fish swimming in a horizontal plane has velocity v with arrowi = (4.00 î + 1.00 ĵ) m/s at a point in the ocean where the position relative to a certain rock is r with arrowi = (14.0 î − 2.80 ĵ) m. After the fish swims with constant acceleration for 19.0 s, its velocity is v with arrow = (23.0 î − 1.00 ĵ) m/s. (a) What are the components of the acceleration of the fish? ax = m/s2 ay = m/s2 (b) What is the direction of its acceleration with respect to unit vector î? ° counterclockwise from the +x-axis (c) If the fish maintains constant acceleration, where is it at t = 26.0 s? x = m y = m In what direction is it moving? ° counterclockwise from the +x-axis

The kinetic energy is related to the motion of the marble, but the potential energy is related to its position. The marble's potential energy is transformed into kinetic energy as it slides down the ramp from the top.

The stone has potential energy when it is at the top of the ramp because gravity will lead it to fall. The term for this is gravitational potential energy. The stone is freed, and the potential energy transforms into kinetic energy as it moves. Kinetic energy is the term used to describe a moving object.

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[tex]75 = 6 \times \frac{?}{?} \times \frac{?}{?} [/tex]

Answer:

the voltage gain of the amplifier is approximately 416.9.

Explanation:

We can use the voltage gain formula of the amplifier to determine its voltage gain:

Voltage Gain = (Output Voltage Amplitude) / (Input Voltage Amplitude)

The output voltage amplitude is given as 18 V peak, and the input voltage amplitude is 1.5 V peak.

To calculate the input voltage in terms of RMS, we can use the formula:

Vrms = Vpeak / sqrt(2)

Therefore, the input voltage amplitude in RMS is:

Vrms = 1.5 Vpeak / sqrt(2) = 1.06 Vrms

The input current amplitude is given as 1 mA peak, and we can similarly calculate the input current amplitude in RMS:

Irms = 1 mA peak / sqrt(2) = 0.707 mA RMS

Now we can use the given information to determine the voltage gain of the amplifier:

Output Voltage Amplitude = 18 V peak

Input Voltage Amplitude = 1.06 Vrms

Input Current Amplitude = 0.707 mA RMS

The current drawn by the amplifier from each of its power supplies is 0.1 A, and since there are two power supplies, the total power consumed by the amplifier is:

P = (2 * 0.1 A) * (± 20 V) = 4 W

We can now use the power gain formula to determine the voltage gain of the amplifier:

Power Gain = (Output Power) / (Input Power)

The output power can be calculated as:

Pout = (Vout^2) / Rload = (18 V peak)^2 / 100 Ω = 3.24 W

The input power can be calculated as:

Pin = (Vrms^2 / Rin) + (Irms^2 * Rin)

where Rin is the input resistance of the amplifier.

Assuming the input impedance of the amplifier is much larger than 100 Ω, we can neglect the first term in the above equation, and we get:

Pin = (Irms^2 * Rin)

Solving for Rin, we get:

Rin = (Pin / Irms^2) = (4 W / (0.707 mA RMS)^2) = 80.4 kΩ

Now we can calculate the input power as:

Pin = (Vrms^2 / Rin) + (Irms^2 * Rin) = (1.06 Vrms)^2 / (80.4 kΩ) + (0.707 mA RMS)^2 * (80.4 kΩ) = 7.77 mW

Therefore, the voltage gain of the amplifier can be calculated as:

Voltage Gain = (Output Power) / (Input Power) = (3.24 W) / (7.77 mW) = 416.9

Therefore, the voltage gain of the amplifier is approximately 416.9.

Answer:

To find the voltage gain of the amplifier, we need to first determine the output voltage in relation to the input voltage. From the information given, we know that the input voltage is 1.5 V peak, and the output voltage is 18 V peak. Therefore, the voltage gain can be calculated as:

Voltage gain = output voltage / input voltage

Voltage gain = (18 V peak) / (1.5 V peak) = 12

This means that the output voltage is 12 times greater than the input voltage.

Next, we need to determine the input impedance of the amplifier. From the information given, we know that the input current is in sinusoidal form with 1 mA peak, and that the amplifier draws a current of 0.1 A from each of its power supplies. Therefore, the input impedance can be calculated as:

Input impedance = input voltage / input current

Input impedance = (1.5 V peak) / (1 mA peak) = 1500 Ω

Now, we can use Ohm's law to determine the power consumed by the amplifier from each of its power supplies:

Power supply current = 0.1 A

Power supply voltage = ± 20 V

Power supply power = (Power supply voltage) x (Power supply current)

Power supply power = (20 V) x (0.1 A) = 2 W

Therefore, the amplifier consumes 2 W from each of its power supplies.

In summary, the voltage gain of the amplifier is 12, the input impedance is 1500 Ω, and the amplifier consumes 2 W from each of its power supplies.

(Please could you kindly mark my answer as brainliest)

Answer:

0.615j would be the answer to your question.

The displacement has a 3 m magnitude and is moving in the opposite direction as the external force, which is pushing backwards.

With the provided information for the 4 kilogramme mass, we can get the spring constant. The displacement of a 1.5 kg mass is then determined using the formula x = F/k. The work needed to stretch a spring x distances from its equilibrium position is W = 12kx2.

We can use the following formula to determine the force a spring exerts:

F = -kx

The magnitude of the force exerted by the spring is:

F = -kx

-600 N = -200 N/m * x

Solving for x, we get:

x = 3 m

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A normative approach to lifespan development involves studying and comparing the typical patterns of development and behavior across different individuals or groups of people at various ages. Here are some benefits of using this approach:

Identifying developmental milestones: A normative approach helps to identify the typical milestones and achievements that people reach at different ages, such as crawling, walking, talking, and reading. This can help parents, educators, and healthcare professionals to monitor and assess a child's development and provide appropriate support and interventions when necessary.

Understanding individual differences: While a normative approach focuses on typical patterns of development, it also recognizes that there are individual differences in development and behavior. By comparing people's development to the norm, we can better understand how and why some individuals may differ from the norm, such as in terms of their physical, cognitive, or socioemotional development.

Informing public policies and interventions: A normative approach can help to inform public policies and interventions that support healthy development across the lifespan. For example, knowledge about the typical milestones of development can inform early childhood education programs, while information about the typical age-related changes in cognition and memory can inform policies related to employment and retirement.

Answer:

See below.

Explanation:

The list of given we have:

(a) We are asked to find the acceleration of the system if the system is released from rest.

We can simply distinguish between the forces operating on the two masses to provide an answer. We must first determine the force affecting the masses. Hence, the only force acting on mass 2 is the gravitational force since it is suspended from the cord.

[tex]Fg=m_2g[/tex]

[tex]F_g=(4.5Kg)(9.8m/s^2)[/tex]

[tex]F_g=44.1N[/tex]

while for the mass 1 we have the static frictional force,

[tex]f_s=u_sN[/tex]

[tex]f_s=(0.60)(11.0Kg)(9.8m/s^2)[/tex]

[tex]f_s=64.68N[/tex]

We may infer that if the system is released from rest, it does not move at all since the static frictional force acting on mass 1 was greater than the gravitational force acting on mass 2, which means the system's acceleration must be equal to [tex]a=0m/s^2[/tex].

(b) We are asked to find the acceleration of the system if the mass 2 moves downward.

For this question, we must draw a free-body diagram (attachment #1).

Since we are able to draw a free-body diagram and identify the force(s) acting on the masses, we can find the acceleration of the system using the equation of Newton's second law, so we have:

[tex]F_\text{net}=m_{sys} a[/tex]

[tex]a=\frac{F_{net}}{m_{sys}}[/tex]

where the [tex]F_{net}[/tex] is the sum of force(s) acting on the system and [tex]m_{sys}[/tex] is the total mass of the system,

[tex]a=\frac{Fg_2-T+T-f_k}{m_1+m_2}[/tex]

[tex]a=\frac{F_g2 - f_k}{m_1+m_2}[/tex]

[tex]a=\frac{m_2g-u_km_1g}{m_1+m_2}[/tex]

substituting all of the given

[tex]a=\frac{(4.5Kg)(9.8m/s^2)-(0.30)(11.0Kg)}{11.0Kg-4.5Kg}[/tex]

[tex]a=\frac{40.8Kgm/s^2}{6.5Kg}[/tex]

[tex]a=6.2769[/tex]

We can conclude that if the mass 2 is going downward then the acceleration of the system would be [tex]6.2769m/s^2.[/tex]

Answer:

i'm going to go with 5

Explanation:

f=ma

55=10a

a=55/10

now we know the constant acceleration

now we just use the  formula

v^2=u^2+2as

now, the kinetic energy formula is 1/2 * m * v^2

1/2 * 10 * (√47.3)^2

1/2 * 10 * 47.3

=236.5 J of kinetic energy

kinetic energy is the energy a moving item has. To accelerate an item, we must apply force. Using force needs us to perform labor. Once the work is completed, energy is transferred to the item, and the thing moves at a new constant speed.

Kinetic energy (KE) is defined in classical mechanics as half of an object's mass (1/2*m) multiplied by velocity squared. For example, if a 10 kilogram item moves at a velocity of 5 meters per second (v = 5 m/s), the kinetic energy is 125 Joules, or (1/2 * 10 kg) * 5 m/s2.

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Answer:

A spring scale measures weight or force when an object is hung from its hook.

Explanation:

a) The mass of air in the balloon is 2850 kg.

b) The buoyant force acting on the balloon is 93258.6 N.

c) The acceleration of the balloon and the riders is 24.8 m/s².

d) the minimum volume the balloon can have before it goes downward instead of upward is 14118.5 m³.

e) The balloon will start to rise more slowly or may even stop rising altogether.

f) The balloon will rise more quickly or may even accelerate.

a. The mass of air in the balloon can be calculated by multiplying the density of the air by the volume of the balloon:

Mass of air = Density of air × Volume of balloon

Mass of air = 0.95 kg/m³ × 3000 m³

Mass of air = 2850 kg

Therefore, the mass of air in the balloon is 2850 kg.

b. The buoyant force acting on the balloon can be calculated using Archimedes' principle, which states that the buoyant force is equal to the weight of the fluid displaced by the object:

Buoyant force = Density of fluid × Volume of fluid displaced x Gravity

Buoyant force = (Density of air - Density of balloon) × Volume of balloon × Gravity

Buoyant force = (1.22 kg/m³ - 0.95 kg/m³) × 3000 m³ × 9.81 m/s²

Buoyant force = 93258.6 N

Therefore, the buoyant force acting on the balloon is 93258.6 N.

c. The net force acting on the balloon and the riders is equal to the buoyant force minus the weight of the system:

Net force = Buoyant force - Weight of system

Net force = 93258.6 N - 400 kg × 9.81 m/s²

Net force = 88836.6 N

The acceleration of the system can be calculated using Newton's second law:

Net force = Mass of system × Acceleration

Acceleration = Net force / Mass of system

Acceleration = 88836.6 N / (400 kg + 2850 kg)

Acceleration = 24.8 m/s²

Therefore, the acceleration of the balloon and the riders is 24.8 m/s².

d. The minimum volume the balloon can have before it goes downward instead of upward can be calculated by setting the buoyant force equal to the weight of the system:

Buoyant force = Weight of system

(Density of air - Density of balloon) × Volume of balloon × Gravity = (Mass of air + Mass of system) × Gravity

Volume of balloon = (Mass of air + Mass of system) / (Density of air - Density of balloon)

Volume of balloon = (2850 kg + 400 kg) / (1.22 kg/m³ - 0.95 kg/m³)

Volume of balloon = 14118.5 m³

Therefore, the minimum volume the balloon can have before it goes downward instead of upward is 14118.5 m³.

e. As the balloon rises, the lower air pressure causes the air around the balloon to become less dense. This means that the density of the fluid that the balloon displaces decreases, which reduces the buoyant force acting on the balloon. As a result, the balloon will start to rise more slowly or may even stop rising altogether if the density of the displaced air becomes equal to the density of the balloon.

f. As the balloon rises, the atmospheric pressure decreases, causing the volume of the balloon to increase. This expansion of the balloon increases the volume of air that it displaces, which in turn increases the buoyant force acting on the balloon. As a result, the balloon will rise more quickly or may even accelerate if the expansion of the balloon is significant enough.

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Answer:

R2 + R3 = R2 R3 / (R2 + R3) = R23         R2 and R3 in parallel

R1 + R23 = R1 R23 / (R1 + R23)     R1 in parallel with R2 and R3

R = R1 R23 / (R1 + R23)

R23 = 147 * 163 / (147 + 163) = 77.3 Ω

R = 77.3 * 140 / (77.3 + 140) = 49.8 Ω

I = 212 / 49.8 = 4.26 amps thru circuit

R23 = 77.3

I23 = 212 / 77.3 = 2.74 amps thru R23

I1 = 212 / 140 = 1.51 thru R1

I1 + I23 = 1.51 + 2.74 = 4.25       current thru entire circuit

Current thru R2 current thru R23 = 2.74 amps

Matching the government activities to the different fiscal policies.

Contractionary Fiscal Policy:

budget indicates a surplus

government is spending less than what it earns

Expansionary Fiscal Policy:

government is spending more on infrastructure development

budget indicates a deficit

government is spending more than what it earns

When the government is spending less than what it earns, it has a budget surplus. This indicates that the government is collecting more revenue than it is spending. This is an example of a contractionary fiscal policy because it reduces the amount of money circulating in the economy, which can help control inflation.

When the government is spending more than what it earns, it has a budget deficit. This indicates that the government is spending more money than it is collecting in revenue. This is an example of an expansionary fiscal policy because it injects more money into the economy, which can stimulate economic growth.

When the government is spending more on infrastructure development, it is an example of an expansionary fiscal policy because it increases government spending and stimulates economic growth.

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The initial momentum of the system before the collision can be calculated as: p1 = m1v1 + m2v2 = -6 kgm/s

After the collision, the two objects stick together and move with a final velocity of v. The final momentum of the system can be calculated as:

p2 = (m1 + m2)v

p2 = 3v

Since momentum is conserved, we can equate p1 and p2 to get:

p1 = p2

-6 kgm/s = 3v

v = -2 m/s

Therefore, the final velocity of the combined object after the collision is -2 m/s.

Momentum conservation is a fundamental principle in physics that states that the total momentum of a closed system remains constant in the absence of external forces. In other words, the rate of an object or a system of things cannot change unless an external force acts on it.

Yes, momentum is a vector quantity that represents the product of an object's mass and velocity, and it describes the tendency of an object to continue moving in the same direction and at the same speed unless acted upon by an external force.

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The final speed of the roller coaster is 454.6 m/s.

To determine the behavior of the roller coaster, we can use the conservation of energy principle, which states that the total energy of a closed system remains constant. The initial energy of the roller coaster is potential energy (due to its height) and kinetic energy (due to its initial speed), and the final energy is potential energy (due to its final height) and kinetic energy (due to its final speed). Assuming no energy losses due to friction or other factors, the initial energy must equal the final energy.

The potential energy of the roller coaster at height h is given by:

Ep = mgh

where m is the mass of the roller coaster, g is the acceleration due to gravity (9.81 m/s²), and h is the height of the roller coaster.

At the top of the roller coaster (where h = 100 m), the potential energy of the roller coaster is:

Ep = (1000.0 kg)(9.81 m/s²)(100.00 m) = 981000 J

The kinetic energy of the roller coaster at the initial speed vi is given by:

Ek = (1/2)mv²

where m is the mass of the roller coaster, and v is its speed.

At the beginning of the roller coaster (where vi = 10.00 m/s), the kinetic energy of the roller coaster is:

Ek = (1/2)(1000.0 kg)(10.00 m/s)² = 50000 J

The total energy of the roller coaster at the beginning of the ride is:

Etotal = Ep + Ek = 981000 J + 50000 J = 1031000 J

At the bottom of the roller coaster, all of the potential energy has been converted to kinetic energy, and the roller coaster has reached its maximum speed. Therefore, the kinetic energy at the bottom of the roller coaster is:

Ek = Etotal - Ep = 1031000 J - 0 J = 1031000 J

The final speed of the roller coaster, vf, is found using the equation:

Ek = (1/2)mv²

Solving for vf:

vf = √(2Ek/m) = √(2(1031000 J)/(1000.0 kg)) = 454.6 m/s

Therefore, the final speed of the roller coaster is approximately 454.6 m/s.

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The complete question is:

a frictionless roller coaster is given an initial speed of vi=10.00m/s , at the initial height h=100:00m,has a mass m=1000.0kg. what is the roller coaster's final speed?

Onthe top and the least luminous stars at the bottom. Temperature is plotted on the horizontal axis, with the hottest stars on the left and the coolest stars on the right.

What is Luminosity?

Luminosity is a measure of the total amount of energy emitted by a star or other celestial object per unit time, regardless of the direction in which it is emitted. It is a measure of the intrinsic brightness of the object, and is often expressed in units of watts or solar luminosities (the amount of energy emitted by the Sun).

The luminosity of a star depends on several factors, including its size, temperature, and age. Larger and hotter stars tend to be more luminous than smaller and cooler stars, because they have a greater surface area and emit more energy per unit area. Young stars are also typically more luminous than older stars, because they are still undergoing nuclear fusion and producing energy at a high rate.

The Hertzsprung-Russell (HR) diagram is a graph that shows the relationship between two key pieces of information about stars:

Luminosity: The amount of energy a star emits per second, measured in units of watts or solar luminosities (the amount of energy emitted by the Sun).

Temperature: The surface temperature of the star, measured in degrees Kelvin (K) or degrees Celsius (°C).

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A unique property of water because of its chemical structure is that it's A. less dense when it's a solid than when it's a liquid.

Water is an incredibly unique substance, and its physical properties are largely due to its chemical structure. Water is a polar molecule, meaning it has a positively charged end and a negatively charged end, which creates an attraction between molecules of water that is known as hydrogen bonding.

This hydrogen bonding is responsible for a number of the unique properties of water, one of which is its density. Water is less dense when it is a solid than when it is a liquid. This is counterintuitive to most substances, which are more dense when they are solid than when they are liquid. The explanation for this is that when water freezes, the hydrogen bonds between the molecules force them to move further apart, resulting in a decrease in density.

This is why ice floats on top of liquid water, and it is why bodies of water don’t freeze from the bottom up.

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The scale reading when the elevator is accelerating can be found using the following formula:

Weight in Elevator = Mass × (Acceleration of Gravity + Acceleration of Elevator)

where Weight in Elevator is the scale reading, Mass is the mass of the person, Acceleration of Gravity is the acceleration due to gravity (9.81 m/s^2), and Acceleration of Elevator is the acceleration of the elevator.

Using this formula, we can solve for the mass of the person:

Weight in Elevator = Mass × (Acceleration of Gravity + Acceleration of Elevator)

598.9 N = Mass × (9.81 m/s^2 - 1.1 m/s^2)

Mass = 65 kg

Now, when the elevator is not moving, the weight of the person will be equal to their mass multiplied by the acceleration due to gravity, which is:

Weight on Ground = Mass × Acceleration of Gravity

Weight on Ground = 65 kg × 9.81 m/s^2

Weight on Ground = 637.65 N

Therefore, the scale reading when the elevator is not moving would be 637.65 Newtons.

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In closed Loop Control System,the input to the system is the desired set-point or reference value.In oen Loop Control System,the input to the system is the desired set-point or reference value.

Value is the importance, worth, or usefulness of something. It is the importance an individual or group places on an object, service, or idea. Value is determined by how much an individual or group is willing to give up to obtain that object, service, or idea. Value can also refer to the monetary worth of an object, service, or idea.

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Answer:

Trials 1-10 were bigger than 11-20, so it is different.

Explanation:

brainlyist pls

The direction of the magnetic field at point P, West of the wire, would be to the South.

The right-hand rule can be used to determine the direction of the magnetic field around a current-carrying wire.

If the thumb of the right hand is pointed in the direction of the current (out of the page), and the fingers wrap around the wire in the direction of the magnetic field, then the palm of the right-hand points in the direction of the magnetic field.

Using this rule, we can determine that the magnetic field at point (P), located west of the wire, will be directed to the south.

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Answer:

44,640 ft

Explanation:

assuming the rocket started from rest, then v₀ = 0

2 min = 120 s

Δx = v₀t + 1/2at²

Δx = 0 + 1/2(6.2 ft/s²)(120 s)² = 44,640 ft ≈ 8.45 mi

Answer:

Because the body regulates water pressure well because we are mostly composed of water

they would be affected because herbivores and omnivores which rely on plants to survive would not recieve the nutrition necessary because for the plant to create food it would need sunlight

Answer:

In physics, the term "fluids" refers to substances that have no fixed shape and are capable of flowing. Fluids can be categorized into two main types: liquids and gases. Both liquids and gases are considered fluids because they can flow and take the shape of their container. Examples of liquids include water, oil, and blood, while examples of gases include air, helium, and carbon dioxide. The study of fluids is known as fluid mechanics and is an important field in physics and engineering.

Explanation:

Therefore, the force in member BC is equal to the vertical component of the force at joint B, which is: F_BC = -V_BC = -28.37 N.

In physics, force is defined as an influence that causes an object to undergo a change in motion or to experience deformation. It is a vector quantity, which means it has both magnitude and direction. The SI unit of force is the Newton (N). According to Newton's laws of motion, a force is required to change the motion of an object. The first law states that an object at rest will remain at rest, and an object in motion will remain in motion at a constant velocity, unless acted upon by an unbalanced force. The second law states that the acceleration of an object is directly proportional to the force applied to it and inversely proportional to its mass (F = ma). The third law states that for every action, there is an equal and opposite reaction.

Here,

To solve this problem, we can use the method of joints to analyze the forces acting on the joints of the frame. The method of joints involves analyzing the forces acting on each joint of a structure in order to determine the internal forces (tension or compression) in the members.

We will start by analyzing joint B, since it has only two unknown forces (the force in member BC and the horizontal force in member AB). We can apply the equations of static equilibrium to this joint:

ΣFx = 0: H_AB = 0

ΣFy = 0: V_AB + V_BC - W = 0

where H_AB and V_AB are the horizontal and vertical components, respectively, of the force in member AB, V_BC is the vertical component of the force in member BC, and W is the weight of the globe.

From the given data, we can determine the values of V_AB and W:

V_AB = -W sin(a) = -20 sin(25°) ≈ -8.37 N

W = 20 N

Substituting these values into the equations of static equilibrium, we can solve for V_BC and H_AB:

V_BC = W - V_AB = 20 + 8.37 = 28.37 N

H_AB = 0

F_BC = -V_BC = -28.37 N

Note that the negative sign indicates that the force in member BC is in compression, which means it is being pushed inward by the forces acting on the structure.

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The displacement vector for a is given below:

A=4.15m, θA=26.5o

Ax=AcosθA = 4.15cos26.5 = 3.7 m

Ay=AsinθA = 4.15sin26.5 = 1.85 m

B= 4.15m, θB =26.5o

Bx=BcosθB = 4.15cos90= 0.0 m

By=BsinθB = 4.15sin90= 4.15 m

a)

(A+B)x= Ax+ Bx= 3.7 – 0.0 = 3.7 m

(A+B)y = Ay+ By= 1.85 + 4.15 = 6.0 m

(A+B)=sqrt[(3.7)^2+(6.0)^2] = 7.05 m

Φ= tan^-1[((A+B)y)/( (A+B)x)] = tan^-1(6.0/3.7) = 58.34o…….counterclockwise from +X axis

b)

(A-B)x= Ax- Bx= 3.7 – 0.0 = 3.7 m

(A-B)y = Ay- By= 1.85 - 4.15 = -2.3 m

(A-B)=sqrt[(3.7)^2+(2.3)^2] = 4.36 m

Φ= tan^-1[((A-B)y)/( (A-B)x)] = tan^-1(-2.3/3.7) = -31.9o = 360-31.9 = 328.1o…….counterclockwise from +X axis

c)

(B-A)x= Bx- Ax= 0.0-3.7 = -3.7 m

(B-A)y = By- Ay= 4.15-1.85 = 2.3 m

(B-A)=sqrt[(-3.7)^2+(-2.3)^2] = 4.36 m

Φ= tan^-1[((B-A)y)/( (B-A)x)] = tan^-1(2.3/-3.7) = -31.9o = 180-31.9 = 148.1o…….counterclockwise from +X axis

d)

(A-2B)x= Ax- 2Bx= 3.7 – 2*0.0 = 3.7 m

(A-2B)y = Ay- 2By= 1.85 – 2*4.15 = -6.45 m

(A-2B)=sqrt[(3.7)^2+(-6.45)^2] = 7.44 m

Φ= tan^-1[((A-2B)y)/( (A-2B)x)] = tan^-1(-6.45/3.7) = -60.16o = = 360-60.16 = 229.84o…….counterclockwise from +X axis

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Answer: 345.15°C

Explanation:

The average kinetic energy of the molecules in an ideal gas is proportional to its temperature in Kelvin scale. So, if the average kinetic energy doubles, then the temperature must also double.

The initial temperature of the gas is 36°C = 36 + 273.15 = 309.15 K.

Doubling the temperature, we get:

Final temperature = 2 × 309.15 K = 618.3 K

Converting back to Celsius scale, we get:

Final temperature = 618.3 - 273.15 = 345.15°C

Therefore, the final temperature of the gas is 345.15°C.

Answer:

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Explanation:

Answer:

X = 8.2 m

Explanation:

m = 4.25 kg, v0 = 15.0 m/s, v = 0 m/s

Since you have to push the block to overcome the static friction to start moving, the force required to set it  in motion must be greater than the difference between the component of weight along the ramp and the  static frictional force. This force with a minimum magnitude equal to the kinetic friction is required to keep the block in a constant motion. The normal force is N = mg cosθ

F ≥ μkN + μsN - mg sinθ = μk mg cosθ + μs mg cosθ - mg sinθ

                                   =mg[( μk + μs)cosθ + sinθ]

                                   =4.25 kgx9.8 m/s2[(0.368+0.663)cos31.5+sin31.5]

                                   = 58.3754 N

Fnet = ma

ma = 58.3754, a = 13.735 m/s2

v2 = v02 - 2aX

02 = (15.0 m/s)2 -2(13.735m/s2)X

X = 8.2 m