Find the discriminant and the number of real roots for this equation.

4x2 + 12x + 9 = 0

A. -144; one real root

B. -144; no real roots

C. 0; one real root

D. 0; two real roots

Discriminant and the number of real roots for this equation are 0, one real root.

Discriminant of a polynomial in math is a function of the coefficients of the polynomial.

The discriminant of a quadratic equation ax2 + bx + c = 0 is in terms of its coefficients a, b, and c. i.e.,

Discriminant = [tex]\sqrt{b^{2} -4ac}[/tex]

Given equation

[tex]4x^{2} +12x+9 = 0[/tex]

Discriminant = [tex]\sqrt{b^{2} -4ac}[/tex]

= [tex]\sqrt{12^{2}-4(4)(9) }[/tex]

= [tex]\sqrt{144-144}[/tex]

D = 0

Therefore, number of real roots is one.

Hence, discriminant and the number of real roots for this equation are 0, one real root.

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