Answer:
They have fewer hydrogen atoms attached to the carbon chain than alkanes
Explanation:
Let's compare ethane (an alkane) with ethene (an alkene) and ethyne (an alkyne):
Ethane's formula is C₂H₄, while ethene's is C₂H₄ and ethyne's C₂H₂.As you can see, alkenes and alkynes have fewer hydrogen atoms attached to the carbon chain due to them having multiple bonds between the carbon atoms.
whats the chemical equation for gypsum (made from Cacl2·2H20 and H2SO4)
what is the valence number of HCO3-.
An atom or ion has 16 protons, 15 neutrons, and 17 electrons. Is it positive, negative, or
neutral? Why? What element is it?
I really need help on this so can someone tell me the answer please!
The pressure inside your
bike tire is 12.2 psi. What is this pressure if expressed in
millimeters of mercury (mm Hg)? (14.7 psi = 1 atm = 760mmHg)
Answer: The pressure 12.2 psi is expressed in millimeters of mercury (mm Hg) as 630.9221 mm Hg.
Explanation:
Given: Pressure = 12.2 psi
According to the standard conversion of units, 14.7 psi = 1 atm = 760mmHg.
Therefore, 1 psi equal to how many mm Hg is calculated as follows.
[tex]14.7 psi = 760 mm Hg\\1 psi = \frac{760}{14.7} mm Hg\\= 51.7149 mm Hg[/tex]
Hence, 12.2 psi will be converted into mm Hg as follows.
[tex]1 psi = 51.7149 mm Hg\\12.2 psi = 12.2 psi \times \frac{51.7149 mm Hg}{1 psi}\\= 630.9221 mm Hg[/tex]
Thus, we can conclude that the pressure 12.2 psi is expressed in millimeters of mercury (mm Hg) as 630.9221 mm Hg.
Which two come together to form an ionic bond?
a. a positive cation and a ngetaive cation
b. a positive cation and a negative anion
c. a positive cation and a positive anion
d. a positive anion and a negative anion
[tex]\huge \fbox \pink {A}\huge \fbox \green {n}\huge \fbox \blue {s}\huge \fbox \red {w}\huge \fbox \purple {e}\huge \fbox \orange {r}[/tex]
b. a positive cation and a negative anion
✏ Anions are negative in nature while cations are positive in nature. Together they come together by an attractive electrostatic force to form an ionic bond.
ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ
[tex] \huge\blue{ \mid{ \underline{ \overline{ \tt ꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐ }} \mid}}[/tex]
opinion on the usage of identification of amine in daily life (medical, agriculture,etc)
Answer:
The usage is explained below
Explanation:
Amines are identified from the use of the hinsberg reaction whereby the amine is mixed well with Hinsberg reagent and done in the presence of an aqueous alkali. In this reaction, the amine will attack the electrophile which will result in the chloride being displaced and the amides being generated.
The uses of identification of amines in daily life are;
- In agriculture, it serves as a good source of making herbicides as well as acting as emulsifiers.
- In medicine, it is used in the manufacture of some popular pain killers like demerol and morphine.
- In medicine, it is used in the manufacture of an anesthetic drug known as novocaine.
- In chemical industries, amines are used as lubricating oils and also as corrosion inhibitors in boilers.
For the reaction: 2H2 + O2 → 2H2O, how many grams of water are produced from
6.00 moles of H2?
Answer:
108 g
Explanation:
2H₂ + O₂ → 2H₂OFirst we convert 6.00 moles of H₂ into moles of H₂O, using the stoichiometric coefficients of the reaction:
6.00 mol H₂ * [tex]\frac{2molH_2O}{2molH_2}[/tex] = 6.00 mol H₂OThen we can convert 6.00 moles of H₂O into grams, using the molar mass of water:
6.00 mol H₂O * 18 g/mol = 108 gThe answer is 108 grams of water.
Give all possible, accurate, correct IUPAC names for the following compounds:
Answer:
A. 4-ethyl-hex-3,5-dien-2-ol.
B. 2-chloro-3-methyl-5-tert-butylphenol.
Explanation:
Hello there!
In this case, according to the given problems, it is possible to apply the IUPAC rules to obtain the following names:
A. 4-ethyl-hex-3,5-dien-2-ol because we have an ethyl radical at the fourth carbon and the beginning of the parent chain is on the Me (CH3) because it is closest to first OH.
B. 2-chloro-3-methyl-5-tert-butylphenol: because we start at the alcohol and have a chlorine atom on the second carbon, a methyl radical on the third carbon, a tert-butyl on the fifth carbon and the parent chain is benzene which is phenol as an alcohol.
Regards!
Matter is anything that takes up space and hasA)mass.B)color.C)length.D)length and width
Answer:
A. Mass
Explanation:
If it takes up space it has to have mass. Not everything that is matter has a color, certain length or width.
What are two benefits of scientists using a diagram to model the water cycle?
A. It can show changes that occur in many different parts of Earth at
the same time.
B. It can be used to show how the parts of the cycle relate to one
another.
C. Only a few factors in the water cycle can be shown on the
diagram.
I D. It can be used to show as much detail as is present in the actual
water cycle.
Use the standard reduction potentials located in the 'Tables' linked above to calculate the equilibrium constant for the reaction:
2H+(aq) + Cu(s) H2(g) + Cu2+(aq)
Hint: Carry at least 5 significant figures during intermediate calculations to avoid round off error when taking the antilogarithm. You may use the OWL references to find the values you may need in this question.
Answer:
3.3 * 10^-12
Explanation:
The balanced equation of the reaction is;
2H+(aq) + Cu(s) ---------> H2(g) + Cu2+(aq)
Hence two electrons were transferred so n=2
E°cell = E°cathode - E°anode
E°cell = 0 V - 0.34 V
E°cell = - 0.34 V
Then;
E°cell = 0.0592/n log K
Substituting values;
- 0.34 = 0.0592/2 log K
- 0.34/0.0296 = log K
-11.486 = log K
K = Antilog (-11.486)
K = 3.3 * 10^-12
What is the freezing point in °C) of a 0.743 m
aqueous solution of KCI?
Enter your rounded answer with
3 decimal places.
Answer:
-0.276 Degrees C
Explanation:
kf of water is 1.86
Freezing point depression= m x kf x i
i= ions present ( K+ Cl-) 1=2
1.86x2X.743= .276
Since its freezinf point depression the freezing point will lower
so
0-.276= -.276
Answer: -2.764
Explanation:
How many grams of product might form for the following reaction if 33.8 L of Oxygen gas is used in the following reaction? LiCl + O2 -> LiClO3
Answer:
91.41 g of LiClO₃.
Explanation:
We'll begin by calculating the number of mole of O₂ that occupied 33.8 L. This can be obtained as follow:
22.4 L = 1 mole of O₂
Therefore,
33.8 L = 33.8 L × 1 mole / 22.4 L
33.8 L = 1.51 mole of O₂
Next, the balanced equation for the reaction.
2LiCl + 3O₂ —> 2LiClO₃
From the balanced equation above,
3 moles of O₂ reacted to produce 2 moles of LiClO₃.
Therefore, 1.51 mole of O₂ will react to produce = (1.51 × 2)/3 = 1.01 mole of LiClO₃.
Finally, we shall determine the mass of 1.01 mole of LiClO₃. This can be obtained as follow:
Mole of LiClO₃ = 1.01 mole
Molar mass of LiClO₃ = 7 + 35.5 + (3×16)
= 7 + 35.5 + 48
= 90.5 g/mol
Mass of LiClO₃ =?
Mass = mole × molar mass
Mass of LiClO₃ = 1.01 × 90.5
Mass of LiClO₃ = 91.41 g
Thus, 91.41 g of LiClO₃ were obtained from the reaction.
Convert 5,500 mg to kg. Show your work to receive full credit.
Use Hess’s Law to calculate the heat of reaction for the following reaction:
2H2O2 → 2H2O +O2 ∆H=?
2H2 +O2 → 2H2O ∆H=-572 KJ
2H2O2 → 2H2 + 2O2 ∆H=376 KJ
The heat of reaction for the reaction 2H₂O₂ → 2H₂O +O₂ is -196 KJ
Calculating heat of reaction using Hess's lawFrom the question, we are to calculate the heat of reaction for the reaction
2H₂O₂ → 2H₂O +O₂ ∆H=?
Using Hess's law
Hess's Law of constant heat summation states that regardless of the multiple stages or steps of a reaction, the total enthalpy change for the reaction is the sum of all changes
From the given equations,
2H₂ +O₂ → 2H₂O ∆H= -572 KJ ---------- (1)
2H₂O₂ → 2H₂ + 2O₂ ∆H= 376 KJ ----------- (2)
Adding equations (1) and (2), we get
2H₂O₂ → 2H₂O +O₂ ∆H= -572 KJ + 376 KJ
2H₂O₂ → 2H₂O +O₂ ∆H= -196 KJ
Hence, the heat of reaction for the reaction 2H₂O₂ → 2H₂O +O₂ is -196 KJ.
Learn more on Calculating heat of reaction using Hess's law here: https://brainly.com/question/26491956
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Use the amount (mol) of solute and amount (mol) of solvent to calculate the mole fraction. An aqueous solution of ethanol, CH3CH2OH, has a concentration of 0.216 mol/L and has a density of 0.996 g/mL. What are the mass percent and mole fraction of CH3CH2OH in this solution
Answer:
%m/m = 0.9975%
Xₐ = 0.0039
Explanation:
In order to do this, we need various data. First to all, we need tje molecular mass of the ethanol. this can be obtained in handbooks, or simply taking the atomic weights of carbon (12 g/mol), Hydrogen (1 g/mol) and oxygen (16 g/mol) and summing those values:
MM C₂H₆O = (2*12) + (6*1) + (16*1) = 46 g/mol
Now, there is an expression that is commonly used to determine the molarity of a solution given the mass percent and density, and assuming of course, 1 liter of solution:
M = d * %m/m * 1000 / MM * 100 (1)
From here, we can solve for %m/m:
%m/m = M * MM * 100 / d * 1000
As the problem is not saying the volume of solution, we can easily assume we have 1 liter of solution. Therefore, the %m/m replacing the given data is:
%m/m = 0.216 *46 * 100 / 0.996 * 1000
%m/m = 0.9975%To get the mole fraction, we first need to get the volume of solvent. From the density, we can get the mass of solution:
m = V * d
m = 1000 * 0.996 = 996 g of solution.
The mass of solute is:
m = 0.216 mol/L * 46 g/mol
m = 9.936 g/L, or simply we have 9.936 g of ethanol in 1 L of solution.
The mass of solvent:
solvent = 996 - 9.936 = 986.064 g
The molecular mass of water, so we can get the moles is 18 g/mol so:
moles water = 986.064 / 18 = 54.78
Finally the mole fraction:
Xₐ = 0.216 / (0.216 + 54.78)
Xₐ = 0.0039Hope this helps
Decide whether below chemical reaction iis an oxidation-reduction ("redox") reaction. If the reaction is a redox reaction, write down the formula of the reducing agent and the formula of the oxidizing agent.
3O2 + 4Fe → 2Fe2O3
Answer:
Explanation:
Yes , it is a redox reaction .
3O₂ + 4Fe → 2Fe₂O₃.
Increase of oxidation number shows oxidation and decrease of oxidation number shows reduction .
Neutral atoms have zero oxidation number .
O₂ and Fe are neutral atoms so their oxidation number is zero.
In Fe₂O₃ , charge on each Fe atom is + 3 . So its oxidation number is + 3 . Similarly charge on each of O in this compound is - 2 . So its oxidation number is -2 .
Oxidation number of Fe increases from 0 to + 3 . Hence it is oxidized .
Oxidation number of O decreases from 0 to -2 . Hence it is reduced .
Fe is oxidized by O ( oxygen ) so oxygen is the oxidizing agent .
O is reduced by Fe ( iron ) so iron is the reducing agent .
Select the element(s) that will have ONE unpaired electron in the p orbital.
Ca
N
B
Ar
Br
Answer: The element B will have ONE unpaired electron in the p orbital.
Explanation:
The electronic configuration of each given element is as follows.
Atomic number of calcium (Ca) is 20.
Ca: [tex]1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 4s^{2}[/tex]
Atomic number of nitrogen (N) is 7.
N: [tex]1s^{2} 2s^{2} 2p^{3}[/tex]
Atomic number of boron (B) is 5.
B: [tex]1s^{2} 2s^{2} 2p^{1}[/tex]
Atomic number of argon (Ar) is 18.
Ar: [tex]1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6}[/tex]
Atomic number of bromine (Br) is 35.
Br: [tex][Ar] 4s^{2} 3d^{10} 4p^{5}[/tex]
Therefore, boron is the only element that have one unpaired electron in the p-orbital.
Thus, we can conclude that element B will have ONE unpaired electron in the p orbital.
1A: Consider these compounds:
A. PbF2
B. Ni(CN)2
C. FeS
D. CaSO4
Complete the following statements by entering the letter(s) corresponding to the correct compound(s). (If more than one compound fits the description, include all the relevant compounds by writing your answer as a string of characters without punctuation, e.g, ABC.)
Without doing any calculations it is possible to determine that magnesium hydroxide is more soluble than __________, and magnesium hydroxide is less soluble than _______.
It is not possible to determine whether magnesium hydroxide is more or less soluble than_______ by simply comparing Ksp values.
1B: For each of the salts on the left, match the salts on the right that can be compared directly, using Ksp values, to estimate solubilities.
(If more than one salt on the right can be directly compared, include all the relevant salts by writing your answer as a string of characters without punctuation, e.g, ABC.)
1. nickel(II) hydroxide
A. Fe(OH)2
2. silver chloride
B. PbS
C. AlPO4
D. MnS
Write the expression for K in terms of the solubility, s, for each salt, when dissolved in water.
nickel(II) hydroxide
silver chloride
Ksp=_______
Ksp=________
Note: Multiply out any number and put it first in the Ksp expression. Combine all exponents for s.
Solution :
Compound Ksp
[tex]$PbF_2$[/tex] [tex]$3.3 \times 10^{-8}$[/tex]
[tex]$Ni(CN)_2$[/tex] [tex]$3 \times 10^{-23}$[/tex]
FeS [tex]$8 \times 10^{-19}$[/tex]
[tex]$CaSO_4$[/tex] [tex]$4.93 \times 10^{-5}$[/tex]
[tex]$Mg(OH)_2$[/tex] [tex]$5.61 \times 10^{-12}$[/tex]
Ksp of [tex]$Ni(CN)_2 << Ksp \text{ of}\ \ Mg(OH)_2$[/tex] and both compounds dissociate the same way. Hence [tex]$Mg(OH)_2$[/tex] is more soluble than [tex]$(B). \ Ni(CN)_2$[/tex]
[tex]$Mg(OH)_2$[/tex] is less soluble than [tex]$(A). \ \ PbF_2 \ ()Ksp \ PbF_2 > Ksp \ \text{ of } \ Mg(OH)_2$[/tex]
It is not possible to determine CD - [tex]$FeS \text{ or} \ CaSO_4$[/tex] is more or less soluble than [tex]$Mg(OH)_2$[/tex] as though they have a different Ksp values their molecular dissociation is also different and they may have a close solubility values.
[tex]$Ni(OH)_2$[/tex] can be directly compared with PbS, [tex]$AlPO_4, MnS$[/tex]
[tex]$\text{For } \ Ni(OH)_2$[/tex]
[tex]$AB_2(s) \rightarrow A^{2+} + 2B^{-}$[/tex]
[tex]$Ni(OH)_2(s) \rightarrow Ni^{2+} + 2OH^-$[/tex]
100
1-s s 2s
Ksp = [tex][A2+][B-]^2 = s \times (2s)^2 = 4s^3[/tex]
Hence they can be directly compared by Ksp values, smaller the Ksp, smaller the solubility.
For Silver Chloride
[tex]$AB(s) \rightarrow A^{x+}+B^{x-}$[/tex]
[tex]$AgCl(s) \rightarrow Ag^+ + Cl^-$[/tex]
1 0 0
1 - s s s
Ksp [tex]$=[A^{x+}][B^{x-}]=s \times s = s^2$[/tex]
Hence, they can be directly compared by Ksp values, smaller the Ksp, smaller the solubility.
This element has an oxidation number of -3 and it has 16 neutrons. What element is this room made of
Answer: Element is P, phosphor
Explanation: Phosphor has oxidation number -III and it has 15 protons. So it is possible to have 16 neutrons. Other elements having oxidation number -III are N and As which can not have an isotope with 16 neutrons.
Calculate the molarity of a solution that contains 5 mol of Li2O in 2.35 L of solution.
Answer:
2.13 M
Explanation:
To solve this problem we need to keep in mind the definition of molarity:
Molarity = moles / litersAs the problem gives us both the number of moles and the volume of solution, we can proceed to calculate the molarity:
Molarity = 5 mol / 2.35 LMolarity = 2.13 MThe answer is 2.13 M.
A saline solution has 1.9 grams of NaCI in 100 mL of solution. Calculate the molarity
Answer: Molality = concentration = 0,33 mol/l
Explanation: Concentration c = n/V and n = m/M
M = 55,44 g/mol and m = 1.9 g , V = 0.100 l
c = m/(MV)
What particle decay is this? 210 83 Bi→210 84 Po
Answer:
Beta emission
Explanation:
In beta emission, a neutron is converted into a proton thereby emitting an electron and a neutrino. A neutrino is a particle that serves to balance the spins.
When a nucleus undergoes beta emission, the mass number of the parent and daughter nuclei remain the same while the atomic number of the daughter nucleus is greater than that of its parent by one unit.
Hence, in beta emission, the daughter nucleus is found one pace to the right of the parent in the periodic table.
How many grams of chlorine gas are needed to make 5.20 x 100 g of a solution that is 2.00 ppm chlorine by mass?
mass:
CI,
Answer:
mass of chlorine = 10.4 grams
Explanation:
Mass of the solution = 5.20 × 10⁶ g
ppm chlorine by mass = 2.00
Recall that:
[tex]ppm = \dfrac{mass \ of \ chorine \ gas (solute)}{ mass of the solution }\times 10^6[/tex]
[tex]2 = \dfrac{mass \ of \ chorine \ gas (solute)}{ 5.20\times 10^6}\times 10^6[/tex]
mass of chlorine = 5.20 × 2.0
mass of chlorine = 10.4 grams
N2O3 → N2 + O2
Name the reactants in this reaction.
Name the products in this reaction.
[tex]\text{N}_{2}\text{O}_{3}=\text{nitrogen trioxide}\\\text{N}_{2}=\text{nitrogen}\\\text{O}_{2}=\text{oxygen}[/tex]
C5H12 + 8O2 —> 5CO2 +6 2O
Balance it
Answer:
it is already balanced
c5h12+8O2-->5CO2 +6h2o
Explanation:
4. Balance the following equation. Then determine the number of mols of Nitrogen formed given the values in a,b and c.
NH3 + O2 → N2 + H2O
a. 4 mol NH3
b. 4 mol N2
c. 4.5 mol O2
Answer:
4NH3 + 3O2 → 2N2 + 6H2O
a. 2 moles
b. 4 moles
c. 3 moles
Explanation:
a. 4 mol NH3
4NH3 + 3O2 → 2N2 + 6H2O
4 : 3 : 2 : 6
4 (mol)
⇒[tex]n_{N2}[/tex] = 4 × 2 ÷ 4 = 2
b. 4 mol N2
c. 4.5 mol O2
4NH3 + 3O2 → 2N2 + 6H2O
4 : 3 : 2 : 6
4.5 (mol)
⇒[tex]n_{N2}[/tex] = 4.5 × 2 ÷ 3 = 3
Consider the incorrectly balanced combustion equation:
2C6H6 + 602 => 12CO2 + 6H2O
Select ALL elements that are not balanced.
Carbon
Hydrogen
Oxygen
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Answer:
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Explanation:
hope it is helpful to you