fthe
Fr= 12 N
What is the magnitude and direction (right or left)
net force acting on the box?
N to the
F, = 15 N
F=3N
F,= 12 N
Intro
Done

Answer:

Height of the first projectile = 49.98 m

Height of the second projectile = 72.52 m

Explanation:

From the given information;

Two projectiles are thrown from the same point with the velocity of49m/s

First is  projected making an angle  θ with the horizontal

and the second at an angle of 90 - θ.

Thus; for the first height to the horizontal; we have;

[tex]H_1 = \dfrac{v^2 sin^2 \theta}{2g}[/tex]  ----- (1)

the second height in the vertical direction is :

[tex]H_2 = \dfrac{v^2 cos^2 \theta}{2g}[/tex]    -----(2)

However; the second is found to rise 22.5 m higher than the first; so , we have :

[tex]\dfrac{v^2 cos^2 \theta}{2g}= 22.5 + \dfrac{v^2 sin^2 \theta}{2g}[/tex]

Let's recall that :

Cos²θ = 1 - Sin²θ

Replacing it into above equation; we have:

[tex]\dfrac{v^2}{2g} - \dfrac{v^2 sin^2 \theta}{2g}= 22.5 + \dfrac{v^2 sin^2 \theta}{2g}[/tex]

[tex]\dfrac{v^2}{2g} - 22.5 = \dfrac{v^2 sin^2 \theta}{g}[/tex]

[tex]\dfrac{1}{2 } \dfrac{v^2}{g} - 22.5 = \dfrac{v^2 sin^2 \theta}{g}[/tex]

[tex]\dfrac{1}{2 } - \dfrac {9.8 \times 22.5}{(49)^2} = sin^2 \theta[/tex]

[tex]\dfrac{1}{2 } - \dfrac {220.5}{2401} = sin^2 \theta[/tex]

[tex]sin^2 \theta= 0.408[/tex]

From (1);

[tex]H_1 = \dfrac{v^2 sin^2 \theta}{2g}[/tex]

[tex]H_1 = \dfrac{49^2 \times 0.408}{2*9.8}[/tex]

[tex]H_1 = \dfrac{979.608}{19.6}[/tex]

[tex]\mathbf{H_1 =49.98 \ m }[/tex]

Height of the first projectile = 49.98 m

Similarly;

From(2)

[tex]H_2 = \dfrac{v^2 cos^2 \theta}{2g}[/tex]    

[tex]H_2 = \dfrac{v^2 (1-sin^2 \theta)}{2g}[/tex]

[tex]H_2 = \dfrac{49^2 (1-0.408 )}{2 \times 9.8}[/tex]

[tex]H_2 = \dfrac{2401 (0.592 )}{19.6}[/tex]

[tex]H_2 = \dfrac{1421.392}{19.6}[/tex]

[tex]\mathbf{H_2 = 72.52 \ m}[/tex]

Height of the second projectile = 72.52 m

Answer:

It has to be important to you.

-It has to be something that you are in control of.

-It has to be attainable, or able to be achieved.

-It has to be clear and specific.

-It has to have a plan.

Wellness

Wellness refers to a healthy state of being in body, mind, and emotion.

Body wellness

means eating right, exercising, and keeping your bodily systems in good health.

Mental wellness

means feeling safe and secure in your environment and at peace with your decisions and actions.

Emotional wellness

means feeling your best and having the ability to deal with many different situations.

Wellness: Setting Goals

The first step to setting a goal is defining it. Keep in mind that not everything you wish for can be a goal. When it comes to physical activity, diet, and exercise, you may wish to run a marathon before the end of the school year. However, this goal could be difficult to achieve if school ends in just a few months and you are not already training. A more reasonable goal might be to be able to run a mile in the amount of time considered healthy for your age group.

Importance of Physical Education

Physical education explores the methods, types, and benefits of physical activity for the body. In addition to staying active, making healthy choices about diet and exercise is important to overall personal and long-term health. Long-term health passed down through generations can also promote healthy family lifestyles.

Fitness

is the ability of the body to function effectively and efficiently during physical activity and is the ability to move joints through an entire range of motion.

Physical exercise

is the act of improving one's body through specific intentional movements.

differences between exercise and fitness

while anyone can exercise, only someone who exercises regularly can be fit.

Why is it important to make healthy choices about your diet and exercise?

Choosing healthy behaviors when it comes to diet and exercise is important to personal health, long-term health, and promoting healthy family lifestyles.

five components of physical education:

-Cardiorespiratory endurance

-Muscular strength

-Muscular endurance

-Flexibility

-Body composition

Explanation:

Life is WORTH LIVING

Answer: I didn’t make my schedule with a support system in mind. But, I can build a support system by finding people who can keep me on track. On the weekends, my friends can be my support system. During the week, it’s not that easy because my friends and family are so busy. I know that my mom goes for a 20-minute walk in the morning before work. Maybe I could walk with her and then work out on my own for 40 minutes afterward.

Explanation: Plato

Answer:

The distance covered by the body is 14.4 m.

Solution,

Initial velocity(u)= 0 m/s( according to Question, the body starts from rest.that's why initial velocity(u) becomes zero.

Acceleration (a)= 0.2 m/s

Time (t):

[tex] \frac{1}{5} minute = \frac{1}{5 } \times 60 \: seconds[/tex]

[tex] = 12 \: seconds[/tex]

Now,

Applying third equations of motion:

[tex]s = ut + \frac{1}{2} a {t}^{2} \\ s = 0 \times 12 + \frac{1}{2} \times 0.2 \times {(12)}^{2} \\s = 0 + 14.4 \\ s = 14.4 \: metre[/tex]

Thus, the distance covered by the body is 14.4 metre.

Further more information:

Answer:

a. 9.52 cm b. 4.34 × 10⁶ m/s

Explanation:

a. The horizontal distance traveled by the electron when it hits the plate.

The electric force F on the electron due to the electric field E of mass, m is

F = -eE = ma

a = -eE/m where a = acceleration of electron

The vertical distance moved by the electron is given by

Δy = ut +1/2at²

u = initial vertical velocity = 0. and take the top plate as y = 0 and bottom plate as y

So,

0 - y = 0 × t + 1/2at²

-y = 1/2at²

substituting a = -eE/m

-y = 1/2(-eE/m)t²

y = eEt²/2m

making t subject of the formula,

t = √(2ym/eE) where t is the time it takes to reach the bottom plate.

Since E = 4.0 × 10² N/C, y = distance between plates = 2.0 cm = 0.02 m, m = 9.109 × 10⁻³¹kg and e = 1.602 × 10⁻¹⁹ C

t = √[(2 × 0.02 m × 9.109 × 10⁻³¹kg)/(1.602 × 10⁻¹⁹ C × 4.0 × 10² N/C)]

t =  √[(0.36436 × 10⁻³¹kgm)/(6.408 × 10⁻¹⁷ N)]

t = √[(0.0569 × 10⁻¹⁴kgm/N)t

t = 0.238 × 10⁻⁷ s

t = 23.8 × 10⁻⁹ s

t = 23.8 ns

The horizontal distance moved when it hits the plates x = vt where v = initial horizontal velocity = 4.0 × 10⁶ m/s

x = 4.0 × 10⁶ m/s × 23.8 × 10⁻⁹ s

= 0.0952 m

= 9.52 cm

b. The velocity of the electron as it strikes the plate.

To find the velocity of the electron as it strikes the plates, we calculate its final vertical velocity V as it strikes the plate. This is gotten from

v' = u + at since u = 0,

v' = at

= -eEt/m

= -(1.602 × 10⁻¹⁹ C × 4.0 × 10² N/C × 0.238 × 10⁻⁷ s)/9.109 × 10⁻³¹kg

= -1.525 × 10⁻²⁴ Ns/9.109 × 10⁻³¹kg

= -0.167 × 10⁷ m/s

= -1.67 × 10⁶ m/s

So, the resultant velocity as it strikes the plate v = √(v'² + v²)

= √((-1.67 × 10⁶ m/s)² + (4 × 10⁶ m/s)²)

= √(2.7889  + 16) × 10⁶ m/s

= √18.7889 × 10⁶ m/s

= 4.335 × 10⁶ m/s

≅ 4.34 × 10⁶ m/s

Answer:

The lightbulbs were exploding after several mins of use

Explanation:

Answer:

the lightbulbs were exploding after several minutes of use

Explanation:

a p e x :))

Answer:

Femoroacetabular impingement

It occurs when an area of your hip joint becomes pinched when you move in certain directions. :)

Answer:

smaller than the object

Explanation:

The rest are incorrect; It has an upright image.

Answer: Smaller Than the object and right-side up

Answer:

C

Explanation:

It is directly propotional to the amount of charge and inversly propotional to distance.

Answer:

C. Distance and amount of charge

Explanation:

The magnitude of the electric potential depends on which factors?

Distance and amount of charge

Answer:

A police car with its siren on is driving towards you, and you perceive the pitch of the siren to increase.

Explanation:

In Physics, Doppler effect can be defined as the change in frequency of a wave with respect to an observer in motion and moving relative to the source of the wave.

Simply stated, Doppler effect is the change in wave frequency as a result of the relative motion existing between a wave source and its observer.

The term "Doppler effect" was named after an Austrian mathematician and physicist known as Christian Johann Doppler while studying the starlight in relation to the movement of stars.

The phenomenon of Doppler effects is generally applicable to both sound and light.

An example of the Doppler effect is a police car with its siren on is driving towards you, and you perceive the pitch of the siren to increase. This is so because when a sound object moves towards you, its sound waves frequency increases, thereby causing a higher pitch. However, if the sound object is moving away from the observer, it's sound waves frequency decreases and thus resulting in a lower pitch.

Other fields were the Doppler effects are applied are; astronomy, flow management, vibration measurement, radars, satellite communications etc.

Answer:

A police car with its siren on is driving towards you, and you perceive the pitch of the siren to increase.

Explanation:

This should be the correct answer.

Answer:

a) 16 N

b) 2.13 m/s²

Explanation:

Draw a free body diagram of the tv stand.  There are four forces:

Weight force mg pulling down,

Normal force N pushing up,

Friction force Nμ pushing left,

and applied force P pulling right.

Sum of forces in the y direction:

∑F = ma

N − mg = 0

N = mg

The net force in the x direction is:

∑F = P − Nμ

∑F = P − mgμ

∑F = 25 N − (7.5 kg) (10 m/s²) (0.12)

∑F = 16 N

Net force equals mass times acceleration:

∑F = ma

16 N = (7.5 kg) a

a = 2.13 m/s²

[tex]\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}[/tex]

Actually Welcome to the Concept of the FRICTION.

Force by Xavier = 25 N

Force of friction in the opposite direction of Xavier = f = umg

where, u = coefficient of kinetic friction.

so we here get as ,

Net force = 16 N

and acceleration = 2.13 m/s^2

Answer:

Medium B is denser than medium C

When light travels from B to C light bends away from the normal .

Refractive index of C with respect to B is 8/9

Ratio of speed of light in medium B to the speed of light in medium A = 4/3

Explanation:

Refractive index of medium A /  Refractive index of medium B =  4/3

Refractive index of medium A /  Refractive index of medium C = 3/2  

Dividing ,

Refractive index of medium B /  Refractive index of medium C

= 3/2  x  3/4

= 9 / 8

Refractive index of medium B  >   Refractive index of medium C

Refractive index of C with respect to B is 8/9

 speed of light in medium B /  the speed of light in medium A

= refractive index of A / refractive index of B = 4 / 3

Answer: [tex]-\frac{1}{2}\times \frac{d[Br^.]}{dt}=+\frac{d[Br_2]}{dt}[/tex]

Explanation:

Rate of a reaction is defined as the rate of change of concentration per unit time.

Thus for reaction:

[tex]2Br^.\rightarrow Br_2[/tex]

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

[tex]Rate=-\frac{d[Br^.]}{2dt}[/tex]

or [tex]Rate=+\frac{d[Br_2]}{dt}[/tex]

Thus [tex]-\frac{d[Br^.]}{2dt}=+\frac{d[Br_2]}{dt}[/tex]

Answer:

Explanation:

Minimum force needed to set the flower in motion = maximum frictional force

possible on the flower by the floor .

= μ x mg

where μ is coefficient of friction of the floor and mg is weight of the flower

= .76 x 11 x 9.8

= 81.9 N

When the flower is in motion , kinetic friction is applied on it

Force of kinetic friction applied on it

= μk x mg where μk is coefficient of  kinetic friction of the floor

= .44 x 11 x 9.8

= 47.43 N

Pushing force is 81.9 N , so net force on flower when it is in motion

= 81.9 - 47.43 N

= 34.47 N

Acceleration = net force / mass

= 34.47 / 11

= 3.133 m /s

distance moved by flower in 3.75 s

s = ut + 1/2 a t²

= 0 + .5 x 3.133 x 3.75²

= 22 m

Answer:

(1) The orbits are ellipses, with focal points ƒ1 and ƒ2 for the first planet and ƒ1 and ƒ3 for the second planet. The Sun is placed in focal point ƒ1.

(2) The two shaded sectors A1 and A2 have the same surface area and the time for planet 1 to cover segment A1 is equal to the time to cover segment A2.

(3) The total orbit times for planet 1 and planet 2 have a ratio a13/2 : a23/2

Answer:

g the day off and I will be there at work and I will be there at work and I will

Explanation:

you are not going to be able to make it to the meeting tonight but I can tomorrow

Answer:

43.43

Explanation:

5.746 x 7.56 = 43.43976

As the least number of desimal is two so our awnser should contain two digits after the decimal point.

Ans: 43.43.

Answer:

43.4 (Plato/Edmentum)

Explanation:

#1: 7.56 * 5.746

#2: 43.43976

#3: 43.4

Answer:

a) The distance travelled by the the locomotive is 30 meters, b) The final displacement of the locomotive is 6 meters westwards.

Explanation:

a) The distance travelled is the sum of magnitudes of distances covered by the train during its motion. That is to say:

[tex]s_{T} = 18\,m + 12\,m[/tex]

[tex]s_{T} = 30\,m[/tex]

The distance travelled by the the locomotive is 30 meters.

b) The displacement is the vectorial distance of the train with respect to a point of reference, since west and east are antiparallel to each other, calculations can be simplified to a scalar form. Let suppose that movement to the east is positive. The calculations are presented below:

[tex]s_{P} = -18\,m +12\,m[/tex]

[tex]s_{P} = -6\,m[/tex]

The final displacement of the locomotive is 6 meters westwards.

Answer:

the dispalcement is 6m and distance travelled is 30m

Explanation:

Answer:

Remember the equation:

F = m*a

where F is force, m is mass and a is acceleration.

If we have F constant. and we want that increases, then we can have the case where m decreases.

The mass can decrease in cases like a rocket, where as the fuel of the rocket consumes, the mass of the rocket decreases and the acceleration increases.

b) The cases where a constant force results in a constant acceleration of zero, is when the force is canceled, an example of this is the constant force of the gravity in all the objects. The objects that are in the ground are being affected by this force, but the gravitational force is canceled with the normal force of the ground. Then we have a constant force that does not cause any acceleration.

Answer:

The velocity of the marble relative to the water is 3.63 m/s

Explanation:

The information given are;

The velocity of the ferry relative to the water = 3.5 m/s

Direction of motion of the ferry = East

The velocity of the marble (on the ferry) relative to the ferry = 0.95 m/s

The direction of the marble = North

The (resultant) velocity of the marble relative to the water, [tex]v_R[/tex], is found as follows;

Resolution of the velocities;

Velocity of the ferry = 3.5·i + 0·j

Velocity of the marble = 0·i + 0.95·j

[tex]v_R[/tex] = Combined (resultant) velocity = √(3.5² + 0.95²) = 3.63 m/s

The velocity of the marble relative to the water = 3.63 m/s.

Answer:

we have ,

mass(m)=785g

volume (v)= 15 cm^3

now , density(d)= m/ v

=785/15

=52.33g/cm^3... is anwer

Answer:

79%

Explanation:

The following data were obtained from the question:

Input temperature = 100°C

Output temperature = 22°C

Efficiency =.?

Next, we shall convert the temperature from celsius to Kelvin temperature. This is illustrated below:

T (K) = T (°C) + 273

Input temperature = 100°C

Input temperature = 100°C + 273 = 373K

Output temperature = 22°C

Output temperature = 22°C + 273 = 295K

The efficiency of the locomotive can be obtained as follow:

Input temperature = 373K

Output temperature = 295K

Efficiency =.?

Efficiency = output /input x 100

Efficiency = 295/373 x 100

Efficiency = 79%

Therefore, the efficiency of the locomotive is 79%.

Answer:

High current flow

Explanation:

Generally , the measuring instruments used by technician also have some resistance, though its value is very low  . So when high current is present in the circuit , that current also passes through the instrument which creates a good potential drop across the instrument . So the external voltage used in the circuit measures less voltage .

Answer:

C.15m/s

Explanation:

60 divided by 4 is 15

Answer:

V = 1.578m/s

Explanation:

(Ma x Ua) + (Mb x Ub) = (Ma + Mb)V

(13500 x 4.5) + (25000 x 0) = (13500 + 25000)V

60750 + 0 = (38500)V

60750 = 38500V

V = 60750/38500

V = 1.578m/s

The speed of the two cars after the collision will be equal to V = 1.578m/s

A collision is any event in which two or more bodies exert forces on each other in a relatively short time. Although the most common use of the word collision refers to incidents in which two or more objects collide with great force, the scientific use of the term implies nothing about the magnitude of the force

Now from the perfectly inelastic collision, the conservation of momentum will be

(Ma x Ua) + (Mb x Ub) = (Ma + Mb)V

(13500 x 4.5) + (25000 x 0) = (13500 + 25000)V

60750 + 0 = (38500)V

60750 = 38500V

V = 60750/38500

V = 1.578m/s

Hence the speed of the two cars after the collision will be equal to V = 1.578m/s

To know more about Collisions follow

https://brainly.com/question/7694106

Explanation:

1) This is a synthesis reaction (two or more reactants combine to form a single product).

2) The coefficients are added to balance the reaction.

3) Adding the states of matter (solid, liquid, gas) will make the reaction more precise.

Answer:

Volts itself is SI Unit of Electric Potential.

Explanation:

Answer:

8 N

Explanation:

Using the equation F=ma (F: force/ m: mass  in kg/ a: acceleration),

F = (800/1000)(10)

F = 8 N

Answer:

2.2 m/s

Explanation:

r = 0.1 m

ω₀ = 0 rad/s

α = 4.4 rad/s²

t = 5 s

ω = αt + ω₀

ω = (4.4 rad/s²) (5 s) + 0 rad/s

ω = 22 rad/s

v = ωr

v = (22 rad/s) (0.1 m)

v = 2.2 m/s

The linear velocity is 2.2 m/s

Given:

r = 0.1 m

ω₀ = 0 rad/s

α = 4.4 rad/s²

t = 5 s

So from the equation for angular acceleration we will get,

ω = αt + ω₀

ω = (4.4 rad/s²) (5 s) + 0 rad/s

ω = 22 rad/s

Angular velocity ω is analogous to linear velocity v

The relation between velocity and angular acceleration is given which is:

v = ωr

v = (22 rad/s) (0.1 m)

v = 2.2 m/s

Therefore, linear velocity of  the point on its rim after 5s is​ 2.2 m/s.

Learn more:

brainly.com/question/13014974

Answer:

20.5m/s

Explanation:

neglecting friction the amount of energy at the bottom equals to the amount of energy at top. Law of conservation of energy.

ME= P.E+k.E

ME= mgh+ 1/2mv*v

ME = (m* 10 *49)+(1/2m(4.6*4.6))

MEtop=500.98m

MEbottom=MEtop: in order to obey the law of conservation of energy

MEbottom=mgh+ 1/2mv*v

500.98m=m*10*29+1/2m v* v

500.98m= m(290+1/2v*v) ...cancel m by m

500.98-290=1/2v*v criss cross multiple

210.98*2=v*v

v=√421.96

v=20.5 m/s

Resultant force is basically the force left after everything is added.

if a ball is being pushed one one side with 180N, and being pushed on teh opposite side with 84N (I added friction and air resistance since they're acting on the same side), then the resultant force would be:

180N - 84N = 96N   (you can determine whether it's positive or negative based on the direction of the vector)