For which situations is it appropriate to use a sample? Select three options.

Answer:

Money in her purse is Rs. 500.

Step-by-step explanation:

Let the money in her purse = Rs. [tex]x\\[/tex]

Let the money in her Money box = Rs. [tex]y[/tex]

As per question statement,

[tex]2x+y=1700[/tex]  ........ (1)

[tex]3x+y=2200[/tex] ....... (2)

To find: Money in her purse = ? i.e. [tex]x=?[/tex]

Let us solve for [tex]x[/tex] using the two linear equations.

We can use substitution method here i.e. find value of one variable from one equation and then substitute that value in other equation.

Using equation (1), we get the value of [tex]y[/tex] as follows:

[tex]y=1700-2x[/tex]

Now, let us put this value of y in equation (2) to find the value of [tex]x[/tex]:

[tex]3x+1700-2x=2200\\\Rightarrow x+1700 = 2200\\\Rightarrow x=2200-1700\\\Rightarrow x = Rs.\ 500[/tex]

Money in her purse is Rs. 500.

Answer:

a) 0

b) 1

c) 0

Step-by-step explanation:

These are common values from the unit circle but you could also just check with your calculator. Just be sure to set it to degree mode and not radian mode.

So if we think of a test tube, it looks sort of like a cylinder. This means that its cross-section would be a circle. To find out how many turns a piece of thread would make around the test tube, we need to find the circumference of the test tube, then divide the length of the string by the circumference.

Step 1) Find the circumference

C = pi x diameter

C = 3.14 x 3

C = 9.42

Step 2) Divide the length of the string by the circumference

90.42 / 9.42 = 9.5987

The string would make approximately 9.60 turns around the test tube.

Hope this helps!! :)

Answer:

see file attached

Step-by-step explanation:

Answer:

2<F(x)<5

Step-by-step explanation:

We can guess that it come between 2 and 5 given the pattern that we see in the table, but there’s no reason we can’t solve it to be sure.

F(x)=3 (Times the square root of 1.5-1)+2

3(square root of .5)+2

3(0.7)+2

2.12+2

4.12

So, yes, it is between 2 and 5

2<F(x)<5

Answer:

1) $10b

2) 20

3) $5a

Answer:

4 batches

Step-by-step explanation:

1/3=2/6, 2/3=4/6

Answer:

see attached diagram

Step-by-step explanation:

1.  1 and 70 are angles on a line (supplementary)

2. vertical angles with 70

3. angles on a line are supplementary

4. 2 and 4 are supplementary interior angles between parallel lines m & n

5. corresponding angle with 70

Answer:

a) [tex]a_n=3\,n-11[/tex]

b) [tex]a_{20}=49[/tex]

c) term number 17 is the one that gives a value of 40

Step-by-step explanation:

a)

The sequence seems to be arithmetic, and with common difference d = 3.

Notice that when you add 3 units to the first term (-80, you get :

-8 + 3 = -5

and then -5 + 3 = -2 which is the third term.

Then, we can use the general form for the nth term of an arithmetic sequence to find its simplified form:

[tex]a_n=a_1+(n-1)\,d[/tex]

That in our case would give:

[tex]a_n=-8+(n-1)\,(3)\\a_n=-8+3\,n-3\\a_n=3n-11[/tex]

b)

Therefore, the term number 20 can be calculated from it:

[tex]a_{20}=3\,(20)-11=60-11=49[/tex]

c) in order to find which term renders 20, we use the general form we found in step a):

[tex]a_n=3\,n-11\\40=3\,n-11\\40+11=3\,n\\51=3\,n\\n=\frac{51}{3} =17[/tex]

so term number 17 is the one that renders a value of 40

Answer:

27_5_10/2

27_5_5

22_5

17

Answer:

-5z^3-z^4+4z^5

I guess the answer is D because it is the most far from -1 rather than the other

Answer: The answer should be D.-0.5

Answer:

[tex]-8y^{25}\\-9y^6\\5y^5[/tex]

Step-by-step explanation:

First one.

[tex]((-y)^5)(8y^{20})=-y^5*8y^{20}=-8y^{5+20}=-8y^{25}[/tex]

Second one

[tex]((-y)^{5} )(9y)=-y^5*9y=-9y^{5+1}=-9y^6[/tex]

and last one

[tex]((-y)^5)(-5)=-y^5*(-5)=5y^5[/tex]

Answer:

0

Step-by-step explanation:

Please check attachment for complete solution

Answer:

D. 0

Step-by-step explanation:

last option

x = 64°

Step-by-step Explanation

x = 1/2[(360° - 2*58°)-2*58°]

x = 1/2[(360° - 2*58°) - 2*58°]

x = 1/2[(360° - 116°) - 116°]

x = 1/2[244° - 116°]

x = 1/2[128°]

x = 64°

Answer: 4

Step-by-step explanation: use pick’s theorem to solve.

I+B/2-1.

We can substitute the variables with our information from the graph:

0+10/2-1=5-1=4 that’s the answe

Hope this helps

Three different whole numbers whose sum and product are equal are 1, 2, and 3.

1 + 2 + 3 = 6

1 x 2 x 3 = 6

As demonstrated above, the sum and product of 1, 2, and 3 is the same.

Hope this helps!! :)

Answer:

1 2 and 3

Step-by-step explanation:

Answer:

3x³ − x² − x − 4 + (-5/(x−1))

Step-by-step explanation:

Use long division (see attached picture).

Answer:

A. [tex] 3 {}^{9} [/tex]

Step-by-step explanation:

[tex]3 {}^{4} \times {3}^{5} = {3}^{4 + 5} = 3 {}^{9} [/tex]

Hope this helps ;) ❤❤❤

Answer:

[tex]\boxed{3^9}[/tex]

Step-by-step explanation:

[tex]3^5 \times 3^4[/tex]

Apply the law of exponents : [tex]a^b \times a^c = a^{b+c}[/tex]

The exponent product rule states that, when multiplying two exponents that have the same base, you can add the exponents.

[tex]3^{5+4}[/tex]

[tex]3^9[/tex]

Answer:

12x^3 + 12x^2y + 15xy - 18x

Step-by-step explanation:

I simply expanded the equation by multiplying everything in the parentheses by 3x.

Answer:

12x^3+12x^2y+15xy-18x

Step-by-step explanation:

3x (4x^2 + 4xy + 5y - 6)

Distribute

3x *4x^2 +3x* 4xy + 3x*5y -3x* 6

12x^3+12x^2y+15xy-18x

Answer:

y= 1

Step-by-step explanation:

A circle forms a sphere only when it goes around a straight line throughout the center so y= 1 because it's (1,0).

The y = 1 is the axis around which the circle cross-section needs to be revolve to create a sphere.

It is given that the circle is on a coordinate plane with the centre at 1 on the y-axis.

It is required to find around which line would the following cross-section need to be revolved to create a sphere.

It is defined as the combination of points that and every point has an equal distance from a fixed point ( called the centre of a circle).

We have a circle on the coordinate plane the centre of the circle lies on the y-axis at 1.

On y=axis the value of x is zero ie. x= 0

The centre of the circle = (0,1)

If a half-circle revovle around the axis which is dividing the circle into two halves.

As we can see in the graph the y-axis and y=1 divide the circle into two halves.

Thus, the line y = 1 is the axis around which the circle cross-section needs to be revolve to create a sphere.

Learn more about circle here:

brainly.com/question/11833983

Answer:

[tex]\boxed{-25x-y}[/tex]

[tex]\boxed{-p^2q +5pq^2}[/tex]

Step-by-step explanation:

[tex](-15x+6y)-(10x+7y)[/tex]

Distribute negative sign.

[tex]-15x+6y-10x-7x[/tex]

Combine like terms.

[tex]\boxed{-25x-y}[/tex]

[tex]2pq(p+q)- (3pq(p-q))[/tex]

Expand brackets.

[tex]2p^2 q+2pq^2 -(3p^2q-3pq^2)[/tex]

Distribute negative sign.

[tex]-3p^2q+3pq^2+2p^2q+2pq^2[/tex]

Combine like terms.

[tex]\boxed{-p^2q +5pq^2}[/tex]

Answer:

Step-by-step explanation:

a.

[tex] - 15x + 6y - (10x + 7y)[/tex]

When there is a (-) in front of an expression in parentheses, change the sign of each term in the expression

[tex] - 15x + 6y - 10x - 7y[/tex]

Collect like terms

[tex] - 15x - 10x + 6y - 7y[/tex]

[tex] - 25x - y[/tex]

b.

[tex]2pq(p + q) - 3pq(p - q)[/tex]

Factor out pq from the expression

[tex]pq(2(p + q) - 3(p - q))[/tex]

Distribute 2 through the parentheses

[tex]pq \: (2p + 2q - 3(p - q)[/tex]

Distribute -3 through the parentheses

[tex]pq \: (2p + 2q - 3p + 3q)[/tex]

Collect like terms

[tex]pq( - p + 5q)[/tex]

Hope this helps...

Best regards!!

Answer:

66666699999

Step-by-step explanation:

Answer:

40

Step-by-step explanation:

We know there are 16 oz in a pound

We can use ratios

15             x

-----  = ----------

6 oz       16 oz

Using cross products

15 * 16 = 6x

240 = 6x

divide by 6

240/6 = 6x/6

40 =x

Answer:

2

Step-by-step explanation:

We can use the slope formula

m = (y2-y1)/(x2-x1)

    = ( -4 - -2)/ ( 2-3)

    = ( -4+2)/( 2-3)

    = -2/ -1

    = 2

Answer:

7x-1

Step-by-step explanation:

i did the test

Answer:

7x-1

Step-by-step explanation:

correct answer on edge

Approximate what the value of [tex]7/15[/tex] is by using calculator.

[tex]7/15\approx0.47[/tex].

And now just multiply by 100 to get percentage.

[tex]100\cdot0.47=\boxed{47\%}[/tex].

Hope this helps.

Answer:

24%

Step-by-step explanation:

7\15 x 100

simplify and get=140\3

dived140\3=48\2

simplify 48\2=24%

Answer:

i think its the answe d but not sure

Answer:

Height above the bottom gorge is 113 feet

Step-by-step explanation:

The width of the gorge = 40 feet

The height of the higher cliff = 158 feet

The height of the lower cliff = 98 feet

The length of the bridge = √((158-98)² + 40²) = 72.11 feet

The slope of the bridge = (158-98)/40 = 1.5

The length of 1/4 of the bridge from the lower cliff =72.11 - 3/4×72.11 = 18.03 feet

The angle of inclination of the bridge = tan⁻¹(1.5) = 56.31°

The height above the bottom at 3/4 from the higher cliff = The height above the bottom at 1/4 from the lower cliff = 98+ 18.03×sin(56.31 ) = 113 feet

Which can also be found directly from the heights of the two cliffs knowing that 3/4 from the higher cliff = 1/4 from the lower cliff giving;

Height above the bottom gorge = 98 + 1/4×(158 - 98) = 113 feet.

Answer:

[tex] Area = 400.4 m^2 [/tex]

Step-by-step Explanation:

Given:

∆UVW,

m < U = 33°

m < V = 113°

VW = u = 29 m

Required:

Area of ∆UVW

Solution:

Find side length UV using Law of Sines

[tex] \frac{u}{sin(U)} = \frac{w}{sin(W)} [/tex]

U = 33°

u = VW = 29 m

W = 180 - (33+113) = 34°

w = UV = ?

[tex] \frac{29}{sin(33)} = \frac{w}{sin(34)} [/tex]

Cross multiply

[tex] 29*sin(34) = w*sin(33) [/tex]

Divide both sides by sin(33) to make w the subject of formula

[tex] \frac{29*sin(34)}{sin(33)} = \frac{w*sin(33)}{sin(33)} [/tex]

[tex] \frac{29*sin(34)}{sin(33)} = w [/tex]

[tex] 29.77 = w [/tex]

[tex] UV = w = 30 m [/tex] (rounded to nearest whole number)

Find the area of ∆UVW using the formula,

[tex] area = \frac{1}{2}*u*w*sin(V) [/tex]

[tex] = \frac{1}{2}*29*30*sin(113) [/tex]

[tex] = \frac{29*30*sin(113)}{2} [/tex]

[tex] Area = 400.4 m^2 [/tex] (to nearest tenth).