find the length of the spiral r=2θ^2 for 0≤θ≤sqrt(21)

Answer:

576 (square yards)

Step-by-step explanation:

length of slanted height of triangle = √(6² + 8²)

= √100

= 10.

surface area = area of 2 triangle faces + area of 3 lengths

= 2 (1/2 X 12 X 8) + 3 (10 X 16)

= 576 (square yards)

The quadratic function f(x) = x² + 10x + 37 from standard form to vertex form is f(x) = (x + 5)² + 12

From the question, we have the following parameters that can be used in our computation:

f(x) = x² + 10x + 37

The above quadratic function is its standard form

f(x) = ax² + bx + c

Start by calculating the axis of symmetry using

h = -b/2a

So, we have

h = -10/2

h = -5

Next, we have

f(-5) = (-5)² + 10(-5) + 37

k = 12

The vertex form is then represented as

f(x) = a(x - h)² + k

So, we have

f(x) = (x + 5)² + 12

Hence, the vertex form is f(x) = (x + 5)² + 12

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Answer:

4 pizzas

Step-by-step explanation:

first of all, subtract parking fee from total:

52 - 4 = 48.

now divide by 12:

48/12

4.

so he he pays for 4 pizzas at $12 each (4 X 12 = 48).

and he pays $4 for parking.

48 + 4 = 52.

Answer:

To transform the graph of f(x)=x√ into g(x)=x+9, we need to apply a horizontal shift to the right by 9 units. This can be done by replacing x in f(x) with x-9 to get g(x)=(x-9)√. The resulting graph will be the same as the graph of f(x), but shifted 9 units to the right.

The value of the definite integral (3x-4)²dx is (3b³ - 12b² + 16b + C) - (3a³ - 12a² + 16a + C), since the limits are not mentioned.

To evaluate the definite integral of (3x-4)² dx, we first need to expand the expression and then find the antiderivative. Finally, we need to apply the limits of integration if they are provided.

Expanding the expression:

(3x-4)² = 9x² - 24x + 16
Finding the antiderivative:

∫(9x² - 24x + 16) dx = 3x³ - 12x² + 16x + C
Now, if we have limits of integration (a, b), we would evaluate the antiderivative at those points and subtract the results:
F(b) - F(a) =[tex](3b^3 - 12b^2[/tex] [tex]+ 16b + C[/tex]) - [tex](3a^3 - 12a^2 + 16a + C)[/tex]
However, since no limits of integration were provided, we cannot evaluate the definite integral further.

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Answer:

11/6

Step-by-step explanation:

For the reciprocal just flip it

The product of (five to the -1st power) and (five to the -3rd power) can be calculated using the properties of exponents. So, the product of (five to the -1st power) and (five to the -3rd power) is equal to 1/625.

When multiplying two expressions with the same base (in this case, five) and different exponents, you can simply add the exponents together. So, for this problem, you will add the exponents -1 and -3, resulting in an exponent of -4.

Therefore, the product of (five to the -1st power) and (five to the -3rd power) is equal to five to the -4th power. To express this as a positive exponent, you can rewrite it as a fraction with the exponent in the denominator: 1/(five to the 4th power). Now, calculate the value: 1/(5^4) = 1/625.

In conclusion, the product of (five to the -1st power) and (five to the -3rd power) is equal to 1/625.

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The Taylor polynomial t3(x) for the function f(x) = xe−7x centered at a is:

t3(x) = f(a) + f'(a)(x-a) + f''(a)(x-a)2/2! + f'''(a)(x-a)3/3!

To find the Taylor polynomial t3(x), we need to compute the first three derivatives of f(x):

f(x) = xe−7x

f'(x) = e−7x − 7xe−7x

f''(x) = 49xe−7x − 14e−7x

f'''(x) = −343xe−7x + 147e−7x

Next, we evaluate these derivatives at x = a and simplify:

f(a) = ae−7a

f'(a) = e−7a − 7ae−7a

f''(a) = 49ae−7a − 14e−7a

f'''(a) = −343ae−7a + 147e−7a

Now, we plug these values into the formula for t3(x):

t3(x) = ae−7a + (e−7a − 7ae−7a)(x-a) + (49ae−7a − 14e−7a)(x-a)2/2! + (−343ae−7a + 147e−7a)(x-a)3/3!

We can simplify this expression to obtain the final form of t3(x):

t3(x) = ae−7a + (x-a)e−7a(1-7(x-a)) + (x-a)2e−7a(49a-7) + (x-a)3e−7a(-343a+147)/6

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The cost of a CD is $5.94 more than the cost of a DVD. Let's assume that the cost of a DVD is "x" dollars, then the cost of a CD is "x+5.94" dollars.

Using this information, we can write the following equations:

5(x+5.94) + 2x = 113.63 (cost of 5 CDs and 2 DVDs)

6(x+5.94) + 2x = ? (cost of 6 CDs and 2 DVDs)

Solving the first equation for "x", we get x = 12.21. Substituting this value in the second equation, we get the cost of 6 CDs and 2 DVDs as $83.64.

Therefore, the cost of 6 CDs and 2 DVDs would be $83.64 at All Bets Are Off Electronics if 5 CDs and 2 DVDs cost $113.63, and CDs cost $5.94 more than DVDs.

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Answer:

z = 56

Step-by-step explanation:

124 and Z form a straight line so they will add to 180

124+z = 180

z = 180-124

z = 56

Answer:

z = 56°

Step-by-step explanation:

We know that vertically opposite angles are equal.

∴ y = 124°

We know that angles in a straight line are added up to 180°.

∴ y + z = 180

124 + z = 180

z = 180 - 124

z = 56°

x = 56° ( vertically opposite angles ⇒ x = z )

Answer:

A. 24 inches

Step-by-step explanation:

A cube is defined by having all three lengths being of equal size,

[tex]V = L^3[/tex]

so to find length from the volume of a cube, you must take the cube root of the volume.

[tex]\sqrt[3]{V} = L[/tex]

[tex]\sqrt[3]{216} = 6[/tex]

That means each side of the cube has a length of 6 inches.

The formula for the perimeter is give below the cube diagram.

[tex]P = 4L[/tex]

Which means we just take the length we found above and multiply it by 4.

[tex]4*6 =24[/tex] inches

Therefore 24 inches is your answer.

Answer: y=−(x−5/2)^2−3/4

The decimal form of the given number which is 5 3/4 is 5.75.

Given number = 5 3/4.

The given number is a fractional number, which is looking like a mixed fraction.

To write the mixed fraction into decimal form first, we have to write it into normal fraction, later we divide it to get the required decimal form.

To convert mixed fraction into normal fraction,

5 3/4 = ((4*5) + 3) / 4 = 23/4

So, the fraction is 23/4.

To convert the fraction into a decimal, we have to divide the numerator by the denominator as shown below,

23/4 = 5.75

From the above analysis, we can conclude that the decimal form of 5 3/4 is 5.75.

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The three additional points on the line are (9, 4), (12, 3) and (15, 2)

From the question, we have the following parameters that can be used in our computation:

(3, 6) and (6, 5)

From the above, we can see that

As x increases by 3, the value of y decreases by 1

This means that the slope of the line is -1/3

Also, we can use the following transformation rule to generate the other points

(x + 3, y - 1)

When used, we have

(9, 4), (12, 3) and (15, 2)

Hence, the three additional points on the line are (9, 4), (12, 3) and (15, 2)

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The equations of the lines with the given gradients and points are:

1. y = -3x + 16

2. y = -5x + 5

3. y = 4x - 20

To find the equation of a line given its gradient and a point it passes through, we can use the point-slope form of a linear equation:

y - y₁ = m(x - x₁),

where (x₁, y₁) represents the given point and m represents the gradient.

Let's calculate the equations for each given gradient and point:

1. Gradient = -3, Point Q(4,4):

Using the point-slope form:

y - 4 = -3(x - 4)

y - 4 = -3x + 12

y = -3x + 16

2. Gradient = -5, Point P(0,5):

Using the point-slope form:

y - 5 = -5(x - 0)

y - 5 = -5x

y = -5x + 5

3. Gradient = 4, Point A(6,4):

Using the point-slope form:

y - 4 = 4(x - 6)

y - 4 = 4x - 24

y = 4x - 20

Therefore, the equations of the lines with the given gradients and points are:

1. y = -3x + 16

2. y = -5x + 5

3. y = 4x - 20

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The perimeter of the isosceles trapezoid is equal to 456 feet which makes the option c correct.

This is a trapezoid in which the base angles are equal and therefore the left and right side lengths are also equal. The opposite angles are supplementary which implies they sum up to 180°.

We shall first find the length of the left and right sides which are of same length as follows:

3x - 2 = 2x + 3

3x - 2x = 3 + 2

x = 5

PQ = 6(25) - 10 = 140

QR = 3(25) - 22 = 53

RS = 9(25) - 15 = 210

PS = 2(25) + 3 = 53

perimeter of the Isosceles trapezoid = 140ft + 53ft + 210ft + 53ft

perimeter of the Isosceles trapezoid = 456ft.

Therefore, the perimeter of the isosceles trapezoid is equal to 456 feet which makes the option c correct.

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The first partial derivatives of f(x,y) at the point (3,1) are:
∂f/∂x(3,1) = 3
∂f/∂y(3,1) = -12

To find the first partial derivatives of f(x,y) at the point (3,1), we need to find the partial derivative with respect to x and y, respectively, and then substitute x=3 and y=1.

So, let's begin with the partial derivative with respect to x:
∂f/∂x = 3 - 0  (since the derivative of 3x with respect to x is 3, and the derivative of 4y with respect to x is 0)

Now, we can substitute x=3 and y=1 into this expression:
∂f/∂x(3,1) = 3 - 0 = 3

So, the partial derivative of f(x,y) with respect to x at the point (3,1) is 3.

Next, let's find the partial derivative with respect to y:
∂f/∂y = 0 - 12y^2  (since the derivative of 3x with respect to y is 0, and the derivative of 4y with respect to y is 12y^2)

Now, we can substitute x=3 and y=1 into this expression:
∂f/∂y(3,1) = 0 - 12(1)^2 = -12

So, the partial derivative of f(x,y) with respect to y at the point (3,1) is -12.

Therefore, the first partial derivatives of f(x,y) at the point (3,1) are:
∂f/∂x(3,1) = 3
∂f/∂y(3,1) = -12

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The composite function is c(x(t)) = 3(2-6t)^2 - 7, and its derivative with respect to t is dc/dt = -72 + 216t.

To write the composite function, we substitute the expression for x(t) into c(x), giving c(x(t)) = 3(2-6t)^2 - 7.

To find the derivative of this composite function with respect to t, we use the chain rule:

dc/dt = (dc/dx) * (dx/dt)

where (dc/dx) is the derivative of c(x) with respect to x, and (dx/dt) is the derivative of x(t) with respect to t.

Taking the derivative of c(x) = 3x^2 - 7 with respect to x, we get:

dc/dx = 6x

And taking the derivative of x(t) = 2 - 6t with respect to t, we get:

dx/dt = -6

Substituting these values into the chain rule formula, we get:

dc/dt = (6x) * (-6)

Since x(t) = 2-6t, we can substitute that expression for x to get:

dc/dt = (6(2-6t)) * (-6)

Simplifying, we get:

dc/dt = -72 + 216t

So the composite function is c(x(t)) = 3(2-6t)^2 - 7, and its derivative with respect to t is dc/dt = -72 + 216t.

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The probability that Ali misses 4 shots out of 25, given that he has a 3-point shooting percentage of 9/10 or 0.9, is approximately 0.1394, or about 13.94%.

The probability of an event occurring is defined by probability. There are numerous real-life scenarios in which we must forecast the outcome of an occurrence.

We can use the binomial distribution to find the probability that Ali misses 4 shots out of 25, given that he has a 3-point shooting percentage of 9/10 or 0.9.

Let X be the number of missed shots out of 25 attempts. Since each shot is either a miss or a make, this is a binomial distribution with n = 25 and p = 1 - 9/10 = 1/10. We want to find P(X = 4), which is:

P(X = 4) = (25 choose 4) * (1/10)⁴ * (9/10)²¹

where "25 choose 4" is the number of ways to choose 4 shots out of 25.

Using a calculator, we can evaluate this expression to find:

P(X = 4) ≈ 0.1394

Therefore, the probability that Ali misses 4 shots out of 25, given that he has a 3-point shooting percentage of 9/10 or 0.9, is approximately 0.1394, or about 13.94%.

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Answer:

Hi,so since this is a triangle with a right angle and that equals to 90 degrees

so we have found our second number.

The sum of angles in a triangle is 180 degrees

so that would be 27+90+x=180

i.e 117 +x =180

solve equation i.e 180 -117=63

therefore x=63 degrees

hope this was helpful

Answer:

90+27+63=180

so the answer is:

X= 63

Answer:

  -1572864

Step-by-step explanation:

You want the 19th term of the geometric sequence with first term -6 and common ratio -2.

The n-th term of a geometric sequence is ...

  an = a1·r^(n-1)

where a1 is the first term, and r is the common ratio.

Using the given values of a1 and r, the 19th term is ...

  a19 = (-6)·(-2)^(19-1) = -1572864

<95141404393>

Answer:

-35.375

Step-by-step explanation:

(-1.5+9.5)=8

5/8 =0.625

7+11=18

0.4*18=36/5

=7.2

7.2/-0.2=

-283/8=

-35.375

We can conclude that the left-hand side (AU (BoC) - (AUB) A (AUC)) and the right-hand side (∅) have no common elements, which proves the equality AU (BoC) - (AUB) A (AUC) = ∅.

To prove the equality AU (BoC) - (AUB) A (AUC) = ∅, we need to show that the left-hand side is an empty set.

First, let's break down the expression step by step:

AU (BoC) represents the union of A with the intersection of B and C. This implies that any element in A, or in both B and C, will be included.

(AUB) represents the union of A and B, which includes all elements present in either A or B.

(AUC) represents the union of A and C, which includes all elements present in either A or C.

Now, let's analyze the right-hand side:

(AUB) A (AUC) represents the intersection of (AUB) and (AUC), which includes elements that are common to both sets.

To prove the equality, we need to show that the left-hand side and the right-hand side have no common elements, i.e., their intersection is empty.

If an element belongs to the left-hand side (AU (BoC) - (AUB) A (AUC)), it must either belong to A and not belong to (AUB) A (AUC), or it must belong to (BoC) and not belong to (AUB) A (AUC).

However, if an element belongs to (BoC), it implies that it belongs to both B and C. Since it does not belong to (AUB) A (AUC), it means that it cannot belong to either A or B or C. Similarly, if an element belongs to A, it cannot belong to (AUB) A (AUC).

Therefore, we can conclude that the left-hand side (AU (BoC) - (AUB) A (AUC)) and the right-hand side (∅) have no common elements, which proves the equality AU (BoC) - (AUB) A (AUC) = ∅.

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(a) Polar coordinate r for P, with r>0 and ?<θ<3π/2 is r=7cos(π/4-θ). (b) Cartesian coordinates for point P are (x,y)=(-7cos(π/4-θ),-7sin(π/4-θ)). (c) The curve passes through the origin twice when 0<θ<2π.

(a) To find r for P, we plug in θ=16π/14 into r=7(2cosθ) and simplify using the identity cos(π/4-θ)=cos(π/4)cos(θ)+sin(π/4)sin(θ)=√2/2(cos(θ)+sin(θ)) to obtain r=7cos(π/4-θ).

(b) To convert from polar to Cartesian coordinates, we use the formulas x=r cos(θ) and y=r sin(θ) and plug in r=7cos(π/4-θ) to get x=-7cos(π/4-θ) and y=-7sin(π/4-θ).

(c) The curve passes through the origin when r=0, which occurs when θ=π/2 and θ=3π/2. Since 0<θ<2π covers each θ value exactly once, the curve passes through the origin twice.

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A certain states might not be visited at all while collecting the Statistics. Statistics for certain states might be visited much less often than others leading to very noisy estimates.

Certain states might not be visited at all while collecting the statistics: In the described manner of estimation, there is a possibility that some states may not be visited during the data collection process. This can result in incomplete or biased estimates if those unvisited states have unique characteristics or play an important role in the overall analysis.

Estimates for certain states might be visited much less often than others leading to very noisy estimates: If the data collection process is not balanced or systematic, certain states may be visited less frequently compared to others. As a result, the estimates for these states could be less reliable and prone to higher levels of uncertainty, leading to noisy or inconsistent results.

Therefore, the correct options are:

Certain states might not be visited at all while collecting the statistics.

Estimates for certain states might be visited much less often than others leading to very noisy estimates.

It is likely that certain states might not be visited at all or may be visited much less frequently than others while collecting statistics, leading to very noisy estimates. This is known as the problem of "sparse data." Therefore, the correct options are:

Certain states might not be visited at all while collecting the statistics.

Statistics for certain states might be visited much less often than others leading to very noisy estimates.

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The car travels 1.40 meters in 0.187 seconds before coming to a stop. To answer this question, we need to use the equation of motion: v(t) = v0 + at where v(t) is the velocity at time t, v0 is the initial velocity, a is the acceleration, and t is the time.

(a) To find how much time it takes for the car to stop, we need to find the time when v(t) = 0. Using the given values, we have:

0 = 15 - 80.2t

Solving for t, we get:

t = 15/80.2 = 0.187 seconds

Therefore, it takes the car 0.187 seconds to stop.

(b) To find how far the car travels in this time, we can use the equation:

d(t) = v0t + 0.5at^2

Substituting the given values, we get:

d(t) = 15(0.187) + 0.5(-80.2)(0.187)^2

Simplifying, we get:

d(t) = 1.40 meters

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The expected frequency is 50 hence, the answer is (d) 50.

Expected frequency is the frequency we would expect to see in a particular category or group if the null hypothesis is true. The null hypothesis assumes a specific distribution or pattern in the data, and the expected frequency is calculated based on that assumption.

Here we have

Individuals in a random sample of 150 were asked whether they supported capital punishment.

If the opinions of the individuals are uniformly distributed, then the expected frequency for each group would be the same.

Since there are three groups (yes, no, and no opinion), the expected frequency for each group is:

Expected frequency = Total frequency / Number of groups

= 150/3 = 50

Therefore,

The expected frequency is 50 hence, the answer is (d) 50.

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The phasor method involves converting the sinusoidal functions into phasors, which are complex numbers representing the amplitude and phase of the sinusoidal function. The phasor for a sinusoidal function y = A sin(ωt + φ) is A e^(iφ), where A is the amplitude and φ is the phase angle.

(a) To find the amplitude of y, we need to add the phasors of y1, y2, and y3. The phasor for y1 is 11 e^(i0) = 11, the phasor for y2 is 21 e^(i30°), and the phasor for y3 is 7.0 e^(-i50°). Therefore, the phasor for y is:

Y = 11 + 21 e^(i30°) + 7.0 e^(-i50°)

To find the amplitude of Y, we can take the magnitude of this phasor:

|Y| = sqrt[(11)^2 + (21)^2 + (7.0)^2] = 24.2

Therefore, the amplitude of y is 24.2.

(b) To find the phase constant of y, we need to find the angle that the phasor Y makes with the positive real axis. We can write the phasor Y in rectangular form:

Y = (11 + 21 cos 30° - 7.0 cos 50°) + (21 sin 30° - 7.0 sin 50°) i

The angle that the phasor Y makes with the positive real axis is:

tan^(-1)[(21 sin 30° - 7.0 sin 50°) / (11 + 21 cos 30° - 7.0 cos 50°)]

Using a calculator, we find that this angle is approximately -6.5°. Therefore, the phase constant of y is -6.5°, or we can say that the phase angle of the phasor Y is -6.5°.

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The area lying outside r=4sinθ and inside r=2+2sinθ is approximately 10.81 square units.

To find the area lying outside r=4sinθ and inside r=2+2sinθ, we need to first graph these two polar curves.

r=4sinθ is a cardioid, while r=2+2sinθ is a limacon with an inner loop.

The area we are looking for is the shaded region between these two curves.

To find the area, we need to integrate the difference between the outer curve (r=4sinθ) and the inner curve (r=2+2sinθ) from θ=0 to θ=2π:

Area = ∫(4sinθ)^2 - (2+2sinθ)^2 dθ from θ=0 to θ=2π

This simplifies to:

Area = ∫(16sin^2θ - 4 - 8sinθ - 4sin^2θ) dθ from θ=0 to θ=2π

Area = ∫(12sin^2θ - 8sinθ - 4) dθ from θ=0 to θ=2π

Using trigonometric identities and integration techniques, we can solve for the area:

Area = 4π - 8/3

Therefore, the area lying outside r=4sinθ and inside r=2+2sinθ is approximately 10.81 square units.

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To find the Taylor series about 0 for the function t3sin(5t), we need to compute its derivatives up to the fourth order at x = 0. First, let's compute the first four derivatives:

f(t) = t^3sin(5t)

f'(t) = 3t^2sin(5t) + 5t^3cos(5t)

f''(t) = 6tsin(5t) + 30t^2cos(5t) - 25t^3sin(5t)

f'''(t) = 6sin(5t) + 90tcos(5t) - 75t^2sin(5t)

f''''(t) = 450cos(5t) - 270t sin(5t)

Next, we evaluate these derivatives at x = 0:

f(0) = 0

f'(0) = 0

f''(0) = 0

f'''(0) = 6

f''''(0) = 450

Finally, we can write the Taylor series about 0 for t3sin(5t) as:

t^3sin(5t) ≈ 0 + 0t + 0t^2 + (6/3!)t^3 + (450/4!)t^4

≈ (1/3!)t^3 + (1/4)t^4

Therefore, the first four nonzero terms of the Taylor series about 0 for t3sin(5t) are (1/3!)t^3 and (1/4!)t^4. These terms approximate the function t3sin(5t) near x = 0 with increasing accuracy as x gets closer to 0.

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