Answers
Given:
Force = 1.38 x 10⁻¹⁸ N northward.
Let's find the magnitude and direction of the electric field
To find the magnitude, apply the formula:
[tex]E=\frac{F}{q}[/tex]Where:
E is the electric field
F is the force = 1.38 x 10⁻¹⁸ N
q is the charge of proton = -1.60 x 10⁻¹⁹ C
Input the values in the equation and solve for E:
[tex]\begin{gathered} E=\frac{1.38\times10^{-18}}{-1.60\times10^{-19}} \\ \\ E=-8.625\text{ N/C} \end{gathered}[/tex]The magnitude of the electric field is -8.625 N/C.
Since the direction of the force is Northward and the polarity of the charge is negative, the direction of the electric field will be opposite the direction of the force.
Therefore, the direction of the electric field is downward.
ANSWER:
8.625 N/C Southward
Answer:
8.625 N/C northward
Explanation:
The electric force can be related to the electric field and charge with which that field interacts via the equations found in Module 7 Section 1.3 and Chapter 18.4 in College Physics.
https://openstax.org/books/college-physics/pages/1-introduction-to-science-and-the-realm-of-physics-physical-quantities-and-units
Related Questions
As shown in the diagram below, a 5.0 kg space rock is located 2.5 x 107 m from the center of the Earth. The mass of the Earth is 6.0 x 1024 kg.ADetermine the force of gravity acting on the space rock, due to the Earth. Calculate the magnitude and state the direction.BCalculate the acceleration the rock would experience.
Answers
Given data
*The given mass of the space rock is m = 5.0 kg
*The given mass of the Earth is M = 6.0 × 10^24 kg
*The separation distance is r = 2.5 × 10^7 m
*The value of the gravitational constant is G = 6.67 × 10^-11 N.m^2/kg^2
(A)
The formula for the force of gravity acting on the space rock, due to the Earth is given as
[tex]F=\frac{GmM}{r^2}[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} F=\frac{(6.67\times10^{-11})(5.0)(6.0\times10^{24})}{(2.5\times10^7)^2} \\ =3.2\text{ N} \end{gathered}[/tex]Hence, the force of gravity acting on the space rock, due to the Earth is F = 3.2 N
(B)
The expression for the acceleration of the rock would experience is given as
[tex]\begin{gathered} F=ma \\ a=\frac{F}{m} \end{gathered}[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} a=\frac{3.2}{5} \\ =0.64m/s^2 \end{gathered}[/tex]Hence, the acceleration the rock would experience is a = 0.64 m/s^2
what is formula for speed wave . what does f and A symbols represent and what unit is speed wave measured in
Answers
I need help with #7 I can’t seem to figure it out
Answers
Given:
Mass, m1 = 10.0 kg
Mass, m2 = 3.60 kg
θ = 37.0 degrees
Let's solve for the following:
(a) Magnitude of the acceleration of 3.60 kg box.
From Newton's second law, we have:
Fnet = ma
m₁g - T = m₁a................equation 1
Applying Newton's second law along an inclined plane, we have:
T - m₂gsinθ = m₂a.............equation 2
Add both equation 1 and 2:
m₁g - T + T - m₂gsinθ = m₁a + m₂a
m₁g - m₂gsinθ = a(m₁ + m₂)
To find the magnitude of aceleration for m2, rewrite the equation for a:
[tex]\begin{gathered} a=\frac{m_{1}g-m_{2}gsin\theta}{m_{1}+m_{2}} \\ \\ a=\frac{g(m_1-m_2sin\theta)}{m_1+m_2} \end{gathered}[/tex]Where:
g is acceleration due to gravity = 9.8 m/s²
[tex]\begin{gathered} a=\frac{9.8(10-3.6\sin 37)}{10+3.6} \\ \\ a=5.64m/s^2 \end{gathered}[/tex]The manitude of acceleration of the 3.60 kg box is 5.64 m/s².
(b). What is he tension in the cable?
To find the tension in the cable, apply the formula:
[tex]\begin{gathered} m_1g-T=m_1a \\ \\ T=m_1g-m_1a \\ \\ T=m_1\mleft(g-a\mright) \\ \\ T=10.0(9.8-5.64) \\ \\ T=41.6\text{ N} \end{gathered}[/tex]The tension in the cable is 41.6 N
ANSWER:
(a) 5.64 m/s²
(b) 41.6 N
(Electron Charge) What charge does a balloon have if it has lost 9.4E12 electrons?
Answers
One coulomb (C) of charge represents an excess or deficit of 6.24 x 10¹⁸ electrons, therefore:
[tex]\begin{gathered} \frac{9.4}{6.24\times10^{18}}=1.5\times10^{-18} \\ \\ Since_{\text{ }}it_{\text{ }}has_{\text{ }}lost_{\text{ }}electrons: \\ \\ +1.5\times10^{-18} \end{gathered}[/tex]Answer:
+1.5x10⁻¹⁸ C
The half-life of iodine-131 is 8.07 days. If 1.3 g are left after 93.2 days, how many grams werein the original sample?
Answers
The formula that describes radioactive decay over time, is the following:
[tex]A=A^{}_0\cdot2^{-t/t_0}[/tex]Where A is the amount of a radioactive element after a time t, if t_0 is the half-life of the given element, for an initial sample A_0.
Solve for A_0, and substitute A=1.3g, t=93.2 and t_0=8.07 to find the initial amount of iodine-131 in the original sample:
[tex]undefined[/tex]Good morning I could really use help with this question please!
Answers
Given:
The charge of X is
[tex]q_x=\text{ 7.5}\times10^{-9}\text{ C}[/tex]The charge of Y is
[tex]q_y=-3.5\times10^{-9}\text{ C}[/tex]The distance between the charges is r = 80 cm.
To find whether there is an increase or decrease in the force of attraction/repulsion if the new charge of y is
[tex]q_y^{\prime}=-6.5\text{ }\times10^{-9}\text{ C}[/tex]and the distance between the charges is the same.
Explanation:
The charges q_x and q_y will have the force of attraction as they have opposite charges.
The magnitude of the force is given by the formula
[tex]F=k\frac{|q_x||q_y|}{r^2}[/tex]Here, the k is the electrostatic constant.
The distance between the charges is the same and the charge on X is also the same.
Thus, the force
[tex]F\propto\text{ \mid q}_y|[/tex]The new charge has a magnitude more than the old charge on Y.
Thus, the force of attraction will increase due to the increase in the magnitude of the charge.
Final Answer: The electrical force of attraction will increase.
Two identical conducting spheres carry charges of +3 coulombs (3C) and –1 coulombs (-1C), respectively. If the spheres are brought into contact and separated, the final charge on each is: a. +1C (b) +2C (c) –1C (d) –2C
Answers
Net charge /2
Q1 = 3 C
Q2= -1 C
Net charge = Q1 +Q2= 3 + (-1) = 2 C
2C/2 = 1C
Answer: +1C (option a )
The pilot of an airplane wishes to fly due north but there is 65km/h wind blowing toward the east. (a) In what direction should the pilot head her plane if it's speed relative to the air is 340km/h. (b) draw a vector diagram that illustrates your results in part a. (c) if the the pilot decreases the air speed of the plane but still wants to head due north should the angle found in part (a) be increased or decreased
Answers
ANSWER
(a) 11.02° west of north
(b) see diagram in EXPLANATION
(c) increased
EXPLANATION
(a) The pilot wants the airplane to fly north. There's a speed relative to the air that is 340km/h and the air speed is 65km/s. Drawing a vector diagram (b) we can see how to find the direction the plane should head:
If the wind is blowing east, it is clear that the plane has to go in opposite direction but still heading north. So the direction is θ degrees west of north. Now we just have to find this angle. The vectors form a right triangle where the direction the angle should take is the hypotenuse and the direction of the wind is the opposite side to the angle θ. Using the sine of the angle:
[tex]\sin \theta=\frac{65\operatorname{km}/h}{340\operatorname{km}/h}[/tex][tex]\sin \theta=\frac{13}{68}[/tex]Solving for θ:
[tex]\theta=\sin ^{-1}\frac{13}{68}=11.02\degree[/tex](c) Let's draw a new diagram with a smaller red vector:
If the red vector (which represents the speed of the plane) is exaggeratedly smaller than before we can see graphically that the angle is increased if the speed of wind's vector is the same.
Above is a distance/time graph showing an object in motion. Use the information
from the graph, write a scenario(story) about what the object is doing during each
section.
To answer, click the text tool or microphone icon in the tool
bar.
Answers
We will have the following:
From time 0 to 20: The object accelerated, until it reached maximum speed.
From time 20 to 30: The object moved at constant speed. [Acceleration 0]
From time 30 to 50: The object deccelerated, until it stopped.
True or false Is it possible for an object to exert a force on another object without feeling a force in return?
Answers
ANSWER
It is not possible
EXPLANATION
According to Newton's third law, for every action (force), there is always a reaction (reactive force).
This means that forces occur in pairs and so if an object exerts a force on another object, it must feel the same amount of force in return.
Therefore, it is not possible.
Vector A represents displacement of 50 m towards North and vector B represents 90 m displacement towards west. Find the resultant vector (A+B)
Answers
ANSWER
[tex]A+B=-90i+50j[/tex]EXPLANATION
We want to find the resultant vector of the two vectors A and B.
First, let us make a sketch of the two vectors:
Let us write the two vectors in component form taking the North as the positive y-direction and the West as the negative x-direction:
[tex]\begin{gathered} A=0i+50j \\ B=-90i+0j \end{gathered}[/tex]Therefore, the resultant vector is:
[tex]\begin{gathered} A+B=0i+50j+(-90i+0j) \\ A+B=0i-90i+50j+0j \\ A+B=-90i+50j \end{gathered}[/tex]That is the answer.
Looking at the spectral lines from the hydrogenspectrum of light, pictured below, and give theWavelength (m), Frequency (Hz), Velocity (m/s),Energy (J) for line c. Use scientific notation asneeded and 3 significant figures ex. 1.23E5.
Answers
ANSWER and EXPLANATION
We want to identify the parameters of the line in the electromagnetic spectrum.
The wavelength of line c is given as 486.13 nanometers. Converting this to meters, we have that the wavelength of line c is:
[tex]\begin{gathered} \lambda=486.13*10^{-9} \\ \lambda=4.86E-7\text{ }m \end{gathered}[/tex]To find the frequency of line c, apply the relationship between the velocity of light and wavelength:
[tex]f=\frac{c}{\lambda}[/tex]where c = velocity of light in a vacuum
f = frequency of the light
Hence, the frequency of line c is:
[tex]\begin{gathered} f=\frac{3.00*10^8}{4.85*10^{-7}} \\ f=6.19E14\text{ }Hz \end{gathered}[/tex]The velocity of light in a vacuum is given by:
[tex]c=3.00E8\text{ }m\/s[/tex]The energy of the line can be found using the formula:
[tex]E=hf[/tex]where E = energy
h = Planck's constant = 6.63E-34 Js
Hence, the energy of line c is:
[tex]\begin{gathered} E=6.63*10^{-34}*6.19*10^{14} \\ E=4.10E-19\text{ }J \end{gathered}[/tex]Those are the answers.
Draw the free-body diagram of the bodiescan you solve for the purple one
Answers
ANSWER
EXPLANATION
It appears that the purple juggling club is already on its way down, based on the position it is with respect to the others.
The weight of the club is one of the forces acting on it, which is making it move downward. The other force acting on the club is the drag, due to air resistance. This force is upward and it slows down the fall of the juggling club.
Can someone please help me with these two they go together to make one question
Answers
1) Since the truck is moving, it has kintic energy. The formula for calculating kinetic energy is expressed as
KE = 1/2mv^2
where
m = mass
v = velocity
From the information given,
m = 60000
v = 27
Thus,
Kinetic energy = 1/2 x 60000 x 27^2 = 21870000 J
The amount of work that must be done to stop the truck must be equal to or greater than the kinetic energy. Thus,
amount of work that must be done to stop the truck = 21870000 J
2) Net force applied = - 300000 N
Recall,
Net Force = mass x acceleration
acceleration = net force/mass
acceleration of the truck = - 300000 /60000 = - 5 m/s^2
Since the acceleration is negative, it is decelerating.
To find the distance before it stops, we would apply one of Newton's formula of motion which is expressed as
v^2 = u^2 + 2as
where
v = final velocity
u = initial velocity
a = acceleration
s = distance
From the information given,
v = 0(becuase it will stop moving)
u = 27
a = - 5
By substituting these values into the formula,
0^2 = 27^2 - 2 x 5 x s
0 = 729 - 10s
10s = 729
s = 729/10
s = 72.9
The truck will move 72.9 meters before stopping
Home Page Physics Interactives Newton's Laws Click/tap the Launch Interactive button. Resize the Interactive as des Explore Use the Interactive to explore the following questions: 1. With Friction and Air Drag furned off, describe the effect that an applied force has upon the velocity? Also, draw the force diagram at the right Label the forces using F for Applied force, Fun for Normal force from the ground, and Fra for the Weight of the sled.
Answers
The force diagram is shown below:
Now, the applied force will accelarate the particle to the right. This means that the velocity of the particle will increase in that direction.
What is the period of water wave if 4 complete waves pass a fixed point in 10 seconds?
Answers
Given:
To complete four waves, time taken is 10 s.
To find the time period of one wave.
Explanation:
The time taken to complete 4 waves is
[tex]4T\text{ = 10}[/tex]The time period will be
[tex]\begin{gathered} T=\text{ }\frac{10}{4} \\ =2.5\text{ s} \end{gathered}[/tex]Thus, the time period of one wave is 2.5 s.
What is the acceleration of an object with a mass of 17kg which is free falling if it feels a force of airresistance of 100.N?
Answers
Consider that the object experiences two forces at time: gravitational force (which is the weight of the object) and friction force due to air resistance. The net force over the object id then:
F = W - Fr
where,
F: net force
W: weight
Fr: friction force = 100.0N
The net force is equal, by Newton second law, to F = m*a, where m is the mass of the object and a is the acceleration.
Then, you have:
m*a = W - Fr
a = (W - Fr)/m
Consider that the weight of the object is:
W = m*g = (17.0 kg)(9.8 m/s^2) = 166.6 N
Then, by replacing the values of W, Fr and m into the expression for a, you obtain:
a = (166.6N - 100.0N)/(17.0kg)
a = 66.6N/17.0kg
a = 3.9 m/s^2
Hence, the acceleration of the object is approximately 3.9 m/s^2
Which of the following is the largest unit of heat energy?a.)jouleb.)calorie c.)Btud.)kilocalorie
Answers
ANSWER
d) kilocalorie
EXPLANATION
One calorie is equivalent to approximately 4.18 Joules, so 1 cal represents a greater amount of heat energy than 1 J.
Then, 1 kilocalorie is equivalent to 1000 calories, so 1 kcal represents a greater amount of heat energy than 1 cal.
Finally, 1 kcal is equivalent to approximately 3.96 BTU, so 1 kcal represents a greater amount of heat energy than 1 BTU.
Hence, of these options, the largest unit of heat energy is kilocalorie.
A glass rod is suspended from a string and charged by rubbing it with a piece of silk.A. After rubbing, what type of charge will be on each object?B. What will happen if the silk is brought close to the glass rod?
Answers
Answer:
A. Glass rod: Positive
Silk: Negative
B. They will attract each other
Explanation:
A silk has a stronger tendency to gain electrons than the glass rod. So, after rubbing, the silk will gain electrons and it will become negatively charged ans the glass rod will lose electrons and it will becamo positively charged.
Then, the glass rod and the silk will have opposite charges, so when the silk is brought close to the glass rod, they will attract each other.
A man has a mass of 150 kg. What does he weigh on earth expressed in N?
Answers
ANSWER:
1470 N
STEP-BY-STEP EXPLANATION:
Given:
Mass (m) = 150 kg
Earth gravity (g) = 9.8 m/s²
We can calculate the weight as follows:
[tex]\begin{gathered} W=m\cdot g \\ \\ \text{ We replacing:} \\ \\ W=150\cdot9.8 \\ \\ W=1470\text{ N} \end{gathered}[/tex]The weight of this man on earth is 1470 N
2) How long does it take sound to travel
a. 30m?
b. 1000m?
Answers
one thousand meters(1000m)
Where does the cart on a roller coaster have the most potential energy?
Answers
The potential energy of the cart is,
[tex]U=\text{mgh}[/tex]where m is the mass, g is the acceleration due to gravity and h is the height of the cart,
As the value of mass and the value of acceleration due to gravity remain constant.
Thus, the maximum value potential energy is at the maximum height.
Hence, the cart will have the maximum potential energy at the top of the roller coaster.
a pendulum bob swings back and forth at the end of its cable where is the pendulum moving the fastest?
Answers
The bob will be moving the fastest when it is vertical.
The bob posseses potential e
Two objects are placed so their centers are 1.19 meters apart, and the force between them is 8.16 x 10-10 newtons. What is the mass of each object if one has twice the mass of the other? Include units in your answers. Answers must be in 3 significant digits.
Answers
Given that the mass of object 1 is m and the mass of object 2 is 2m.
The distance between two objects is r = 1.19 m
The force between two objects is
[tex]F=8.16\times10^{-10}\text{ N}[/tex]The formula for the force can be written as
[tex]F=\frac{Gm\times2m}{r^2}[/tex]Here, the universal gravitational constant is G = 6.67 x 10^(-11) m^3 kg^(-1)s^(-2)
The mass will be
[tex]m^{}=\sqrt{\frac{Fr^2}{2G}}[/tex]Substituting the values, the mass will be
[tex]\begin{gathered} m=\sqrt[]{\frac{8.16\times10^{-10}\times(1.19)^2}{2\times6.67\times10^{-11}}} \\ =\sqrt[]{8.662} \\ =2.943\text{ kg} \end{gathered}[/tex]The mass of object 1 is 2.94 kg and the mass of object 2 is
[tex]\begin{gathered} 2\times2.943 \\ =\text{ 5.886 kg} \end{gathered}[/tex]A pure silver lions fan throws a roll of toilet paper at 7.2 m/s from her seat at Ford‘s field during a recent game. how fast is the 0.4 KG roll going when it strikes an opposition player 16. 1 m below?
Answers
Given:
The mass of the roll is m =0.4 kg.
The velocity of the roll is v = 7.2 m/s at a height h = 16.1 m.
To find the velocity when it strikes the opposition player, where height h'= 0 m
Explanation:
According to the law of conservation of energy, the total energy is always conserved, so
[tex]\begin{gathered} (P\mathrm{}E\mathrm{})_h+(K\mathrm{}E.)_h=(P.E.)_{h^{\prime}}+(K.E.)_{h^{\prime}} \\ mgh+\frac{1}{2}mv^2=mgh^{\prime}+\frac{1}{2}mv^{\prime2} \end{gathered}[/tex]Here, g = 9.8 m/s^2 is the acceleration due to gravity.
On substituting the values, the velocity will be
[tex]\begin{gathered} 0.4\times9.8\times16.1+\frac{1}{2}\times0.4\times(7.2)^2=0.4\times9.8\times0+\frac{1}{2}\times0.4v^{\prime2} \\ 63.112+10.368=0+0.2v^{\prime2} \\ v^{\prime}=19.17\text{ m/s} \end{gathered}[/tex]Final Answer: The velocity of the roll when it strikes the player is 19.17 m/s
An unknown radioactive element decays with a half life of 5.125 days. What is the decay constant for the element? Express your answer in 1/day.
Answers
Given
Half life is t=5.125 days
To find
The decay constant
Explanation
The decay constant is given by
[tex]\begin{gathered} \lambda=\frac{0.693}{t} \\ \Rightarrow\lambda=\frac{0.693}{5.125} \\ \Rightarrow\lambda=0.135 \end{gathered}[/tex]Conclusion
The decay constant is 0.135 /day
A dog is running in the park. First, she runs 55 meters east, then 25 meters west, then 11 meters east. What is the dog's total displacement at the end?
Answers
Displacement is the distance between the initial and the final position.
Let the direction east as the positive direction, and west as the negative direction.
The displacement can be calculated as,
[tex]55-25+11=41\text{ m}[/tex]Therefore the displacement of the dog is 41 m
Use the table and the diagram below to correctly label the force that is shown by the arrow pointing RIGHT.
Answers
The frictional forces (including air resistance) always point to the direction which is opposite to the movement of an object. If the object is not moving and the frictional force corresponds to a static friction, then it points to the opposite direction of the applied force.
From the diagram, if we assume that the object is not moving, then the arrow that points towards the right corresponds to the applied force.
Therefore, the answer is:
[tex]\text{Applied Force}[/tex]When a pitcher throws a baseball, it reaches a top speed of 39 m/s. If thebaseball takes 1.5 seconds to travel from the pitcher to the catcher, what isits acceleration? (Assume the ball is moving at 0 m/s right before it leavesthe pitcher's hand.)A. 23 m/s2B. 17 m/s2C. 11 m/s2D. 26 m/s2
Answers
Given,
The final velocity of the ball, v=39 m/s
The initial velocity of the ball, u=0 m/s
The time duration, t=1.5 s
The final velocity of an object upon which an accleration, a, acts for a duration of t seconds is given by one of the equations of motion as
[tex]v=u+at[/tex]By substituting the known values and simplifying the resulting equation we will get the acceleration of the ball.
Thus,
[tex]\begin{gathered} 39=0+a\times1.5 \\ \Rightarrow a=\frac{39}{1.5} \\ 26m/s^2 \end{gathered}[/tex]Thus the acceleration of the ball is 26 m/s²
Therefore the right answer is option 4.
What is one way to change water from a liquid to a solid?decrease the massdecrease the temperatureincrease the massincrease the temperature
Answers
Decrease the temperature
Explanation
Freezing, or solidification, is a phase transition in which a liquid turns into a solid when its temperature is lowered to or below its freezing point.
When liquid water loses thermal energy, it undergoes freezing : changing state from a liquid to a solid.
so, the lose of thermal energy means
Decrease the temperature
I hope this helps you