A rod gets bent into an arc with a radius of R. The distribution of charges along the rod is uniformly linear. the promise in the arc's middle.
What does net potential mean?The potential attributable to each charge when considered separately adds up to the total potential at the origin. Therefore, the effort required to gradually move a charge form infinite to a origin is equal to the sum of the charge as well as the voltage source between the start and end sites.
What is the equation for a semicircular ring's moment of inertia?The equation $I=mr2$, in which m and r are the ring's mass and radius, describes its inertia moment of the a semicircular circle about just a line that passes through its center and is in the plane of a ring.
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two objects are thrown from the top of a tall building and experience no appreciable air resistance. one is thrown up, and the other is thrown down, both with the same initial speed. what are their speeds when they hit the street?two objects are thrown from the top of a tall building and experience no appreciable air resistance. one is thrown up, and the other is thrown down, both with the same initial speed. what are their speeds when they hit the street?they are traveling at the same speed.the one thrown down is traveling faster.the one thrown up is traveling faster.
The speed when they hit the street will be equal to each other.
What is Air resistance?Air resistance and gravity are the two fixed forces of nature which move on any object on Earth. For example, when a plane flies through the air, the air particles are pressing against the aeroplane, making it harder for the aircraft to move. When you see a feather fall, it is greatly affected by air resistance.
What is Gravity ?A force applied to all bodies on Earth is Weight ( W ), which is caused by Earth's gravity. If a body is free falling, its only acceleration is g , gravity. So gravity increases velocity. Both objects will show a change in their velocities because of gravity.
The velocity for both objects if one is thrown up and other is thrown down is same which is given by this formula:
where,
v= final velocity,
v₀= initial velocity,
h is the difference in height between building and street and g= acceleration due to gravity.
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does turning up the thermostat in the middle of the night for 15 minutes reduce the amount of time it takes it to reach temp in the morning?
Yes, turning up the thermostat in the middle of the night for 15 minutes reduce the amount of time it takes it to reach temp in the morning.
The United States Department of Energy suggests turning thermostats back 7 to 10 degrees from their normal settings for 8 hours per day in order to achieve annual savings of up to 10%. The Department of Energy estimates that savings of approximately 1 percent can be achieved for each degree of thermostat adjustment that is made every 8 hours. The amount of time it takes for the temperature to reach the desired level in the morning can be reduced by raising the thermostat for fifteen minutes in the middle of the night.
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if a ball is thrown into the air with a velocity of 40 fts, its height in feet t seconds later is given by y 40t 16t2. (a) find the average velocity for the time period beginning when t 2 and lasting (i) 0.5 second (ii) 0.1 second (iii) 0.05 second (iv) 0.01 second
The change in position or displacement (Δx) divided by the time intervals (Δt) in which the displacement occurs yields the average velocity.
What is the average velocities of ball?Depending on the sign of the displacement, the average velocity can be positive or negative.
To begin, in order to calculate average velocities, we need the position for each instant mentioned:
Y(2) = 2 ft
Y(2.5) = 0 ft
Y(2.1) = 13.44 ft
Y(2.05) = 14.76 ft
Y(2.01) = 15.7584 ft
Let us now compute the average velocities:
V(2 - 2.5) = Y(2.5) - Y(2) / 2.5 - 2
= -32 ft/s
V(2 - 2.1) = Y(2.1) - Y(2) / 2.1 - 2
= -25.6 ft/s
V(2 - 2.05) = Y(2.05) - Y(2) / 2.05 - 2
= -24.8 ft/s
V(2 - 2.01) = Y(2.01) - Y(2) / 2.01 - 2
= -24.16 ft/s
Now, we can derive the expression for y for the instantaneous velocity:
For t=2s, V(t) = 40 - 32t V(2) = -24ft/s
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write a hamiltonian function representing an electron in the presence of a stationary positive point charge
A hamiltonian function representing an electron in the presence of a stationary positive point charge is
H = (p^2)/(2m) - (e^2)/(4πε_0r)
What is a hamiltonian function?Generally, The Hamiltonian function representing an electron in the presence of a stationary positive point charge is given by:
H = kinetic energy + potential energy = (p^2)/(2m) - (e^2)/(4πε_0r)
where
p = momentum of the electron m = mass of the electron e = charge of the electron (assumed to be negative) ε_0 = vacuum permittivity r = distance between the electron and the positive point charge.Note that the first term represents the kinetic energy of the electron, and the second term represents the potential energy of the electron due to the attractive electrostatic force from the positive point charge.
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which of the following statements about forces is false? group of answer choices forces change the momentum of a body forces always occur in equal and opposite pairs where there is no force, objects continue to move the way they were moving there are places on earth where all forces are absent forces cause an acceleration to take place
The statement that is false is "there are places on earth where all forces are absent." Forces, such as gravity, are always present on Earth.
All the given statements are true except the statement "there are places on earth where all forces are absent." is false.
Forces change the momentum of a body,forces always occur in equal and opposite pairs (Newton's third law), where there is no force, objects continue to move the way they were moving, and forces cause an acceleration to take place are all true statements about forces.
Newton's third law simply states that there is an equal and opposite reaction to every action. So, if object A exerts a force on object B, object B will exert an equal but opposite force on object A.
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Two barges full of salted toad guts have a collision. The red barge has a mass of 150 000 kg and is traveling Northwest at 0. 25 m/s. The blue barge has a mass of 100 000 kg and is traveling Southeast at 0. 1 m/s. After the collision the blue barge has a velocity of 0. 32 m/s to the Northwest. What is the final velocity of the red barge? Is this collision elastic?
When the red barge collides with the blue barge, which has a mass of 1000000 kg, its final velocity with in collision elastic becomes 0.311 m/s.
Define the term collision elastic?A elastic collision is one in which the system does not experience a net loss of kinetic energy as a result of a collision. In elastic collisions, momentum as well as kinetic energy are both conserved.The given data:
m1= 150000 kg, v1= 0.25 m/s, m2= 1000000 kg, v2= 0.32 m/sUsing the law of conservation of momentum.
Following the formula, the red barge's final velocity (v3) is determined.
m1×v1+ m2×v2= (m1+m2)v3
Put the values;
150000 × 0.25+ 1000000×0.32= (150000+1000000)×v3
37500+ 320000= 1150000×v3
357500 = 1150000×v3
v3 = 0.311 m/s
Thus,
After one head-on elastic hit where the projectile is substantially more substantial than the target, the target particle's velocity will be nearly twice as fast as the projectile, but really the projectile's velocity will essentially be unaffected.
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a ball is dropped from the roof of a tall building. if the ball bounces back to a height of 34 m. what was the velocity with which it left the ground?
The velocity with which the ball left the ground when it is dropped from a tall building is calculated to be 25.82 m/s.
Height to which a ball bounces back s = 34 m
From the equations of kinematics, we know, the relation connecting height, velocities and acceleration as,
v² - u² = 2 a s
where, v is the final velocity
u is the initial velocity
a is the acceleration
s is the height travelled
Here, u = 0 and a is the acceleration due to gravity
v² = 2 × 9.8 × 34
v² = 666.4
v = 25.82 m/s
Thus, the velocity with which the ball left the ground is calculated to be 25.82 m/s.
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A blender is 70% efficient. It has a total input power of 600 W. Calculate the useful output power. Help meh. I has no idea ¯\_(ツ)_/¯
The useful output power of the blender is 420 W.
How to calculate useful output power?To calculate the useful output power of the blender, we can use the equation:
P_output = P_input * efficiency
Where P_output is the useful output power, P_input is the total input power, and efficiency is the percentage of input power that is converted to useful output power.
Given that the total input power is 600 W and the blender is 70% efficient, we can substitute these values into the equation to find the useful output power:
P_output = 600 W * 0.70
P_output = 420 W
Therefore, the useful output power of the blender is 420 W.
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A 2. 0 kg toy car is released at the top of a frictionless track on the left and rolls off of the track from its right
side ramp. The car starts at a height of 0. 80 m, goes through a 0. 50 m diameter loop, and exits the ramp at a
height of 0. 25 m.
what is the change in the cars gravitational potential energy form A to B?
The change in the car's gravitational potential energy from A to B is calculated as 4.90 J.
What is Gravitational potential energy?Gravitational potential energy may be characterized as a type of energy that is typically possessed or acquired by an object due to an alteration in its position when it is present in a gravitational field. In more simple terms, it can be revealed that gravitational potential energy is an energy that is associated with gravitational force or gravity.
According to the question,
The formula for gravitational potential energy is as follows:
Gravitational potential energy = mgh.where m is the mass (in kg) of the body. G is the magnitude of the gravitational field that the body is exposed to. H is the height at which the body is located.
First, you have to calculate the gravitational potential energy of the car on point A, i.e. U₁= (2.0 kg)(9.8 m/s²)(0 m)= 0 J.
Second, the Gravitational potential energy of the car on point B is found as, U₂= (2.0 kg)(9.8 m/s²)(0.25 m)= 4.90 J.
Now, you must have to calculate the change in the car’s gravitational potential energy: ΔU= U₂-U₁= 4.90 J - 0 J= 4.90 J.
Therefore, the change in the car's gravitational potential energy from A to B is calculated as 4.90 J.
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what charge q should be placed at the center of the square to keep the other four charges in equilibriumn
Answer:
To keep the other four charges in equilibrium, the charge q that should be placed at the center of the square is equal in magnitude but opposite in sign to the total charge of the other four charges.
If an astronaut weighs 981 N on Earth and only 160 N on the
Moon, then what is his mass on Earth?
Answer: The mass on Moon will be 98. 1 kg.
Explanation:
As per the known fact, the mass is independent of acceleration due to gravity of planet.
Why should a person warm up before exercising?
To gradually increase blood flow to the body
To spend extra time thinking about exercise
To keep from getting too tired after the activity
To help increase muscle strength
Answer:
To gradually increase blood flow to the body
a 90.0 kg astronaut receives a 30.0 n force from her jetpack. how much faster is she be moving after 2.00 seconds?
After 2.00 seconds, the astronaut is moving at the speed of 0.67 m/s. The result is obtained by using the concept of Newton's second law.
What is Newton's second law?The Newton's second law states that "The acceleration is directly proportional to the net force acting on an object and inversely proportional to the object's mass." It can be expressed as
a = ∑F/m
or
∑F = ma
Where
∑F = net force (N)a = acceleration (m/s²)m = object's mass (kg)An astronaut moves after receiving a force. We have
m = 90.0 kgF = 30.0 Nt = 2.00 sFind the speed of the astronaut moving!
The force makes the astronaut moves from rest to a certain speed.
The speed can be calculated by the Newton's second law.
∑F = ma
∑F = m (v₁ - v₀)/t
30.0 = 90.0 (v₁ - 0)/2.00
60.0 = 90.0v₁
60.0/90.0 = v₁
v₁ = 2/3
v₁ = 0.67 m/s
Hence, the astronaut is moving at the speed of 0.67 m/s.
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What is the SI unit of K so that the equation Velocity = K x density is correct Give answer in terms of basic units. (Kg^-1m45^-1)
The SI unit of K so that the equation Velocity = K x density is correct is given as
K=m^4/s-kgK= m4/s−kg
What is velocity?Velocity is described as the directional speed of an object in motion as an indication of its rate of change in position as observed from a particular frame of reference and as measured by a particular standard of time.
The SI unit of velocity is m/s and the Si unit of density is kg/m^3kg/m3 .
Adding the SI units of both quantities, we have that :
m/s=K\times kg/m^3m/s=K×kg/m3
In terms of dimensions,
[LT^{-1}]=K\times [ML^{-3}][LT−1]=K×[ML−3]
Dimension of K is :
[K]=[M^{-1}L^4T^{-1}][K]=[M−1L4T−1]
SI unit of K is :
K=m^4/s-kgK=m4/s−kg
Hence, the required solution is K=m^4/s-kgK=m4/s−kg
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how fast does the earth rotate near the equator persona 3
Roughly 1,700 km/h. The Earth rotates faster than sound near the equator.
How quickly rotates the Earth close to the equator?
The Earth's circumference is around 40,075 kilometres at the equator; multiplying this by the length of the day yields a spin speed of approximately 1670 kilometres per hour.
How many times does the equator revolve in a day?
Each 24-hour day, the Earth rotates once around its axis. The speed of Earth's spin at its equator is around 1,000 miles per hour (1,600 km per hour). Every day of your existence, this day-night spin has taken you outside and under the sun and stars.
Can people feel the Earth's spin?
The speed of Earth is rapid. It orbits the Sun at a speed of roughly 67,000 miles (107,000 kilometres per hour), spinning (rotating) at about 1,000 miles (1600 kilometres) per hour. Due to the consistent speeds, we are not aware of any motion.
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Around 1,700 km/h.Correct!. Its circumference is approximately 40,075 kilometers at the equator; multiplying this by the length of the day yields a value of 1670 kilometers per hour for the equator-bound speed of rotation.
How quickly rotates the Earth close to the equator? Around 1,700 km/h.Correct!. With players trying their hardest to finish quickly, the game can be completed in as little as 44 hours.Between 65 and 66 hours are typically needed to finish the main game alone.Shinjiro is ultimately kept alive on October 4 by his pocket watch.He is thrown in a coma rather than killed by the bullet because it hits the pocket watch instead of piercing him.Players who save Shinjiro at the end of the story have the option to spend time with him thanks to New Game+. Despite the fact that Persona 3 is a good game, it has many gloomy themes that are inappropriate for young players.To learn more about equator refer
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technically a geosynchronous satellite is one that orbits the earth once per sidereal day, which is 23.93 hours, not 24 hours. why is this? and how much difference will it make to the altitude of the satellite
Geosynchronous satellite makes a round around the earth in 29.93 hours. It makes a difference of 36000 km difference in the altitude.
Geosynchronous satellites are those that remains stationery with respect to a place. This is because their time period to complete a cycle is 23.93 hours, that is exactly the same as the rotation period of the earth. So the satellite appears stationery. The velocity of the geosynchronous satellite around the earth is 3.07 km/s or 3070 m/s.
GMm/(R+h)² = mv²/(R+h)
GM/v² = (R+h)²
Where R is the radius of the earth = 6.37 × 10⁶ m, h is the altitude of the satellite above the earth, and M is the mass of the earth that is 6 × 10²⁴ kg, G = 6.67 × 10⁻¹¹ Nm²/kg²
(6.67 × 10⁻¹¹ ×6 × 10²⁴)/(3070)² = (R+h)
(R+h) = 42461989 m
6.37 × 10⁶ + h = 42461989
h = 42461989 - 6.37 × 10⁶
h = 36.09 × 10⁶ m
h = 36000 km.
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suppose a 3000 cm3 container holds 7.0 g of nitrogen gas at a pressure of 200 kpa . the gas can be heated at constant pressure if a piston moves outward to let the gas expand as it's heated. alternatively, the gas can be heated at constant volume if the piston is locked in place to prevent expansion. how does the heat required for one of these processes compare to the heat required for the other process? how much heat is required to double the volume and temperature at constant pressure?
The heat required would be Q = 7.0 g/28 g/mol * 20.8 J/molK * (2T - T) = 544 J.
What is heat?Heat is the transfer of energy from one body or system to another due to the difference in their temperatures. Heat is commonly transferred through thermal conduction, convection, radiation, or when two bodies with different temperatures come into direct contact.
The heat required for a process at constant pressure is greater than the heat required for a process at constant volume. This is because when a gas is heated at constant pressure, work is done to push the piston outward, so more energy is required.
To double the volume and temperature at constant pressure, the heat required would be equal to the change in internal energy of the system,
which can be calculated using the equation Q = nCvΔT,
where n is the number of moles of gas,
Cv is the molar heat capacity,
and ΔT is the change in temperature.
In this case, the molar heat capacity of nitrogen gas is 20.8 J/molK,
So the heat required would be Q = 7.0 g/28 g/mol * 20.8 J/molK * (2T - T) = 544 J.
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calculate the amgnitued of the cetripetal force acting on earth as it orbits the sun, assuming a circular orbit and an orital speed of 3.00 times 10^4 meters per second
Answer:
Approximately [tex]3.59\times 10^{22}\; {\rm N}[/tex] (assuming that the orbit is circular.)
Explanation:
When an object is in a circular orbit of radius [tex]r[/tex] with a (linear) speed of [tex]v[/tex], the centripetal acceleration of this object would be [tex]a = (v^{2} / r)[/tex]. If the mass of the object is [tex]m[/tex], magnitude of the net force on this object would be [tex]F = m\, a = (m\, v^{2} / r)[/tex].
Look up the mass of the Earth: [tex]m \approx 5.9722\times 10^{24}\; {\rm kg}[/tex].
Look up the radius of the orbit (mean distance between the Earth and the Sun): [tex]r \approx 1.4960\times 10^{11}\; {\rm m}[/tex] (one Astronomical Unit.)
It is given that the linear orbital speed is [tex]v = 3.00 \times 10^{4}\; {\rm m\cdot s^{-1}}[/tex].
Therefore, magnitude of the centripetal force (net force) on the Earth would be:
[tex]\begin{aligned}F &= m\, a = \frac{m\, v^{2}}{r} \\ &\approx \frac{(5.9722 \times 10^{24}\; {\rm kg})\, (3.00 \times 10^{4}\; {\rm m\cdot s^{-1}})^{2}}{1.4960 \times 10^{11}\; {\rm m}} \\ &\approx 3.59 \times 10^{22}\; {\rm N} \end{aligned}[/tex].
A penny is dropped off the top of the Statue of Liberty, 93 m tall. What is the speed of the penny after 2.5 seconds (assuming no air resistance)?
The speed of the penny after 2.5 seconds is 24.5 m/s.
What is speed?
Speed is a scalar quantity that refers to "how fast an object is moving." It is the rate at which an object changes its position, and it is measured in units of distance per unit of time (such as meters per second or miles per hour). Speed is related to the distance traveled by an object and the time it takes to travel that distance, and it can be calculated by dividing the distance traveled by the time it took to travel that distance.
The speed of an object in free fall can be calculated using the equation:
v = g * t
where v is the velocity, g is the acceleration due to gravity (approximately 9.8 m/s^2 on the Earth's surface) and t is the time elapsed.
In this scenario, the penny is dropped off the top of the Statue of Liberty, which is 93 m tall, and we want to find the speed of the penny after 2.5 seconds.
So, we can substitute the values in the equation:
v = 9.8 m/s^2 * 2.5 s = 24.5 m/s
Therefore, the speed of the penny after 2.5 seconds is 24.5 m/s (assuming no air resistance).
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If you go to the moon, which force is greater? The force of gravity that you exert on the moon or the force of gravity the moon exerts on you?
The force you exert on the moon
The force the moon exerts on you
The force of gravity you exert on the moon equals the force of gravity the moon exerts on you
WILL GIVE BRAINLIEST AWARD
The force of gravity the moon exerts on you is greater than the force of gravity you exert on the moon.
What is the force of gravity?The force of gravity is a fundamental pressure of nature that acts between two gadgets with mass. It's miles the pressure that attracts objects toward every other, and its energy is proportional to the mass of the gadgets and the space among them. The pressure of gravity is liable for the motion of planets and different celestial gadgets, as well as for maintaining items on the floor. It turned into first described by way of Sir Isaac Newton in his laws of motion and normal gravitation, which stated that every item inside the universe attracts each different item with a pressure proportional to the product of their masses and inversely proportional to the rectangular of the distance between them.
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The force the moon exerts on you is greater.
What do you mean by gravity?Gravity is a force of attraction between two objects in space that is proportional to the masses of the objects and inversely proportional to the square of the distance between them. It is the force that holds planets in orbit around stars and is what causes objects to fall to the ground when dropped. On Earth, the force of gravity is what gives weight to objects and what keeps us anchored to the surface. The strength of the gravitational force is determined by the mass of the objects and the distance between them, with more massive objects having a stronger gravitational pull.
The force of gravity is the force with which a celestial body attracts objects toward its center. The force of gravity is proportional to the mass of the object and inversely proportional to the square of the distance between the objects. The force of gravity acts as the source of the weight of objects. The force of gravity is responsible for holding objects in orbit around the earth and other celestial bodies. The most well-known example of the force of gravity is the attraction between the earth and moon, which causes the tides.
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consider a 70-kg woman who has a total foot imprint area of 400 cm2. she wishes to walk on the snow, but the snow cannot withstand pressures greater than 0.5 kpa. determine the minimum size of the snowshoes needed (imprint area per shoe) to enable her to walk on the without sinking.
The minimum size of the snowshoes needed to enable her to walk without sinking will be 1.37 m².
Assumption:
(i) Her weight is uniformly distributed on the imprint area
(ii) the weight of the shoes is negligible
Now, given that mass of women, m = 70 kg
For a pressure of 0.5 kPa on the snow, the imprint area of one shoe must be:
A = W/P
here, W = mg = 70 kg . 9.81 m/s² = 70x9.81 N
P = 0.5 kPa = 0.5 x 1000 N/m²
so, A = [tex]\frac{70x9.81 N}{0.5(1000)N/m^2}[/tex]
or A = 1.37 m²
Therefore, the minimum size of the snowshoes needed to enable her to walk without sinking will be 1.37 m².
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a spring has a force constant of 100 n/m and an unstretched length of 0.07 m. one end is attached to a post that is free to rotate in the center of a smooth table, as shown in the top view above. the other end is attached to a 1 kg disc moving in uniform circular motion on the table, which stretches the spring by 0.03 m. friction is negligible. 10. what is the centripetal force on the disc? (a) 0.3 n (b) 3n (c) 10 n (d) 300 n (e) 1,000 n 11. what is the work done on the disc by the spring during one full circle?
In a circle at constant speed, the work done is zero since the Force is always perpendicular to the distance moved as you move incrementally around the circle.
What is uniform circular motion?An object moves in a circle at a consistent speed in a motion known as uniform circular motion. Any point on a propeller, for instance, that is rotating continuously, is moving uniformly in circles. The second, minute, and hour hands on a watch are some further examples. It is amazing that despite the constant rotation rate, points on these revolving objects are actually speeding. We must consider the motion in terms of vectors in order to see this.
A centripetal motion is an Objects having a constant speed have zero acceleration in one-dimensional kinematics. In two- and three-dimensional kinematics, a particle can experience acceleration even if its speed is constant if it follows a curved trajectory, like a circle.
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a 6.5 kg object is suspended by a string from the ceiling of an elevator. the acceleration of gravity is 9.8 m/s 2 . determine the tension in the string if it is accelerating upward at a rate of 2.6 m/s 2 . answer in units of n. answer in units of n.
The rightward directions she gives are as follows: 1. Move 400 meters to the northwest. 3. The wealth is hidden there, 700 meters to the east-southeast.
What else do u mean by 9.8m s2 of acceleration caused by gravity?This means that anything is pushed toward the center of the earth, which causes the pulled object to accelerate by 9.8 meters per second as it "falls" to the earth. As a result, each second that such a body is dragged towards the earth, its velocity (speed with direction) increases by around 9.8 meters per second.
Is the gravity always 9.8 inches?It should be remembered that gravitation is not a continuous force; gravity weakens the more you are from the center of the Earth. Since it fluctuates from 9.83 at the poles to 9.78 at the equator, it isn't even a consistent at the surface. Due to this, we utilize an average value of 9.8.
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Electromagnetic waves transfer energy from one ____ to ____ ?
an electron and a proton are placed close to each other. what is the direction of the electric field due to these charges at some point a great distance from them? an electron and a proton are placed close to each other. what is the direction of the electric field due to these charges at some point a great distance from them? the electric field points away from the electron and the proton. the electric field points toward the electron and the proton. the electric field is zero.
The electric field due to these charges at some point a great distance from them is zero.
What is electric field?Electric field is a physical field created by a static electric charge or a changing electric charge. It is a vector field that exerts force on other charged particles. Electric fields are created when electric charges are separated, and the strength of the field is determined by the amount of charge and the distance from the charge.
This is because the electric field from an individual charge is inversely proportional to the square of the distance from it, and so the electric field from the two charges cancel each other out when the distance is greater than the separation between the electron and proton.
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a ball thrown at a brick wall bounces directly back with the same speed it had when it struck the wall. has the velocity of the ball changed? explain.
Yes, the velocity of the ball has changed as it changed its direction from hitting the wall and after it struck the wall.
Speed is a scalar which means it has magnitude but not the direction. Velocity, on the other hand, is a vector with both magnitude and a direction. As the speed of two cars may be the same, if they are heading to different directions, then their velocity are not identical.
The velocity of he ball has changed. Let's call that the initial direction positive, when the ball was going towards the wall, its velocity is positive +V. But when it bounces directly back, the direction is now is negative -V. The direction of the velocity has changed, even though the magnitude has not.
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g assume that there are no other targets between moon and earth, and therefore range aliasing can be tolerated. what is the maximum pulse repetition frequency that can be used for the purpose of mapping the (half-sphere) surface of the moon?
Assuming that range aliasing can be tolerated and there are no other targets between the moon and Earth, a pulse repetition frequency of around 10-20 MHz would likely be sufficient for mapping the moon surface.
The maximum pulse repetition frequency (PRF) that can be used for mapping the surface of the moon is determined by the need to avoid range ambiguities and to achieve the desired resolution. The PRF is the number of pulses emitted per second. A high PRF allows for high resolution mapping but also increases the chance of range ambiguities.
If range ambiguities can be tolerated, a high PRF can be used to achieve a high resolution map. The altitude of the spacecraft, the size of the antenna, and the desired resolution of the map are also factors that determine the maximum PRF. A general estimate is that a PRF of around 10-20 MHz would be sufficient for mapping the surface of the moon with a high resolution.
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A car that has a mass of 1,500 kg is turning in a horizontal circle that has a radius of 20 meters. If the coefficient of friction between the car and the ground is 0.6, what is the maximum speed the car can take the turn without skidding?
The maximum speed the car weighing 1500kg and turning in a horizontal circle which has a radius of 20 meters can take the turn without skidding at 10.84m/s.
What is Maximum speed?Maximum speed is the highest rate of speed that can be attained. Acceleration is the velocity, and because velocity has both a magnitude and direction associated with it, the acceleration changes when an object change the magnitude of their motion, the direction of their motion, or both of these.
Radius of the circular path, r = 20 m
Mass of the car, M = 1500 kg
Maximum speed of the car = v
The coefficient of friction, μ = 0.6
The centrifugal force will balance the friction force so that the car does not slip.
Therefore, mv²/r = μmg
v²/r = μg
v² = μgr
v = √(μgr)
v = √(0.6 × 9.8 × 20)
v = √(117.6)
v = √(294,000)
v = √(117.6)
v = 10.84m/s
Therefore, the maximum velocity of the car is 10.84 meter per second.
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you stand on a tall cliff and throw a ball so that it is initially moving purely horizontally. if we neglect the effect of air friction, what is the motion of the ball a short time later.?
If we neglect the effect of air friction, then the motion of the ball a short time later will be a combination of horizontal and vertical motion.
What is the motion of the ball after a short time?If you stand on tall cliff and throw ball so that it is initially moving purely horizontally and neglecting the effect of air friction, motion of the ball a short time later will be combination of horizontal and vertical motion. This is because the only force acting on ball is gravity, which will pull the ball downwards. Therefore, ball will experience a vertical acceleration due to gravity, while continuing to move horizontally at constant velocity.
Motion of the ball is a parabolic path, which is the trajectory of projectile under the influence of gravity. Horizontal component of the motion will remain constant, while vertical component will be affected by gravity and will decrease until ball reaches maximum height and then it will increase again until the ball hit the ground.
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A ball is thrown horizontally from the roof of a building 85 m tall with a speed of 10.6 m/s.
a. How much later does the ball hit the ground?
b.
How far from the building will it land?
C. What is the velocity of the ball just before it hits the ground?
Answer:
1) [tex]t=4.16s[/tex]
2) [tex]s=44.10m[/tex]
3) [tex]v_{final}=40.84\frac{m}{s}[/tex]
Explanation:
a) How long till it hits the ground?
Since the person threw the ball perfectly horizontal, the ball has 0 vertical velocity at the start. In fact, it takes the same time for the ball to reach the ground if they dropped the ball instead of throwing. The acceleration in a vertical drop is gravity ([tex]a=9.81\frac{m}{s^2}[/tex])
Basically, we'll solve first part as if he just dropped the ball.
Use this linear motion formula:
[tex]s=v_{inital}(t_{final} -t_{initial})+1/2a(t_{final}-t_{inital})^2[/tex]
Since [tex]v_{initial} =0[/tex] we can remove that part from equation:
[tex]s=1/2a(t)^2[/tex]
[tex]85=1/2*9.81(t)^2[/tex] Plug and solve
[tex]170=9.81(t)^2[/tex]
[tex]17.33=t^2[/tex]
[tex]t=4.16s[/tex]
b) How far away does it land?
We will use the same formula above for horizontal motion.
[tex]s=v_{inital}(t_{final} -t_{initial})+1/2a(t_{final}-t_{inital})^2[/tex]
[tex]s=v(t)+0[/tex] (Remove the last part since [tex]a=0[/tex])
[tex]s=10.6(4.16)[/tex]
[tex]s=44.096m[/tex]
c) How fast was it traveling vertically at the end?
Use this other linear motion formula for this step. s=85m (height of building).
[tex]v_{final} ^2-v_{initial} ^2=2as[/tex]
[tex]v_{final} ^2-0^2=2(9.81)*(85)[/tex] Started with 0 vertical velocity.
[tex]v_{final} ^2=1667.7[/tex]
[tex]v_{final}=40.837m/s[/tex]
According to the question of speed, a) 16.05 seconds does the ball hit the ground, b) 169.33 m far from the building will it land, c) 37.68 m/s is the velocity of the ball just before it hits the ground.
What is speed?
Speed is the rate at which something moves or an object's rate of motion. It can be measured in metres per second, kilometres per hour, and miles per hour, and is often used to describe the motion of objects, such as vehicles, animals, or natural phenomena.
a. The time it takes for the ball to hit the ground is given by the equation t = (2×h)/v, where h is the height of the building (85 m) and v is the initial velocity of the ball (10.6 m/s). Plugging in the given values, we get t = (2×85)/10.6 = 16.05 seconds.
b. The distance from the building at which the ball will land is found using the equation x = vt, where v is the initial velocity (10.6 m/s) and t is the time it takes for the ball to hit the ground (16.05 seconds). Plugging in the given values, we get x = 10.6×16.05 = 169.33 m.
c. The velocity of the ball just before it hits the ground is determined by the equation v = √(2gh), where g is the acceleration due to gravity (9.8 m/s2) and h is the height of the building (85 m). Plugging in the given values, we get v = √(2×9.8×85) = 37.68 m/s. This is the velocity of the ball just before it impacts the ground.
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