For each function choose whether it’s graph opens upward or downward.Choose the equation with the widest graph.Choose the equation with the narrowest graph.

For Each Function Choose Whether Its Graph Opens Upward Or Downward.Choose The Equation With The Widest

Answers

Answer 1

a) if a > 0 the graph opens upward and if a < 0 it opens downward, hence:

up, up, up, down

b) widest: y = 2/3|x|

c) narrowest: y = 4|x|

For Each Function Choose Whether Its Graph Opens Upward Or Downward.Choose The Equation With The Widest

Related Questions

SHORT ANSWERWhy is 3Vx + 4x2not a polynomial?Answer in complete sentences.Н.BI U SX2 x?E= = =ATXVXEnter your answer here

Answers

[tex]\begin{gathered} \text{The expression;} \\ 3\sqrt[]{x}+4x^2 \end{gathered}[/tex]

is not a polynomial because the power of the unknown for polynomials are always positive integers.

In this case, the power of x has 0.5

the diagonals of a square measure 20. what is the length of a side of the squareleave anwer in simplest radical form

Answers

The square is formed by 2 right triangles, where 20 is the hypotenuse.

We can apply the Pythagorean theorem:

c^2 = a^2 + b^2

Where:

c = hypotenuse = 20

a & b = the other 2 legs of the triangle = s

Since a square has 4 equal sides s, both legs of the triangle are the same (s)

Replacing:

20^2 = s^2+s^2

Solve for s

20^2 = 2 s^2

20^2 = 2 s^2

400 = 2 s^2

400/2 = s^2

200 = s^2

√200 = s

√(2 x 100 ) = s

√2 √100 = s

10 √2 = s

Describe how the graph of the function is a transformation of the original function f.y=f(x-49)This results in a Answer shift to the graph Answer units Answer.

Answers

Given an original function

[tex]f(x)[/tex]

Its graph is plotted as

When the function is transformed to the function

[tex]y=f(x-49)[/tex]

Its plot becomes

The above plot shows that the graph moves horizontally to the right by 49 units

Thus, this results in a right shift to the graph

49 units

Find a formula for P = f(t), the size of the population that begins in year t = 0 with 2070 members and decreases at a 3.9% annual rate. Assume that time is measured in years. P = f(t) =

Answers

[tex]P=f(t)=P(1-0.039)^t[/tex]

Explanation

Step 1

let

[tex]P=f(t)[/tex]

where P represent the population, and t represents the time in years

so,

when t=0, P=2070

[tex]\begin{gathered} P=f(t) \\ 2070=f(0) \end{gathered}[/tex]

Step 2

if the population decrease 3.9% every year,in decimal form

[tex]\begin{gathered} \text{3}.9\text{ =3.9/100= 0.039} \\ \end{gathered}[/tex]

so,after 1 year the population is

[tex]\begin{gathered} P_1=P(1-0.039)\rightarrow Eq1 \\ P_1=P(0.961) \\ P_1=2070(0.961) \\ P_1=1989.27 \end{gathered}[/tex]

now, after the 2 years

[tex]\begin{gathered} P_2=P_1(1-0.039)=P(1-0.039)(1-0.039)=P(1-0.039)^2 \\ \end{gathered}[/tex]

now, after 3 years

[tex]P_3=P_2(1-0.039)=P(1-0.039)(1-0.039)(1-0.39==P(1-0.039)^3[/tex]

now, we can see the function

[tex]\begin{gathered} P(1-0.039)^t\rightarrow P_f=P(1-0.039)^t \\ f(t)=P(1-0.039)^t \end{gathered}[/tex]

I hope this helps you

Which is more, 10 tons or 20,004 pounds?

Answers

A ton is equivalent to 2000 pounds. Then, 10 tons are 20,000 pounds.

Therefore, 20,004 pounds is more.

The topic is solving radical equations, but im just confused on whether to squafe it or not[tex]2 \sqrt{n} = n - 3[/tex]

Answers

a We are given the following radical equation

[tex]2\sqrt[]{n}=n-3[/tex]

To solve this equation we need to square both sides of the equation

[tex]\begin{gathered} (2\sqrt[]{n})^2=(n-3)^2 \\ 4n=(n-3)^2 \end{gathered}[/tex]

Apply the squares formula on right-hand side of the equation

[tex](a-b)^2=a^2+b^2-2ab[/tex]

So the equation will become

[tex]\begin{gathered} 4n=n^2+3^2-2(n)(3) \\ 4n=n^2+9-6n \\ 0=n^2+9-6n-4n \\ 0=n^2+9-10n \\ n^2-10n+9=0 \end{gathered}[/tex]

So we are left with a quadratic equation.

The standard form of a quadratic equation is given by

[tex]ax^2+bx+c=0[/tex]

Comparing the standard equation with our equation we get the following coefficients

a = 1

b = -10

c = 9

Now recall that quadratic formula is given by

what are the ordered pairs of the solutions for this system of equations?f (x)=x^2-2x+3;f (x)=-5x+1

Answers

we get:

[tex]\begin{gathered} x^2-2x+3=-5x+1\rightarrow \\ x^2+3x-2=0\rightarrow x=\frac{-3+\sqrt[]{17}}{2},x=\frac{-3-\sqrt[]{17}}{2} \end{gathered}[/tex]

so the pairs are,

[tex](\frac{-3+\sqrt[]{17}}{2},\frac{15-5\sqrt[]{17}}{2}+1),(\frac{-3-\sqrt[]{17}}{2},\frac{15+5\sqrt[]{17}}{2}+1)[/tex]

Instructions: Solve the triangle, find m

Answers

step 1

Find out the measure of angle A

we have that

In the given right triangle

[tex]\begin{gathered} cosA=\frac{17}{38}\text{ ----> by CAH} \\ \\ A=cos^{-1}(\frac{17}{38}) \\ A=63^o \end{gathered}[/tex]

step 2

Find out the measure of angle C

Remember that

In the right triangle

A+C=90 degrees -----------> by complementary angles

[tex]\begin{gathered} 63^o+C=90^o \\ C=90^o-63^o \\ C=27^o \end{gathered}[/tex]

Please help me I'm struggling very muchx^3+14x^2+48x=0

Answers

ANSWER

The solutions are:

• x = 0

,

• x = -6

,

• x = -8

EXPLANATION

First we can see that there's and x in every term of the polynomial, so one of the solutions to the equation is when x = 0, because x is a common factor:

[tex]\begin{gathered} x^3+14x^2+48x=0 \\ x(x^2+14x+48)=0 \end{gathered}[/tex]

The other two solutions - we know that there are three because the degree of the polynomial is 3 - are the zeros of the polynomial in parenthesis. We can solve it with the formula:

[tex]\begin{gathered} ax^2+bx+c=0 \\ x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \end{gathered}[/tex]

In our polynomial, a = 1, b = 14 and c = 48:

[tex]\begin{gathered} x=\frac{-14\pm\sqrt[]{14^2-4\cdot48}}{2} \\ x=\frac{-14\pm\sqrt[]{196-192}}{2} \\ x=\frac{-14\pm\sqrt[]{4}}{2} \\ x=\frac{-14\pm2}{2} \\ x_1=\frac{-14-2}{2}=\frac{-16}{2}=-8 \\ x_2=\frac{-14+2}{2}=\frac{-12}{2}=-6 \end{gathered}[/tex]

Therefore the solutions to the equation are x = 0, x = -8 and x = -6

Answer:

x = - 8, x = - 6, x = 0

Step-by-step explanation:

x³ + 14x² + 48x = 0 ← factor out x from each term

x(x² + 14x + 48) = 0 ← factor the quadratic

consider the factors of the constant term (+ 48) which sum to give the coefficient of the x- term (+ 14)

the factors are + 8 and + 6 , then

x(x + 8)(x + 6) = 0

equate each factor to zero and solve for x

x = 0

x + 8 = 0 ⇒ x = - 8

x + 6 = 0 ⇒ x = - 6

Ben and Jerry’s sells 3 times more ice cream cones ($2) than shakes ($9). If last month’s sales totaled $9,600, how many of each were sold?

Answers

It is given that the sales of ice cream is three times as shakes.

Let x be the number of ice creams and y be the number of shakes,

So x=3y.

Also the total sales if ice cream is $2 and shake is $9 is $9600 so it follows:

[tex]\begin{gathered} 2x+9y=9600 \\ 2\times3y+9y=9600 \\ 15y=9600 \\ y=640 \end{gathered}[/tex]

Since x=3y so it follows that x=1920.

So Number of shakes sold is 640 and number of ice cream cones sold is 1920.

Hannah bought an emerald pendant online. It cost $751 plus 19% shipping and handling. What was the total cost? Round your answer to the nearest dollar: $

Answers

To find the shipping cost we can use the rule of three:

[tex]\begin{gathered} 751\rightarrow100 \\ x\rightarrow19 \end{gathered}[/tex]

Then:

[tex]x=\frac{19\cdot751}{100}=\frac{14269}{100}=142.69[/tex]

Therefore the total cost is $893.69

Evaluate the expression when X = 2X to the second power -8x -3

Answers

[tex]x^2-8x-3[/tex]

Evaluate for x = 2:

[tex](2)^2-8(2)-3=4-16-3=4-19=-15[/tex]

What is the remainder when x^2 + 5x - 24 is divided by x - 6?

Answers

Given:

The dividend is,

[tex]x^2+5x-24[/tex]

The divisor is,

[tex]x-6[/tex]

To find: The remainder

Explanation:

Let us take,

[tex]p(x)=x^2+5x-24[/tex]

Using the remainder theorem,

Let p(x) be any polynomial of degree greater than or equal to one and let a be any real number.

If p(x) is divided by the linear polynomial x - a, then the remainder is p(a).

Here,

[tex]a=6[/tex]

Substitute the value of a in the above polynomial.

[tex]\begin{gathered} p(6)=6^2+5(6)-24_{} \\ =36+30-24 \\ =42 \end{gathered}[/tex]

Hence, the remainder is 42.

Final answer: The remainder is 42.

so I have to make a table for the following equations and then graph them y= 2x+7

Answers

we have

y= 2x+7​

this is the equation of the line

Make the table

For different values of x, calculate the values of y

so

For x=-1

y=2*(-1)+7

y=5

For x=0

y=2*(0)+7

y=7

For x=1

y=2*(1)+7

y=9

For x=2

y=2*(2)+7

y=11

therefore

we have the points

(-1,5) (0,7) (1,9) (2,11)

Plot the points and join them to graph the line

using a graphing tool

see the attached figure

please wait a minute

In Livingston, the use of landlines has been declining at a rate of 20% every year. of there are 23,000 landlines this year, many will there be in 6 years?? if necessary, round your answer to the nearest whole number

Answers

In 6 years there are

Apply N1= 230000

N = N1 - N1•20/100 - N1• (20/100)^2 - N1•(20/100/^3 - N1•(20/100)^4 - N1(20/100)^5 - N1•(20/100) ^6

Then replace 20/100= 1/5

N= 23000 - 23000 • ( 1/5 + 1/25 + 1/125/ + 1/625 + 1/3125 + 1/15625 )

N= 23000 - 5750 = 17250

Then answer is

In 6 years there will be 17250 landlines

2. Rewrite by factoring the GCF from each expression.a) 8r + 12O 8 (r + 3)O 4 (2r + 3)O 4 (2r + 12)O 8 (r + 12)

Answers

We are asked to rewrite the given expression by factoring the GCF from the expression.

[tex]8r+12[/tex]

GCF is the greatest common factor.

Factors of 8 = 1, 2, 4, 8

Factors of 12 = 1, 2, 3, 4, 6, 12

Notice that the greatest common factor is 4

So, take out 4 from the expression

[tex]8r+12=4(2r+3)[/tex]

Therefore, the correct answer is

[tex]4(2r+3)_{}[/tex]

Does the graph show an increasing or decreasing linear function?A) IncreasingB) Decreasing

Answers

The values of the y-variable decrease as the values of the x-variable increase, then the graph shows a decreasing liner function

How many time would Tamir have to swims to make the season pass less expensive than paying for each visit individual

Answers

Let x be the number of times Tamir swims

Season pass :

C = 185 where c is the total cost

Pay per day:

C = 5x

We want

185 < 5x so the season pass costs less than the pay per day

Divide each side by 5

185/5 < 5x/5

37 < x

He needs to swim more than 37 days so

38 or more days

Answer 38 or more days

Convert 10,000 feet to meters and kilometers

Answers

Answer:

10000 feet = 3048 meters = 3.048 kilometers

Explanation:

Recall,

1 foot = 0.3048 meters

10000 feet = 10000 x 0.3048

10000 feet = 3048 meters

Also,

1 meter = 0.001 kilometers

3048 meters = 3048 x 0.001

= 3.048 kilometers

What is the domain and range of the function? 15c

Answers

The first thing we have to know is that the Domain are all the values that x can take in the function and that the Range are all the values that the function takes in y

Taking this into account, the best way to see the domain and range is by graphing the function

[tex]\begin{gathered} f^{-1}(x)=3+\log _4(\frac{1-x}{3}) \\ f^{-1}(x)=3+\log _4(1-x)-\log _4(3) \end{gathered}[/tex]

If you want to find the Domain we have to guarantee that what is inside the logarithm and have a x is greater than zero:

[tex]\begin{gathered} 1-x>0 \\ 1>x \end{gathered}[/tex]

This means that the domain will only be those values less than 1

standing 200ft from the base of an antenna, Maria measures the angle of elevation to the top of the antenna to be 38 degrees. If her eye level is 5ft above the ground, what is the height of the antenna to the nearest foot?

Answers

Given: The bearing and distance of Maria and an antenna

To Determine: The height of the antenna from the given information

Solution

From the given information, the diagram below can be deduced

From the diagram above, the height of the antenna is TB

Using SOH CAH TOA

[tex]\begin{gathered} tan38^0=\frac{TC}{EC} \\ EC=BG=200ft \\ SO, \\ tan38^0=\frac{TC}{200} \\ TC=200\times tan38^0 \end{gathered}[/tex][tex]\begin{gathered} TC=156.257ft \\ TB=TC+CB \\ EG=CB=5ft \\ TB=156.257+5 \\ TB=161.257ft \\ TB\approx161ft \end{gathered}[/tex]

Hence, the height of the antenna is 161ft

Given parallelogram ABCD; ED=7x and BD=16x-38. Find BD. * B C E А D

Answers

[tex]\begin{gathered} \text{Note since it's a paragellogram then we have.} \\ ED\text{ = }\frac{1}{2}\times BD \\ 7x\text{ = }\frac{1}{2}\times(16x-38) \\ 7x\text{ =}\frac{(16x-38)}{2} \\ By\text{ cross multiplying we have.} \\ 7x\text{ }\times\text{ 2 = 16}x\text{ -38} \\ 14x\text{ = 16}x\text{ - 38} \\ By\text{ collecting like term we have.} \\ 14x-\text{ 16}x\text{ = -38} \\ -2x\text{ = -38} \\ x\text{ = }\frac{-38}{-2}\text{ = 19} \\ x\text{ = 19} \\ \text{Therefore, BD = 16}x\text{ - 38} \\ \text{ BD = 16}\times19\text{ - 38} \\ \text{ BD = 304 - 38} \\ \text{ BD =}266 \end{gathered}[/tex]

f(x)=4x^2+7x-18 find f(-9)

Answers

To find f(-9) you have to replace x = -9 into f(x) as follows:

f(x)=4x²+7x-18

f(-9) = 4(-9)² + 7(-9) - 18

f(-9) = 4(81) - 63 - 18

f(-9) = 324 - 63 - 18

f(-9) = 243

X - y = 0X + y = - 4

Answers

We are given the following system of equations:

[tex]\begin{gathered} x-y=0,(1) \\ x+y=-4,(2) \end{gathered}[/tex]

We are asked to determine the solution by graphing the system.

To do that we will graph each of the equations. We will solve for "y" in equation (1), to do that we will add "y" to both sides:

[tex]\begin{gathered} x-y+y=y \\ x=y \end{gathered}[/tex]

Switching the direction of the equation we get:

[tex]y=x[/tex]

Now, we graph the equation. We notice that this is the equation of a line since it has the form:

[tex]y=mx+b[/tex]

In this case, m = 1 and b = 0.

To graph a line we need to know two points in the line. We will determine those points by giving values to "x". We will substitute the value x = 0, we get:

[tex]y=0[/tex]

Substituting "x = 1" we get:

[tex]y=1[/tex]

Therefore, the two points are:

[tex]\begin{gathered} (x_1,y_1)=(0,0) \\ (x_2,y_2)=(1,1) \end{gathered}[/tex]

Now we plot both points and join them with a line. The graph is the following:

Now we solve for "y" in equation (2). To do that we will subtract "x" from both sides:

[tex]y=4-x[/tex]

Now, we graph using the same procedure as before. We will graph both lines in the same coordinate system and we will determine their interception point, like this:

The interception point is the solution of the system. Therefore, the solution is:

[tex](x,y)=(-2,-2)[/tex]

Can this relation also be represented as {(-1, 1), (0, -2), (3, 1), (4, -1)}.?

Answers

In general, a relation can be represented by a set of ordered pairs (x,y), where x is a value in the domain of the relation and y is its corresponding value in the codomain.

Therefore, in our case, the relation is

[tex]\lbrace(0,-2),(3,1),(4,-1),(-1,-1)\rbrace[/tex]

On the other hand, notice that (-1,1) is in the given set; that implies that the corresponding value of -1 in the codomain is 1 which is not true.

Thus, the answer is NO. It must be (-1,-1), not (-1, 1)

Find the perimeter and area of a rectangle of cardboard measuring 18.2 cm by 5.6 cm Perimeter: I cm Enter an integer or decimal number (more

Answers

The perimeter of a rectangle is given by the following formula:

P = 2w+ 2l

Where w is the width and l is the length of the figure.

The area of a rectangle is given by the following formula:

A = w×l

By replacing 18.2 for l and 5.6 for w, we get:

P = 2×5.6 + 2×18.2 = 47.6

A = 5.6×18.2 = 101.92

Then, the perimeter of the rectangle equals

How do I do this math problem I’m kinda lazy

Answers

Add 12 on both sides.

17x-12<90
+12 +12
—————
17x<102

Divide by 17 on both sides

17x
— 17 cancels out leaving you with just x.
17

102 divided by 17 is 6.

X<6

Graph 6 on the number line like this:

6(open circle) with arrow like this:
<————-

<————-6

Find the values of each variable using sin, cos or sine

Answers

To obtain the value of x, substitute the values of the following.

[tex]\begin{gathered} \theta=70\degree \\ \text{opposite side}=x \\ \text{hypothenuse}=30 \end{gathered}[/tex]

Thus, we obtain the following

[tex]\begin{gathered} \sin \theta=\frac{opposite\text{ side}}{hypothenuse} \\ \sin 70\degree=\frac{x}{30} \end{gathered}[/tex]

Multiply both sides of the equation by 30 and then simplify.

[tex]\begin{gathered} 30\sin 70\degree=x \\ x\approx28.19 \\ x\approx28 \end{gathered}[/tex]

Since the two sides are equal, the base angles must be equal. Thus, we obtain the following.

[tex]\begin{gathered} \theta=70\degree \\ \text{adjacent side}=y \\ \text{hypothenuse}=30 \end{gathered}[/tex]

Substitute the values using the following equation.

[tex]\begin{gathered} \cos \theta=\frac{adjacent\text{ side}}{hypothenuse} \\ \cos 70\degree=\frac{y}{30} \end{gathered}[/tex]

Multiply both sides of the equation by 30 and then simplify.

[tex]\begin{gathered} 30\cos 70\degree=y \\ y\approx10.26 \\ y\approx10 \end{gathered}[/tex]

Therefore, the value of x is approximately 28.19 and the value of y is approximately 10.26.

Choose the equation of the horizontal line that passes through the point (-5,9)

Answers

We are asked to find the equation of the horizontal line that passes through the point (-5, 9)

Recall that point-slope is given by

[tex]y-y_1=m(x_{}-x_1)[/tex]

Where m is the slope of the line and x1 and y1 are the coordinates of the given point.

We know that the slope of a horizontal line is 0.

So let us substitute m = 0 and the given point into the above formula

[tex]\begin{gathered} y-9_{}=0\cdot(x_{}-(-5)_{}) \\ y-9=0 \\ y=9 \end{gathered}[/tex]

Therefore, the equation of the line is y = 9

The angle of depression from d measures 25 if EF= 10 find De.

Answers

Step 1: You draw the diagram

The term angle of depression denotes the angle from the horizontal downward to an object. An observer's line of sight would be below the horizontal.

The angle of depression is equal to angle

Step 2: Apply trigonometric ratio to find the side DE.

[tex]\begin{gathered} \tan \theta\text{ = }\frac{Opposite}{\text{Adjacent}} \\ \theta\text{ = 25} \\ \text{Opposite DE = ?} \\ \text{Adjacent EF = 10 yd} \end{gathered}[/tex]

Step 3: Substitute the values in the tangent equation to find side DE.

[tex]\begin{gathered} \tan 25\text{ = }\frac{DE}{10} \\ 0.4663\text{ = }\frac{DE}{10} \\ \text{Cross multiply} \\ DE\text{ = 10 x 0.4663} \\ DE\text{ = 4.663} \end{gathered}[/tex]

Final answer

DE = 4.7 yard

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