spotlight on a boat is 2.5 m above the water, and the light strikes the water at a point that is 8.0 m horizontally displaced from the spotlight (see the drawing). The depth of the water is 4.0 m. Determine the distance d, which locates the point where the light strikes the bottom. Assume water has a refraction index of 1.333
Answer:
Explanation:
Let i be the angle of incidence and r be the angle of refraction .
From the figure
Tan ( 90 - i ) = 2.5 / 8
cot i = 2.5 / 8
Tan i = 8 / 2.5 = 3.2
i = 72.65°
From snell's law
sini / sin r = refractive index
sin 72.65 / sinr = 1.333
sin r = .9545 / 1.333
= .72
r = 46⁰
From the figure
Tan r = d / 4
Tan 46 = d /4
d = 4 x Tan 46
= 4 x 1.0355
=4.14 m .
which term describes the process of transferring charge without the direct contact
What nuclear reaction is shown in the equation below?
Answer:
nuclear fission!!!
The nuclear fission is taken place in the given reaction.
What is nuclear fission and how it was related to the given equation?Nuclear fission reaction is the process how the larger energy particles hit by a neutron and separated into lighter elements with some energy. The lighter elements can exhibit energy in the form of electromagnetic radiation and in the form of kinetic energy.
For an example, the most known nucleus is Uranium - 235. This Uranium - 235 has the half life period of 740 million years. The Uranium - 235 when bombarded with neutrons, this causes the U-235 nucleus to split, producing, on average, Barium-141, Krypton-91, and three neutrons.
The given reaction is thus a nuclear fission reaction.
Thus, Option A is the correct answer.
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A wave has a frequency of 6 Hz and a speed of 30 m/s. What is the wavelength of the wave?
a) 180 m
b) 0.2 m
c) 36 m
d) 5 m
Answer:
D. 5m
Explanation:
fλ = c, where f is frequency, λ is wavelength and c is speed.
6λ=30
λ=30/6=5
Who discovered the laws of planter motion ?
Answer: Johannes Kepler
Explanation:
Kepler discovered that Mars' orbit was an ellipsoid using the exact data that Tycho had obtained.
State the
the properties of magnets.
Answer:
All magnets have two poles: the North Pole and the South Pole.
Magnets attract ferromagnetic materials such as iron, nickel, and cobalt.
The magnetic force of a magnet is stronger at its poles than in the middle.
A freely suspended magnet always points in North-South direction.
Hope this helps
im back and need help
Always here to help. Bring it!!!
Newton's theory of gravitation allows people to successfully predict when and where an eclipse may be observed.
a. True
b. False
Answer:
A. True, I think
Explanation:
A radio antenna broadcasts a 1.0 MHz radio wave with 20.0 kW of power. Assume that the radiation is emitted uniformly in all directions.
1) What is the wave's intensity 30 km from the antenna
2) What is the electric field amplitude at this distance?
Answer:
1) [tex]I=1.8*10^{-6}\: W/m^{2}[/tex]
2) [tex]E=0.037 \: V/m[/tex]
Explanation:
1)
The intensity equation is given by:
[tex]I=\frac{P}{4\pi r^{2}}[/tex]
Where:
P is the power of the radio waver is the distance from the source[tex]I=\frac{20000}{4\pi (30000)^{2}}[/tex]
[tex]I=1.8*10^{-6}\: W/m^{2}[/tex]
2)
Now, the intensity and the electric field are related as:
[tex] I=0.5c\epsilon_{0}E^{2}[/tex]
Here:
c is the speed of lightε₀ is the electric permittivityE is the electric fieldWe need to solve it for E.
[tex]E= \sqrt{\frac{2I}{c\epsilon_{0}}}[/tex]
[tex]E= \sqrt{\frac{2(1.8*10^{-6})}{(3*10^{8})(8.85*10^{-12})}}[/tex]
[tex]E=0.037 \: V/m[/tex]
I hope it helps you!
Which has a greater momentum: a 0.0010 kg bullet going
250 m/s OR a 80 kg student walking at 4 m/s? Which has
more inertia? Which has more kinetic energy?
Answer:
Momentum is Mass x Velocity.
Its pretty obvious that the 80kg student Moving at 4ms-¹ has more momentum.
80x4 = 320kgms-1
0.001x250= 0.25kgms-¹
The Second student also Has More Inertia. Inertia is the resistance to motion offered by a Body. An Object with greater mass has more tendency to resist Motion .
So
The 80Kg student wins all.
Answer:
i think it is 80 kg
Explanation:
if a box experiences three 400 n forces to the left and three different 410 n forces to the right which way does it go
Answer:
Explanation:
will accelerate to the right, because three different 410 N is greater than three different 400 N
The proper time between two events is measured by clocks at rest in a reference frame in which the two events: The proper time between two events is measured by clocks at rest in a reference frame in which the two events:
a. are separated by the distance a light signal can travel during the time interval
b. occur at the same time
c. satisfy none of the above
d. occur in Nashville occur at the same coordinates
The proper time between two events is measured by clocks at rest in a reference frame in which the two events occur in Nashville occur at the same coordinates. So, option d.
What is meant by frame of reference ?The perspective from which you perceive and measure things is known as a reference frame. It's applied to describe how an object is moving or where it is.
Here,
Depending on the frame of reference, the time elapsed between two occurrences may vary, according to the Theory of Special Relativity.
The duration between two events occurring in the rest frame, as measured from a reference frame in motion relative to the rest frame, will always be longer than the correct time. Time dilation is a phenomenon that develops in accordance with the relativity of space and time.
A single clock that is present for both occurrences can be used to determine the right time difference between them.
The appropriate time between two events is the amount of time that elapses within a frame in which the two events take place at the same location, to put it another way.
Hence,
The proper time between two events is measured by clocks at rest in a reference frame in which the two events occur in Nashville occur at the same coordinates. So, option d.
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Two parallel plates are charged
with 3.08*10^-9 C of charge.
What must the area of the plates
be to create an electric field of
9220 N/C?
(Unit = m^2)
Answer:
0.0377
Explanation:
Trust brother
Answer:
0.0377
Explanation:
At a soft drink bottling plant, a horizontal section of pipe carrying citric acid in liquid form goes from a cross-sectional area of 8.00 cm2, fluid flow speed of 320 cm/s, and pressure of 1.40 105 Pa to a section of pipe with a cross-sectional area of 3.70 cm2. The density of the citric acid is 1660 kg/m3. For the section of smaller pipe, determine the liquid flow speed and the liquid pressure.
(a) the liquid flow speed m/s
(b) the liquid pressure Pa
Answer:
a) [tex]V_2=8m/s[/tex]
b) [tex]P_2=9.54*10^4 Pa[/tex]
Explanation
From the question we are told that:
Initial Area of pipe [tex]A_1=8.00 cm^2[/tex]
Initial Fluid flow speed [tex]r_1 =320 cm/s,\approx 320*10^{-2}[/tex]
Initial Pressure of [tex]\rho_1 =1.40*10^5 Pa[/tex]
Final area of pipe [tex]A_2 =3.70 *10^{-2} cm^2[/tex]
Density of acid [tex]\rho=1660kg/m^3[/tex]
a)
Generally the equation for continuity is mathematically given by
[tex]A_1V_1=A_2V_2\\\\V_2=\frac{A_1*V_1}{A_2}[/tex]
Since volume is directly proportional to rate of flow
[tex]V_2=\frac{8*320}{3.20} *10^{-2}[/tex]
[tex]V_2=8m/s[/tex]
b)
Generally the Bernoulli's equation is mathematically given by
[tex]p_1+\frac{1}{2}\rho v_1^2+\rho gh_1=P_2+\frac{1}{2}\rho v_2^2+\rho gh_2\\\\with\ h_1=h_2\\\\p_1+\frac{1}{2}\rho v_1^2=P_2+\frac{1}{2}\rho v_2^2[/tex]
Therefore
[tex]P_2=P_1+\frac{1}{2}\rho(v_1^2-V_2^2)\\\\P_2=(1.40*10^5)+\frac{1}{2}(1660)(v_1^2-V_2^2)[/tex]
[tex]P_2=9.54*10^4 Pa[/tex]
The left end of a long glass rod 9.00 cmcm in diameter, with an index of refraction 1.55, is ground and polished to a convex hemispherical surface with a radius of 4.50 cmcm. An object in the form of an arrow 1.52 mmmm tall, at right angles to the axis of the rod, is located on the axis 25.0 cmcm to the left of the vertex of the convex surface.
A) Find the position of the image of the arrow formed by paraxial rays incident on the convex surface. (answer is s1 in units cm)
B) Find the height of the image formed by paraxial rays incident on the convex surface. (answer is y1 in units mm)
C) Is the image erect or inverted?
I have tried solving this problem multiple ways and even referred to previous answers, but nothing seems to work. I will rate lifesaver for anyone who shows a correct explanation of how to solve and approach this problem. I greatly appreciate any help you can provide!
Answer:
A) s' = 18.85 cm
B) Height is 0.739 mm
C) the image is inverted.
Explanation:
We are given;
Diameter; D = 9 cm
Radius; R = d/2 = 9/2 = 4.5 cm = 0.045 m
Refractive Index of glass; n₂= 1.55
Height of object; y = 1.52 mm = 0.00152 m
Object distance s = 25 cm = 0.25 m
Now, Refractive index of air is 1 from online values.
Thus; n_1 = 1
A) To find the position of the image of the arrow formed by paraxial rays incident on the convex surface which is denoted by s', we will use the formula;
((n_1)/s) + n₂/s' = (n₂ - n_1)/R
Plugging in the relevant values, we have;
(1/0.25) + 1.55/s' = (1.55 - 1)/0.045
(1/0.25) + 1.55/s' = 12.222
1.55/s' = 12.222 - (1/0.25)
1.55/s' = 12.222 - 4
1.55/s' = 8.222
s' = 1.55/8.222
s' = 0.1885 m
s' = 18.85 cm
B) We will use the magnification formula to calculate the height of the image formed by paraxial rays incident on the convex surface denoted by y';
m = y'/y = -n_1•s'/n_2•s
Thus;
y' = -(y × n_1 × s')/(n_2•s)
y' = -(0.1885 × 1 × 0.00152)/(1.55 × 0.25)
y' = -0.739 mm
Height is 0.739 mm inverted.
C) Since the height of y' is negative, then it means the image is inverted.
A car with a mass of 800 g and velocity of 15 m/s collided with a truck of a velocity of 20 m/s, if the momentum is conserved what is the mass of the truck?
Question: A car with a mass of 800 g and velocity of 15 m/s collided with a truck moving in opposite direction with a velocity of 20 m/s, if the momentum is conserved and they both move with a common velocity of 10 m/s, what is the mass of the truck?
Answer:
0.133 kg
Explanation:
Applying the law of conservation of momentum,
Total momentum before collision = Total momentum after collision
mu+m'u' = V(m+m')................... Equation 1
Where m = mass of the car, m' = mass of the truck, u = initial velocity of the car, u' = initial velocity of the truck, V = common velocity.
From the question,
Given: m = 800 g = 0.8 kg, u = 15 m/s, u' = -20 m/s, V = 10 m/s
Substitute these values into equation 2
(0.8*15)+(m'*20) = 10(0.8+m')
Solve for m'
12-20m' = 8+10m'
-20m'-10m' = 8-12
-30m' = -4
m' = -4/-30
m' = 0.133 kg
Consider a linear harmonic oscillator and let, yo and y, be its real, normalized ground and first
excited state energy eigenfunctions respectively. Let Ayo + Byi with A and B real numbers be the
wave function of the oscillator at some instant of time. Show that the average value of x is in
different from zero. What values of A and B maximize (x) and what values minimize it?
general
A Boy can raise a load of 200N up to a
height of 2.5m in 15 seconds. calculate his
power
Explanation:
f=mg
=200×10
=200N
Now,
work done=df
25×200
=500J
Solid pressure depends on?
Answer:
The pressure of the solid on the surface depends on the area of contact. The area of contact between the two surfaces. The greater the force or the smaller the area the greater the pressure.
(credits to the rightful owner for these answers :)
A 10.0kg ball is falls from a window 7.00m above the ground. What will be the velocity of the ball as it strikes the ground?
Answer:
Explanation:
To find out something's speed (or velocity) after a certain amount of time, you just multiply the acceleration of gravity by the amount of time since it was let go of. So you get: velocity = -9.81 m/s^2 * time, or V = gt.22
The gravity of Earth is attracting a person towards the center with 500N of gravitational force. The person is exerting a reactionary force on the Earth with how much force?
Answer:
The force is being pulled my the gravity or it could be a third party thing like a black hole you feel me
Explanation:
A hydraulic system is lifting a 11760 N car using a cylinder with an area of 0.25 m
squared. What force is applied to the small cylinder if it has an area of 0.0125 m
squared?
Answer: 588 N
Explanation: pressure = force/area, or p = F/A. Then p1=p2
And F1//A1 = F2/A2 . F2 = F1·A2/A1 = 11760 N·0.0125 m²/ 0.25 m²
Approximately how big did the cores of the jovian planets become before they could accrete gas directly from the protosolar nebula?
1,000 Earth masses
10 Earth masses
1 Earth mass
100 Earth masses
[tex]\huge{\textbf{\textsf{{\color{navy}{An}}{\purple{sw}}{\pink{er}} {\color{pink}{:}}}}}[/tex]
100 Earth masses.
thanks hope it helpsI hope it's correctParticle A has less mass than particle B. Both are pushed forward across a frictionless surface by equals forces for 1 s. Both start from rest.
a. Compare the amount of work done on each particle. That is, is the work done on A greater thane, less than, or equal to the work done on B? Explain.
b. Compare the impulses delivered to particles A and B. Explain.
c. Compare the final speeds of particles A and B. Explain.
An Particle a has Weston practical.
What is Friction?
The resistance to motion of one object moving in relation to another is known as friction. It is not regarded as a fundamental force like gravity or electromagnetic, according to the International Journal of Parallel, Emergent and Distributed Systems(opens in new tab).
According to the book Soil Mechanics(opens in new tab), scientists started putting together the laws governing friction in the 1400s.
However, because the interactions are so complex, characterizing the force of friction in various circumstances typically requires experiments and can't be derived from equations or laws alone. There are numerous exceptions to every frictional general rule.
Therefore, An Particle a has Weston practical.
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One way to provide artificial gravity (i.e., a feeling of weight) on long space voyages is to separate a spacecraft into two parts at the ends of a long cable, and set them rotating around each other. A craft has been separated into two parts with a mass of 70600 kg each, at the ends of a cable with their centers of mass 155 m apart, rotating around the center point of the cable with a period of 385.3 seconds.
1) If the cable is reeled in so that the the centers of the two pieces are now only 119.35 m apart, what will the new period be?
2) What happens to the angular momentum L and kinetic energy K of the system consisting of both pieces of the space ship when the two pieces are pulled closer to the center?
Answer:
1) T = 649.86 s, 2) L₀ = L_f, [tex]\frac{K_o}{K_f}[/tex] = 4.8
Explanation:
1) As the system of the two bodies is isolated, its angular momentum is conserved
initial instant. r₀ = 155 m, T₀= 385.3 s
L₀ = I₀ w₀
final instant. r = 119.35 m
L_f = I w
L₀ = L_f
I₀ w₀ = I w
w = [tex]\frac{I_o}{I} \ w_o[/tex]
let's consider each object as punctual
I = m r²
at angle velocity and period are related
w = 2pi / T
we substitute
[tex]\frac{2\pi }{T} = \frac{m r^2}{m _o^2 } \ \frac{2\pi }{T_o}[/tex]
[tex]\frac{1}{T} = ( \frac{r}{r_o} )^2 \ \frac{1}{T_o}[/tex]
T = [tex](\frac{r_o}{r} )^2 \ T_o[/tex]
let's calculate
T = [tex]( \frac{155}{119.35} )^2 \ 385.3[/tex]
T = 649.86 s
2) The angular momentum is conserved because the system is isolated.
Let's look for kinetic energy
K_total = 2 K = 2 (½ I w²)
K_total = I 4π² / T²
K_total = 2m r² 4 π² / T²
for r = 155 m
K₀ = 8π² m r₀² / T₀²
for r = 119.35 m
K_f = 8π² m r² / T²
the relationship is
[tex]\frac{K_o}{K_f} = ( \frac{r_o \ T}{ r \ \ T_o} )^2[/tex]
[tex]\frac{K_o}{K} = ( \frac{ 155 \ \ \ 649.86}{ 119.35 \ 385.3})^2[/tex]
[tex]\frac{K_o}{K_f}[/tex] = 4.8
A soccer player with a mass of 80.0 kg kicks a ball by applying a 20.0 N force. What force does the ball exert on the player?
A. 160. N
C. 2.50 N
B. 0.400 N
D. 20.0N
Answer:
F = 160.0 N
Explanation:
Given: Soccer payer with a mass = 80 kg, force = 20 N
To find: force
Formula: [tex]F=ma[/tex]
Solution: It is summarized by the equation: Force (N) = mass (kg) × acceleration (m/s²). Thus, an object of constant mass accelerates in proportion to the force applied.
F = m × a
F = 20 kg - 10 = 2
F = 80 × 2 = 160
F = 160.0 N
Newtons are derived units, equal to 1 kg-m/s². In other words, a single Newton is equal to the force needed to accelerate one kilogram one meter per second squared.
name the basic principle on which generators work.
electromagnetic induction?
Four point masses are connected by rods of negligible mass and form a square with sides of length 32.2 cm. Three of the masses are 1.5 kg and one is 3.0 kg. How far from the 3.0 kg mass is the center of mass of the system
Solution :
Placing the[tex]$3 \ kg$[/tex] mass at the [tex]$\text{origin}$[/tex] and line up the square up with the axes.
[tex]$x_{cm} = \frac{\sum_i x_i m_i}{\sum_i m_i }$[/tex]
[tex]$=\frac{1.5 a + 1.5a +0 +0}{7.5}$[/tex]
[tex]$=\frac{3a}{7.5}$[/tex]
[tex]$=\frac{2a}{5}$[/tex]
[tex]$y_{cm} = \frac{\sum_i y_i m_i}{\sum_i m_i }$[/tex]
[tex]$=\frac{1.5 a + 1.5a +0 +0}{7.5}$[/tex]
[tex]$=\frac{3a}{7.5}$[/tex]
[tex]$=\frac{2a}{5}$[/tex]
Therefore, r = [tex]$\sqrt2 \left(\frac{2a}{5}\right)$[/tex]
[tex]$=\frac{2 \sqrt2}{5}a$[/tex]
It s given that the side of the square is a = 32.2 cm
So, r [tex]$=\frac{2 \sqrt2}{5}a$[/tex]
[tex]$=\frac{2 \sqrt2}{5}\times 32.2$[/tex]
= 18.21 cm
So the distance of the 3 kg mass from the center of mass, r= 18.21 cm
8. Aunt Barbara sets a full 2.0 kg milk carton on the kitchen table for breakfast. After the family has eaten, she pours herself a cup of coffee, sits down, and picks up the milk carton, only to find that the 20 N force she exerts accelerates the carton upward at a surprising 50 m/s². Calculate and describe why the milk carton accelerates up faster than Aunt Barbara expect
We know that the frequency and wavelength of an oscillation are related by the velocity of the wave . In standing waves, the wave velocities of the different harmonics are the same.Think about why this may be and explain that in your notebook. (Hint: The wave velocity is dependent on the static properties of the oscillating object like mass per unit length and tension)
Answer
the medium does not change the speed of the on they should change.
Explanation:
The speed of the waves is constant for a given medium, depending on the physical properties of the medium,
When a wave is strapped on a wall of a medium it does not change the properties of the medium, the wave changes direction, but since the medium does not change the speed of the on they should change.