Find the total area of the figure.A. 57 square yardsB. 66 square yardsC. 180 square yards D. 234 square yards
Answers
The given structutre can be divided to 3 parts.
Let the first part be the rectangle ABHI.
The area of the section-1 is,
[tex]\begin{gathered} Arae(ABHI)=9\text{ yd}\times11\text{ yd} \\ =99 \end{gathered}[/tex]The second part is also a rectangle. The area of the rectangle BCFG is,
[tex]\begin{gathered} \text{Area(BCFG)}=(9+4)\times9 \\ =13\times9 \\ =117 \end{gathered}[/tex]The third section is a triangle. The area of the triangle CED is,
[tex]\begin{gathered} \text{Area(CED)}=\frac{1}{2}\times9\times4 \\ =18 \end{gathered}[/tex]The total area of the given structure is,
[tex]\begin{gathered} A=\text{Area (ABHI)+ Area(B}CFG\text{)}+\text{ Area(}CDE\text{)} \\ =99+117+18 \\ =234\text{ square yards} \end{gathered}[/tex]Thus, the total area of the given structure is 234 square yards, and the correct option is option D.
Related Questions
Enter the values of X & Y in the solution for each system in the following table
Answers
System 1
[tex]\begin{gathered} 3x\text{ - 4y = 6} \\ x\text{ + 4y = 18} \end{gathered}[/tex]Using Elimination method:
Add equation 1 to equation 2:
[tex]\begin{gathered} (3x\text{ -4y\rparen +}(x\text{ + 4y\rparen = 6 + 18} \\ 3x\text{ - 4y + x + 4y = 24} \\ Collect\text{ like terms} \\ 3x\text{ + x -4y + 4y = 24} \\ 4x\text{ = 24} \\ x\text{ = }\frac{24}{4} \\ x\text{ = 6} \end{gathered}[/tex]Substitute the value of x into any of the equation and solve for y
[tex]\begin{gathered} x\text{ + 4y = 18} \\ 6\text{ + 4y = 18} \\ Collect\text{ like terms} \\ 4y\text{ = 18-6} \\ 4y\text{ = 12} \\ y\text{ = }\frac{12}{4} \\ y\text{ =3} \end{gathered}[/tex]Solution: (6,3)
System 2:
[tex]\begin{gathered} 3x\text{ - 4y = -3} \\ 4x\text{ - 3y = 10} \end{gathered}[/tex]Using Elimination method
Multiply the first equation by 3 and the second by 4
[tex]\begin{gathered} 9x\text{ - 12y = -9} \\ 16x\text{ - 12y =40} \end{gathered}[/tex]Subtract the resulting first equation from the second:
[tex]\begin{gathered} (16x\text{ - 12y\rparen - \lparen9x - 12y\rparen = 40 -\lparen-9\rparen} \\ 16x\text{ - 12y - 9x + 12y =49} \\ Collect\text{ like terms} \\ 16x\text{ -9x - 12y + 12y = 49} \\ 7x\text{ = 49} \\ Divide\text{ both sides by 7} \\ \frac{7x}{7}\text{ = }\frac{49}{7} \\ x\text{ = 7} \end{gathered}[/tex]Substitute the value of x into any of the equation and solve for y
[tex]\begin{gathered} 4x\text{ -3y =10} \\ 4\times7\text{ - 3y =10} \\ 28\text{ - 3y = 10} \\ Collect\text{ like terms} \\ -3y\text{ = 10-28} \\ -3y\text{ = -18} \\ y\text{ = }\frac{-18}{-3} \\ y\text{ =6} \end{gathered}[/tex]Solution: (7,6)
Answer Summary
tenth20, 13, 13, 6, 3, 12, 7, 20, 20Range:x✓x f(x) VX X(x) x] 3 2TTMean:Median:
Answers
Range = Highest value - Lowest value
= 20 - 3
= 17
Mean =
[tex]\frac{Sum\text{ of all the items}}{total\text{ number of items}}\text{ = }\frac{20\text{ + 13 + 13 + 6 + 3 +12 + 7 + 20 + 20}}{9}=\text{ }\frac{114}{9}\text{ = }\frac{38}{3}[/tex]Median = Middle value when the items are arranged in either increasing or decreasing order
Arranging the items In increasing order we have:
3, 6, 7, 12, 13, 13, 20, 20, 20.
Hence the median is the 5th item = 13
Mode = The most occuring item
The most occuring item or number is 20 (occuring three times)
solve the following system of equation using the substitution method 5x + 3y equals 1 x + 2y equals 3
Answers
5x + 3y = 1 Equation (1)
x + 2y= 3 Equation (2)
Isolating x in the equation 2, we have:
x = 3 - 2y
Replacing x=3- 2y in the equation 1, we have:
5(3 - 2y) + 3y = 1
15 -10y + 3y = 1 (Distributing)
15 -7y = 1 (Adding like terms)
-7y = 1 - 15 (Subtracting 15 on both sides of the equation)
-7y = -14 (Subtracting)
y= -14/(-7) (Dividing by - 7 on both sides of the equation)
y = 2
Replacing y=2 in the equation 2
x = 3 - 2*2
x= 3 - 4 (Multiplying)
x= -1 (Subtracting)
The answers are : x= -1 and y=2.
rotate the point x(-5,8) 270 degrees counter clockwise what would be the image point be explain your answer using complete sentences make sure to label your point correct
Answers
A(x,y) becomes A'(y,-x):
So:
x(-5, 8) ------------>x'(8,5)
For a 90 Degree Rotation counter clockwise:
A(x,y) becomes A' (-y,x)
Therefore:
A(1,5)----------->A'(-5,1)
B(3,6)----------->B'(-6,3)
C(5,2)------------>C'(-2,5)
D(3,1)------------->D'(-1,3)
please help I'm practicing my math problems but I have trouble with this kind of problem please help I'm practicing for a test
Answers
Given:
9 > d, if d = 3
To check if this statement is true, substitute d for 3.
We have:
9 > 3
Since 9 is greater than 3, this inequality statement can be said to be true.
ANSWER:
True
Form the differential equation of the family of circles touching the x-axis at origin?
The right answer will be marked as Brainliest
Answers
[tex]{ \red{ \tt{y'( {x}^{2} - {y}^{2}) - 2xy = 0}}} [/tex]
Step-by-step explanation:
Consider the equation
[tex]{ \green{ \tt{ {(x - h)}^{2} + {(y - k)}^{2} = {a}^{2}}}} [/tex]
Here, C = (0,a) i.e. (h,k) and radius = a
Above equation is,
[tex]{ \green{ \tt{ {(x - 0)}^{2} + {(y - a)}^{2} = {a}^{2}}}} [/tex]
[tex]{ \green{ \tt{ {x}^{2} + {y}^{2} - 2ay + {a}^{2} - {a}^{2} = 0}}}[/tex]
[tex]{ \green{ \tt{ {x}^{2} + {y}^{2} - 2ay = 0}}}[/tex]
[tex]{ \green{ \tt{ {x}^{2} + {y}^{2} = 2ay}}} \: \: {eq}^{n} (1)[/tex]
[tex]{ \green{ \tt{2x + 2yy' = 2ay'}}}[/tex]
[tex]{ \green{ \tt{ \frac{2x + 2yy'}{y'} = 2a}}}[/tex]
[tex]{ \green{ \tt{ \frac{2x + 2yy'}{y'} = 2a}}}[/tex]
Put this in Equation no. (1)
x² + y² = (2x+2yy')y/y'
y'(x²+y²) = 2x + 2y²y'
x²y' + y²y' - 2xy - 2y²y' = 0
x²y' - y²y' - 2xy = 0
Therefore,
y'(x²-y²)-2xy = 0
Write a similarity statement about the three triangles shown in the diagram
Answers
In the figure we can see that the triangles has an angle of 90º and an equal side.
So for that reason we know that the following angles are equal:
So they are similar because of the statement ASA
2.) A farmer mistakenly makes a deal with a local grocery store to give them 1 ear of corn on day 1, 2 ears of corn on day 2, 4 ears of corn on day 3, until the corn doubles for an entire month. Write a recursive formula for this situation.
Answers
Answer:
[tex]\begin{cases}a_1=1\\a_{n+1}=2 a_n\end{cases}[/tex]
Step-by-step explanation:
A recursive formula for a sequence allows you to find the nth term of the sequence provided you know the value of the previous term in the sequence.
The first three terms of the sequence are:
[tex]a_1=1[/tex][tex]a_2=2[/tex][tex]a_3=4[/tex]Therefore, as each term of the sequence is twice the previous term it is a geometric sequence.
When writing a recursive rule, remember to include the definition of the first term of the sequence.
Therefore, the recursive formula for the given situation is:
[tex]\begin{cases}a_1=1\\a_{n+1}=2 a_n\end{cases}[/tex]
-----------------------------------------------------------------------------------------------
Additional information
The "a" signifies "term". So a₁ is the first term, a₂ is the second term ... aₙ is the nth term. Therefore, aₙ₊₁ is the next term.
"u" is regularly used instead of "a", but as "a" is used as the first term when writing explicit formulas, it is more preferable.
As a recursive formula for a sequence allows you to find the nth term of the sequence provided you know the value of the previous term in the sequence, to find the 6th term for example, we would need to calculate the previous terms first:
[tex]\implies a_1=1[/tex]
[tex]\implies a_2=2 \cdot a_1=2 \cdot 1=2[/tex]
[tex]\implies a_3=2 \cdot a_2=2 \cdot 2=4[/tex]
[tex]\implies a_4=2 \cdot a_3=2 \cdot 4=8[/tex]
[tex]\implies a_5=2 \cdot a_4=2 \cdot 8=16[/tex]
[tex]\implies a_6=2 \cdot a_5=2 \cdot 16=32[/tex]
Note: It is more preferable to find an explicit formula for the nth term of a sequence since with an explicit formula we do not need to calculate the previous term(s).
The explicit formula for this sequence of this question is:
[tex]a_n=2^{n-1}[/tex]
Therefore, to find the 6th term using the explicit formula, simply substitute n = 6 into the formula:
[tex]\implies a_6=2^{6-1}=2^5=32[/tex]
As you can see, it yields the same result as the recursive formula but without the need to calculate the preceding terms.
The volume V (in cubic feet) of a rectangular box with a square base is described by the equation V=L^2H, where H is the height (in feet) of thr box and L is the length (in feet) of the base. Find thr volume of a 4-foot-tall cardboard box whose square base has a length of 2 feet.
Answers
In the given data :
[tex]\text{ The volume of the rectangular box with squre base is V = L}^2H[/tex]where L is the length and H is the height.
For the 4 foot tall cardoard box,with the square base has length = 2feet
The volume of the carboard is describe as :
[tex]\text{ Volume = L}^2H[/tex]here we have, length = Square length = 2 feet
Breadth = Height of the cardboard = 4 foot
Substitute the value and simplify:
[tex]\begin{gathered} \text{ Volume = L}^2H \\ \text{ Volume=2}^2\times4 \\ \text{Volume = 4}\times4 \\ \text{Volume =16 f}eet^3 \end{gathered}[/tex]So, the volume of cardboard is 16 feet³
Answer : Volume of cardboard is 16 feet³
Lenna is a software sales woman. Her base salary is $2500 and she makes an additional $40 for every copy of history is fun she sells. Let P represent her total pay in dollars, and let N represent the number of copies of history is fun she sells. Write an equation relating P to N. Then use this equation to find her total pay if she sells 26 copies of history is fun.Equation- Total pay if lena sells 26 copies-
Answers
We need to find the equation relating P to N. Also, we need to find P when N = 26.
We know that N is the number of copies of "history is fun" she sells and that she makes an additional $40 for every copy she sells.
Thus, the total additional she receives for selling those N copies is, in dollars:
[tex]40\cdot N[/tex]Also, we know that her base salary is $2500. Thus, her total pay P, in dollars, is given by:
[tex]P=2500+40N[/tex]Now, when she sells 26 copies of "history is fun", N = 26, and we have:
[tex]\begin{gathered} P=2500+40\cdot26 \\ \\ P=2500+1040 \\ \\ P=3540 \end{gathered}[/tex]Answer
Equation: P = 2500 + 40N
Total pay if Lenna sells 26 copies: $3540
WAGES Mark has already earned money for mowing lawns over the summer when he takes a job at the local grocery store, earning $9.50 per hour. After working 16 hours at the grocery store, Mark has earned a total of $292. Write a linear equation to represent the amount of money m that Mark has earned this summer after working h hours at the grocery store.
Answers
The linear equation m = 9.50h + 140 represents the amount of money m earned by Mark in h hours while working at the grocery store in summer.
Mark earns $9.50 per hour while working at local grocery store
Total money earned by Mark after working for 16 hours is $292
As per the given condition, the points are (16, 292)
The slope of the linear equation is represented by $9.50
Hence, M = 9.5(16, 292)
Standard linear equation is given by
m = Mx + b … (1)
Substitute the values in the equation to get the values of b
292 = 9.5(16) + b
⇒ b = 292 - 152
⇒ b = 140
Substitute the values in the equation (1) again to get linear equation
⇒ m = 9.50h + 140
Hence, the linear equation is m = 9.50h + 140
To learn more about linear equation here
https://brainly.com/question/11897796
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3 liters of water are shared equally by 5 people. How much water does each person get? Write a division equation to represent the situation
Answers
Each person get 0.6 liters of water.
1 Find the value(s) of x that make each equation true:
3x+1/2 - 1/3 = x
Answers
Answer:
x = - 1/3
Step-by-step explanation:
Multiply both sides of the equation by the LCM of 2 and 3 (which is 6 ) to get
9x+3 - 2 = 6x
9x +1 = 6x subtract 6x and subtract 1 from both sides to get
3x = -1
x = - 1/3
I don’t know how to do this can I get some help plss
Answers
The triangle in the question is a right triangle.
Recall that a right triangle that has an angle measuring 45 degrees is an isosceles triangle. This means that the two lines adjacent to the right angle are equal.
Going by this definition, we have that:
[tex]BC=AC[/tex]Therefore:
[tex]AC=3[/tex]The length of the hypotenuse can be gotten using the Pythagorean Theorem:
[tex]\begin{gathered} AB^2=3^2+3^2 \\ AB=\sqrt{9+9}=\sqrt{18}=3\sqrt{2} \end{gathered}[/tex]Hence, we can calculate the value of the ratios provided:
[tex]\begin{gathered} \sin A=\frac{BC}{AB} \\ \cos A=\frac{AC}{AB} \\ \tan A=\frac{BC}{AC} \end{gathered}[/tex]Using the calculated value, we have the answers to be:
[tex]\begin{gathered} \sin A=\frac{3}{3\sqrt{2}}=\frac{1}{\sqrt{2}}=\frac{\sqrt{2}}{2} \\ \cos A=\frac{3}{3\sqrt{2}}=\frac{1}{\sqrt{2}}=\frac{\sqrt{2}}{2} \\ \tan A=\frac{3}{3}=1 \end{gathered}[/tex]ANSWER
[tex]\begin{gathered} \sin A=\frac{\sqrt{2}}{2} \\ \cos A=\frac{\sqrt{2}}{2} \\ \tan A=1 \end{gathered}[/tex]I = $440, P= 1, r= 5%, t = 4 years
Answers
We have to use the simple interest formula
[tex]I=P(1+rt)[/tex]Let's replace the given information
[tex]440=P(1+0.05\cdot4)[/tex]Then, we solve for P.
[tex]\begin{gathered} 440=P(1+0.2) \\ 440=P(1.2) \\ P=\frac{440}{1.2}\approx366.67 \end{gathered}[/tex]Hence, the principal is around $366.67.Use the standard algorithm to solve 22,742 x 29
Answers
ANSWER:
STEP-BY-STEP EXPLANATION:
We have the following operation:
[tex]22742\cdot \:29[/tex]We solve in the standard way just like this:
write the equation for a parabola with a focus at (-8,-1) and a directrix at y= -4y =
Answers
Since the directrix is y=-4, use the equation of a parabola that opens up or down.
[tex]\mleft(x-h\mright)^2=4p(y-k)[/tex]where vertex is at (h,k) and focus is at (h,k+p)
The vertex is halfway between the directrix and focus. Find the y-coordinate of the vertex using the following
[tex](-8,\frac{-1-4}{2})=(-8,-\frac{5}{2})[/tex]Find the distance from the focus to the vertex.
The distance from the focus to the vertex and from the vertex to the directrix is |p|. Subtract the y-coordinate of the vertex from the y-coordinate of the focus to find p.
[tex]p=-1+\frac{5}{2}=-\frac{2}{2}+\frac{5}{2}=\frac{-2+5}{2}=\frac{3}{2}[/tex]Substitute in the known values for the variables into the equation
[tex](x-h)^2=4p(y-k)[/tex][tex](x+8)^2=4\cdot\frac{3}{2}\cdot(y+\frac{5}{2})[/tex]Simplify
[tex](x+8)^2=6\cdot(y+\frac{5}{2})[/tex]in y=ax^2+bx+c form:
[tex]\begin{gathered} x^2+16x+64=6y+15 \\ x^2+16x+64-15=6y \\ x^2+16x+49=6y \\ y=\frac{1}{6}x^2+\frac{16}{6}x+\frac{49}{6} \end{gathered}[/tex]if(x) = x4 - 6x2 +3 Find the intervals where f is concave up and where it is concave down. Locate all inflection points. (You may write on the next page if you need more space for this question.)
Answers
You have the following function:
[tex]f(x)=x^4-6x^2+3[/tex]In order to determine the intervals, it is necessary to calculate the first derivative of the function, equal it to zero, and identify the zeros of the equation, just as follow:
[tex]\begin{gathered} f^{\prime}(x)=4x^3-12x=0 \\ 4x(x^2-3)=0 \end{gathered}[/tex]the zeros of the previous equation are:
[tex]\begin{gathered} x_1=0 \\ x_2=\sqrt[]{3} \\ x_3=-\sqrt[]{3} \end{gathered}[/tex]Next, it is necessry if the previous values are minima or maxima. Evaluate the second derivative for the previous values of x. If the result is greater than 0, then, it is a minimum. If the result is lower than zero, it is a maximum:
[tex]\begin{gathered} f^{\prime}^{\prime}(x)=12x^2-12 \\ f^{\prime}^{\prime}(0)=12(0)^2-12=-12<0 \\ f^{\prime}^{\prime}(\sqrt[]{3})=12(\sqrt[]{3})^2-12=24>0 \\ f^{\prime}^{\prime}(-\sqrt[]{3})=12(-\sqrt[]{3})^2-12=24>0 \end{gathered}[/tex]Then, for x=0 there is a maximum, and for x=-√3 and x=√3 there is a minimum.
Hence, until x = -√3 the function decreases. In between x=-√3 and x=0 the function increases. In between x=0 and x=√3 the function decreases and from x=√3 the function increases.
Furthermore, it is necessary to find the inflection points. Equal the second derivative to zero and solve for x:
[tex]\begin{gathered} f^{\prime}^{\prime}(x)=12x^2-12=0 \\ x^2=1 \\ x=\pm1 \end{gathered}[/tex]then for x=1 and x=-1 there are inflection points.
The interval where the function is concave up is:
(-∞ , -1) U (1, ∞)
The interval where the function is concave down is:
(-1,1)
Bob the builder leaned a ladder against a tree in order to climb and build a treehouse. Bob wants to find the measure of the angle between the groundand the ladder. Which equation can Bob use to find the value of x?
Answers
Okay, here we have this:
Considering the provided information, we are going to identify which equation can Bob use to find the value of x, so we obtain the following:
We want to know an angle from the measure of the opposite leg and the adjacent leg, and the trigonometric ratio that relates these data is the tangent. Then substituting in the formula of the tangent we have:
[tex]\tan (x)=\frac{opposite}{adjacent}[/tex]Replacing:
[tex]\tan (x)=\frac{15}{8}[/tex]Finally we obtain that the correct answer is the second option.
Coach Carter's budget to buy new uniforms is between $400 and $600. If anew set of uniforms cost $40 each, how many new sets can he afford to buy?Variable Represents:Inequality:Solve:Sentence:
Answers
Problem
Coach Carter's budget to buy new uniforms is between $400 and $600. If a
new set of uniforms cost $40 each, how many new sets can he afford to buy?
Solution
Variable Represents:
x= represent the number of sets that he can afford to buy
Inequality:
400 < 40x< 600
Solve:
400/40< x < 600/60
10 < x < 15
Sentence:
For this case we can conclude that the number of sets that he can afford to buy are between 10 and 15
The surface area of a rectangular prism is 174 square inches. The rectangular base has one side length 3 times the other. The height of the prism is 5 inches. What are the maximum lengths of the sides of the base?A. 6 inches and 18 inchesB. 8.7 inches and 26.1 inchesC. 4.35 inches and 13.05 inchesD. 3 inches and 9 inches
Answers
EXPLANATION:
We are given the following details for a triangular prism;
[tex]\begin{gathered} \text{Surface area}=174 \\ \text{Width}=w \\ \text{Length}=3w \\ \text{Height}=5 \end{gathered}[/tex]Note that for the rectangular base, one side is 3 times the other. Hence, if the width is w, then the length would be 3 times w.
The surface area of a rectangular prism is;
[tex]S=2(wl+hl+hw)[/tex]With the side lengths given we can now substitute and we'll have;
[tex]\begin{gathered} 174=2(\lbrack w\times3w\rbrack+\lbrack5\times3w\rbrack+\lbrack5w\rbrack) \\ 174=2(3w^2+15w+5w) \end{gathered}[/tex]Divide both sides by 2;
[tex]\begin{gathered} 87=3w^2+15w+5w \\ 87=3w^2+20w \end{gathered}[/tex]We shall now move all terms to one side of the equation;
[tex]3w^2+20w-87=0[/tex]We can now solve this quadratic equationwith the quadratic equation formula;
[tex]x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]Where the variables are;
[tex]a=3,b=20,c=-87[/tex][tex]w=\frac{-20\pm\sqrt[]{20^2-4(3)(-87)}}{2(3)}[/tex][tex]w=\frac{-20\pm\sqrt[]{400+1044}}{6}[/tex][tex]w=\frac{-20\pm\sqrt[]{1444}}{6}[/tex][tex]w=\frac{-20\pm38}{6}[/tex][tex]w=\frac{38-20}{6},w=\frac{-38-20}{6}[/tex][tex]w=3,w=-9\frac{2}{3}[/tex]We now have two solutions. We shall take the positive one since our side lengths cannot be a negative value.
Therefore having the width as 3, the length which is 3 times the width is 3 times 3 and that gives 9.
Therefore;
ANSWER:
[tex]D\colon3\text{inches and 9 inches}[/tex]57. The graph of y=8-r represents the graph of y=r’ after(1) a vertical shift upwards of 8 units followed by a reflection in the x-axis.(2) a reflection in the x-axis followed by a vertical shift of 8 units upward.(3) a leftward shift of 8 units followed by a reflection in the y-axis.(4) a reflection across the x-axis followed by a rightward shift of 8 units.
Answers
Recall that the function represented by the graph of the function h(x) reflected over the x-axis is:
[tex]-h(x)\text{.}[/tex]Also, recall that the graph represented by the graph of the function h(x) translated n units up is:
[tex]h(x)+n\text{.}[/tex]Therefore, the function represented by the graph of
[tex]y=x^2[/tex]after a reflection over the x-axis followed by a translation of n units up is:
[tex]y=-x^2+8.[/tex]Using the commutative property of addition we get:
[tex]y=8-x^2\text{.}[/tex]Answer: Second option.
$5,200 at 3% for 7 yearswhat is the simple interest?what is the total amount? hey mr or ms we need your help:)
Answers
simple interest = $1092
Total amount = $6292
Explanation:Principal = $5200
rate = 3% = 0.03
time = 7 years
Applying simple interest formula:
[tex]\begin{gathered} I\text{ = PRT} \\ \text{where I = interest} \\ I\text{ = P}\times R\times T \end{gathered}[/tex]I = 5200 × 0.03 ×7
I = $1092
simple interest = $1092
We are to find total amount after getting the interest:
Amount = principal + interest
Amount = $5200 + $1092
Amount = $6292
which two operations are needed to write the expression that reprsents "eight more than the product of a number and two"?
Answers
The first operation we have to take into account will be the product of a number and two, this is 2 times a number or 2*x, taking x as any number
The second one is an addition, eight more is written as +8.
The expression that represents the statement is 2x+8
if John makes $55 in 2 hours how much Would he make working 8 hours ?
Answers
You can use a rule of three to find the answer to this question.
$55------>2
x---------->8
The value of x, that is the amount he will do in 8 hours, is:
[tex]x=\frac{55\cdot8}{2}=220[/tex]He will make $220 in 8 hours.
Answer: 220
Step-by-step explanation:
because it is
evaluate the expression when c=4 and y=3 [tex]8 {x}^{2} + \frac{51}{y} [/tex]simplify as much as possible
Answers
EXPLANATION:
The steps to follow to evaluate an expression are the following:
-We must first replace the values in the corresponding assigned variable.
-Then we must begin to perform the operations of higher degree in this case, first solve the fraction, as well as double the 4.
The exercise is as follows:
[tex]\begin{gathered} 8x^2+\frac{51}{y} \\ 8(4)^2+\frac{51}{3} \\ 8(16)+17 \\ 128+17 \\ 145 \\ \text{the answer is 145} \end{gathered}[/tex]What is the measure of the reference angle for a -284° angle?
Answers
The measure of the reference angle for a -284 degree angle can be determined as,
[tex]\begin{gathered} RA=360^{\circ}-284^{\circ} \\ =76^{\circ} \end{gathered}[/tex]Thus, option (c) is the correct solution.
The quotient of a positive integer and a negative integer is:
Undefined
Positive
A
C.
0
Negative
B
D
Answers
Answer:
D
Step-by-step explanation:
D.Negative
The quotient of a positive integer and a negative integer is negative.
how should kelesha determine the amount she will pay for her computer?
Answers
Given:
The original price of the computer, CP = $900.
The discount rat offered on all computers, R=10%
Kalesha has a $100 gift card.
The discount is applied on the original price of the computer. So, Kalesha should first take 10% off and then only subtract $100 from it.
Therefore, the answer is " Take 10% off, then subtract $100.
The discount amount for the computer is calculated as,
[tex]\begin{gathered} D=\frac{R}{100}\times CP \\ =\frac{10}{100}\times900 \\ =90 \end{gathered}[/tex]Now, the amount after taking 10% off is,
[tex]\begin{gathered} A=CP-D \\ =900-90 \\ =810 \end{gathered}[/tex]There is a $100gift card. So, the final amount that Kalesha should pay can be calculated as,
[tex]undefined[/tex]Anna saved $40 each month from babysitting for 1 and 1/4 years.She spent 70% of her savings on a computer How much money did Anna have left?
write your answer as a decimal (to 2 places)
Answers
Anna have left [tex]\$180[/tex] money.
In the given question,
Anna saved [tex]\$40[/tex] each month from babysitting for [tex]1[/tex] and [tex]1/4[/tex] years.
She spent [tex]70\%[/tex] of her savings on a computer.
We have to find the money that left for Anna.
Anna saved [tex]\$40[/tex] each month.
She saved money for [tex]1[/tex] and [tex]1/4[/tex] years.
As we know that in a year have [tex]12[/tex] months.
Now we finding the months in [tex]1/4[/tex] years.
Since [tex]1[/tex] year [tex]=12[/tex] months
So [tex]1/4[/tex] years [tex]=12/4[/tex] months
So [tex]1/4[/tex] years [tex]=3[/tex] months
Now we finding the total months in [tex]1[/tex] and [tex]1/4[/tex] years.
There have [tex]12+3=15[/tex] months in [tex]1[/tex] and [tex]1/4[/tex] years.
Now find the total money that Anna saved.
[tex]=\$40\times15\\=\$600[/tex]
Hence, Anna saved [tex]\$600[/tex] in [tex]1[/tex] and [tex]1/4[/tex] years.
She spend [tex]70\%[/tex] of her saving.
Now finding how much she spend on buying computer.
So Spend Money for Computer [tex]=\$600\times70\%[/tex]
Since percent is shows the ration with [tex]100[/tex]. So we can write [tex]70\%[/tex] as [tex]70/100[/tex]. Now the equation is
Spend Money for Computer [tex]=\$600\times\frac{70}{100}[/tex]
Simplifying
Spend Money for Computer [tex]=\$6\times70[/tex]
Spend Money for Computer [tex]=\$420[/tex]
Now we finding the left money after buying the computer.
She saved total money [tex]=\$600[/tex]
Spend Money for Computer [tex]=\$420[/tex]
Now Left Money [tex]=\$600-\$420[/tex]
Now Left Money [tex]=\$180[/tex]
Hence, Anna have left [tex]\$180[/tex] money.
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