Answer:
Within a molecule, the bond angle refers to the angle found between the central atom and its bonded atoms. The total number of bonded atoms and the unshared pairs of electrons within a molecule is the number of electron domains.
By considering the Lewis formula for methanol it is witnessed that the central carbon atom comprises no unshared pair of electrons and four bonded atoms. Therefore, 4 is the number of electron domains present around the carbon atom, so the bond angle present in the given case will be 109.5 degrees. Thus, the bond angles of H-C-O and H-C-H will equivalent to 109.5 degrees.
There are two unshared pairs of electrons and two bonded atoms around the central oxygen atom. Therefore, 4 will be the number of electron domains around the atom of oxygen. Thus, a 109.5 degree will be the bond angle found on it, and therefore, the bond angle of C-O-H will also be equivalent to a 109.5 degree. Hence, in the methanol, CH3OH, the bond angles of H-C-H, C-O-H, and H-C-O will be 109.5 degrees.
Consider the following reversible reaction. Upper C upper O (g) plus 2 upper H subscript 2 (g) double-headed arrow upper C upper H subscript 3 upper O upper H (g). What is the equilibrium constant expression for the given system? K e q equals StartFraction StartBracket upper C upper O EndBracket StartBracket upper H 2 EndBracket superscript 2 over StartBracket upper C upper H subscript 3 upper O upper H EndBracket EndFraction. K e q equals StartFraction StartBracket upper C upper H subscript 3 upper H upper O EndBracket over StartBracket upper C upper O EndBracket StartBracket upper H 2 EndBracket superscript 2 EndFraction. K e q equals StartFraction StartBracket upper C upper O EndBracket StartBracket upper H 2 EndBracket over StartBracket upper C upper H subscript 3 upper O upper H EndBracket EndFraction. K e q equals sart fraction StartBracket upper C upper H subscript 3 upper O StartBracket upper C upper O EndBracket StartBracket upper H 2 EndBracket EndFraction.
Answer:
[tex]Keq=\frac{[CH_3OH]}{[CO][H_2]^2}[/tex]
Explanation:
Hello,
In this case, for the described reaction at equilibrium:
[tex]CO(g)+2H_2(g)\rightleftharpoons CH_3OH(g)[/tex]
The analysis of the law of mass action allows us to write the equilibrium expression as shown below:
[tex]Keq=\frac{[CH_3OH]}{[CO][H_2]^2}[/tex]
Which is written considering that carbon monoxide, hydrogen and methanol are all in gaseous phase, for that reason all of them are included in the expression due to homogeneous equilibrium. Moreover, since hydrogen has a stoichiometric coefficient of 2, it is squared in the law of mass action.
Best regards.
Answer:
the answer is B if your looking for the letter
Explanation:
K e q equals StartFraction StartBracket upper C upper H subscript 3 upper H upper O EndBracket over StartBracket upper C upper O EndBracket StartBracket upper H 2 EndBracket superscript 2 EndFraction.
Amino acids are the building blocks of proteins. The simplest amino acid is glycine . Draw a Lewis structure for glycine. (Hint: The central atoms in the skeletal structure are nitrogen bonded to carbon which is bonded to another carbon. The two oxygen atoms are bonded directly to the right-most carbon atom.
Answer:
Sorry for the lack of precision, if you have any questions you can consult me again.
Explanation:
Glycine is an amino acid, forms proteins and is also called in its molecular chemical formula as C2H5NO2
What is the temperature, in degrees Celsius, of a substance with a temperature of 49K? –322°C –224°C 224°C 322°C
Answer:
-224ºC
Explanation:
Answer:
-224c
Explanation:
Lead forms two compounds with oxygen. One contains 2.98g of lead and 0.461g of oxygen. The other contains 9.89g of lead and 0.763g of oxygen. For a given mass of oxygen, what is the lowest whole-number mass ratio of lead in the two compounds
The given question is incomplete, the complete question is:
Lead forms two compounds with oxygen. One contains 2.98g of lead and 0.461g of oxygen. The other contains 9.89g of lead and 0.763g of oxygen. For a given mass of oxygen, what is the lowest whole-number mass ratio of lead in the two compounds that combines with a given mass of oxygen?
Answer:
The lowest whole-number mass ratio in the two compounds is 1:2.
Explanation:
There is a need to find the mole ratio between lead and oxygen atoms in order to find the whole-number mass ratio of lead in the two compounds. In the first compound, the given mass of lead is 2.98 grams, the molar mass of lead is 207.2 gram per mole.
The no. of moles can be determined by using the formula,
moles = mass/molecular mass
moles = 2.98 g/207.2 g/mol
= 0.0144 moles
The mass of oxygen in the compound I is 0.461 grams, the molecular mass of oxygen is 16 gram per mol.
moles = 0.461 g /16 g/mol
= 0.0288 moles
The ratio between the lead and oxygen in the compound I is 0.0144/0.0288 = 1:2
On the other hand, in the compound II, the mass of lead given is 9.89 grams, therefore, the moles of lead in compound II is,
moles = 9.89 g / 207.2 g/mol
= 0.0477 moles
The mass of oxygen given in compound II is 0.763 grams, the moles of oxygen present in the compound II is,
moles = 0.763 g / 16 g
= 0.0477 moles
The ratio between the lead and oxygen in the compound II is, 0.0477 moles lead /0.0477 moles oxygen = 1:1
Hence, of the two compounds, the lowest ratio is found in the compound I, that is, 1:2.
A buffered solution has a pH of 7.5. What would happen to the pH if a small
amount of acid were added?
Answer:
Dear user,
Answer to your query is provided below
When small amount of acid was added to buffered solution, pH will change very less.
Explanation:
Buffer solution resists change in ph on adding small amount of acid or base but when we calculate the value of buffer capacity we take the change in ph when we add acid or base to 1 lit solution of buffer.This contradicts the definition of buffer solution.
A solution has a hydrogen ion (or hydronium ion) concentration of 1.00×10−9 M.
What is the pH of the solution?
7.5
8.0
8.5
9.0
A sample of gas has a volume of 571 mL at a pressure of 4.04 atm. The gas is compressed and now has a pressure of 7.17 atm. Predict whether the new volume is greater or less than the initial volume, and calculate the new volume. Assume temperature is constant and no gas escaped from the container.
Answer:
The new volume is less than the initial volume.
The new volume is 322mL
Explanation:
Based on Boyle's law, the pressure of a gas is inversely proportional to its volume under constant temperature. That means if the pressure of a gas is increased, the volume decrease and vice versa. The formula is:
P₁V₁ = P₂V₂
Where P is pressure and V is volume of 1, initial state and 2, final states.
In the problem, the pressure of the gas increased from 4.04atm to 7.17atm, That means the new volume is less than initial volume because the gas is compressed occupying less volume.
Replacing in Boyle's equation:
4.04atm*571mL = 7.17atmV₂
322mL = V₂Beeing the new volume of the compressed gas 322mL
Summarize the feedback loop (transfer of energy) between the microbes and the mushrooms. (Video #1)
What is the Nitrogen Cycle? Discuss the 3 types of microbes required for the nitrogen cycle. What would happen to the soil if the microbes were not there?(Video #2)
Where and how does carbon move? How do plants help recycle CO2? Where do plants get their CO2 from? (Video #3)
Scientists are wondering how soil and soil microbes interact, how they will respond to global warming, specifically what will happen to the levels of CO2 and CH4 if the soil warms up.
Analyze the Results from this student’s data (Links to an external site.)
Based on these results, (1) would the warming of the climate cause an increase or a decrease in soil respiration? Use data to back up your claim. (2) How might this impact the environment?
Answer:
Cyanobacteria, Azotobactor and Azospirillum are the microbes which is required for nitrogen cycle.
Explanation:
Nitrogen Cycle is a type of cycle in which nitrogen moves from atmosphere to the earth surface and again return back to the atmosphere. Cyanobacteria, Azotobactor and Azospirillum are the microbes which is required for nitrogen cycle. If these microbes is vanished from the environment, the nitrogen cannot be converted into other forms. Carbon is present in the atmosphere in carbondioxide form. This CO2 is used by the plants from atmosphere and make food from it. When these plants are eaten by animals, this CO2 is again release in the atmosphere. Due to global warming, the microbes present in the soil die due to increase in temperature of the soil. Levels of CO2 and CH4 increases if the soil warms up. With the increase in temperature, soil respiration increases which leads to more emission of CO2 and as a result more global warming occurs.
Question
2 Points
An object in a fluid will sink if:
A. the buoyant force is larger than the weight of the object.
B. the buoyant force is larger than the mass of the object.
C. the buoyant force is smaller than the weight of the object.
D. the buoyant force is smaller than the mass of the object.
SUBM
Answer:
c
Explanation:
when the weight of the object is greater than the buoyant force sinking is occurred.
Arrange the ff substances in order of increasing tendency to donate electrons with reasons
Alpha- ketoglutarate, Oxaloacetate ,O2, NADP+, Malate
Answer:
Alpha- ketoglutarate --> NADP+ --> Oxaloacetate --> O2.
(O2 has the HIGHEST tendency to donate electrons).
Explanation:
Okay, we are to Arrange Alpha- ketoglutarate, Oxaloacetate ,O2, NADP+ and Malate in order of increasing tendency to donate electrons, therefore, the correct order is;
Alpha- ketoglutarate --> NADP+ --> Oxaloacetate --> O2.
And this result can be gotten if we consider these compounds in their oxidative mechanism and check their potential values.
(1). When Alpha- ketoglutarate react with CO2, it gives isocitrate and standard redox potential value of -0.38.
(2). NADP+ with react with two moles of electrons and one mole of hydrogen ion to produce NADPH and standard redox potential value of -0.32.
(3). Oxaloacetate will react with two moles of hydrogen ion and electrons respectively to produce standard redox potential value of -0.18 and Malate.
(4). O2 will react with 4 moles of hydrogen ion and electrons respectively to produce 2 moles of water and standard redox potential value of +0.82.
CONCLUSION: the higher the negative values of the potential, the lesser the electron affinity and vice versa.
Choose the species that is incorrectly matched with its electronic geometry.
1. BeBr2 : linear
2. CF4 : tetrahedral
3. NH3 : tetrahedral
4. H2O : tetrahedral
5. PF3 : trigonal bipyramidal
Answer:
PF3 : trigonal bipyramidal
Explanation:
PF3 has 4 domains around the central phosphorus (3 shared pairs and one lone pair of electrons), thus the electron geometry that has 4 domains is tetrahedral not trigonal bipyramidal
From the options the specie that is incorrectly matched is ( 5 ) ; PF₃ : trigonal bipyramidal
The specie PF₃ is composed of 3 shared pairs and one unshared pair of electrons ( i.e. It has 4 domains ) as seen in the Lewis structure of PF₃. therefore when writing its electronic geometry, it should expressed/written as tetrahedral and not trigonal bipyramidal.
Hence we can conclude that The specie that is incorrectly matched is PF3 : trigonal bipyramidal
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What are three things that
living things need to live?
Answer:
Water, air, and food.
Explanation:
All living things need air water and food to live.
Answer:
the first the Question is what do you need to live then that your answer
food,water,air ;]
A 4.215 g sample of a compound containing only carbon, hydrogen, and oxygen is burned in an excess of oxygen gas, producing 9.582 g CO2 and 3.922 g H2O. What percent by mass of oxygen is contained in the original sample?
Answer:
[tex]\% O=27.6\%[/tex]
Explanation:
Hello,
In this case, for the sample of the given compound, we can compute the moles of each atom (carbon, hydrogen and oxygen) that is present in the sample as shown below:
- Moles of carbon are contained in the 9.582 grams of carbon dioxide:
[tex]n_C=9.582gCO_2*\frac{1molCO_2}{44gCO_2}*\frac{1molC}{1molCO_2} =0.218molC[/tex]
- Moles of hydrogen are contained in the 3.922 grams of water:
[tex]n_H=3.922gH_2O*\frac{1molH_2O}{18gH_2O} *\frac{2molH}{1molH_2O} =0.436molH[/tex]
- Mass of oxygen is computed by subtracting both the mass of carbon and hydrogen in carbon dioxide and water respectively from the initial sample:
[tex]m_O=4.215g-0.218molC*\frac{12gC}{1molC} -0.436molH*\frac{1gH}{1molH} =1.163gO[/tex]
Finally, we compute the percent by mass of oxygen:
[tex]\% O=\frac{1.163g}{4.215g}*100\% \\\\\% O=27.6\%[/tex]
Regards.
Express your answer to three significant figures.
This balanced equation shows the reaction of sodium hydroxide and sulfuric acid:
2NaOH + H2SO4 - Na2SO4 + 2H20.
In a laboratory experiment, a student mixes 355 grams of sulfuric acid with an excess of sodium hydroxide. What is the theoretical mass of
sodium sulfate produced? Refer to the periodic table and the polyatomic ion resource.
The theoretical mass of sodium sulfate is
grams.
Answer: The theoretical mass of [tex]Na_2SO_4[/tex] is, 514 grams.
Explanation : Given,
Mass of [tex]H_2SO_4[/tex] = 355 g
Molar mass of [tex]H_2SO_4[/tex] = 98 g/mol
First we have to calculate the moles of [tex]H_2SO_4[/tex].
[tex]\text{Moles of }H_2SO_4=\frac{\text{Given mass }H_2SO_4}{\text{Molar mass }H_2SO_4}[/tex]
[tex]\text{Moles of }H_2SO_4=\frac{355g}{98g/mol}=3.62mol[/tex]
Now we have to calculate the moles of [tex]Na_2SO_4[/tex]
The balanced chemical equation is:
[tex]2NaOH+H_2SO_4\rightarrow Na_2SO_4+2H_2O[/tex]
From the reaction, we conclude that
As, 1 mole of [tex]H_2SO_4[/tex] react to give 1 mole of [tex]Na_2SO_4[/tex]
So, 3.62 mole of [tex]H_2SO_4[/tex] react to give 3.62 mole of [tex]Na_2SO_4[/tex]
Now we have to calculate the mass of [tex]Na_2SO_4[/tex]
[tex]\text{ Mass of }Na_2SO_4=\text{ Moles of }Na_2SO_4\times \text{ Molar mass of }Na_2SO_4[/tex]
Molar mass of [tex]Na_2SO_4[/tex] = 142 g/mole
[tex]\text{ Mass of }Na_2SO_4=(3.62moles)\times (142g/mole)=514g[/tex]
Therefore, the theoretical mass of [tex]Na_2SO_4[/tex] is, 514 grams.
Energy that is not utilized for work or heat transfer is converted to the chemical energy of body fat containing about 39 kJ/g. How many grams of fat will you gain if you eat 10,000 kJ (about 2390 kcal) one day and do nothing but sit relaxed for 14.3 h and sleep for the other 9.70 h
Answer:
[tex]m=107.8g[/tex]
Explanation:
Hello,
In this case, for the given information, we can compute the gained grams by firstly compute the energy consumed by 14.3 h of being sit relaxed and 9.70 h of sleeping:
[tex]E_{sit}=120\frac{J}{s}*\frac{3600s}{1h} *14.3h*\frac{1kJ}{1000J} =6177.6kJ\\\\E_{sleep}=83\frac{J}{s}*\frac{3600s}{1h} *9.70h*\frac{1kJ}{1000J} =2898.36kJ[/tex]
Then, we compute the energy used that day:
[tex]E_T=10000kJ-2898.36kJ-6177.6kJ=4203.28kJ[/tex]
Finally, the mass by considering the consumed fat:
[tex]m=\frac{4203.28kJ}{39kJ/g} \\\\m=107.8g[/tex]
Regards.
Which image best represents the particles in liquids
Answer:
The 2nd Picture represents the particles in liquids.
Explanation:
A volume of 105 mL of H2O is initially at room temperature (22.00 ∘C). A chilled steel rod at 2.00 ∘C is placed in the water. If the final temperature of the system is 21.50 ∘C , what is the mass of the steel bar? Use the following values: specific heat of water = 4.18 J/(g⋅∘C) specific heat of steel = 0.452 J/(g⋅∘C) Express your answer to three significant figures and include the appropriate units.
Answer:
25.0 grams is the mass of the steel bar.Explanation:
Heat gained by steel bar will be equal to heat lost by the water
[tex]Q_1=-Q_2[/tex]
Mass of steel= [tex]m_1[/tex]
Specific heat capacity of steel = [tex]c_1=0.452 J/g^oC[/tex]
Initial temperature of the steel = [tex]T_1=2.00^oC[/tex]
Final temperature of the steel = [tex]T_2=T=21.50^oC[/tex]
[tex]Q_1=m_1c_1\times (T-T_1)[/tex]
Mass of water= [tex]m_2= 105 g[/tex]
Specific heat capacity of water=[tex]c_2=4.18 J/g^oC[/tex]
Initial temperature of the water = [tex]T_3=22.00^oC[/tex]
Final temperature of water = [tex]T_2=T=21.50^oC[/tex]
[tex]Q_2=m_2c_2\times (T-T_3)-Q_1=Q_2(m_1c_1\times (T-T_1))=-(m_2c_2\times (T-T_3))[/tex]
On substituting all values:
[tex](m_1\times 0.452 J/g^oC\times (21.50^o-2.00^oC))=-(105 g\times 4.18 J/g^oC\times (21.50^o-22.00^o))\\\\m_1*8.7914=241.395\\\\m_1=\frac{219.45}{8.7914} \\\\m_1=24.9\\\\ \approx25 \texttt {grams}[/tex]
25.0 grams is the mass of the steel bar.Answer:
[tex]m_{steel}=24.9g[/tex]
Explanation:
Hello,
In this case, since the water is initially hot, the released heat by it is gained by the steel rod since it is initially cold which in energetic terms is illustrated by:
[tex]\Delta H_{water}=-\Delta H_{steel}[/tex]
That in terms of mass, specific heat and temperature change is:
[tex]m_{water}Cp_{water}(T_f-T_{water})=-m_{steel}Cp_{steel}(T_f-T_{steel})[/tex]
Thus, we simply solve for the mass of the steel rod:
[tex]m_{steel}=\frac{m_{water}Cp_{water}(T_f-T_{water})}{-Cp_{steel}(T_f-T_{steel})} \\\\m_{steel}=\frac{105mL*\frac{1g}{1mL}*4.18\frac{J}{g\°C}*(21.50-22.00)\°C}{-0.452\frac{J}{g\°C}*(21.50-2.00)\°C} \\\\m_{steel}=24.9g[/tex]
Best regards.
The partial pressure of CO2 gas above the liquid in a carbonated drink is 0.45 atm. Assuming that the Henry's law constant for CO2 in the drink is that same as that in water, 3.7 x 10-2 mol/L atm, calculate the solubility of carbon dioxide in this drink.
Answer:
[tex]M_{CO_2}=0.01665M[/tex]
Explanation:
Hello,
In this case, the Henry's law allows us to relate the molar concentration and partial pressure of a solute (carbon dioxide) in a solution (solvent is water) by:
[tex]M_{CO_2}=H_{CO_2}p_{CO_2}[/tex]
Whereas we introduce the Henry constant, therefore, we can easily compute the molar solubility by:
[tex]M_{CO_2}=p_{CO_2}*H_{CO_2} =0.45atm*3.7x10^{-2}\frac{M}{atm}\\\\M_{CO_2}=0.01665M[/tex]
Regards.
Why are covalent substances gases and liquid rather than solids?
Covalent compounds are held together with an intra molecular attraction which is weaker than metallic bond
hence covalent compounds exist as liquids, gases and soft solids
Question 1 of 10
How is each element represented in the periodic table?
A. Each element is in an order based on alphabetical order.
B. Each element is listed as an abbreviation of the first letters of its
DE ME
C. Each element is represented by a one or two-letter symbol.
D. Each element is listed in its own box based on when it was
discovered
Answer:
C
Explanation:
A- incorrect, not in alphabetical order
B- incorrect, symbol for salt in NA not SA
C- correct
D- incorrect, not based on discovery
Each element represented in the periodic table is represented by a one or two-letter symbol.Hence , Option (C) is Correct.
What is Periodic Table ?
The periodic table, also known as the periodic table of the elements, is a tabular display of the chemical elements.
It is widely used in chemistry, physics, and other sciences, and is generally seen as an icon of chemistry.
Each element represented in the periodic table is represented by a one or two-letter symbol.Hence , Option (C) is Correct.
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what is the maximum number of electrons in p&q shell
Answer:
6 electrons
Explanation:
:)
hope this helps :))))))))
Answer:
each p shell can hold max. 6 electorns
i dont know what a q shell is
Which food has the least amount of monounsaturated fat?
Answer:
Butter
Explanation:
Assume you have a table like the one below.
It tells you the mass of each type of fat in a 14 g sample of food.
Start at the top of the Monounsaturated Fat column.
Go straight down until you reach the smallest number in the column (3.7).
Then, move horizontally left until you reach the Food column.
The food with the least amount of monounsaturated fat is butter.
Which of the following is a correct representation of the isotope of sulfur that has 19 neutrons? sulfur-19 sulfur-35 sulfur-16 sulfur-32
Answer:
sulfur-35
Explanation:
Sulfur-35 is a radioactive isotope that contains 19 neutrons.
Isotopes are represented with mass numbers. Mass number is the addition of number of proton and number of neutrons.
The number of proton in sulfur = 16
Number of neutron = 19
So, mass number = no. of protons + no. of neutrons
= 16 + 19
= 35
Hence, the correct answer is sulfur-35.
Answer:
sulfur -35
sulfur negative thirty fiveFor the reaction A+B↽−−⇀C+D, assume that the standard change in free energy has a positive value. Changing the conditions of the reaction can alter the value of the change in free energy (ΔG). Classify the conditions as to whether each would decrease the value of ΔG, increase the value of ΔG, or not change the value of ΔG for the reaction. For each change, assume that the other variables are kept constant.
A. Adding a catalystb.
B. Increasing [C] and [D]
C. Coupling with ATP hydrolysis
D. Increasing [A] and [B]
Explanation:
a. Adding a catalyst
no effect .( Catalyst can only change the activation energy but not the free energy).
b. increasing [C] and [D]
Increase the free energy .
c. Coupling with ATP hydrolysis
decrease the free energy value .
d.Increasing [A] and [B]
decrease the free energy.
A volume of 38.7 mL of H2O is initially at 28.0 oC. A chilled glass marble weighing 4.00 g with a heat capacity of 3.52 J/oC is placed in the water. If the final temperature of the system is 26.1 oC , what was the initial temperature of the marble? Water has a density of 1.00 g/mL and a specific heat of 4.18 J/goC. Enter your answer numerically, to three significant figures and in terms of oC.
Answer:
- 61.2°C = Initial T°
Explanation:
This is a calorimetry problem, where the heat from the water was gained by the marble.
Q = m . C . ΔT
where ΔT is final T° - initial T°, C is the specific heat and m, mass.
By the volume of water, we realize the mass (we apply density):
1 g/mL = mass / 38.7 mL
38.7 g = mass of water
Now, we need to find out the specific heat for the marble and we have Heat Capacity data
Heat Capacity = C . m
3.52 J/°C / 4 g = C → specific heat → 0.88 J/g °C
We make the equations for both heats:
m . C . ΔT from water = m . C . ΔT from the marble
38.7 g . 4.18 J/g°C ( 26.1°C - 28°C) = 4 g . 0.88 J/g °C . (26.1°C - Initial T°)
307.35 J = 4 g . 0.88 J/g °C . (26.1°C - Initial T°)
- 307.35 is a negative value, because the was has decreased the temperature, is a loss of heat, but we have to work with the positive number.
307.35 J / (4 . 0.88 °C/J) = 26.1°C - Initial T°
87.32°C = 26.1°C - Initial T°
- 61.2°C = Initial T°
DATA AND CALCULATIONS: (you must show your calculations) Part I. Determination of accuracy of a graduated cylinder Calculations: Experimental Step Measurable Mass of empty graduated cylinder 47.229 g Mass of filled graduated cylinder 71.821 g Mass of water (filled – empty) g Volume of water, calculated (calculated from mass of water, using the equation “density = mass/volume”, given the fact that the density of water is exactly 1 g/mL) mL Volume of water, measured (from the reading of the scale on the graduated cylinder) 25.0 mL Percent difference between measured and calculated volumes of water [(measured-calculated)/calculated] ×100% %
Answer:
[tex]\large \boxed{2 \, \%}[/tex]
Explanation:
1. Data
Mass of graduated cylinder = 47.229 g
Mass of graduated cylinder + water = 71.821 g
Actual volume of water = 25.0 mL
2. Calculations
(a) Mass of water
Mass = 71.821 g -47.229 g = 24.592 g
(b) Volume of water
[tex]\text{Volume} = \dfrac{\text{mass}}{\text{volume }} = \dfrac{\text{24.592 g}}{\text{ 1 g/mL}} = \text{24.592 mL}[/tex]
(c) Percent Difference
[tex]\begin{array}{rcl}\text{Percent difference}&= &\dfrac{\lvert \text{Measured - Calculated}\lvert}{ \text{Calculated}} \times 100 \,\%\\\\& = & \dfrac{\lvert 25.0 - 24.492\lvert}{24.492} \times 100 \, \% \\\\& = & \dfrac{\lvert 0.5\lvert}{24.492} \times 100 \, \%\\ \\& = & 0.02 \times 100 \, \%\\& = & \mathbf{2 \, \%}\\\end{array}\\\text{The percent difference is $\large \boxed{\mathbf{2 \, \%} }$}[/tex]
From the given electron configurations, predict which one is for a representative element?
A) 1s22s22p63s23p64s2
B) 1s22s22p63s23p63d74s2
C) 1s22s22p63s23p63d64s2
D) 1s22s22p63s23d5
From the given electron configurations, predict which one is for a representative element is 1s₂, 2s₂, 2p₆,3s₂, 3p₆, 3d₆, 4s₂.
What is element ?A chemical element is a species of atoms, including the pure material made entirely of that species, that have a specific number of protons in their nuclei. Chemical elements, unlike chemical compounds, cannot be reduced by any chemical process into simpler molecules.
The most basic form of a material is an element. In general, it cannot be streamlined or divided into smaller parts. A component of an element is an atom. A certain element only has one kind of atom per atom. Protons, neutrons, and electrons, which are subatomic particles, make up atoms.
We begin by applying the aufbau principle to the prediction of the electron configuration of an atom. It instructs us to fill the lowest energy accessible orbital, one electron at a time. It operates through element 18 (argon) in a filling pattern that is simple to predict: 1s, 2s, 2p, 3s, then 3p.
Thus, option C is correct.
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(B1-MC-12) How many of the following are oxidation-reduction reactions? NaOH (aq) + HCl (aq) → NaCl (aq) + H2O (l) Cu (s) + 2AgNO3 (aq) → 2Ag (s) + Cu(NO3)2 (aq) Mg(OH)2 (s) → MgO (s) + H2O (l) N2 (g) + 3H2 (g) → 2NH3 (g) a. 0 b. 1 c. 2 d. 3 e. 4
Answer:
C
Explanation:
They involve losing and gaining of electrons therefore there is a change of state from either solid to aqueous or vise versa
Among the given reactions only two are oxidation-reduction reactions.
Cu (s) + 2AgNO₃ (aq) → 2 Ag (s) + Cu(NO₃)₂
N₂ (g) + 3 H₂ (g) → 2 NH₃
Therefore, option (c) is correct.
What are the oxidation-reduction reactions?The reactions involve the transfer of electrons from one chemical substance to another chemical substance. These electron-transfer reactions are known as redox reactions or oxidation-reduction reactions.
These reactions involved energy changes in the form of heat, light, electricity, etc. The oxidation and reduction reaction is accompanied by the addition of oxygen or hydrogen to different substances.
The first reaction is NaOH (aq) + HCl (aq) → NaCl (aq) + H₂O. In which there is no change in the oxidation number of elements therefore, it is not a redox reaction.
In the second reaction, Cu (s) + 2AgNO₃ (aq) → 2 Ag (s) + Cu(NO₃)₂ . There is a change in the oxidation state of copper from 0 to +2 and the oxidation number of Ag from +1 to 0. It means both oxidation and reduction are involved in this chemical reaction.
In the third reaction Mg(OH)₂ (s) → MgO (s) + H₂O (l), again there is no change in the oxidation number of Mg. The fourth reaction is the formation of ammonia in which the oxidation number of N changes from 0 to -3 and the H from 0 to +1. Therefore, it is an oxidation-reduction reaction.
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Write the chemical reaction for hydrogen thiocyanate in water, whose equilibrium constant is Ka. Include the physical states for each species
Write the chemical reaction for thiocyanate ion in water, whose equilibrium constant is Kb. Include the physical states for each species
Answer:
HSCN (aq) + H₂O(l) ⇄ SCN⁻(aq) + H₃O⁺(aq) Ka
SCN⁻ (aq) + H₂O(l) ⇄ HSCN (aq) + OH⁻(aq) Kb
Explanation:
We identify the formula:
HSCN → hydrogen thiocyanate which is also known as Thiocyanic acid
HSCN (aq) + H₂O(l) ⇄ SCN⁻(aq) + H₃O⁺(aq) Ka
As an acid, it gives proton to the solution. It is a weak acid, because the Ka
Ka = [SCN⁻] . [H₃O⁺] / [HSCN]
As a weak acid, the thiocyanate ion, will be the conjugate strong base. In water It can make hydrolisis:
SCN⁻ (aq) + H₂O(l) ⇄ HSCN (aq) + OH⁻(aq) Kb
As a base, it takes a proton from water.
Kb = [HSCN] . [OH⁻] / [SCN⁻]
H-S-C-N is the structure of hydro-thi-ocyanate.
H-S-C-N structure:1. combines with water, it produces the ion thiocyanate and the ion hydronium.
2. When thiocyanate combines with water, it produces the ion hydrogen thiocyanate and the ion hydroxy.
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Upon the addition of water, As2O3 is converted to H3AsO3. During the titration H3AsO3 is oxidized to H3AsO4 and MnO4- is reduced to Mn2 . Write a balanced net ionic equation for the reaction
Answer:
5H3AsO3(aq) + 2MnO4-(aq) + 6H+(aq) → 5H3AsO4(aq) + 2Mn2+(aq) + 3H2O(aq)
Explanation:
Every net balanced ionic equation is composed of a union of two half equations;
The oxidation half equation (indicating electron loss) and the reduction half equation (indicating electron gain). Remember that redox reactions is a process in which electrons are lost and gained by chemical species simultaneously. One specie looses electrons in the oxidation half equation while the other specie gains electrons in the reduction half equation.
The balanced redox reaction equation shows the overall redox process and shows at a glance the total number of elect tribe lost or gained in the redox process. The overall redox reaction equation for the titration described in the question is;
5H3AsO3(aq) + 2MnO4-(aq) + 6H+(aq) → 5H3AsO4(aq) + 2Mn2+(aq) + 3H2O(aq)