Find the slope of the line passing through the points (-2, 8) and (3,8).
Please help!!

Answer:

70.132,70

Step-by-step explanation:

68.090,00

+ 2.042,70

_________

70.132,70

Answer:

yes its is slope

Step-by-step explanation:

Answer:

9

Step-by-step explanation:

After substituting the given values of x and y in the equation, all that can apply are (0, 2), (3, 0), and (6, -2).

Mathematical expressions with two algebraic symbols on either side of the equal (=) sign are called equations.

This relationship is illustrated by the left and right expressions being equal. The left-hand side equals the right-hand side is a basic, straightforward equation.

As per the given information in the question,

The given equation is,

2x + 3y = 6

Now, substitute the corresponding points and check,

1. For points (0, 2)

2(0) + 3(2) = 6

6 = 6, this is correct.

2. For points (0, 6)

2(0) + 3(6) = 18

6 ≠ 18, this is incorrect.

3. For points (2, 3)

2(2) + 3(3) = 6

13 ≠ 6, this is incorrect.

4. For point (3, -2)

2(3) + 3(-2) = 6

0 ≠ 6, this is incorrect.

5. For point (3, 0)

2(3) + 3(0) = 6

6 = 6, this is correct.

6. For point (6, -2)

2(6) + 3(-2) = 6

6 = 6, this is correct.

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Answer:

w=1.5 or w=13.5

Step-by-step explanation:

this is one answer:

multiply w on both sides to leave u with

4.5=3w

divide both sides by 3

[tex]\frac{4.5}{3}=\frac{3w}{3}[/tex]

1.5=w

_____________________

this is the second one if the first one is wrong:

multiply 4.5 on both sides so that the 4.5/w would leave u with just only w alone.

then 3*4.5=13.5

w=13.5

hope dis helps if not then im not dat smart enough ;?

Answer: P is arc; Q is the centre of the circle; R is the radius; S is the circumference

Step-by-step explanation: P is arc: it is a continuous part of the circumference (S) of the circle;

Q is the centre of the circle which is at any point in time R points away from P;

R is the radius: the line segment between any point of a circle and its centre, Q;

S is the circumference of the circle: the line that bounds a circle.

Answer:

i think the answer if (-9,-3)

Step-by-step explanation:

Tell me if i got it right so i can see where i made a mistake IF i got it wrong

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

a ) Two matrices cannot be multiplied.

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

b )

The answer is | 20 - 4 - 12 |

| 8 2 19 - |

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

Answer:

18, 36, 54, 72, 90...

Step-by-step explanation:

Answer:

A) - 54.48

Step-by-step explanation:

Just plug it into the calculator like this;  (-68.1) x 0.8, which equals -54.48.

the answer is negative because you multiplied a positive # and a negative #.

Answer:

A. -5

Step-by-step explanation:

-9 + 4 = -5

hope this helps

Answer:

$10.06

Step-by-step explanation:

Since there are 2 people, multiply the amount they each get by 2.

5.03 times 2=10.06

Final answer  10.06

Hope this helps:)

Answer:First suppose that the roots of the equation

x2−bx+c=0(1)

are real and positive. From the quadratic formula, we see that the roots of (1) are of the form

b±b2−4c⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯√2.

For the root or roots to be real, we require that b2−4c≥0, that is, b2≥4c. In order for them to be positive, we require that

b−b2−4c⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯√>0.

This immediately tells us that b>0, but we can go further. We can rearrange this to get

b>b2−4c⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯√,

which (assuming that b>0) is true if and only if

b2>b2−4c,

since both sides of the inequality are positive so we may square. But then

4c>0.

That is, if the roots are real and positive then b>0 and b2≥4c>0.

Now suppose that b>0 and b2≥4c>0.

Then the roots of (1) are real since b2−4c≥0, and b>0 guarantees that the root b+b2−4c⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯√ is positive.

So it remains to show that b−b2−4c⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯√>0. We have that

4c>0,

so that

b2>b2−4c,

then square rooting shows that

b>b2−4c⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯√,

so the roots of (1) are real and positive, as required.

Approach 2

the curve y equals x squared minus b x plus c showing two positive roots for y equals zero

This is intended to be a proof without words! We have from the diagram that:

If c, b and b2−4c are all positive, there are two real positive roots for x2−bx+c=0 (if b2=4c, we have two real positive equal roots).

If there are two real positive roots for x2−bx+c=0, then c and b are positive and b2−4c is non-negative.

(Why is the distance between the roots b2−4c⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯√?)

Approach 3

When solving problems about the roots of polynomials, it is often useful to find expressions those roots must satisfy and see if this tells us anything new. If α and β denote the roots of the equation, then

x2−bx+c=(x−α)(x−β)=x2−(α+β)x+αβ

and so α+β=b and αβ=c.

We also know that the roots of a quadratic equation are real if and only if the discriminant is non-negative, that is, if and only if b2−4c≥0.

Using these facts, if α and β are both real and positive, then b=α+β>0, c=αβ>0 and b2≥4c, as above.

Conversely, if b>0 and b2≥4c>0, then we know the discriminant is positive and hence both roots are real. We also have that

αβ>0(2)

and

α+β>0.(3)

As α and β are both real, by (2), we know that α and β are either both positive or both negative. However, if α and β were both negative, then (3) could not possibly hold. Hence α and β are both positive, as required.

We now sketch on a graph the region where b>0, c>0 and b2≥4c:

The curve b squared = 4 c as a quadratic with the c-axis vertical and the b-axis horizontal. The region below it is shaded.

The region of the b-c plane for which b>0, c>0 and b2≥4c

Sketch the region of the b-c plane in which the roots of the equation are real and less than 1 in magnitude.

We know that in order for the roots to be real we need b2≥4c as in the first part. We now need to find the region where

−1<b±b2−4c⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯√2<1.(4)

We have b−b2−4c⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯√2≤b+b2−4c⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯√2 so we only need to consider the values for which both

−1<b−b2−4c⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯√2andb+b2−4c⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯√2<1.

Firstly, we will consider the values for which

b+b2−4c⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯√<2.

Rearranging gives

b2−4c⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯√<2−b.

So b<2, as the square root is non-negative, and we can square both sides to get

b2−4c<4−4b+b2,

which we may rearrange to find c>b−1.

We will now consider the values for which

−2<b−b2−4c⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯√.

Similarly, we can rearrange to get

b2−4c⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯√<b+2.

So b>−2, and we can, as before, square to get

b2−4c<b2+4b+4,

and hence c>−b−1.

To sketch the graph, we start by considering the boundary curves b2=4c, c=b−1 and c=−b−1, and the points at which they intersect. We can see that the two lines only intersect when b=0 and c=−1, and the lines intersect the curve when

b2=4b−4andb2=−4b−4

which rearrange to

(b−2)2=0and(b+2)2=0.

This tells us that each line intersects with the curve in only one place and so these lines must be tangent.

Is there a way we could have deduced this directly from (4)?

What do the lines being tangent signify in terms of our equation x2−bx+c=0?

Is this a representation of a well-known property of these equations?

Sketching the graph then yields the following picture:

The graph with the previous curve and the lines 4 c = 4 b minus 4 and 4 c = minus 4 b - 4. Each line touches the curve once and the two lines intersect at (0, minus 1). The region between the three lines/curves is shaded.

The shaded region is where b2≥4c, c>b−1, c>−b−1 and −2<b<2

We might notice that when we derived the inequalities c>b−1 and c>−b−1, a lot of the work we did was very similar.

We might also notice that the graph above is symmetric about the c axis. Why is this?

Does the graph give us any ideas about how we might deduce one inequality from the other?

Step-by-step explanation:

Answer:

b = 1/4

Step-by-step explanation:

We will use 4 as a common denominator.

3 × 2 = 6        2 × 2 = 4

Now we have the equation 6/4 + b = 7/4

Answer: 1.45

Step-by-step explanation:

Answer:

20 Km per hour.

The constant of proportionality is 5.5

Step-by-step explanation:

y = kx

k = constant of proportionality

y = 5.5x

Answer:

d

Step-by-step explanation:

Answer:

$24.96

Step-by-step explanation:

Total number of gallons irede had in his tank = 6.4gallons

Price per gallon is $3.90

To get the cost of 6.4gallons;

If 1 gallon = $3.90

6.4gallons = $x

Cross multiply

1 * x = 3.90 * 6.4

x = 24.96

Hence Irene spent $24.96 on gas

Answer: 3/1300

Sorry I’m late !!

Answer:

D

Step-by-step explanation:

24        X

----  =   ----          than cross multiply and solve for X

30       100

Answer:

I am not sure I this one but The answer is efither B or D

Try going with the answer D if its not the answer its my fault. I am sorry if You get this wrong.

Answer:

w=v/lh

Step-by-step explanation:

Answer: ion know i'm guessing 4

Step-by-step explanation: because it shows 8 at the top, so since it's full and it's 4,000 then that'll basically make 8 the 4000, so since 4 is half of 8 then we prolly have our answer right there

Answer: It would be 20

Step-by-step explanation: The formula for height would be h= v/pi r squared, just plug in the numbers

Answer:

x = 3/7

Step-by-step explanation:

[tex]\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}[/tex]

Actually Welcome to the Concept of the Straight lines.

Since the slope of the line, m = -1/2

and we know that, line equation is, y=mx+c

so the answer is, option 1.)

1.) y-4 = -1/2 (x+6)

Answer:

He can make 4 batches of sugar cookies.

Step-by-step explanation: 4x1/2=2 and because he lost 1 cup, he only has 2 cups left

Answer:

p = 304

Step-by-step explanation:

Given p is inversely proportional to q² then the equation relating them is

p = [tex]\frac{k}{q^2}[/tex] ← k is the constant of proportion

To find k use the condition p = 19 when q is 8, then

19 = [tex]\frac{k}{8^2}[/tex] = [tex]\frac{k}{64}[/tex] ( multiply both sides by 64 )

k = 1216

p = [tex]\frac{1216}{q^2}[/tex] ← equation of proportion

When q = 2, then

p = [tex]\frac{1216}{2^2}[/tex] = [tex]\frac{1216}{4}[/tex] = 304

The value of p is equal to 304 when q is equal to 2

Given :

If p is inversely proportional to the square of q

when y is inversely proportional to x then [tex]y=\frac{k}{x}[/tex]

given that p is inversely proportional to the square of q. the equation becomes

[tex]p=\frac{k}{q^2}[/tex]

when p is 19 the value of q is 8

Replace the values and find out k

[tex]p=\frac{k}{q^2}\\19=\frac{k}{8^2}\\19=\frac{k}{64}\\[/tex]

Multiply both sides by 64

k=1216

Now we find out p when q is 2

Replace k value and q value to find out p

[tex]p=\frac{k}{q^2} \\\\p=\frac{1216}{2^2} \\p=304[/tex]

The value of p is equal to 304 when q is equal to 2

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Answer:

Multiply both terms of the numbers

hense you would do: 2(9a + 12) = 18a + 24

It doesn't have to be 2 however. If can be any number you want it to be

Step-by-step explanation:

Answer:

12+9a is equivelent to 9a+12 :-)

Step-by-step explanation:

Answer:

hour 3 to hour 4

Step-by-step explanation:

that is where the slope is the least steep