makes sense since the line increases 1 block of height for every 1 block is travels horizontally.

Next, you will need the y-intercept which is -1 because the line intercept the y axis at the value of -1 so the b value is -1.

Finally, plug the values into the y=mx+b to get

y = 1x - 1 or y = x - 1

(x and 1x are the same thing)

what is the diameter of a sphere with a volume of 6329 ft 3 , 6329 ft 3 , to the nearest tenth of a foot?

Answers

Therefore, the diameter of the sphere is approximately 20.2 feet when the volume is 6329 cubic feet.

The formula for the volume of a sphere is V = (4/3)πr³, where r is the radius of the sphere. To find the diameter, we need to find the radius first.

(4/3)πr³ = 632

r³ = (3/4)(6329/π)

r = ∛(3(6329/4π))

r ≈ 10.1 feet (rounded to one decimal place)

The diameter of the sphere is twice the radius, so:

d = 2r

≈ 20.2 feet (rounded to one decimal place)

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find the center and radius of the sphere whose equation is given by x2+y2+z2+4x−2z−8=0

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To find the center and radius of the sphere whose equation is given by x²+y²+z²+4x−2z−8=0, follow these steps:


Step 1: Rewrite the given equation in the standard form of a sphere.
The standard form of a sphere's equation is (x-a)²+(y-b)²+(z-c)²=r², where (a, b, c) is the center and r is the radius.



Step 2: Complete the squares for the x and z terms.
(x²+4x)+(y²)+(z²-2z)=8
(x+2)²-4+(y²)+(z-1)²-1=8


Step 3: Move the constants to the other side of the equation.
(x+2)²+(y²)+(z-1)²=13



Now the equation is in standard form. We can identify the center and radius. Step 4: Identify the center and radius.
The center (a, b, c) = (-2, 0, 1), and the radius r = √13. So, the center of the sphere is (-2, 0, 1), and the radius is √13.

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A system of equations consisting of a circle and a line is graphed. Which sttements about the number of possible solutions are correct? Check all that apply.

Answers

The requried statements about the number of possible solutions are shown below.

The correct statements are:

A circle and a line can intersect at one point, so the system can have one solution.A circle and a line can intersect twice, so the system can have two solutions.A circle and a line do not have to intersect, so the system can have no solution.

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a clinical trial has been conducted to evaluate the efficacy of a new drug to enable weight loss for obese patients. a pool of 249 obese individuals are chosen for the study. study participants must track their weight at home daily to compute their body-mass index (bmi) and have a clinical evaluation once per week at a local hospital over six months to complete the clinical trial. at the end of six months, it is found that 47% of those who received the new drug completed the clinical trial. those who completed the clinical trial are found to have reduced their bmi by 3.2 kg/m2, on average, over six months. explain how these results could be affected by bias and how that could affect the data.

Answers

There are several potential sources of probability in this study that could affect the results.

Selection bias could occur if the 249 individuals chosen for the study were not representative of the larger population of obese individuals. For example, if the study only recruited participants from a certain geographic area or demographic group, the results may not be generalizable to other populations.

Measurement bias could occur if the methods used to measure BMI were inaccurate or inconsistent. If the measurements were taken in a non-standardized way, or if the same person was not consistently measuring BMI throughout the study, the results may not be reliable.

Attrition bias could occur if participants dropped out of the study at different rates depending on whether they received the new drug or a placebo. For example, if participants who experienced negative side effects from the new drug were more likely to drop out, the results may overestimate the drug's effectiveness.

Reporting bias could occur if participants in the study provided inaccurate or incomplete information about their weight or BMI. For example, if participants underreported their weight or failed to record their weight on certain days, the results may not be accurate.

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what is the mean, mode, and median​

Answers

The mean, median and mode for the data-set in this problem is given as follows:

Mean: $400.41 million.Median: $345.1 million.Mode: No mode.

How to obtain the mean, median and the mode?

Before obtaining the measures, we obtain the ordered data-set, as follows:

200, 202.6, 228.7, 281.4, 334, 356.2, 359, 453, 652.7, 936.5.

The mean is given by the sum of all observations divided by the number of observations, hence:

Mean = (200 + 202.6 + 228.7 + 281.4 + 356.2 + 334 + 359 + 453 + 652.7 + 936.5)/10

Mean = $400.41 million.

The data-set has an even cardinality, hence the median is given by the mean of the two middle elements, as follows:

Median = (334 + 356.2)/2

Median = $345.1 million.

The data-set does not have a mode, as there is no observation that appears more than once. The mode of a data-set is the observation that appears the most times in a data-set.

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please try to answer the questions you know; with workings. i would recommend doing it on a hardcover book and uploading a picture. thank you so so much <3

Answers

The measures of the angles and the proofs are shown below

Calculating the measures of the angles

Circle 4

The angle at the centre is twice the angle at the circumference

So, we have

360 - ∠BOD = 2 * 110

Evaluate

∠BOD = 140

Circle 5

Angle in a semicircle is 90 degrees

So, we have

∠ABD + 19 = 90

∠ABD = 71

Angles in the same segment are equal

So, we have

∠ACB = 19

Circle 6

Angle in a semicircle is 90 degrees

So, we have

5y + y = 90

y = 15

So, we have

∠BAC = 5 * 15

∠BAC = 75

Circle 7

By corresponding angle theorem, we have

∠ABO = ∠CDO

By the sum of opposite internal angles in a triangle, we have

∠BOC = ∠BAO + ∠ABO

Substitute ∠ABO = ∠CDO

∠BOC = ∠BAO + ∠CDO --- proved

The angles at the edges are equal because they are corresponding angles of congruent isosceles triangles

Cyclic Quadrilateral

The opposite angles of cyclic quadrilaterals add up to 180 degrees

So, we have

180 - ∠x + 180 - ∠y = 180

Evaluate

∠x + ∠y = 180 --- proved

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Right in equation of the line of the graph with the coordinates 0,4 and 5,8 graph it

Answers

An equation of the line of the graph is y = 4x/5 + 4.

A graph of this equation is shown below.

How to determine an equation of this line?

In Mathematics and Geometry, the point-slope form of a straight line can be calculated by using the following mathematical equation (formula):

y - y₁ = m(x - x₁)

Where:

x and y represent the data points.m represent the slope.

First of all, we would determine the slope of this line;

Slope (m) = (y₂ - y₁)/(x₂ - x₁)

Slope (m) = (8 - 4)/(5 - 0)

Slope (m) = 4/5

At data point (0, 4) and a slope of 4/5, a linear equation for this line can be calculated by using the point-slope form as follows:

y - y₁ = m(x - x₁)

y - 4 = 4/5(x - 0)  

y = 4x/5 + 4

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A family has a unique pattern in their tile flooring on the patio. An image of one of the tiles is shown.

A quadrilateral with a line segment drawn from the bottom vertex and perpendicular to the top that is 7 centimeters. The right vertical side is labeled 3 centimeters. The portion of the top from the left vertex to the perpendicular segment is 4 centimeters. There is a horizontal segment from the left side that intersects the perpendicular vertical line segment and is labeled 6 centimeters.

What is the area of the tile shown?

58 cm2
44 cm2
74 cm2
70 cm2

Answers

Therefore, the area of the tile shown is approximately 58 cm^2, which is closest to the first option, 58 cm^2.

How to solve for the area

We know that BC = 3 cm and CD = 7 cm. We also know that AD = 4 cm and BD = 6 cm. To find the length of AB, we can use the Pythagorean theorem:

AB^2 = Ad² + BD²

AB^2 = 4² + 6²

AB² = 52

AB = √(52) =

2 * √(13) cm

Area = (1/2) x (sum of parallel sides) x (distanc)

In this case, the sum of the parallel sides is AB + BC = 2sqrt(13) + 3 cm, and the distance between them is CD = 7 cm. So:

Area = (1/2) x (2* √(13) + 3) x 7

Area = (√(52) + 3/2) x 7

Area ≈ 58 cm²

Therefore, the area of the tile shown is approximately 58 cm^2, which is closest to the first option, 58 cm^2.

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A new machine that deposits cement for a road requires 12 hours to complete one-half mile section of the road. An older machine requires 16 hours to pave the same amount of road. After depositing cement for 4 hours, the new machine develops mechanical problem and quits working. The older machine is brought into place and continues the job. How long in hours does it take the older machine to complete the job?

Answers

The older device will finish the final 1/6 mile in 4/3 hours. After the new machine stops operating, the task would therefore take the older machine 4/3 hours to complete.

Find out first how much of the new machine's route it covers in 4 hours:

Since the new machine takes 12 hours to complete a half-mile section, it takes 6 hours to complete a quarter-mile section (half of a half-mile). Therefore, in 4 hours, it would complete:

4 / 6 = 2 / 3 of a quarter-mile section

This means that there is still a remaining distance of:

1/4 - 2/3(1/4) = 1/6 mile

The older machine can finish a half mile in sixteen hours, which translates to a quarter mile in eight.  Therefore, it can complete the remaining 1/6 mile in:

(1/6) / (1/4) * 8 = 4/3 hours

Thus, it would take the older machine 4/3 hours to complete the job.

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Recall in class we showed the derivation of logistic regression from Naive Bayes as- sumptions. At that time, we assumed the variance o2 of class-conditional probability distri- bution is independent of class index k and feature index j. Now we generalize it by removing the assumption of ožk being independent of j and k. Namely, ok of the class-conditional probability distribution p(x;\y = k) now depend on both indices. jk - Is the new form of p(x;\y = k) still implying the same logistic regression formula p(y|X)? If not, write down the new form of logistic regression.

Answers

In the original derivation of logistic regression from Naive Bayes assumptions, we assumed that the variance σ^2 of a class-conditional probability distribution is independent of class index k and feature index j. Now, by generalizing and allowing σ^2_jk to depend on both indices, the class-conditional probability distribution p(x|y=k) is now affected by this change.

This new assumption affects the logistic regression formula p(y|X) because it no longer relies on the original independence assumption. Consequently, the logistic regression model will need to account for the new variances σ^2_jk, which depend on both class index k and feature index j.

The new form of logistic regression will likely be different from the original formula, as it must now accommodate the modified variances in class-conditional probability distributions. Unfortunately, without more information, it is not possible to provide the exact new form of logistic regression here. However, it's important to note that this new form should consider the dependency of σ^2_jk on both indices j and k.

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Find the first 4 non-zero terms of the Taylor series expansion of f(x)=e^x sin x, c=0. (Derive from the Taylor series of e^x and sin x).

Answers

The first four non-zero terms of the Taylor series expansion of f(x)=e^x sin x, centered at c=0, are: f(x) = x + x^2/2 + x^3/3! + ...

To find the Taylor series expansion of f(x)=e^x sin x, we need to first find the Taylor series expansions of e^x and sin x centered at c=0.

The Taylor series expansion of e^x centered at c=0 is:

e^x = 1 + x + (x^2)/2! + (x^3)/3! + ...

And the Taylor series expansion of sin x centered at c=0 is:

sin x = x - (x^3)/3! + (x^5)/5! - (x^7)/7! + ...

To find the Taylor series expansion of f(x)=e^x sin x, we need to multiply these two series together. We can do this using the "r series" method, where we take the product of the first r terms of each series and then add up all the resulting terms.

So the first term of the series for f(x) is simply the product of the first term of each series:

f(x) = e^0 * sin(0) = 0

The second term is the sum of the product of the second term of the e^x series and the first term of the sin x series, and the product of the first term of the e^x series and the second term of the sin x series:

f(x) = e^0 * sin(x) + e^x * sin(0) = x

The third term is the sum of the product of the third term of the e^x series and the first term of the sin x series, the product of the second term of the e^x series and the second term of the sin x series, and the product of the first term of the e^x series and the third term of the sin x series:

f(x) = e^0 * sin(x) + e^x * sin(0) + (x^2)/2! * sin(x) = x + x^2/2

The fourth term is the sum of the product of the fourth term of the e^x series and the first term of the sin x series, the product of the third term of the e^x series and the second term of the sin x series, the product of the second term of the e^x series and the third term of the sin x series, and the product of the first term of the e^x series and the fourth term of the sin x series:

f(x) = e^0 * sin(x) + e^x * sin(0) + (x^2)/2! * sin(x) + (x^3)/3! * sin(0) = x + x^2/2 + x^3/3!

So the first four non-zero terms of the Taylor series expansion of f(x)=e^x sin x, centered at c=0, are:

f(x) = x + x^2/2 + x^3/3! + ...

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Danika and Sofie are staring up at a helicopter. Danika is directly east of the helicopter and Sofie is directlv west. The anale of elevation from Danika to the
helicopter is 31°. The angle of elevation from Sofie to the helicopter is 10°
Danika and Sofie are 100 feet apart. Find the height of the helicopter above the
ground. Round to two decimal places as necessary

Answers

Answer:

Height of helicopter above ground = 13.63 feet

Step-by-step explanation:

See attached image to support explanation

B is the point vertically below where the helicopter is located

s is the distance from Sofie to B

d is the distance from Danika to B

We have
s + d = 100 ==> s = 100 -d

h is the height of the helicopter from the base

Both triangles are right triangles

For a right triangle,
tan x = Side opposite hypotenuse/Side adjacent to hypotenuse
where x is the angle between the side adjacent to the hypotenuse

Using this information for both triangles we get

[tex]\tan 10 = \dfrac{h}{s}\\or\\h = s ( \tan 10)\\\\\tan 31 = \dfrac{h}{d}\\or\\h = d (\tan31)\\\\[/tex]

Therefore
s (tan 10) = d ( tan 31)

But s = 100 -d:
(100-d) tan 10 = d ( tan 31)

100(tan 10) - d(tan 10) = d (tan 31)

Switch sides:
d (tan 31) = 100 (tan 10) - d( tan 10)

Add d (tan 10) to both sides:
d (tan 31) + d ·(tan 10) = 100(tan 10)

d(tan 31 + tan 10) = 100 (tan 10)

[tex]d = \dfrac{100(\tan 10)}{\tan 31 + \tan 10}[/tex]

Using a calculator we can compute right side as

[tex]\dfrac{100(\tan 10)}{\tan 31 + \tan 10} = 22.6878[/tex]

So
d = 22.6878

Plug this value of d into h = d sin 31 to get
h = d (tan 31)

h = 22.688 (0.6009)

h = 13.6322....

= 13.63 rounded to 2 decimal places

Height of helicopter above ground = 13.63 feet

the table shows the u.s. city average price of iceberg lettuce, in cents per pound, for selected months and years. price of iceberg lettuce (cents per pound) month year feb mar apr may jun 2004 80.5 81.3 80.1 71.0 75.1 2005 73.0 82.9 100.4 92.6 89.5 2006 79.4 81.5 86.9 96.7 84.8 2007 92.0 91.5 98.6 87.9 85.6 2008 89.5 87.3 90.2 86.8 86.0 2009 93.0 87.5 90.7 88.7 87.6 classify the april 2007 price of 98.6 cents per pound. justify your classification. it is a relative maximum because it is larger than all eight surrounding prices. it is a relative minimum because it is smaller than all eight surrounding prices. it is a saddle point because it is larger than the two adjacent prices in the same column, but smaller than the two adjacent prices in the same row. it is a saddle point because it is larger than the two adjacent prices in the same row, but smaller than the two adjacent prices in the same column. it is a saddle point because it is larger than the two adjacent prices on one diagonal, but smaller than the two adjacent prices on the other diagonal. correct: your answer is correct. classify the april 2008 price of 90.2 cents per pound. justify your classification. it is a relative maximum because it is larger than all eight surrounding prices. it is a relative minimum because it is smaller than all eight surrounding prices. it is a saddle point because it is larger than the two adjacent prices in the same column, but smaller than the two adjacent prices in the same row. it is a saddle point because it is larger than the two adjacent prices in the same row, but smaller than the two adjacent prices in the same column. it is a saddle point because it is larger than the two adjacent prices on one diagonal, but smaller than the two adjacent prices on the other diagonal. correct: your answer is correct. there are three additional critical points in the table. find these points. relative maximum point apr correct: your answer is correct. , 2005 correct: your answer is correct. , 100.4 correct: your answer is correct. relative minimum point feb incorrect: your answer is incorrect. , 2005 incorrect: your answer is incorrect. , saddle point ---select--- , ---select--- ,

Answers

The relative maximum point in April 2005, was 100.4; the relative minimum point in May 2004, was 71.0; the saddle point in June 2006, was 84.8.

The April 2007 price of 98.6 cents per pound is a saddle point because it is larger than the two adjacent prices in the same row (91.5 and 87.9), but smaller than the two adjacent prices in the same column (86.9 and 100.4).

The April 2008 price of 90.2 cents per pound is a relative minimum because it is smaller than all eight surrounding prices.

The three additional critical points in the table are:

1. Relative maximum point: April 2005, 100.4
2. Relative minimum point: May 2004, 71.0
3. Saddle point: February 2006, 79.4 (larger than the two adjacent prices in the same row, but smaller than the two adjacent prices in the same column).

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A rectangle's perimeter and its area have
the same numerical value. The length of the
rectangle is 6 centimeters.
Write an equation that can be used to find x, the
width of the rectangle in centimeters.

Answers

Answer:

A rectangle's perimeter and its area have

the same numerical value. The length of the

rectangle is 6 centimeters.

Write an equation that can be used to find x, the

width of the rectangle in centimete

Step-by-step explanation:

Answer :

According to the question it's given that,

A rectangle's perimeter and its area have the same numerical value. The length of the rectangle is 6 centimeters.

Required Formulas,

[tex]:\implies[/tex] perimeter of rectangle is 2(l+ b)

[tex]:\implies[/tex] Area of rectangle = l × b

Also, Length of rectangle is 6 cm.

Perimeter of rectangle

[tex]:\implies[/tex] 2(6 + x)

[tex]:\implies[/tex] 12 + 2x

Area of rectangle

[tex]:\implies[/tex] l × b

[tex]:\implies[/tex] 6 × x

[tex]:\implies[/tex] 6x

Now, A rectangle's perimeter and its area have the same numerical value.

Perimeter of rectangle = Area of rectangle

[tex]:\implies[/tex] 12 + 2x = 6x (required equation)

Therefore this is the required equation to find the width of the rectangle.

If cosx=square root of 3/2 , find cos (x+pi)

Answers

The value of cos (x + pi) is -✓3/2, based on the stated information and known trigonometric values.

As per the known fact, the value of x wil be 30° as it is the specific value whose cosine or cos is ✓3/2. Now, we also know that π represents 180°. Also, the formula for cos (a + b) is cos A cos B - sin A sin B.

So, cos (x + pi) will be -

cos x cos pi - sin x sin pi

Keeping the values and solving -

cos (x + pi) = cos 30 cos 180 - sin 30 sin 180

cos (x + pi) = (✓3/2 × -1) - (1/2 × 0)

cos (x + pi) = -✓3/2

Hence, the value of cos (x + pi) is -✓3/2.

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(PLEASE AND ASAP I WILL GIVE 100 PIONTS) What is the horizontal distance between (–14, –20) to (7, –20)?

7 units
21 units
–7 units
–21 units

Answers

Answer:

The two points have the same y-coordinate of -20, so they lie on the same horizontal line.

Step-by-step explanation:

To find the horizontal distance between them, we can simply subtract their x-coordinates:

distance = 7 - (-14) = 7 + 14 = 21

Therefore, the horizontal distance between (–14, –20) and (7, –20) is 21 units.

Answer:

Step-by-step explanation:

21 units

4. Triangle RST below will be dilated with the
origin as the center of dilation and a scale
factor of 4. What will be the coordinates of
the vertices of the dilated image, AR'ST?
12
11
10
C.
9
8
7
RTS
0123456789101112
A. R'(4, 12), S'(12, 12), T'(8,4)
B. R'(4, 12), S'(9, 9), T'(8, 1)
R' (2, 6), S'(12, 12), T'(4, 2)
fallby
D. art
R(1, 2), S (1,1). T(1, 2)

Answers

The coordinates of the image of the triangle RST following a dilation by a with the origin as the center of dilation and a scale factor of 4 are;

A. R'(4, 12), S'(12, 12), T'(8, 4)

What is a dilation transformation?

A dilation transformation is a transformation in which the image dimensions are obtained by resizing the dimensions of the pre-image using a scale factor.

The vertices of the triangle RST are; R(1, 3), S(3, 3), and T(2, 1)

The coordinates of the image of the point (x, y) following a dilation by a scale factor of a about the origin is; (a·x, a·y)

Therefore, the coordinates of the dilated image of the triangle RST after a dilation with the origin as the center of dilation and a scale factor of 4 are;

R(1, 3) ⇒ R'(4 × 1, 4 × 3) = R'(4, 12)

S(3, 3) ⇒ S'(4 × 3, 4 × 3) = S'(12, 12)

T(2, 1) ⇒ T'(4 × 2, 4 × 1) = T'(8, 4)

The correct option is therefore;

A. R'(4, 12), S'(12, 12), T'(8, 4)

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