This task involves creating two complex commands. The first command should find the 10 most frequently used words in a text file, and the second command should find the 10 least frequently used words.
These commands should each be written as a single line in Bash script, utilizing commands such as `xargs`, `grep`, `sort`, and others.
To find the 10 most frequently used words in a file, you can use the following command:
```bash
tr '[:space:]' '[\n*]' < filename.txt | grep -v "^\s*$" | sort | uniq -c | sort -bnr | head -10
```
The `tr` command replaces spaces with newline characters, creating a word-per-line format. `grep -v "^\s*$"` removes empty lines, `sort` orders the words, and `uniq -c` combines identical lines and prefixes them with a count. `sort -bnr` sorts lines based on the count in reverse numerical order, and `head -10` returns the top 10 lines.
To find the 10 least frequently used words, use the same command but replace `head -10` with `tail -10`.
```bash
tr '[:space:]' '[\n*]' < filename.txt | grep -v "^\s*$" | sort | uniq -c | sort -bnr | tail -10
```
This command line is similar to the first one, but it prints the last 10 lines instead of the first, revealing the least frequent words.
Learn more about Bash scripting here:
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