For each equation, state the reaction type and then balance the equation.
___Na3PO4 + ___HCl → ___H3PO4 + ___NaCl Will give brainliest

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The heat of reaction for the reaction 2H₂O₂ → 2H₂O +O₂ is -196 KJ

From the question, we are to calculate the heat of reaction for the reaction

2H₂O₂ → 2H₂O +O₂               ∆H=?

Using Hess's law

Hess's Law of constant heat summation states that regardless of the multiple stages or steps of a reaction, the total enthalpy change for the reaction is the sum of all changes

From the given equations,

2H₂ +O₂ → 2H₂O                   ∆H= -572 KJ ---------- (1)

2H₂O₂ → 2H₂ + 2O₂              ∆H= 376 KJ ----------- (2)

Adding equations (1) and (2), we get

2H₂O₂ → 2H₂O +O₂               ∆H= -572 KJ + 376 KJ

2H₂O₂ → 2H₂O +O₂               ∆H= -196 KJ

Hence, the heat of reaction for the reaction 2H₂O₂ → 2H₂O +O₂ is -196 KJ.

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Answer:

amine

Explanation:

We have to bear in mind that amines are basic compounds. This idea will be very important in attempting to answer this question.

So, when she adds 5% HCl solution in order to extract the organic layer, the amine forms a hydrochloride salt which is contained in the aqueous layer.

The addition of a base such as NaOH leads to the formation of a white precipitate of the amine.

The elemental particles like the atoms, molecules and compounds present in a given substance is called an Avogadro's number. This number is expressed as [tex]N_{A}[/tex] and is equal to [tex]6.022 \times 10^{23} \;\rm mol^{-1}[/tex].

[tex]8.06 \times 10 ^{23}[/tex] molecules are present in 135 g of Teflon [tex]\rm C_{2}F_{4}[/tex].

Given,

We have 135 g, so moles will be:

[tex]\begin{aligned}\rm Moles (n) &=\dfrac{ \rm Mass }{\;\rm Molar \;\rm mass}\\\\\rm n &= \dfrac{135 \rm g }{100.02 \rm g/mol} \\\\\rm n &= 1.34 \;\rm mole\end{aligned}[/tex]

Hence,

1 mole contains [tex]6.022140857 \times 10^{23}[/tex] (Avogadro's number)

So 1.34 moles will contain,

[tex]\begin{aligned}&=1.34 \times 6.022140857 \times 10^{23}\\\\&= 8.06 \times 10 ^{23}\;\rm molecules\end{aligned}[/tex]

Therefore, [tex]8.06 \times 10 ^{23}[/tex] molecules are present in 135 g of Teflon [tex]\rm C_{2}F_{4}[/tex].

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Answer:

Charles's law states that the volume of a given amount of gas is directly proportional to its temperature on the kelvin scale when the pressure is held constant

The volume of a given gas sample is directly proportional to its absolute temperature at constant pressure (Charles's law). The volume of a given amount of gas is inversely proportional to its pressure when temperature is held constant (Boyle's law)

Explanation:

~Hope this helps

Answer:

2.13 M

Explanation:

To solve this problem we need to keep in mind the definition of molarity:

As the problem gives us both the number of moles and the volume of solution, we can proceed to calculate the molarity:

The answer is 2.13 M.

Answer:

Explanation:

The atomic number of uranium (see periodic table) is 92, and the mass number of the isotope is given as 238. Therefore, it has 92 protons, 92 electrons, and 238 — 92 : 146 neutrons

Uranium has an atomic number of 92. There are 146 neutrons, 92 protons, and 92 electrons in 238U+5. The number of neutrons can vary from 141 to 146.

Chemical element uranium has the atomic number 92 and the letter U. It is an actinide metal in the periodic table's silvery-gray series. There are 92 protons and 92 electrons in an atom of uranium, of which 6 are valence electrons.

Since uranium has an atomic number of 92, its atomic structure consists of 92 protons and 92 electrons. The nucleus of U-238 contains 146 neutrons, but this number can range from 141 to 146.

With 92 protons and 146 neutrons, Uranium-238 is the heaviest element in nature. The overall mass and charge of the nucleus are 238 nucleons, or +92.

Thus, Uranium has an atomic number of 92. There are 146 neutrons, 92 protons, and 92 electrons in 238U+5.

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Answer: A volume of 2997 liters of fluorine gas is needed to form 999 L of sulfur hexafluoride gas if the given reaction takes place at 2.00 atm and 273.15 K.

Explanation:

The given reaction is as follows.

[tex]S(s) + 3F_{2}(g) \rightarrow SF_{6}(g)[/tex]

This show that 3 moles of fluorine is reacting to give 1 moles of sulfur hexafluoride.

According to the ideal gas formula,

PV = nRT

This means that volume of a gas is directly proportional to the number of moles. Hence, volume of fluorine required is calculated as follows.

[tex]3 \times 999 L\\= 2997 L[/tex]

Thus, we can conclude that a volume of 2997 liters of fluorine gas is needed to form 999 L of sulfur hexafluoride gas if the given reaction takes place at 2.00 atm and 273.15 K.

Answer:

B 1.17

Explanation:

There is .02 mols of nacl in a .4M solution

so you multiply by the molar weight of NaCl (58.44)

Answer:

Potassium phosphide (K3P)

Solution :

Compound                      Ksp

[tex]$PbF_2$[/tex]                               [tex]$3.3 \times 10^{-8}$[/tex]

[tex]$Ni(CN)_2$[/tex]                        [tex]$3 \times 10^{-23}$[/tex]

FeS                                [tex]$8 \times 10^{-19}$[/tex]

[tex]$CaSO_4$[/tex]                           [tex]$4.93 \times 10^{-5}$[/tex]

[tex]$Mg(OH)_2$[/tex]                      [tex]$5.61 \times 10^{-12}$[/tex]

Ksp of [tex]$Ni(CN)_2 << Ksp \text{ of}\ \ Mg(OH)_2$[/tex] and both compounds dissociate the same way. Hence [tex]$Mg(OH)_2$[/tex] is more soluble than [tex]$(B). \ Ni(CN)_2$[/tex]

[tex]$Mg(OH)_2$[/tex]  is less soluble than [tex]$(A). \ \ PbF_2 \ ()Ksp \ PbF_2 > Ksp \ \text{ of } \ Mg(OH)_2$[/tex]

It is not possible to determine CD - [tex]$FeS \text{ or} \ CaSO_4$[/tex]  is more or less soluble than [tex]$Mg(OH)_2$[/tex]  as though they have a different Ksp values their molecular dissociation is also different and they may have a close solubility values.

[tex]$Ni(OH)_2$[/tex]  can be directly compared with PbS, [tex]$AlPO_4, MnS$[/tex]

[tex]$\text{For } \ Ni(OH)_2$[/tex]

[tex]$AB_2(s) \rightarrow A^{2+} + 2B^{-}$[/tex]

[tex]$Ni(OH)_2(s) \rightarrow Ni^{2+} + 2OH^-$[/tex]

100

1-s s 2s

Ksp = [tex][A2+][B-]^2 = s \times (2s)^2 = 4s^3[/tex]

Hence they can be directly compared by Ksp values, smaller the Ksp, smaller the solubility.

For Silver Chloride

[tex]$AB(s) \rightarrow A^{x+}+B^{x-}$[/tex]

[tex]$AgCl(s) \rightarrow Ag^+ + Cl^-$[/tex]

1 0 0

1 - s s s

Ksp [tex]$=[A^{x+}][B^{x-}]=s \times s = s^2$[/tex]

Hence, they can be directly compared by Ksp values, smaller the Ksp, smaller the solubility.

Explanation:

sodium has a positive charge and chlorine has a negative charge a negative and a positive charge you automatically for an ionic bond therefore the chlorine has to have a negative one charge

Answer:

108 g

Explanation:

First we convert 6.00 moles of H₂ into moles of H₂O, using the stoichiometric coefficients of the reaction:

Then we can convert 6.00 moles of H₂O into grams, using the molar mass of water:

The answer is 108 grams of water.

Answer:

The difference in the properties of water can be attributed to physical changes to the hydrogen and oxygen atoms on a subatomic level. The properties of the gases are combined to give water its properties. When substances chemically combine, products with completely different properties form.

Answer:

They are composed of different atoms

Explanation:

The guy above me said it better :|

Answer:

The molecular formula for Potassium Carbonate is K2CO3. The SI base unit for amount of substance is the mole. 1 grams Potassium Carbonate is equal to 0.0072356020563581 mole. Note that rounding errors may occur, so always check the results.

Explanation:

The molecular formula for Potassium Carbonate is K2CO3. The SI base unit for amount of substance is the mole. 1 grams Potassium Carbonate is equal to 0.0072356020563581 mole.

Answer:

Two types of reaction

Explanation:

Alkanes undergo only substitution reactions but alkenes and alkynes undergo both substitution and addition reactions

[tex]\text{N}_{2}\text{O}_{3}=\text{nitrogen trioxide}\\\text{N}_{2}=\text{nitrogen}\\\text{O}_{2}=\text{oxygen}[/tex]

Answer:

The Milky Way

Explanation:

Answer:

Your answer is the Milky WAy!

Brainliest?

Answer: The element B will have ONE unpaired electron in the p orbital.

Explanation:

The electronic configuration of each given element is as follows.

Atomic number of calcium (Ca) is 20.

Ca: [tex]1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 4s^{2}[/tex]

Atomic number of nitrogen (N) is 7.

N: [tex]1s^{2} 2s^{2} 2p^{3}[/tex]

Atomic number of boron (B) is 5.

B: [tex]1s^{2} 2s^{2} 2p^{1}[/tex]

Atomic number of argon (Ar) is 18.

Ar: [tex]1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6}[/tex]

Atomic number of bromine (Br) is 35.

Br: [tex][Ar] 4s^{2} 3d^{10} 4p^{5}[/tex]

Therefore, boron is the only element that have one unpaired electron in the p-orbital.

Thus, we can conclude that element B will have ONE unpaired electron in the p orbital.

Answer:

0.011 moles

Explanation:

Applying,

PV = nRT.................... Equation 1

Where P = Pressure, V = Volume, n = number of moles, R = Molar gas constant, T = Temperature.

Make n the subject of the equation

n = PV/RT.................. Equation 2

From the question,

Given: P = 105 kPa = (105×0.00986923) = 1.036 atm, V = 250 mL = 0.25 L, T = 23 °C = (273+23) = 296 °C

Constant: R = 0.082 atm.dm³/K.mol

Substitute these values into equation 2

n = (1.036×0.25)/(0.082×296)

n = 0.011 moles

Answer: Element is P, phosphor

Explanation:  Phosphor has oxidation number -III and it has 15 protons. So it is possible to have 16 neutrons. Other elements having oxidation number -III are N and As which can not have an isotope with 16 neutrons.

Explanation:

Ionic product of water, Kw

[tex]Kw = [OH {}^{ - } ][H _{3} O {}^{ + } ] \\ 1.0 \times {10}^{ - 14} = (1 \times {10}^{ - 11} )[H _{3} O {}^{ + } ] \\ [H _{3} O {}^{ + } ] = \frac{(1.0 \times {10}^{ - 14}) }{(1 \times 10 {}^{ - 11}) } \\ ][H _{3} O {}^{ + } ] = 0.001 \: M[/tex]

Answer:

d

Explanation:

i just did it

The  functional group in the following molecule CH₃CH₂OCH₂CH₃ is ether.

Functional group is defined as a substituent or group of atoms or an atom which causes chemical reactions.Each functional group will react similarly regardless to the parent carbon chain to which it is attached.This helps in prediction of chemical reactions.

The reactivity of functional group can be enhanced by making modifications in the functional group .Atoms present in functional groups are linked to each other by means of covalent bonds.They are named along with organic compounds according to IUPAC nomenclature.

Functional group inter conversion is also possible by retro -synthesis.In some cases , functional groups can be charged molecules.

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b. a positive cation and a negative anion

✏ Anions are negative in nature while cations are positive in nature. Together they come together by an attractive electrostatic force to form an ionic bond.

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The complete question is shown in the image attached to this answer.

Answer:

C

Explanation:

Let us quickly remember that the EMF of a cell under non standard conditions in given by the Nernst equation.

This equation states that;

E = E°cell - 0.592/n log Q

Where

E = EMF under non standard conditions

E°cell= standard EMF of the cell

n = number of electrons transferred

Q = reaction quotient

If the reaction quotient is greater than 1 then cell potential is less than the standard cell potential.

The cell that generates the lowest cell potential is the cell depicted in option C because Q has the greatest positive value(Q<1).

The cell potential is the redox potential that measures the acquired to lost electrons at the electrodes. The lowest cell potential is generated by cell C with 0.5 M.

EMF is the electromotive force that is the total of the electric potential difference produced at the half cells of the galvanic cell (electrochemical cell).  

EMF of the cell is given as,

[tex]\rm E = \rm E^{\circ} - \dfrac{0.592}{n}\; log Q[/tex]

Here, E is the electromotive force, [tex]\rm E^{\circ}[/tex] is the standard EMF, n is the number of the transferred electrons, and Q is the reaction quotient.

When the reaction quotient (Q) is greater than 1 then, cell potential will be less than standard cell potential.

Therefore, cell C with 0.5 M and Q > 1 is a similar cell.

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