Find the value of sin(θ) for an angle theta in standard position with a terminal ray that passes through the point (4,-3)

Answers

Answer 1

Answer:

[tex]\dfrac{-3}{5}[/tex]

Step-by-step explanation:

It is given that a terminal ray that passes through the point (4,-3).

x = 4

y = -3

Using Pythagoras theorem, the value of hypotenuse is

[tex]r=\sqrt{x^2+y^2}[/tex]  

[tex]r=\sqrt{(-3)^2+(4)^2}[/tex]  

[tex]r=\sqrt{9+16}[/tex]  

[tex]r=\sqrt{25}[/tex]  

[tex]r=5[/tex]

We, know that

[tex]\sin \theta = \dfrac{y}{r}[/tex]

[tex]\sin \theta = \dfrac{-3}{5}[/tex]

Therefore, the value of [tex]\sin \theta[/tex] is [tex]\dfrac{-3}{5}[/tex].

Answer 2

Answer:

Step-by-step explanation:


Related Questions

When deriving the quadratic formula by completing the square, what expression can be added to both sides of the equation to create a perfect square trinomial?

Answers

Answer:

According to steps 2 and 4. The second-order polynomial must be added by [tex]-c[/tex] and [tex]b^{2}[/tex] to create a perfect square trinomial.

Step-by-step explanation:

Let consider a second-order polynomial of the form [tex]a\cdot x^{2} + b\cdot x + c = 0[/tex], [tex]\forall \,x \in\mathbb{R}[/tex]. The procedure is presented below:

1) [tex]a\cdot x^{2} + b\cdot x + c = 0[/tex] (Given)

2) [tex]a\cdot x^{2} + b \cdot x = -c[/tex] (Compatibility with addition/Existence of additive inverse/Modulative property)

3) [tex]4\cdot a^{2}\cdot x^{2} + 4\cdot a \cdot b \cdot x = -4\cdot a \cdot c[/tex] (Compatibility with multiplication)

4) [tex]4\cdot a^{2}\cdot x^{2} + 4\cdot a \cdot b \cdot x + b^{2} = b^{2}-4\cdot a \cdot c[/tex] (Compatibility with addition/Existence of additive inverse/Modulative property)

5) [tex](2\cdot a \cdot x + b)^{2} = b^{2}-4\cdot a \cdot c[/tex] (Perfect square trinomial)

According to steps 2 and 4. The second-order polynomial must be added by [tex]-c[/tex] and [tex]b^{2}[/tex] to create a perfect square trinomial.

Answer: D

Step-by-step explanation:

EDGE 2023

Bao can eat 12 chicken wings in 3 minutes.She eats the chicken wings at a constant rate how many chicken wings can bao eat in 12 minutes

Answers

Answer:

48 wings

Step-by-step explanation:

12:3 is the ratio. So multiply both of it by 4. Then it would be 48:12

Answer:

48 chicken wings

Step-by-step explanation:

If Bao can eat 12 chicken wings in 3 minutes and 12 minutes is 3 minutes times 4, then the answer would be 12 chicken wings times 4, so 12 times 4, which is 48, so the answer would be 48 chicken wings.

Solve by the quadratic formula: x^2= 6x-4

Answers

Answer:

3 [tex]\pm[/tex] [tex]\sqrt{5}[/tex].

Step-by-step explanation:

x^2 = 6x - 4

x^2 - 6x + 4 = 0

Now, we can use the quadratic formula to solve.

[tex]\frac{-b\pm\sqrt{b^2 - 4ac} }{2a}[/tex], where a = 1, b = -6, and c = 4.

[tex]\frac{-(-6)\pm\sqrt{(-6)^2 - 4 * 1 * 4} }{2 * 1}[/tex]

= [tex]\frac{6\pm\sqrt{36 - 4 * 4} }{2}[/tex]

= [tex]\frac{6\pm\sqrt{36 - 16} }{2}[/tex]

= [tex]\frac{6\pm\sqrt{20} }{2}[/tex]

= [tex]\frac{6\pm2\sqrt{5} }{2}[/tex]

= 3 [tex]\pm[/tex] [tex]\sqrt{5}[/tex]

x = 3 [tex]\pm[/tex] [tex]\sqrt{5}[/tex].

Hope this helps!

what are the like terms??? 5x2+3x-10+7x2-8x+11 PLEASE HELP!!!! ASAP!!!!

Answers

Answer:

5x² and 7x² are like terms because they contain x².

3x and 8x are like terms because they contain x.

10 and 11 are like terms because they are constants.

Step-by-step explanation:

Let's recall that the definition of like terms is that they are terms that contain the same variables raised to the same power and only like terms can be combined.

Upon saying that, we have:

5x² and 7x² are like terms because they contain x²

3x and 8x are like terms because they contain x

10 and 11 are like terms because they are constants.

HELPPPPPPPPPPPPPPPpppp

Answers

Answer:

Option (A)

Step-by-step explanation:

Two bases of the the given cylinder are circular in shape in the given picture.

When we take a cross-section of the cylinder parallel to the bases or perpendicular to the height, we get a circle exactly same as the bases (As shown on the rectangular slide).

Cross-section will have the same radius as the bases of the cylinder.

Therefore, Option (A) will be the answer.

Identifying relationships from diagrams

Answers

Answer: <CED is the right angle, which measures 90 degrees. Since the measure of a straight angle is 180 degrees. <CEA must also be 90 degrees by the Definition of Right Angle. A bisector cuts the angle measure in half. m<AEB is 45 degrees.

four less than three times a number is 20

Answers

Answer:

3x-4

Step-by-step explanation:

Have a good day!!

Answer:

3x-4

Step-by-step explanation:

ASAP!! Please help me. I will not accept nonsense answers, but will mark as BRAINLIEST if you answer is correctly with solutions.

Answers

Answer:

The function has two real roots and crosses the x-axis in two places.

The solutions of the given function are

x = (-0.4495, 4.4495)

Step-by-step explanation:

The given quadratic equation is

[tex]G(x) = -x^2 + 4x + 2[/tex]

A quadratic equation has always 2 solutions (roots) but the nature of solutions might be different depending upon the equation.

Recall that the general form of a quadratic equation is given by

[tex]a^2 + bx + c[/tex]

Comparing the general form with the given quadratic equation, we get

[tex]a = -1 \\\\b = 4\\\\c = 2[/tex]

The nature of the solutions can be found using

If [tex]b^2- 4ac = 0[/tex] then we get two real and equal solutions

If [tex]b^2- 4ac > 0[/tex] then we get two real and different solutions

If [tex]b^2- 4ac < 0[/tex] then we get two imaginary solutions

For the given case,

[tex]b^2- 4ac \\\\(4)^2- 4(-1)(2) \\\\16 - (-8) \\\\16 + 8 \\\\24 \\\\[/tex]

Since 24 > 0

we got two real and different solutions which means that the function crosses the x-axis at two different places.

Therefore, the correct option is the last one.

The function has two real roots and crosses the x-axis in two places.

The solutions (roots) of the equation may be found by using the quadratic formula

[tex]$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$[/tex]

[tex]x=\frac{-(4)\pm\sqrt{(4)^2-4(-1)(2)}}{2(-1)} \\\\x=\frac{-4\pm\sqrt{(16 - (-8)}}{-2} \\\\x=\frac{-4\pm\sqrt{(24}}{-2} \\\\x=\frac{-4\pm 4.899}{-2} \\\\x=\frac{-4 + 4.899}{-2} \: and \: x=\frac{-4 - 4.899}{-2}\\\\x= -0.4495 \: and \: x = 4.4495 \\\\[/tex]

Therefore, the solutions of the given function are

x = (-0.4495, 4.4495)

A graph of the given function is also attached where you can see that the function crosses the x-axis at these two points.

A cube has a side length of 5 cm. Determine the surface area of the largest pyramid that will fit inside the cube. Round if necessary.

Answers

Answer:

The surface area of the pyramid is 80.9 cm²

Step-by-step explanation:

The side length, s of the cube is given as 5 cm

Therefore, the largest pyramid that can fit into the cube will have a base side length, s = The side length of the cube = 5 cm

The height, h of the largest pyramid = The height of the cube = 5 cm.

The surface area of a pyramid =  Area of base, A + 1/2 × Perimeter of base, P × Slant height, S

The slant height of the pyramid = √(h² + (s/2)²) = √(5² + (5/2)²) = (5/2)×√5

The perimeter of the base = 4×5 = 20 cm

The area of the base = 5×5 = 25 cm²

The surface area of a pyramid = 25 + 1/2×20×(5/2)×√5 = 80.9 cm².

The surface area of a pyramid =  80.9 cm².

The total value of a collection of nickels and dimes is $3.05. If the number of nickels is 19 greater than the number of dimes, how many nickels are in the collection?

Answers

Answer:

N = 33

Step-by-step explanation:

N = D + 19

.05N + .10 D = 3.05

N = 33

D = 14

Solve this system of linear equations. Separate
the x- and y-values with a comma.
15x + 4y = -80
5x + 5y = 10​

Answers

Answer:

  (-8,10)

Step-by-step explanation:

hope i helped!

u can substitute if u want to recheck

can i get brainliest pls?

-Zylynn

Katya has $20.00 to spend at her college bookstore, where all students receive a 20% discount . katya wants to purchase a copy of a book that normally sells for $22.50 plus 10% sales tax. how much dose the book sell for dose katya have enough money bc bc?

Answers

Answer:

here you go :)

Step-by-step explanation:

You would take 20% of $22.50 (22.5 multiplied by .2). You would get $4.50 off of the book with the discount. So you would subtract 4.5 from 22.5 and get $18. Then you would take 10% of $18 for the sales tax. (18 multiplied by .1). You would get $1.80 towards sales tax. you would then add $1.80 to $18 and get $19.80.

How many x-intercepts does the graph of y=2x^2-8x+15 have?

Answers

The graph of y=2x^2-8x+15 has no x-intercepts.

Please answer the question in the image below ASAP

Answers

Answer:

B

Step-by-step explanation:

Here, we have a grain silo having 2 shapes fused together to make it.

A cylinder and then a hemisphere ( half sphere)

Now, we want to calculate the volume of grain that could completely fill the silo.

Mathematically, to do that, we will need to add the volume of the cylinder to the volume of the hemisphere.

Mathematically,

Volume of cylinder is;

pi * r^2 * h

From the question, r = 6 ft and h = 168 with pi = 22/7

Substituting these values, we have

Volume of cylinder= pi * 6^2 * 168 = 6,048 pi

The volume of the sphere will be;

4/3* pi * r^3= 4/3 * pi * 6^3 = 288 pi

So the total volume of the silo will be;

288 pi + 6,048 pi = 6336 pi

So to have the final result, let’s multiply by value of pi

6336 * 22/7 = 19,193 ft^3

The closest answer here probably due to previous approximations is 19,008 ft^3

PLEASE ANSWER FAST.What is the probability that only girls bought lunches? 25% 41.6% 75% 50%

Answers

Answer:

The correct answer is 50.6195

Step-by-step explanation:

The probability that only girls bought lunches is given as D. 50%

How to solve

To find the probability that only girls bought lunches, we solve:

We can see that the total number of girls is 30 and the total number of both boys and girls is 60

So, to solve, it becomes:

30/60= 50%

Probability is a mathematical concept used to measure the likelihood of an event occurring, ranging from 0 (impossible) to 1 (certain), and is calculated using ratios, frequencies, or subjective judgments.

Read more about probability here:

https://brainly.com/question/23417919

#SPJ2

Which list of ordered pairs represents solutions to x+y=2?
(-4, 6), (0, 2), (4, 2)
(-4, 6), (0, 2), (4, -2)
04-4, -6), (0, 2), (4, 2)​

Answers

Answer:

(-4, 6), (0, 2), (4, -2)

Step-by-step explanation:

You just need to guess and check.

(-4,6) → -4 + 6 = 2 ✔

(0,2) → 0+2 = 2 ✔

(4,2) → 4 + 2 = 6

(4, -2) → 4 - 2 = 2 ✔

(-4,-6) → -4 - 6 = -10

The correct answer is the second list (-4, 6), (0, 2), (4, -2)

What is the value of this expression when a = 2 and b = -3?
5

Answers

Answer:

5 is the answer..

Step-by-step explanation:

simply by calculating

30 POINTS!!!

Suppose f(x) = x2 and
g(x) = (1/3)^2. Which statement best compares the graph of g(x) with the graph of f(x)?

Image attached

Please help!!!

Answers

Answer:

A. The graph of g(x) is vertically compressed by a factor of 3.

Step-by-step explanation:

When there is a fraction, that means that there is a veritcal dilation.

Hope this helps! Good luck!

a system of linear equations is given by the tables. One of the tables is represented by the equation y= -1/3x + 7

the equation that represents the other equation y= x +

the solution of the system is ( , )​

Answers

Answer:

Other equation: y = 1/3x + 5

Solution: (3, 6)

Step-by-step explanation:

Slope-Intercept Form: y = mx + b

Slope Formula: [tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

Step 1: Identify tables

1st table is the unknown equation

2nd table is the known equation (found using y-intercept 7)

Step 2: Find missing equation

m = (6 - 5)/(3 - 0)

m = 1/3

y = 1/3x + b

5 = 1/3(0) + b

5 = b

y = 1/3x + 5

Step 3: Find solution set using substitution

1/3x + 5 = -1/3x + 7

2/3x + 5 = 7

2/3x = 2

x = 3

y = 1/3(3) + 5

y = 1 + 5

y = 6

Fill in the blank with a constant, so that the resulting expression can be factored as the product of two linear expressions: 2ab-6a+5b+___ Please include an explanation too!

Answers

Answer:

[tex]2ab - 6a + 5b - 15[/tex]

Step-by-step explanation:

Given

[tex]2ab - 6a + 5b + \_[/tex]

Required

Fill in the gap to produce the product of linear expressions

[tex]2ab - 6a + 5b + \_[/tex]

Split to 2

[tex](2ab - 6a) + (5b + \_)[/tex]

Factorize the first bracket

[tex]2a(b - 3) + (5b + \_)[/tex]

Represent the _ with X

[tex]2a(b - 3) + (5b + X)[/tex]

Factorize the second bracket

[tex]2a(b - 3) + 5(b + \frac{X}{5})[/tex]

To result in a linear expression, then the following condition must be satisfied;

[tex]b - 3 = b + \frac{X}{5}[/tex]

Subtract b from both sides

[tex]b - b- 3 = b - b+ \frac{X}{5}[/tex]

[tex]- 3 = \frac{X}{5}[/tex]

Multiply both sides by 5

[tex]- 3 * 5 = \frac{X}{5} * 5[/tex]

[tex]X = -15[/tex]

Substitute -15 for X in [tex]2a(b - 3) + 5(b + \frac{X}{5})[/tex]

[tex]2a(b - 3) + 5(b + \frac{-15}{5})[/tex]

[tex]2a(b - 3) + 5(b - \frac{15}{5})[/tex]

[tex]2a(b - 3) + 5(b - 3)[/tex]

[tex](2a + 5)(b - 3)[/tex]

The two linear expressions are [tex](2a+ 5)[/tex] and [tex](b - 3)[/tex]

Their product will result in [tex]2ab - 6a + 5b - 15[/tex]

Hence, the constant is -15

The table below represents an exponential function, g, that has been vertically shifted from the parent function, f(x)= 2^x. Determine the size of shift from function f to function g. Then plot the points of a function that is shifted only half as much as g from the parent function, f. Use the same x- values as used in the table for function g. Table x 0 1 2 3 4 g(x) -11 -10 -8 -4 4

Answers

Answer:

1. The size of shift from function f to function g is -12

2. The plot of the points of a function that is shifted only half as much as g from the parent function f is in the attached file in blue color.

Step-by-step explanation:

Parent function: f(x)=2^x

x=0→f(0)=2^0→f(0)=1

x=1→f(1)=2^1→f(1)=2

x=2→f(2)=2^2→f(2)=4

x=3→f(3)=2^3→f(3)=8

x=4→f(4)=2^4→f(4)=16

Size of the shift from function f to function g: s

s=g(0)-f(0)=-11-1→s=-12

s=g(1)-f(1)=-10-2→s=-12

s=g(2)-f(2)=-8-4→s=-12

s=g(3)-f(3)=-4-8→s=-12

s=g(4)-f(4)=4-16→s=-12

Points of a function h that is shifted only half as much as g from the parent function, f. Use the same x- values as used in the table for function:

s2=s/2→s2=(-12)/2→s2=-6

x   h(x)

0   1+(-6)=1-6=-5  

1    2+(-6)=2-6=-4

2   4+(-6)=4-6=-2

3    8+(-6)=8-6=2

4    16+(-6)=16-6=10

Solve the following 2 + 8 ÷ 2 x 3

Answers

Answer:

14

Step-by-step explanation:

Solution,

Use the BODMAS Rule:

B = Bracket

O = Of

D = Division

M= Multiplication

A = Addition

S = Subtraction

Now,

Let's solve,

[tex]2 + 8 \div 2 \times 3[/tex]

First we have to divide 8 by 2

[tex] = 2 + 4 \times 3[/tex]

Calculate the product

[tex] = 2 + 12[/tex]

Calculate the sum

[tex] = 14[/tex]

Hope this helps...

Good luck on your assignment..

Answer:

14

Step-by-step explanation:

2 + 8 ÷ 2 x 3 =

There is an addition, a division, and a multiplication. According to the correct order of operations, we do first the multiplications and divisions in the order they appear from left to right.

= 2 + 4 x 3

= 2 + 12

Now we do the addition.

= 14

Mike ran 2 km in 13 minutes.  If he continues at this same pace, how long will it take Mike to run 7 km?  Round your answer to the nearest minute.

minutes

Answers

Answer:

46 minutes.

Step-by-step explanation:

2 km in 13 minutes would equal to 6 minutes and 30 seconds per km.

minutes: 6 x 7 = 42

seconds: 30 x 7 = 210

seconds pt 2: 210/60 = 3 minutes 30 seconds

adding altogether: 42 minutes + 3 minutes 30 seconds + 45 minutes 30 seconds, rounded would equal to 46 minutes

help me Please!!!!!!!​

Answers

Answer:

[tex]2\sqrt{14\\}[/tex] = q

Step-by-step explanation:

use geometric mean method

4/s = s/10

s^2 = 40

s = 2[tex]\sqrt{10}[/tex]

consider the triangle STR and using the Pythagorean theorem

[tex]s^{2} +16 = q^{2} \\[/tex]

[tex](2\sqrt{10})^{2} +16 = q^{2}[/tex]

40 + 16 = q^2

56 = q^2

[tex]2\sqrt{14\\}[/tex] = q

At 3:30 p.m., Berto’s train was 34 miles past the egg farm, traveling at an average speed of 85 miles per hour. At the same time on a nearby track, Eduardo’s train was traveling at an average speed of 110 miles per hour and had 12 miles to go before it reached the egg farm. To the nearest hundredth of an hour, after how much time will the trains meet up? 0.11 hours 0.25 hours 0.88 hours 1.84 hours green t-shirts

Answers

Answer:

Step-by-step explanation:

Berto’s train was 34 miles past the egg farm .

Eduardo’s train had 12 miles to go before it reached the egg farm.

Distance between two trains = 34 + 12 = 46 miles

This distance has to be reduced to zero for their crossing each other .

Rate at which this distance is reduced  = their relative velocity

= 110 - 85

= 25 miles / h       [ They are moving in the same direction ]

So, time taken for them to meet each other

= 46 / relative velocity

= 46 / 25

= 1.84 hours .

Answer:

The answer is D or 1.84 hours.

Step-by-step explanation:

I got 100% on this quiz.

first correct answer gets best marks ​

Answers

Answer:

the answer would be x is less than 6.

Step-by-step explanation:

the reason why it would not be x is less than or equal to 6 is that the circle is not filled in.

Answer:

B

Step-by-step explanation:

x≤6

We can see from the graph that it starts from 6 and goes to 5, 4, 3, 2.

Hope this helps ;) ❤❤❤

Find the area ratio of a regular octahedron and a tetrahedron regular, knowing that the diagonal of the octahedron is equal to height of the tetrahedron.

Answers

Answer:

[tex]\frac{4}{3}[/tex]

Step-by-step explanation:

The area of a regular octahedron is given by:

area = [tex]2\sqrt{3}\ *edge^2[/tex]. Let a is the length of the edge (diagonal).

area = [tex]2\sqrt{3}\ *a^2[/tex]

Given that the diagonal of the octahedron is equal to height (h) of the tetrahedron i.e.

a = h, where h is the height of the tetrahedron and a is the diagonal of the octahedron. Let the edge of the tetrrahedron be e. To find the edge of the tetrahedron, we use:

[tex]h=\sqrt{\frac{2}{3} } e\\but\ h=a\\a=\sqrt{\frac{2}{3} } e\\e=\sqrt{\frac{3}{2} }a[/tex]

The area of a tetrahedron is given by:

area = [tex]\sqrt{3}\ *edge^2[/tex] = [tex]\sqrt{3} *(\sqrt{\frac{3}{2} }a)^2=\frac{3}{2}\sqrt{3} *a^2[/tex]

The ratio of area of regular octahedron to area tetrahedron regular is given as:

Ratio = [tex]\frac{2\sqrt{3}\ *a^2}{\frac{3}{2} \sqrt{3}*a^2} =\frac{4}{3}[/tex]

I NEED HELP WITH THIS! I need to pass...

Answers

Answer:  A) The log parent function has negative values in the range.

Step-by-step explanation:

The domain of y = ln (x)  is D: x > 0

The domain of y = [tex]\sqrtx[/tex][tex]\sqrt x[/tex]  is  D: x ≥ 0

The range of y = ln (x)  is: R: -∞ < y < ∞

So the only valid option is A because the range of a log function contains negative y-values when 0 < x < 1.

Which graph represents the solution set for the system x+y greater than or equal to 5 and -3x+2y less than or equal than to -2

Answers

Step-by-step explanation:

in each equation once substitute the value of x as 0 and again y as zero by this way you will get two values of X and y .

then again find the slope for each equation by the formula

slope= -coefficient of x / coefficient of y

for example,

X+y is greater or equals to 5

or, X+y= 5

or, X=5-y

or, when y is equals to zero

X= 5

and when X is equals to zero

y= 5

then plot the above point in the graph with respect to its slope and the shaded part is the solution

Please help me to solve this . Thank you so much .
And if possible , could you explain the answer too ?

Base on the diagram , state

a) The point which is 2 cm from R and 4 cm from P

b) The point which is more than 2 cm from R and 4 cm from T

c) The location of a moving point X in the diagram such that it is less than 4 cm from P and more than 2cm from R

d) The location of a moving point Y in the diagram such that YR < 2 cm and YP < 4 cm

e)The location of a moving point Z in the diagram such that ZT > 4 cm , ZP > 4 cm and ZR > 2 cm

Answers

Answer:

a) N

b) L

c) area I

d) area II

e) area VI

Step-by-step explanation:

a) the points that are 2cm from R are Q, N, M, S. Then, points that are 4cm from P are K, N, R. So, the only one point that works for both is N.

b) the points that are >2cm from R are P, K, L, T. We do not count those are exactly 2cm from R. Then, points that are 4cm from T are R, M, L. Ans is L.

c) <4cm from P, are area I and II. Then area that are >2cm from R are I, VI, and V. So, the only area that works for both is I.

d) <2cm from R, are areas II, III, and IV. Then, <4cm from P, are areas I and II. So, the only one works for both is area II.

e) >4cm from T, are areas I, II, III, VI. Then, >4cm from P, are III, IV, V, VI. Finally, >2cm from R, are areas I, VI, V. The only one that works for all three conditions is area VI.

Other Questions
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