Answer:
α = 5 rad / s²
Explanation:
This is a rotational kinematics exercise.
They indicate the initial velocity wo = 10 rad / s
w = w₀ + α t
α = [tex]\frac{w-w_o }{t}[/tex]
let's calculate
α = [tex]\frac{30-10}{4}[/tex]
α = 5 rad / s²
The velocity, the angular relation are the same in all the points of the wheel, the velocities and linear accelerations are the ones that change
a = α r
v = w r
A pinball machine uses a spring that is compressed 4.0 cm to launch a
ball. If the spring constant is 13 N/m, what is the force on the ball at the
moment the spring is released?
Answer: 0.52N
Explanation:
Formula
F=ke
Givens
e= 4.0cm>>>0.04m
k=13N/m
Plug givens into formula
F= (13N/m)(0.04m)
F=0.52N
The force on the ball at the moment the spring is released will be F =0.52N
What is a spring force ?When a spring is stretched or compressed , it displaces from equilibrium position . As a result , a restoring force will act ( which act opposite to the direction of force applied on the string ) and tends to retract the spring back to its original position . The force is called spring force
Given
x = 4cm = 0.04 m
spring constant is(k) = 13 N/m
F( spring force on the ball ) = ?
F = -k x
F = -(13)(.04)
F ( spring force) = - 0.52N
The force on the ball at the moment the spring is released will be F =0.52N
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The idea that John Marshall, the first Chief Justice of the Supreme Court, singularly established the principle of judicial review in Marbury v. Madison(1803)
a. Was an idea created and supported by James Madison and his friend Marbury.b. Is ridiculous because the US Supreme Court had made constitutional rulings well before Marbury v. Madison.c. Was an idea created and supported by Congress.d. Is a well established in the historical record and the papers of John Marshall
Answer:
c. Was an idea created and supported by Congress.
Explanation:
The idea that John Marshall, the first Chief Justice of the Supreme Court, singularly established the principle of judicial review in Marbury v. Madison(1803) was an idea created and supported by Congress.
In LEDs, the longer leg (wire) is always
connected to the ____ terminal
a) negative
b) neutral
c) positive
d) Any terminal
Positive
In an LED, the longer lead is always connected to the positive terminal
PLEASE HELP ME I WILL GIVE BRAINLY
Select five short rope exercises and describe how they are done.
Answer:
Jumping battle slams - just move the rope up and down
Alternating jump wave - jump and move the rope side to side
Alternating wide circles - move the rope in a circle position
Jumping jacks
Squat to sholder
Explanation:
The guy above me is correct give him Brainliest
HELP PLS!!!!!!! 20 POINTS
Answer:
Cayla ? please whats going on ?
Explanation:
Which of the following explains a projectile's parabolic motion? Choose all that apply
The law of inertia
acting on the x axis
The acceleration on
the x axis
The applied force
keeping the
projectile moving
The downward
force of gravity
3. Tabulate the difference between a Static friction and Kinetic friction.
Answer:
Static friction is what keeps the box from moving without being pushed, and it must be overcome with a sufficient opposing force before the box will move. Kinetic friction is the force that resists the relative movement of the surfaces once they're in motion.
What are examples of water on Earth that are part of the water cycle
A student made the claim that a 4 gram paintball fired from a paintball gun at 90 m/s could have about the same kinetic energy as a 1 gram BB pellet fired from a BB gun at 180 m/s. Do you agree or disagree with the student's claim? Use evidence and mathematical reasoning to support your response.
Answer:
I do agree with the student. Because imagene you have a tissue and a stick. And you throw them at the same speed , the stick will go farther because it' s heavier but the tissue would just blow around and not go forward because it is not heavy enought.
Explanation:
Hope this is correct have a terrific day.
You are called as an expert witness to analyze the following auto accident: Car B, of mass 2100 kg, was stopped at a red light when it was hit from behind by car A, of mass 1500 kg. The cars locked bumpers during the collision and slid to a stop. Measurements of the skid marks left by the tires showed them to be 7.30 m long, and inspection of the tire tread revealed that the coefficient of kinetic friction between the tires and the road was 0.65.
(a) What was the speed of car A just before the collision?
(b) If the speed limit was 35 mph, was car A speeding, and if so, by how many miles per hour was it exceeding the speed limit?
Answer:
Explanation:
Force of friction at car B ( break was applied by car B ) =μ mg = .65 x 2100 X 9.8 = 13377 N .
work done by friction = 13377 x 7.30 = 97652.1 J
If v be the common velocity of both the cars after collision
kinetic energy of both the cars = 1/2 ( 2100 + 1500 ) x v²
= 1800 v²
so , applying work - energy theory ,
1800 v² = 97652.1
v² = 54.25
v = 7.365 m /s
This is the common velocity of both the cars .
To know the speed of car A , we shall apply law of conservation of momentum .Let the speed of car A before collision be v₁ .
So , momentum before collision = momentum after collision of both the cars
1500 x v₁ = ( 1500 + 2100 ) x 7.365
v₁ = 17.676 m /s
= 63.63 mph .
( b )
yes Car A was crossing speed limit by a difference of
63.63 - 35 = 28.63 mph.
(a) The speed of car A just before the collision is 51.58 mph.
(b) With the given speed limit of 35 miles per hour, car A was crossing the speed limit by 16.58 mph.
What is collision?
The event when two objects strike each other from either direction, then such event is known as a collision. During the collision, the speed of colliding objects may vary according to the direction of the approach.
Given data -
The mass of car A is, mA = 1500 kg.
The mass of car B is, mB = 2100 kg.
The length of the skid mark is, d = 7.30 m.
The coefficient of kinetic friction between tires and road is, [tex]\mu = 0.65[/tex].
(a)
The combined kinetic energy of both cars is,
[tex]KE_{T}=\dfrac{1}{2} (mA+mB)v^{2}\\\\KE_{T}=\dfrac{1}{2} (1500+2100)v^{2}\\\\KE_{T}=1800v^{2}[/tex]
Applying the work-energy principle as,
Work done due to kinetic friction = Combined kinetic energy of cars
[tex]F \times d = KE_{T}\\\\(\mu \times (mA+mB)\times g) \times d = KE_{T}\\\\(0.65 \times (1500+2100)\times 9.8) \times 7.30 = 1800v^{2}\\\\v = 9.64 \;\rm m/s[/tex]
Converting into mph as,
[tex]v = 9.64 \times 2.23\\\\v = 21.49 \;\rm mph[/tex]
To know the speed of car A , we shall apply the law of conservation of momentum. Let the speed of car A before collision be v₁.
So , momentum before collision = momentum after collision of both the cars
1500 x v₁ = ( 1500 + 2100 ) x 21.49
v₁ = 51.58 mph
Thus, we can conclude that the speed of car A just before the collision is 51.58 mph.
(b)
With the given speed limit of 35 mph, the obtained speed of car A before the collision is 51.58 mph. Clearly, car A is crossing the speed limit. And the difference is,
= 51.58 - 35 = 28.63 mph.
= 16.58 mph
Thus, we can conclude that car A was crossing the speed limit by 16.58 mph.
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a toy of mass 600 is whirled by a child in a horizontal circle using a string of length 2m with a linear speed of 5 m/s determine the angular velocity of the toy?
Explanation:
angular velocity = velocity/radius
= 5/2
= 2.5 rad/s
This is one popular brand of exercise machine for a crossword puzzle
Answer:
Aerobics I think.
Explanation:
Rebecca was deciding what color to paint her room. She was deciding between sky blue, sea green, or canary yellow. While thinking about which color would be best, she wondered why things had color at all, such as the sky being blue. What makes the sky appear to be blue?
A. Only blue light can pass through the atmosphere without hitting particles.
B. The particles in the atmosphere are naturally blue.
C. Only blue light is absorbed by the particles in the atmosphere.
D. Only blue light is reflected by the particles in the atmosphere.
Answer:D
Explanation:
The reason behind the sky appear to be blue is that only blue light is reflected by the particles in the atmosphere. Hence, option D is correct.
What is Refraction?Refraction is the process by which a wave changes direction while transitioning from one material to another in physics. As an illustration, waves move more quickly in water depths than in shallow.
A wave will loop around till it is moving perpendicular to the beach if it is approaching a beach at such an angle because the wave's outer portion goes quicker than its inner portion. In warm air compared to cold, sound waves move more quickly.
A lake's surface starts to cool at night, and any sound waves which ascend are bent downward by the warmer upper layers of the atmosphere.
Therefore, it concludes that option D is correct.
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12. An organ pipe that is 1.75 m long and open at both ends produces sound of
frequency 303 Hz when resonating in its second overtone. What is the speed of
sound in the room?
295 m/s
328 m/s
354 m/s
389 m/s
401 m/s
Answer:
354 m/s
Explanation:
For the second overtune (Third harmonic) of an open pipe,
λ = 2L/3................................ Equation 1
Where L = Length of the open pipe, λ = Wave length.
Given: L = 1.75 m.
Substitute into equation 1
λ = 2(1.75)/3
λ = 1.17 m.
From the question,
V = λf.......................... Equation 2
V = speed of sound in the room, f = frequency
Given: f = 303 Hz.
Substitute into equation 2
V = 1.17(303)
V = 353.5
V ≈ 354 m/s
Hence the right answer is 354 m/s
Sound wave A is moving through a medium that is decreasing temperature.
Sound wave B is moving from a liquid to a gas medium
Which statement can be made about both waves?
1. They will speed up
2. They will increase the
density of their medium
3. They will slow down
4. They will decrease the density of their medium
The satement that can be made about sound wave A and sound wave B is, they will slow down.
Relationship between sound wave and temperatureThe relationship between sound waves and temperature is given by the following formula;
[tex]v = \sqrt{\frac{\gamma RT}{M} }[/tex]
The speed of sound wave increases with increase in temperature, and vice versa.
Speed of sound wave in liquid and gaseous mediumSound wave is mechanical wave, because it requires material medium for its propagation. Sound will travel faster in liquid medium than gaseous medium because of number of molecules per unit volume.
Thus, the satement that can be made about sound wave A and sound wave B is, they will slow down.
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What is the independent variable in the following testable question? Does changing the height of a ramp affect how far a car will travel?
Question 1 options:
the type of car
height of the ramp
how far the car will travel
the type of material the ramp is made out of
Answer:
Height of the ramp
Explanation:
The independent variable is always what the person doing the experiment can change or modify. So if the question is about whether the height of the ramp with effect the car, that is indeed what they are changing or modifying in the experiment.
After supper, your mother runs the warm pan under cold water. The pan cools off quickly. This is an example of -
conduction
convection
radiation
Answer:
conduction (the heat is transferring to the air)
A plane takes off at St. Louis, flies straight to Denver, and then returns the same way. The plane flies at the same speed with respect to the ground during the entire flight, and there are no head winds or tail winds. Since the earth revolves around its axis once a day, you might expect that the times for the outbound trip and the return trip differ, depending on whether the plane flies against the earth's rotation or with it. Is this expectation true or false
Answer:
In the Both time
Explanation:
A plane takes off at St.Louis, flies straight to Denver, and then returns the same way. The plane flies at the same speed with respect to the ground during ...
Depending on whether the plane flies against the earth's rotation or with it. Is this expectation is true statement.
What is Plane?Physical quantities such as work, temperature, and distance can all be completely represented in daily life by their magnitude. The laws of arithmetic can, however, be used to explain how these physical values relate to one another.
Motion in two dimensions is another name for motion in a plane. For instance, a projectile moving in a circle. The origin, along with the two coordinate axes X and Y, will serve as the reference point for the investigation of this kind of motion.
Therefore, Depending on whether the plane flies against the earth's rotation or with it. Is this expectation is true statement.
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a toy of mass 600 is whirled by a child in a horizontal circle using a string of length 2m with a linear speed of 5 m/s determine the centripetal force experience by the toy?
there you go, 15N. I hope this helps
g A 4-foot spring is elongated167feet long after a mass weighing 16 pounds is attached to it. The medium throughwhich the mass moves offers a damping force numerically equivalent to92times the instantaneous velocity.(a) Find the equation of motion if the mass is initially released from the equilibrium position with a downwardvelocity of 2 ft/s. (Use the convention that displacements measured below the equilibrium position are positive).(b) What is the velocity of the mass whent
Answer: hello question b is incomplete attached below is the missing question
a) attached below
b) V = 0.336 ft/s
Explanation:
Elongation ( Xo) = 16/ 7 feet
mass attached to 4-foot spring = 16 pounds
medium has 9/2 times instanteous velocity
a) Find the equation of motion if the mass is initially released from the equilibrium position with a downward velocity of 2 ft/s
The motion is an underdamped motion because the value of β < Wo
Wo = 3.741 s^-1
attached below is a detailed solution of the question
Equipotential lines are usually shown in a manner similar to topographical contour lines, in which the difference in the value of consecutive lines is constant. Clear the equipotential lines using the Clear button on the voltage tool. Place the first equipotential line 1 m\rm m away from the charge. It should have a value of roughly 9 V\rm V. Now, produce several additional equipotential lines, increasing and decreasing by an interval of 3 V\rm V (e.g., one with 12 V\rm V, one with 15 V\rm V, and one with 6 V\rm V). Don�t worry about getting these exact values. You can be off by a few tenths of a volt.Which statement best describes the distribution of the equipotential lines?1-The equipotential lines are closer together in regions where the electric field is weaker.2-The equipotential lines are closer together in regions where the electric field is stronger.3-The equipotential lines are equally spaced. The distance between each line is the same for all adjacent lines.
Answer:
the correct one is 2. the equipotential lines must be closer together where the field has more intensity
Explanation:
The equipotential line concept is a line or surface where a test charge can move without doing work, therefore the potential in this line is constant and they are perpendicular to the electric field lines.
In this exercise we have a charge and a series of equipotential lines, if this is a point charge the lines are circles around the charge, where the potential is given by
V = k q / r
also the electric field and the electuary potential are related
E = [tex]- \frac{dV}{dr}[/tex]
therefore the equipotential lines must be closer together where the field has more intensity
When checking the answers, the correct one is 2
The following statements are related to the force of a magnetic field on a current-carrying wire. Indicate whether each statement is true or false.
1) The magnetic force on the wire is independent of the direction of the current.
A) True
B) False
2) The force on the wire is directed perpendicular to both the wire and the magnetic field.
A) True
B) False
3) The force takes its largest value when the magnetic field is parallel to the wire.
A) True
B) False
Answer:
1) B: False
2) A: True
3) B: False
Explanation:
1) Statement is false because the force is not independent of the current but rather depends on the direction of the field and current.
2) Statement is true as per right hand thumb rule.
3) The statement is false because force takes its largest value when the magnetic field direction and electric current direction are perpendicular to each other.
Which formula is used to find an object's acceleration?
a= Δt – Δν
a= Δv + Δt
a= Δv/ Δt
a= Δt/Δv
Answer:
its the third one
What is a target ceiling ?
Answer:
Target ceiling. the upper limit of your physical activity. Target fitness zone. Above the threshold of training and below the target ceiling.
Hope this helps. Can u give me brainliest
Explanation:
A wave has a wavelength of 1.5 meters and frequency of 125 Hz. What is the wave speed?
The tension in a string from which a 4.0 kg object is suspended in an elevator is equal to 44 N. What is the acceleration of the elevator, if upward is the positive direction. Write the numerical value only with 2 decimal places. Do not write the unit. If the acceleration is negative (downward) include the negative sign in your answer.
Answer: 1
Explanation:
Given
Tension is the string [tex]T=44\ N[/tex]
mass of object [tex]m=4\ kg[/tex]
Tension is greater than the weight of the object i.e. elevator is moving upward
we can write
[tex]\Rightarrow T-mg=ma\\\Rightarrow T=m(g+a)\\\Rightarrow 44=4(10+a)\\\Rightarrow 11=10+a\\\Rightarrow a=1\ m/s^2[/tex]
A garden hose attached with a nozzle is used to fill a 20-gallon bucket. The inner diameter of the hose is 1 inch and it reduces to 0.5 inch at the nozzle exit. If the average velocity in the hose is 8ft/s, determine (a) the volume and mass flow rates of water through the hose (4-point), (b) how long it will take to fill the bucket with water (3-point), and (c) the average velocity of water at the nozzle exit (3-point).
Answer:
a. i. 0.044 ft³/s ii. 2.75 lb/s
b. 62.3 s
c. 32 ft/s
Explanation:
(a) the volume and mass flow rates of water through the hose
i. The volume flow rate
The volume flow rate, Q = Av where A = cross-sectional area of nozzle at inlet = πd²/4 where r = diameter of nozzle at inlet = 1 inch = 1/12 ft and v = average velocity in the nozzle = 8 ft/s.
So, Q = Av
= πd²v/4
= π(1/12 ft)² × 8 ft/s/4
= 0.175/4 ft³/s
= 0.044 ft³/s
ii. The mass flow rate
The mass flow rate, M = ρQ where ρ = density of water = 62.4 lb/ft³ and Q = volume flow rate = 0.044 ft³/s
So, M = ρQ
= 62.4 lb/ft³ × 0.044 ft³/s
= 2.745 lb/s
≅ 2.75 lb/s
(b) how long it will take to fill the bucket with water
Since we have 20 gallons = 20 × 1 gallon, we convert if to cubic feet. So, 20 gallons = 20 × 1 gallon = 20 × 0.137 ft³ = 2.74 ft³.
Since V = Qt where V = volume, Q = volume flow rate and t = time, making t subject of the formula, we have
t = V/Q
= 2.74 ft³/0.044 ft³/s
= 62.27 s
≅ 62.3 s
(c) the average velocity of water at the nozzle exit
Using the continuity equation,
A₁v₁ = A₂v₂ where A₁ = cross-sectional area of nozzle at inlet = πd₁²/4 where d₁ = diameter of nozzle at inlet = 1 inch = 1/12 ft, v₁ = average velocity in the nozzle = 8 ft/s, A₂ = cross-sectional area of nozzle at inlet = πd₂²/4 where d₂ = diameter of nozzle at inlet = 0.5 inch = 0.5/12 ft, v₂ = average velocity at exit nozzle.
So, A₁v₁ = A₂v₂
(πd₁²/4)v₁ = (πd₂²/4)v₂
πd₁²v₁/4 = πd₂²v₂/4
Dividing through by π/4. we have
So, d₁²v₁ = d₂²v₂
making v₂ subject of the formula, we have
v₂ = d₁²v₁/d₂²
v₂ = (d₁²/d₂²)v₁
v₂ = (d₁/d₂)²v₁
substituting the values of the variables into the equation, we have
v₂ = (1/0.5)² × 8 ft/s
v₂ = (2)² × 8 ft/s
v₂ = 4 × 8 ft/s
v₂ = 32 ft/s
tank contains 335 kg of water at a uniform temperature of 60oC. The tank is insulated and not heated; it neither loses nor gains heat through the walls of the tank. A valve is opened and water exits the tank at a rate of 0.5 kg/sec and a temperature of 60oC. After 10 seconds the valve is closed again . Using the assumption that water at zero degrees centigrade contains zero energy and considering only internal, how much energy left the tank through the valve during this 10 second period; report as kJ.
Answer:
Explanation:
Thermal energy or internal energy gain or loss = mass x specific heat x temperature
specific heat of water = 4.2 kJ / kg degree Celsius
mass of water lost in 10 second = rate of loss x time = .5 x 10 = 5 kg .
heat energy associated with lost water = 5 x 4.2 x ( 60 - 0 ) = 1260 kJ .
Heat energy lost = 1260 kJ .
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What is the dependent variable of this testable question? How does the temperature of a tennis ball affect the height of its bounce?
Question 2 options:
brand of tennis balls
the age of the tennis ball
temperature of a tennis ball
height of its bounce
ILL GIVE BRANLIEST TO THE CORRECT ONE
Answer:
Height of its bounce
Explanation:
The dependent variable is always what is being measured or the data collected.
Particles q1, 92, and q3 are in a straight line.
Particles q1 = -5.00 x 10-6 C,q2 = -5.00 x 10-6 C,
and q3 = -5.00 x 10-6 C. Particles q1 and q2 are
separated by 0.500 m. Particles q2 and q3 are
separated by 0.250 m. What is the net force on 92?
Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right
-5.00 x 10-6 C
-5.00 x 10-6
-5.00 x 10-6 C
91
92
93
0.500 m
0.250 m
q1 = -5.00 x 10-6 C
q2 = -5.00 x 10-6 C
q3 = -5.00 x 10-6 C
E1 = kq/r^2 = ( 9 x 10^9)( 5 x 10^-6)/(0.5^2) = 180000 N/C to the left
E2 = kq/r^2 = ( 9 x 10^9)( 5 x 10^-6)/(0.25^2) = 720000 N/C to the right
E net = 720000 - 180000 = 540000 N/C to the right
F = qE
F = (-5 x 10^6 C)(540000 N/C) = - 2.7 N
The force on q2 is 2.7 N to the left.
The net electrostatic force on the q2 is 2.7N owards left
The equation for electrostatic force is
[tex]F= k\frac{q_{1}q_{2} }{r^{2} }[/tex]
where k = [tex]9*10^{9} Nm^{2}/C^{2}[/tex] and r is the distance separating charges q1 and q2.
the force has to be calculated on a charge q2 = -5.0 ×[tex]10^{-6}[/tex] C by the charges q1= -5.0 ×[tex]10^{-6}[/tex] C and q3= -5.0 ×[tex]10^{-6}[/tex] C
distance between q1 and q2 is 0.5 m = 5×[tex]10^{-1}[/tex]m
distance between q2 and q3 is 0.25 m = 25×[tex]10^{-2}[/tex]m
force due to charge q1
[tex]F_{1}[/tex] = 9×[tex]10^{9}[/tex]×(-5)×(-5)×[tex]10^{-12}[/tex]/25×[tex]10^{-2}[/tex] N = +0.9N = 0.9N towards right
[tex]F_{2}[/tex] = 9×[tex]10^{9}[/tex]×(-50)×(-4)×[tex]10^{-12}[/tex]/625×[tex]10^{-4}[/tex] N = -3.6N = 3.6N towards left
hence net force F = [tex]F_{1}+F_{2}[/tex]
= 0.9N - 3.6N = -2.7N
F = 2.7 N towards left
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