For the wild type (unmutated) enzyme, you measure a rate of p-nitrophenol release by the change in absorbance at 405 nm (for the slower phase only) of 0.216 (in a cuvette with a pathlength of 1 cm) over the course of two minutes. Use the Beer-Lambert Law to calculate the concentration of product released over this time; the extinction coefficient of p-nitrophenol at 405 nm is 18,000 M-1 cm-1.

Answers

Answer 1

Answer:

1.2x10⁻⁵M = Concentration of the product released

Explanation:

Lambert-Beer's law states the absorbance of a solution is directly proportional to its concentration. The equation is:

A = E*b*C

Where A is the absotbance of the solution: 0.216

E is the extinction coefficient = 18000M⁻¹cm⁻¹

b is patelength = 1cm

C is concentration of the solution

Replacing:

0.216 = 18000M⁻¹cm⁻¹*1cm*C

1.2x10⁻⁵M = Concentration of the product released

Related Questions

Coal, oil, and natural gas are called _______.
A.
fossil fuels
B.
renewable resources
C.
nuclear power
D.
solar energy

Answers

Answer:

I think it's A. I'm pretty sure.

Explanation:

Answer:

Coal, oil and natural gas are called _________A. fossil fuels

Calculate the value of the equilibrium constant for the following system, where the concentrations of reactants and products are: [NO]=1.2x10^-3M , [NO2]=1.5x10-^1M , [N2O]=2.4x10^-3M

Answers

Answer:

The equilibrium constant is 2.08x10⁵

Explanation:

Based on the reaction:

3NO ⇄ N₂O + NO₂

The equilibrium constant, k, is defined as:

k = [NO₂] [N₂O] / [NO]³

Where the [] is the molarity in equilibrium of each specie.

Computing te values of the problem:

k = [1.5x10⁻¹M] [2.4x10⁻³M] / [1.2x10⁻³M]³

k = 2.08x10⁵

The equilibrium constant is 2.08x10⁵

3. Determine the enthalpy of formation for propane. 3C(s, gr) + 4H2(g) ---> C3H2(g) CzH3(g) AH = -2219.9 kJ C(s, gr) AH = -393.5 kJ H,(g) AH = -285.8 kJ a. -205.7 /mol b. -103.8 kJ/mol Å C. + 205.7 /mol d. + 103.8 /mol​

Answers

Answer:

b I hope this is right good luck

1.20×10−8s to nanoseconds

Answers

Answer:

There are 12 nanoseconds in [tex]1.2\times 10^{-8}\ s[/tex].

Explanation:

We need to convert [tex]1.2\times 10^{-8}\ s[/tex] to nanoseconds.

We know that,

[tex]1\ s=10^9\ ns[/tex]

Now using unitary method to solve it such that,

[tex]1.2\times 10^{-8}\ s=1.2\times 10^{-8}\ \times 10^9\\\\=1.2\times 10\\\\=12\ ns[/tex]

So, there are 12 nanoseconds in [tex]1.2\times 10^{-8}\ s[/tex].

water and Air are needed for iron rust answer true or false​

Answers

Answer:True

Explanation:

PLZ GIVE ME BRAINLIEST, I NEED IT

Answer: True


Explanation: also true

A 38.22 mL aliquot of weak acid that has a concentration of 0.882 M will be titrated with 0.289 M NaOH. Calculate the pH of of the solution upon neutralization of half of the weak acid. The Ka of the acid is 6.8×10-7.

Answers

Answer:

pH = 6.167

Explanation:

The weak acid, HX, reacts with NaOH as follows:

HX + NaOH → NaX + H₂O

Where 1 mole of HX with 1 mole of NaOH produce 1 mole of NaX (The conjugate base of the weak acid).

Now, using H-H equation:

pH = pKa + log [NaX] / [HX]

Where pH is the pH of the buffer

pKa is -log Ka = 6.167

And [NaX] [HX] are the molar concentrations of each specie

Now, at the neutralization of the half of HX, the other half is as NaX, that means:

[NaX] = [HX]

And:

pH = pKa + log [NaX] / [HX]

pH = 6.167 + log 1

pH = 6.167

What was the purpose of letting the transformed cells sit in LB for a few minutes before spreading them onto the plates?

A. This allows time for the cells to express the antibiotic resistance gene

B. This allows the cells to take up the plasmid after the heat shock procedure

C. This allows time for the cells to warm up before plating

D. This allows cells time to start glowing green

Answers

I think c ... C this is the correct

An analytical chemist is titrating 111.0 mL of a 0.3700 M solution of aniline (C6H5NH2) with a 0.3500 M solution of HNO3. The pK_b of aniline is 9.37. Calculate the pH of the base solution after the chemist has added 79.1 mL of the HNO_3 solution to it.

Answers

Answer:

The answer is "4.31"

Explanation:

aniline millimoles [tex]= 111 \times 0.37 = 41.07[/tex]

added [tex]HNO_3[/tex]  millimoles [tex]= 79.1 \times 0.35 = 27.685[/tex]

[tex]\to 41.07 - 27.685 = 13.385[/tex] millimoles aniline left

[tex]\to 27.685[/tex] millimoles salt formed

total volume[tex]= 111 + 79.1 = 190.1\ mL\\\\[/tex]

[tex]\to [aniline] = \frac{13.385}{190.1} = 0.07 \ M\\\\\to [salt] =\frac{ 27.685}{ 190.1} = 0.146\ M\\\\\to pOH = pKb + \frac{\log [salt]}{ [base]}\\\\\to pOH = 9.37 + \frac{\log [0.146]}{[0.07]}\\\\\to pOH = 9.69\\\\\to pH = 14 - 9.69\\\\\to pH = 4.31\\[/tex]

Chrysanthemic acid occurs as a mixture of esters in flowers of the chrysanthemum (pyrethrum) family.

a. True
b. False

Answers

Answer:

A: True

Explanation:

Statement is true because chrysanthemic acid is formed naturally as a result of production of two molecules of dimethylallyl diphosphate which forms pyrophosphate ester.

Thus, it belongs to the pyrethrum family

How many molecules of O2 will be required to produce 28.8 g of water?

Answers

I think 1.67 x 10^20

Addition of sugar to water will result in increase of boiling point
TRUE OR FALSE

Answers

Answer:

true

Explanation:

true. i think. :) sorry if i’m wrong, i’m not the brightest.

A 36.6-mol sample of Co represents how many atoms?

Answers

Answer:

2.20 x 10²⁵ atoms

Explanation:

Atoms of CO= 36.6-mol sample

From Avogadro's constant, which is

(6.022 × 10^ 23 atoms per mole)

Then

Number of atoms=[ 6.022 × 10^ 23 atoms/mole] × [36.6-mol]

= 2.20 x 10²⁵ atoms

Hence, number of atom is 2.20 x 10²⁵ atoms

The molecular weight (MW) of CuSO4 is 250g/mol. How many grams of CuSO4 are needed to make a 10 ml solution that has a molarity of 2.0 M?

Answers

Answer:

Explanation:

(The MW of CuSO4 is 250 g/mol).

Answer:

5 grams of CuSO4

Explanation:

First you make a stoichiometric relationship between the molarity and liters. So there is 2 mols per every liter. Then you put in the moleculur weight( for every mol there is 250 g). Then you have to get rid of the liters, so you times the equation by 0.01(this was found by 10ml converted into liters). After all of that you should end up with 5 grams of CuSo4

please help me please

Answers

Answer:

Two advantages are: Its cheap and it is a renewable energy source. Two disadvantages are it's not windy everyday and it will take up a lot of space for windmills.

Explanation:

Which of the following is a metal?


a.
silicon, Si, Z = 14

b.
phosphorus, P, Z = 15

c.
thallium, Tl, Z = 81

d.
arsenic, Z = 33

e.
nitrogen, N, Z = 7

Answers

Answer:

A.................. I think the answer

Why do we test for free chlorine in drinking water?

Answers

Answer:

The presence of free chlorine in drinking water is correlated with the absence of most disease-causing organisms, and thus is a measure of the potability of water

I NEED HELP WITH THIS ASAPP

Answers

the answer is stationary bc between those two times the car is not moving as seen by the flat line

Why is a rotting apple a reaction in which energy is neither absorbed nor released?
A. The chemical energy in the reactants is almost equal to the chemical energy in the products.
B. The chemical energy in the reactants is much greater than the chemical energy in the products.
C. The chemical energy in the reactants is much less than the chemical energy in the products.
( don’t send links, I won’t click them)

Answers

I don’t know the answer but ik it is due to oxidation rooting apple is a reaction but it neither absorb or release energy

25m
45m
Help pls.........

Answers

Answer:

45m

Explanation:

The weight for this compound is 74. what is the molecular formula​

Answers

Explanation:

ur question is incomplete what elements make the compound and we talk of mass not weight and what are the units kjmol ,grams ,kgs

Calculate the pOH of this solution. pH = 1.90 pOH =

Answers

Answer:

12.1

Explanation:

Since the pH has been given, the pOH can be found by using the formula

pH + pOH = 14

pOH = 14 - pH

From the question we have

pOH = 14 - 1.9

We have the final answer as

12.1

Hope this helps you

Answer:

12.10

Explanation:

b) A piece of solid gold was heated from 274K to 314K using 55.7J of energy to raise the
temperature. What mass of gold was present?​

Answers

Answer:

Explanation:

So we know q = mc[tex]\Delta[/tex]T.

q = 55.7 J

c = 0.129j/g°C

and [tex]\Delta[/tex]T = 314-274 = 40°C.

and m is mass which can solve since we got every other variable. We will get m = 10.8g.

Question 6 of 30 Carbon dioxide subliming is an example of which of the following?​

Answers

Answer:

dry ice or solid carbon(iv)oxide

Explanation:

carbon(iv)oxide that sublimes is known as dry ice or solid CO2 and it is used to refrigerate food instead of ordinary ice which will just melt when exposed to hot conditions and there4 will lead to the destruction of food. dry ice will sublime the moisture from the food there4 keeping out any moisture

What is the correct coefficient for Fe2O3 in the balanced version of the following equation?

Fe2O3 + 3H2 → 2Fe + 3H2O

__Fe2O3+3H2→2Fe+3H2O

Answers

Answer:

The coefficient of Fe₂O₃ is 1

Explanation:

__Fe₂O₃ + 3H₂ —> 2Fe + 3H₂O

To know the correct coefficient of Fe₂O₃, we shall balanced the equation. This can be obtained as follow:

Fe₂O₃ + H₂ —> Fe + H₂O

There are 2 atoms of Fe on the left side and 1 atom on right side. It can be balance by writing 2 before Fe as shown below:

Fe₂O₃ + H₂ —> 2Fe + H₂O

There are 3 atoms of O on the left side and 1 atom on the right side. It can be balance by writing 3 before H₂O as shown below:

Fe₂O₃ + H₂ —> 2Fe + 3H₂O

There are 2 atoms of H on the left side and 6 atoms on the right side. It can be balance by writing 3 before H₂ as shown below:

Fe₂O₃ + 3H₂ —> 2Fe + 3H₂O

Now, the equation is balanced.

Thus, the coefficient of Fe₂O₃ is 1


10. Which of the following group of colors of the visible light is listed from
lowest to highest frequency?
A. Blue, green, red
C. Red, violet, green
B. Green, blue, red
D. Red, green, violet​

Answers

Answer:

The correct answer is - D. Red, green, violet​.

Explanation:

Visible light is the spectrum of light that can be seen by the naked eyes of humans without any equipment. This spectrum has various frequency light that helps us see things in color. The frequency of light ranges between seven different colors in which violet has the highest frequency and red has the lowest.

The different frequencies are as follows:

color               frequency

red (limit) 1.77

red                  1.91

orange  2.06

yellow  2.14

green  2.25

cyan  2.48

blue          2.75

violet (limit) 3.10

On this basis of this the group of colors of the visible light is listed from

lowest to the highest frequency - Red, green, violet​

What happens to the conductivity of water when a base is dissolved in it.

Answers

Answer:

See Explanation

Explanation:

The conductivity of water refers to how much it conducts electricity. The electrical conductivity of water increases as more ions are dissolved in it.

Hence, increase in concentration of dissolved ions improves the electrical conductivity of water.

Therefore, when a base (which is an ionic substance) is dissolved in water, the concentration of ions present increases and the conductivity of the solution increases accordingly since ions are charge carriers in solution.

The addition of a base to the sample results in an increase in the conductivity of the sample.

Conductivity can be defined as the transfer of charge by the sample. The sample has consisted of the ions that mediate the transfer of charge.

The sample with a high number of ions has consisted of high conductivity and vice versa. The dissolution of acid or base to the solution results in an increase in the number of ions in the solution, and thereby there has been an increase in the charge transfer.

Thus, with the increase in the charge transfer, there has been an increase in the conductivity of the sample.

For more information about the conductivity of the sample, refer to the link:

https://brainly.com/question/6072723

Hey can someone pls help me answer these questions? It should be easy maybe. It’s just science. The question just won’t to know where you would put the arrow above to show the motion of the plates. Where would I put it?

Answers

Hehehehwgwgw. Be the hardest thing ever for a long day and I have a windows

The different unit cell types have a different packing efficiency. The simple cubic has the least efficient packing and the face-centered cubic has the most efficient packing (sometimes the face-centered cubic is called cubic closest packing). You can determine what percent of the unit cell is occupied by (1) determining the volume of the whole unit cell and (2) determining the volume of the occupied space by the atoms in the unit cell. Remember that the volume of a cube is V

Answers

Answer:

The answer is "52.8".

Explanation:

Please find the graph file in the attachment.

They have the atoms in 8 corners with one unit cell in an one so mesh (SCC).

Atoms throughout the corner contribute [tex]\frac{1}{8}[/tex]to both the cell unit

Atom number per SCC unit cell, [tex]Z = (8 \times \frac{1}{8}) = 1[/tex]

Let 'r' become the atom's radius.  [tex]r = 3.43\times 10^{-8}\ \ cm[/tex]

We can see from the diagram that edge length [tex]AB = a = 2r[/tex]

[tex]Packing\ efficiency = \frac{(1 \ atom \ Volume \times Z)}{Volume \ of \ unit\ cell \times 100}\\\\[/tex]

                                 [tex]= \frac{\frac{4}{3}\times \pi \times r^3 \times 1}{a^3 \times 100}\\\\=\frac{\frac{4}{3}\times \pi \times r^3 \times 1}{(2r)^3 \times 100} \\\\=\frac{\frac{4}{3}\times \pi \times( 3.43\times 10^{-8}cm)^3 \times 1}{(2\times 3.43\times 10^{-8}cm)^3 \times 100}\\\\= 52.8 \%[/tex]

Zn(s), Zn(NO3)2 (0.3 M) || Cu(s), CuCl2 (0.5 M)

(Need help solving these questions, so I can solve the rest of the questions like this in my lab. It is greatly appreciated. Thank you)

2. Write the half reactions that occur at the anode and cathode in this electrochemical cell. Annotate which half reaction occurs at the anode and the cathode.
3. Write the overall balance reaction of this electrochemical cell.
4. Calculate E°cell of this electrochemical cell. (include units)
5. Calculate the reaction quotient (Q) of this reaction.
6. Calculate the expected Ecell for this reaction

Answers

Answer:

See Explanation

Explanation:

At the anode;

Zn(s) -----> Zn^2+(aq) + 2e

At the cathode;

Cu^2+(aq) + 2e ------> Cu(s)

Overall electrochemical reaction;

Zn(s)  + Cu^2+(aq) ------>  Zn^2+(aq) + Cu(s)

E°cell = E°cathode - E°anode

E°cell = 0.34 - (-0.76)

E°cell = 1.1 V

Q = [0.3 M]/[0.5 M]

Q = 0.6

From Nernst equation;

Ecell =  E°cell - 0.0592/n log Q

Ecell = 1.1 - 0.0592/2 log (0.6)

Ecell = 1.1 - 0.0296 log (0.6)

Ecell = 1.11 V

Gelatinization happens with what type of Carbohydrate?

Answers

it happens with starch granules!
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