from a point a on the ground, the angle of elevation to the top of a tall building is . from a point b, which is ft closer to the building, the angle of elevation is measured to be . find the height of the building.

False.

the given augmented matrix is in reduced row echelon form.

The augmented matrix is said to be in reduced row echelon form (RREF) if it satisfies the following conditions:

1. The first nonzero element in each row (called the "pivot") is 1.
2. The pivot in each row is to the right of the pivot in the previous row.
3. All entries above and below each pivot are zero.

In the given augmented matrix, the first row is (1,1,0) and the second row is (0,1,0). Since the first nonzero element (the pivot) in the first row is 1, and the pivot in the second row is to the right of the pivot in the first row, the matrix satisfies conditions (1) and (2) for being in RREF.

Also, since the entry below the pivot in the first row is 0, and all entries in the third column are 0, the matrix satisfies condition (3).

Therefore, the given augmented matrix is in reduced row echelon form.

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The vector 2v is ⟨-10, -6⟩ when the vector v is ⟨-5, -3⟩ we get by multiplying

To find 2v, we simply need to multiply each component of the vector v by 2:

2v = 2⟨-5, -3⟩

Multiply 2 with the vector v

= ⟨2(-5), 2(-3)⟩

= ⟨-10, -6⟩

Therefore, the vector 2v is ⟨-10, -6⟩ when the vector v is ⟨-5, -3⟩

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The equation of the axis of symmetry for the parabola is x = 4.

In this problem we find the representation of a parabola whose axis of symmetry is parallel with the y-axis, the formula of the parabola is:

y = a · x² + b · x + c

Where:

And the axis of symmetry of the parabola is shown below:

x = h

Where h is the x-coordinate of the vertex.

If we know that vertex has coordinates (h, k) = (4, - 1), then the equation of the axis of symmetry is x = 4.

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The difference in overall gain is $299.30.

For Stock A:

Purchase price: $90 per share

Number of shares: 120

Total purchase cost: 120 * $90 = $10,800

Selling at high price: $105.19

Selling at low price: $103.25

High price sale proceeds: 120 * $105.19 = $12,622.80

Low price sale proceeds: 120 * $103.25 = $12,390

Profit/loss at high price: $12,622.80 - $10,800 = $1,822.80

Profit/loss at low price: $12,390 - $10,800 = $1,590

Difference for Stock A: $1,822.80 - $1,590 = $232.80

For Stock B:

Purchase price: $145 per share

Number of shares: 35

Total purchase cost: 35 * $145 = $5,075

Selling at high price: $145.18

Selling at low price: $143.28

High price sale proceeds: 35 * $145.18 = $5,081.30

Low price sale proceeds: 35 * $143.28 = $5,014.80

Profit/loss at high price: $5,081.30 - $5,075 = $6.30

Profit/loss at low price: $5,014.80 - $5,075 = -$60.20

Difference for Stock B: $6.30 - (-$60.20) = $66.50

total difference in overall gain between selling at the current day's high price or low price:

Difference for Stock A + Difference for Stock B = $232.80 + $66.50 = $299.30

So, the correct statement is:

The difference in overall gain is $299.30.

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The situation where we can approximate the sampling distribution with a normal distribution is Op = .90 and n = 32.

In order to approximate the sampling distribution with a normal distribution, both of the following conditions must be satisfied:

The sample size n must be large enough (typically, n >= 30).

The population proportion p and the sample size n must satisfy np >= 10 and n(1-p) >= 10.

Let's check these conditions for each of the given situations:

Op = 24 and n = 30: Since np = 24*30/100 = 7.2 < 10 and n(1-p) = 22.8 < 10, we cannot approximate the sampling distribution with a normal distribution in this case.

Op = .90 and n = 32: Since np = 28.8 >= 10 and n(1-p) = 3.2 >= 10 are both satisfied, we can approximate the sampling distribution with a normal distribution in this case.

Op = .08 and n = 50: Since np = 4 < 10 and n(1-p) = 46 >= 10 are not both satisfied, we cannot approximate the sampling distribution with a normal distribution in this case.

Op = .70 and n=9: Since np = 6.3 >= 10 and n(1-p) = 2.7 < 10 are not both satisfied, we cannot approximate the sampling distribution with a normal distribution in this case.

Therefore, the situation where we can approximate the sampling distribution with a normal distribution is Op = .90 and n = 32.

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For f(x) = 4/(1+x), a = 2, the Taylor series is given by:

f(x) = f(a) + f'(a)(x-a) + (f''(a)/2!)(x-a)^2 + (f'''(a)/3!)(x-a)^3 + ...

We first need to find the derivatives of f(x):

f(x) = 4/(1+x)
f'(x) = -4/(1+x)^2
f''(x) = 8/(1+x)^3
f'''(x) = -48/(1+x)^4
f''''(x) = 384/(1+x)^5

Now, we can evaluate the Taylor series at x = 2:

f(2) = 4/(1+2) = 4/3
f'(2) = -4/(1+2)^2 = -4/9
f''(2) = 8/(1+2)^3 = 8/27
f'''(2) = -48/(1+2)^4 = -16/81

Substituting these values into the Taylor series, we get:

f(x) = 4/3 - 4/9(x-2) + 8/27(x-2)^2 - 16/81(x-2)^3 + ...

Therefore, the first four nonzero terms of the Taylor series for f(x) centered at a = 2 are:

4/3, -4/9(x-2), 8/27(x-2)^2, -16/81(x-2)^3

For f(x) = 3xe^x, a = 0, the Taylor series is given by:

f(x) = f(a) + f'(a)x + (f''(a)/2!)x^2 + (f'''(a)/3!)x^3 + ...

We first need to find the derivatives of f(x):

f(x) = 3xe^x
f'(x) = 3e^x + 3xe^x
f''(x) = 6e^x + 3xe^x
f'''(x) = 9e^x + 3xe^x
f''''(x) = 12e^x + 3xe^x

Now, we can evaluate the Taylor series at a = 0:

f(0) = 0
f'(0) = 3
f''(0) = 6
f'''(0) = 9

Substituting these values into the Taylor series, we get:

f(x) = 3x + 3x^2 + 3x^3 + 9/2x^4 + ...

Therefore, the first four nonzero terms of the Taylor series for f(x) centered at a = 0 are:

3x, 3x^2, 3x^3, 9/2x^4

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The value of x in the expression is x = - 14

Remember that an algebraic expression is an equation that contains one or more variables.  It is built up from constant algebraic numbers, variables, and the algebraic operations (addition, subtraction, multiplication, division and exponentiation by an exponent that is a rational number)

The given equation is

-1/2 x + 6 = 4x - 3

Collecting the like terms to have

- 1/2 x - 4x = -3 -6

(2x - 8)/ 4 = - 9

Cross and  multiply to have

2x -8 = -36

2x = -36 +8

2x = -28

Making x the subject of the relation we have

x = -28/2

Therefore the value of x = - 14

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When evaluating a square root, you should acknowledge both the positive and negative roots. Hence, the given statement is false.

The square of a number is the value that is obtained when we multiply the number by itself, while the square root of a number is obtained by finding a number that when squared gives the original number.

When evaluating a square root, you should acknowledge both the positive and negative roots.

Example: √8

= √(4×2)

= ±2√2

Hence, the given statement is false.

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X is used as a Place holder for the value(s) in math. Oh and angle BAG should be around 135!

The journal entry to record indirect labor consists of A. Debit Factory Overhead $ 5, 700, credit Factory Wages Payable $ 5, 700.

Indirect labor charges, like those for factory supervisors or maintenance crew, cannot be exclusively attributed to a given product or job.

Instead, they are typically allotted to all jobs depending on predetermined rates/bases in job order costing, by debiting a Factory Overhead account and crediting an accounting option such as Factory Wages Payable or Accrued Wages Payable.

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The awnesr is

= 120

10(8+4)

This simple proportion equation will result to 592

In mathematics, a proportion is a statement that two ratios or fractions are equal. It expresses the relationship between two quantities or sets of quantities that are proportional or have a constant ratio to each other.

For example, the statement "2/3 = 4/6" is a proportion, which means that the ratio of 2 to 3 is the same as the ratio of 4 to 6. This proportion can be simplified by dividing both sides by 2, giving "1/3 = 2/3", which means that one-third is equal to two-thirds.

Proportions are commonly used in various fields such as finance, science, and engineering to solve problems related to scaling, measurement, and comparison.

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5,040 arrangements can be made using 4 letters of the word hyperbolas if no letter is to be used more than once.

To find the number of arrangements that can be made using 4 letters of the word "hyperbolas" without repeating any letters, we need to use the formula for permutations.

The formula for permutations of n objects taken r at a time is:

P(n,r) = n! / (n-r)!

Where "n" is the total number of objects and "r" is the number of objects we are choosing.

In this case, we have 10 letters in the word "hyperbolas" and we need to choose 4 of them without repetition. So we can plug in the values:

P(10,4) = 10! / (10-4)!
P(10,4) = 10! / 6!
P(10,4) = (10 x 9 x 8 x 7 x 6!) / 6!
P(10,4) = 10 x 9 x 8 x 7
P(10,4) = 5,040

Therefore, there are 5,040 different arrangements that can be made using 4 letters of the word "hyperbolas" without repeating any letters.

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The area of the painted face of the brick is 104 square inches units

The vertices of the face are (−4, 2), (−4, −11), (4, 2), and (4, −11)

The distance between the coordinates are

√[(-4 + 4)^2 + (2 + 11)^2] = 13

√[(-4 - 4)^2 + (-11 + 11)^2] = 8

So, we have

Area = 13 * 8

Area = 104

Hence, the area is 104 square inches units

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Answer: The answer is C

Step-by-step explanation:

Yes, two numbers could have 16 as their HCF and 380 as their LCM.

Right here's how you could find those two numbers:

Step 1: prime Factorization

Write the high factorization of the LCM, 380, because the manufactured from its prime elements:

[tex]380 = 2^2 * 5 * 19[/tex]

Step 2: HCF Calculation

The HCF of numbers is the highest common element that divides each numbers evenly. since the HCF of the 2 numbers is 16, every of the two numbers have to be divisible by means of 16.

Step 3: number Formation

permit the two numbers be 16a and 16b, in which a and b are co-top (meaning they haven't any common elements aside from 1).

Step 4: LCM Calculation

The LCM of numbers is the smallest variety this is divisible by way of each numbers. because the LCM of the two numbers is 380, we will write:

LCM(16a, 16b) =[tex]2^2 * 5 * 19[/tex]

To find the values of a and b, we need to discover the smallest viable values of a and b such that their product is identical to 19. considering the fact that a and b are co-top, a × b can most effective be 19 or 1.

Case 1: a × b = 1

If a × b = 1, then a = 1 and b = 1, which means that that the 2 numbers are 16 and 16. but, 16 isn't divisible by using 19, so this case is not valid.

Case 2: a × b = 19

If a × b = 19, then the two numbers are 16 × 1 and 16 × 19, which can be 16 and 304, respectively.

Step 5: Verification

We will verify that the two numbers, 16 and 304, have 16 as their HCF and 380 as their LCM as follows:

HCF(16, 304) = 16 (seeing that 16 is the largest common factor of 16 and 304)

LCM(16, 304) = 3040/sixteen = 380 (due to the fact 3040 is the smallest multiple of 16 and 304)

Consequently, the 2 numbers with 16 as their HCF and 380 as their LCM are 16 and 304.

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In terms of deviation from the average salary, David is doing better in his company than Andrew is in his. However, it's important to note that there may be other factors that impact their overall job performance and success within their respective companies.

To determine who is doing better in comparison to their coworkers, we need to calculate the z-scores for both Andrew and David. The z-score measures the number of standard deviations a data point (in this case, their salaries) is away from the mean (average salary). The formula for the z-score is:

z = (X - μ) / σ

where X is the individual's salary, μ is the average salary, and σ is the standard deviation.

For Andrew:
X = $45,000 EC
μ = $41,000 EC
σ = $7,000 EC

z = ($45,000 - $41,000) / $7,000
z = $4,000 / $7,000
z = 0.5714

For David:
X = $38,000 EC
μ = $35,000 EC
σ = $1,700 EC

z = ($38,000 - $35,000) / $1,700
z = $3,000 / $1,700
z = 1.7647

Comparing these deviations, we can see that David is doing better in comparison to his coworkers than Andrew is. David's deviation is larger than Andrew's, which means that his salary is further above the average salary in his company than Andrew's is in his.

A higher z-score indicates a better position compared to coworkers. In this case, David has a higher z-score (1.7647) compared to Andrew (0.5714), meaning that David is doing better in comparison to their coworkers.

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Answer: El precio unitario de las palomitas es de $60 y el precio unitario del refresco es de $70.

Primero, podemos descomponer el costo total de la primera visita al cine en el costo de las palomitas y el costo de los refrescos:

- 5 palomitas + 7 refrescos = $630

- Palomitas = $x, Refrescos = $y

- 5x + 7y = 630

Luego, podemos descomponer el costo total de la segunda visita al cine en el costo de las palomitas y el costo de los refrescos:

- 8 palomitas + 11 refrescos = $1000

- Palomitas = $x, Refrescos = $y

- 8x + 11y = 1000

Ahora podemos resolver este sistema de ecuaciones para encontrar el precio unitario de las palomitas y del refresco. Primero, despejamos y de la primera ecuación:

- 5x + 7y = 630

- 5x = 630 - 7y

- x = (630 - 7y) / 5

Luego, sustituimos esta expresión para x en la segunda ecuación:

- 8x + 11y = 1000

- 8[(630 - 7y) / 5] + 11y = 1000

- 504 - 45.6y + 11y = 1000

- 65.4y = 496

- y = 7.58

Finalmente, podemos sustituir este valor para y en la primera ecuación para encontrar el valor de x:

- 5x + 7(7.58) = 630

- 5x = 578.86

- x = 115.77

Por lo tanto, el precio unitario de las palomitas es de $60 y el precio unitario del refresco es de $70.

Step-by-step explanation:

So the probability that a randomly selected resident from the land of Oz is a member of the lollipop guild and has a home in emerald city is 0.15.

Since lollipop guild membership is independent of having a home in emerald city, we can find the probability of both events occurring by multiplying their individual probabilities:

P(lollipop guild and emerald city) = P(lollipop guild) * P(emerald city)

P(lollipop guild) = 0.20 (given)

P(emerald city) = 0.75 (given)

Therefore,

P(lollipop guild and emerald city) = 0.20 * 0.75

= 0.15

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Answer:

Step-by-step explanation:

Here are the match-ups:

Han:  x+2<20

Mai: x-2<20

Tyler: 2x<20

Priya: 1/2<20

The unit of measurement that Mia should use for the surface area of the prism is B. in ².

Determining the surface area of an object requires calculating the total measure of its covered space. This figure is quantified in square units, as it consists of deriving two-dimensional lengths and widths from its surfaces, which are then multiplied to arrive at the entire area.

As dimensions only concern a flat outline, it follows that all recorded measurements will take on some form of squared units like m² or in² - invariably pegged to the realm of two-dimensionality.

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Yes, it is possible for a process to pass through the 2nd or 4th quadrant. The 2nd quadrant is characterized by negative values of work done and positive values of heat added.

This could happen in a scenario where a gas is compressed at a constant temperature, which results in negative work done, but heat is added to the gas to maintain its temperature. The 4th quadrant is characterized by negative values of both work done and heat added. This could happen in a scenario where a gas is expanded at a constant temperature, which results in negative work done and no heat is added or removed from the gas.

As for the effect of a negative value of the polytropic index 'n', it indicates that the process is non-adiabatic and not reversible. A negative value of 'n' means that the process is not able to maintain constant heat transfer or constant entropy. This could result in energy losses and a decrease in the efficiency of the process. It could also indicate that the process is not in equilibrium and is being driven by external forces. Overall, a negative value of 'n' can have negative effects on the performance and stability of a process.

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there is a related property known as the chain rule which can be used to differentiate a difference of functions.

The correct response is: c. Only statement i is true.

Statement i is known as the linearity of differentiation and is a fundamental property of derivatives. It states that the derivative of a sum of functions is equal to the sum of their derivatives.

On the other hand, statement ii is not true in general. The derivative of a difference of functions is not equal to the difference of their derivatives. However, there is a related property known as the chain rule which can be used to differentiate a difference of functions.

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The probability that a randomly selected set of 3 will include 1 A and 2 Bs is 0.3 or 30%.

To find the probability that a randomly selected set of 3 will include 1 a and 2 bs, we first need to determine the total number of possible sets of 3 that can be selected from the sample space.

Since the sample space contains 6 as and 4 bs, the total number of possible sets of 3 that can be selected is:

10C3 = (10!)/(3!*(10-3)!) = 120

This means there are 120 different ways to select a set of 3 from the sample space.

Next, we need to determine the number of sets of 3 that include 1 a and 2 bs. To do this, we can use the combination formula:

6C1 * 4C2 = (6!)/(1!*(6-1)!) * (4!)/(2!*(4-2)!) = 6*6 = 36

This means there are 36 different sets of 3 that include 1 a and 2 bs.

Finally, we can calculate the probability of selecting a set of 3 that includes 1 a and 2 bs by dividing the number of sets that meet this condition by the total number of possible sets:

36/120 = 3/10

Therefore, the probability that a randomly selected set of 3 will include 1 a and 2 bs is 3/10.

Given that the sample space contains 6 As and 4 Bs, let's find the probability that a randomly selected set of 3 will include 1 A and 2 Bs.

1. First, calculate the total number of ways to choose 3 elements from a set of 10 (6 As and 4 Bs). We use the combination formula:

C(n, r) = n! / (r!(n-r)!)
C(10, 3) = 10! / (3!(10-3)!) = 10! / (3!7!) = 120

2. Next, find the number of ways to choose 1 A from the 6 As and 2 Bs from the 4 Bs:

C(6, 1) = 6! / (1!(6-1)!) = 6! / (1!5!) = 6
C(4, 2) = 4! / (2!(4-2)!) = 4! / (2!2!) = 6

3. Multiply the number of ways to choose 1 A and 2 Bs:

Number of favorable outcomes = C(6, 1) × C(4, 2) = 6 × 6 = 36

4. Finally, calculate the probability:

Probability = Number of favorable outcomes / Total number of outcomes = 36 / 120 = 3/10 or 0.3

So, the probability that a randomly selected set of 3 will include 1 A and 2 Bs is 0.3 or 30%.

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Answer:

1 meter

Step-by-step explanation:

Circumference of circle = 2 · r · π

Circumference = 2π

Let's solve

2π = 2 · r · π

2 = 2 · r

r = 1 meter

So, the radius is 1 meter

Answer:

Rudy's house is approximately 2.8 miles away from Javier's house.

Step-by-step explanation:

We can use the Pythagorean theorem to solve this problem. Let x be the distance from Rudy's house to Javier's house. Then, we can set up the following equations based on the given information:

x^2 + 1^2 = 3^2 (using the distance between Javier's and Steve's houses)

x^2 = 9 - 1

x^2 = 8

x ≈ 2.8

Therefore, Rudy's house is approximately 2.8 miles away from Javier's house.

Answer:

y=(8/7)x+8

Step-by-step explanation:

calculate the slope: rise over run, 8/7 and add the y intercept of 8.

The 95% confidence interval for the true (population) average time spent on the website is (16.08, 23.92) minutes. This means we can be 95% confident that the true average time spent on the website falls within this range.

To estimate the true (population) average time spent on the Relentless.com website at a 95% confidence level, we can use the formula for a confidence interval:
CI = X ± Zα/2 * (σ/√n) where X is the sample mean (20 minutes), σ is the population standard deviation (25 minutes), n is the sample size (250), and Zα/2 is the critical value from the standard normal distribution for a 95% confidence level (1.96).
Plugging in the values, we get:
CI = 20 ± 1.96 * (25/√250)
Simplifying, we get:
CI = 20 ± 3.92

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Answer:

[tex] \frac{6 {x}^{2} - 12x - 48 }{3 {x}^{2} - 12x - 36 } = \frac{6( {x}^{2} - 2x - 8)}{3( {x}^{2} - 4x - 12)} = \frac{6(x + 2)(x - 4)}{3(x + 2)(x - 6)} = \frac{2(x - 4)}{x - 6} = \frac{2x - 8 }{x - 6} [/tex]

To test the claim that men have a higher rate of red/green color blindness. If p_ m > p_ w, the claim is supported, indicating that the proportion of men with color blindness is larger.

To test the claim that men have a higher rate of red/green color blindness, we need to compare the proportions of color blindness in men and women. Let p-m be the proportion of men with red/green color blindness and p-w be the proportion of women with red/green color blindness.

We can set up the null hypothesis as H0: p-m = p-w, meaning there is no difference in the proportions of color blindness between men and women. The alternative hypothesis is Ha: p-m > p-w, meaning the proportion of men with color blindness is larger.

To test this claim, we can use a two-sample proportion z-test. The formula for the test statistic is:

z = (p-m - p-w) / sqrt(p-hat * (1 - p-hat) * (1/n-m + 1/n-w))

where p-hat is the pooled sample proportion:

p-hat = (x-m + x-w) / (n-m + n-w)

In this case, x-m = 72, x-w = 6, n-m = 800, and n-w = 2100. Plugging in the values, we get:

p-hat = (72 + 6) / (800 + 2100) = 0.024

z = (0.09 - 0.002) / sqrt(0.024 * 0.976 * (1/800 + 1/2100)) = 3.09

Using a significance level of 0.05, the critical z-value for a one-tailed test is 1.645. Since our calculated z-value of 3.09 is greater than the critical value, we can reject the null hypothesis and conclude that there is evidence to support the claim that men have a higher rate of red/green color blindness than women.
In the study of red/green color blindness, 800 men and 2100 women were randomly selected and tested. Among the men, 72 have red/green color blindness, and among the women, 6 have red/green color blindness. To test the claim that men have a higher rate of red/green color blindness, compare the proportions: p_ m (proportion of men with color blindness) and p_ w (proportion of women with color blindness). If p_ m > p_ w, the claim is supported, indicating that the proportion of men with color blindness is larger.

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The amount of fabric that is needed for the tent is 18350 in² (optionC)

A prism is a solid shape that is bound on all its sides by plane faces. The surface area of a prism is expressed as ;

SA = 2B +pH

where B is the base area , p is the perimeter of the base and H is the height of the prism.

Base area =1/2bh

= 1/2 × 50× 70

= 25 × 70

= 1750in²

Perimeter of the base = 74+74+50

= 198 in

height = 75in

Therefore SA = 2×1750 +198 × 75

= 3500 + 14850

= 18350 in²

therefore the amount of fabric that will be needed nis 18350 in²

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