Find the y-intercept and the slope of the line. y=-5/4x+3

Answer: 45

Step-by-step explanation:

The Median is the Middle # in the set.

I hope this helps!

Answer:8755

Step-by-step explanation:100%+3%=103% in decimal form 1.03

8500x1.03=8755

Answer:

35%

Step-by-step explanation:

First, we add :)

25 + 35 + 40 = 100

Now we divide :)

35/100 = 0.35 = 35%

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Answer:

30%

Step-by-step explanation:

You Do it

Answer:

The answer is 274

Step-by-step explanation:

Now,

Definition of Variance:

So,

[tex] \frac{ {(87 - 78)}^{2} + ( {46 - 78)}^{2} + (90 - 78) {}^{2} + ({78 - 78)}^{2} + ( {89 - 78)}^{2} } {5} [/tex]

[tex]Var(X) \: = \frac{1370}{5} = 274 \\ [/tex]

Thus, The variance of the sequence is 274.

Answer:

Let x be the cost price.

Let y be the marked price

Gain = 20%

Then , sale price = 120/100 * x = 1.2x

Now , sale price is after 10% discount from marked price.

Hence , marked price, y = 1.2x/90 * 100 =

y * 0.9 = x * 1.2

Now, with 20% discount, sale price = y * 80/100 = 0.8y

Now, profit = 0.8y — x

Now, 0.8y — x = 350

0.8 * x * 1.2/0.9 — x = 350

1.0667x — x = 350

Hence, x = 350/0.0667= Rs.5250

Hence marked price = (5250 + 350) * 100/80 = Rs.7000

Answer:

The weight, in pounds, of one bag of beans.

Step-by-step explanation:

Since we know that there are 15 bags of beans, we can eliminate the first option and anything about something other than th e beans. Also, we know that we are not given the information on how heavy the bag of beans are, so with process of elimination, the 3rd one is the answer.

I hope this helped!

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Answer:

[tex]\displaystyle \large{\frac{11}{3} < \sqrt{17} < \sqrt{20}}[/tex]

Step-by-step explanation:

( 1 ) 11/3

[tex]\displaystyle \large{\frac{11}{3}}[/tex] can be converted to mixed fractions to [tex]\displaystyle \large{3\frac{2}{3}}[/tex]

Therefore, 11/3 is at least around 3, almost 4. It could be more than 3.5 by approximation but not exactly 4.

( 2 ) √20

[tex]\displaystyle \large{\sqrt{20}=\sqrt{5\cdot 4}}\\\displaystyle \large{\sqrt{20}=\sqrt{5\cdot 2\cdot 2}}\\\displaystyle \large{\sqrt{20}=2\sqrt{5}}[/tex]

We know that [tex]\displaystyle \large{\sqrt{4}=2}[/tex] so [tex]\displaystyle \large{\sqrt{5} > \sqrt{4}}[/tex] which means approximately, [tex]\displaystyle \large{\sqrt{20}}[/tex] can be either at least 4.3 up to 4.4

( 3 ) √17

We know that [tex]\displaystyle \large{\sqrt{16} = 4}[/tex] so [tex]\displaystyle \large{\sqrt{17}}[/tex] can be at least 4.1 up to 4.2, but it’s obvious that the square root of 17 is less than square root of 20 since [tex]\displaystyle \large{\sqrt{a} > \sqrt{b}}[/tex] for a > b

Hence, from least to greatest:

[tex]\displaystyle \large{\frac{11}{3} < \sqrt{17} < \sqrt{20}}[/tex]

According to the given sine function, it is found that the period of rotation is of 0.21 seconds.

Suppose a sine function modeled by:

[tex]y = A\sin{[B(x + c)]}[/tex]

The period is given by:

[tex]P = \frac{2\pi}{B}[/tex].

In this problem, the function is:

h(t)=60+45 sin (30t).

The vertical shift and the amplitude do not interfer in the period, hence B = 30 and:

[tex]P = \frac{2\pi}{30} = 0.21[/tex]

The period of rotation is of 0.21 seconds.

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Answer:

See below ↓↓↓↓↓

Step-by-step explanation:

= 1 more than a number (a)

= q less than 9

= 3 times y added to 7

= a number (x) divided by 3 more than 9

= 3 times x added to 10

Answer:

Step-by-step explanation:

Remark

You could do this simply by taking 3 jumps, without using a formula. That would work as well, but I think it is easier just to make 3 jumps.

Jump One

The frog starts out 6 meters from an edge. (He/she starts at the middle). The frog makes 1 jump.

He lands 3 meters (1/2 the distance) from the edge.

Jump Two

He jumps in such a way that he is 1/2 the distance from the edge. So far he is 3 meters away. His jump puts him 1 1/2 meters from the edge.

Jump Three

The frog makes one last jump. It is 1 1/2 meters from the edge. The third jump takes it 1/2 * 3/2 = 3/4 a meter away from the edge.

Answer: 3/4 of a meter from the edge.

Answer:

m(C)<m(B)<m(A).

Step-by-step explanation:

1) according to the condition the shortest side is AB, the longest side is BC, the middle is AC. Then

2) the smallest angle is BCA (or C), the middle angle is ABC (or B), the largest angle is BAC (or A).

The list of the angles from smallest to largest are C, B and A.

Given that a triangle has side measurements represented in terms of the variable m, where m > 6.

AB = m - 2

BC = m + 4

AC = m

We need to list the angles from smallest to largest.

Since none of the sides are equal, therefore it is a scalene triangle.

Let us consider m = 6.

Then,

AB = m - 2

AB = 6 - 2

AB = 4

BC = m + 4

BC = 6+4

BC = 10

AC = m

AC = 6

It means that the longest side is BC, the medium side is AC and the shortest side is AB.

We know that the longest side of a triangle corresponds to the largest angle and vise versa.

Therefore,

The smallest angle is angle C.

The medium angle is angle B.

The largest angle is angle A

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Answer:

the last answer is -1 :))))))

+ - makes a minus

+ + make a plus

-- makes a plus

7.0 - 2.9 = 4.1

Hope this helps!

Answer:

x^2 - 5x - 66

Step-by-step explanation:

1. Distrubute the x to the x and -11 so you will get x^2 - 11x

2. Distrubute the 6 to x and -11 and you get 6x - 66

3. Combine like terms (x^2 - 11x + 6x - 66) you will get x^2 - 5x - 66

Answer:

4x - 5y = 25

Step-by-step explanation:

Answer:

50

Step-by-step explanation:

100/2=50

Answer:

100 divided by 2 is 50

Step-by-step explanation:

i just did it in my head

[tex] \Large{\boxed{\sf x = 9}} [/tex]

[tex] \\ [/tex]

Given equation:

[tex] \sf 10 + \dfrac{x}{3} = 13 [/tex]

[tex] \\ [/tex]

Subtract 10 from both sides:

[tex] \sf 10 + \dfrac{x}{3} - 10 = 13 - 10 \\ \\ \sf \dfrac{x}{3} = 3 [/tex]

[tex] \\ [/tex]

Multiply both sides by 3:

[tex] \sf 3 \times \dfrac{x}{3} = 3 \times 3 \\ \\ \\ \boxed{\boxed{\sf x = 9}} [/tex]

[tex] \\ \\ [/tex]

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Answer:

Step-by-step explanation:

In this question we have provided an equation that is 10 + X/3 = 13 . And we're asked to find the value of X .

Solution : -

[tex] \longmapsto \qquad \: 10 + \dfrac{X}{3} = 13[/tex]

Step 1 : Multiplying with 3 on both sides :

[tex]\longmapsto \qquad \:(10 + \dfrac{X}{3} ) \times 3=13\times3[/tex]

Now by using distributive property multiplying 3 with 10 as well as X/3 :

[tex] \longmapsto \qquad \: (10 \times 3) + ( \dfrac{X}{ \cancel{3}} \times \cancel{3}) = 13 \times 3[/tex]

On calculating further , We get :

[tex] \longmapsto \qquad \: 30 + X = 39[/tex]

Step 2 : Subtracting with 30 on both sides :

[tex] \longmapsto \qquad \: \cancel{30} + X - \cancel{30} = 39 - 30[/tex]

On calculating further , We get :

[tex] \longmapsto \qquad \: \purple {\underline{{\boxed{\frak{X= 9}}}}}[/tex]

Verifying : -

Now we are checking whether our answer is correct or wrong by substituting values of x in given equation . So ,

Therefore , our value for x is correct .

Answer:

- 4

Step-by-step explanation:

the absolute value function always give a positive result , that is

| - a | = | a | = a

then

- | - 4 | = - | 4 | = - 4

Step-by-step explanation:

[tex] \frac{5}{ {x }^{2} + 6x + 8} = \frac{a}{x + 2} + \frac{b}{x + 4} \\ factorizing \: the \: denominator \: of \: the \: first \: term \\ {x}^{2} + 6x + 8 \\ {x}^{2} + 4x + 2x + 8 \\ ( {x}^{2} + 4x)( + 2x + 8) \\ x(x + 4) + 2(x + 4) \\( x + 2)(x + 4) \\ \\ \\ \\ \frac{5}{(x + 2)(x + 4)} = \frac{a}{x + 2} + \frac{b}{x + 4 } \\ multiplying \: by \: the \: lcm = (x + 2)(x + 4) \\ 5 = a(x + 4) + b(x + 2) \\ put \: x = - 4 \\ 5 = a( - 4 + 4) + b( - 4 + 2) \\ 5 = a(0) + b( - 2) \\ 5 = 0 - 2b \\ 5 = - 2b \\ b = \frac{5}{ - 2} \\ b = - 2 \ \frac{1}{2} \\ substituting \: b = - 2 \frac{1}{2} and \: put \: x = - 2 \\ 5 = a( - 2 + 4) + b( - 2 + 2) \\ 5 = a(2) + b(0) \\ 5 = 2a \\ a = 2 \frac{1}{2} \\ a + b = 2 \frac{1}{2} + ( - 2 \frac{1}{2} ) \\ 2 \frac{1}{2} - 2 \frac{1}{2} \\ a + b = 0[/tex]

Answer:

For all of these triangles apply the formula;

A = BH x 1/2

Where 'B' represents the base, 'H' stands for the height, and 1/2 just means to divide the product of the two lengths (base x height) by 2.

1.

Base = 9.1

Height = 31.2

Plug into formula:

A = BH x 1/2

A = 9.1(31.2) x 1/2

A = 283.92 x 1/2

A = 283.92/2

A = 141.96 square centimetres.

2.

Base = 5

Height = 3 3/4 which can be considered 3.75

Plug into formula:

A = BH x 1/2

A = 5(3.75) x 1/2

A = 18.75 x 1/2

A = 18.75/2

A = 9.375 square kilometres.

3.

Base = 2.4

Height = 3.2

Plug into formula:

A = BH x 1/2

A = 2.4(3.2) x 1/2

A = 7.68 x 1/2

A = 7.68/2

A = 3.84 square inches.

4.

Base = 11

Height = 60

Plug into formula:

A = BH x 1/2

A = 11(60) x 1/2

A = 660 x 1/2

A = 660/2

A = 330 square millimetres.

5.

Base = 10

Height = 13 1/2 which can be considered 13.5

Plug into formula:

A = BH x 1/2

A = 10(13.5) x 1/2

A = 135 x 1/2

A = 135/2

A = 67.5 square feet.

Answer:

1. 141.96 cm²

2. 9⅜ km²

3. 3.84 in

4. 10.39mm

5. 66.67 ft

Step-by-step explanation:

Formula of Area of Triangle : ½ × base × height

1. = ½ × 9.1 × 31.2

= 9.1 × 15.6

= 141.96 cm²

2. = ½ × 3¾ × 5

= ½ × 15/4 × 5

= 15/8 × 5

= 75/8 = 9⅜ km²

3. = ½ × 3.2 × 2.4

= 3.84 in

4. = tan c = AB/BC

c = tan -¹ (AB/BC)

c = tan -¹ (60/11)

c = 79.61

A = 90 - 79.61 = 10.39mm

5. = ½ × 13⅓ × 10ft

= 66.666 ≈ 66.67 ft

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Answer:

x = the amount of money Jane had before she took out any

x - 135 = 650

x = 785

Step-by-step explanation:

Let x = the amount of money Jane had before she took out any

Set up the equation

x - 135 = 650

To solve the equation, we must add 135 on both sides to cancel the -135 on the left side of the equal sign.

x - 135 = 650

x = 785

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Answer:

D. $43.00x + $466.43 < $1,059.35

Step-by-step explanation:

He has $1,059.35.

The amount of speakers he buys is x.

Each speaker is $43.00, and he is buying one television, which is $466.43.

All of the speakers he buys and(+) the television must be less than $1,059.35 because that's all he has. It cannot be more, which is why the equation is $43.00x + $466.43 < $1,059.35.

Hope this helps!

Answer:

D

Step-by-step explanation:

its $43 each and he wants to buy more than one so that means thats x

that marks out C

so 43.00x +466.43 is less than 1,059.35

I really feel like one of them should have less than/greater than or equal to sign but without I think its D

Answer:

4 5/6

Step-by-step explanation:

Turn both 8 1/3 and 3 1/2 into improper fractions (just to make it less complicated).

8 1/3 = 25/3

3 1/2 = 7/2

Then, try and make the denominators the same by finding the LCD (least common denominator).

The least common denominator of 3 and 2 is 6. Multiply both the denominators (3 and 2) to get 6, multiply the numerator with it as well (I can't explain this part properly, but the fractions will somehow explain).

[tex]\frac{25*2}{3*2}[/tex] = [tex]\frac{50}{6}[/tex]

[tex]\frac{7*3}{2*3}[/tex] = [tex]\frac{21}{6}[/tex]

So, then subtract (50/6 - 21/6).

50/6 - 21/6

= 29/6 = 4 5/6

So, 8 1/3 - 3 1/2 is 4 5/6.

Answer:

I believe it is B

Step-by-step explanation:

it has somewhat some thing to do with the lines at BC it's had to put in words

The postulate or theorem can be used to prove that ΔABC ≅ ΔDCB is ASA.

The correct option is A.

Congruency is a concept in geometry that refers to the equality of shape and size between two or more geometric figures. When two figures are congruent, it means that they have exactly the same shape and size, and their corresponding sides and angles are equal.

In ΔABC and ΔDCB

<BAC= <BDC (given)

<BCA= <DBC(given)

CB = CB (common)

So, by ASA criteria ΔABC ≅ ΔDCB.

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Right angled triangle

Area:-

[tex]\\ \rm\rightarrowtail \dfrac{1}{2}BH[/tex]

[tex]\\ \rm\rightarrowtail \dfrac{1}{2}(2.4)(1.8)[/tex]

[tex]\\ \rm\rightarrowtail 1.2(1.8)[/tex]

[tex]\\ \rm\rightarrowtail 2.16cm^2[/tex]

Answer:

midine y=2

amplitude -3

period 5pie

Answer:

15.8

I think there is a part of the question missing (the triangle is a right triangle)

hope this helps

+let me know if you need an explanation

Answer:

B: y = 2x + 3

Step-by-step explanation:

The 2x is the slope, and the 3 is the y-intercept

The y-intercept is kinda like how far the slope is from zero, but it can only be applied to the y-axis.

The slope is... well... the slope-- like how steep it is. If a slope is 2/1, like in the graph, it will go higher 2 units every 1 unit across. Or, if the slope is 1/4: The slope will go 1 unit higher every 4 units