The magnitude of the velocity of the of the chain when 5.58m of the chain is hanging vertically is 10.46m/s.
Given the length of chain (s) = 5.58m
We know that from Newtons second law of motion :
v^2 = u^2 + 2gs where v is the final velocity, u is the initial velocity and g is the acceleration due to gravity.
Here u = 0m/s as the chain is at rest initially.
So, v^2 = 0 + 2 x 9.8 x 5.58
v^2 = 109.368
v = √109.368 = 10.46m/s
Hence the magnitude of the velocity of the of the chain = 10.46m/s.
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does the glancing incident or near normal incidence result in a higher percentage of reflected light?
No, the glancing incident or near normal incidence does not result in a higher percentage of reflected light.
The percentage of reflected light is determined by the reflectivity of the surface and the angle of incidence. If the angle of incidence is closer to normal, then the reflected light will be more concentrated and will have a higher intensity, but the percentage of reflected light will remain the same.
The term "incidence" describes the emergence of new cases of illness or damage within a community within a predetermined time frame.
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determine how to distribute an additional mass of 6 g at the three vertices of the plate to move the balance point of the plate to
The additional mass should be distributed as 2.75g, 0.25g, and 3 gm at vertices V1, V2, and V3 respectively, to move the center of mass of the plate at (2, 2).
The center of mass (x, y) of a triangular plate with vertices V1=(0,1), V2=(8,1), and V3=(2,4) can be calculated by taking the average of the x and y coordinates of the vertices.
x = (0 + 8 + 2)/3 = 10/3
Similarly y = 6/3 = 2
So, the center of mass of the plate is (4, 2).
New center of the mass is (2, 2)
w1 + w2 + w3 = 6 g ....eqn(1)
Mass of the plate, m = 3 g
To distribute an additional mass of 6 g at the three vertices of the plate to move the balance point of the plate to (2,2), we need to determine the masses w1, w2, and w3 that need to be added at each vertex.
The formula for finding the center of mass of a system of point masses is:
x = (w1 × x1 + w2 × x2 + w3 × x3 + m × 10/3)/(m + w1 + w2 + w3)
y = (w1 × y1 + w2 × y2 + w3 × y3 + m × 2)/(m + w1 + w2 + w3)
2 = (w1 × 0 + w2 × 8 + w3 × 2 + 3 × 10/3)/(3 + 6)
18 = 8w2 + 2w3 + 10
8 = 8w2 + 2w3....eqn(2)
Similarly
2 = (w1 × 1 + w2 × 1 + w3 × 4 + 3 × 2)/(3+6)
18-6 = w1 + w2 + 4w3
12 = w1 + w2 + 4w3 ...... eqn(3)
On solving three equations
6 = w1 + w2 + w3
8 = 8w2 + 2w3
12 = w1 + w2 + 4w3
We get
w1 = 2.75 g
w2 = 0.25 g
w3 = 3 g
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--The given question is incomplete, the complete question is:
"A thin triangular plate of uniform density and thickness has vertices V1=(0,1), V2=(8,1), and V3=(2,4), and the mass of the plate is 3 g.
Determine how to distribute an additional mass of 6g at the three vertices of the place to move the balance point of the plate to (2,2). Hint: Let w1,w2,w3 denote the masses added to the three vertices so that w1+w2+w3= 6."--
a car can sustain a maximum acceleration of 1 m/s/s, a maximum deceleration of 2 m/s/s, and a top speed of 20 m/s. determine the minimum amount of time it will take for this car to travel one kilometer if it starts from rest and finishes at rest, i.e., stops at the one kilometer mark g
If it starts from rest can travel 1000m, in a straight path, and again it has to come to rest at the end of 1000m, then minimum 70s will be taken.
According to the question, the car starts off at a stop, travels up to a top speed of 20 m/s, and then comes to a stop. This implies that the vehicle must have first reached its maximum speed before braking to a stop.
Let, [tex]T_1[/tex] and [tex]T_2[/tex] be the time for acceleration (attaining maximum velocity) and deceleration (come to the rest) respectively.
Then,
[tex]T_1[/tex] = (Maximum velocity - initial velocity) / acceleration
⇒ [tex]T_1=\frac{20-0}{1}=20sec[/tex]
Then, distance travelled in time [tex]T_1[/tex],
⇒ [tex]S_1=UT_1+\frac{1}{2}aT_1^2[/tex]
⇒ [tex]S_1=0+\frac{1}{2}*1*20^{2}[/tex]
⇒ [tex]S_1= 200m[/tex]
Similarly,
⇒ [tex]T_2=\frac{0-20}{-1}=20sec[/tex]
⇒ [tex]S_2=UT_2+\frac{1}{2}aT_ 2^2[/tex]
⇒ [tex]S_2=(20*20)-(\frac{1}{2}*1*20^2)[/tex]
⇒ [tex]S_2=400-200=200m[/tex]
∴ Distance travelled at uniform velocity is
⇒ [tex]S = 1000-(S_1+S_2)[/tex]
⇒ [tex]S=1000-(200+200)=1000-400=600m[/tex]
This 600m is travelled at a speed of 20m/s.
and time of travel for constant velocity is
⇒ [tex]T_3=\frac{S}{V}[/tex]
⇒ [tex]T_3=\frac{600}{20}=30sec[/tex]
Hence, total time for travel
⇒ [tex]T=T_1+T_2+T_3=(20+20+30)sec=70sec[/tex]
On a V-T graph, it can be displayed here(See picture).
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how to calculate velocity given displacement is 0 m, time interval is 35s, but the vector is going down
The velocity will be 0 m/s. We calculated it as shown below.
It is the directional speed of a moving object, as measured by a specific unit of time and viewed from a particular vantage point, that is called velocity. Vectorial velocity describes the displacement that an object or particle experiences with respect to time. It is accepted that the metre per second (m/s) is the unit of magnitude of velocity (also called speed). As well as meters per second (m/s), centimeters per second can also be used to express magnitude.
Velocity = [tex]\frac{Displacement}{Time}[/tex]
= 0/ 35
= 0 m/s
So , The velocity will be 0 m/s.
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A boat has a speed of 2 m/s. It accelerates for half a minute to reach a speed of 8 m/s. Work out the acceleration of the boat.
The accelaration of the boat, given the speed of the boat and the time taken to reach the speed, is 0.2 m / s².
How to find the accelaration ?Acceleration can be found by dividing the change in the speed of an object by the time it takes.
The change in speed is:
= 8 m / s - 2 m / s
= 6 m /s
The change in time is:
= 1 / 2 x 60 seconds per minute
= 30 seconds
The acceleration is:
= 6 / 30
= 0.2 m / s²
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Answer:
0.2
Explanation:
Acceleration = change in velocity / time = (8 m/s – 2 m/s) / 30s = 0.2 m/s2
Two point charges are placed on the x axis. (Figure 1)The first charge, q1 = 8. 00nC , is placed a distance 16. 0m from the origin along the positive x axis; the second charge, q2 = 6. 00nC , is placed a distance 9. 00m from the origin along the negative x axis. EAx,EAy = 0,0. 300 N/C An unknown additional charge q3 is now placed at point B, located at coordinates (0 m, 15. 0 m ). Find the magnitude and sign of q3 needed to make the total electric field at point A equal to zero
The magnitude of charge q3 is 3*10^4 N/C and it has a positive sign.
To find the magnitude and sign of the additional charge q3 needed to make the total electric field at point A equal to zero, we can use the principle of superposition of electric fields. This principle states that the total electric field at any point in space is the vector sum of the electric fields due to each individual charge.
We can start by calculating the electric field due to each of the two point charges q1 and q2 at point A, which is located at the origin. The electric field due to a point charge q at a distance r from it is given by the equation:
E = k*q/r^2
Where k is the Coulomb constant and q is the charge.
For q1, the electric field at point A is:
E1 = kq1/(16m)^2 = 910^9 * 810^-9 / 256 = 310^4 N/C
For q2, the electric field at point A is:
E2 = kq2/(9m)^2 = 910^9 * 610^-9 / 81 = 610^4 N/C
Since q2 is on the negative x-axis, the electric field is pointing in the negative x direction.
Now we can calculate the total electric field at point A by adding these two fields vectorially.
E = E1 + E2 = 310^4 N/C - 610^4 N/C = -3*10^4 N/C
The total electric field at point A is pointing in the negative x direction.
To make the total electric field equal to zero, we need to add an additional charge q3 at point B that has the same magnitude as the total electric field but pointing in the opposite direction. The magnitude of q3 is -3*10^4 N/C, and since it is pointing in the positive x-direction, the sign of q3 is positive.
So, the magnitude of q3 is 3*10^4 N/C and it has a positive sign.
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a cable is stretched between two posts 3.00 m apart. the speed of waves on this cable is 96.0 m/s , and the tension in the cable is 175 n . if a standing wave on this cable has five antinodes, what is the wavelength of the standing wave?
The wavelength of the standing wave will be 1.2 m if a cable is stretched between two posts 3.00 m apart. the speed of waves on this cable is 96.0 m/s, and the tension in the cable is 175 n. if a standing wave on this cable has five antinodes.
Length, l = 2 m
speed of waves, v = 96 m
Tension, T = 175 N
Antinodes, n = 5 means 5th harmonic
We know that,
l = nλ/2
or λ = 2l/n = 2x3/5 = 1.2 m
Therefore, the wavelength of the standing wave will be 1.2 m if a cable is stretched between two posts 3.00 m apart. the speed of waves on this cable is 96.0 m/s, and the tension in the cable is 175 n. if a standing wave on this cable has five antinodes.
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The frequency of waves from a radio station is 15 megacycles per second. Calculate their wavelength. Please help!!
The wavelength of waves whose frequency of waves from a radio station is 15 megacycles per second is 20m
Given the frequency of radio waves (f) = 15 megacycles per second
The number of complete wave cycles that pass a location in a unit of time is the definition of frequency. The SI frequency unit is called a Hertz (Hz). A sinusoidal wave's frequency is defined as the total number of full oscillations that every wave constituent performs in a unit of time.
Let the wavelength = ∧
The speed of light waves (v) = 3 x 10^8m/s
We know that frequency = velocity/wavelength
Then f = v/∧ such that ∧ = v/f
∧ = 3 x 10^8/15 x 10^6 = 20m
Hence the wavelength of radio waves = 20m
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016 (part 1 of 2) 10.0 pointa objects with masses of 232 kg and 638 kg are separated by 0.342 m. a 60.6 kg mass is placed midway between them. 232 kg 538 kg 60.6 kg © - 0.342 m find the magnitude of the net gravitational force exerted by the two larger masses on the 60.6 kg mass. the value of the universal gravi tational constant is 6.672 × 10-11 n • m? /kg? answer in units of n. 017 (part 3 of 2) 10.0 points leaving the distance between the 232 kg and the 638 kg masses fixed, at what distance from the 538 kg mass (other than infinitely remote ones) does the 60.6 kg mass experience a net force of zero? answer in units of m
The magnitude of the net gravitational force exerted by the two larger masses on the 60.6 kg mass is 3.958e-9 N. The distance at which the 60.6 kg mass experiences a net force of zero is infinitely remote.
What is the value of the universal gravitational constant?The universal gravitational constant, denoted as G, is a physical constant that is used to describe the strength of the gravitational force between two objects. Its value is approximately 6.672 x 10^-11 Nm^2/kg^2. This constant is used in the equation for the force of gravity, which is F = G(m1m2)/r^2, where m1 and m2 are the masses of the two objects, and r is the distance between them. The constant is considered to be a fundamental constant of nature and is used in many fields of physics, including cosmology and celestial mechanics.
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what is the angular separation (in radians) between the central maximum and the first-order maximum?
The angular separation between the central maximum and the first-order maximum is equal to 1.22 radians.
This is the angle between the two points on the wavefront that have the same intensity of the wave, and is determined by the wavelength of the wave and the distance between the two points.
The angular separation is an important factor in understanding the behavior of a wave, as it affects the intensity of the wave at different points.
Additionally, the angular separation between two points on the wavefront can provide insight into the wavelength of the wave, as longer wavelengths yield larger angular separations.
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The value of the electric field at a distance of 28.8 m from a point charge is 68.3 N/C and is directed radially in toward the charge.
What is the charge? The Coulomb constant
is 8.98755 × 10⁹ Nm²/C².
Answer in units of C. Answer in units of
C.
To determine the charge, we can use the equation for the electric field due to a point charge:
E = k * q / r^2
Where E is the electric field, k is the Coulomb constant (8.98755 x 10^9 Nm^2/C^2), q is the charge, and r is the distance from the point charge.
We can rearrange this equation to solve for q:
q = E * r^2 / k
Plugging in the given values:
q = (68.3 N/C) * (28.8 m)^2 / (8.98755 x 10^9 Nm^2/C^2)
q = (68.3 N/C) * (826.24 m^2) / (8.98755 x 10^9 Nm^2/C^2)
q = (68.3 N/C) * (826.24 m^2/C^2)
q = (68.3 N/C) * (826.24 / 8.98755 x 10^9) C
q = (68.3 N/C) * (9.26 x 10^-9) C
q = 6.36 x 10^-7 C
The charge is approximately 6.36 x 10^-7 Coulombs.
why do cars accelerated up the slopes at the same speed but required different amounts of force
Answer:
The same way Newton’s apple fell from the tree and failed to “fall” back up. The steeper the slope the faster the pull of gravity will act. Assuming you are providing the exact same power to a car an upslope will slow the car and a down slope will speed the car. The greater the slope, the greater effect. Until you reach vertical, you should never operate a vehicle in such a manner.
Explanation:
Invisible forces that are exerted between electric charges at a distance is evidence that each charge is surrounded by an electric.
1. Source
2. Field
3. Outlet
4. Plug
An electric field is an invisible field of force created by the attraction and repulsion of electric charges (the cause of electric flow) and is measured in volts per meter (V/m). With increasing distance from the field source, the electric field's intensity decreases.
Electrostatics Force :Electrostatic forces are attractive or repulsive forces between particles that have already been created by their respective electric charges. The electrical force between stationary charged substances is generally known as the electrostatic force.
An electric field is an area around a charged object where the electric force of the object acts on other charged objects. Electric fields weaken the further they are from the charge. The electric field is invisible.
You see, electrically charged particles like protons and electrons actually have invisible force fields around them.
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an ice floe has a rectangular shape with a surface area of 3 m2 and 1 m thick. what is the maximum mass of a polar bear can sit on the floor before sinking? (ice density 900 kg/m3, sea water density 1025 kg/m3)
The maximum mass of a polar bear can sit on the floor before sinking is 3075 kg.
What do you mean by mass?The mass of an object is constant and does not change with location, unlike weight which does change depending on the gravitational pull of the planet.
Mass can be determined by measuring the gravitational force on an object using a device called a balance or scale. The International System of Units (SI) unit of mass is the kilogram (kg)
The maximum mass of a polar bear that can sit on the ice floe before it sinks is determined by the buoyancy force. The buoyancy force is equal to the weight of the water that the ice floe displaces, which is equal to the volume of the ice floe multiplied by the density of seawater.
The volume of the ice floe is 3m2 * 1m = 3 m3.
The buoyancy force is 3m3 * 1025 kg/m3 = 3075 kg.
The mass of the polar bear that can sit on the ice floe before it sinks is equal to the buoyancy force. So the maximum mass of a polar bear that can sit on the ice floe before sinking is 3075 kg.
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Write a statement that explains how the internal and external structures you are discussing work together to support growth and reproduction.
(I WILL GIVE 90 POINTS IF YOU ANSWER THIS!)
Answer: plants have internal and external structures that support growth and reproduction Examples of internal structures are the xylem and phloem Examples of external structures are the roots and stems. All of these structures provide plants with nutrients and food
Explanation: BRAIN
4 A block of mass 500g is pulled from rest on a horizontal
frictionless bench by a steady force Fand travels 8m in 2 s.
Find
I
a the acceleration,
b the value of F.
The acceleration and force of the block is 4 m/s² and 2 N respectively.
What do you mean by acceleration?Acceleration is a measure of the change in an object's velocity over time. It is defined as the rate at which an object changes its velocity, either in speed or direction. Mathematically, acceleration is calculated as the change in velocity (delta v) divided by the change in time (delta t): a = Δv / Δt. In other words, it is the rate of change of velocity. Acceleration has units of meters per second squared (m/s^2) in the International System of Units (SI).
The acceleration of the block can be calculated using the formula:
a = Δv / t, where Δv is the change in velocity and t is the time interval.
Since the block starts from rest, its initial velocity is 0 m/s, and its final velocity can be calculated as v = a × t = 8 m/s.
So, a = [tex]\frac{v}{t}[/tex] = [tex]\frac{8m/s}{2s}[/tex] = 4 m/s².
The value of F can be calculated using Newton's second law, which states that the net force on an object is equal to its mass times acceleration:
F = ma = 500 g × 4 m/s² = 2 N.
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in taking your pulse, you count 76 heartbeats in 1 min m i n . part a what is the period of your heart oscillations?
Your heart beats with a Time period of 0.789 seconds.
Your heart beats 76 times per minute, or n.
One minute, or the 60s, is required to complete 76 heartbeats.
now, by figuring out the frequency
The speed of direction varies in current per second is known as frequency. It is denoted in hertz (Hz), and Hertz is the unit of measurement that is used internationally. One hertz is equal to one heartbeat per second.
f = n/t
The time is t, and the number of heartbeats is n.
f= 76/60
f= 1.2666 Hz
to determine the duration
The time period is the inverse of the frequency or one divided by frequency.
T = 1/f
T = 1/ 1.266
T = 0.789s
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Your heart beats for 0.789 seconds each time.
The number of times your heart beats each minute is n.
76 heartbeats must occur in one minute, or the 60s.
Now, by determining the frequency
Frequency is the measure of how quickly a direction changes in current per second. It is expressed in hertz (Hz), the internationally accepted unit of measurement. Heartbeats per second are measured in hertz.
f = n/t
There are n heartbeats per second and time t.
f= 76/60
f= 1.2666 Hz
to establish the timeframe
The time period is equal to the frequency divided by one, or the inverse of the frequency.
T = 1/f
T = 1/ 1.266
T = 0.789s
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a heated gas expands and presses on a piston moving the piston. in this example, work is done: a) by the gas on the piston. b) on the gas by the heat source. c) by the piston on the gas. d) by the surroundings on the system.
Work is done: a) by the gas on the piston.
Pressure-volume work is work done by the expansion of a gas against a constant pressure, such as that provided by a moveable piston.The pressure-volume work (displacement work) is the work don on the gas or by the gas due to the acting gas pressure during a change in volume.If the initial and final state of a gas in a thermodynamic process are known, it is imperative to know the exact course of the state curve in the volume-pressure diagram in order to determine the pressure-volume work. This is because, depending on the path, there are different areas under the curves and thus different pressure-volume work.The pressure-volume work thus depends to a decisive extent on how the process proceeds exactly between the initial and final state. The pressure-volume work as a path-dependent quantity is a typical process variable.To know more about thermodynamics visit:
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Regardless of which method of delivery a speaker might think is appropriate for a speaking event, the audience has expectations about how messages should be delivered as well. This is a situation that speakers need to carefully consider before selecting a delivery method for their speech.
-true
-false
Delivery method for their speech is True.
How does the context of the speaking event affect the audience's expectations for the delivery of a speech?The context of the speaking event can greatly affect the audience's expectations for the delivery of a speech. For example, in a formal setting such as a business conference, the audience may expect a more professional and formal delivery, with the use of slides or visual aids and a well-structured speech. In contrast, at a casual event such as a family gathering, the audience may expect a more relaxed and conversational delivery, with less emphasis on visual aids and a more informal structure. Additionally, the topic of the speech, the background of the audience and the purpose of the speech can also affect the audience's expectations. Therefore, a speaker should be aware of the context of the event, and adjust their delivery method accordingly.
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A compressor for a jackhammer expands the air in the hammer’s cylinder at a constant pressure of 8. 6 x 10^5 Pa. The increase in the cylinder’s volume is 4. 0^5 x 10^-4 m^3. During the process, 9. 5 J of energy is transferred out of the cylinder as heat.
A. What is the work done by the air
B. What is the change in the air’s internal energy
C. What type of ideal thermodynamic process does this approximate
The work done by the air is 88.06kJ, the change in the air’s internal energy is 357.8J and the type of ideal thermodynamic process is isobaric process.
Given the constant pressure of cylinder (P) = 8.6 x 10^5Pa.
The increase in the cylinder’s volume is (V) = 4.0^5 x 10^-4 m^3.
The energy transferred out of the cylinder as heat (Q) = 9.5J
(a) We know that work done (W) = -PexternalΔV
W = -8.6 x 10^5 x 4.0^5 x 10^-4 = -88.06kJ
Hence the work done is 88.06kJ.
(b) From first law of thermodynamics we know that change in internal energy is equal to heat released - work done.
ΔU = Q - W where W is work and U is internal energy.
ΔU = -9.5 - 348.3 = -357.8J
(c) The type of ideal thermodynamic process this approximates is isobaric process. Under constant pressure, the isobaric process is a thermodynamic process. Even though the pressure is constant in this operation, the temperature, volume, and internal energy are not.
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Consider an object of mass 2 kg resting on the floor. The coefficient of static friction between the object and the floor is us& What force must be applied on the object to move it?
The maximal static friction force (F) between surfaces in contact prior to motion starting is divided by the normal force (N) to determine the coefficient of static friction. Solving yields a value of 1.08 m/s2.
Find coefficient of static friction ?
The maximal static friction force (F) between surfaces in contact prior to motion starting is divided by the normal force (N) to determine the coefficient of static friction.
Static friction's highest value is F s = _s mg.
where _s is the static friction coefficient
50kg is the box's weight in meters.
Gravitational acceleration is equal to 9.81 m/s2.
F s = 0.5×50×9.81 =245 N
The object must be in motion because the applied force exceeds the static friction's maximum value, F s.
As a result, kinetic friction rather than static friction must be considered.
by the equilibrium state
ma = F k m g
where F = 250 N, k = kinetic friction coefficient = 0.4, and m = 50 Kg
a = box's acceleration
50a = 250-0.4×50×9.81
Solving yields a value of 1.08 m/s2.
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Lab: Magnetic and Electric Fields
Assignment: Lab Report
On engenuity
A magnetic field is a field that explains how magnetism affects an item in space.
How are the magnetic and electric fields connected? A magnetic field is a field that explains how magnetism affects an item in space.The strength of the electric force at any particular place in space is what is known as the electric field.The rate at which a charge travels through a space is called current.Because a changing electric field generates a magnetic field, and a changing magnetic field generates an electric field, electricity and magnetism are essentially two sides of the same phenomenon.(This is why physicists more frequently use the terms "electromagnetism" or "electromagnetic" forces collectively than individually.)Electric fields can be produced by magnetic fields as well as electric charges.Similar to how magnets may produce magnetic fields, electric fields can likewise produce magnetic fields.To learn more about magnetic field refer
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Answer:
lab report is attached
Explanation:
the equator is characterized by relatively high or low atmospheric pressure aloft
The equator is characterized by relatively low atmospheric pressure aloft.
What is equator?The equator is a large circle that circles the planet Earth, being in a plane perpendicular to the axis of the planet and being equally spaced from geographic poles.
The geographic Equator, also known as the terrestrial Equator, is the imaginary line on the surface of the Earth from which latitude is calculated; it is the line at 0° latitude. It separates Earth into the Northern and Southern hemispheres.
Equatorial regions are hotter, which causes the air above to expand, lose density, and ascend. At this latitude, this results in a low pressure band.
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can you draw a gaussian surface that offers a simple way to compute the electric field surrounding a charged dipole?
Yes No
When there is the proper symmetry, Gauss's law can be used to quickly determine the electric field.One of these scenarios is not the case of an electric dipole.
Can the electric field caused by an electric dipole be calculated using Gauss's law? When there is the proper symmetry, Gauss's law can be used to quickly determine the electric field.One of these scenarios is not the case of an electric dipole.The flux across any Gaussian surface surrounding an electric dipole should be zero as it encloses no net charge, and this is in fact the case.The net charge enclosed (qenc) divided by the permittivity of free space (qenc/0) determines the flux of the electric field E passing through any closed surface S (a Gaussian surface): =SEndA=qenc/0.The electric field caused by an electric dipole cannot be determined using the Gauss theorem since an electric dipole has equal and opposing charges, and since no electric field is present when the net charge of the system is zero, an electric dipole does not have an electric field surrounding it.
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if two magnets are placed on a table, which statement describes a situation with the most attraction between the two magnets
Answer:
Unlike charges attract
Explanation:
the force between unlike charges is strong,and the closer the charges are the stronger the electrostatic force between them
A 124-kg balloon carrying a 22-kg basket is descending with a constant downward velocity of 25. 1 m/s. A 1. 0-kg stone is thrown from the basket with an initial velocity of 12. 6 m/s perpendicular to the path of the descending balloon, as measured relative to a person at rest in the basket. That person sees the stone hit the ground 17. 6 s after it was thrown. Assume that the balloon continues its downward descent with the same constant speed of 25. 1 m/s. ?
The distance between the balloon and the rock can be found by using Pythagorean theorem: d = 198 .2 m
Find the solution ?The motion of the stone is the motion of a projectile, thrown with a horizontal speed of
vx = 15 .0 m/s
and with an initial vertical velocity of
= 20.0 m/s
where we have put a negative sign to indicate that the direction is downward.
h is the initial height
g = -9.81 m/s^2 is the acceleration due to gravity
The stone hits the ground after a time t = 6.00 s, so at this time the vertical position is zero:
y(6.00 s) = 0
Substituting into eq.(1), we can solve to find the initial height of the stone, h: = 296 .m
(b) 176.6 m
The balloon is moving downward with a constant vertical speed of
v x = -20.0 m/s
and substituting t = 6.0 s and h = 296.6 m, we find the height of the balloon when the rock hits the ground:
y(t) = 176.6 m
(c) 198.2 m
In order to find how far is the rock from the balloon when it hits the ground, we need to find the horizontal distance covered by the rock during the time of the fall.
The horizontal speed of the rock is
v x = 15.0 m/s
So the horizontal distance travelled in t = 6.00 s is
d x = 90 m
Considering also that the vertical height of the balloon after t=6.00 s is
d y = 176.6 m
The distance between the balloon and the rock can be found by using Pythagorean theorem:
d = 198 .2 m
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a 700 kg car moving at 20 m/s collides with a stationary truck with mass 1400 kg. the two vehicles interlock as a result of the collision. what is the speed of the car/truck combination? what type of collision is this (elastic, inelastic, or explosion)?
The speed of the car truck combination is calculated to be 0.667 m/s and it is a type of inelastic collision.
Mass of the car m₁ = 700 kg
Velocity of the car u₁ = 20 m/s
Mass of the stationary truck m₂ = 1400 kg
Velocity of the stationary truck u₂ = 0
The momentum before collision is, m₁ u₁ = 700× 20 = 1400 kg m/s
As, we know from the principle of conservation of linear momentum,
momentum before the collision of trucks is equal to momentum after the collision of trucks.
The momentum after the collision is (m₁ + m₂) vf = 1400 kg m/s
(700 + 1400) vf = 1400
2100 vf = 1400
vf = 0.667 m/s
Now, let us compare kinetic energies before and after collision.
Kinetic energy before collision = 1/2 m₁ u₁² = 1/2 × 700× 20² = 14×10⁴ kg m/s
Kinetic energy after collision =1/2 (m₁+m₂) vf₂ = 1/2(700 + 1400) 0.667² = 467.13 kg m/s
As kinetic energy is not conserved, the type of collision is said to be an inelastic collision.
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A physics demo launches a ball horizontally while dropping a second ball vertically at exactly the same time. Which ball hits the ground first?
Launched (horizontally) ball Dropped ball Both hit at the same time
In this physics demonstration, the ball that is dropped vertically and the one that is launched horizontally will both make contact with the ground at distinct times. The ball that falls vertically will first hit the ground.
This is because the force of gravity acts downward on both balls, causing them to accelerate toward the ground. However, the horizontally launched ball experiences the launch force as well, giving it an initial horizontal velocity. The ball's rate of descent to the ground is slowed by this horizontal velocity, resulting in a longer time spent on the ground.
On the other hand, the vertically dropped ball only experiences the force of gravity because it has no initial horizontal velocity. This indicates that it descends straight down at a steady rate and reaches the ground earlier than the horizontally launched ball.
What is speed?The rate at which an object's position changes over time is measured by its velocity. It has magnitude and direction because it is a vector quantity. Meters per second (m/s) is the International System of Units (SI) standard for measuring velocity.
Mathematically, velocity can be represented as:
v = x/t, where x is the object's change in position (or displacement), t is the change in time, and v is the velocity.
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a large air mass is moving over flat land from a desert to an ocean true or false - prescriptions likely as the air mass moves closer to the ocean
A large air mass moving over flat land from a desert to an ocean is a true statement.
Why air mass moves closer to the ocean?The temperature, humidity, and pressure of the air mass, as well as the temperature, humidity, and pressure of the water beneath it, are the data
Scientists need to know to assist them to estimate the possibility of precipitation as the air mass travels closer to the ocean.
Being a warm front, the precipitation is expected to contain a few scattered clouds. This is due to the fact that the air mass of the desert is passing over an ocean, which implies that a heated, dry air mass is passing over a cold air mass.
Therefore, it is a true statement.
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the motor has a resistance of 9.7 ohms . when the motor switch is closed (meaning that branch of the circuit now has current flowing through it), what power does the bulb consume?
Lighting uses typically range from 2 to 100 watts (W), depending on size and kind.
A 60W bulb consumes how much electricity?A 60W light bulb was previously used as an example. By virtue of its 60W rating, it consumes 60 joules of energy every second it is turned on. This indicates that 216,600 joules of energy would be expended over the length of 3,600 seconds, or 60 minutes.Lighting uses typically range from 2 to 100 watts (W), depending on size and kind. LED bulbs only require 2 to 18 W, compared to the 25 to 100 W used by conventional incandescent lamps. 110 volts or less and typically less than 1 amp are drawn by light bulbs.Lighting uses typically range from 2 to 100 watts (W), depending on size and kind.To learn more about electricity refer to:
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