For the chemical reaction 2KI+Pb(NO3)2⟶PbI2+2KNO3 how many moles of lead(II) iodide (PbI2) are produced from 8.0 mol of potassium iodide (KI)? number of moles: mol

Answers

Answer 1

Answer:

the number of moles is 6

Explanation:

The computation of the number of moles is given below:

According to the question

Since 2 mol of KI produces 1 mol of PbI2

based on the above information  

The number of moles would be  

8 mol will produce 6 mol of PbI2

Therefore the number of moles is 6

Hence, the same is considered and relevant too

The other things would be ingored


Related Questions

Which salt preparation uses a burette and a pipette

Answers

potassium chloride from potassium hydroxide and hydrochloric acid

why phenol is more acid than alcohol????​

Answers

Answer:

Phenol is more acidic than alcohol due to resonance stabilization of the phenoxide ion.

how many ions does magnesium phosphite have? how many of those are anions? please explain thought process.

Answers

Answer:

We can simply refer to the cation in the ionic compound as magnesium. Phosphorus, Pstart text, P, end text, is a group 15 element and therefore forms 3- anions.

Explanation:

Because it is an anion, we add the suffix -ide to its name to get phosphide as the name of the ion.

.35L sample of helium gas is collected at 295 K and 0.98 ATM what volume would this gas occupy at STP

Answers

Answer:

0.3857 litres is the answer

In what industry do fertilizers and pesticides wash off and contaminate water supplies?Construction Oil Transportation Agriculture

Answers

Answer:

The answer is agriculture.

Explanation:

Answer: Agriculture

Explanation:

I got it right on my exam

I am doing a exam in science need help.
What type of energy comes from the motion of tiny particles of matter?

Answers

Answer:

here you are

Explanation:

atomic energy

Which of the following molecules are Polar? Select all that apply.
Group of answer choices
A.CH3Cl
B.HF
C.O2
D.PF5
E.HCN
F.SeBr6
G.H2S

Answers

The molecule that is polar is B C G

Compared to water, metals heat up faster because they have

Answers

Answer: the answer would be a lower specific heat.

Explanation:

A buffered solution _______. Select the correct answer below: fails to keep hydronium and hydroxide ion concentrations nearly constant when strong acids or bases are added. maintains a constant or nearly constant pH when small amounts of strong acids or bases are added. acts to keep the hydroxide ion concentration nearly constant. acts to keep the hydronium ion concentration nearly constant.

Answers

I believe it is the second one

The correct option for the given question about Buffer Solution is Option B) which is maintains a constant or nearly constant pH when small amounts of strong acids or bases are added.

What is a Buffer Solution?When a little quantity of acid or base is diluted or added, the buffer solution undergoes very slight variations in its hydrogen ion concentration (pH). pH may be maintained in buffer solutions, which are mixtures of a weak acid and its conjugate base or a weak base and its conjugate acid.Acidic and alkaline buffers are the two main groups into which buffer solutions are commonly categorized.A weak acid and its salt are combined with a strong base to create an acidic buffer, which has an acidic pH.A weak base, its salt, and a strong acid are combined to create an alkaline buffer, which has a basic pH.

Thus we conclude that when weak acids or bases are supplied in small amounts, the pH remains steady or almost constant.

Learn more about Buffer Solution here:

https://brainly.com/question/26416276

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The process of breaking a compound down into its elements is called
rearrangement
recombination
decomposition
dessication

Answers

I believe it’s decomposition

A student in the lab accidentally poured 45 mL of water into a graduated cylinder containing 15 mL of 3.0 M HCL. What is the concentration of the new solution?

Answers

Answer:

The correct approach is "1 M".

Explanation:

The given values are:

Volume of HCL,

V₁ = 45 ml

In prepared solution,

V₂ = 15 ml

Concentration,

C₁ = ?

C₂ = 3.0 M

As we know,

⇒  [tex]V_1C_1=V_2C_2[/tex]

or,

⇒      [tex]C_1=\frac{V_2C_2}{V_1}[/tex]

On substituting the values, we get

⇒           [tex]=\frac{15\times 3}{45}[/tex]

⇒           [tex]=\frac{45}{45}[/tex]

⇒           [tex]=1 \ M[/tex]

Use the following Balanced Equation to complete the question: 2 Al + 6 HBr → 2 AlBr3 + 3 H2

If you have 10 moles of Al how many moles of H2 can be produced?


*Will give Brainly!*

Answers

Here is the answer enjoy

When P4O10(s) reacts with H2O(l) to form H3PO4(aq) , 453 kJ of energy are evolved for each mole of P4O10(s) that reacts. Write a balanced thermochemical equation for the reaction with an energy term in kJ as part of the equation.

Answers

Answer:

P4O10 + 6H2O → 4H3PO4         ΔH = 453 kJ

Explanation:

A thermochemical reaction is one in which the amount of heat gained/evolved is written as part of the reaction equation.

A thermochemical equation helps us to judge whether an equation is endothermic or exothermic. For an endothermic reaction, ΔH  is positive while for an exothermic reaction ΔH is negative.

Since, the reaction of one mole of P4O10(s)  with H2O(l) to form H3PO4(aq) evolves 453 kJ of energy for each mole of P4O10(s) that reacts. Then we can write;

P4O10 + 6H2O → 4H3PO4         ΔH = 453 kJ

Plzz help me well mark brainliest if you are correct

Answers

Answer:

A. non renewable energy sources cannot be used over again and renewable energy sources can be used again

Answer:

A. Nonrenewable energy sources cannot be used over again. Renewable energy sources can be used again.

Explanation:

Atoms of which elements form bonds without satisfying the octet rule?

Answers

Answer:

Helium and hydrogen......

visible light travels from place to place as a

Answers

Answer:

Light can travel in three ways from a source to another location: (1) directly from the source through empty space; (2) through various media; (3) after being reflected from a mirror.

Explanation:

125.0 mL of 2.00 M NaCl solution is diluted to a concentration of 1.50 M. How many mL of water was added to the original volume? (Hint: must find V2 first) 1

166.7 ml
30.9 mL
41.7 ml
292 mL
(no links and please show work)​

Answers

Answer:

Option A

Explanation:

As we know

C1V1 = C2V2

C1 = concentration of solution before dilution

V1 = Volume of solution before dilution

C2 = concentration of solution after dilution

V2 = Volume of solution after dilution

Substituting the given values in above equation, we get -

125 mL * 2.00 M  = X mL * 1.50 M

X mL = 125 mL * 2.00 M  / 1.50 M

X = 167 mL

Hence, option A is correct

gases are really _______ and molecules are full of _______, bouncing around constantly

Answers

Gases are really spread out and the atoms and molecules are full of energy - , bouncing around constantly.

Answer:Gases are really spread out and the atoms and molecules are full of energy - , bouncing around constantly.

Explanation:

g At elevated temperatures, molecular hydrogen and molecular bromine react to partially form hydrogen bromide: H 2 (g) Br 2 (g) 2HBr (g) A mixture of 0.682 mol of H 2 and 0.440 mol of Br 2 is combined in a reaction vessel with a volume of 2.00 L. At equilibrium at 700 K, there are 0.516 mol of H 2 present. At equilibrium, there are ________ mol of Br 2 present in the reaction vessel.

Answers

Answer: At equilibrium , there are 0.274 moles of [tex]Br_2[/tex]

Explanation:

Moles of  [tex]H_2[/tex] = 0.682 mole

Moles of  [tex]Br_2[/tex] = 0.440 mole

Volume of solution = 2.00 L

Initial concentration of [tex]H_2[/tex] = [tex]\frac{0.682}{2.00}=0.341 M[/tex]

Initial concentration of [tex]Br_2[/tex] =  [tex]\frac{0.440}{2.00}=0.220 M[/tex]

Equilibrium concentration of [tex]H_2[/tex] = [tex]\frac{0.516}{2.00}=0.258 M[/tex]

The given balanced equilibrium reaction is,

             [tex]H_2(g)+Br_2(g)\rightleftharpoons 2HBr(g)[/tex]

Initial conc.   0.341 M    0.220 M        0 M    

At eqm. conc.   (0.341-x) M   (0.220-x) M   (2x) M

Given : (0.341-x) M = 0.258 M

x= 0.083 M

Thus equilibrium concentartion of [tex]Br_2[/tex] = (0.220-0.083) M = 0.137 M

Thus moles of [tex]Br_2[/tex] at equilibrium = [tex]0.137M\times 2.00L=0.274mol[/tex]

At equilibrium , there are 0.274 moles of [tex]Br_2[/tex]

why is space cold ???

Answers

Because the space is ultimate thermos.

Suppose that scientists want to study a feature of the galaxy that is very far away. They decide to use a telescope that observes high-energy gamma rays. Explain why this would be a good choice.

Answers

Answer & Explanation:

Gamma rays are the most energetic form of electromagnetic radiation. By observing the distant galaxy at gamma-rays, scientists can search for new physics, test theories, and perform experiments that are not possible in earth-bound laboratories.

What's the bond between two atoms of hydrogen?​

Answers

Answer:There is a iin dipole attraction between two hydrogen atom

Explanation:

The same atoms have the ion dipole attraction between them the same atoms repel each other

A gas has a volume of 10 L at 200 K and a pressure of 1.5 atm . What would the volume of the gas be at 300 K and 2atm of pressure ?

Answers

Answer:

jeyjeyjetnetney

Explanation:

thmrhmrhmrum

A sample of chlorine gas has a volume of 0.30 L at 273 K and 1 atm pressure. What temperature (in ∘C) would be required to increase the volume to 1.0 L ?

Answers

Answer:

[tex]T_2=637\°C[/tex]

Explanation:

Hello there!

In this case, considering this problem as pressure constant, since the change is exhibited in temperature and volume only, it is possible for us to use the Charles' law as shown below:

[tex]\frac{V_2}{T_2}=\frac{V_1}{T_1}[/tex]

Thus, by solving for the final temperature, we obtain:

[tex]T_2=\frac{T_1V_2}{V_1}\\\\T_2=\frac{273K*1L}{0.30L}\\\\T_2=910K-273\\\\T_2=637\°C[/tex]

Best regards!

A solution contains 1.817 mg of CoSO4 (155.0 grams/mole) per mL. Calculate the volume (in mL) of 0.009795 M Zn2 needed to titrate the excess complexing reagent after the addition of 70.00 mL of 0.009005 M EDTA to a 20.00 mL aliquot of the Co2 solution.

Answers

Answer:

85.952 ml [tex]Zn^2^+[/tex]  needed to titrate the excess complexing reagent .

Explanation:

Lets calculate

After addition of 80 ml of EDTA the solution becomes = 20 + 70 = 90 ml

As the number of moles of [tex]CoSO_4[/tex] =[tex]\frac{Given mass }{molar mass}[/tex]

                                                       =[tex]\frac{1.817}{155}[/tex]

                                                          =0.01172

Molarity = [tex]\frac{no. of moles}{volume of solution}[/tex]

           =[tex]\frac{0.01172}{20}[/tex]

        =0.000586 moles

Excess of EDTA = concentration of EDTA - concentration of CoSO4

                            = 0.009005 - 0.000586

                           = 0.008419 M

As M1V1 ( Excess of EDTA ) = M2V2 [tex](Zn^2^+)[/tex]

           [tex]0.008419\times100ml=0.009795\times V2[/tex]

           [tex]V2=\frac{0.008419\times100}{0.009795}[/tex]

             V2 =85.952 ml

Therefore , 85.952 ml [tex]Zn^2^+[/tex] needed to titrate the excess complexing reagent .

Atoms in the same GROUP have the same...

A . Size
B. Temperature
C. Number of energy levels
D. Reactivity

Answers

Answer:

reactivity

Explanation:

for example atoms in group 7 react by gaining 1 electron to become stable but they do not have the same number of energy levels


How many grams of Co, are produced when 88 g of o, is reacted with an excess of
butane?

Answers

Answer:

[tex]74.5gCO_2[/tex]

Explanation:

Hello there!

In this case, for the described reaction, it is possible to realize there is a 13:8 mole ratio between oxygen (O2) and carbon dioxide (CO2); moreover, since the molar mass of the former is 32.00 g/mol and that of latter is 44.01 g/mol, the produced mass of the required product turns out to be:

[tex]88gO_2*\frac{1molO_2}{32.00gO_2}*\frac{8molCO_2}{13molO_2}*\frac{44.01gCO_2}{1molCO_2} \\\\=74.5gCO_2[/tex]

Best regards!

Reaction of Nitrile with Grignard Grignard reagents react with nitriles to give an intermediate imine anion that is hydrolyzed by the addition of water to yield a ketone. The mechanism is similar to the reduction of a nitrile to an amine except that only one nucleophilic addition occurs instead of two, and the nucleophile is a carbanion rather than a hydride ion.

Required:
Draw curved arrows to show the movement of electrons. in this step of the mechanism. Arrow-pushing Instructions

Answers

Answer:

its a.

Explanation:

Considering change of state descriptions, select the name of the change of state for when energy is absorbed. Group of answer choices sublimation freezing condensation deposition

Answers

Answer: Sublimation

Explanation:

Sublimation : It is a process in which a solid directly changes to gaseous phase by providing heat.

Freezing is a process in which a liquid changes into solid phase when allowed to cool.

Condensation is a process in which a gas changes into liquid phase when allowed to cool.

 Deposition is a  process in which a gas deposits as solid phase when allowed to cool.

Thus change of state where energy is absorbed is sublimation.

Convert 5.28 x 1019 molecules of C6H1206 to grams.

Answers

Answer:

[tex]m=0.0158g[/tex]

Explanation:

Hello there!

In this case, it is possible to comprehend these mass-particles problems by means of the concept of mole, molar mass and the Avogadro's number because one mole of any substance has 6.022x10²³ particles and have a mass equal to the molar mass.

In such a way, for C₆H₁₂O₆, whose molar mass is about 180.16 g/mol, the referred mass would be:

[tex]m=5.28x10^{19}molecules*\frac{1mol}{6.022x10^{23}molecules}*\frac{180.16g}{1mol}\\\\m=0.0158g[/tex]

Best regards!

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