The domain of the function f(x, y) = ln(6 − x^2 − 5y^2) is the set of all (x, y) pairs such that 6 − x^2 − 5y^2 is positive.
The natural logarithmic function ln is defined only for positive arguments. Therefore, for f(x, y) = ln(6 − x^2 − 5y^2) to be defined, the argument 6 − x^2 − 5y^2 must be positive.
To find the domain of the function, we solve the inequality:
6 − x^2 − 5y^2 > 0
Rearranging, we get:
x^2 + 5y^2 < 6
This is the equation of an ellipse centered at the origin with semi-axes lengths a = √6 and b = √(6/5). Therefore, the domain of f(x, y) is the interior of this ellipse. That is, the set of all (x, y) pairs such that x^2 + 5y^2 is less than 6. In interval notation, this can be written as:
{(x, y) | x^2 + 5y^2 < 6}
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Consider the set of square matrices with zeros any possible values off the diagonal along their diagonal, but (a) For the 2-by-2 case, how many of the 2 terms of the determinant must be zero if 0? a11 a22 (b) For the 3-by-3 case, how many of the 6 terms of the determinant must be zero if al a22 = a33=0? (c) For the 4-by-4 case, how many of the 24 terms of the determinant must be zero if 0? a22 = a33 a11 a44
Two of the diagonal elements being zero will result in the determinant being zero.
For square matrices of size n, with zeros anywhere possible off the diagonal and along their diagonal, we call these diagonal matrices.
(a) For the 2-by-2 case, the determinant of a 2-by-2 diagonal matrix is given by:
det(A) = a11 a22
If a11 or a22 is zero, then the determinant is zero. Therefore, if one of the diagonal elements is zero, the determinant will be zero.
(b) For the 3-by-3 case, the determinant of a 3-by-3 diagonal matrix is given by:
det(A) = a11 a22 a33
If a11, a22, or a33 is zero, then the determinant is zero. Therefore, if one of the diagonal elements is zero, the determinant will be zero.
(c) For the 4-by-4 case, the determinant of a 4-by-4 diagonal matrix is given by:
det(A) = a11 a22 a33 a44
If a11, a22, a33, or a44 is zero, then the determinant is zero. Therefore, if one of the diagonal elements is zero, the determinant will be zero.
If a22 and a33 are both zero, then the determinant of the 4-by-4 matrix is given by:
det(A) = a11 * 0 * 0 * a44 = 0
Therefore, two of the diagonal elements being zero will result in the determinant being zero.
In general, for an n-by-n diagonal matrix, if k diagonal elements are zero, then the determinant is zero if k > n-1, and non-zero if k ≤ n-1.
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n problems 15–24, solve for y1s2, the laplace transform of the solution y1t2 to the given initial value problem.
we obtain the Laplace transform of the solution y1s2 to the initial value problem.
A general explanation of Laplace transforms and how they can be used to solve initial value problems.
The Laplace transform is a mathematical tool that allows us to transform a function of time (such as a differential equation) into a function of a complex variable s (called the Laplace variable). The Laplace transform of a function f(t) is defined as:
F(s) = L{f(t)} = ∫[0, ∞) f(t) e^(-st) dt
where s is a complex number of the form s = σ + iω, and σ and ω are real numbers. The Laplace transform has many properties that make it useful for solving differential equations, such as linearity, differentiation, and integration rules.
To solve an initial value problem using Laplace transforms,
we first take the Laplace transform of both sides of the differential equation, and use the linearity property to simplify the equation into a simpler algebraic equation involving the Laplace transforms of the unknown function.
We then solve this algebraic equation for the Laplace transform of the unknown function, and finally take the inverse Laplace transform to obtain the solution in the time domain.
The initial conditions of the problem are also taken into account by using the properties of the Laplace transform to express the initial conditions in terms of the Laplace transform of the function.
By solving the algebraic equation for the Laplace transform of the function with the initial conditions, we obtain the Laplace transform of the solution y1s2 to the initial value problem.
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three airlines serve a small town in ohio. airline a has 53% of all scheduled flights, airline b has 32% and airline c has the remaining 15%. their on-time rates are 82%, 64%, and 36%, respectively. a flight just left on-time. what is the probability that it was a flight of airline a?
The probability that it was a flight of airline A is equal to approximately 0.6268, or about 62.68%
Let A, B, and C be the events that a flight is operated by airlines A, B, and C, respectively.
And let O be the event that a flight is on-time.
The conditional probability of A given O is equal to P(A|O).
Using Bayes' theorem, we have,
P(A|O) = P(O|A) × P(A) / P(O)
where P(O|A) is the probability that a flight of airline A is on-time.
P(A) is the probability that a flight is operated by airline A.
And P(O) is the probability that a flight is on-time regardless of which airline operates it.
Calculate these probabilities as follows,
P(O|A) = 0.82, the on-time rate of airline A
P(A) = 0.53, the proportion of flights operated by airline A
P(O) = P(O|A) × P(A) + P(O|B) × P(B) + P(O|C) × P(C)
= 0.82 × 0.53 + 0.64 × 0.32 + 0.36 × 0.15
= 0.6934
Plugging in these values, we get,
P(A|O) = 0.82 × 0.53 / 0.6934
Simplifying it,
P(A|O) = 0.6268
Therefore, the probability that the on-time flight that just left was operated by airline A is approximately 0.6268, or about 62.68%.
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Find the inverse of f(x)=6x^2-7
The inverse of the given function is g'(x) = ±√x-7/6
Given that a function g(x) = 6x²-7,
We need to find the inverse of the given function.
To find the inverse of any function, we flip the x and y in the original function.
f(x) = 6x² - 7
y = 6x² - 7
x = 6y² - 7
6y² = x - 7
y = ±√x-7/6
Hence the inverse of the given function is g'(x) = ±√x-7/6
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From 1868
to 2010,
there were two African Americans who were elected to the US House of Representatives but denied their seat,
and so never served. One was elected in 1868,
and the other was elected in 1872. If these two were added to the total number of African American representatives from 1868
to 2010,
what percentage of representatives would have served in the time period from 1868
to 1930?
To calculate the percentage of representatives who would have served in the time period from 1868 to 1930, we need to determine the total number of African American representatives during that period.
From the information given, we know that there were two African American representatives who were elected but denied their seat. Therefore, the total number of African American representatives during the time period from 1868 to 1930 would be the number of African American representatives elected and served plus the two who were elected but denied their seat.
Let's assume there were "x" African American representatives who were elected and served during the period from 1868 to 1930.
So, the total number of African American representatives during that period would be (x + 2) because we are adding the two who were elected but denied their seat.
To calculate the percentage, we divide the number of African American representatives who served by the total number of representatives and multiply by 100:
Percentage = (x / (x + 2)) * 100
Unfortunately, we don't have the specific number of African American representatives who served during that period, so we cannot calculate the exact percentage.
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Find the function f(x) = (x^2 - 2)(x^2 - √2) find the value(s) of x in which f’(x) = 0. to the hundredths place.
The value(s) of x in which f’(x) = 0 are x = 0 and [tex]x= ^+_-\sqrt{2+\sqrt2}[/tex] to the hundredth place.
First we need to find the derivative of f(x) for that we can use the product rule:
we know that [tex]f(x) = (x^2 - 2)(x^2 - \sqrt2)[/tex] so the first derivative f'(x) is equal to:
[tex]f'(x) = [(x^2 - 2)(2x)] + [(x^2 - \sqrt2)(2x)][/tex]
after simplifying the derivative further, we get:
[tex]f'(x) = 2x(x^2 - \sqrt2 - 2)[/tex]
We need to find the value of x for which the function f(x) =0:
So we can set f'(x) to zero and solve for x to find what is the value of x that satisfies the given equation.
[tex]2x(x^2 - \sqrt2 - 2) = 0[/tex]
Therefore, either 2x = 0 (i.e., x = 0) or [tex]x^2 - \sqrt2 - 2[/tex] = 0.
To solve for x in the second equation we can add 2 and [tex]\sqrt2[/tex] to both sides and then take the square root of both sides:
[tex]x^2 = 2 + \sqrt2\\x = ^+_- \sqrt{2 + \sqrt2}[/tex]
Therefore, the value(s) of x in which f’(x) = 0 are x = 0 and [tex]x= ^+_-\sqrt{2+\sqrt2}[/tex] to the hundredth place.
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Divide.
(20x2-12x+8)+ (2x+8)
280
2x-8
280
O 10x-34+.
O 10x +34+
O 10x +46 +
2x-8
376
2x-8
376
2x+8
O 10x-46+.
The final expression is 20(5x - 1)2 + 2x + 8.
The given expression is (20x2-12x+8)+ (2x+8). We are required to simplify the given expression.To do that, we will first simplify the expressions inside the parentheses followed by the addition.(20x2-12x+8) can be written as 4 * 5x2-3x+2. This is because we can take 4 as the GCF (Greatest Common Factor) from the given expression. 4 is also a perfect square so we can write 4 * 5x2-3x+2 as 2 * 2 * 5x2-3x+2.
This expression can further be simplified using the (a + b)2 formula which is a2 + 2ab + b2. In this case, a is 5x and b is 1. Hence, we can write 2 * 2 * 5x2-3x+2 as 2 * 2 * (5x - 1)2. Now, the given expression becomes 2 * 2 * (5x - 1)2 + (2x + 8).We will simplify this expression further by distributing the factor 2 on the right-hand side of the addition. Therefore, the given expression becomes 2 * 2 * (5x - 1)2 + 2x + 2 * 4. This can be simplified to get the following expression:20(5x - 1)2 + 2x + 8We have now successfully simplified the given expression.
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HELP ME PLSSSSS THIS IS MY MISSING ASSIGNMENT
Answer:10
Step-by-step explanation:
10
square root of 100 is 10 because 10×10=100
let f (x) represent a function.
drag and drop the answers into the boxes to correctly match the descriptions with the given transformations.
The two transformations are:
f(x + 5/4) this is a translation of 5/4 units to the left.f(x) - 5/4 this is a translation of 5/4 units down.How to identify the transformations?For a function f(x) we define:
Vertical translation of N units as:
g(x) = f(x) + N
if N > 0, the translation is up.
if N <0, the translation is down.
Horizontal translation of N units as:
g(x) = f(x + N)
if N > 0, the translation is to the left.
if N <0, the translation is to the right.
Here we have two transformations:
f(x + 5/4) this is a translation of 5/4 units to the left.
f(x) - 5/4 this is a translation of 5/4 units down.
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What is the equation of the line???
Answer:
y = -3x - 1
Step-by-step explanation:
Pick any 2 points on the line and find the slope, m:
(-1, 2) and (1, -4)
m = (-4 - 2) / (1 - -1) = -6/2 = -3
The y-intercept, b, is -1 (read it right off the graph, where the line passes through the y axis).
Equation of the line in y = mx + b form:
y = -3x - 1
the empty set is not a vector space. it fails to satisfy only one of the requirements from the definition. which one?
since there are no elements in the empty set that can serve as a zero vector. The empty set has no elements, so it cannot have a zero vector, and thus it cannot be a vector space.
The empty set fails to satisfy the requirement that there exists a zero vector, since there are no elements in the empty set that can serve as a zero vector. Therefore, the empty set cannot be considered a vector space.
The empty set is not a vector space because it fails to satisfy the requirement of having a zero vector. A vector space must have a zero vector (also known as the identity element) that, when added to any other vector in the space, results in the original vector. The empty set has no elements, so it cannot have a zero vector, and thus it cannot be a vector space.
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If a signal Q is defined as 'signal Q: STD_LOGIC_VECTOR(2 to 8):="1001011";' what vector is returned from Q(5 to 6)? (5 points) a. "10" b. "01" c. "00" d. "11" e. None of the above
The vector returned from Q(5 to 6) is "01".
In the given signal definition, "signal Q: STD_LOGIC_VECTOR(2 to 8):=""1001011"";", the range of indices from 2 to 8 specifies a 7-bit STD_LOGIC_VECTOR with the value "1001011". When accessing a range of indices within this vector, we use the syntax Q(m to n), where m and n are the starting and ending indices of the desired range, respectively.
Therefore, when we access Q(5 to 6), we are retrieving the 5th and 6th elements of the vector, which correspond to the values "01". Thus, the vector returned from Q(5 to 6) is "01". Option (b) is the correct answer.
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Find the quadratic equation!
The quadratic equation on the given graph is y = (x - 2)² - 9.
How to find the quadratic equation?For a quadratic with leading coefficient a and vertex (h, k), the equation is:
y = a*(x - h)² + k
Here we can see that the vertex is at (2, -9), replacing that:
y = a*(x - 2)² - 9
We can see that the y-intercept is at y = -5, then:
-5 = a*(0 - 2)² - 9
-5 = a*4 - 9
-5 + 9 = a*4
4 = a*4
4/4 = a
1 = a
The quadratic is:
y = (x - 2)² - 9
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find the indefinite integral and check the result by differentiating. ∫2xx2 47dx
The indefinite integral of 2x^2/47dx is (2/47)∫x^2dx which equals (2/47)(x^3/3) + C, where C is the constant of integration. To check this result, we can differentiate the obtained expression using the power rule of differentiation. The derivative of (2/47)(x^3/3) is (2/47)(3x^2/3) which simplifies to (2/47)x^2, which is the integrand we started with. Therefore, the obtained result is correct.
In summary, the indefinite integral of 2x^2/47dx is (2/47)(x^3/3) + C, where C is the constant of integration. We can check this result by taking the derivative of the obtained expression and verifying that it equals the original integrand.
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For sample of 29 New England cities sociologist studies the crime rate in each city (crimes per 100,000 residents) as function of its poverty rate (in %) and its median income (in Si,0OOs): He finds that SSE = 4,166,091 and SST = 7,712,159. a. Calculate the standard error of the estimate: (Round your answer to 4 decimal places ) Standard Error This is a numeric cell, s0 please enter numbers only: b-1. What proportion of the sample variation in crime rate is explained by the variability in the explanatory variables? (Round your answer to 4 decimal places:) Explained proportion b-2. What proportion is unexplained? (Round your answer to decimal places ) Unexplained proportion
a. standard error = √(4,166,091/27) = 888.56 (rounded to 4 decimal places), b-1. 46.06% of the sample variation in crime rate is explained by the poverty and median income variability, and b-2. Therefore, 53.94% of the sample variation in crime rate is unexplained.
a. To calculate the standard error of the estimate, we first need to calculate the degrees of freedom, which is n-2, where n is the sample size. In this case, n=29, the degree of freedom is 27. Then, we can use the formula:
standard error = √(SSE/df)
Plugging in the values we have, we get:
standard error = √(4,166,091/27) = 888.56 (rounded to 4 decimal places)
b-1. To find the proportion of sample variation in the crime rate that is explained by the variability in the explanatory variables, we can use the formula:
R-squared = 1 - (SSE/SST)
Plugging in the values we have, we get:
R-squared = 1 - (4,166,091/7,712,159) = 0.4606 (rounded to 4 decimal places)
Therefore, 46.06% of the sample variation in crime rate is explained by the variability in the poverty rate and median income.
b-2. To find the proportion of sample variation in the crime rate that is unexplained, we can simply subtract the explained proportion (R-squared) from 1:
Unexplained proportion = 1 - 0.4606 = 0.5394 (rounded to 4 decimal places)
Therefore, 53.94% of the sample variation in crime rate is unexplained.
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if the average value of a continuous function f on the interval −2 4 is 12 what is ∫4−2f(x)8 dx
The value of the integral ∫[4,-2] f(x) 8dx is -576.
If the average value of a continuous function f on the interval [−2, 4] is 12
∫ 4−2 f(x) 8 dx = 12 (4 - (-2) )
∫ 4−2 f(x) 8 dx = 72
The integral of ∫ [4,-2] f (x) 8dx is constant value
∫ [4,-2] f (x) 8 dx = 8 ∫ [4,-2] f (x) dx
we already know that ∫ [-2,4] f (x) dx = 72
The integral over the interval [4,-2] by using the property of definite integrals
∫ [a, b] f (x) dx = -∫ [b, a] f (x) dx
∫ [4,-2] f (x) dx = -∫ [-2,4] f (x) dx = -72
Putting value back into the original expression, we get:
∫ [4,-2] f (x) 8dx = 8 ∫ [4,-2] f (x) dx = 8(-72) = -576
The value of the integral ∫ [4,-2] f (x) 8dx is -576.
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Vector vector u equals vector PQ has initial point P (2, 14) and terminal point Q (7, 3). Vector vector v equals vector RS has initial point R (29, 8) and terminal point S (12, 17). Part A: Write u and v in linear form. Show all necessary work. (4 points) Part B: Write u and v in trigonometric form. Show all necessary work. (8 points) Part C: Find 7u − 4v. Show all necessary calculations. (3 points)
The vectors presented in linear form using the coordinates of the points on the vectors are;
Part A; [tex]\vec{u}[/tex] = <5, -11>, [tex]\vec{v}[/tex] = <-17, 9>
Part B; [tex]\vec{u}[/tex] = 12.08·(cos(-65.56°), sin(-65.56°)), [tex]\vec{v}[/tex] = 19.24·9cos(-27.9°), cos(-27.9°)
Part C; 7·u - 4·v = <33, -41>
What is a vector?A vector is a quantity that has both magnitude and direction.
Part A;
The initial point of the vector u is; P(2, 14), and the final point of the vector u is Q(7, 3)
The vector u in linear form is therefore; [tex]\vec{u}[/tex] = <7 - 2, 3 - 14> = <5, -11>
The initial point of the vector v is; R(29, 8), and the final point of the vector u is S(12, 17)
The vector v in linear form is therefore; [tex]\vec{v}[/tex] = <12 - 29, 17 - 8> = <-17, 9>
Part B
Pythagorean Theorem indicates;
Magnitude of the vector u, |u| = √(5² + (-11)²) ≈ 12.08
The direction of the vector u is; arctan(-11/5) ≈ -65.56°
The vector in trigonometric form is therefore; [tex]\vec{u}[/tex] = 12.08 × (cos(-65.56°), sin(-65.56°)
Magnitude of the vector v, |v| = √((-17)² + 9²) ≈ 19.24
The direction of the vector v is; arctan(9/(-17)) ≈ -27.9°
The vector in trigonometric form is therefore; [tex]\vec{v}[/tex] = 19.24 × (cos(-27.9°), sin(-27.9°))
Part C;
7·u = <7 × 5, 7 × (-11)> = <35, -77>
-4·v = <(-4) × (-17), (-4) × 9> = <68, -36>
7·u - 4·v = <35 - 68, -77 - (-36)> = <33, -41>
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(q19) Which is an even function?
The even function in the context of this problem is given as follows:
A. [tex]f(x) = -x^4[/tex]
What are even and odd functions?In even functions, we have that the statement f(x) = f(-x) is true for all values of x.In odd functions, we have that the statement f(-x) = -f(x) is true for all values of x.If none of the above statements are true for all values of x, the function is neither even nor odd.The fourth power function has the same output values for x and -x, meaning that:
[tex]-x^4 = -(-x)^4[/tex]
Hence option A gives the even function in the context of this problem.
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write the sum using sigma notation. 12 22 32 132 k = 1
In sigma notation, the sum is represented as follows: ∑ (k^2 + 1), k = 1 to 2.
The given sum is: 12 + 22 + 32 + 132.
To write this sum using sigma notation, we can observe the pattern in the terms. The first term is 12, the second term is 22 (which is 12 + 1), the third term is 32 (which is 22 + 1), and the fourth term is 132 (which is 32 + 1 + 2).
We can see that each term is obtained by adding the square of the position number (k^2) to the previous term, along with an additional constant value of 1 or 2 depending on the position.
So, let's write the sum using sigma notation:
∑ [(k^2 + c(k-1))], where k starts from 1 and goes up to 4.
In this notation, k represents the position of the term, k^2 represents the square of the position number, and c represents the constant value added to the previous term.
For the given sum, the constant value c changes depending on the position of the term:
For the first term (k = 1), c is 1.
For the second term (k = 2), c is 1.
For the third term (k = 3), c is 1.
For the fourth term (k = 4), c is 2.
So, the corrected sigma notation for the given sum is:
∑ [(k^2 + c(k-1))], k = 1 to 4.
This indicates that we sum the terms (k^2 + c(k-1)) as k takes values from 1 to 4, where c changes based on the position of the term.
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Graph y=1/5x+3
Identify the x-intercept
Answer:
To find the x-intercept of the line y = (1/5)x + 3, we need to set y to zero and solve for x, since the x-intercept is the point where the line crosses the x-axis.
0 = (1/5)x + 3
Subtracting 3 from both sides:
-3 = (1/5)x
Multiplying both sides by 5:
-15 = x
Therefore, the x-intercept of the line y = (1/5)x + 3 is at the point (-15, 0).
radical(-4x) ⁴= ?????
The result of the expression radical(-4x)^4 is -16x² in the context of complex numbers.
The expression you provided, radical(-4x)^4, involves taking the fourth power of the square root of -4x. Let's break it down step by step.
First, let's simplify the square root of -4x:
√(-4x)
The square root of a negative number is not defined in the real number system. Therefore, this expression has no real number solution. In other words, the square root of -4x cannot be evaluated when considering only real numbers.
However, if we move to the complex number system, where the square root of negative numbers is defined, we can proceed further. In the complex number system, the square root of -1 is denoted as "i" or the imaginary unit.
Thus, if we rewrite the expression using the imaginary unit:
√(-4x) = 2i√x
Now, let's raise this expression to the fourth power:
(2i√x)^4
To raise a complex number to the fourth power, we need to multiply it by itself four times:
(2i√x)^4 = (2i√x)(2i√x)(2i√x)(2i√x)
Simplifying this expression, we get:
(2i√x)(2i√x)(2i√x)(2i√x) = -16x²
Therefore, the result of the expression radical(-4x)^4 is -16x² in the context of complex numbers.
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Consider the basis b of mathbb r^2 consisting of vectors left begin array c 1 cr 1 end array right mbox and left begin array c 6 cr 6 end array right find vec x in mathbb r 2 whose coordinate vector relative to the basis b is vec x b left begin array c 6 cr 1 end array right
The condition that ensures a solution for the mentioned equation is :
1. b₂ = 2b₁ and 6b₁-3b₃ +b₄ = 0.
In mathematics, an equation is a formula that connects two expressions with the equal sign = to indicate that they are equal. An equation consists of two expressions joined by an equal sign ("="). Expressions for both sides of the equals sign are called the "left side" and the "right side" of the equation. Usually the right side of the equation is assumed to be zero. If this is accepted, it does not reduce the generality, since it can be done by subtracting the right side from the two sides.
According to the Question:
Given that:
x₁+ 2x₂= b₁ ------------------------- (1)
2x₁ + 4x₂ = b₂ ------------------------- (2)
3x₁ + 7x₂ = b₃ ------------------------ (3)
3x₁ + 9x₂ = b₄ ------------------------ (4)
From equation (1) and (2), we get:
b₂ = 2b₁
After analysis equation (1), we have:
6b₁-3b₃ +b₄ = 0
Using equation (1), (3) and (4), we get:
3(x₁+2x₂) -6(3x₁+7x₂) + 3x₁ + 9x₂ ≠ 0
Putting the value from equation (1),(3) and (4), we get:
6(x₁+2x₂) -3(3x₁+7x₂) + 3x₁ + 9x₂ = 0
Hence option (1) is correct.
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Complete Question:
Consider the following system of linear equations:
x₁+ 2x₂= b₁
2x₁ + 4x₂ = b₂
3x₁ + 7x₂ = b₃
3x₁ + 9x₂ = b₄
which one of the following conditions ensures that a solution exists for the above system.
1. b₂ = 2b₁ and 6b₁-3b₃ +b₄ = 0
2. b₃ = 2b₁ and 6b₁-3b₃ +b₄ = 0
3. b₂ = 2b₁ and 3b₁-6b₃ +b₄ = 0
4. b₃ = 2b₁ and 3b₁-6b₃ +b₄ = 0
find the exact value of the expression, if it is defined. (if an answer is undefined, enter undefined.) tan−1 tan 6
The exact value of the expression, if it is defined for tan−1 tan 6 = tan 6 = 6 radians.
To discover the exact fee of the expression tan (tan 6), we want to understand the homes of inverse tangent and tangent features and their courting.
The tangent characteristic (tan^(-1) x) relates the ratio of the sine and cosine of an angle. It has a periodicity of π radians, this means that its values repeat after every π radians. In other phrases, tan (x + nπ) = tan x, in which n is an integer.
The inverse tangent characteristic (tan^(-1) x), also known as arctan or atan, is the inverse of the tangent function. It takes a ratio as input and returns the perspective whose tangent is that ratio.
Now, allow's to analyze the expression tan^(-1) (tan 6). Since 6 radians is inside the first duration of the tangent characteristic (0 to π radians), tan 6 is defined and falls within the variety of values for which the inverse tangent function is described.
Since tan^(-1) (tan 6) is the inverse of the tangent function carried out to the value of tan 6, we will count on the expression to simplify to the unique enter attitude, that's 6 radians.
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in a simple frugal economy the consumption function is c = 200 0.8y, and exogenous desired investment is 100. equilibrium aggregate output/income (y*) for this economy is
The equilibrium aggregate output or income (y*) for this frugal economy is 1500.
In a simple frugal economy, the consumption function is given as c = 200 + 0.8y, where c represents consumption and y represents income. The exogenous desired investment is given as 100. To find the equilibrium aggregate output or income (y*), we need to equate the total output (Y) to the total expenditure (E) in the economy.
Y = C + I (where C represents consumption and I represents investment)
Substituting the values given in the problem, we get:
Y = (200 + 0.8y) + 100
Simplifying the equation, we get:
Y = 300 + 0.8y
Now, to find the equilibrium output or income, we need to solve for y such that Y = y.
Y = y
300 + 0.8y = y
Solving for y, we get:
y* = 1500
Therefore, the equilibrium aggregate output or income (y*) for this frugal economy is 1500.
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What expressions are equivalent to 8x+72
which ordered pairs are solutions to the equation 6x + 5y=5? a. (2,−7/5), b. (3,−13/5), c. (0,1), d. (7,5) e. none of the above
Answer:
[tex]a. \: (2. \frac{ - 7}{5} )[/tex]
Step-by-step explanation:
Greetings!!!!
To get the answer substitute these values that are given in the choices to the equation and crosscheck the expression.
[tex]6(2) + 5( \frac{ - 7}{5} ) = 5[/tex]
cancel out 5 by 5
[tex]12 - 7 = 5[/tex]
subtract 7 from 12
[tex]5 = 5[/tex]
If you have any questions tag it on comments
Hope it helps!!!!
find the area of the surface obtained by rotating the curve y=1 3x2 y=1 3x2 from x=0x=0 to x=4x=4 about the yy-axis.
The surface obtained by rotating the curve y=1/3x^2 from x=0 to x=4 about the y-axis can be found by using the formula for the surface area of a solid of revolution: S = 2π∫a^b f(x)√(1 + [f'(x)]^2) dx.
In this case, f(x) = 1/3x^2, so f'(x) = 2/3x. Substituting these into the formula, we get S = 2π∫0^4 (1/3x^2)√(1 + (2/3x)^2) dx. Evaluating this integral, we get S = (16/3)π(√13 - 1). Therefore, the area of the surface is (16/3)π(√13 - 1). To find the surface area, we first need to express the equation of the surface in terms of a function of x, since we are rotating the curve about the y-axis. To do this, we solve the equation y = 1/3x^2 for x in terms of y: x = √(3y). Next, we use the formula for the surface area of a solid of revolution, which involves integrating the function √(1 + [f'(x)]^2) over the interval of rotation. In this case, f(x) = 1/3x^2 and f'(x) = 2/3x. Substituting these into the formula and integrating over the interval x=0 to x=4, we get the formula S = 2π∫0^4 (1/3x^2)√(1 + (2/3x)^2) dx. Evaluating this integral, we get S = (16/3)π(√13 - 1), which is the surface area of the solid of revolution.
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Chris rented a truck for one day. There was a base fee of $15.99 , and there was an additional charge of 77 cents for each mile driven. Chris had to pay $234.67 when he returned the truck. For how many miles did he drive the truck?
Answer:
Chris drove the truck for 284 miles.
Step-by-step explanation:
Let us assume the total number of miles driven by Chris be [tex]x[/tex]. Now, as per the question, we can say that the sum of the base fee and the additional charge for each mile will be equal to the total rent that Chris will have to pay when he returns the truck. Next, we know that 1 cent = [tex]1/100[/tex] $. So, we have,
77 cents = 0.77 $
So, we can say that,
⇒[tex]15.99+0.77x=234.67[/tex]
⇒[tex]0.77x=234.67-15.99[/tex]
⇒[tex]0.77x=218.68[/tex]
⇒[tex]x=218.68/0.77[/tex]
⇒[tex]x=284[/tex]
Hence, Chris drove for a total of 284 miles when he returned the truck.
find the coordinate vector of a = 4 5 6 7 with respect to the basis = e22, e21, e12, e11 of m22.
The coordinate vector of a vector a = (4, 5, 6, 7) with respect to given basis of M22 is a column vector [x1, x2, x3, x4], where x1, x2, x3 , x4 are the coefficients of the linear combination of the basis vectors that gives a. That is,
a = x1 e22 + x2 e21 + x3 e12 + x4 e11
To find the coefficients xi, we solve the system of linear equations given by:
[ e22 | e21 | e12 | e11 ] [ x1 ] [ 4 ]
[ x2 ] = [ 5 ]
[ x3 ] [ 6 ]
[ x4 ] [ 7 ]
We can solve this system using row reduction:
[ e22 | e21 | e12 | e11 ] [ 1 0 0 0 ] [ 4 ].
[ 0 1 0 0 ] = [ 5 ]
[ 0 0 1 0 ] [ 6 ]
[ 0 0 0 1 ] [ 7 ]
Therefore, the coordinate vector of a with respect to the given basis is:
[x1, x2, x3, x4] = [4, 5, 6, 7]
In other words, a = 4 e22 + 5 e21 + 6 e12 + 7 e11.
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i need help bad please
Answer:
(1.5, 4), (2, 0.25)
Step-by-step explanation:
The question wants you to select the plotted points that are not within the group and wants them as an ordered pair. So we are going to type them in (x, y) format. The x-axis is the number of pounds and the y-axis is the price ($). Each tick on the x-axis seems to increase by 0.1 lbs. Each tick on the y-axis seems to increase by $0.25.
I see two pink spots that have ventured away from the rest of the crop (pun intended). The top spot is at 1.5 pounds and a cost of $4.00. This ordered pair would then be (1.5, 4). The bottom spot is at 2 pounds and a cost of $0.25. This ordered pair would then be (2, 0.25).
So in that box you are going to type: (1.5, 4), (2, 0.25)
If the program you are using has any rules about trailing zeros, make sure to follow those, because your answer could also technically be: (1.5, 4.00), (2, 0.25)