Frank organized a raffle. He sells 300 tickets for £5 each. The prizes cost £400. He gives 55% of the profit to Charity A and 45% of the profit to Charity B. Work out how much each charity receives.

The values of the expression when using the completing the square method is given below

To complete the square for x²-16x+c, we need to add and subtract the square of half the coefficient of x, which is (-16/2)² = 64. So:

x² - 16x + c = (x - 8)² - 64 + c

To complete the square, we added (-16/2)² = 64, but we subtracted it again to keep the expression equivalent. Therefore, c - 64 is the value that completes the square.

Similarly, for x² + 7x + c, we add and subtract (7/2)² = 49/4:

x² + 7x + c = (x + 7/2)² - 49/4 + c

So c - 49/4 completes the square.

For x²- 9x, we add and subtract (9/2)² = 81/4:

x² - 9x = (x - 9/2)² - 81/4

Therefore, c - 81/4 completes the square.

To factor x²- 14x, we can factor out x:

x² - 14x = x(x - 14)

To factor x² + 30x, we can factor out x:

x² + 30x = x(x + 30)

To factor x²- 9x, we can factor out x:

x² - 9x = x(x - 9)

To solve x² + 10x = 16 by completing the square, we first add and subtract (10/2)² = 25:

x² + 10x + 25 - 25 = 16

(x + 5)² = 41

x + 5 = ±√41

x = -5 ±√41

To solve x² - 3x = 7 by completing the square, we first add and subtract (3/2)² = 9/4:

x² - 3x + 9/4 - 9/4 = 7

(x - 3/2)² = 37/4

x - 3/2 = ±√(37/4)

x = 3/2 ±√(37/4)

To solve x² + 15x = 12 by completing the square, we first add and subtract (15/2)² = 225/4:

x² + 15x + 225/4 - 225/4 = 12

(x + 15/2)² = 129/4

x + 15/2 = ±√(129/4)

x = -15/2 ±√(129/4)

a. Let L be the length of the wading pool. Then its width is L - 12. The height is 1 foot, so the volume is:

V = L(L - 12)(1) = L² - 12L

b. To complete the square for the expression L² - 12L, we add and subtract (12/2)² = 36:

L² - 12L + 36 - 36 = (L - 6)² - 36

So the volume can be written as:

V = (L - 6)² - 36

To find the dimensions of the wading pool that give a volume of 108 cubic feet, we set V = 108 and solve for L:

(L - 6)² - 36

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In the given right angled triangle, using Pythagorean theorem, the value of x is 12.73 units.

The Pythagorean theorem, also known as Pythagoras' theorem, is a basic relationship between a right triangle's three sides in Euclidean geometry. According to this rule, the length of the squares on the other two sides add up to the length of the square whose side is the hypotenuse, or the side across from the right angle. This theory can be expressed as the Pythagorean equation, which is an equation relating the lengths of the sides a, b, and the hypotenuse c:

a² + b² =c²

The longest side of a right-angled triangle, or the side across from the right angle, is called the hypotenuse.

In the given right angled triangle, using Pythagorean theorem,

x² = (9[tex]\sqrt{2}[/tex] )²+ (9[tex]\sqrt{2}[/tex] )²

x² = 81×2

x = [tex]\sqrt{162}[/tex]

x = 12.73 units

Therefore, the value of x will be 12.73 units.

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The inequality to determine how much more money he needs to save so he can buy the shoes is x ≥ $45

Let x be the amount of money Jordan still needs to save to buy the shoes.

The total cost of the shoes is $75, and Jordan has already saved $30. Therefore, the amount of money he still needs to save is:

x = $75 - $30

Simplifying the right side:

x = $45

So, the inequality that represents how much more money Jordan needs to save is:

x ≥ $45

This means that Jordan needs to save at least $45 more to be able to buy the shoes.

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Answer:

To see why, we can compare the graphs of the two functions. The graph of ƒ(x) = e^x is an exponential function that starts at the point (0,1) and increases rapidly as x increases. The graph of g(x) = 5e^x is also an exponential function, but it starts at the point (0,5), which is five times higher than the starting point of ƒ(x). This means that g(x) is a vertical stretch of ƒ(x) by a factor of 5.

Option a) g(x) = e^x + 7 is a vertical shift of ƒ(x) by 7 units, but it does not represent a vertical stretch.

Option b) g(x) = 1/3e^x is a vertical compression of ƒ(x) by a factor of 1/3, rather than a vertical stretch.

Option d) g(x) = e^4x represents a horizontal stretch of ƒ(x) by a factor of 1/4, but it does not represent a vertical stretch.

The elimination of the equations 18x-6y=-20 and -9x+3y=15 is 0 = 10, which is a contradiction. This means that there is no solution to the system of equations.

What is an elimination?

To eliminate one of the variables, we need to manipulate one or both of the equations so that when we add them together, one of the variables is eliminated.

Let's start with the given equations:

18x - 6y = -20

-9x + 3y = 15

We can see that the coefficients of y in both equations are opposite, which means we can eliminate y by adding the two equations together. However, we need to make sure the coefficients of y have the same absolute value, so we'll multiply the second equation by 2:

18x - 6y = -20

-18x + 6y = 30

Now we can add the two equations together:

0x + 0y = 10

This equation simplifies to 0 = 10, which is a contradiction. This means that there is no solution to the system of equations. In other words, the two equations represent two parallel lines that never intersect.

Alternatively, we can recognize that the two equations represent the same line when simplified, since the second equation is simply half of the first equation. In this case, there are infinitely many solutions, since any point on the line satisfies both equations.

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Complete question is: The elimination of the equations 18x-6y=-20 and -9x+3y=15 is 0 = 10.

Therefore , the solution of the given problem of angles comes out to be m∠G= 63° is the response to the second component of the query.

The curved lines which make up the ends of a skew are divided by its highest and bottom walls using Cartesian measurements. There is a possibility who two poles will collide at an intersection. Another result of two objects interacting is an angle. They most closely mimic dihedral shapes. Two line beams can be arranged in different ways between their extremities to form a two-dimensional curve.

Here,

m∠E + m∠F + m∠G = 180°

Additionally, we are aware that mE = (5x + 6)°, mF = (4x - 6)°, and mG = (5x - 2)°. When we enter these numbers into the formula above, we obtain:

=> (5x + 6)° + (4x - 6)° + (5x - 2)° = 180°

When we simplify and find x, we obtain:

=> 14x - 2 = 180

=> 14x = 182

=> x = 13

Now that we know the three vectors' values:

=> m∠E = (5x + 6)° = (5(13) + 6)° = 71°

=> m∠F = (4x - 6)° = (4(13) - 6)° = 46°

=> m∠G = (5x - 2)° = (5(13) - 2)° = 63°

In light of this, mE = 71°, mF = 46°, and mG = 63°.

The first portion of the question has the following solution:

=>  m∠EFG = m∠E + m∠F + m∠G = 71° + 46° + 63° = 180°.

m∠G= 63° is the response to the second component of the query.

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The 90% confidence interval for the population proportion is (0.1171, 0.1829).

To calculate the confidence interval, we first need to find the point estimate of the population proportion. The point estimate is the sample proportion which is given by:

p-bar = x/n = 60/400 = 0.15

where x is the number of items that failed the test and n is the sample size.

Next, we need to find the margin of error, which is given by:

ME = z*√(p_bar(1-p_bar)/n)

where z is the z-score corresponding to the confidence level, p_bar is the sample proportion, and n is the sample size.

For a 90% confidence level, the z-score is 1.645 (using a standard normal distribution table). Substituting the values, we get:

ME = 1.645*√(0.15(1-0.15)/400) = 0.0329

Finally, we can construct the confidence interval by adding and subtracting the margin of error from the point estimate:

CI = p_bar ± ME = 0.15 ± 0.0329 = (0.1171, 0.1829)

Therefore, we are 90% confident that the true population proportion of items that will fail the test is between 0.1171 and 0.1829.

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Answer:

105

Step-by-step explanation:

10² is 100

100+5=105

From the given information provided, Laura can cut 3 one-thirds strips from the 1 meter long ribbon.

If Laura has a strip of ribbon 1 meter long, we need to find out how many one-thirds strips can be cut from it.

To do this, we need to divide the length of the ribbon by the length of each one-third strip:

Number of one-thirds strips = Length of ribbon / Length of one-third strip

The length of each one-third strip is 1/3 meters, since one-third of a meter is required to make each strip.

So we can substitute these values into the formula:

Number of one-thirds strips = 1 meter / (1/3 meter)

Number of one-thirds strips = 1 meter x (3/1)

Number of one-thirds strips = 3

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Max has approximately 111 friends on January 1st of the next year.

Given that Max has 30 friends on January 1st, the number of friends increases by 21% every month.

We need to find out how many friends Max has on January 1st of the next year,

which is 12 months later.

First, we will calculate the number of friends Max has after one month: 30 + (21% of 30) = 30 + 0.21*30 = 36So, after the first month, Max has 36 friends.

Now, we will calculate the number of friends Max has after two months: 36 + (21% of 36) = 36 + 0.21*36 = 43.56 ≈ 44So, after the second month, Max has 44 friends.

Similarly, we can calculate the number of friends Max has after 12 months:30 + (21% of 30) + (21% of 30) + ... (12 times)≈ 30 + 6.3 + 7.65 + ... (12 terms)≈ 111.1

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Yuri will spend $ X more on concrete than on soil and wood.

When answering questions on Brainly, it is important to be factually accurate, concise, and professional.

It is also important to provide a step-by-step explanation of how you arrived at your answer.

The question is asking about the cost of materials for a patio, garden, and deck.

Let's break down the information we have.

Area of the patio = enter your response

Here

Cost of concrete = $ enter your response

Here

Area of the garden = enter your response

here

Cost of soil = $ enter your response

here

Total area of the deck = enter your response

here

Cost of wood = $ enter your response

here

Yuri will spend $ enter your response here more on concrete than on soil and wood.

To find the cost of each material, we need to multiply the area by the cost per unit area.

For example, the cost of concrete would be the area of the patio multiplied by the cost of concrete per unit area.

Let's call the cost per unit area for concrete C, the cost per unit area for soil S, and the cost per unit area for wood W.

Area of patio = P

Cost of concrete = C

Area of garden = G

Cost of soil = S

Total area of deck = D

Cost of wood = W

Yuri will spend X more on concrete than on soil and wood.

To find the values of P, C, G, S, D, and W, we need to use the information given in the question.

However, some values are missing.

We can use the given information to create equations that will help us find these values.

For example, we know that the total area of the deck is the sum of the area of the patio and the area of the garden, so we can write:

D = P + G

Similarly, we can write an equation for the cost of each material.

For example, the cost of concrete is the area of the patio multiplied by the cost per unit area for concrete, so we can write:

C = P * C

Similarly, we can write equations for the cost of soil and wood:

S = G * W, W = D * W

Now we have three equations and three unknowns: P, G, and D. We can solve this system of equations to find these values.

Let's solve for P and G first.

We'll use the equation

D = P + G

to eliminate G from the equations.

C = P * CS = G * WP = D - G

Substitute P = D - G into the first two equations.

C = (D - G) * CW = D * W - G * W

Now we have two equations and two unknowns: D and G.

We can solve for these values.

We'll use the equation

W = D * W - G * W

to eliminate W from the equations.

C = (D - G) * CS = G * SD = P + G = 2G - (W / C)

Substitute D = P + G into the first two equations.

C = P * C + G * CS = G * SW = P + G - DC = P * C + (D - P) * C + (W / C) * C = 2P * C + W

We can now solve for P, G, and D.

P = (C + S + W / C) / 2G = (S + W / C) / 2D = P + G = (C + S + W / C) / 2 + (S + W / C) / 2P = enter your response

here

C = enter your response

here

S = enter your response

here

W = enter your response

here

G = enter your response

here

D = enter your response

here

Now we can find the value of X, which is the difference between the cost of concrete and the combined cost of soil and wood.

X = C - (S + W)X = enter your response.

The area of the patio is enter your response here ​, so the cost of concrete is ​$ enter your response here. The area of the garden is enter your response here ​, so the cost of soil is ​$ enter your response here. The total area of the deck is enter your response here ​, so the cost of wood is ​$ enter your response here.

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Question:

Yuri bought a new house. The diagram shows the layout of his backyard. Yuri is designing improvements that he wants to make. Yuri plans to fill the patio with concrete, the garden with a special soil mixture, and the remaining areas that surround the hot tub with a wood deck. The table shows the costs associated with each project. How much more will Yuri spend on concrete than on soil and wood?

The repair costs $90 for parts, plus $70 per hour for labor describes the situation. The solution has been obtained by using the equation.

What is an equation?

An equation is an assertion that two expressions containing variables and/or numbers are equivalent. The basic driving factors behind the growth of mathematics have been the attempts to rationally answer equations, which are essentially questions.

We are given an equation of the function as C(x) = 90 + 70x.

This depicts that $90 is fixed cost whereas $70 is variable cost and is dependent on the value of x.

So, the statement that describes the given situation is that the he repair costs $90 for parts, plus $70 per hour for labor.

Hence, the fourth option is the correct option.

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If an automobile manufacturer of a certain model of car wants to estimate the mileage this model car gets in highway driving. The manufacturer needs to sample at least 39 cars.

We can use the formula for the margin of error in a confidence interval for a mean:

Margin of Error = z* (σ/√n)

Where:

z* is the critical value of the standard normal distribution for the desired level of confidence, which is 90% in this case.

σ is the known population standard deviation, which is 5.7 mpg.

n is the sample size we want to determine.

We want the margin of error to be 1.5 mpg, so we can set up the equation:

1.5 = 1.645 * (5.7 / √n)

where 1.645 is the z-score for 90% confidence level.

Simplifying this equation, we get:

√n = 1.645 * (5.7 / 1.5)

√n = 6.251

Squaring both sides, we get:

n = 39.07

Rounding up to the nearest integer, we get:

n = 39

Therefore, the manufacturer needs to sample at least 39 cars to estimate the highway mileage with a 90% confidence interval and a margin of error of 1.5 mpg.

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This problem is a classic example of applying the stars and bars combinatorial method.

To solve this problem, we need to distribute 23 identical objects into 7 distinct containers so that none of the containers is empty. Let's start by assuming that each container has at least one object. This means we have distributed 7 objects, leaving 16 objects to be distributed.

We can now use the stars and bars method to distribute these 16 objects. Imagine placing all 16 objects in a line, and placing 6 dividers between them to separate them into 7 groups (one for each container). Each group will then receive the objects that are to the left of the divider.

For example, if we have the sequence OO|OOO|O|OOO|OO|OO|O, this corresponds to 2 objects in the first container, 3 objects in the second container, 1 object in the third container, and so on.

The number of ways to place the 6 dividers in the sequence of 16 objects is the same as the number of ways to choose 6 positions out of 16 to place the dividers. This can be computed using the formula for combinations:

$${16 \choose 6} = \frac{16!}{6!(16-6)!} = 8008$$

Therefore, there are 8008 ways to distribute 23 identical objects into 7 distinct containers so that no container is empty.

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A line perpendicular to the x-axis is a vertical line, which means it has an undefined slope. Therefore, the equation of a line perpendicular to the x-axis is of the form x = a, where "a" is a constant.

When it comes to the sale of products such as pet food, the veterinary practice is at an advantage over feed stores and grocery stores because they have better knowledge and understanding about the pet food, and they have established trust with their customers.

Pet food is a nutrient-rich food specially designed for domestic animals, like dogs, cats, and other pets. It is made from various animal and plant-based sources, such as beef, fish, and corn. Since pet food is designed to meet the nutritional needs of the pets, it must be balanced and complete to provide them with the necessary nutrients they need to be healthy and active.

Veterinarians are at an advantage over feed stores and grocery stores when it comes to the sale of pet food because they have the knowledge and expertise about the pet food. They are aware of the specific nutritional requirements of the pets and the various pet food brands available in the market. They can provide advice and recommendations to pet owners on what type of pet food is best suited for their pets based on their age, breed, and health conditions.

                             Moreover, veterinary practices have established trust with their customers. When customers know they can rely on a particular veterinary practice for quality products and trustworthy advice, they are more likely to shop there repeatedly.

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The angle that satisfies the necessary requirements is  1041° - 2(360°) = 321°. Coterminal angles are those with the same terminal point in the standard position.

To understand, follow the 2 basic steps:

Step 1: Find the specified angle.

Step 2: Finding a coterminal angle.

Tally up or tally down a multiple of 360.

θ = 1041°

Every multiple of 360 degrees added or subtracted results in an angle that is coterminal with the provided angle.

Hence, 1041° - 2(360°) = 321° is an angle that satisfies the necessary requirements.

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The number of license plates that can be made if repetition of letters and digits is allowed is:

67,600

Can be found by multiplying the number of possibilities for each position.

License plates are made using 2 letters followed by 2 digits. In this case, repetition is allowed, which means that each of the 2 letters can be any of the 26 letters of the English alphabet, and each of the 2 digits can be any of the 10 digits from 0 to 9. Thus, the total number of possible license plates can be found by multiplying the number of possibilities for each position.

There are 26 choices for each of the two letter positions, and 10 choices for each of the two digit positions, so the total number of possible license plates is:

26 x 26 x 10 x 10 = 67,600

Therefore, there are 67,600 plates that can be made if repetition of letters and digits is allowed.

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Answer:

remember, in order to calculate the weight on earth, we need to multiply the mass of the object with the force of Gravity (9.8 m/s^2 on earth)

so, her weight would be:

48 x 9.8 = 470.4 >>>>>>> Will be 470 if we round it to the nearest whole number.

Step-by-step explanation: Hope this helps. Mark me brainliest!! :)))

Answer: 470

Step-by-step explanation:

Answer:

[tex]26a - 10 = 2(13a - 5)[/tex]

[tex]~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$ 850\\ P=\textit{original amount deposited}\dotfill & \$500\\ r=rate\to 10\%\to \frac{10}{100}\dotfill &0.10\\ t=years \end{cases} \\\\\\ 850 = 500[1+(0.1)(t)] \implies \cfrac{850}{500}=1+0.10t\implies \cfrac{17}{10}=1+0.10t \\\\\\ \cfrac{17}{10}-1=0.10t\implies \cfrac{7}{10}=0.10t\implies \cfrac{7}{(10)(0.10)}=t\implies 7=t[/tex]

Answer:

Step-by-step explanation:

Okay so you've gotta start with the y-intersect. The line hits the y-axis at 7, so your B is 7 (y=mx+7).

Since the line is going down, it's a negative slope, so your m will be a negative (y=-mx+7)

The line matches up exactly with (1,4), which shows the line moving down 3 for every 1 movement to the right. That makes your equation for the line y=-3x+7 or y=-3/1x+7

a) The probability that during next second the number of alpha particales omitted from 1 gram is at most 6 is 0.998.

b) The probability that during next second the number of alpha particales omitted from 1 gram is at least 2 is 0.985.

c) The probability that during next second the number of alpha particales omitted from 1 gram is at least 3 and at most 6 is 0.679.

This problem is an application of the Poisson distribution, which is commonly used to model the number of events occurring in a fixed interval of time. In this case, we are interested in the number of alpha particles emitted by 1 gram of the radioactive element in one second.

The average rate of emission is given as 3.9 alpha particles per second. This means that the mean or expected number of alpha particles emitted by 1 gram of the element in one second is also 3.9.

(a) To find the probability that at most 6 alpha particles are emitted from 1 gram of the element in one second, we can use the Poisson distribution with λ=3.9 and x=0, 1, 2, 3, 4, 5, or 6.

The probability is given by the cumulative distribution function (CDF) of the Poisson distribution, which can be calculated using software or a table. For example, using a Poisson table or calculator, the probability is approximately 0.998.

(b) To find the probability that at least 2 alpha particles are emitted, we can use the complementary probability: P(at least 2) = 1 - P(none or 1). Using the Poisson distribution with λ=3.9 and x=0 or 1, we find P(none or 1) = 0.015. Therefore, P(at least 2) = 1 - 0.015 = 0.985.

(c) To find the probability that at least 3 and at most 6 alpha particles are emitted, we need to add the probabilities for x=3, 4, 5, and 6. Using the Poisson distribution with λ=3.9, we can calculate P(x=3) = 0.089, P(x=4) = 0.172, P(x=5) = 0.212, and P(x=6) = 0.206. Therefore, the probability is approximately 0.679.

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Answer:

[tex]\frac{25}{11}[/tex]

Step-by-step explanation:

an improper fraction is one where the value on the numerator is larger than the value on the denominator.

2 [tex]\frac{3}{11}[/tex] is a mixed number, that is a whole number and a fraction

this can be converted to an improper fraction by summing the 2 parts , that is the whole number and the proper fraction as

2 + [tex]\frac{3}{11}[/tex]

= [tex]\frac{22}{11}[/tex] + [tex]\frac{3}{11}[/tex]

= [tex]\frac{22+3}{11}[/tex]

= [tex]\frac{25}{11}[/tex]

or

multiplying the whole number by 11 and adding 3 , over 11

[tex]\frac{2(11)+3}{11}[/tex]

= [tex]\frac{22+3}{11}[/tex]

= [tex]\frac{25}{11}[/tex]

Answer: Rectangular prism & Cylinder

Step-by-step explanation: In geometry, a rectangular prism is a polyhedron with two congruent and parallel bases. It is also called a cuboid. A rectangular prism has six faces, and all the faces are in a rectangle shape and have twelve edges. Because of its cross-section along the length, it is said to be a prism.

A cylinder is a three-dimensional shape consisting of two parallel circular bases, joined by a curved surface. The center of the circular bases overlaps each other to form a right cylinder. The line segment joining the two centers is the axis, that denotes the height of the cylinder.

Rounded to two decimal places, the value of the test statistic is 0.41.

The value of the test statistic to compare the publisher's reported percentage of 75% and the marketing executive's claim that the actual percentage is different can be found by using the formula z = (p1 - p2)/(sqrt[p*(1-p)*((1/n1)+(1/n2))]), where p is the pooled proportion, p1 is the proportion of the publisher's readers owning the particular make of car, p2 is the proportion of the random sample owning the particular make of car, n1 is the total number of the publisher's readers, and n2 is the total number of the random sample.

In this case, p = [tex](75% + 69%)/2 = 72%, p1 = 75%, p2 = 69%, n1[/tex]is unknown, n2 = 250. Thus, the test statistic is z =[tex](75%-69%)/(sqrt[72%(1-72%)((1/n1)+(1/250))]) = 0.41.[/tex]

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A female student's probability of not receiving an A is 0.56, or 56%.

Probability and probability, as well as its cognates in various modern languages, come from the educated Latin of the Middle Ages called probabilis, which Cicero used to refer to a viewpoint as being plausible or generally accepted. Ancient French probabilite is where the word probability came from (14 c.)

We must utilise the data in the table to determine the likelihood that a female student will not receive an A.

There are 16 male students and 9 female students in the class, according to the table. Of the nine female students, four received As compared to five Bs.

Hence, the The likelihood that a female student won't receive an A is: P (Female student does not have an A) = Total number of female students / Number of female students without an A

P

Female student does not have an A (Female student does not have an A) = 5/9 P(Female student does not have an A) = 0.56 or 56%.

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The width of the rectangular garden is 9.5 feet.

Given that the perimeter of a rectangular garden is 43.8 feet and its length is 12.4 feet.

Let's assume the width of the rectangular garden be "w".

Now we need to find the width of the garden.

Solution: Perimeter of a rectangular garden is given by the formula: P = 2(l + w)

where l = length and w = width.

Substituting the given values in the above formula,

we get43.8 = 2(12.4 + w)

We can solve for "w" by simplifying the above equation.

43.8 = 24.8 + 2w43.8 - 24.8 = 2w19 = 2w

Dividing both sides by 2,we get

w = 9.5 feet.

Therefore, the width of the rectangular garden is 9.5 feet.

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An expression for the number of amoebas after 24 hours is 1 × 2²⁴ = 16,777,216

Single-celled creatures knοwn as amοebas reprοduce asexually. An amοeba begins tο reprοduce when its genetic material dοubles, twο nuclei are fοrmed, and it begins tο alter shape by develοping a thin "waist" in the centre. Typically, this prοcedure gοes οn until the cells are finally divided intο twο.

Amοeba reprοduce typically asexually thrοugh a prοcess called binary fissiοn. The cell splits intο twο daughter cells οf equal size fοllοwing the replicatiοn οf its genetic material by mitοtic divisiοn.

a. It is given that an amοeba divides tο fοrm twο amοebas after οne hοur sο there are 2 amοebas after 1 hοur.

b. It is given that οne hοur later, each οf the twο amοebas divides tο fοrm twο mοre amοebas sο there are 2×2=4 amοebas after 2 hοurs.

c. The number οf amοebas is dοubling after each hοur since each amοeba divides intο twο amοebas every hοur. This means that the number οf amοebas after 6 hοurs can be fοund by multiplying the οriginal number οf amοebas, which was 1, by 2 six times. The number οf amοebas after 6 hοurs is then 1 × 2⁶ = 2⁶= 64 amοebas.

d. Using the same pattern frοm part (c), the number οf amοebas after 24 hοurs is 1 × 2²⁴ = 2²⁴ = 16,777,216 amοebas.

Expression = 1 × 2²⁴ = 16,777,216

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