Considering the Law of Universal Gravitation, the mass of the second object is 78090.19 kg.
The Law of Universal Gravitation is a law that states that bodies, by the simple fact of having mass, experience a force of attraction towards other bodies with mass, called gravitational force.
This law establishes that every particle attracts any other particle with a force directly proportional to the product of the masses of both and inversely proportional to the square of the distance that separates them:
[tex]F=G\frac{m1m2}{r^{2} }[/tex]
where m1 and m2 are their masses; r the distance between them and G a universal constant that is called the constant of gravitation.
In this case, you know:
F= 0.128 NG=6.67× 10⁻¹¹ Nm²/kg²m1= 1300 kgm2= ?r= 0.23 mReplacing:
[tex]0.128 N=6.67x10^{-11}\frac{Nm^{2} }{kg^{2} } \frac{1300 kg m2}{(0.23 m)^{2} }[/tex]
Solving:
[tex]0.128 N=1.639x10^{-6}\frac{N}{kg }x m2[/tex]
m2=0.128 N ÷ 1.639×10⁻⁶ [tex]\frac{N}{kg}[/tex]
m2=78090.19 kg
In summary, the mass of the second object is 78090.19 kg.
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https://brainly.com/question/858421?referrer=searchResultshttps://brainly.com/question/2347945?referrer=searchResultsA circular coil consisting of 500 turns with an area of 6.0x10-4 m 2 is rotating in a uniform magnetic field. At the start, the normal to the coil is perpendicular to the magnetic field. After 15s, the normal to the coil is 60⸰ with the magnetic field. The average induced emf is -0.058V. What is the magnitude of the magnetic field?
The magnitude of the magnetic field in the coil is 21.65 T.
The given parameters;
number of turns, N = 500 turnsarea of the coil, A = [tex]6\times 10^{-4} \ m^2[/tex]change in time, t = 15 sThe induced emf in the coil is determined by applying Faradays law;
[tex]emf =N \frac{d\phi }{dt} \\\\emf = N ( \frac{\phi _2 - \phi_1}{t} )\\\\emf= N(\frac{BAsin\ 60 - BAsin\ 90}{t} )\\\\emf = NBA(\frac{sin60 - sn90}{t} )\\\\-0.058 = 500(6\times 10^{-4})\times B\times (\frac{0.866 - 1}{15} )\\\\-0.058 = -0.00268B\\\\B = \frac{0.058}{0.00268} \\\\B = 21.65 \ T[/tex]
Thus, the magnitude of the magnetic field in the coil is 21.65 T.
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As the distance between two objects changes, how does the gravitational force between them change?
Answer:
Explanation:
The gravitational force = G * m1 * m2 / r^2
That means as the distance increases, r get's bigger and m1 and m2 don't change, the force decreases. Read that sentence carefully. In physics, it is very important to know what goes up and goes down means and especially why.
Power of an electric motor is 1 h.p. what does it mean ?
Answer: HP = Horse Power.
Explanation: it is the unit given to tell the motor's particular power and 1hp = 746 watts.
Arthur (mass 79 kg) and Violet (mass 50 kg) are trying to play on a seesaw. If Violet sits 4 m from the fulcrum, at what distance from the fulcrum should Arthur sit
Hi there!
There are two torques acting on the system:
τ (Arthur) = RW = R(790N)
τ (Violet) = RW = 4(500N) = 2000N
∑τ = 0 = τ(Violet) - τ(Arthur)
Thus:
τ(Violet) = τ(Arthur)
2000 = 790R
R ≈ 2.53m
Thirty Joules of energy are transferred out of a system. The energy is lost through heat, mechanical, and electrical energy. If mechanical energy took up 10 J and electrical energy took up 5 J, how many Joules were lost through heat energy?
OPTIONS
5 J
15 J
30 J
45 J
Answer:
its 15 J i belive
Explanation:
If two stars are in a binary system with a combined mass of 5.5 solar masses and an orbital period of 12 years, what is the average distance between the two stars
The average distance between the two stars is 792 light years
Let the mass of the first star be [tex]m_1[/tex]
Let the mass of the second star be [tex]m_2[/tex]
The combined mass of the two stars, [tex]m_1+m_2=5.5[/tex] solar masses
The orbital period of the stars, P = 12 years
Average distance between the two stars, D = ?
The average distance between the two stars can be calculated using Kepler's equation
[tex]D=(m_1+m_2)P^2[/tex]
Substitute [tex]m_1+m_2=5.5[/tex] and P = 12 into the formula [tex]D=(m_1+m_2)P^2[/tex]
[tex]D=5.5(12^2)[/tex]
D = 5.5(144)
D = 792 light years
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An object has an acceleration of 6.0 m/s/s. If the NetForce was tripled and the mass was halved, then the new acceleration would be _____ m/s/s
Hi there!
We know that:
∑F = ma
If you tripled the net force and halved the mass:
3F = 1/2ma
Rearrange for 'a':
3F × 2 = ma
6F = ma
Thus, the new acceleration would be 6 times the original, or 36 m/s².
The diagram shows what happened in the Rutherford and Marsden scattering experiment. Complete this sentence: The particle shown in red will come straight back from the foil because it is __________ by the charge in the gold nucleus.
From Rutherford and Marsden scattering experiment, we can conclude that the particle shown in red will come straight back from the foil because it is deflected by the charge in the gold nucleus.
Rutherford proposed Planetary model atom, which visualized an atom to consists of a positively charged heavy core called the nucleus around which negatively charged electrons circle in orbits much as planets move round the sun
Thus, from Rutherford and Marsden scattering experiment, we can conclude that the particle shown in red will come straight back from the foil because it is deflected by the charge in the gold nucleus.
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the answer is reflected or u can say repelled
A helicopter travelling at a velocity of 15 m/s [W] accelerates uniformly at a rate of 7.0 m/s2 [E] for 4.0 s. What is the helicopter’s final velocity?
If we take West to be the negative direction, then the initial velocity is -15 m/s and the acceleration (which points East) is +7.0 m/s².
After t = 4.0 s, the helicopter's velocity is
-15 m/s + (7.0 m/s²) (4.0 s) = +13 m/s
or 13 m/s [E].
Please find attached photograph for your answer.
Hope it helps.
Do comment if you have any query.
Which is true of the intensity of sound?
Answer:
c.
Explanation:
1 Loudness and pitch are two important properties of a musical sound.
a If a musician plays a softer note, which property has been changed,
loudness or pitch?
b If the musician makes the note lower, which property has been
changed, loudness or pitch?
Calculate the relative molecular of calcium carbonate
* as following method*
Answer:
100.22
Explanation:
Have a great day!
The student investigates how the resistance of a thermistor varies with temperature. The student has a power supply, a thermistor, an ammeter, a voltmeter and some connecting leads. Describe an investigation the student could carry out to measure the resistance of a thermistor between –10 °C and 70 °C.
Your answer should include:
1. Any other apparatus the student will need
2. The measurements to be taken
3. How the data should be processed.
(This question is worth 6 marks on my assignment so I just really want to get down the best possible answer for it.)
The characteristics of the thermistors allow to design an experiment to analyze the dependence of resistance with temperature;
1) We set up the circuit
2) We look for the current of the circuit and we keep it fixed.
3) We look for the thermistor resistances for each temperature.
4) Plot Resistance versus Temperature.
A Thermitor is an element whose resistance changes with temperature, for example a platinum resistance.
An experiment that we can carry out to measure is to set up the attached circuit where we have:
A DC power supply. A resistor to control the maximum current in the circuit and avoid thermal problems in the thermistor. A thermistor. A thermometer placed next to the thermistor. A source of heat under the thermistor under a glass with ice and water, but without affecting the other elements of the circuit.
Let's start by looking for the current in the circuit.
In thermistors, the resistance for room temperature is given, so if we measure the voltage across the fixed resistor, we can shrink the voltage across the thermistor.
[tex]V_{source} = V_R + V_{therm} \\V_{therm} = V_{source} - V_R \\ i = \frac{V_{therm} }{R_{therm}}[/tex]
This current remains fixed, since the fixed resistance is greater than the resistance of the thermistor throughout the range.
Second step.
Now we can change the temperature that is measured in the thermometer, for each temperature the voltage in the fixed resistance is measured, the resistance in the thermistor is calculated.
[tex]R_{therm} = \frac{V_{source} - V_R}{i}[/tex]
Third step.
We end with a graph of resistance versus temperature of the curve obtained, it is possible to understand the behavior of the resistance of the thermistor with temperature.
In conclusion with the characteristics of thermistors we can design an experiment to analyze the dependence of resistance with temperature:
1) We set up the circuit
2) We look for the current of the circuit and we keep it fixed.
3) We look for the thermistor resistances for each temperature.
4) Plot Resistance versus Temperature.
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A person drops two objects from the same height. One object weighs 15 N, and the other weighs 10 N. How does the mass of the objects relate to the force of gravity on them? A. The 10 N object has the same mass as the 15 N object. B. The 10 N object has more mass than the 15 N object. C. The 15 N object has twice the mass of the 10 N object. D. The 15 N object has more mass than the 10 N object. SUR
Answer:
Your answer would be D :)
Explanation:
An object with a higher mass will always fall faster due to gravity acting upon it. 15 N is more massive than the 10 N object, so statement D is correct.
An object weights 1000N on the earth’s surface. [ g=10N/Kg]
Calculate its mass
Answer: An object weights 1000N on the earth's surface. ... Calculate its mass ... strength is 10 N/kg how many newtons does a 30kg object weigh.
Explanation:
PLEASE ANSWER ASAP
A 5 kg bowling ball traveling at 2 m/s hits a motionless 10 kg bowling ball. If the smaller ball bounces back at a speed of -1 m/s, what will be the speed of the larger ball after the collision?
Hi there!
Recall the conservation of momentum:
m1v1 + m2v2 = m1v1' + m2v2'
Let m1 = 5 kg ball and m2 = 10 kg ball
Since m2 is at rest, we can rewrite:
m1v1 = m1v1' + m2v2'
Plug in the given values:
5(2) = 5(-1) + 10v2'
Solve for v2':
10 = -5 + 10v2'
15 = 10v2'
15/10 = 1.5 m/s
We know that,
m1v1 + m2v2 = m1v1' + m2v2'
5 x 2 + 0 = 5 x -1 + 10 x v2'
10= -5 +10 x v2'
15 = 10 x v2'
v2' = 15/10
v2' = 1.5 m/s
hence , the speed of the larger ball after the collision will 1.5m/s
atom a has an atomic number of 40 atom b has an atomic number of 20 and a mass of 40 which of these is an accurate statement
Answer:14
Explanation:cuz
what are the three different ways to tell the difference between a solar and lunar eclipse?
Answer:
Solar eclipses occur when the Moon passes between Earth and the Sun, leaving a moving region of shadow on Earth's surface. Lunar eclipses occur when Earth passes between the Sun and the Moon, casting a shadow on the Moon. This is an annular eclipse.
(credits to "britannica")
Explanation:
An amateur astronomer has just discovered a dwarf planet in an orbit past Pluto. Choose the best unit of measure to describe how far out in the solar system it is from the Sun.
I=24
Q=400C
t=102
Help please
[tex] \huge \bf༆ Answer ༄[/tex]
The given terms in the question are : -
I = Electric current = 2 AmperesQ = Charge = 400 CoulombsWe have been given the task to find out time (t)
The formula that can be used to find time is : -
[tex] \sf \: I = \dfrac{ Q}{t}{} [/tex]
Rearrange the formula,
[tex] \sf \: t = \dfrac { Q}{I }[/tex]
Solve for time (t)
[tex] \sf t = \dfrac{400}{2} [/tex][tex] \sf t = 200 \: \: sec[/tex][tex]꧁ \: \large \frak{Eternal \: Being } \: ꧂[/tex]
Question 2
You can make the puck travel in complex ways by placing a set of charges around on the field. So, here’s your game challenge:
Arrange sources charge around to propel the puck from its starting position into the goal. That’s pretty easy for a straight shot; you just put a negative charge behind the goal. But what if there are barriers along the way? This is a real test of your physical understanding, including Newton’s laws of motion and electrostatic forces. Game’s on!
Part A
On the control bar, check the Trace and Field boxes. The game has three Difficulty levels. Start with Difficulty level one and arrange source charges to get the puck into the goal. Once you’ve made a score at any level, increase the Difficulty level. Take a screen capture of two of your most difficult goals and paste them here. At least one of these should be at Difficulty level 2 or 3.
Answer:
A. The electric field lines point outward and the black puck moves backwards. From this I can see that I can't put the red charge in front of the black puck because it will go away from the goal.
B. The electric field lines point inward and the black puck moves forwards and backwards. The conclusion I made from this was the blue charge by itself will not be able to get into the goal.
C.The puck moves faster when the mass increases and moves slower when the mass decreases. The more mass, the more force that is applied to the puck.
D. The relationship between the speed of the black puck and its distance from the blue charge is when the puck is further away from the blue charge, the slower the puck moves away from it.
Explanation:
Brainlest if this helped!
What is its time interval between the release of the ball and the time it reaches its maximum height? Its initial vertical speed is 9 m/s and the acceleration of gravity is 9.8 m/s 2 . Neglect air resistance.
Answer:
The time to reach max height is h = 1/2 g t^2
The time to fall is the same as that for an equivalent rise
m g h = 1/2 m v^2 KE vs PE
Here: (Vf - VI) / g = t = -9 / -9.8 = .92 s
2. In a race, if a runner starts and stops at the same position, what is their
displacement? *
Answer:
It is the same
Explanation:
I Jsut know
A body is accelerated constantly. What is the form of the graph? A. cubic. B. inverse. C. linear. D. quadratic.
Answer:
D is the correct answer for this question.
Explanation:
I had done this already
Glucose typically enters the cell through which mechanisms
Answer:
facilitated diffusion
Which of the following are for vector directione?
A Outside 45 degrees
G 35 degrees north of east
D 35 degrees inside
Can anyone help out with this question?
I'll mark as brainliest
Thankyou.
Answer:
p=I×B
Explanation:
If a current 'I' flows through a given element in your circuit, losing voltage 'V' in the process, then the power 'P' dissipated by that circuit element is the product of that current and voltage.
why does the energy of characteristic x rays tend to increase for heavier elements?
The energy of characteristic x rays tend to increase for heavier elements
because the charge of the nucleus increases.
X ray is a form of an electromagnetic spectrum and the energy is directly
proportional to the charge of the nucleus. This implies that an increase in
the nucleus charge will lead to a corresponding increase in x ray energy
and vice versa.
X rays energy is also usually more in heavier elements than when
compared to lighter elements
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1+1 =?
2+2=?
3+3=?
1+1 =?
2+2=?
3+3=?
Answer:
here is your answer
1+1=2
2+2=4
4+4=8
Plzzzz help meeeeee plzzz
hun I wish I can help you but I have the same problem here!! sorry