Find the measure of the indicated arc

Answer:

x = -20/11

Step-by-step explanation:

and how -(11 x)/4 - 5 = 0

1/4 (7 x - 12) = 1/2 (9 x + 4)

hope this helps

Answer:

X = 11/20

Step-by-step explanation:

7/4x-3=2+9/2x

We move all terms to the left:

7/4x-3-(2+9/2x)=0

Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R

Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R

We add all the numbers together, and all the variables

7/4x-(9/2x+2)-3=0

We get rid of parentheses

7/4x-9/2x-2-3=0

We calculate fractions

14x/8x^2+(-36x)/8x^2-2-3=0

We add all the numbers together, and all the variables

14x/8x^2+(-36x)/8x^2-5=0

We multiply all the terms by the denominator

14x+(-36x)-5*8x^2=0

Wy multiply elements

-40x^2+14x+(-36x)=0

We get rid of parentheses

-40x^2+14x-36x=0

We add all the numbers together, and all the variables

-40x^2-22x=0

a = -40; b = -22; c = 0;

Δ = b2-4ac

Δ = -222-4·(-40)·0

Δ = 484

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:

x1=−b−Δ√2ax2=−b+Δ√2a

Δ−−√=484−−−√=22

x1=−b−Δ√2a=−(−22)−222∗−40=0−80=0

x2=−b+Δ√2a=−(−22)+222∗−40=44−80=−11/20

Answer:

A

Step-by-step explanation:

I am to determine the future value of Thomas' deposit with annual compounding

The formula for calculating future value:

FV = P (1 + r)^n

FV = Future value  

P = Present value  

R = interest rate  

N = number of years  

840 x (1.075)^5 = 1205.93

I am to determine the future value of Sherill's deposit in 5 years using simple interest

The amount that would be in the account = amount deposited + interest earned on deposit

interest earned on deposit can be determined by determining the simple interest

Simple interest = amount deposited x time x interest rate

1250 x 0.069 x 5 = 431.25

Amount that would be in her account after 5 years = 1250 +  431.25 =  1681.25

Sheril's money is higher by - 1681.25 -  1205.93 = 475.32

Answer:

She has completed 4 problems

Step-by-step explanation:

Take the total number of problems and multiply by the percent completed

20 * 20%

20 * .20

4

She has completed 4 problems

Answer:

4

Step-by-step explanation:

Answer: 9.

Step-by-step explanation:

6 large rooms which will add up to 18

9 small rooms which will also add up to 18 totaling the 36 guests.

The no. of small and large rooms in the hotel are 9 and 6 respectively.

A linear equation is an algebraic equation of degree one. In general, the variable or the variables(in the case of a linear equation in two variables) the variables are x and y.

Given, Emily is blocking off several rooms in a hotel for guests coming to her wedding.

Let us assume that small rooms be x and large rooms to be y.

Emily booked a total of 15 rooms which is x + y = 15...(i).

which can accommodate 36 guests altogether which is 2x + 3y = 36...(ii)

Now if we multiply eqn(i) by 2 it'll be 2x + 2y = 30...(iii)

Now subtracting eqn(iii) from eqn(ii) we get y = 6.

substituting the value of y in eqn(iii) we get x = 9.

So, the number of small rooms is 9 and no. of large rooms is 6.

learn more about linear equations here :

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Answer:

540

Step-by-step explanation:

area of trapezium is b×h

Answer:

540 Sq m

Step-by-step explanation:

Area of parallelogram EFGH

= base * height

= 30 * 18

= 540 Sq m

Answer:

[tex]X=85.123m[/tex]

[tex]Y=184.88m[/tex]

Step-by-step explanation:

From the question we are told that:

Campfire Bearing from Colonel[tex]x=N 71 \textdegree E[/tex]

Distance b/w Colonel and Sarge [tex]Z=235feet[/tex]

Campfire Bearing from Sarge [tex]y=N 45 \textdegree E[/tex]  

Generally the angles x' and y' are solved

[tex]x'=90 \textdegree-71 \textdegree[/tex]

[tex]x'=19 \textdegree[/tex]

[tex]y'=90 \textdegree-45 \textdegree[/tex]

[tex]y'=45 \textdegree[/tex]

Generally the angle z' is  solved

Sum of angles of a triangle is 180

Therefore

[tex]z'=180 \textdegree-(19+45) \textdegree[/tex]

[tex]z'=116 \textdegree[/tex]

Generally the sine rule equation for for all distances is mathematically given by

[tex]\frac{Z}{sinz'}=\frac{X}{sinx'}=\frac{Y}{siny}[/tex]

Generally the the distance b/w the Colonel and the campfire X is mathematically given as

[tex]\frac{235}{sin116}=\frac{X}{sinx'}[/tex]

[tex]\frac{235}{sin116}=\frac{X}{sin19}[/tex]

[tex]X=85.123m[/tex]

Generally the the distance b/w Sarge and the campfire X is mathematically given as

[tex]\frac{235}{sin116}=\frac{Y}{siny}[/tex]

[tex]\frac{235}{sin116}=\frac{Y}{sin45}[/tex]

[tex]Y=184.88m[/tex]

Question:

A particle moves along the x-axis so that its position at time t>0 is given by [tex]x(t)=\frac{t^2 -9}{3t^2 +8}[/tex]

Show that the velocity of the particle at time t is given by [tex]v(t) = \frac{70t}{(3t^2 + 8)^2}[/tex]

Answer:

[tex]v(t) = \frac{70t}{(3t^2 + 8)^2}[/tex]

Step-by-step explanation:

Given

[tex]x(t)=\frac{t^2 -9}{3t^2 +8}[/tex]

Required

Show that:

[tex]v(t) = \frac{70t}{(3t^2 +8)^2}[/tex]

To calculate v(t), we use:

[tex]v(t) = x'(t)[/tex]

So, we have:

[tex]x(t)=\frac{t^2 -9}{3t^2 +8}[/tex]

Apply quotient rule

[tex]x'(t) = \frac{vu' - uv'}{v^2}[/tex]

Where

[tex]u =t^2 - 9[/tex]

[tex]v=3t^2 + 8[/tex]

So:

[tex]u =t^2 - 9[/tex]

[tex]u' = 2t[/tex]

[tex]v=3t^2 + 8[/tex]

[tex]v' = 6t[/tex]

So, we have:

[tex]x'(t) = \frac{vu' - uv'}{v^2}[/tex]

[tex]x'(t) = \frac{(3t^2 + 8) * 2t - (t^2 - 9) * 6t}{(3t^2 + 8)^2}[/tex]

Expand the numerator

[tex]x'(t) = \frac{6t^3 + 16t - 6t^3 + 54t}{(3t^2 + 8)^2}[/tex]

Collect like terms

[tex]x'(t) = \frac{6t^3 - 6t^3+ 16t + 54t}{(3t^2 + 8)^2}[/tex]

[tex]x'(t) = \frac{70t}{(3t^2 + 8)^2}[/tex]

Recall that:

[tex]v(t) = x'(t)[/tex]

[tex]v(t) = \frac{70t}{(3t^2 + 8)^2}[/tex]

Proved

Answer:

C. 70%

Step-by-step explanation:

35 / 50 = 70/100 = 70%

So she will be 70% accurate in the next shot.

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

Answer:

C

Step-by-step explanation:

because d + Q = 19 is just counting the coins, not the monetary value

and .25q + .10d signs values per coin type.

Answer:

-3 = D

Step-by-step explanation:

A really smart freind of mine says this is the answer.

Answer:

a. x = 180 - (j + k)

b.

j + k = (5x - 2) + (2x - 2) = 7x - 4

l = x

x = 180 - (7x - 4)

x = 180 - 7x + 4

8x = 184

x = 184/8

x = 23

l = 23°

j = 5x - 2

j = 5 × 23 - 2

j = 115 - 2

j = 113°

k = 2x - 2

k = 2 × 23 - 2

k = 46 - 2

k = 44°

or k = 180 - (23 + 113) = 180 - 136 = 44°

Answer:

hello your question has a missing diagram attached below is the missing diagram

answer :  

Mark the point of intersection S of circles R and P, and construct line QS ( option 2 )

Step-by-step explanation:

when constructing a tangent line from one point ( lets say Q as seen in the question ) to a circle P. The next step should be to mark a point of intersection between  the given circles and then construct a line through it

Answer:

Mark the point of intersection S of circles R and P, and construct line QS.

Step-by-step explanation:

This is correct because after you create circle R that intersects circle p, you're supposed to mark the intersection points.  If your in FLVS, it would be in lesson 7.04.  I also got this right on my test.  Good luck!

Answer:

[tex]m=-\frac{1}{2}[/tex]

Step-by-step explanation:

[tex]\mathrm{Slope\:between\:two\:points}:\quad \mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}[/tex]

[tex]m=\frac{9-10}{6-4}[/tex]

Answer:

£1500

Step-by-step explanation:

If Dan starts out with £1200 and he gets 5% per year compound interest you would multiply 1200×0.05 and get 60, this is the amount of money that was collected with interest every year. Now you need to multiply 60×5 and get 300. With the total interest over 5 years we need to add the interest and the original amount which would be 1200+300=1500.

Answer:

Midpoint (-2,4)

distance nearest tenth = 8.9

The approximate distance = 9

Step-by-step explanation:

Formulas

PQ midpoint = (x2 + x1)/2, (y2 + y1)/2

distance d = sqrt( (x2 - x1)^2 + (y2 - y1)^2 )

Givens

x2 = -4

x1 = 0

y2 = 1

y1 = 7

Solution

M(PQ) = (-4+0)/2, (1 + 7)/2

M(PQ) = -2, 4

The midpoint is -2,4

The distance = sqrt( (4 - 0)^2 + (1 + 7)^2 )

The distance = sqrt(16 + 64)

The distance = sqrt(80)

The distance = 4√5           exactly

The distance = 8.94    

The distance = 8.9            To the nearest tenth

Question 2

The distance is rounded to the nearest whole number which is 9.

Answer:

B. 44°

Step-by-step explanation:

Central angle = 3x + 10°

Inscribed angle = 2x - 17°

Now

Central angle = 2 * inscribed angle

( Central angle is double of the inscribed angle standing on same arc)

3x + 10° = 2 ( 2x - 17°)

3x + 10° = 4x - 34°

4x - 3x = 34 ° + 10°

x = 44°

Hope it will help :)❤

Answer:

1. 11x + 11.  2. 3x - 4.

Step-by-step explanation:

sorry if im wrong

Answer:

5 / 8

Step-by-step explanation:

Total possible outcomes = (1, 2, 3, 4, 5, 6, 7, 8)

Odd outcomes = (1, 3, 5, 7)

Outcomes > 7 = 8

Required outcomes = (1, 3, 5, 7, 8)

Number of required outcomes = 5

P(pointer stops on odd or number > 7) = required outcome / Total possible outcomes

P(pointer stops on odd or number > 7) :

= 5 / 8

Answer:

hjrkfkfkfof

Step-by-step explanation:

jfkfbfhrhrnrjdur rier

C=160 degrees because it is the same angle as the known angle, 160+160=320

leaving 40 degrees unknown,

2 angles left that are the same angle meaning that b=20 degrees

Answer:

-2

Step-by-step explanation:

Given equation

x - 2y = 4

2y = x - 4

y = ( x - 4 ) / 2

y = x/2 - 4 /2

y = x/2 - 2

Comparing with y = mx + b

y-intercept (b) = - 2

Hope it will help :)❤

Answer:gamma

Step-by-step explanation:alpha and beta can be stopped more easily

Answer:

[tex]x^2+y^2=9[/tex]

Step-by-step explanation:

Equation of a circle (when centred at the origin):

[tex]x^2+y^2=r^2[/tex] where r is the radius of the circle

Plug in the point (0,3) to solve for the radius squared

[tex]0^2+3^2=r^2\\9=r^2[/tex]

Plug r² back into the original equation

[tex]x^2+y^2=9[/tex]

I hope this helps!

Answer:

B

Step-by-step explanation:

Use the definition of a logarithm,  log b ( x ) = y  ⟹  b y = x , to convert from the logarithmic form to the exponential form. 10^ 4 = x

The exponential equation out of the specified options that is equivalent to this logarithmic equation log x = 4 is given by: Option B: 10^4 = x

When you raise a number with an exponent, there comes a result.

Lets say you get [tex]a^b = c[/tex]

Then, you can write 'b' in terms of 'a' and 'c' using logarithm as follows

[tex]b = \log_a(c)[/tex]

'a' is called base of this log function. We say that 'b' is the logarithm of 'c' to base 'a'

Log with base e = 2.71828... is written as [tex]\ln(x)[/tex] simply.

Log with base 10 is written as [tex]\log(x)[/tex] simply.

The given logarithmic equation is;

[tex]\log x = 4[/tex]

Since, log with base 10 is written as [tex]\log(x)[/tex] simply, therefore, we have:

[tex]\log_{10} x = 4[/tex]

Using the definition of logarithm, we get;

[tex]x = 10^4[/tex]

Equivalently, [tex]10^4 = x[/tex] (option B).

Thus, the exponential equation out of the specified options that is equivalent to this logarithmic equation log x = 4 is given by: Option B: 10^4 = x

Learn more about logarithm here:

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Answer:

Area:12.5663706            Circumference: 12.5663706

Step-by-step explanation:

Answer:

$20.30  plus tax

Step-by-step explanation:

You multiply 28 x .30 and that is your discount.

Answer:

$20.30

Step-by-step explanation:

Answer: 1

Step-by-step explanation: