Answer:
5.62e-12 M
Explanation:
Since pH is concetration of H+
pOH is concentration of OH-
so 14-2.75= POH =11.25
and since 10^-PoH = concetration in Molarity
10^-11.25
5.62e-12
This element has an oxidation number of -3 and it has 16 neutrons. What element is this room made of
Answer: Element is P, phosphor
Explanation: Phosphor has oxidation number -III and it has 15 protons. So it is possible to have 16 neutrons. Other elements having oxidation number -III are N and As which can not have an isotope with 16 neutrons.
Use the amount (mol) of solute and amount (mol) of solvent to calculate the mole fraction. An aqueous solution of ethanol, CH3CH2OH, has a concentration of 0.216 mol/L and has a density of 0.996 g/mL. What are the mass percent and mole fraction of CH3CH2OH in this solution
Answer:
%m/m = 0.9975%
Xₐ = 0.0039
Explanation:
In order to do this, we need various data. First to all, we need tje molecular mass of the ethanol. this can be obtained in handbooks, or simply taking the atomic weights of carbon (12 g/mol), Hydrogen (1 g/mol) and oxygen (16 g/mol) and summing those values:
MM C₂H₆O = (2*12) + (6*1) + (16*1) = 46 g/mol
Now, there is an expression that is commonly used to determine the molarity of a solution given the mass percent and density, and assuming of course, 1 liter of solution:
M = d * %m/m * 1000 / MM * 100 (1)
From here, we can solve for %m/m:
%m/m = M * MM * 100 / d * 1000
As the problem is not saying the volume of solution, we can easily assume we have 1 liter of solution. Therefore, the %m/m replacing the given data is:
%m/m = 0.216 *46 * 100 / 0.996 * 1000
%m/m = 0.9975%To get the mole fraction, we first need to get the volume of solvent. From the density, we can get the mass of solution:
m = V * d
m = 1000 * 0.996 = 996 g of solution.
The mass of solute is:
m = 0.216 mol/L * 46 g/mol
m = 9.936 g/L, or simply we have 9.936 g of ethanol in 1 L of solution.
The mass of solvent:
solvent = 996 - 9.936 = 986.064 g
The molecular mass of water, so we can get the moles is 18 g/mol so:
moles water = 986.064 / 18 = 54.78
Finally the mole fraction:
Xₐ = 0.216 / (0.216 + 54.78)
Xₐ = 0.0039Hope this helps
What are two benefits of scientists using a diagram to model the water cycle?
A. It can show changes that occur in many different parts of Earth at
the same time.
B. It can be used to show how the parts of the cycle relate to one
another.
C. Only a few factors in the water cycle can be shown on the
diagram.
I D. It can be used to show as much detail as is present in the actual
water cycle.
whats the chemical equation for gypsum (made from Cacl2·2H20 and H2SO4)
1A: Consider these compounds:
A. PbF2
B. Ni(CN)2
C. FeS
D. CaSO4
Complete the following statements by entering the letter(s) corresponding to the correct compound(s). (If more than one compound fits the description, include all the relevant compounds by writing your answer as a string of characters without punctuation, e.g, ABC.)
Without doing any calculations it is possible to determine that magnesium hydroxide is more soluble than __________, and magnesium hydroxide is less soluble than _______.
It is not possible to determine whether magnesium hydroxide is more or less soluble than_______ by simply comparing Ksp values.
1B: For each of the salts on the left, match the salts on the right that can be compared directly, using Ksp values, to estimate solubilities.
(If more than one salt on the right can be directly compared, include all the relevant salts by writing your answer as a string of characters without punctuation, e.g, ABC.)
1. nickel(II) hydroxide
A. Fe(OH)2
2. silver chloride
B. PbS
C. AlPO4
D. MnS
Write the expression for K in terms of the solubility, s, for each salt, when dissolved in water.
nickel(II) hydroxide
silver chloride
Ksp=_______
Ksp=________
Note: Multiply out any number and put it first in the Ksp expression. Combine all exponents for s.
Solution :
Compound Ksp
[tex]$PbF_2$[/tex] [tex]$3.3 \times 10^{-8}$[/tex]
[tex]$Ni(CN)_2$[/tex] [tex]$3 \times 10^{-23}$[/tex]
FeS [tex]$8 \times 10^{-19}$[/tex]
[tex]$CaSO_4$[/tex] [tex]$4.93 \times 10^{-5}$[/tex]
[tex]$Mg(OH)_2$[/tex] [tex]$5.61 \times 10^{-12}$[/tex]
Ksp of [tex]$Ni(CN)_2 << Ksp \text{ of}\ \ Mg(OH)_2$[/tex] and both compounds dissociate the same way. Hence [tex]$Mg(OH)_2$[/tex] is more soluble than [tex]$(B). \ Ni(CN)_2$[/tex]
[tex]$Mg(OH)_2$[/tex] is less soluble than [tex]$(A). \ \ PbF_2 \ ()Ksp \ PbF_2 > Ksp \ \text{ of } \ Mg(OH)_2$[/tex]
It is not possible to determine CD - [tex]$FeS \text{ or} \ CaSO_4$[/tex] is more or less soluble than [tex]$Mg(OH)_2$[/tex] as though they have a different Ksp values their molecular dissociation is also different and they may have a close solubility values.
[tex]$Ni(OH)_2$[/tex] can be directly compared with PbS, [tex]$AlPO_4, MnS$[/tex]
[tex]$\text{For } \ Ni(OH)_2$[/tex]
[tex]$AB_2(s) \rightarrow A^{2+} + 2B^{-}$[/tex]
[tex]$Ni(OH)_2(s) \rightarrow Ni^{2+} + 2OH^-$[/tex]
100
1-s s 2s
Ksp = [tex][A2+][B-]^2 = s \times (2s)^2 = 4s^3[/tex]
Hence they can be directly compared by Ksp values, smaller the Ksp, smaller the solubility.
For Silver Chloride
[tex]$AB(s) \rightarrow A^{x+}+B^{x-}$[/tex]
[tex]$AgCl(s) \rightarrow Ag^+ + Cl^-$[/tex]
1 0 0
1 - s s s
Ksp [tex]$=[A^{x+}][B^{x-}]=s \times s = s^2$[/tex]
Hence, they can be directly compared by Ksp values, smaller the Ksp, smaller the solubility.
Describe the environment of Antarctica.
Answer:
Antarctica is a desert. It does not rain or snow a lot there. When it snows, the snow does not melt and builds up over many years to make large, thick sheets of ice, called ice sheets.
Explanation:
Matter is anything that takes up space and hasA)mass.B)color.C)length.D)length and width
Answer:
A. Mass
Explanation:
If it takes up space it has to have mass. Not everything that is matter has a color, certain length or width.
if someone spilled 750. mL of said sulfuric acid how many Liters of 6.00 M aluminum hydroxide would we need to neutralize it?
Answer:
5
Explanation:
when does y’all’s summer start? I really curious bc mine start at may 16 when it usually start at may 26 ?
Answer:
we dont have summer breaks here
What's the balanced chemical equation for sodium azide + water?
Select the element(s) that will have ONE unpaired electron in the p orbital.
Ca
N
B
Ar
Br
Answer: The element B will have ONE unpaired electron in the p orbital.
Explanation:
The electronic configuration of each given element is as follows.
Atomic number of calcium (Ca) is 20.
Ca: [tex]1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 4s^{2}[/tex]
Atomic number of nitrogen (N) is 7.
N: [tex]1s^{2} 2s^{2} 2p^{3}[/tex]
Atomic number of boron (B) is 5.
B: [tex]1s^{2} 2s^{2} 2p^{1}[/tex]
Atomic number of argon (Ar) is 18.
Ar: [tex]1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6}[/tex]
Atomic number of bromine (Br) is 35.
Br: [tex][Ar] 4s^{2} 3d^{10} 4p^{5}[/tex]
Therefore, boron is the only element that have one unpaired electron in the p-orbital.
Thus, we can conclude that element B will have ONE unpaired electron in the p orbital.
Chloral, Cl3C―CH═O, reacts with water to form the sedative and hypnotic agent chloral hydrate, Cl3C―CH(OH)2. Draw Lewis structures for each of these substances. Draw them in decreasing molecular weight from left to right.
Answer:
See attached figure.
Explanation:
Hello there!
In this case, according to the given substances, we recall the concept of Lewis structure as such showing the bonds and valence electrons each atom has in the molecule. Thus, since chlorine atoms have seven valence electrons, carbon atoms four of them, hydrogen atoms have 1 and oxygen atoms 6, we are able to draw such Lewis dot structures, by obeying the octet as shown on the attached figure.
Best regards!
Question 32 (2 points)
Kepler's laws about the solar system
Question 32 options:
describe why objects in space behave in a certain way
can be changed on the basis of new data and experimentation
prove that theories on space are non-testable
explain what happens in nature under certain conditions
Answer: Describe why objects in space behave in a certain way
Explanation: Got it right on the test
Answer:b
Explanation:test
Use Hess’s Law to calculate the heat of reaction for the following reaction:
2H2O2 → 2H2O +O2 ∆H=?
2H2 +O2 → 2H2O ∆H=-572 KJ
2H2O2 → 2H2 + 2O2 ∆H=376 KJ
The heat of reaction for the reaction 2H₂O₂ → 2H₂O +O₂ is -196 KJ
Calculating heat of reaction using Hess's lawFrom the question, we are to calculate the heat of reaction for the reaction
2H₂O₂ → 2H₂O +O₂ ∆H=?
Using Hess's law
Hess's Law of constant heat summation states that regardless of the multiple stages or steps of a reaction, the total enthalpy change for the reaction is the sum of all changes
From the given equations,
2H₂ +O₂ → 2H₂O ∆H= -572 KJ ---------- (1)
2H₂O₂ → 2H₂ + 2O₂ ∆H= 376 KJ ----------- (2)
Adding equations (1) and (2), we get
2H₂O₂ → 2H₂O +O₂ ∆H= -572 KJ + 376 KJ
2H₂O₂ → 2H₂O +O₂ ∆H= -196 KJ
Hence, the heat of reaction for the reaction 2H₂O₂ → 2H₂O +O₂ is -196 KJ.
Learn more on Calculating heat of reaction using Hess's law here: https://brainly.com/question/26491956
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Which refers to the distance between two crests or two troughs on a transverse wave?
wavelength
amplitude
frequency
hertz
Answer:
wavelength
Explanation:
it is the distance between two crests ot two troughs
ajhsggsgvsbnsnnsnwbwbsbsvsccsvsbsbnsbwvvvdsvbs
Answer:
thank uuuuuuu for freeeee pointssssss!!!!!..
Explanation:
hope it is helpful to you
A saline solution has 1.9 grams of NaCI in 100 mL of solution. Calculate the molarity
Answer: Molality = concentration = 0,33 mol/l
Explanation: Concentration c = n/V and n = m/M
M = 55,44 g/mol and m = 1.9 g , V = 0.100 l
c = m/(MV)
1) A container holds 5,000 mL of CO2 at 742 atm. What will be the volume of the CO2 if the pressure is increased to 795 atm?
Answer:
[tex]V_2=4667mL[/tex]
Explanation:
Hello there!
In this case, based on the given information, it is possible for us to provide an answer to this question by using the Boyle's law as directly proportional relationship between volume and pressure:
[tex]P_2V_2=P_1V_1[/tex]
Thus, by solving for the final volume, V2, as required, we obtain the following:
[tex]V_2=\frac{P_1V_1}{P_2} \\\\V_2=\frac{5,000mL*742atm}{795atm}\\\\V_2=4667mL[/tex]
Regards!
N2O3 → N2 + O2
Name the reactants in this reaction.
Name the products in this reaction.
[tex]\text{N}_{2}\text{O}_{3}=\text{nitrogen trioxide}\\\text{N}_{2}=\text{nitrogen}\\\text{O}_{2}=\text{oxygen}[/tex]
4. Balance the following equation. Then determine the number of mols of Nitrogen formed given the values in a,b and c.
NH3 + O2 → N2 + H2O
a. 4 mol NH3
b. 4 mol N2
c. 4.5 mol O2
Answer:
4NH3 + 3O2 → 2N2 + 6H2O
a. 2 moles
b. 4 moles
c. 3 moles
Explanation:
a. 4 mol NH3
4NH3 + 3O2 → 2N2 + 6H2O
4 : 3 : 2 : 6
4 (mol)
⇒[tex]n_{N2}[/tex] = 4 × 2 ÷ 4 = 2
b. 4 mol N2
c. 4.5 mol O2
4NH3 + 3O2 → 2N2 + 6H2O
4 : 3 : 2 : 6
4.5 (mol)
⇒[tex]n_{N2}[/tex] = 4.5 × 2 ÷ 3 = 3
Convert 5,500 mg to kg. Show your work to receive full credit.
What is the freezing point in °C) of a 0.743 m
aqueous solution of KCI?
Enter your rounded answer with
3 decimal places.
Answer:
-0.276 Degrees C
Explanation:
kf of water is 1.86
Freezing point depression= m x kf x i
i= ions present ( K+ Cl-) 1=2
1.86x2X.743= .276
Since its freezinf point depression the freezing point will lower
so
0-.276= -.276
Answer: -2.764
Explanation:
How many grams of chlorine gas are needed to make 5.20 x 100 g of a solution that is 2.00 ppm chlorine by mass?
mass:
CI,
Answer:
mass of chlorine = 10.4 grams
Explanation:
Mass of the solution = 5.20 × 10⁶ g
ppm chlorine by mass = 2.00
Recall that:
[tex]ppm = \dfrac{mass \ of \ chorine \ gas (solute)}{ mass of the solution }\times 10^6[/tex]
[tex]2 = \dfrac{mass \ of \ chorine \ gas (solute)}{ 5.20\times 10^6}\times 10^6[/tex]
mass of chlorine = 5.20 × 2.0
mass of chlorine = 10.4 grams
Empirical formula of C6H10O6
Answer:
I don't know.
Explanation:
I actually don't know the answer so I wrote the answer is "I don't know" or simply "I dunno".
opinion on the usage of identification of amine in daily life (medical, agriculture,etc)
Answer:
The usage is explained below
Explanation:
Amines are identified from the use of the hinsberg reaction whereby the amine is mixed well with Hinsberg reagent and done in the presence of an aqueous alkali. In this reaction, the amine will attack the electrophile which will result in the chloride being displaced and the amides being generated.
The uses of identification of amines in daily life are;
- In agriculture, it serves as a good source of making herbicides as well as acting as emulsifiers.
- In medicine, it is used in the manufacture of some popular pain killers like demerol and morphine.
- In medicine, it is used in the manufacture of an anesthetic drug known as novocaine.
- In chemical industries, amines are used as lubricating oils and also as corrosion inhibitors in boilers.
Consider the following reactants:
BeCl2(aq) + 2AgNO3(aq) →
A. Predict the products and write the balanced equation.
B. Identify the type of reaction and explain your answer.
Answer: (a) The products are [tex]Be(NO_{3})_{2}[/tex] and AgCl. The balanced equation is [tex]BeCl_{2}(aq) + 2AgNO_{3}(aq) \rightarrow Be(NO_{3})_{2}(aq) + 2AgCl(s)[/tex].
(b) The type of reaction is double displacement reaction.
Explanation:
(a) The complete reaction equation will be as follows.
[tex]BeCl_{2}(aq) + 2AgNO_{3}(aq) \rightarrow Be(NO_{3})_{2}(aq) + 2AgCl(s)[/tex]
Number of atoms on reactant side are as follows.
Be = 1Cl = 2Ag = 2[tex]NO_{3}[/tex] = 2Number of atoms present on product side are as follows.
Be = 1Cl = 2Ag = 2[tex]NO_{3}[/tex] = 2Here, number of atoms on both reactant and product side are the same. Hence, it is a balanced chemical equation.
(b) A reaction in which two reactant species tend to change their ions with each other and form new compounds. This type of reaction is called double displacement reaction.
As the given reaction is as follows.
[tex]BeCl_{2}(aq) + 2AgNO_{3}(aq) \rightarrow Be(NO_{3})_{2}(aq) + 2AgCl(s)[/tex]
This shows that ions are being exchanges by the reactants [tex]BeCl_{2}[/tex] and
[tex]AgNO_{3}[/tex]. The ions are [tex]Be^{2+}[/tex], [tex]Cl^{-}[/tex], [tex]Ag^{2+}[/tex] and [tex]NO^{2-}_{3}[/tex].
Therefore, this reaction is a double displacement reaction.
We can also perform a similar calculation for the mass defect and binding energy for nuclear reactions using the masses of the atoms and any other atomic particles that are part of the reaction. With this in mind, calculate the mass defect in amu and kg, and binding energy in J for the reaction of 1 neutron with U-235 to produce Te-137, Zr-97, and some neutrons. Balance the nuclear equation first before proceeding.
U-235 = 235.04393 amu, 01n = 1.00867 amu, Te-137 = 136.92532 amu, Zr-97 = 96.91095 amu
Boron-10 undergoes fission via thermal neutron capture of a single neutron to produce lithium-7, an alpha particle, and energy. Write a balanced nuclear equation, and then calculate the mass defect in amu and kg, and binding energy in J.
B-10 = 10.01294 amu, 01n = 1.00867 amu, Li-7 = 7.01600 amu, α (He-4) = 4.00260 amu
Answer:
See Explanation
Explanation:
[tex]\frac{235}{92} U + \frac{1}{0} n ---->\frac{137}{52} Te + \frac{97}{40} Zr +2\frac{1}{0} n[/tex]
Hence the mass defect is;
[235.04393 + 1.00867] - [ 136.92532 + 96.91095 + 2(1.00867)]
= 236.0526 - 235.85361
= 0.19899 amu
Since 1 amu = 1.66 * 10^-27 Kg
0.19899 amu = 0.19899 * 1.66 * 10^-27 = 3.3 * 10^-28 Kg
Binding energy = Δmc^2
Binding energy = 3.3 * 10^-28 Kg * (3 * 10^8)^2 = 2.97 * 10^-11 J
ii) [tex]\frac{10}{5}B + \frac{1}{0}n-----> \frac{7}{3} Li + \frac{4}{2} He + Energy[/tex]
Hence the mass defect is;
[10.01294 + 1.00867] - [7.01600 + 4.00260]
= 11.02161 - 11.0186
= 0.00301 amu
Since 1 amu = 1.66 * 10^-27 Kg
0.00301 amu = 0.00301 * 1.66 * 10^-27 = 4.997 * 10^-30 Kg
Binding energy = Δmc^2
Binding energy = 4.997 * 10^-30 Kg * (3 * 10^8)^2 = 4.5 * 10^-13 J
Choose the function whose graph is given by:
A. y = cos x-2
B. y = cos(x - 2)
C. y = sin x + 1
D. y = cos x-1
Which of the following is most accurate regarding the water cycle
Answer:
Is this question multiple choice if it is i can most likely answer it!
Explanation: