From a cross between a short-haired guinea pig (hh) and a long-haired guinea pig (Hh), what would be the possible phenotypes of the offspring?
A. 100% will have long hair.
OB. 75% will have long hair; 25% will have short hair.
OC. 50% will have long hair; 50% will have short hair.
O D. 25% will have long hair; 75% will have short hair.

Unnillium (101)

Unnilbium (102)

Unniltrium (103)

Unnilquadium (104)

Unnilpentium (105)

Unnilhexium (106)

Unnilseptium (107)

Unniloctium (108)

Unnilennium (109)

Ununnillium (110)

Answer:

What about it? I don't get the question

Answer:

Sample A

Explanation:

Molarity of a solution can be calculated using the formula:

Molarity = number of moles (mol) ÷ volume (vol)

For Sample A:

V = 300ml = 300/1000 = 0.3 L

Molarity = 1M

n = number of moles (mol)

1 = n/0.3

n = 0.3moles

For Sample B:

V = 145 mL = 145/1000 = 0.145L

Molarity = 1.5 M

n = number of moles

1.5 = n/0.145

n = 1.5 × 0.145

n = 0.22 moles

Based on the above results (moles), sample A with 0.3 moles contains the larger concentration of sodium chloride.

Answer:

0.60 moles of atoms of carbon

Explanation:

Step 1: Given data

Step 2: Calculate the number of carbon atoms in the given sample

According to the chemical formula of the compound, the molar ratio of C to O is 2:6, that is, there are 2 moles of atoms of C every 6 moles of atoms of O. The number of moles of atoms of C is:

1.8 mol O × 2 mol C / 6 mol O = 0.60 mol C

Answer:

A

Explanation:

Hydrogen isn't an alkali metal

Answer:

hydrogen

Explanation:

hydrogen is a gas not a metal

Wilma- tt

Wilbur- TT

c) 100% chance

d) 100% chance

it has been a while since I've done this so it could be wrong but im pretty sure its correct

Wilbur's family claims it is pure so they have TT

and his wife simply has big eyes so its tt

so the chances of their children having either eye shape is 100%

I'm sorry- im not too good at explaining it ><

Answer:

I had the answer

Explanation:

Moles to particles Now suppose you want to determine how many particles of sucrose are ... Driving Question Board Have students revisit the DQB to remind themselves of the Unit and Module questions.

Answer:

14.93 g

Explanation:

First we convert 1.2 x 10²³ atoms of arsenic (As) into moles, using Avogadro's number:

Then we can calculate the mass of 0.199 moles of arsenic, using its molar mass:

Thus, 1.2x10²³ atoms of arsenic weigh 14.93 grams.

Answer:

C

Explanation:

1atm=760torr

X=250torr

Cross multiply

760torrX=250torr*atm

Divide both sides by 760torr

X=250torr*atm/760torr

X=0.32895atm

X=0.329atm

Option C is collect

Answer:

3.84 J/g°C

Explanation:

Using the formula as follows:

Q = m × c × ∆T

Where;

Q = amount of heat (J)

m = mass of substance

c = specific heat of copper

∆T = change in temperature (°C).

Based on the provided information;

Q = 43783J

m = 24g

∆T = 500°C - 25°C = 475°C

c = ?

Using Q = m × c × ∆T

43783 = 24 × c × 475

43783 = 11400c

c = 43783 ÷ 11400

c = 3.84 J/g°C

Answer:

20 moles of Iron are needed

Explanation:

In 1 mole of Iron (III) oxide, Fe₂O₃, there are 2 moles of Iron, Fe. The equation that we can write is:

2 moles Fe = 1 mole Fe₂O₃

To find the moles of iron that are needed to produce 10 moles of Fe₂O₃ we must use this equation as follows:

10 moles of Fe₂O₃ * (2 moles Fe / 1mole Fe₂O₃) =

Answer:

its e

Explanation:

Answer:

[Ba²⁺] = 1.58 × 10⁻³ M

[Cl⁻] = 3.16 × 10⁻³ M.

Explanation:

Step 1: Calculate the molar concentration of BaCl₂

We have 3.50 mL (V₁) of a 0.00450 M (C₁) BaCl₂ solution and we dilute it to a final volume of 10.00 mL (V₂). We can calculate the final concentration of BaCl₂ by using the dilution rule.

C₁ × V₁ = C₂ × V₂

C₂ = C₁ × V₁ / V₂

C₂ = 0.00450 M × 3.50 mL / 10.00 mL = 1.58 × 10⁻³ M

Step 2: Calculate the molar concentrations of the Ba²⁺ and Cl⁻ ions

Let's consider the dissociation of BaCl₂.

BaCl₂(aq) ⇒ Ba²⁺(aq) + 2 Cl⁻(aq)

The molar ratio of BaCl₂ to Ba²⁺ is 1:1. The molar concentration of Ba²⁺ is 1/1 × 1.58 × 10⁻³ M = 1.58 × 10⁻³ M.

The molar ratio of BaCl₂ to Cl⁻ is 1:2. The molar concentration of Cl⁻ is 2/1 × 1.58 × 10⁻³ M = 3.16 × 10⁻³ M.

Answer:

Sample B

Explanation:

In this case, we need to determine the empirical formula for each sample. The one that match the formula of the propene would be the sample.

Let's do Sample A:

C: 60 g;       H: 12 g

1. Calculate moles:

We need the atomic weights of carbon (12 g/mol) and hydrogen (1 g/mol):

C: 60 / 12 = 5

H: 12 / 1 = 12

2. Determine number of atoms in the formula

In this case, we just divide the lowest moles obtained in the previous part, by all the moles:

C: 5 / 5 = 1

H: 12 / 5 = 2.4    or rounded to two

3. Write the empirical formula:

Now, the prior results, represent the number of atoms in the empirical formula for each element, so, we put them with the symbol and the atoms as subscripted:

C₁H₂ = CH₂

Therefore, sample A is not the same as propene.

Sample B:

C: 72 g    H: 12 g

Following the same steps, let's determine the empirical formula for this sample

C: 72 / 12 = 6 ---> 6 / 6 = 1

H: 12 / 1 = 12 ----> 12 / 6 = 2

EF: CH₂

Sample C:

C: 84 g    H: 10 g

C: 84 / 12 = 7 ----> 7 / 7 = 1

H: 10 / 1 = 10    ----> 10 / 7 = 1.4 or just 1

EF: CH

Sample D

C: 90 g      H: 10 g

C: 90 / 12 = 7.5     -----> 7.5 / 7.5 = 1

H: 10 / 1 = 10  -------> 10 / 7.5 = 1.33 or just 1

EF: CH

Neither compound has the same empirical formula as C3H6, but C3H6 is a molecular formula, so, if we just simplify the formula we have:

C3H6  -----> CH₂

Therefore, sample B is the one that match completely. Sample B would be the one.

Hope this helps

Answer:

The answer is "Option 2".

Explanation:

Answer:

Explanation:

The density is  

1.1 g c m 3 .

Answer: When exhaust from car engines spreads throughout our atmosphere and adds to pollution then it is an example of increase in entropy.

Explanation:

A degree of randomness in the molecules of a substance is called entropy.

When exhaust from car engines spreads throughout our atmosphere then it means the molecules are moving at a faster speed due to which they spread into the atmosphere rapidly.

This means that the entropy of exhaust is increasing.

Thus, we can conclude that when exhaust from car engines spreads throughout our atmosphere and adds to pollution then it is an example of increase in entropy.

An increase in entropy

Answer: The event air molecules that are surrounding the metal will speed up, and the molecules in the metal will slow down would most likely take place over the next few minutes.

Explanation:

A process in which heat is evolved is called an exothermic process.

When hot metal plate at [tex]150^{o}C[/tex] is placed in air at room temperature then heat is given off by the metal plate due to which there will occur a decrease in kinetic energy of its molecules.

As a result, molecules in the metal will slow down.

Whereas heat is absorbed by the air molecules from the metal due to which kinetic energy of air molecules will increase.

Thus, we can conclude that the event air molecules that are surrounding the metal will speed up, and the molecules in the metal will slow down would most likely take place over the next few minutes.

Answer:

200.0lg

Explanation:

please give a brainliest

Answer:

3 NaOH (aq) + H3PO4 (aq) → Na3PO4 (aq) + 3 H2O (l)

Explanation:

This is an acid-base reaction (neutralization): NaOH is a base, H3PO4 is an acid.

When the equation is balanced, and the coefficient of H₂O is 3.

To balance the chemical equation:

NaOH + H₃PO₄ ⇒ Na₃PO₄ + H₂O

The number of atoms of each element is the same on both sides of the equation.

Balance the hydrogen atoms. There are three hydrogen atoms on the left side and two hydrogen atoms on the right side. To balance the hydrogen atoms, multiply H₂O by a coefficient of 3:

NaOH + H₃PO₄ ⇒ Na₃PO₄ + 3H₂O

If the oxygen (O) atoms are balanced. There are four oxygen atoms on the right side, but only two oxygen atoms on the left side. To balance the oxygen atoms, we need to multiply NaOH by a coefficient of 2.

To learn more about the chemical equation, follow the link:

https://brainly.com/question/28792948

#SPJ6

Answer:

1) 1.5 kg

2) 0.6 kg

Explanation:

[tex](3)(30) = 60m, m = 90/60 = 1.5[/tex] kg

[tex](0.8)(15) = 20m, m = 12/20 = 0.6[/tex] kg

Answer:

B.Anything that takes up space and has mass

When Magnesium comes in contact with Oxygen, it reacts with Oxygen causing a layer of Magnesium Oxide on the metal. If Magnesium is burnt, it will cause a bright white light creating Magnesium Oxide.

The initial appearance of Magnesium is a ribbon with a layer of Magnesium Oxide.

Happy to help :)

If you need any more help feel free to ask

Answer:

See Explanation

Explanation:

We can write the molecular orbital configuration of molecules in the same way as we write the orbital electron configuration of atoms. The valence electrons in the molecule are filled into molecular orbitals of appropriate energy in accordance to the Aufbau principle.

For CO;

σ2s2, σ*2s2, Π2py2, Π2pz2, σ2px2

For NO;

σ2s2, σ*2s2, Π2px2, Π2py2, σ2pz2, Π*2px1

For CN-;

σ2s2, σ*2s2, Π2px2, Π2py2, σ2pz2

These are the ground state electron configurations of these molecules.

Answer:

Explanation:

The boiling point will increase due to dissolution of sugar in water . Increase in boiling point ΔT

ΔT = Kb x m , where Kb is molal elevation constant water , m is molality of solution

Kb for water = .51°C /m

moles of sugar = 16.90 / 342.3

= .04937 moles

m = moles of sugar /  kg of water

= .04937 / .04090

= 1.207

ΔT = Kb x m

= .51 x 1.207

= .62°C .

So , boiling point of water = 100.62°C .

Answer:

the molar mass for Fe and Cl

Answer:

90.26%

Explanation:

From the question given above, the following data were obtained:

Theoretical yield of AlCl₃ = 1551 g

Actual yield of AlCl₃ = 1400 g

Percentage yield =?

The percentage yield of the reaction can be obtained as follow:

Percentage yield = Actual yield / Theoretical yield × 100

Percentage yield = 1400 / 1551 × 100

Percentage yield = 140000 / 1551

Percentage yield = 90.26%

Thus, the percentage yield of the reaction is 90.26%