EXPLANATION
The expression for the midpoint is as follows:
[tex]\text{Midpoint}=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})[/tex]Where (x_1,y_1) = E = (-8,4) and (x_2,y_2) = F = (3,-2)
Substituting terms:
[tex]\text{Midpoint}=(\frac{-8+3}{2},\frac{4-2}{2})[/tex]Adding numbers:
[tex]\text{Midpoint}=(-\frac{5}{2},1)[/tex]In conclusion, the midpoint is at (-5/2, 1)
Given the inequalities y < 2x + 2 and y> x-7 graphed on the same coordinategrid, which of the following coordinates gives a true statement?A. (-2,2)B. (4,0)C. (0,4)D. None of the above
we have a system of inequalities
y<2x+2
y>x-7
The solution of the given system is the shaded area below the dashed line y=2x+2 and above the dashed line y=x-7.
If an ordered pair is a solution of the system, then the ordered pair must lie on the shaded region of the solution
using a graphing tool
we have the points
(-2,2)
(4,0)
(0,4)
A solution is the point (4,0)
The answer is the option Cquestion is in the image Don't graph. I can do that
Given:
[tex]\begin{gathered} f(x)\text{ = }\frac{1}{2}(4)^x \\ g(x)\text{ = -}\frac{1}{2}(4)^x \end{gathered}[/tex]The value of the function at any point is obtained by substituting the point into the function.
f(0):
[tex]\begin{gathered} f(0)\text{ = }\frac{1}{2}(4)^0 \\ =\text{ }\frac{1}{2} \end{gathered}[/tex]f(1):
[tex]\begin{gathered} f(1)\text{ = }\frac{1}{2}(4)^1 \\ =\text{ 2} \end{gathered}[/tex]g(0):
[tex]\begin{gathered} g(0)\text{ = -}\frac{1}{2}(4)^0 \\ =-\frac{1}{2} \end{gathered}[/tex]g(1):
[tex]\begin{gathered} g(1)\text{ = -}\frac{1}{2}(4)^1 \\ =\text{ -2} \end{gathered}[/tex]equations with parentheses answer for 4(3 +c) = c+4
Given:
4(3 + c) = c + 4
Let's solve for c.
Expand the parenthesis using distributive property:
4(3)
I don't know how to begin or try this problem
length =24, width =15
1) The best way to tackle this question is by sketching this out:
2) We can think of it as a rectangle whose area is 360yd². Since the farmer has 54 yds we can write out this:
We can set two equations: one evolving the sum of three sides and the other one the area:
[tex]\begin{gathered} 2b+h=54 \\ bh=360 \\ ----- \\ 2b=54-h\Rightarrow b=27-\frac{h}{2} \\ bh=360 \\ (27-\frac{h}{2})h=360 \\ \\ 27h-\frac{h^2}{2}=360 \\ -\frac{h^2}{2}+27h-360=0 \\ \frac{h^2}{2}-27h+360=0 \\ h=\frac{27\pm\sqrt[]{(27)^2-4(\frac{1}{2})(360)}}{2(\frac{1}{2})} \\ h=24 \\ --- \\ 2b+24=54 \\ 2b=54-24 \\ 2b=30 \\ b=15 \end{gathered}[/tex]__ + (-3) = 0Which number goes in the box to make the number sentence true?A. -6B. -3c. OD. 3E. 6
Given data:
The given expression is __ + (-3) = 0.
The given expression can be written as,
[tex]\begin{gathered} x+(-3)=0 \\ x-3=0 \\ x=3 \end{gathered}[/tex]Thus, the correct option is (D).
Fill in the blank below with the correct units.A) David went skiing on a mountain that is about 2 ____ high.A: millimetersB: centimetersC: metersD: KilometersB) Justin squeezed an orange and got about 70 ______ of juice.A: MillilitersB: LitersC) Diane's pet dog has a mass of 7 _____.A: GramsB: Kilograms
We must analyze the statements to find the solution.
We must find the unit that corresponds to the magnitude.
A) David went skiing on a mountain that is about 2 ____ high.
D: Kilometers
B) Justin squeezed an orange and got about 70 ______ of juice.
A: Milliliters
C) Diane's pet dog has a mass of 7 _____.
B: Kilograms
1. What inequality represents the sentence?(1 point)C0UThe product of a number and 12 is no more than 15.12n< 15O12n > 1512n > 1512n<15hjb
First, the product of a number and 12 can be wu
Write an equation of the line passing through (-2,7) and having slope -5 . Give the answer in slope-intercept form.The equation of the line in slope-intercept form is enter your response here.
The line passes through (-2, 7) and m = - 5.
Slope-intercept form: y = mx + b; then:
7 = (-5)(-2) + b
7 = 10 + b
b = -3
y = -5x - 3
An architect's sketch of plans for the front of a garage in the shape of pentagon is shown below. What is the approximate perimeter of thefront of the garage?-8-6 -4 -2A. about 36 ftB. about 21 ftC. about 10 ftD. about 77 ft
Using the given pentagon, let's find the perimeter.
From the graph, we can deduce the vertices of the pentagon below:
(0, 9.5), (5.5, 7), (5.5, 0), (-5.5, 0), (-5.5, 7)
Let's find the perimeter.
To find the perimeter, let's first find the length of each side using the distance formula:
[tex]d=\sqrt{(x_2-x_1)^2+(y_2+y_1)^2}[/tex]Now, let's label the figure:
Thus, we have the following:
• Length of AB:
Where:
(x1, y1) ==> (0, 9.5)
(x2, y2) ==> (5.5, 7)
We have:
[tex]\begin{gathered} AB=\sqrt{(5.5-0)^2+(7-9.5)^2} \\ \\ AB=\sqrt{(5.5)^2+(-2.5)^2} \\ \\ AB=\sqrt{30.25+6.25}=\sqrt{36.50} \\ \\ AB=6.04\text{ ft} \end{gathered}[/tex]The length of AB = 6 ft
Also the length of AE will be 6 ft.
• Length of BC:
Where:
(x1, y1) ==> (5.5, 7)
(x2, y2) ==> (5.5, 0)
Thus, we have:
[tex]\begin{gathered} BC=\sqrt{(5.5-5.5)^2+(0-7)^2} \\ \\ BC=\sqrt{0+(-7)^2} \\ \\ BC=7\text{ ft} \end{gathered}[/tex]The length of BC = 7 ft
The length of DE will also be 7 ft.
• Length of CD:
Where:
(x1, y1) ==> (5.5, 0)
(x2, y2) ==> (-5.5, 0)
Thus, we have:
[tex]\begin{gathered} CD=\sqrt{(5.5-(-5.5))^2+(0-0)^2} \\ \\ CD=\sqrt{(5.5+5.5)^2} \\ \\ CD=\sqrt{11^2} \\ \\ CD=11\text{ ft} \end{gathered}[/tex]Therefore, we have the following side lengths.
• AB = 6 ft
,• BC = 7 ft
,• CD = 11 ft
,• DE = 7 ft
,• AE = 6 ft
To find the perimeter, let's sum up the side lengths:
Perimeter = AB + BC + CD + DE + AE
Perimeter = 6 + 7 + 11 + 7 + 6
Perimeter = 37 ft
Therefore, the perimeter of the front garage is about 36 ft.
• ANSWER:
A. about 36 ft.
Graph the solution set of the following linear inequality:2y < 2x + 4AnswerKeypadKeyboard ShortcutsThe line will be drawn once all required data is provided and will update whenever a value is updated. Theregions will be added once the line is drawn.101Choose the type of boundary line:Dashed -O Solid (-) O--)5Enter two points on the boundary line:10--5310Select the region you wish to be shaded:5ОАOB19
Explanation
[tex]2y<2x+4[/tex]
To graph an inequality, treat the <, ≤, >, or ≥ sign as an = sign, and graph the equation. If the inequality is < or >, graph the equation as a dotted line. If the inequality is ≤ or ≥, graph the equation as a solid line.
Step 1
a)isolate y in the inequality
[tex]\begin{gathered} 2y<2x+4 \\ \text{divide both sides by 2} \\ \frac{2y}{2}<\frac{2x+4}{2} \\ y=\frac{2x+4}{2}=\frac{2x}{2}+\frac{4}{2} \\ y=x+2\Rightarrow\text{ Line} \end{gathered}[/tex]Step 2
draw the line:to do that we need 2 points from the line
a) for x=0
[tex]\begin{gathered} y=x+2 \\ \text{replace} \\ y=0+2=2 \\ \text{hence} \\ \text{Point 1(0,2)} \end{gathered}[/tex]b)for x= 3
[tex]\begin{gathered} y=x+2 \\ \text{replace} \\ y=3+2=5 \\ \text{hence} \\ \text{Point 1(3,5)} \end{gathered}[/tex]c) draw a dotted line that passes trought point 1( 0,2) and point 2 (3,5)
d) as we are searching for the y values smaler thatn the function
[tex]ywe need to take the area under the linetherefore, the answer is
Find x and y.[A] x = 24; y = 12[B] x=27; y = 12[C] x = 24; y = 9[D] x = 27: y = 9
Sum of angle in a straight line = 180 degrees
So, (9x - 9y) + 72 = 180--------1
Also
(-4x + 14y) = 72-------2 ( they are corresponding angles)
From equation 1
9x -9y = 180 -72
9x - 9y = 108
divide through by 9
x - y = 12
x = 12 + y
Substitute x = 12 + y in equation 2
- 4 ( 12 + y) + 14y = 72
-48 -4y + 14y = 72
10y = 72 + 48
10y = 120
y = 120/10 = 12
Substitute y = 12 in x = 12 +y
x = 12 + 12 = 24
Thus the solutions are x= 24 , y = 12 (option A)
What is the shape of the distribution shown below Choose 1 answer
Answer: The distribution is symmetrical
Simplify 8* (9 + 2 ) - 6 / 2
solution
[tex]\begin{gathered} 8\times(9+2)-6/2 \\ 8\times(11)-3 \\ 88-3 \\ 85 \end{gathered}[/tex]answer: 85
What is the solution to the system of equations? O (-6, -2) O (-2, 6) O (2,-4) O (4,2)
Given the system of equations:
2x - 3y = -6
y = -⅓x - 4
To find the solution to the system, graph both lines.
The point of intersection will be the solution.
Thus, we have the graph attached below:
From the graph above, we can see that both lines intersect ( meet each other) at (-6, -2)
Quadratic: y = - x2 - 4x - 1 Step 1: Identify the coefficients a = ? b = ? C = ? a = 1. b = 4, and c = 1 a = -1. b = -4, and c = 1 a = 1. b = -4. and C = -1 a = - 1. b = -4. and C = -1
The general quadratic equation is:
y = ax² + bx + c
where a, b, and c are the coefficients
In the case of
y = -x² - 4x - 1
the coefficients are:
a = -1
b = -4
c = -1
A suit being sold for $268 has a 33% discount.Find the original cost of the suit.
Let x represent the original cost of the suit.
To calculate the discount, they calculated the 33% of the original price and then subtracted the result from the original price.
To calculate the 33% of any given value you have to do as follows:
33/100=0.33
0.33x → represents the 33% of the original price.
The price with discount was obtained by subtracting the 33% discount from the original price, symbolically:
x-0.33x=268
Clear the value of x:
[tex]\begin{gathered} 0.67x=268 \\ x=\frac{268}{0.67} \\ x=400 \end{gathered}[/tex]The original price of the suit is $400
Is 15.1 greater than 1480.8?
ANSWER
1480.8 is greater than 15.1
EXPLANATION
We want to find which number is greater between 15.1 and 1480.8
We see that the highest place value in the number 15.1 is Tens, i.e.:
T U Tnth
1 5 . 1
While in 1480.8, the highest place value is Thousands, i.e.:
T H T U Tnth
1 4 8 0 . 8
Since Thousands is greater than Tens, we see that 1480.8 is greater than 15.1
Can u please help me solve? I am reviewing for a final, ty
Solution
Part A : The students verify the two identity very well and it was properly
solved
[tex]\begin{gathered} sin^2x+cos^2x=1 \\ sin^2x=1-cos^2x \\ cos^2x=1-sin^2x \end{gathered}[/tex]reason why the substitution work for both students
Also the inverse of identity like
[tex]\begin{gathered} \frac{1}{sinx}=cosecx=cscx \\ \frac{1}{tanx}=cotx \\ where \\ tanx=\frac{sinx}{cosx} \\ cotx=\frac{cosx}{sinx} \end{gathered}[/tex]Therefore the two identity that where used by students A's is
[tex]\begin{gathered} cos^2x=1-sin^2x \\ \frac{1}{sinx}=cscx \end{gathered}[/tex]The first one appear in Step 3, while the second one appear in Step 5
someone help me with this question..this is a practice question
Answer:
68
Explanation:
We start with the mode:
[tex]\text{Mode}=l+\frac{(f_1-f_0)\times h}{(2f_1-f_0-f_2)}[/tex]Where the terms are defined as follows:
[tex]\begin{gathered} l=\text{lower limit of the modal class} \\ f_1=\text{frequency of the modal class} \\ f_0=\text{frequency of the class before the modal class} \\ f_2=\text{frequency of the class after the modal class} \\ h=\text{size of the class interval} \end{gathered}[/tex]From the table, the modal class is 65-69.
Therefore:
[tex]\begin{gathered} l=\text{6}5 \\ f_1=\text{1}9 \\ f_0=\text{1}0 \\ f_2=\text{1}3 \\ h=\text{5} \end{gathered}[/tex]We substitute into the formula:
[tex]\begin{gathered} \text{Mode}=65+\frac{(19-10)\times5}{(2\times19-10-13)} \\ =65+\frac{9\times5}{15} \\ =65+\frac{45}{15} \\ =65+3 \\ =68 \end{gathered}[/tex]The mode of the given data is 68.
Which equation can be used to generate the following set of ordered pairs?(-5,20), (0,-5), (1,-4)(4,11) A. y = -6x - 10B. y = x^2 - 5C. y = x + 25D. y = 2x + 3
Given the ordered pairs of points:
(-5, 20), (0, -5), (1, -4), (4, 11)
Let's dtetermine the equation that can be used to generate the given set of ordered pairs.
Input the value of x and y in the equation, if the equation turns out to be true, i.e the left side equals the right side for all ordered pairs, then the equation can be used to generate the set of ordered pairs.
Let's start from the first equation.
• Equation A.
y = -6x - 10
(-5, 20)
Substitute -5 for x and 20 for y:
20 = -6(-5) - 10
20 = 30 - 10
20 = 20
(0, -5):
Substitute 0 for x and -5 for y:
-5 = -6(0) - 10
-5 = 0 - 10
-5 ≠ -10
Since this equation is not true for the second ordered pair, this equation A cannot be used to generate the given set of ordered pairs.
• Equation B.
y = x² - 5
(-5, 20):
Substitute -5 for x and 20 for y
20 = -5² - 5
20 = 25 - 5
20 = 20
(0, -5):
Substitute 0 for x and -5 for y
-5 = 0² - 5
-5 = 0 -5
-5 = -5
(1, -4):
Substitue 1 for x nd -4 for y
-4 = 1² - 5
-4 = 1 - 5
-4 = -4
(4, 11)
Substitute 4 for x and 11 for y
11 = 4² - 5
11 = 16 - 5
11 = 11
Here, the equation is true for all set of ordered pairs. Therefore, we can say this equation (y = x² - 5) can be used to generate the given set of ordered pairs.
ANSWER:
B. y = x² - 5
9. Six months later, there were no tricycles in the shop. There were onlybicycles and tandem bikes. There are a total of 68 seats and 120 wheels inthe shop. Let: B be the bicycles and N be the tandem bikes. How do youtranslate this into mathematical equations? *
Each bicycle has 2 wheels and 1 seat, and each tandem bike has 2 wheels and 2 seats. So, we can write this mathmatically by writing one equation for the amount of seats and one for the amount of wheels.
If each bicycle has 2 wheels and each tandem bike also have 2 wheels, then the total number of wheels, 120, will be:
[tex]\begin{gathered} 2B+2N=120 \\ 2(B+N)=120 \\ B+N=60 \end{gathered}[/tex]Smilarlly, if each bicycle has 1 seat and each tandem bike has 2 seats, then the total number of seats, 68, will be:
[tex]\begin{gathered} 1B+2N=68 \\ B+2N=68 \end{gathered}[/tex]So, in the end, we have a system of two equations:
[tex]\begin{gathered} B+N=60 \\ B+2N=68 \end{gathered}[/tex]Determine if I II m based on the information given on the diagram. If yes, state the converse that roves the lines are arallel.
Looking at the diagram, there is a transversal cutting across lines m ans n. The angles formed are congruent because they are 90 degrees. We can see that the angles are in similar positions and in the same side of the transversal. This means that they are corresponding angles.
Recall the corresponding angles postulate which states that if corresponding angles are congruent when two lines are crossed by a transversal, then the two lines crossed by the transversal are parallel
Thus,
line l is parallel to line m
The correponding angles converse prove that they are parallel
Jane is standing 1000’from the base of the Washington Monument.She discovers that the angle of elevation is about 29 degrees.About how tall is the Washington Monument.
Hello there. To solve this question, we'll need to remember some properties about trigonometry.
Let's start by drawing the situation:
Since we don't know Jane's height, we don't need to consider the point of view starting by her eye height. In this case, we can solve directly for the height of the monument.
For this, we'll use the tangent. This trigonometric function relates the opposite side to an angle to its adjacent side by the following ratio:
[tex]\tan (\alpha)=\frac{opposite\text{ side}}{\text{adjacent side}}[/tex]Using opposite side as h (for height), adjacent side is the distance between Jane and the monument, 1000 and alpha equals to the angle 29º, we have:
tan(29º) = h/1000
Multiply both sides of the equation by 1000
h = 1000tan(29º)
Using a calculator, we have that tan(29º) is approximately equal to 0.5543
Hence, we have that
h approx. 55.43 meters.
A farmer wants to fence in 120,000 square feet of land in a rectangular plot and then divide it into two equal plots with another fence parallel to the short sides. What is the least amount of fence needed to accomplish this?
Solution
- The question says the area of the rectangular farmland is 120,000 square feet. This means that if the length is x and the breadth is y, then, the area can be represented as:
[tex]\begin{gathered} x\times y=120,000 \\ xy=120,000 \end{gathered}[/tex]- Next, we are told that the land is to be divided in the middle by another fence into two equal halves. We are also told that the fence is parallel to the shorter side, implying that the larger side is the side is divided into two.
- Let us depict this last statement in the figure below:
- The length of fence needed is simply the length of the outer perimeter of the fence and also the length of the dividing fence. Thus, the length of fence needed can be expressed as follows:
[tex]\begin{gathered} L=\text{ Perimeter of the Big Rectangle}+\text{ Length of the dividing fence} \\ L=2(x+y)+y \\ \text{ Expand,} \\ L=2x+2y+y \\ \\ \therefore L=2x+3y \end{gathered}[/tex]- This is an expression for the amount of fence needed by the question. Let us proceed to write this equation in terms of either x or y alone using the first equation
[tex]\begin{gathered} \text{ From the first equation,} \\ y=\frac{120,000}{x} \\ \\ \text{ Thus, we have} \\ L=2x+3y \\ L=2x+3\times\frac{120,000}{x} \\ \\ L=2x+\frac{360,000}{x} \end{gathered}[/tex]- We are asked to find the least amount of fence needed. In order to get this, we need to find the derivative of the function of L(x) with respect to x. After this, we equate that derivative to zero.
- The derivative represents the increase or decrease of the total material length (L) with respect to length (x)
- Equating that derivative to zero tells us that the change in those values has been completely minimized
- Thus, we have:
[tex]\begin{gathered} L^{\prime}=2+(-1)\frac{360,00}{x^2} \\ \\ L^{\prime}=2-\frac{360,000}{x^2} \\ \\ \text{ Equate the derivative to zero} \\ \\ 2-\frac{360,000}{x^2}=0 \\ \\ \text{ Multiply through by }x^2 \\ \\ 2x^2-360,000=0 \\ \text{ Divide through by 2} \\ \\ x^2-180,000=0 \\ x^2=180000 \\ Take\text{ the square root of both sides} \\ \\ x=\sqrt{180,000}ft \\ OR \\ x=424.264ft \end{gathered}[/tex]- Thus, if x = 424.264, then, we can find the least amount of fence needed by
[tex]\begin{gathered} L=2x+\frac{360,000}{x} \\ \\ \text{ Put }x=424.264 \\ \\ L=2(424.264)+\frac{360,000}{424.264} \\ \\ \therefore L=1,697.056ft \end{gathered}[/tex]Final Answer
The least amount of fence required is 1697.056ft
Find the GCF of each pair of monomials 54hg and 18g
GCF is the greatest common factor of two terms
54 and 18 have common factors, let us find the factors of each one and find the common factors
18 = 1 x 18, 2 x 9, 3, x 6, then
Its factors are 1, 2, 3, 6, 9, 18
54 = 1 x 54, 2 x 27, 3 x 18, 6 x 9
Its factors are 1, 2, 3, 6, 9, 18, 27, 54
The common factors of both are
1, 2, 3, 6, 9, 18
The greatest one is 18
Both terms have variable g, then
GCF of them is 18g
The GCF of 54hg and 18g is 18g
I need help answering this question : Triangle ABC and triangle PQR are right triangular sections of a fire escape as shown. Is each story of the building the same hight? Explain.
Yes, they are the same height since there is a theorem (Side-Side-Angle) that says if two triangles has two sides congruents and is right angled, then they're congruent, also we can demostrate it we the pythagoras theorem:
[tex]a^2+b^2=c^2[/tex]If a and b of differents triangles are the same, so c of the two triangles would be the same too. a, b and c are the sides of the triangle.
A trap for insects is in the shape of a triangular prism. The area of the base is 4.5 in and the height of the prism is 3 in. What is the volume of this trap? The volume of the trap is in?
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data
triangular prism (trap)
base area = 4.5 in²
height = 3in
volume = ?
Step 02:
volume = base area * h
= 4.5 in² * 3 in
= 13.5 in³
The answer is:
The volume of the trap is 13.5 in³
Click an item in the list or group of pictures at the bottom of the problem and holding the button down drag it into thecorrect position in the answer box Release your mouse button when the tem s place you change your mind dragthe item to the trashcan click the trashcan to clear all your answerIndicate the equation of the given line in standard forThe line that contains the point Q-2 and is parallel to the line whose ecuation1 - 4 - 2/3 (x-3)
Given the equation of a line:
[tex]y\text{ - 4 = }\frac{2}{3}\text{ (x - 3)}[/tex]Step 1: Obtain the slope of the given line
Writing this equation in the standard slope-intercept form, we will obtain the following
[tex]\begin{gathered} y\text{ - 4 = }\frac{2}{3}x\text{ - }\frac{2}{3}\times3 \\ \\ y\text{ - 4 =}\frac{2}{3}x\text{ - 2} \end{gathered}[/tex][tex]y\text{ =}\frac{2}{3}x\text{ - 2+ 4}[/tex][tex]y\text{ = }\frac{2}{3}x\text{ + 2}[/tex]If we compare this to y = mx + b, where m is the slope and b the intercept
the slope of the line is
[tex]\frac{2}{3}[/tex]Step 2: Getting the equation of the line,
The equation of a line given a slope is given by
[tex]\text{slope = }\frac{y-y_1}{x-x_1}[/tex]where x1 and y1 are the coordinates of the points parallel, in this case
x1 =1, y1 = -2
[tex]\frac{2}{3}\text{ =}\frac{y-\text{ (-2)}}{x\text{ -1}}[/tex][tex]\frac{2}{3}\text{ =}\frac{y\text{ +2}}{x\text{ - 1}}[/tex]Cross multiplying
2 (x - 1) = 3 (y +2)
expand the parenthesis
2x - 2 = 3y + 6
3y = 2x -2 -6
3y = 2x - 8
Divide both sides by 3
[tex]y\text{ = }\frac{2}{3}x\text{ - }\frac{8}{3}[/tex]Answer is y = 2x/3 - 8/3
Which of the following figures is an angled cross section?
Given data:
The given figures.
The figure (a) is parallel to the base, the figure (b) is perpendicular to the base, the figure (c) is inclined to the base, and the figure (d) is also parallel to the base.
Thus, option (c) is correct.
Suppose the figure shows f(t), the interest rate on an investment t years after the initial deposit. The straight line is tangent to the graph of y=f(t) when t=8. How fast was the internet rate riding at that time?
Concept:
The slope of the tangent to the curve at any point gives the instantaneous rate of change of the function.
From the given graph, it is observed that the line is tangent to the curve at point (8,9).
So the slope of this line will give the rate of change of the function i.e. interest rate at that instant.
The slope (m) of the line joining (0,0) and (8,9) is given by,
[tex]\begin{gathered} m=\frac{9-0}{8-0} \\ m=\frac{9}{8} \\ m=1.125 \end{gathered}[/tex]Since the slope comes out to be positive, it means that the function is increasing with respect to time.
Thus, the interest rate is increasing at the rate 1.125, at the given time instant.